#help me find the area and perimeter
radiant venture
terse prawnBOT
digital meadow
Hi! Find the Distance from one point to the next point. Then from one point to another adjacent point. Finally, solve for area by multiplying those two results together. Solve for perimeter by multiplying each result by two and adding the products together.
radiant venture
There are so many ways to find those distances. What method is your class using?
One way is to draw in lines, see image with red line segments. Consider the red line on the right. Its top point is (5, 5). The bottom can be figured out. The bottom of the line hits the horizontal axis. That axis has all y-slots as 0s. Notice the two given points on that axis are (-8, 0) and (9, 0). The red line is just going to be (5, 0).
We get this from the top point of the line (5, 5). To go down vertically to the horizontal axis, we go with the point (5, 0). From (5, 5) to (5, 0) is a simple distance to calculate. The x-position of the line doesn't change, but the y-position does. Can you find how long this line is?
If we want the length from (5, 5) to (9, 0), we need to see the triangle formed by connecting (5, 5) to (9, 0) and the red line coming out of (5, 5). We have one length already, the red line.
To get another length, we can use the distance between the bottom of red line to (9, 0). Remember, the red line's bottom is at (5, 0). How far is it from (5, 0) to (9, 0) ? We don't need any fancy calculations.
Now we know two lengths of the 3 sided triangle. The Pythagorean Theorem allows us to find the hypotenuse length, which is the line that connects (5, 5) to (9, 0).
Once you have this length, the remaining 3 sides of the park use basically the same process. The red lines give us right angles with the horizontal axis. This allows the use of Pythagorean Theorem to find the hypotenuse lengths for park.
Treat this like a grid where you'd graph something in algebra class. This allows you to read off lengths like the red line segments and horizontal legs of various triangles.
There are various formulas for distances between two points. And those can be applied here as well. Reading off the points just looked the easiest route to me from the figure.
what is ifif ... oh my. I'll save that file again and try again
vivid pecan
why is it a screenshot of a post on reddit
radiant venture
Please notice the little scale info in text on that graph. 1 unit = 5 m. For example, if I go from {0, 0} to {1, 0}, that is 1 unit. Now, I have to convert that to m ... 1 * 5 = 5
vivid pecan
kekw
radiant venture
cause the photo edit program that opened by default made a mess of usability, lol