Can anyone solve this ? Been having trouble myself

[floral cargo]

you have a linear system of 6 equations and 6 unknowns, by evaluating the first two and derivatives at x=0, and the second two and derivatives at x=3

e.g. f_1(0) = f_2(0), 2 = k

[floral cargo]

$j = 4$ ? shouldn't $f'_1(0) = 2$

[fading gorge]

H_Fish

[floral cargo]

d = 0 so

$540 a + 108 b + 18 c = 2$

$405 a + 108 b + 27 c + 2 = 6$

$243 a + 81 b + 27 c + 8 = 7$

[fading gorge]

H_Fish

[floral cargo]

$a = -\frac{11}{81}, b = 1, c = -\frac{49}{27}$

[fading gorge]

H_Fish