Help please

[final bison]

I need help on these two

[broken moth]

for q13, since all the angles are equal, you know that each angle must be 60deg and each side must be of equal length.

for x:
consider the lower triangle.
one angle is 80, the other is 60. so the third angle must be 180-80-60 = 40. now the 40deg is for the lower triangle. but the complete triangle's angle at that vertex is 60. so, x is 60-40 = 20deg.

for y:
the length of each side must be the same. one side is given as 46. so 16+y must also equal 46. so 16+y = 46. therefore, y = 30

for q14, there are 2 triangles. the lower left is an equilateral, while the upper right is an isosceles.

for x:
you know that in an isosceles triangle, angles opp to equal sides are the same. now, consider the vertex where the given 2 equal sides meet. the angel belonging to the equilateral triangle is 60. so the other one must be 180-60 = 120. now, the remaining 2 angles of the isosceles are the same, which is x. so 120+x+x = 180, or 2x = 60. so, x = 30deg

for y:
you know one side of the eq triangle is 20. because it is already given with the markers. now, the remaining sides of the eq triangle must also be 20. so, 5y = 20. therefore y = 4.