#How to solve this
8 messages · Page 1 of 1 (latest)
keep studying these and you will solve it
Notice if you divide by a fraction you can multiply with the inverse fraction meaning flipping the numerator and the denominator
Aditya gamer
$\frac{ 5(x^2y)^3}{(x^3y)^4} * \frac{(3x^2y)^5}{15x^5y^5} \\
\frac{5x^6y^3}{x^{12}y^4 } * \frac{243x^{10}y^5}{15x^5y^5}\\
\frac{5}{x^6y} * \frac{81x^5}{5}\\
\frac{81}{xy}$
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