#need help with finding x axis symmetry in this case

6 messages · Page 1 of 1 (latest)

next eagle
#

So i got graph f (x) = 1/4 (x - 6)^2
it's not written in ax^2 + bx + c so idk what to do here

daring summitBOT
next eagle
#

graph is written in a (x - h)^2 + k

#

so my vertex is (6,0)

#

nvm got it it's the point of the vertex

#

.solved