#Combinatorics
pulsar portal
proven lindenBOT
ashen tinsel
What have you tried? I think you first choose which 6 will go into pairs, then it's just multi-choice for 6C2,2,2 and 6C3,3
pulsar portal
wdym which 6 goes into pairs?
there is 3 groups of 2 and 2 groups of 3
@ashen tinsel
ashen tinsel
yes, so 6 people get put into pairs
ashen tinsel
I mean, there are many ways to do this question. It's probably better for you to start with what you have, because otherwise I might lead you down a path that's unintuitive for you.
why 2x(6C3) for the 2 groups of 3?
pulsar portal
because theres 6 people
and we need to choose 3 from them
oh wait if you do that then theres already 2 groups
because u choose one gorup and the remaining 3 is a group
so you do not need to multiply by 2?
ashen tinsel
you definitely don't need to multiply by 2
ashen tinsel
You actually need to divide by 2 though
pulsar portal
how come?
ashen tinsel
Let's say the people are ABCDEF. If you choose one group to be ABC, the other is automatically DEF. But if you choose one group to be DEF, the other is ABC.
pulsar portal
do I need to divide by 2 for the 2 groups of 3 or the 3 groups of 2?
@ashen tinsel
and so is it 6c2 x 6c3/2?
ashen tinsel
we're talking about the groups of 3 right now
it's going to be a bit more complicated for the groups of 2
pulsar portal
oh ok
ashen tinsel
(But I need to go make dinner now)