How does the limit of ln(x)/x as a approaches infinity equal to e^0? | Mathematics | Page 1

forest kayakBOT Oct 26, 2023, 2:21 AM

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clever owl Oct 26, 2023, 2:37 AM

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Probably skipping a bunch of steps

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if you substitute x=e^y, then you get y/e^y, apply L'Hopital's, then you have e^(-y) so it should be 0.

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Yeah, this screenshot is just nonsense.

twin tulip Oct 26, 2023, 4:20 AM

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So is this wrong?

clever owl Oct 26, 2023, 5:48 AM

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Yes

#How does the limit of ln(x)/x as a approaches infinity equal to e^0?