#Trigonometry Problem
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umm.. i think there was maybe supposed to be an angle for ii
if sin(theta) = sqrt(3) / 2
= opposite / hypotenuse
cos(theta) = adjacent / hypotenuse
can find the adjacent side using pythagorean theorem
and therefore the value of cos(theta)
area of the triangle is base * height, so would just need to find the height (opposite side) to the angle