#Is S a field?
5 messages · Page 1 of 1 (latest)
5 messages · Page 1 of 1 (latest)
$S={x+\sqrt[3]{2}y: x,y \in \Q}$
rabbits_advocate
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Can anyone explain why S is not a field?
Not closed under multiplication, e. g. Doesn't have $\sqrt[3]{4}$