Square Root 2 Proof

[pale jungle]

Why are you trying to get even numbers? You cannot look at even or odd numbers in irrational numbers.

Only the set Z^+ can be used for odd or even numbers.

[pale jungle]

wait and I will tell you about the contradiction on paper

[pale jungle]

You are saying we need to prove √2 is an irrational number

Basically lets start by saying in this fraction of p/q=√2 p,q>1, where p and q are mutually prime

so that p/q=√2.

Now after squaring both sides p^2/q^2=2

That is now after you multiply 2 on both sides you will see 2q=p^2/q

Obviously from here we can see 2q is an integer but p^2/q is not an integer since they are natural numbers and mutually prime and q>1

so 2q and p^2/q cannot be equal

√2 cannot be expressed as p/q

Therefore, √2 is an irrational number

Hope you understood

sorry I misread your question but you are supposed to prove p^2 will be equal to an even number not 'p'

So I suppose this is alright this is alright

I think it has already been answered but anyway I will answer it too

[pale jungle]

We both answered but the person looking for the answer vanished into thin air

😂 That's what really happened

Yeah lol