Trignometry Quiz

[blissful acorn]

sure you can always ask for help here!

what specifically do you need help with?

[willow lily]

Do you have any materials to review?

[random cobalt]

yea i have 2 packets

I can send it tomorrow

[cinder girder]

@random cobalt what specific topics do you need help understanding/reviewing for

I'd assume that at least the earlier pages you sent are pretty easy (names of different types of angles and all that)

[random cobalt]

photo 7 n on are things i need to review on

i just wanna make sure i’ll ace this test

i just struggle with not knowing what to calculate

[cinder girder]

For example 10 there's nothing wrong per se with the way you did it but I think the best way would have been to use the side length shortcut for 45-45-90 triangles from earlier in the packet

so instead of 1000^2 + 1000^2 = c^2 and solving for c it would have been easier to just say c = sqrt(2)*1000

or think of it this way 1000^2 + 1000^2 = c^2 is the same thing as 2 x 1000^2 = c^2 so c= sqrt(2 x 1000^2) = 1000 x sqrt(2)

for Task 2 example 5 there's nothing particularly wrong about the way you solved it but personally I think it would have been a bit easier to manipulate the terms into the function y^2 + 2y - 8 = 0 by foiling and the (-1 - y)^2 term and simplifying, and then factorize that into (y-2)(y+4) = 0 which just straight up tells you y = 2,-4

but once again your method works just fine too just potentially a little bit slower

Task 2 example 6 is just the sqrt(2)*Side length method for 45-45-90 triangles again

For task 3 example 7 I think this is probably the way that they wanted you to depict the standard position angle. Because although -60° is a coterminal angle with 300° they are technically different and you’ll be expected to understand that difference.

Example 8 is fine

For example 9 make sure you write -135 instead of just 135

other than that I see no issues whatsoever and only like 1 or 2 of the things I pointed out are actually issues