PARABOLA algebra 1 i need help asap

[tidal widget]

well the graph just looks like a simple -x^2 function

so plug in -15 into -x^2

and you have your answer

make sure to pay attention to signs

great im in 10th grade honors

youre good. just do practice problems, and ask your teacher if you don't understand

ok

but @rancid socket a u shaped graph is called a quadratic, and is the function x^2. similar to linear equations like y=mx+b, quadratic equations are just y=x^2

yes exactly

you are correct.

so since you know that the function is an upside down U, it means, the equation you need to plug x into will be in the form y=-x^2

oh well this is even easier

So since you know what x is, just go to the where x=-15 on the x axis, and wherever the line hits -15, the y value is the answer

hold on

sort of, except you have to see where the line crosses the x=-15

like the intersection point

you are correct, it would be 2.5

the brown line is x=-15

and g(x) crosses x=-15 at 2.5 like you said

no problem I was there once too

I also have some world history work i need to finish which is why i am not responding right away

but you plot it at -15, 2.5

because that looks to be where the intersection point is

no you plot it on the line

yes on the line. beacuse you are finding when the function is at x=-15, what is the y value

np, ask your teacher about it, Im sure they will be able to help you understand better

oh lol

nice