Help!

[main jasper]

the gradient of AC is the negative reciprocal of the gradient of BC.

You can use that to find q. Then put it into the equation for the gradient of AC to find p.

[simple gazelle]

I don't think thats right

if angle ABC is a right angle

that would mean AB is perpendicular to BC

It doesn't mention anywhere that AC and BC are perpendicular

And if you do it that way, it gives you that q is 5.5 when it specifically states q is an integer

[main jasper]

you're right, I got the lines mixed up

are you a-level? do you know the vector dot product?

you can form 2 simultaneous equations by using the gradient AC and the dot product of the vectors BC and BA, because that would equal zero.

then solve the two equations for p and q

[simple gazelle]

no sorry i don't know vector dot

the reason i say gcse - a-level

is cause its preparatory work for a-level but the difficulty of the questions will most likely be gcse

is that the only method?

or are there any other possibilities?

[main jasper]

2 simultanious equations:

one from the gradient AC

another form the equating the gradient of AB with the negative reciprocal of the gradient of BC, because they're perpendicular

solve for p and q

[simple gazelle]

Hello, sorry for the late reply

I don't know how i could use the gradient from AC since the y intercept is not given and the points given don't have both an x and y value (given to you)