Unsure if I am meant to solve for A first? if so how so | Mathematics | Page 1

valid mortar Aug 30, 2023, 9:39 AM

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serene windBOT Aug 30, 2023, 9:39 AM

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gray basinBOT Aug 30, 2023, 12:35 PM

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GabeDoubleU

quiet lintel Aug 30, 2023, 3:00 PM

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100=5x5x4

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So

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log(base a) 100= log(base a) 5+log(base a) 5+log(base a) 4

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log(base a) 100= 0.488 + 0.488 +0.420

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log(base a) 100= answer

#Unsure if I am meant to solve for A first? if so how so