#Calc 2 problem
12 messages · Page 1 of 1 (latest)
thats the indefinite integral, need to calculate definite from t =0 to t=t
also note that if your answer were right then you'd have travelled a nonpositive distance despite always having positive velocity x.x
velocity is the derivative of position
if position is s = s(t) then velocity is ds/dt
so in other words what you got is just the position at t not the distance (i.e., change in position) it moved after t seconds.
for that you need s(t)-s(0).
Isnt there just the simple solution of getting a function describing distance traveled as a function of time by taking the velocity function times t?
As v(t) gives us velocity in meters per second, if we then multiply by the amount of time surpassed we should get the amount of meters traveled
Ofc the definite integral gives the same result, but this way is just much simpler if correct.