One-Variable Quadratic inequality | Mathematics | Page 1

proper vault Jul 21, 2023, 1:35 PM

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Given the solutions of ax²+bx+c＜0 (a≠0) are x＜α or x＞β, (α＞0, β＞0 ), Find bx²+ax+c＞0

The solution below is what I can get right now

neon lanceBOT Jul 21, 2023, 1:35 PM

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proper vault Jul 21, 2023, 3:43 PM

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excuse me?

maiden cedar Jul 21, 2023, 4:42 PM

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The quadratic that you're given, ax²+bx+c＜0, has 3 variables, but the information you're given only has 2 variables. On the surface, it seems like that's going to make this messy, but your original quadratic can be simplified without changing the roots.

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I recommend that you first assume a>0, finish that version of the question, then go back and do the other case.

proper vault Jul 22, 2023, 7:29 AM

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i got an answer rn but im not sure

maiden cedar Jul 22, 2023, 3:13 PM

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I just realized that you can actually reduce the sign of a.

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Well done.

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Yeah, that looks good to me. Strange question.

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If you want a little more clarity on the question, you might try plugging in some values for alpha and beta.

proper vault Jul 23, 2023, 4:54 AM

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thx

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.solved

#One-Variable Quadratic inequality