#function transforms
13 messages · Page 1 of 1 (latest)
If you do them one by one, which one do you first get stuck on?
Stop you got stuck at step 1?
Or...?
Sure
f_2=f_1(x/2)*
Same applies to everything else
what
I don't know what you're saying but f_2(x)=f_1(x/2)=f(x/2-2)=1/(x/2-2)
@steep sandal Frick my bad I forgot about this channel
(xy)/2-2x=1
xy/2=3
No, the x on the right does not just vanish
You don't need to multiply both sides by (y/2-2)
Just take the reciprocal of both sides
Did you get help yet or is this still an open question?