#area
22 messages · Page 1 of 1 (latest)
Cut the shape into multiple other more familiar shapes
I recommend 2
Triangles and 1 rectangle
I think you should make it into 1 30*40 rectangle and 1 little triangle
calculate it as the whole rectangle minus the area of the missing triangle
I get you man, let’s call the bottom side of the first triangle x and the bottom side of the second triangle y
We don’t know the exact values of x and y but we know that x+y = 40
The areas of the top triangles is (1/2)(6x) + (1/2)(6y) = 3x + 3y
We can factor that into 3(x + y)
So even though we still don’t know what x is and we still don’t know what y is we know that x + y = 40 and can still get the area
You don't even need pythagorean theorem for this, right? Since the top 2 triangles are really just the negative of one triangle, and any triangle is really just half a rectangle
So it's just 40*(30-6)+(40*6)/2=1080
I believe that's what Matisse was getting at as well
Which looking at it now is a shorter equation of 40*30-6*40/2=1080 as well...
What you can do is you can draw the top segment to complete the full rectangle
First find the area of the full rectangle
Then find the area of the triangle formed after drawing the top segment of the full rectangle
And subtract the area of that triangle from the area of the rectangle
They anyways give you the base and the height of the triangle just try to find it
@mental whale