need help w these 2

[zealous hound]

I can’t seem to figure these out.

[zealous hound]

The directions are: Find the area of each regular polygon. Round your answer to the nearest tenth if necessary

[undone onyx]

S=25√3 см2

[zealous hound]

For which one

And how’d u get it if u don’t mind me asking

[marble harbor]

For the triangle, if we assume they are "regular polygons" then each angle is 60°

Because sum of angles inside a triangle = 180°

Ask google if you dont believe

And after that, you do
Area = (base)(height)/2

Im lazy so pull out your calculator

You're also on the way for the hexagon, you can think of it as 6 equilateral triangles, so this time you have the h instead of the hypothenuse so
sin(60)=opposite/hypothenuse

So
(8√3)/sin(60) = hypothenuse
and again, because its 6 equilateral triangles in a regular hexagon, the hypothenuse will be equal to the base so you can use the formula for the triangle then multiply by 6

The last triangle is a bit more annoying, but the line you erased is like a ... bisector?

Yep bisector is the term, so it splits the two angles equally, which means you can built this triangle

Now more trig suffering~

Actually lemme change the colors

If you get the orange from
sin(30)=4/orange line
You add orange line to 4 and you'll get the height

If you find purple from
tan(30)=4/purple line
You double that and you get the base

Then bh/2

Have fun~