#Hard time solving the term " 2x = ln(x-1) * (x-1) "
11 messages · Page 1 of 1 (latest)
you can represent the natural log as ln((x-1)^(x-1))
try going from there
Yes, ive tried to actually do this as such: e = (x-1)^((x-1)/2x)
that makes sense, just try breaking apart the exponent
Maybe you should try to derivate the expression after divide by X - 1 so you get an implication. Sorry if I didn't understand your question