Solve this using vu’ + uv’/ v^2 | Mathematics | Page 1

hasty caveBOT Apr 23, 2023, 6:43 AM

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lament light Apr 23, 2023, 6:47 AM

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Let u = 2x^2+3x+9
Let v = 2x+5

untold valve Apr 23, 2023, 6:48 AM

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What did you try so far.

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Show us your work

lament light Apr 23, 2023, 6:49 AM

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@misty star

green ridge Apr 23, 2023, 7:03 AM

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@misty star differentiation right?

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I think yes

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Basically $$\frac{d(\frac{u}{v})}{dx}=\frac{vu'+uv'}{v²}$$

main moatBOT Apr 23, 2023, 7:06 AM

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Very Scary Penguin

green ridge Apr 23, 2023, 7:06 AM

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So here you can easily see that the "u" here is 2x²+3x+9
While v is 2x+5

untold valve Apr 23, 2023, 7:08 AM

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What do you mean you were correct

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We have no other information other than having a question and a given method to solve it

green ridge Apr 23, 2023, 7:09 AM

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Alr use chain rule then

untold valve Apr 23, 2023, 7:09 AM

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Thats why I asked for any work you did

green ridge Apr 23, 2023, 7:09 AM

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First let's talk about u'

untold valve Apr 23, 2023, 7:09 AM

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What do you mean you were correct?

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Show us what you've tried so far

green ridge Apr 23, 2023, 7:11 AM

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It's given by $$\frac{d(2x²+3x+9)}{dx}$$
That gives $$\frac{d(2x²)}{dx}+\frac{d(3x}{dx}+\frac{d(9)}{dx}$$

main moatBOT Apr 23, 2023, 7:11 AM

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Very Scary Penguin

untold valve Apr 23, 2023, 7:18 AM

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This is all..?

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It will remain as a fraction

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Simplify the numerator

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Also, it is written as

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$\frac{\dd \left(\frac{u}{v}\right)}{\dd x}$ and not $\frac{\dd y}{\dd x}{\frac{u}{v}}$

main moatBOT Apr 23, 2023, 7:22 AM

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untold valve Apr 23, 2023, 7:23 AM

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The second one means something else

exotic ice Apr 22, 2024, 7:29 AM

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.close

#Solve this using vu’ + uv’/ v^2