Im trying to solve this exercise where it says:
prove that if x,y are real numbers ∀x∃y(2y=x2+x)
i solved it like:
y = (x^2 + x)/2
so 2(x^2 + x) / 2 = x^2 + x
meaning that :
x^2 + x = x^2 + x
and that is true because
x^2 + x - x^2 + x = 0 .
so there will always exist at least one y for all x that satisfies the equation...
Is this proof enough? or am i missing anything? I dont even know what method that is.. it just seems logical ...
#Not sure if the way I proved something is correct.
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