Math | Mathematics | Page 1

urban marsh Mar 11, 2023, 3:29 AM

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I need help with this problem

tired kindleBOT Mar 11, 2023, 3:29 AM

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oblique coyote Mar 11, 2023, 11:21 AM

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its very simple concept

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fg(x) = f(g(x))

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&

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f/g(x) = f(g^-1)(x)

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@urban marsh

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replace variable x by the required function in each case

half marten Mar 11, 2023, 11:37 AM

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I don’t think it’s f(g(x))

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It would rather be f(x)g(x)

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Else they would have write (fοg)(x)

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Same for (f/g)(x)

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Thus you just have to develop the product (-2x^2-10x+5)(-3x+7)

oblique coyote Mar 11, 2023, 12:00 PM

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oo oki i have been away from this stuff for a decent amount of time so might have been wrong

tiny coral Mar 11, 2023, 2:15 PM

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simply, fg(x) = f(x).g(x)
and f/g(x) = f(x)/g(x) ; g(x) =/= 0

So, fg(x) = 6x^3 + 16x^2 - 85x +35
f/g(x) = 2x^2 + 10x - 5/ 3x - 7 ; the numerator doesn't have real roots thus can't be factorised

half marten Mar 11, 2023, 2:31 PM

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f does have real roots

#Math