help-43

[scenic yacht]

i see

OHHH

N1 CHOICES FOR first step

OMDs

this makes much more sense in conte

x

then the number of ways to arrange is just going to be 3!

ah

tysm

just wrapping my head around the definition took time

.close

[compact pewter]

Channel closed

Closed by @scenic yacht

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lusty thistle]

hello can someone help me with this please ?

[native shard]

what’s confusing

[lusty thistle]

i have tried diff awnser but its never the good one

[native shard]

find the slope of the line

[compact pewter]

@lusty thistle Has your question been resolved?

[compact pewter]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen frost]

I'm taking some linear algebra notes for myself. I'm trying to visualize how the shortest distance between a plane and the origin works. Does the following visualization and explanation seem correct to you?

[mortal vapor]

what is the point P supposed to be; regardless of the answer if these are supposed to be notes I think this might be too terse for later reference

your explanation is to just replace p0 and n hat with different symbols

which (to me, and more concerningly to you in the future) is pretty meaningless

[fallen frost]

P is the location of the normal vector on the plane.

[mortal vapor]

normal or unit normal

well actually both have the same issue

you're not guaranteed the plane is the right distance away for the endpoint of the (unit) normal vector (which might be facing the wrong direction by the way) to actually be on the plane

[fallen frost]

In order to compute the projection between p_0 and n, you only need the angle, right? not the position?

the direction of the normal is handled with |.| absolute value.

[mortal vapor]

I agree.

But this to me reads like you explaining |p0 . n hat| directly

not whatever you're doing with P

my concern is purely with your explanation

[fallen frost]

well, the explanation is basically verbalizing what's on the picture, I guess.

It's saying that I can think of n-hat as a vector from the origin to the plane, and p_0 as a vector from the origin to the plane.

and then the picture has that, and then the projection kinda makes sense to me.

[mortal vapor]

I would be more careful with the distinction between being a vector to the plane and not just parallel to the vector you are actually describing, and (personally) write down why n hat and not any other vector (to the plane) since your explanation so far doesn't do that

[fallen frost]

n is because the plane equation uses that vector, so it's already handy.

a vector from the origin to n is to help visualize the projection -- the angle, mostly.

[mortal vapor]

-# just to expand on this, any explanation for your notes should match what makes most sense to you rather than necessarily others, but if I think it's wrong / doesn't explain enough it's likely to cause issues for you too in x months

[mortal vapor]

are you saying if I had some other vector

say q to point c

then |p0 . q hat| would also give the distance?

[fallen frost]

no, I'm not making that statement.

The plane equation and the distance formula use p_0 and n, so that's why they are in the visualization.

[mortal vapor]

why does taking the dot product with n hat give the distance

I think your explanation should have the answer to that written down

[fallen frost]

the dot product is : ||n|| ||p_0|| cos theta. If n is unit, then it's ||p_0|| cos theta. Which is just basically the length of p_0, taking into account the angle.

I know that part, so I don't have to write it down.

[mortal vapor]

if you're certain you're going to also know that in future whenever you look at these notes (and I'm assuming "taking into account angle" means what I think it does, though I'm not entirely sure) then that's fine

[fallen frost]

I guess I was more asking if the explanation and visualization where factually incorrect. I understand that my way of thinking may not jive with the way others would explain it for themselves, but it's personal flavor, I guess. I have some other notes related to that note, so I won't be completely lost.

[mortal vapor]

"taking into account the angle" is a very vague way of implying "this is the distance we want"

[fallen frost]

but, overally the explanation/visualization doesn't seem factually incorrect to you?

[mortal vapor]

I would repeat something about what's happening being finding the length of the perpendicular to the plane

I wouldn't call it wrong per se

but the explanation is missing so many details when taken on its own I think it may as well be

[fallen frost]

I'll heed your advice and think of a way to spruce it up.

[mortal vapor]

this following a similar diagram with B and P makes some of the lack of detail acceptable though I agree

[fallen frost]

Thank you for taking a look over it. I appreciate it.

🙂

.close

[compact pewter]

Channel closed

Closed by @fallen frost

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woven lodge]

help idk how to figure this out -- this is calc ab

[upper bane]

do you know the standard limit definition of the derivative?

[woven lodge]

Is it this

sorry the image is loadijng

this right

ok but now what

[dusty lance]

sorry wait, I think you need the other definition

[woven lodge]

o

wait what other definition

[upper bane]

close, but you need the one in terms of x, not h

[dusty lance]

x -> a definition

[upper bane]

also non-light mode moment

[woven lodge]

LOL mb

[upper bane]

npnp

[woven lodge]

ok lemme look

the bottom one instead?

[upper bane]

yup

then just do a direct comparison with the form you have

[woven lodge]

okay

OH is the answer A?

[dusty lance]

iirc yes

[woven lodge]

THANks guys

[native shard]

bro just scroll up

[woven lodge]

so much

[dusty lance]

it gets more confusing when it isnt only x being plugged in

[woven lodge]

yeah

I didnt know there was another definition too 😔

[dusty lance]

I can look through my notes and send you an example I just did?

pretty sure I did them last week

[woven lodge]

o its ok I only needed that one 👍

.close

[compact pewter]

Channel closed

Closed by @woven lodge

Use .reopen if this was a mistake.

[rare cliff]

asd

Hello, I'm new, I just started university. I want to know if anyone can help me. They're giving me rank and mastery of a function, but I don't understand.

[verbal kiln]

#❓how-to-get-help

#math-discussion

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz yoke]

On 71th republic day parade, captain RS Meel is planing for parade of following two group:

(a) First group of Army troops of 624 members behind an army band of 32 members.

(b) Second group of CRPF troops with 468 soldiers behind the 228 members of bikers.

These two groups are to march in the same number of columns. This sequence of soldiers is followed by different states Jhanki which are showing the culture of the respective states.

(i) What is the maximum number of columns in which the army troop can march?

(ii) What is the maximum number of columns in which the CRPF troop can march?

(iii) What is the maximum number of columns in which total army troop and CRPF troop together can march past?

(iv) What should be subtracted with the numbers of CRPF soldiers and the number of bikers so that their maximum number of column is equal to the maximum number of column of army troop?

[quartz yoke]

.close

[compact pewter]

Channel closed

Closed by @dense plinth

Use .reopen if this was a mistake.

[verbal kiln]

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary mulch]

did I do something wrong

[upper bane]

if you think you did something wrong, perhaps it would also be nice to tell us what you think you did wrong

[wary mulch]

Now I think I am on the right track

this must be what the question is trying to tell us

[wary mulch]

wait a minute I might know how to answer this now

[upper bane]

...what?

[wary mulch]

I simplified it

[upper bane]

I don't know what that achieves, but okay I guess...?

what you've managed to do is find the intersection point of the two graphs

[wary mulch]

but my sketch of log_3x^2 is incorrect

maybe because i havnt used enough x values

[quartz yoke]

u didnt set it equal to the other half of the equation i think

[wary mulch]

I did

right here

[heady sonnet]

I am looking at your original question, double check your transfer in the equations

[wary mulch]

transfer in the equations?

[thorny urchin]

two values is not sufficient for a good log graph

also note the domain of the function

the log rules apply for positive arguments
log(a^b) = b * log (a)
for a > 0
here
log_3(x^2) = log_3( |x|^2) = 2log_3(|x|)

your y value in your table is also wrong for x=3

[compact pewter]

@wary mulch Has your question been resolved?

[hard flame]

@wary mulch ?

[wary mulch]

yes but for x^2, even if u input a negative number

it iwll be positive

[hard flame]

Are you already answered or you need another one to help?

[wary mulch]

sure

I am still confused so yeah

[hard flame]

Could you show me the problem you are having?

[verbal kiln]

It’s pinned.

In all channels the issue is the pinned message or the messages below it.

[hard flame]

Oh ok!

I have a bit of difficulty to see, might take a bit of time.

Ok, yeah, you’re definitely on the right track here.
When you combine the two logs, you get log₃(x²/x) = log₃(x), and setting that equal to 0 gives x = 1.
That’s exactly what the question was trying to lead you toward nice work noticing it!

@wary mulch

[wary mulch]

yes so i got that

right

[hard flame]

Ok, great, anything else you need?

[wary mulch]

this is what I got when i put it on desmos

its not

same as my sketch

[hard flame]

Ok.

Oh I see what you mean the sketch and Desmos look a bit different, yeah.
Remember that log₃(x²) only makes sense for x ≠ 0, but it actually matches 2·log₃(x) for x > 0.
For negative x, log₃(x²) is still defined because x² > 0, which is why the red curve continues to the left while log₃(x) doesn’t.
That’s probably why your sketch didn’t line up perfectly Desmos shows the full domain for x².

@wary mulch, this is a interesting question.

[wary mulch]

Remember that log₃(x²) only makes sense for x ≠ 0, but it actually matches 2·log₃(x) for x > 0.

wdym

[hard flame]

Oh sorry, I meant that for x > 0, you can rewrite
log₃(x²) as 2·log₃(x) that’s a logarithm rule.

But that only works when x is positive, because log₃(x) isn’t defined for negative x.
That’s why Desmos shows the red curve (log₃(x²)) on both sides, but the blue one (log₃(x)) only on the right.

@wary mulch

[wary mulch]

I was watching organic chemistry, hes been emphasising tthat 2 points is enough for a sketch

[wary mulch]

Yep I am reading this rn

[hard flame]

Ok!

[wary mulch]

why both sides? You said only works when x is positive

[hard flame]

Minute.

[thorny urchin]

for a rough sketch,
they're also seem to be determining stuff like asymptotes too
the more points you have the more accurate you'll be

the log rules apply for positive arguments
log(a^b) = b * log (a)
for a > 0
here
log_3(x^2) = log_3( |x|^2) = 2log_3(|x|)

[hard flame]

Ah good question for x greater than zero log base 3 of x squared equals two times log base 3 of x but when x is less than zero x squared is still positive so log base 3 of x squared is defined but log base 3 of x is not that is why the both sides version only works when x is positive

[wary mulch]

Is that something Im failing on?

[thorny urchin]

that's part of it,
also

your y value in your table is also wrong for x=3
how are you getting y=1 when x=3 for
y = log_3(x^2)

[wary mulch]

for which function?

oh nvm

[kind viper]

is there a reason you wrote all this in words

[hard flame]

I wanted to make sure the explanation was clear conceptually, not just symbolically. But you’re right, it would look cleaner with proper notation. I’ll rewrite it that way next time.

[native shard]

bro are you a chatbot

[chilly basalt]

okay....95% LLMing...

[hard flame]

?

What does chatbot even mean?

[native shard]

facts

[hard flame]

?

[native shard]

LLM

[hard flame]

Yeah and?

Just trying to explain so it is clear enough...

[chilly basalt]

Friendly reminder, using ai tools to help in this server is strictly against the rule.

[hard flame]

I am not using ai tools.

[native shard]

💀

[hard flame]

What?

[native shard]

maybe its a language thing

[upper shore]

this is what they mean by this

[hard flame]

Going on a little break, see you in a couple of minutes.

[wary mulch]

sorry, y = 2 when x=3

[chilly basalt]

Let's move this to hlounge, I'd like to keep this channel on topic

[wary mulch]

for that function, I shoulve have used negative numbers because it will turn positive

[thorny urchin]

you should've accounted for that, yes

[wary mulch]

so what x values should I use

organic chemistry said I use the x values when I make the argument equate to the base and 1

because they are easy to work with

[thorny urchin]

use powers of your base (in this case 3) for ease of calculation
its fine to use positive ones,
but recognise that you have an even function

and reflect what you get over the y-axis

[wary mulch]

powers of your base?

I dont understand

[thorny urchin]

3^1, 3^2, etc

since your log evaluates nicely at those values

[wary mulch]

how will that make it ease for calculation

oh ok

[wary mulch]

its fine to use positive ones,
but recognise that you have an even function
and reflect what you get over the y-axis

I also dont understand these 3 lines

[thorny urchin]

how would you approach graphing something like y=x^4

[wary mulch]

its an even function

as x aproaches +inf, y approaches +inf

as x approaches -inf, y approaches +inf

[thorny urchin]

and then?

[wary mulch]

thats the end behaviour so u sketch it in terms of that

[thorny urchin]

how are you going to sketch with just the end behaviour

[wary mulch]

u need the

x intercepts

y inercepts

[thorny urchin]

can you show the whole process

[wary mulch]

yes

but what do i graph

[thorny urchin]

i mostly care about the prep, before you graph

[wary mulch]

axis of symmetry

-b/2a to find the x axis of symmetry

and then sub that x coordinate into f(x)= to get the minimum/maximum

[thorny urchin]

-b/(2a) doesn't apply in general
also recognising that you have an even function, you should know that the axis of symmetry will be x=0

what else will you be doing

[wary mulch]

find the first derivative

equate it to 0

to find st. points

find second derivative

input the x coordinate of the st point into second derivative

to find the nature

ie. minmum/maximum

[thorny urchin]

what else

you're ignoring/not mentioning one of the most basic things

[wary mulch]

label the

graph

x axis

y axis

[thorny urchin]

what else

[wary mulch]

intervals

[thorny urchin]

what intervals

[wary mulch]

intervals of the graph

[thorny urchin]

wdym

[wary mulch]

The axis parameter

[thorny urchin]

wdym

[thorny urchin]

oh yes, but even before doing this

you've made no mention of making a table of values or evaluating a few values of x to get some points

[wary mulch]

oh yes

[thorny urchin]

and my point is that when you recognise that you have an even function,
you could just make the table for one side
as the other side would just be a reflection (from property of an even function)

[wary mulch]

so i dont need to evaluate

negative x values

because they will be reflected

[thorny urchin]

yes

[wary mulch]

what about odd functions

with odd functions

I will need to evaluate negative x values

[thorny urchin]

they y value will be the negative of the value from the corresponding positive x

f(-a) = -f(a)

f(3) = 7
if odd
f(-3) = -7

[wary mulch]

yes

f(-x)=-f(x)

[thorny urchin]

and the same idea applies to the
log_3(x^2)

[wary mulch]

log_3(x^2) is an even function right

[thorny urchin]

yes

[wary mulch]

what about x^3

with an odd function

[thorny urchin]

wdym

[wary mulch]

wait one second, ill come back to this

[compact pewter]

@wary mulch Has your question been resolved?

[compact pewter]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty mountain]

My answer is 9...but not in options

[thorny urchin]

what does your c represent

[lofty mountain]

child

[thorny urchin]

what about the child

[lofty mountain]

age

[thorny urchin]

at what time

present? past? future?

[lofty mountain]

present

[thorny urchin]

now what does your a,b represent

age of parents at what time,
present? past (when the child was born)? future?

[fair scarab]

correct answer: 3 years

[thorny urchin]

Please don't just give answers away. The answer alone is meaningless. If you want to help, try to guide them through the problem.

Don't give full worked solutions away either.

[fair scarab]

sorry, dude

[compact pewter]

@lofty mountain Has your question been resolved?

[compact pewter]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short ferry]

Why is the angle between A'C and BC' 90°?

[short ferry]

,rccw

[short ferry]

I already proved it analytically and by computing some lengths and using using triangles (I moved B to C, the lengths of zhe resulting triangle were root2 root3 root5 so its right triangle)

Is there some simple way tp just see it

[covert creek]

Uhh..., project of A'C onto plane B'BCC' is B'C and B'C is perpendicular to BC' so BC' and A'C form 90 angle

[short ferry]

That doesnr always work

Projection doesnt preserve angles

[covert creek]

It always work tho, that's what I was taught

[short ferry]

Imagine if it was BD' instead, projecting it would result in 0 angle

[covert creek]

No

I meant it only works for 90° angle

[short ferry]

Oh it works for 90° if one of the lines already lies in the plane

[covert creek]

Okay so

• B'C is perpendicular to BC'
• A'B' is perpendicular to BC'
  => BC' is perpendicular to the whole plane A'B'CD hence it's perpendicular to A'C

[short ferry]

Alr, ig this works

Thabks

.close

[compact pewter]

Channel closed

Closed by @short ferry

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[serene coral]

$\begin{cases} y^2+xy^2=6x^2 \ (xy)^2+1=5x^2 \end{cases}$

[boreal girder]

Thomas

[serene coral]

I'm back

[round sonnet]

i cant solve it but i am interrested to learn how to solve it

[pine thicket]

The new line didn't register

[sick shard]

was there any reason to use cases here when you could have written the same without that

or the question is something else

[serene coral]

it's like an equation set

[sick shard]

y²+xy²=6x⁴y²+1
you can isolate y² from here then
6x⁴y²+1=5x²
substitute the value here

[serene coral]

it's supposed to be 2 equations, with the (xy)^2 being the start of a new onw

[sick shard]

oh

i understand

$\begin{cases} y^2+xy^2=6x^2 \ (xy)^2+1=5x^2 \end{cases}$

[serene coral]

how do you do it?

[sick shard]

lol

again the same?
y² can be isolated and substituted

or even x can be isolated and substituted

[serene coral]

that gives me one good solution and one monstrous solution

[sick shard]

show your work

[serene coral]

earlier on this channel

doesn't know how to link to it tho

[sick shard]

np i will find it wait

#help-43 message

[covert creek]

#help-43 message

wut

[sick shard]

2 times now

lmao

[serene coral]

@covert creek how do you manage to do the latex but not me

[covert creek]

because Im unemployed

nah you're missing a "\" in your text

[sick shard]

$6x^4-5x^3-5x^2+x+1=0$

[sick shard]

so we are here

[serene coral]

not rlly

by using rrt, we found that one solution is 1/2

[sick shard]

,w 27t³+28t-326/27=0

[boreal girder]

Sending query to Wolfram Alpha, please wait.

Something went wrong!

An unexpected error occurred while processing your command!
The error has been reported and should be fixed soon.
If the error persists, please contact our friendly support team at our support guild!

Exception

aiohttp.client_exceptions.ClientConnectorError: Cannot connect to host public5c.wolframalpha.com:443 ssl:default [Name or service not known]

[serene coral]

,w 3x^3 - x^2 - 3x - 1 = 0

[boreal girder]

Sending query to Wolfram Alpha, please wait.

Something went wrong!

An unexpected error occurred while processing your command!
The error has been reported and should be fixed soon.
If the error persists, please contact our friendly support team at our support guild!

Exception

aiohttp.client_exceptions.ClientConnectorError: Cannot connect to host public5c.wolframalpha.com:443 ssl:default [Name or service not known]

[covert creek]

wolfram alpha is cooked so

[sick shard]

it is ugly

i looked at Google

[compact pewter]

@serene coral Has your question been resolved?

[serene coral]

<@&286206848099549185>

[quick trellis]

hi

What's the question

[serene coral]

.

i've isolated y and got a beautiful solution and a reallly ugly one

[quick trellis]

this?

[serene coral]

using rrt we have x = 1/2

and the quotient is $3x^3-x^2-3x-1$

[boreal girder]

Thomas

[quick trellis]

ok

[serene coral]

any way find x?

[compact pewter]

@serene coral Has your question been resolved?

[compact pewter]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[covert creek]

I think this would be related to linear algebra which I haven't learnt but I want to know the differences between these two

[covert creek]

$\vec{u} \wedge \vec{v}$ and $\vec{u} \times \vec{v}$

[boreal girder]

Fionna The Unemployed

[covert creek]

What I know is that they're both ||u||||v||sin(theta)

[karmic stirrup]

I think that's another way to denote it?

there are also tw\o ways to denote dot product

[covert creek]

I dunno

[hexed crow]

if you found the wedge product in physics or applied math, it most likely is the cross product written differently.

[covert creek]

First time I sae that circle symbol for dot product

[karmic stirrup]

we use it for some reason

[hexed crow]

however, if you meant the "actual" wedge product, consider looking up exterior algebras.

[viscid canopy]

they are algebraically different but have a connection in R^3

both are also antisymmetric

[karmic stirrup]

what's R^3?

[covert creek]

okay in the video I'm watching it prefer to "bivector" which's also introduced

[hexed crow]

a vector space consisting of ordered triples of real numbers.

[hexed crow]

as a reply to this.

[viscid canopy]

yes bivector is a result of the wedge operation

[karmic stirrup]

how does that look like?

[hexed crow]

consider any 3D coordinate system. to describe a point in this system, you need 3 coordinates (x, y, z). that's R^3 in a very simple nutshell.

[karmic stirrup]

oh thats a fancy way to put it

[covert creek]

Interesting, so wedge product is bivector so the magnitude of bivector or the wedge product is an area right?

if so then basically we can't define cross product as area but bivector?

[viscid canopy]

we can define the cross product using a bivector but we use the hodge star to show the isomorphism

[covert creek]

Math is weird, thanks y'all I learnt new things today

.close

[compact pewter]

Channel closed

Closed by @covert creek

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich pollen]

Prime factorize 1010101010101010101010101010101010101.

[rich pollen]

It can be represent as:
(10^38 - 1)/99

[kind viper]

!status

[compact pewter]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[kind viper]

also how many 1's do you intend for this number to contain?

...19, i guess, given your representation of it.

[rich pollen]

correct

[mellow hedge]

1. I don't know where to begin.

[kind viper]

the question was directed at OP, not you

also, two accounts of which one is literally made today?

and both joined the server today?

[rich pollen]

correct

[rich pollen]

yes

I am not Joshebrk21, btw

[wooden slate]

ig this server is famous !

[kind viper]

anyway

i would try at least ruling out some small primes that definitely don't divide this

[compact pewter]

@rich pollen Has your question been resolved?

[brazen quiver]

oh, there is a cute trick for this one.

here's a hint, what is 91 * 111? What about 9091 * 11111?

[compact pewter]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm sky]

hey, can anyone help me with this equation

[fair raft]

tu connais la formule pour arctan(a)-arctan(b)?

[storm sky]

oui

ohhh

ouii

maintenet je sais comment peut-je la résoudre

merci bcp

.close

[compact pewter]

Channel closed

Closed by @storm sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[full willow]

OOPS, i apologise, wrong channel

[compact pewter]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[verbal kiln]

[full willow]

☠️ XD

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[molten grotto]

cauchy first theorem fails?

What should I do next?

Limit tends to infinity

an=(n/n)^p?

p>0

[carmine garden]

Apply cauchy's theorm to the 2ns one

[carmine garden]

idts

[carmine garden]

Try finding a_{n+1}/a_n

the limit of this

if that's less than 1, the limit should be 0, as you should prove

@molten grotto

[molten grotto]

Ratio test fails here

i got 1

[carmine garden]

oh

really?

[molten grotto]

But how?

[carmine garden]

wait a min

I think you made a mistake

can you show your working for ratio test

[molten grotto]

Ohh hang on

[carmine garden]

,rccw

[carmine garden]

uh, where did the sum go

[molten grotto]

Ratio test?

[carmine garden]

You want $\lim {n \to \infty} \frac{ \sum{i=1}^{n} n^p}{n^{p+1}}$

right

[molten grotto]

yes

[boreal girder]

wai

[carmine garden]

now find $a_{n+1}/a_n$ again

[boreal girder]

wai

[carmine garden]

It should be 0

[molten grotto]

n^p+1/n^p+2 × n^p+1/n^p

[carmine garden]

$\frac{ \sum_{i=1}^{n+1} n^p}{(n+1)^{p+1}} \cdot \frac{ n^{p}}{ \sum_{i=1}^{n} n^p}$

[boreal girder]

wai

[carmine garden]

find me this

[molten grotto]

Oh no

I found my mistake

Yeah 0

But tell me that why it is different

If i use riemann integral

1/(p+1)

[carmine garden]

Uh, i just realised I have a midsem in an hour lol

Sorry

[molten grotto]

Ohh it's ok

Thanks

.close

[compact pewter]

Channel closed

Closed by @molten grotto

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo merlin]

hi we're starting differential forms so im sorry for how clueless i am but how did they get this expression of the wedge product?

[echo merlin]

from my understanding, $\alpha=\sum_i\alpha_idx^i$ and $\beta=\sum_i\beta_idx^i$ give that $\alpha\wedge\beta=\sum_{i,j}\alpha_i\beta_i dx^i\wedge dx^j$

[boreal girder]

Syrenate

[compact pewter]

@echo merlin Has your question been resolved?

[echo merlin]

<@&286206848099549185> 🥺

[tall lantern]

Let me check if I can help you.
I mean, let me check the exercise.

[tall lantern]

Of which, what do you want me to explain to you?

[echo merlin]

the expression of $\alpha\wedge\beta$, i dont see how they got that form

[boreal girder]

Syrenate

[tall lantern]

Okey Let's go little by little

You understand this

If you understand this then we can operate

[tall lantern]

Hi?

[echo merlin]

hi sorry!

uh i can see that $\beta=f\alpha$ gives that $\alpha\wedge\beta=0$ but is the reverse implication true?

[boreal girder]

Syrenate

[tall lantern]

This is what the exercise gives us in terms of information

So, knowing this and that you know the forms of the summations

You make the product

And in the end you would release the final function

What is the one that Appears

The main problem you may have is making the product

[echo merlin]

well im fine getting here

what do you mean release the final function?

[tall lantern]

Let me eat and I'll continue explaining.

I am referring to the expression that appears in the solution.

If you have any concerns about exercising, I'll resolve it for you when I finish eating.

[echo merlin]

it's how you get from the 3rd image to the 4th that im really struggling to see

[echo merlin]

okay! thanks for helping!

i think i was able to derive it in the reverse direction, does this look okay?

[tall lantern]

So you got it now??? You don't need any more information?

[echo merlin]

okay great! thanks sm :)

.close

[compact pewter]

Channel closed

Closed by @echo merlin

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral kelp]

guys this is my working and have been checked based on the mark scheme. i wanted to make sure

is the "mean" always the (lower confidence interval + upper confidence interval) divide by two?

or is it just because the sample is a random sample? and E(X) of a random sample is (X1+X2)/2 ?

wait guys i just realized theres something odd. if mean is np, and variance is npq, then the standard deviation is not 0.4(1-0.4)? bcs 0.4 is np, and 1-0.4 means 1-np, and not 1-q. is it rlly wrong? or is n considered as 1 here?

[compact pewter]

@floral kelp Has your question been resolved?

Channel closed

Closed by @floral kelp

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint cliff]

how would i determine what this graph looks like

[bleak dock]

do you know what y = 5 cos x looks like?

[flint cliff]

5 is the amplitude

and then

because im given 4 options to choose from

[bleak dock]

and then you stretch this graph in the x-direction

also, if $0 \le \theta \le 4 \pi$, what is the inequality for $\theta/2$?

[boreal girder]

south

[flint cliff]

4pi/2

[bleak dock]

right, 0/2 and 4pi/2 or 0 and 2pi

[flint cliff]

whats does the inequality show?

[bleak dock]

that the graph has one full period

[flint cliff]

okay and then

do we need to determine where it crosses on the x axis

[bleak dock]

you don't need to

maybe if it helps you I guess

[flint cliff]

so ik the ampltitude and the period

[bleak dock]

can you send a picture of the options?

[flint wing]

south w the clutch

[bleak dock]

I think it's pretty obvious

you have -cos, cos, -sin, and sin

[flint cliff]

so its the first one

[dawn wadi]

Yup 👍

[bleak dock]

yep!

[flint cliff]

.close

[compact pewter]

Channel closed

Closed by @flint cliff

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[robust flicker]

halp

[verbal kiln]

Start by plugging in 𝑎 directly.

[robust flicker]

we get 0/0 form again

[verbal kiln]

which would result in?

[robust flicker]

ive tried to get take some variable t such that t = x-a

so now the new limit t tends to 0

[cursive harbor]

Stop suggesting LH to people as a first option smh

[untold grail]

you dont need to though

[kind viper]

lhopital sends you to hospital

[kind viper]

have you worked with limits that contian roots like this one

[verbal kiln]

me? I wasn’t.

[cursive harbor]

I love how three of us were here to jump anyone who said LH

[kind viper]

subbing t := x-a is a good idea btw

[cursive harbor]

It's been deleted

[verbal kiln]

Ohhh i see.

[robust flicker]

not really, im kinda new

[robust flicker]

i was listenin in class but here i cant rlly get ques

[noble sorrel]

😭 thats the first thing i do so. i just said without seeing lmao

[carmine garden]

hint: Rationalise

[noble sorrel]

dude

[robust flicker]

k gimme 2 mins imma try

[carmine garden]

LH is the worst

[verbal kiln]

multiply by the conjugate? I feel like it’s wrong but idk

[noble sorrel]

but we are getting correct answer from lh right? 1/ root 2a?

[carmine garden]

Math isn't about answers, but the process too

[robust flicker]

can you explain what the conjugate means

[cursive harbor]

JEE does irrepairable harm

[carmine garden]

that gives ||(2x-2a) ||in num

[kind viper]

generally: conjugate of A - B is A + B

[noble sorrel]

no need to attack me like that

[verbal kiln]

so no?

[kind viper]

the idea behind conjugates is to set up a difference of squares identity in the part you want to rationalize

[carmine garden]

uh, it works

[robust flicker]

whats goin on 😭

[carmine garden]

helpers arguing

[verbal kiln]

but not the best approach?

[carmine garden]

probably not, but it works well, and teaches a tecnhniuqe

[verbal kiln]

I see…

[robust flicker]

so....

[brittle phoenix]

/refresh

[carmine garden]

rationalise

[robust flicker]

not getting anything useful

[carmine garden]

$\lim_{x \to a}\frac{2(x-a)}{(x-a) \cdot (\sqrt{3x-a}+ \sqrt{x+a})}$

you should get thos

[boreal girder]

wai

[robust flicker]

ye i got it

[carmine garden]

now what

[robust flicker]

oh i didnt realize it cuts

damn it

[kind viper]

that's the fundamental idea behind pretty much ALL algebraically solvable limit problems.

to crystallize a pair of factors that cause the 0/0 and then cancel them off -- or as you would say, cut them.

[robust flicker]

does rationilaize work with this too

[carmine garden]

well, with some work, yes

sort of

[kind viper]

the word is "rationalize"

and you were looking for: rationalization

rational-ize

anyway yes it does but its gonna take a bit of tinkering.

[cursive harbor]

What point are we taking the limit at

I'm guessing 0 but still

[robust flicker]

sry my tabs a lil hard to type in

[native shard]

why are you replying to that

[cursive harbor]

My bad

Discord being weird

[native shard]

but yes i assume 0

[robust flicker]

the ques js getting harder 😭

[verbal kiln]

Integer limit?

[cursive harbor]

Integer limit is fucked up lmao

[verbal kiln]

I wonder why does it change anything?

[cursive harbor]

Cuz the limit doesn't exist in reals

[verbal kiln]

oh.

[robust flicker]

it is what it is and ill need to get tis down b4 the exam 😭

please this is the last 🙏

[compact pewter]

@robust flicker Has your question been resolved?

[robust flicker]

.clear

erm

[compact pewter]

Channel closed

Closed by @robust flicker

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid bobcat]

I rlly dont understand how i can find the roots of this second derivative?

[rotund wave]

remove the 2

[low sequoia]

it is better if you separate the components with parentheses

$(2e^{-x})(\sin(x))$

[vapid bobcat]

So ot is possible to find the roots of this algebraic?

[viscid canopy]

if xy = 0 then what does this tell us about x or y?

[rotund wave]

yes

[boreal girder]

MarcoMa210

[low sequoia]

it's like solving a factored polynomial now

sin(x) or 2e^-x can be 0

[vapid bobcat]

Ohhhhhhh now i get it

Sp it can be k*pi with k element of the Z

Right

[low sequoia]

k*2pi

[vapid bobcat]

Ohh alright

Thanks!

[low sequoia]

wait no

i was wrong

k*pi was right

[vapid bobcat]

Hahah np

[low sequoia]

brainfart

[vapid bobcat]

Everyone gets that sometimes

[low sequoia]

@vapid bobcat close the channel if you're done with .close

[vapid bobcat]

oh okay

.close

[compact pewter]

Channel closed

Closed by @vapid bobcat

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant gust]

No clue what to do next I’m stuck in trying to figure the area of the gray one and I’m stuck at 19h-hb

[native shard]

you're trying to find the area in terms of h and b?

[buoyant gust]

No h and x

X is the base of the smaller rectangle

[native shard]

ok it seems like you had it

can you write x in terms of b?

[buoyant gust]

I don’t really know what this means

X is 19-b

If that’s what u asked

[native shard]

can't make it much clearer im afraid

[native shard]

yea

so what's the issue

[buoyant gust]

Do I have the answer

[native shard]

yes

[buoyant gust]

Oh

Are you sure

There isn’t a number or anything

[native shard]

i don't speak whatever language that is but it seems to ask for it in terms of h and b

🤷‍♂️

so yea it won't be a number

[buoyant gust]

It’s asking for the area of the shaded rectangle

[native shard]

yea but where it says variablerna b och h

i'm guessing that sentence somehow translates to in terms of b and h

[buoyant gust]

Define the graymarked area in the variables b and h

Oh

I do have the answer

[native shard]

yes

[buoyant gust]

Ok thanks

.close

[compact pewter]

Channel closed

Closed by @buoyant gust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense parrot]

Not asking for math help rn but wondering if there is a server like this for chemistry or physics 😭

[rigid perch]

#old-network

[dense parrot]

thank u

.close

[compact pewter]

Channel closed

Closed by @dense parrot

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim lodge]

What would my bounds be

for this triple

I know y is 0 to 1

an i ask

[slim lodge]

how do you know that z = x+y based off of this slope

[slim lodge]

wait i lied

idk what it is

[bronze cargo]

well that's just half a cube

so .5 ?

[slim lodge]

.5

?

what

[bronze cargo]

nevermind

[quaint elm]

0 + 0 + 0 = 0, 1 + 0 + 1 = 2, 0 + 0 + 1 = 1 ts so easy

[slim lodge]

well

no

[tranquil prawn]

Well, you can start limiting by the x coordinates

For that you can just list all the x coordinates of the points of the tetrahedron

And find the range

@slim lodge

[compact pewter]

@slim lodge Has your question been resolved?

[compact pewter]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim lodge]

-2x^2 - 2z^2 = -2r^2

?

i thought that was only for

-x^2-y^2

i didnt know it could apply to z^2 as well

[dusky nymph]

well you can express any two rectangular coordinates in polar coordinates

i guess that's what they're doing here?

without context (what is E, what is D) it's hard to say for sure

[slim lodge]

so like

even y^2 -z^2

?

[dusky nymph]

sure, as long as you're careful not to define the same (r, theta) for more than one pair of rectangular coordinates (use different variable names if needed to avoid confusion)

[slim lodge]

thx

.close

[compact pewter]

Channel closed

Closed by @slim lodge

Use .reopen if this was a mistake.

[slim lodge]

,w (2(2)^3)/3

[boreal girder]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dark945850

[slim lodge]

,w 16-16/3

[boreal girder]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dark945850

[slim lodge]

,w (2(2)^4)/4

[boreal girder]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dark945850

[slim lodge]

,w graph z= 1-y

[boreal girder]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dark945850

[slim lodge]

,w graph y = x^2

[boreal girder]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dark945850

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[low pulsar]

how can i solve 3x+2/2x-3 = 3/2

[dusky nymph]

pls use brackets as appropriate, do you mean: (3x+2) / (2x-3) = 3/2?

[low pulsar]

what does the brackets do

[dusky nymph]

expresses the order in which you want to do the operations

$(3x + 2) / (2x - 3)$ means $\frac{3x+2}{2x-3}$

[boreal girder]

Bungo

[low pulsar]

yeah that

[dusky nymph]

ok, the most straightforward way would be to multiply both sides by 2x-3

[low pulsar]

alright

so i also multiply 3/2 by (2x-3)

[dusky nymph]

yep

[low pulsar]

kk

[desert yoke]

And if you see an inaquility on that form you need to separate on when the denominator is bigger and smaller than 0, cuz if it’s smaller you gotta invert the inequality sign.
(Doesn’t apply to this)

[low pulsar]

i obtained 6x*2 +4x - 15 = 3x - 4.5

[desert yoke]

(3x+2)/(2x-3) times 2x-3 will just make the denominator one, you shouldn’t do (3x+2).(2x-3)

[low pulsar]

then i shouldnt do 3/2 (2x-3)

[desert yoke]

You should

[low pulsar]

but its both sides

[desert yoke]

But if you remove the denominator and multiply (3x+2) by (2x-3) you’re multiplying by (2x-3)²

Because when multiplying (3x+2)/(2x-3) by (2x-3), you’rs multiplying by the value 3x+2 is being divided, thus it is equal to (3x+2).1

The other side you do operate “normally” because 3/2 is not being divided by (2x-3)
Does it make sense?

[low pulsar]

yeah but then did i do a mistake in the other problems

cause i was multiplying by the denominator

both sides

oh

wait

i get it

[desert yoke]

When you multiply a certain number a/b by b, it’s equal to a.(b/b)=a

[low pulsar]

yeah i didnt do a mistake

not sure how i forgot

[desert yoke]

The other side doesn’t have this “denominator b”, so it just multiplies

[low pulsar]

so its 3x+ 2 = 3x - 4.5

[desert yoke]

Yes

[low pulsar]

alright

[desert yoke]

Then you do the first degree equation and find the value

[low pulsar]

theres no value

no solution

[desert yoke]

Why?

Ok yea

Let me actually try it on a paper..

[low pulsar]

try because

3x - 3x

2 = -4.5

[verbal kiln]

There are no solutions.

opal is correct.

Is there anything else you need help with? Sorry for popping in so late

[low pulsar]

no worries thanks guys for ur help

.close

[compact pewter]

Channel closed

Closed by @low pulsar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[verbal kiln]

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble basalt]

ok so far i have

call VWX=a

VXW=a

VYZ=a

and VZY=a

so VWY=VXZ

and so WY=VY-VW=XZ=VZ-VX because VW=VX and VY=VZ

so thats part A

but how part B

[paper anchor]

Have you tried congruency?

Triangle WYZ and Triangle XZY

You still here @nimble basalt ?

[nimble basalt]

oop yea

uh

well i tried

but like

you have one side

and one angle

[paper anchor]

We can find the other too

[nimble basalt]

wait no

theres 2 sides

[paper anchor]

By similarity between VWX and VYZ

[nimble basalt]

im blind

i deadass just. didnt see that they shared a base

[paper anchor]

Well there's YZ common

[nimble basalt]

ok yea then SAS and we're done

[paper anchor]

And WYZ = XZY

But what's the other side?

[nimble basalt]

WY=XZ

what we proved in first part

[paper anchor]

Yes, dude I was literally thinking I'm gonna have to make you work more than you have to for proving this sides to be equal and I missed that that's what you did in the first part xD

Well that's it then, that should prove them to be equal

[nimble basalt]

yea

.solved

[compact pewter]

Channel closed

Closed by @nimble basalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact pewter]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[pallid rune]

hi, remember my hint?

[heady spruce]

no lol

[rotund sphinx]

salut

[heady spruce]

took a good nap

[pallid rune]

okay, let me dig it out for youu

@heady spruce

[heady spruce]

ok

i see it going as a circle

[pallid rune]

right

a circle centered at where?

[heady spruce]

B

[pallid rune]

hmm not really. it says C can only be perpendicular to OD, which means it can't be anything but directly down from B. which coordinate is the circle centered at? hint: ||think about where B can go. what's the difference positionally between that shape, and the points C can be?||

[heady spruce]

hmm

[pallid rune]

can you tell me where B can go first? what shape is it, and where is it centered?

[heady spruce]

b is 4 units away frm c

[pallid rune]

mhm, that'll help. but I meant the possible points B can be at

remember C is just hanging from a string that goes through B

[heady spruce]

yea

[pallid rune]

what do the possible points B can be trace out?

@heady spruce

[heady spruce]

well

i think its circle but

[pallid rune]

yes, it is!

[pallid rune]

can you see why? think about a hanging from two points (A and B). you can move one of the points anywhere you'd like, as long as it is 11-4=7 away from A

now where is it centered?

[heady spruce]

B?

cir B is centered at O

[pallid rune]

the possible points B can be is centered at B?

[heady spruce]

?

[pallid rune]

let me get a geogebra for you

[heady spruce]

ok

[pallid rune]

the length of AB+BC=AB+4=11. so how long must AB be?

@heady spruce

[heady spruce]

7

[pallid rune]

right. it must be 7, and also 7 away from A

[heady spruce]

ye

[pallid rune]

so where is the circle for the possible points for B centered at?

(all the points that are 7 away from A is a circle with radius ||7|| centered at…?)

[heady spruce]

(0,12)?

[pallid rune]

correct!

[heady spruce]

0,19

[pallid rune]

now C is a distance 4, down from B. that means the possible points for C are a distance 4 down from the possible points for B. what does that mean for the circles?

[heady spruce]

0,5

7,12

-7,12

[pallid rune]

what do these points mean

[heady spruce]

where B is

[pallid rune]

I see, yeah they are places where B could be, but not all of them

all the points where B can be is a circle centered at A with radius 7

all the points C can be is 4 down vertically from B, which means the whole circle is shifted four units down

do you see?

[heady spruce]

yea

[pallid rune]

okay

now, where on the circle for C is nearest to D

[heady spruce]

hm

[pallid rune]

https://www.geogebra.org/calculator/xexasyyg

[heady spruce]

uh

[pallid rune]

move B

(this is to get a feel of what's happening)

[heady spruce]

ok

ahh

it kinda helps my crappy imaginiation

[pallid rune]

it'd help to have a diagram with you

on a paper

[heady spruce]

ye

[pallid rune]

how do you think you can minimize C's distance

[heady spruce]

well

thats the hard part

[pallid rune]

draw lines

from points that look important

[heady spruce]

ok

[pallid rune]

I made you find the center (E) for a reason

[heady spruce]

?

[pallid rune]

connect E and D

[heady spruce]

oh

[pallid rune]

what do you notice?

[heady spruce]

one sec

nvm

c is

mid point

wait

[pallid rune]

hmm, do we know that?

can you tell me how to get the least possible value of CD? that is, where do we put C so that it's the least?

[heady spruce]

where C intersects ED

[pallid rune]

yes!

now, to find the length of CD, we first have to find the length of ED

can you do that?

[heady spruce]

ED=17

[pallid rune]

now can you find the length of EC?

that way we can subtract it from 17 and get CD

[heady spruce]

EC=7

[pallid rune]

so CD=?

[heady spruce]

10

tysm

[pallid rune]

np!

[heady spruce]

.close

[compact pewter]

Channel closed

Closed by @heady spruce

Use .reopen if this was a mistake.

[compact pewter]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight condor]

I need assistance determining the region in which h is continuous.

[cursive harbor]

Well, how much do you understand about continuity

When is a function continuous

And what can you do to continuous functions to have them stay continuous

[midnight condor]

If it is defined at a given point and the limit as the function approaches said points equals its value.

[midnight condor]

I am unsure

[wide moss]

What are you having difficulty with exactly?

On the screenshot it looks as if you've chosen the correct option already

[cursive harbor]

Good

[cursive harbor]

Well

What happens if you add two continuous functions

[midnight condor]

I didn't solve this. It's just a practice example I was sent.

[midnight condor]

It results in another continuos function im assuming?

[cursive harbor]

Good

How about multiplication

[midnight condor]

yes

[cursive harbor]

Good

And how about division

[midnight condor]

It depends on whether the denominator of the fraction will equal 0

[cursive harbor]

Yup

It's continuous everywhere except where the denominator is zero

At that point it's not even defined

Now finally

What about composition

[midnight condor]

Ahh, I'm assuming for the problem, I need to determine where xy are not defined for h(x,y)?