#help-42

1 messages · Page 131 of 1

eternal shard
#

2nd domino's successor is the 3rd domino

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like a chain

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and like

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you had n = k and n = k+1 now you flip the succesor n = k+2

warm pewter
#

Ohhhhhhhhhhhh

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Very good explanation

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Ok understood

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Can u help me w one more

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By the way thanks a lot I actually get it

eternal shard
warm pewter
#

This one is divisibility

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ii) I am stuck

potent lotusBOT
eternal shard
#

what are your thoughts on approaching this

warm pewter
#

We just do the same thing which is a base case

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N=1

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And then we assume for n=k that like it is divisible by 16

eternal shard
#

yeeeeeeeeeeeeeeedsssss

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can you tell what happens for n = 1

warm pewter
#

Yes the result gives 112 and we can factorise the 16 out to show that it is true

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So 16(7)

eternal shard
#

yesss

#

well done

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now we know for some n f(n) is divisible by 16

warm pewter
#

Yessssssss

eternal shard
#

now we need to show for f(n+1)

#

using the fact that f(n) is divisible by 16

warm pewter
#

Yes

eternal shard
#

,, f(n+1) = 5^{(n+1)+2}-4(n+1)+9 = 5^{n+3}-4n+5

potent lotusBOT
eternal shard
#

this is what we wanna show now

warm pewter
#

Yes

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But aren’t they the same thing

eternal shard
#

no

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so we basically want to show this

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using the assumption that f(n) is divisible

warm pewter
#

Is it f(n+1) - f(n) bc if both r divisible by 16 then subtracted would be divisible too

eternal shard
#

well yes

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but we want to prove f(n+1) is divisible by 16

warm pewter
#

Try to factorise 16 out

warm pewter
eternal shard
#

uhm

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i dont know how you would go about it that way

warm pewter
#

Bc we found f(k)

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Idk too

eternal shard
#

My try would be to use the assumption instantly like we know that f(n) is divisble by 16 which means f(n) is some multiple of 16

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like

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f(n) = 16m for some m

warm pewter
#

Yes

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Ok I under

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Stand what u mean

eternal shard
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then i would try to algebraically derive f(n+1)

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and see what happens

potent lotusBOT
eternal shard
#

ok we need a 5^n+3 and instead of 9 we need a 5

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we could multiply by 5

potent lotusBOT
warm pewter
#

Yepppo

eternal shard
#

now we need a -4n and a 9

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so we can write -20n as a difference that has -4n

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same with 45

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we can write 45 as a sum of two numbers where one is 9

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can u do that

warm pewter
#

-4n-16n + 9 + 36

eternal shard
#

ooooooooooooooooooooooooooooooooooooooooooooooooooooooo

warm pewter
#

Omg

potent lotusBOT
eternal shard
#

now let's bring 36 and 16n to the other side

potent lotusBOT
eternal shard
#

winnie what can you conclude

warm pewter
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Idk bc -36 cannot be factorised

eternal shard
#

we now have f(n+1) on the left

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and on the right

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some terms with 16

warm pewter
#

😅

eternal shard
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remember

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you are almos at the finishing line

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it's almost wonnie

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o shoo

warm pewter
#

5x16m + 16(n+1)-48

eternal shard
#

😭

warm pewter
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Wait

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HAHAHAHAHAA

eternal shard
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i thought 36 was divisible by 16 i am so dumb

warm pewter
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HHAAHAHAHAAHAHAHHAAHAHAHAHAJAA

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NOOOO

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Ur so smart

eternal shard
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hmm

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we did a mistake

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we dont need a 9

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we need a 5

warm pewter
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Ohhhhhh

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Ok so

eternal shard
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but uhm

warm pewter
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5+40

eternal shard
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yea 40 is also not good

warm pewter
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Hmmmm

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Omg wait

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Omggggg

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I think ik what we did

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Wrong

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It’s not 5 it’s -13

eternal shard
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😭

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i wrote it down wrong

eternal shard
warm pewter
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I didn’t even see that

eternal shard
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i did

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ok let's restart ok 😄

warm pewter
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Ok!!!

potent lotusBOT
warm pewter
#

Is it n+3

potent lotusBOT
eternal shard
warm pewter
#

Ohhhhhh

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Ok got it

eternal shard
#

Keep in mind

potent lotusBOT
eternal shard
#

THATS whaat u said with 13

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todays is the 13th too

warm pewter
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Omg yes

eternal shard
#

so we need 45 asa difference with 13

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can u do that pro

warm pewter
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Omgggggg

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32

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Omggggfddssss

eternal shard
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YA

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yea you are done basically

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q.e.d

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can u finish it

potent lotusBOT
eternal shard
#

yea i believe u

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u had it right

warm pewter
#

5^n+3-20n-45 = 5x16m
How do you type so fast?

eternal shard
#

discord likes me?

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i guess

warm pewter
#

Is this the same for all divisibikity rule questions

eternal shard
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yesss

warm pewter
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I’m on phone it’s so hard

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Ok I will just do this

eternal shard
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if something is divisible by some number

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then you can write it as a multiple of that number

warm pewter
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Ahhhhhh

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This makes sm sense

eternal shard
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f(n) divisible by x means f(n) = xm where m is an integer

warm pewter
#

Ohhhhhhhhhhhh

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Omg yes

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I will try this for other questions tomorrow

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By the way thanks sm u spent so much brainpower and time

eternal shard
#

you deserve it!

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you are a very good student

warm pewter
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If I have questions can I dm u 🥲 but not frequent or else I’m gonna disturb too much

warm pewter
#

😂

eternal shard
calm coralBOT
#

@warm pewter Has your question been resolved?

calm coralBOT
#
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calm coralBOT
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junior zodiac
#

i have a question

calm coralBOT
junior zodiac
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k = 2 btw

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i get all these seperate cases

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case 1, the cdf is always 0

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case 2 we can integrate with the given bounds

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but i dont really understand case 3 (and case 4, but they look pretty symmetrical)

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why do we fill in F(x,y) with y = 1 is my question

glass heart
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F(x,y) is the probability P(X<x,Y<y). but thats the same as P(X<x,Y<1) cause Y>1 has prob 0

calm coralBOT
#

@junior zodiac Has your question been resolved?

calm coralBOT
#
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manic timber
#

what do they mean actual value?

calm coralBOT
manic timber
#

do we just make another estimate with more subdivisions and call that the actual value?

leaden thunder
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just pick an arbitrary increasing function that goes through the same points

manic timber
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how

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should i just use a power regression on desmos?

leaden thunder
#

just draw it on paper

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the picture will give away the estimates being under or over

manic timber
#

ohh

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thanks

#

.close

calm coralBOT
#
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calm coralBOT
#
Available help channel!

Send your question here to claim the channel.

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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cloud gyro
#

hello

calm coralBOT
cloud gyro
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im trying to change the bounds of integration

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this is what i have so far

verbal pumice
cloud gyro
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but its the wrong answer

wary tundra
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bro is just googling lmao

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lemme check

calm coralBOT
# verbal pumice

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

verbal pumice
#

we are the same person

cloud gyro
#

sorry that is just my ipad discord

wary tundra
#

thats cool... an alt account... you are banned

#

jk

cloud gyro
#

oh naur

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it says in the solutions

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that the leftmost x value should be 0

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but i dont know how to get that

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help

wary tundra
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lemme think

cloud gyro
#

i think i remember my professor saying that i cant have a function as bounds for my outer integral

wary tundra
#

wait a sec

cloud gyro
#

should i ask chatgpt he frustrates me when i ask him math questions

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sorry yes

wary tundra
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hows this?

cloud gyro
#

oh woah i think youre right

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wait why sinx on the bottom

wary tundra
#

The given bound x=arcsin(y) can be written as y=sin x

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since

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x ranges from

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arcsin(0) = 0 to pi/2

verbal pumice
#

but in the original equation it’s the area under arcsin

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oh wait is it not?

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i might have misinterpreted

wary tundra
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who are you know?

verbal pumice
#

i am hi sorry

wary tundra
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aah same guy , my bad

verbal pumice
#

it’s okay lol!

verbal pumice
kind axle
#

what book are you using for multivar calc

verbal pumice
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oh these were just problems my professor wrote down for us to solve

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i don’t think she’s got them from the book but i use multivariable calc 8th ed

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mc

wary tundra
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Since x= arcsin(y) was the lower bound in the original integral, this means that y starts at sin(x) where we can wite in term of x

verbal pumice
#

mcgraw*

kind axle
#

Hm never heard of that one

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But alright

verbal pumice
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sorry mccallum huges hallet

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i got the names mixed up from a different textbook

wary tundra
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originally, x starts at arcsin(y) meaning for a fixed y, we must solve for the corresponding lower x value

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bruh.... are you good at Binomial?

verbal pumice
#

not good

wary tundra
#

i'm cooked

verbal pumice
#

your question looks too big brain form me

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for*

wary tundra
#

ig its not

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lmoa

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what you doin rn?

verbal pumice
cloud gyro
#

this is the answer im sorry i should have posted this earlier

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but it looks like she forgot to switch the dx dy

wary tundra
#

soo... my answer isn't correct?

verbal pumice
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ah man

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you had the x bound right

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better than me

wary tundra
#

nah, sin x whould be in lower limit

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your sir is wrong here

verbal pumice
#

i shall ask chatgpt

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wait

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how did you get the 0 to pi/2

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you could be right, there were a lot of errors in the solutions manual

wary tundra
verbal pumice
wary tundra
#

ig you should get some rest for now

verbal pumice
#

what do you mean my friend 😭

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i’m still confused

wary tundra
#

get some sleep

verbal pumice
#

wouldn’t the x left most x bound depend on the function?

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it’s only 7pm for me, but i will let you go

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what is your chess elo

wary tundra
verbal pumice
#

WOAH

wary tundra
verbal pumice
#

NUH UH

#

wow that’s impressive

wary tundra
#

UH HUH

verbal pumice
#

good for you man

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alright thanks for the help

wary tundra
#

whats yours?

kind axle
tame quail
#

damn

verbal pumice
#

i’d rather not disclose 😔

tame quail
#

that's high

verbal pumice
#

that’s IM level. you’re crazy good

wary tundra
tame quail
#

I can't play rn

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about to work

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sorry

kind axle
#

aw i was hoping you could do a quick game

tame quail
#

you would probably crush me though

wary tundra
wary tundra
tame quail
#

I'm like 1500 USCF

wary tundra
tame quail
#

depends on the time control

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in blitz maybe

wary tundra
#

choose one.... bad opening or without queen?

tame quail
#

anyway I can't play right now unfortunately

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depends on how bad the opening is

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in some openings you lose your queen

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so

kind axle
verbal pumice
#

do any of you big brain chess players know why the left bound doesn’t depend on the function

tame quail
#

that's not as bad as being down a queen

verbal pumice
#

the upper bound is pi/2

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oh you mean for y

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oh i get it

tame quail
#

yeah

wary tundra
verbal pumice
#

oh that really just cleared all my questions

wary tundra
tame quail
#

you get more development and arguably the bishop pair is better in the opening/middle game

wary tundra
tame quail
#

being down a piece is significantly worse than down an exchange

verbal pumice
wary tundra
tame quail
#

not to mention down a queen

tame quail
wary tundra
#

ohk... i'll give you my queen in few moves...

tame quail
#

but maybe like

#

the fried liver?

#

let me be the attacker and allow it

verbal pumice
#

cow opening 😏

wary tundra
tame quail
wary tundra
tame quail
#

ok sure

#

I can't now though

wary tundra
verbal pumice
#

when will this tournament take place

wary tundra
#

fuck

tame quail
#

dude I can't play now 😭

#

just started working

wary tundra
verbal pumice
#

DOWN

wary tundra
#

ohk... same goes for you... take my queen

verbal pumice
#

so uh maybe a worse opponent for you

wary tundra
verbal pumice
#

…bullet

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i just spam play bullet and hope the time runs out

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that’s my strategy

wary tundra
verbal pumice
#

i’m ashamed to say

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ok i’m down for that

wary tundra
#

ohk ohk

verbal pumice
#

where do you want to play

wary tundra
verbal pumice
#

let’s go!

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wait i’m getting nervous knowing you’re 2300

#

I MESSED UP

#

IM OUT FOR YOUR CLOCK BUDDY

#

that was a good game

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i liked your strategy not letting me take any pieces

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being down a whole queen is just too unfair i think

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oh did you want white?

wary tundra
#

i should have grinded more

verbal pumice
#

do you want white

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i’ll resign

wary tundra
#

nah

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i'm fine with black

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just don't take my pawn

verbal pumice
#

okay

wary tundra
#

only the queen at first

verbal pumice
#

are you sure?

wary tundra
#

then you can take as much as pawns you want

kind axle
wary tundra
#

after you get the queen

verbal pumice
#

i could trade the queen for 2 bishops

wary tundra
verbal pumice
#

LOL

#

your wish

wary tundra
#

get back to game

verbal pumice
#

i can’t move for some reason

#

ok

#

scholars mate attempt

#

oh shake my head 😦

calm coralBOT
#

@cloud gyro Has your question been resolved?

wary tundra
#

lets do one proper

verbal pumice
#

oh man

#

okay

#

can you send another challenge i think i lost the page

wary tundra
verbal pumice
#

uh i think it’s lost 😞

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good game

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you destroyed me

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it’s back to studying for me.

wary tundra
#

i think so

verbal pumice
#

yes lol

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thanks for the games

wary tundra
#

hats the time there?

verbal pumice
#

and the help with my math

wary tundra
#

whats*

verbal pumice
#

it’s 7:30pm

wary tundra
#

nice.. ^AM here

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6

#

AM

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i should sleep no

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now*

verbal pumice
#

NOW?

#

yes you should

wary tundra
#

yes?

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should i?

verbal pumice
#

YES

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have a good night

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or morning..?

wary tundra
#

good morning

verbal pumice
#

good morning

#

thanks for the help!

#

.close

wary tundra
#

i'm not sleeepy

verbal pumice
#

GO TO BED

#

😭

#

6am 😭

wary tundra
#

plz... let me stay

verbal pumice
#

.close

#

.close

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WHY WONT THIS THING CLOSE

wary tundra
#

hehe

verbal pumice
#

YOU NEED TO SLEEP

wary tundra
#

i'm find dude... i woke up at 4

calm coralBOT
#
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verbal pumice
#

goodbye friend!

wary tundra
#

whats your age?

cloud gyro
#

im 19

wary tundra
#

damn... same

cloud gyro
#

AND YOURE 2300??

#

ive failed as a person

#

man

calm coralBOT
#
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hardy sail
calm coralBOT
hardy sail
#

hi guys

#

I've been looking for an hour to figure out how to solve this operation without giving me a coherent result.

#

(It's not for me, it's for my sister who is in third grade and goes to high school)

manic hawk
#

What do the symbols mean?

#

!original

calm coralBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

hardy sail
icy parrot
hardy sail
calm coralBOT
# icy parrot Help

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

hardy sail
#

pls help

#

<@&286206848099549185>

calm coralBOT
#

@hardy sail Has your question been resolved?

calm coralBOT
#

@hardy sail Has your question been resolved?

calm coralBOT
#

@hardy sail Has your question been resolved?

keen flare
#

since this is just an expression

#

doesn't seem to equal anything

calm coralBOT
#
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stable hollow
calm coralBOT
stable hollow
#

Okay so for c

#

Ik how to find reflections and stretches

#

How do I find the verticle and horizontal translations?

#

Like how many units it moved up/down and left/right

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Do I need to draw out the stretch first?

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Or how tf

#

<@&286206848099549185>

calm coralBOT
#

@stable hollow Has your question been resolved?

calm coralBOT
#
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stable hollow
calm coralBOT
stable hollow
#

So how do I do 15

#

First find the inverse?

#

So

#

(X+2) over 4 = f^-1 (x)

wanton wave
velvet osprey
#

also lowercase x not uppercase X, careful w/ that

#

otherwise yes f^-1(x) = (x+2)/4

stable hollow
velvet osprey
#

well you have yourself a formula for the inverse now

#

all that's left to do is to find its values at the points they want

stable hollow
#

So solve for x?

#

Is this written correctly?

velvet osprey
#

no you are overthinking it.

#

do you know how to evaluate a function at a point?

stable hollow
#

Idk

#

Can someone just tell me

#

I should've been sleeping 5 hours ago 😭

#

(4+2)/4 = 4

#

This?

buoyant ridge
#

when you say f(3), what is 3? what does it represent

velvet osprey
#

(4+2)/4 isn't equal to 4

stable hollow
#

Nvm

#

Bro

#

Just what do I put where

velvet osprey
#

f^-1(4) = (4+2)/4 = what you want

velvet osprey
stable hollow
#

Mb

#

Can someone just

#

Idk

velvet osprey
#

f^-1(4) = (4+2)/4 = what you want

#

for letter a

stable hollow
#

??

#

I don't see a

velvet osprey
#

letter a) like in the question

#

it has four subproblems

hasty mulch
stable hollow
#

Idk

velvet osprey
#

you asked to show what needs to be done, i showed you what needs to be done

#

if you are deliberately depriving yourself of sleep this is only your problem but not ours

hasty mulch
potent lotusBOT
stable hollow
#

I think I understand

#

3/2

stable hollow
#

Study

hasty mulch
#

$f^{-1}(x) = \frac{x+2}{4}$.

velvet osprey
potent lotusBOT
stable hollow
#

(x+2)/4

#

So for this example

#

You plug in whatever you want to find

#

Into x

#

And whatever it = is the answer

hasty mulch
stable hollow
#

Exactly

#

So let's do 9c

#

15c*

#

(8+2)/4

#

10/4

#

5/2

#

?

hasty mulch
#

Exactly.

stable hollow
#

Ok thank you so much 🙏🏻

#

I need to sleep now

hasty mulch
#

You're welcome, and be sure to get enough sleep.

stable hollow
#

Yeah

#

Well

#

I'm waking up in Leeds than 6 hours

#

Normaly I get 6.5-7 before tests and do fine

#

This might be bad though

velvet osprey
#

definitely very bad

stable hollow
#

Anyways cya

#

Sleeping rn

hasty mulch
#

Alright, bye!

stable hollow
#

So idk

hasty mulch
#

.close

#

Wait, can someone close the channel-

velvet osprey
#

only OP or a green name can close

#

i'll just do it myself

#

.close

calm coralBOT
#
Channel closed

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hasty mulch
#

Oh, I see.

calm coralBOT
#
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south obsidian
calm coralBOT
south obsidian
#

Someone can help me in this please

hasty mulch
#

Is the question asking to simplify?

desert star
south obsidian
hasty mulch
#

Wait a minute. If the question is asking to simplify, there wouldn't be two sides to the equation.

#

Oh, it's asking to solve for x.

south obsidian
#

My bad

hasty mulch
#

OK, question 2b, right?

south obsidian
#

Yesyes

hasty mulch
#

First, simplify the left-hand-side.

#

Do you know how?

south obsidian
#

I did the whole exercise but my teacher got a different result from mine and I asked chat got but now I'm confused so I just need you to tell me if I did it right

calm coralBOT
south obsidian
#

Wait

#

Im transcripting my letter is trash

hasty mulch
#

Take your time, no worries.

south obsidian
south obsidian
hasty mulch
#

And what was the result your teacher got?

south obsidian
south obsidian
hasty mulch
#

Let's see if we can recreate your teacher's result.

#

$$\frac{1}{2}(\frac{10}{3}x-\frac{2}{9})-\frac{1}{3}=\frac{7}{3}x$$
$$\frac{10}{6}x-\frac{2}{18}-\frac{1}{3}=\frac{7}{3}x$$

potent lotusBOT
hasty mulch
#

...

#

I gotta go, sorry...

south obsidian
#

Ouuuh

#

Ok 😔

#

Goodbye

#

.close

calm coralBOT
#
Channel closed

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hasty mulch
south obsidian
#

.reopen

calm coralBOT
#

calm coralBOT
#
Channel closed

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calm coralBOT
#
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zenith summit
calm coralBOT
zenith summit
#

how do I show A is orthogonal and that A can be chosen s.t. det(A) = 1

#

i can only show that det(A) = ±1

quick talon
#

Hey

#

I gave you an answer yesterday and you said A is supposed to be a matrix

#

Well the answer I gave you IS a matrix

#

Just try the product will you ?

zenith summit
#

w and v are column vectors so w^T v will give me a scalar

#

@quick talon

quick talon
#

This is w v^T

zenith summit
#

oh ok

#

yeah fine that makes sense

zenith summit
quick talon
#

How do you show a matrix is orthogonal

zenith summit
#

A^T A = I

#

is one way

#

or the columns of A form an orthonormal basis of R^n

quick talon
zenith summit
quick talon
#

Just write it and I’ll tell you

zenith summit
quick talon
#

That’s not how you write it

#

Lose the basis B, it’s just adding complexity

zenith summit
zenith summit
#

[v]_B is a column vector on its own (coordinates of v in the standard basis)

quick talon
zenith summit
#

no that's not what i was talking about

zenith summit
#

it does but i had already worked out this much so it would be nice if there's a way to continue on from there

calm coralBOT
#

@zenith summit Has your question been resolved?

calm coralBOT
#
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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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summer mica
#

im confused on how ther side splitter works

summer mica
calm coralBOT
#

Show your work, and if possible, explain where you are stuck.

summer mica
#

so ive got that 25/x+9=10/x

#

I believe thats right

rustic osprey
summer mica
#

and then you cross multiply i believe

rustic osprey
summer mica
#

But im confused on whats next

rustic osprey
#

$25x=10(x+9)$

potent lotusBOT
#

Civil Service Pigeon

rustic osprey
#

I would use the distributive property on the right hand side

summer mica
#

so 25x=10x+90

#

so 15x=90

#

so x= 6

#

using that info i can tell y is the mid segment

#

so y=20

#

and then would z be 25/10=z/20

#

so z/20 comes from y and then 25/10 comes from the sides

rustic osprey
#

What

#

Those sides don’t correspond with the similar triangles

#

25 and 10 are sides of the larger triangle, y is a side of the smaller triangle, and z is a side of the larger triangle

summer mica
#

thats how my math teacher explained the last one

rustic osprey
#

Uh

rustic osprey
#

20 and 25 correspond

#

y and z correspond

#

So 20/25 = y/z

#

Done

summer mica
#

on a previous question

rustic osprey
#

That’s what I did just now

#

😕

summer mica
#

16/12 is from the sides?

rustic osprey
#

Yeah

rustic osprey
#

16

rustic osprey
#

12

summer mica
#

So why can’t I use 25/10

#

5)-(/ from the sides

#

I meant that’s from the sides

rustic osprey
#

You need to set the ratio of the corresponding side lengths equal

#

As I said earlier, those side lengths don’t correspond.

summer mica
#

Wdym they don’t correspond

rustic osprey
#

They don’t “match up”

summer mica
#

I’m confused

rustic osprey
#

Here, AB and DE match up, as do AC and DF

#

And BC and EF

#

So we can set each of those ratios equal to each other

#

What we can’t say is something like AB/DE=AC/EF

#

Because while AB and DE correspond, AC and EF don’t

summer mica
#

Oh ok that makes more sense

#

How can I tell if they’re corresponding

rustic osprey
#

Look at the figure

#

They’re opposite the congruent angles

summer mica
#

Wouldn’t angle c angle b and angle a be confruent same for e f g

rustic osprey
#

??

#

We’re using the convention that same number of arcs -> congruent

#

Ex. Angles C and F are both marked with three arcs, hence they’re indicated to be congruent

summer mica
#

Like this

rustic osprey
#

Uh

summer mica
#

I can’t draw my hands are cold

rustic osprey
#

It looks like you drew a river pattern 💀

#

Just refer to the angles with the vertex names (ex. Angle ABF)

summer mica
#

This might be better

#

Those angles are congruent is what I’m saying

#

And the top one is a similar angle for all the triangles

rustic osprey
#

All I’m seeing is a creative interpretation of an ear 😭

rustic osprey
#

Also you got like 5 minutes before I gotta dip

#

So you’ve been warned

summer mica
#

So cbf is congruent to dce and bag

#

Same goes for other side

#

They all share the common angle of m<d

#

And y is parallel to bf and ag

rustic osprey
#

(and z, which is what I was implicitly using earlier)

summer mica
#

Z is bf

rustic osprey
#

Oh is it

#

Maybe I should stop using the marked up figure lol

summer mica
#

Oh I am to 😭

#

Oh I get it now on the first one the lengths are pairs but on the second one they’re not

#

So 25/20=z/ what would go on the denominator of z

#

Or 20/25 mb

rustic osprey
#

(Since 20 and y are part of the same triangle, DCE)

#

(And 25 and z are part of the same triangle, DBF)

summer mica
#

So z/25

#

So 20/25=z/25

rustic osprey
#

???

#

Where is z/25 coming from

summer mica
#

You said z and 25 are same triangle

rustic osprey
#

Ok let me rephrase

#

You can’t mix and match

#

20/25 is taking the ratio of a side of DCE to the corresponding side of DBF

#

So you need to do the same for your second proportion

summer mica
#

So z/10?

rustic osprey
#

Do z and 10 correspond?

#

Also they’re both part of BDF

#

So that has the same issue as I just said (namely that if one proportion is taking the ratio of the sides between the two triangles, so must the second)

summer mica
#

What would z denominator be then

rustic osprey
#

Since you put the side for DBF in the denominator for the first proportion, z should be in the denominator, not the numerator.

#

But work with what I’ve been saying

summer mica
#

Oh ok

rustic osprey
#

Your numerator in the first proportion was the side corresponding to BD in triangle DCE

#

The same exact logic applies.

summer mica
#

Oh so would it be 5?

rustic osprey
#

??

summer mica
#

Or no

rustic osprey
#

Remember what I said earlier about corresponding sides and angles

#

What angle is side z opposite to (in triangle DBF)

summer mica
#

It would be 20?

#

Z is in the middle

rustic osprey
#

That’s not an angle.

summer mica
#

Ik

#

I’m asking if the numerator would be 20

rustic osprey
#

No

summer mica
#

Oh

#

Side z’d angle would be opposite to angle d right?

rustic osprey
#

Yes

#

So what angle must the corresponding side in triangle DCE be opposite to

summer mica
#

Dec?

rustic osprey
summer mica
#

There’s no other angler

#

Angles

#

In triangle dce

rustic osprey
#

My point earlier (and now) is that the corresponding sides are opposite the same angle.

#

So since z is opposite angle D, the corresponding side in triangle DCE is also opposite angle D.

summer mica
#

Than I don’t get what’s opposite of dce

#

Angle

rustic osprey
#

Mate.

rustic osprey
#

(That’s an arrow btw - ik the pointing part looks kinda flat)

summer mica
#

Yea d is opposite of angle 180

rustic osprey
summer mica
#

Yea

rustic osprey
#

That’s all I was asking for this whole time

rustic osprey
summer mica
#

I’ve got to go temporarily

calm coralBOT
#

@summer mica Has your question been resolved?

calm coralBOT
#
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calm coralBOT
#
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spare kettle
#

What's the difference between all of these distributions?

calm coralBOT
#

Please don't occupy multiple help channels.

bleak peak
#

you see the normal distribution has a 'bell shape'

#

For the uniform one, in terminology, the standard derivation would be very small

#

The mean of the skewed left one is very close to the maximum value of x and vice versa for the skewed right

calm coralBOT
#

@spare kettle Has your question been resolved?

calm coralBOT
#
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calm coralBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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remote mural
calm coralBOT
remote mural
#

Im just asking for g(x) how am i supposed to factorise it

#

i tried x(2x^2 - x) but then i dont know how to factorise whats inside the brackets

#

i mean i can do x(2x-1) but what do i do with the second x

remote mural
#

then i just get x^2 = 0

eternal shard
#

2x³-x² = 2x(x²)-1(x²)

eternal shard
#

you want to factorize

#

you look for the gcd in each term

remote mural
#

sorry let me try to explain why im confused i input the equation into desmos and i get 3 points

eternal shard
#

you mean 3 roots?

remote mural
#

Yeah

#

no not 3 roots

#

3 points

eternal shard
#

the in between is not a root

#

yes

remote mural
#

why would they show me it

eternal shard
#

x²(2x-1) = 0

remote mural
#

okay thank you

eternal shard
#

and y = x²(2x-1)

#

y = x²(2x-1) shows you all points that satisfy this equation

#

which resembles that curve

#

x²(2x-1) = 0 this gives you the solutions of x-intercepts which are two roots (one double)

remote mural
#

ohhh thats why

#

okay thanks

#

.close

calm coralBOT
#
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calm coralBOT
#
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frank jungle
calm coralBOT
frank jungle
#

I've taken trivial examples in my head so I think it's true

#

But Im not sure how to prove it

old falcon
#

thonk i think you need more here

#

right

frank jungle
#

Wdym?

old falcon
#

like if W1 = W2

frank jungle
#

It kind of makes intuitive sense right

old falcon
#

but B1 != B2

frank jungle
#

Hmm

#

Counter example?

#

😂

old falcon
#

i mean can you think of one

frank jungle
#

I mean that's literally it right

old falcon
#

try to think of a subspace with 2 possible bases

#

not super hard

frank jungle
#

Let W_1 = W_2 = R

old falcon
#

simpler lol

frank jungle
#

and B_1 = {1} and B_2 = {2}

old falcon
#

but sure yea

#

thats what i was thinking

#

so youd need some kind of qualification i think on the basis

frank jungle
#

I'll clarify it with my teacher

old falcon
#

in order to make this true

#

but clearly as written not true

frank jungle
#

Thank you for your help!

#

.close

calm coralBOT
#
Channel closed

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calm coralBOT
#
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• Be polite and have a nice day!

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lost elm
#

In how many ways can you arrange the word "HONULULU" (the spelling is intentionally made incorrect such that it has 3U's) so that no 2 Ls and no 2Us are together

lost elm
bronze adder
lost elm
#

I dont think there are 2760 cases(above 50%)in which the condition might be true, and i do not understand where i have went wrong

bronze adder
#

generating function?

lost elm
bronze adder
#

nvm

#

you're manually counting the cases up?

next mesa
#

hey

#

what kind of this question

lost elm
#

atleast I wouldve

#

but idk how to reliably count that much with less innaccuracy'

lost elm
#

also is there a reliable computer program to list and eliminate all cases for a given word so that you can check urself if what the anser u got is correct

calm coralBOT
#

@lost elm Has your question been resolved?

magic tulip
#

but LU is not?

lost elm
magic tulip
#

,w \frac{8!}{3!2!} - \frac{3 \cdot 7!}{2!} - \frac{7!}{3!} + 3 \cdot 6!

potent lotusBOT
calm coralBOT
#

@lost elm Has your question been resolved?

calm coralBOT
#

@lost elm Has your question been resolved?

calm coralBOT
#
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calm coralBOT
#
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wheat wyvern
calm coralBOT
wheat wyvern
#

I first made the triangle

#

Then did trig sub

#

.close

calm coralBOT
#
Channel closed

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potent igloo
calm coralBOT
#
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next fossil
#

Hi

calm coralBOT
next fossil
#

Have not learned trig inverses properly, can someone help me

eternal shard
potent lotusBOT
remote mural
# next fossil

What are you trying to do with this equation? Send the full problem?

next fossil
#

Derivative

#

I further simplified to 8x/ (8x^2)(root8x^2 -1)

#

Ye

#

How

#

Conjugate it?

#

Or do you multiple the denominators

#

The 2 should just be for the radical inside

#

Ik I wrote it wrong but I did it right

#

The arrow is pointing at what I’m on

#

So left with 1/xroot8x^2 -1

#

Ah I see

#

Got one more

#

Do I have to do both derivatives separately

dull wagon
#

wdym by separately

next fossil
#

So then idk how to take the inverse of 2x

#

I know trig inverses derivatives

#

I haven’t learned actual inverse derivatives

dull wagon
#

the idea is that you don't need to explicitly find the inverse function

next fossil
dull wagon
#

apply the formula given to you, (its a good exercise to derive or look up where it comes from)
plug x=1 into that

next fossil
#

2 - sin(x)

#

2 - sin(1)

dull wagon
#

not what i asked you to do

next fossil
#

What am I supposed to do

dull wagon
#

apply the formula given to you, (its a good exercise to derive or look up where it comes from)
plug x=1 into that

#

you're given a formula for derivative of an inverse function
(f^-1)'(x) = ...

#

start by plugging x=1 into that

next fossil
#

Idk how to do that

dull wagon
#

literally replace all x in that with 1

next fossil
#

From what I can’t even take the derivative of the inverse tho

dull wagon
#

you're literally given the formula for it

next fossil
#

I literally have not learned how to do it

dull wagon
#

don't overthink this first step

#

$(f^{-1})'(\red{x}) = \frac{1}{f'(f^{-1}(\red{x}))} \ \
(f^{-1})'(\red{1}) = \ ?$

potent lotusBOT
#

ℝαμOmeganato5

next fossil
#

What id do is like take y = 2x flip it so it’s x= 2y and have y = 1/2x and take the derivative of that

dull wagon
#

no

#

you can't ignore the cos(x)

#

and as i've said before, do not make any attempt to find f^-1(x) itself

#

its not needed and quite complex

next fossil
#

So what would my first step be

dull wagon
#

please read what i've said above

next fossil
#

I have been but it doesn’t make sense

#

I need to see it happening I can’t understand just from words

#

Just a first step

dull wagon
#

if you were given
g(x) = x + 7
how would you find
g(8)

next fossil
#

Plug 8 as x

dull wagon
#

yes

#

same idea here

next fossil
#

So do I just do 2(1) + cos(1)

#

??

dull wagon
#

you are given the formula for
(f^-1)'(x)
and you want to know
(f^-1)'(1)

#

no

#

forget about the rest of the question and focus on only that

next fossil
#

Yes

wheat wyvern
dull wagon
#

same idea as

if you were given
g(x) = x + 7
how would you find
g(8)

wheat wyvern
#

🏃 sorry to interrupt carry on

next fossil
#

But I haven’t learned any of the steps of how to take undersea derivatives

dull wagon
#

undersea?

next fossil
#

Plug 8 in and get g(8) = 15

dull wagon
#

exact same idea here

next fossil
#

So what do I plug 1 into

dull wagon
#

you're given the formula for
(f^{-1})'(x) right?

next fossil
#

IDK HOW TO USE THE FORMULA atleast tell him how to apply the equation into the formula

dull wagon
#

use it the same way you used

if you were given
g(x) = x + 7
how would you find
g(8)

#

you wanted to know
g(some specific value)
replace all x in your given equation with that value

next fossil
#

Bro please is there any other way you can explain this

#

I’m not understand this way

#

Like show me what the first step is instead it’ll make more sense to me that way

#

The theory I’ll understand from the application and the steps

dull wagon
#

this is simply evaluting functions at a value in general

next fossil
#

Rather than learning the theory first

dull wagon
#

please don't overthink this

#

do the same thing you did

Plug 8 in and get g(8) = 15

#

exact same idea applies

next fossil
#

Are you saying make 2x + cosx = 1

dull wagon
#

no

#

forget about f(x)

#

Plug 8 in and get g(8) = 15
you replaced all x in the equation with 8 to achieve that

#

the same applies here, replace all $x$ in the equation with 1
$$(f^{-1})'(\red{x}) = \frac{1}{f'(f^{-1}(\red{x}))}$$
$$(f^{-1})'(\red{1}) = \ ?$$

potent lotusBOT
#

ℝαμOmeganato5

dull wagon
#

don't worry about anything else at this stage

#

more steps will come after

next fossil
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1/f prime (f inverse at 1)

dull wagon
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yes

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good

next fossil
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Okay

dull wagon
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$$(f^{-1})'(1) = \frac{1}{f'(\blue{f^{-1}(1)})}$$

potent lotusBOT
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ℝαμOmeganato5