#help-42
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like a chain
and like
you had n = k and n = k+1 now you flip the succesor n = k+2
Ohhhhhhhhhhhh
Very good explanation
Ok understood
Can u help me w one more
By the way thanks a lot I actually get it
okk
yes
what are your thoughts on approaching this
We just do the same thing which is a base case
N=1
And then we assume for n=k that like it is divisible by 16
Yes the result gives 112 and we can factorise the 16 out to show that it is true
So 16(7)
Yessssssss
Yes
,, f(n+1) = 5^{(n+1)+2}-4(n+1)+9 = 5^{n+3}-4n+5
this is what we wanna show now
no
so we basically want to show this
using the assumption that f(n) is divisible
Is it f(n+1) - f(n) bc if both r divisible by 16 then subtracted would be divisible too
Try to factorise 16 out
Why can’t I prove it this way
My try would be to use the assumption instantly like we know that f(n) is divisble by 16 which means f(n) is some multiple of 16
like
f(n) = 16m for some m
Yepppo
now we need a -4n and a 9
so we can write -20n as a difference that has -4n
same with 45
we can write 45 as a sum of two numbers where one is 9
can u do that
-4n-16n + 9 + 36
ooooooooooooooooooooooooooooooooooooooooooooooooooooooo
Omg
now let's bring 36 and 16n to the other side
winnie what can you conclude
Idk bc -36 cannot be factorised
😅
5x16m + 16(n+1)-48
😭
but uhm
5+40
yea 40 is also not good
+9 not -9
I didn’t even see that
Ok!!!
Is it n+3
we make it multiplying by 5
Keep in mind
Omg yes
5^n+3-20n-45 = 5x16m
How do you type so fast?
Is this the same for all divisibikity rule questions
yesss
if something is divisible by some number
then you can write it as a multiple of that number
f(n) divisible by x means f(n) = xm where m is an integer
Ohhhhhhhhhhhh
Omg yes
I will try this for other questions tomorrow
By the way thanks sm u spent so much brainpower and time
If I have questions can I dm u 🥲 but not frequent or else I’m gonna disturb too much
it's easier to help u with the texit bot here, so i would prefer to help you on the server instead 
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i have a question
19c
k = 2 btw
i get all these seperate cases
case 1, the cdf is always 0
case 2 we can integrate with the given bounds
but i dont really understand case 3 (and case 4, but they look pretty symmetrical)
why do we fill in F(x,y) with y = 1 is my question
F(x,y) is the probability P(X<x,Y<y). but thats the same as P(X<x,Y<1) cause Y>1 has prob 0
@junior zodiac Has your question been resolved?
oh right thank you
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what do they mean actual value?
do we just make another estimate with more subdivisions and call that the actual value?
just pick an arbitrary increasing function that goes through the same points
just draw it on paper
the picture will give away the estimates being under or over
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hello
but its the wrong answer
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
we are the same person
sorry that is just my ipad discord
oh naur
it says in the solutions
that the leftmost x value should be 0
but i dont know how to get that
help
lemme think
i think i remember my professor saying that i cant have a function as bounds for my outer integral
wait a sec
The given bound x=arcsin(y) can be written as y=sin x
since
x ranges from
arcsin(0) = 0 to pi/2
but in the original equation it’s the area under arcsin
oh wait is it not?
i might have misinterpreted
who are you know?
i am hi sorry
aah same guy , my bad
it’s okay lol!
wait i’m pretty sure it’s the bound underneath the curve because in the original equation it says the arcsin graph is the leftmost bound
what book are you using for multivar calc
oh these were just problems my professor wrote down for us to solve
i don’t think she’s got them from the book but i use multivariable calc 8th ed
mc
Since x= arcsin(y) was the lower bound in the original integral, this means that y starts at sin(x) where we can wite in term of x
Stewart?
mcgraw*
originally, x starts at arcsin(y) meaning for a fixed y, we must solve for the corresponding lower x value
bruh.... are you good at Binomial?
not good
i'm cooked
i’m trying to ponder at this
this is the answer im sorry i should have posted this earlier
but it looks like she forgot to switch the dx dy
soo... my answer isn't correct?
i shall ask chatgpt
wait
how did you get the 0 to pi/2
you could be right, there were a lot of errors in the solutions manual
bruh, you also did the same thing.. don'tchu know that?
no i got this answer 😭
ig you should get some rest for now
get some sleep
wouldn’t the x left most x bound depend on the function?
it’s only 7pm for me, but i will let you go
what is your chess elo
2308
UH HUH
whats yours?
@tame quail wants to play
damn
i’d rather not disclose 😔
that's high
that’s IM level. you’re crazy good
ohk.... but i'm not currently loggin in this device... soo if you got some opensource chess website... i'm in send me link
aw i was hoping you could do a quick game
you would probably crush me though
lemme make some arrangements
how about, i play without my queen?
well I would win then
I'm like 1500 USCF
let see.... time will tell
choose one.... bad opening or without queen?
anyway I can't play right now unfortunately
depends on how bad the opening is
in some openings you lose your queen
so
Halloween Gambit
do any of you big brain chess players know why the left bound doesn’t depend on the function
that's not as bad as being down a queen
because that's the upper bound
yeah
a4 Ra3 capure my rook with your bishop.... i'll take that ith knoght then... same goes for h1 side
oh that really just cleared all my questions
that's not even that bad lol
damn
you get more development and arguably the bishop pair is better in the opening/middle game
exachange rooks with bishop... that aint bad?
no
being down a piece is significantly worse than down an exchange
that’s what the 11 year old kid i’d babysit used to play
soo... tell me what should i play
not to mention down a queen
I would just take the queen honestly lol
ohk... i'll give you my queen in few moves...
cow opening 😏
wanna play as white.... I LITERALLY GAVE YOU MY QUEEN
under what conditions?
i'll play as white...
when will this tournament take place
fuck
you in for chess?
ohk... same goes for you... take my queen
so uh maybe a worse opponent for you
thats actully good
i'm dead for real then... 5min blitz
ohk ohk
where do you want to play
let’s go!
wait i’m getting nervous knowing you’re 2300
I MESSED UP
IM OUT FOR YOUR CLOCK BUDDY
that was a good game
i liked your strategy not letting me take any pieces
being down a whole queen is just too unfair i think
oh did you want white?
i should have grinded more
okay
only the queen at first
are you sure?
then you can take as much as pawns you want
close this channel move to #chess-go-shogi
after you get the queen
i could trade the queen for 2 bishops
nah... no trading... full sacrifice... lmao
get back to game
@cloud gyro Has your question been resolved?
lets do one proper
uh i think it’s lost 😞
good game
you destroyed me
it’s back to studying for me.
i think so
hats the time there?
and the help with my math
whats*
it’s 7:30pm
good morning
i'm not sleeepy
plz... let me stay
hehe
YOU NEED TO SLEEP
i'm find dude... i woke up at 4
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goodbye friend!
whats your age?
im 19
damn... same
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hi guys
I've been looking for an hour to figure out how to solve this operation without giving me a coherent result.
(It's not for me, it's for my sister who is in third grade and goes to high school)
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Help
!occupied
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@hardy sail Has your question been resolved?
@hardy sail Has your question been resolved?
@hardy sail Has your question been resolved?
are you trying to solve for x or just rearrange?
since this is just an expression
doesn't seem to equal anything
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Okay so for c
Ik how to find reflections and stretches
How do I find the verticle and horizontal translations?
Like how many units it moved up/down and left/right
Do I need to draw out the stretch first?
Or how tf
<@&286206848099549185>
@stable hollow Has your question been resolved?
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yeah
use a slash for fractions. (x+2)/4
also lowercase x not uppercase X, careful w/ that
otherwise yes f^-1(x) = (x+2)/4
Then what
well you have yourself a formula for the inverse now
all that's left to do is to find its values at the points they want
(X+2)/4 = 4
So solve for x?
Is this written correctly?
Idk
Can someone just tell me
I should've been sleeping 5 hours ago 😭
(4+2)/4 = 4
This?
when you say f(3), what is 3? what does it represent
(4+2)/4 isn't equal to 4
f^-1(4) = (4+2)/4 = what you want
please do not call me bro.
Question 15a).
You want the inverse when x is 4
Idk
you asked to show what needs to be done, i showed you what needs to be done
if you are deliberately depriving yourself of sleep this is only your problem but not ours
What is $\frac{4+2}{4}$.
Omega
I wasn't planning on needing to do a bunch of stuff and not being able to sifsy
Study
$f^{-1}(x) = \frac{x+2}{4}$.
f^{-1}
Omega
(x+2)/4
So for this example
You plug in whatever you want to find
Into x
And whatever it = is the answer
No, they give you x. Just calculate the value.
Exactly.
You're welcome, and be sure to get enough sleep.
Yeah
Well
I'm waking up in Leeds than 6 hours
Normaly I get 6.5-7 before tests and do fine
This might be bad though
definitely very bad
Alright, bye!
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Oh, I see.
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Is the question asking to simplify?
@south obsidian
Yes
Wait a minute. If the question is asking to simplify, there wouldn't be two sides to the equation.
Oh, it's asking to solve for x.
OK, question 2b, right?
Yesyes
I did the whole exercise but my teacher got a different result from mine and I asked chat got but now I'm confused so I just need you to tell me if I did it right
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
How did you do it?
Take your time, no worries.
Here is
And what was the result your teacher got?
-1/3
Let's see if we can recreate your teacher's result.
$$\frac{1}{2}(\frac{10}{3}x-\frac{2}{9})-\frac{1}{3}=\frac{7}{3}x$$
$$\frac{10}{6}x-\frac{2}{18}-\frac{1}{3}=\frac{7}{3}x$$
Omega
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Try redoing the question until you get it. Sorry I can't help you...
.reopen
✅
Its okay
.close
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how do I show A is orthogonal and that A can be chosen s.t. det(A) = 1
i can only show that det(A) = ±1
Hey
I gave you an answer yesterday and you said A is supposed to be a matrix
Well the answer I gave you IS a matrix
Just try the product will you ?
is there a way to continue from here though
How do you show a matrix is orthogonal
Try this
yeah but i can't figure out how to do the multiplication
Just write it and I’ll tell you
what do you mean?
ok sure
[v]_B is a column vector on its own (coordinates of v in the standard basis)
no that's not what i was talking about
this is a different matrix i came up with
it does but i had already worked out this much so it would be nice if there's a way to continue on from there
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im confused on how ther side splitter works
Show your work, and if possible, explain where you are stuck.
Put parentheses around your first denominator, but yes
and then you cross multiply i believe
Yeah you can do that
But im confused on whats next
$25x=10(x+9)$
Civil Service Pigeon
I would use the distributive property on the right hand side
so 25x=10x+90
so 15x=90
so x= 6
using that info i can tell y is the mid segment
so y=20
and then would z be 25/10=z/20
so z/20 comes from y and then 25/10 comes from the sides
What
Those sides don’t correspond with the similar triangles
25 and 10 are sides of the larger triangle, y is a side of the smaller triangle, and z is a side of the larger triangle
thats how my math teacher explained the last one
Uh
16/12 is from the sides?
Yeah
.
You need to set the ratio of the corresponding side lengths equal
As I said earlier, those side lengths don’t correspond.
Wdym they don’t correspond
They don’t “match up”
I’m confused
Here, AB and DE match up, as do AC and DF
And BC and EF
So we can set each of those ratios equal to each other
What we can’t say is something like AB/DE=AC/EF
Because while AB and DE correspond, AC and EF don’t
Wouldn’t angle c angle b and angle a be confruent same for e f g
??
We’re using the convention that same number of arcs -> congruent
Ex. Angles C and F are both marked with three arcs, hence they’re indicated to be congruent
Uh
I can’t draw my hands are cold
It looks like you drew a river pattern 💀
Just refer to the angles with the vertex names (ex. Angle ABF)
This might be better
Those angles are congruent is what I’m saying
And the top one is a similar angle for all the triangles
All I’m seeing is a creative interpretation of an ear 😭
.
Also you got like 5 minutes before I gotta dip
So you’ve been warned
So cbf is congruent to dce and bag
Same goes for other side
They all share the common angle of m<d
And y is parallel to bf and ag
(and z, which is what I was implicitly using earlier)
Z is bf
Oh I am to 😭
Oh I get it now on the first one the lengths are pairs but on the second one they’re not
So 25/20=z/ what would go on the denominator of z
Or 20/25 mb
.
(Since 20 and y are part of the same triangle, DCE)
(And 25 and z are part of the same triangle, DBF)
You said z and 25 are same triangle
Ok let me rephrase
You can’t mix and match
20/25 is taking the ratio of a side of DCE to the corresponding side of DBF
So you need to do the same for your second proportion
So z/10?
Do z and 10 correspond?
Also they’re both part of BDF
So that has the same issue as I just said (namely that if one proportion is taking the ratio of the sides between the two triangles, so must the second)
What would z denominator be then
Since you put the side for DBF in the denominator for the first proportion, z should be in the denominator, not the numerator.
But work with what I’ve been saying
Oh ok
Your numerator in the first proportion was the side corresponding to BD in triangle DCE
The same exact logic applies.
Oh so would it be 5?
??
Or no
Remember what I said earlier about corresponding sides and angles
What angle is side z opposite to (in triangle DBF)
That’s not an angle.
No
Dec?
.
My point earlier (and now) is that the corresponding sides are opposite the same angle.
So since z is opposite angle D, the corresponding side in triangle DCE is also opposite angle D.
Mate.
Yea d is opposite of angle 180
So hence y is your corresponding side
Yea
That’s all I was asking for this whole time
And as a result, you get this ^
I’ve got to go temporarily
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What's the difference between all of these distributions?
Please don't occupy multiple help channels.
you see the normal distribution has a 'bell shape'
For the uniform one, in terminology, the standard derivation would be very small
The mean of the skewed left one is very close to the maximum value of x and vice versa for the skewed right
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Im just asking for g(x) how am i supposed to factorise it
i tried x(2x^2 - x) but then i dont know how to factorise whats inside the brackets
i mean i can do x(2x-1) but what do i do with the second x
why not x^2
then i just get x^2 = 0
2x³-x² = 2x(x²)-1(x²)
what is that supposed to argue
you want to factorize
you look for the gcd in each term
sorry let me try to explain why im confused i input the equation into desmos and i get 3 points
you mean 3 roots?
why would they show me it
x²(2x-1) = 0
okay thank you
and y = x²(2x-1)
y = x²(2x-1) shows you all points that satisfy this equation
which resembles that curve
x²(2x-1) = 0 this gives you the solutions of x-intercepts which are two roots (one double)
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I've taken trivial examples in my head so I think it's true
But Im not sure how to prove it
Wdym?
like if W1 = W2
It kind of makes intuitive sense right
but B1 != B2
i mean can you think of one
I mean that's literally it right
Let W_1 = W_2 = R
simpler lol
and B_1 = {1} and B_2 = {2}
but sure yea
thats what i was thinking
so youd need some kind of qualification i think on the basis
I'll clarify it with my teacher
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In how many ways can you arrange the word "HONULULU" (the spelling is intentionally made incorrect such that it has 3U's) so that no 2 Ls and no 2Us are together

I dont think there are 2760 cases(above 50%)in which the condition might be true, and i do not understand where i have went wrong
generating function?
what
no
atleast I wouldve
but idk how to reliably count that much with less innaccuracy'
permutaions and combinations
also is there a reliable computer program to list and eliminate all cases for a given word so that you can check urself if what the anser u got is correct
@lost elm Has your question been resolved?
that is to say, LL and UU are forbidden
but LU is not?
yes LU is permitted
,w \frac{8!}{3!2!} - \frac{3 \cdot 7!}{2!} - \frac{7!}{3!} + 3 \cdot 6!
@lost elm Has your question been resolved?
@lost elm Has your question been resolved?
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Your sin/cos^2 integral is wrong
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Hi
,rcw
What are you trying to do with this equation? Send the full problem?
Derivative
I further simplified to 8x/ (8x^2)(root8x^2 -1)
Ye
How
Conjugate it?
Or do you multiple the denominators
The 2 should just be for the radical inside
Ik I wrote it wrong but I did it right
The arrow is pointing at what I’m on
So left with 1/xroot8x^2 -1
Ah I see
Got one more
Do I have to do both derivatives separately
wdym by separately
So then idk how to take the inverse of 2x
I know trig inverses derivatives
I haven’t learned actual inverse derivatives
the idea is that you don't need to explicitly find the inverse function
apply the formula given to you, (its a good exercise to derive or look up where it comes from)
plug x=1 into that
not what i asked you to do
What am I supposed to do
apply the formula given to you, (its a good exercise to derive or look up where it comes from)
plug x=1 into that
you're given a formula for derivative of an inverse function
(f^-1)'(x) = ...
start by plugging x=1 into that
Idk how to do that
literally replace all x in that with 1
From what I can’t even take the derivative of the inverse tho
you're literally given the formula for it
I literally have not learned how to do it
don't overthink this first step
$(f^{-1})'(\red{x}) = \frac{1}{f'(f^{-1}(\red{x}))} \ \
(f^{-1})'(\red{1}) = \ ?$
ℝαμOmeganato5
What id do is like take y = 2x flip it so it’s x= 2y and have y = 1/2x and take the derivative of that
no
you can't ignore the cos(x)
and as i've said before, do not make any attempt to find f^-1(x) itself
its not needed and quite complex
So what would my first step be
please read what i've said above
I have been but it doesn’t make sense
I need to see it happening I can’t understand just from words
Just a first step
if you were given
g(x) = x + 7
how would you find
g(8)
Plug 8 as x
you are given the formula for
(f^-1)'(x)
and you want to know
(f^-1)'(1)
no
forget about the rest of the question and focus on only that
Yes
thank you!!
same idea as
if you were given
g(x) = x + 7
how would you find
g(8)
🏃 sorry to interrupt carry on
But I haven’t learned any of the steps of how to take undersea derivatives
undersea?
Plug 8 in and get g(8) = 15
exact same idea here
So what do I plug 1 into
you're given the formula for
(f^{-1})'(x) right?
IDK HOW TO USE THE FORMULA atleast tell him how to apply the equation into the formula
use it the same way you used
if you were given
g(x) = x + 7
how would you find
g(8)
you wanted to know
g(some specific value)
replace all x in your given equation with that value
Bro please is there any other way you can explain this
I’m not understand this way
Like show me what the first step is instead it’ll make more sense to me that way
The theory I’ll understand from the application and the steps
this is simply evaluting functions at a value in general
Rather than learning the theory first
please don't overthink this
do the same thing you did
Plug 8 in and get g(8) = 15
exact same idea applies
Are you saying make 2x + cosx = 1
no
forget about f(x)
Plug 8 in and get g(8) = 15
you replaced all x in the equation with 8 to achieve that
the same applies here, replace all $x$ in the equation with 1
$$(f^{-1})'(\red{x}) = \frac{1}{f'(f^{-1}(\red{x}))}$$
$$(f^{-1})'(\red{1}) = \ ?$$
ℝαμOmeganato5
1/f prime (f inverse at 1)
Okay
$$(f^{-1})'(1) = \frac{1}{f'(\blue{f^{-1}(1)})}$$
ℝαμOmeganato5


i think you need more here