#help-42
1 messages · Page 29 of 1
$x\in(-\infty,-1]U[0,3]$
what you wrote: $$x \in (-\infty, -1) \cup (0, 3)$$
Haylsune Miku
excludes the value of -1
oh ri ght
cmon, use \in at least
cool
lol no i mean
instead of e
which is a letter
use \in which is the set includes symbol
\textbackslash{}in $\in$ \
\textbackslash{}infty $\infty$
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hey, can someone explain what the image and rank of f are, please?
i get what a monomorphism and an epimorphism is
but how would i prove that f is either??
also, how can Imf = W when Imf is a subset of W
or subspace??
subset also contains the "the two sets are equal" case usually
V is a subspace of V for example
it's useless to say but it's true
huh
did you solve the previous parts then ?
yh, i've done (i), i've found the kerf, the null is the same as the kernel
oh, i needa find the dimension?! 😩
the basis for the kerf is (0,0) which confirms it defo maps to the zeroth vector
the zero vector can't be part of any basis
cause that screws up linear independence
oh right
you can take it as a definition if you want, dimension of the 0 space is 0
(there are technical reasons for that to work)
i'm kinda struggling to visualise this whole vector space stuff. i learn better when i can imagine what i'm working with. like when we worked with mapping functions in the real space, that's pretty much minecraft but labelled correctly. aghghghghgh
oki
so null(f) = dimkerf = 0. is this always true coz kerf has to map to the zeroth vector??
if x is a vector in ker f, that means f(x) = 0
what dim(ker f) = 0 means is that, if f(x)=0 then x has to be the zero vector
welcome to lin alg, precise language is important here
it is a subspace of the input space of f yes
oh ok
okay, i got that for the most part. what's an image? the notes say it's all the possible output vectors
output vectors from V to W??
oh-
from the diagram, W has Imf and the zeroth vector, are those outputs??
yes they are the outputs from f
the zero vector is inside Imf indeed
cause you always have f(0_V) = 0_W [the subscripts are just to say in what space these objects are], whatever the linear transformation f you have
f is the transformation
f(0_V) is the result of when you give 0_V as an input to f
and that result is a vector in W
since the transformation f goes from V to W
ohhh
wait, the Imf which is the output is just what was spat out -> (a_1 + a_2, 0, 2a_1 - a_2) and its basis would be the coefficients i think (1, 0, 2)
no?
(╯°□°)╯︵ ┻━┻
yh
it consists of all the vectors f(x) for some x in V
yh
i now understand that
alright
do you know of any yt vid that explains this thoroughly?
https://www.youtube.com/watch?v=fNk_zzaMoSs&list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab if you want something with intuition
Beginning the linear algebra series with the basics.
Help fund future projects: https://www.patreon.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Home page: https://www.3blue1brown.com/
Correction: 6:52, the screen should show [x1, y1] + [x2, y2] = [x1+x2, y1+y2]
Full series: http://3b1b.co/eola
Fu...
https://ocw.mit.edu/courses/18-06-linear-algebra-spring-2010/ if your linalg classes suck and you want to see the clasees from a guy from MIT
thank you 🫡
finish, i can watch the vids at a later time
okay, i asked my course mate for some more help and looked at the notes again, at the rank-nullity thm formula
"dimkerf + dimImf = dimV"
yep
my friend subbed in the standard bases for R^2 -> (1,0) and (0,1) into the thingy on the right hand side
i've done that too
to get a basis of the image yeah that's fine
"(0,0,-1)" you mean (1,0,-1)
no no
(a_1 + a_2, 0, 2a_1 - a_2). sub in (0,1), a_1 as --
yes i have 🤦♂️
yh (1,0,-1)
then its dimension would be the number of vectors in the basis
which is 2 here
so slay
yeah be careful there's no linear dependencies in here
in this scenario R^2 -> R^3 there's no problem
if you go from the bigger space to the smaller space you'll have issues like that
so dim ker f is 0, dim im f = 2 then
okay, last one. monomorphic or epimorphic? or both? 🤨
yep
monomorphism is an injective linear transformation
points in vector space V would map to at most one point in vector space W
from my understanding of it
and then epimorphism is just surjection
yes
and yes
let's think about epi first cause it's easier
we have dim im f = 2, does that tell you anything about surjectivity of f ?
what's the dimension of the output space R^3 ?
so do you think im f = R^3 then ?
that's what it means for the transformation to be surjective
being able to access every output from one input by f
yeah I guess I'll let you reread your notes then
[resending so i don't have to scroll up]
the question should be very easy to answer when you know nullity and rank of f
okay, hold on
I gtg quite soon though
indeed
so ours is monomorphic
but why and how
they didn't show you the proof or what
i haven't read it, it's a paragraph. but i will do so now
thanks a lot
i don't wanna keep you longer :p
g'night
night ^^
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isnt it supposed to be dv=6e^6xdx?
How are we supposed to know if you don't give us the original question?
wow
Though I'm guessing it's
good guess
$\int x \cdot e^{6x} \dd x$
RedstonePlayz09
yee
:moyai
.
ye why
I mean, why yes?
There is no 6 in the integral.
You choose one part to be u, and the other to be dv
In this case we chose u = x and dv = e^(6x)dx
arent you supposed to apply exponential function rule?
Sorry I don't understand what you mean
Ok, but we aren't differentiating e^(6x)
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can someone check my answer for the new equation, i usually mess up plugging it in and putting the wrong parantheses. and if you can show me the step by step process
@tired wasp Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
@tired wasp Has your question been resolved?

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why are these different?
i used laplace transform to obtain the expression
but wolfram alpha gives another solution that (seems) not the same
both also give sin2t
@azure willow Has your question been resolved?
huh
taking the second derivative of them + them = sin2t, no?
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how many boolean functions of f(x,y,z) with 3 variables x,y,z where the following conditions apply: f(0,0,0) = 0, f(0,0,1) != f(0,1,0) and f(1,0,0) <= f(1,1,1) exists? with != i mean not equal
I understand that you have to divide the problem in 2 cases, one where f(1,0,0) is equal to f(1,1,1) and other where f(1,0,0)<f(1,1,1) but I don't really know how to solve it from there.
<@&286206848099549185>
@dim glade Has your question been resolved?
there are three cases rather, they are equal because both 1, or they are equal because both 0
or f(1,0,0)<f(1,1,1)
then you have 2 cases for f(0,0,1) != f(0,1,0)
3 Fs remain free, so 2 cases three times, and that's the solution
@dim glade Has your question been resolved?
So 2^5+2^4 where 2^5 is the amount when equal and 2^4 when f(1,0,0) = 0 & f(1,1,1) = 1?
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how do i find orthocentre if i dont dont know the angles of the triangle
,,\triangle
🚗
Is there a specific problem ur working on
yes
the midpoint of the sides of a traingle are 5,0 5,12 and 0,12. find orthocentre
i have finded the vertexes of this triangle
but cant move further
Oh well from this triangle it's not too bad, pythagorean theorem shows it's a right triangle
the answer should be 0,0 then
how do you know its a right angles triangle?, like you calculated it fast i suppose, was there a trick you used?
well 5-12-13 is a pythagorean triple
you calculated thier distance first that means
Well in this instance I didn't have to cus I just saw the 5's and the 12's and recognized it as a part of a common set of integer triples which satisfy a^2 + b^2 = c^2
Another rly common one is 3-4-5
ah yea got it, thanks 992qqoloy, i suppose thats your real name
Yeah lol
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Could someone teach me how to do this question?
everg
now to satisfy b search a,b real number such that $af(x)+b$ satisfy b
clear ?
now to satisfy b search a,b real number such that $af(x)+b$ satisfy b
everg
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can someone help me with this question?
ok holup
sinAcosB + 48/65
Sina is 3/5
what rule is that
Pog
Pythagorean theorem
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
👍👍
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You can hint to them about pythagorean theorem, not do it for them
Okay sir
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i am confused where the y prime comes from, I agree with everything else there from the product rule but where does a y prime come from
@tribal idol Has your question been resolved?
<@&286206848099549185>
so you are saying that the chain rule must also be applied within the product rule?
The product rule requires you to differentiate e^y
Which gives e^y * y'
So yes
Also why is there a minus over there
Unless I'm not seeing the whole question where this somehow makes sense
ye it should be a plus
and like
if you have y^3
would you have to do the same thing then
like im thinking the derivative is jus 3y^2
It isn't
If y is a function of x, and you're taking the derivative with respect to x
You also need to multiply by the derivative of y
For example if y was x^2
Would you say the derivative of (x^2)^3 is 3(x^2)^2?
(It isn't)
It's 3(x^2)^2 * 2x
(Of course you can just simplify it to x^6 and then take the derivative normally)
well this would be the chain rule, how am I meant to apply the chain rule to one variable tho (y)
for example
in this case, there is only one term (y)
in your case, there were 2 terms (x^2)
You know y is a function of x
You can think of it as if y is some expression involving x, but we don't know what
And you want to take the derivative of that expression, cubed.
What if you had:
(x^2 + 2x - 1 - x^100)^3
You can't just say the derivative is 3 * (x^2 + 2x - 1 - x^100)^2
You have to multiply by the derivative of the "inside" aswell
In your case, we're using y to denote a function of x.
okay i see that then but, if we do the chain rule doesn't it become multiplied by g prime of x. in other words multiplied by the inner fumctions derivative
So although we don't know what y is, we know that by the chain rule we must multiply by its derivative.
Yes
That's what we're doing
For example
e^y
Let's define f(x) = e^x
We want the derivative of f
I mean
Of e^y
e^y is just f, after plugging in y (which is again, some function of x)
well isn't the inner function derivative of y^3 just the derivative of 3
which is 0
So when taking the derivative, you take the derivative as if it was e^x (you get e^y) and then you multiply by y'
?
No
For the derivative of y^3
It's like x^3 by plugging in y
so you take the derivative of x^3, which is 3x^2
plug in y, you get 3y^2
and finally multiply by y'
okay let me try asking a different question
what is the inner and outter fucntion of
y^3 ?
Outer function is x^3
inner function is y
Can you show me how you were introducted to the chain rule?
Like what's the phrasing of the theorem you are familiar with?
I'll try to explain it according to how you learned it
yeah so i waas told
X ??
So you are given that y is a function of x.
And you want the derivative of y^3
So let's say f(x) = x^3, and y(x) is some function of x we don't know
y^3 is just f(y(x))
Now, differentiating gives you f'(y(x)) * y'(x)
f'(x) = 3x^2 so f'(y(x)) = 3y^2
hummm
I gtg right now, if you still have questions you'll have to wait for someone else.
alr thanks
interesting
so only when there is a Y in the part you are solving for is when you do this chain rule
if it were an X we dont do it
can someone verify?
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someone please help me?
people who havent finished 4 years / total of people that did college
?
its asking for the probability that someone hasn't finished 4 years of college
i understand what you're saying
how can i find the number of ppl that didnt finish the college?
it says in the table
How do I get help
That didn't help
it says years of college, right?
rigght
theres a section that says 4 years or less
theres a category called "math help (available)"
ohh i thought that meant as in
@coral osprey where
people who finished college less than 4 years
literally in the section above this one
haha word problems
right here
no more question
ur distracting me
theres ur answer
ok so would it be
38/82?
which is 19/41
in simplified
yes
WHAT IS THIS
do you still want help on it lmao
based on this, it looks like they want you to include people who haven't attended college at all
keep in mind that probability of not __ is the same as 1-the probability of __
uhh 47
WHAT
47 is the denominator?>
its asking who has not completed (wrong reply lol)
the probability that they have completed 4 years is 47/167
and then find the opposite, who haven't completed
uh
oh
LOl
wait yeah but its asking for ppl who didnt complete
so why isnt it 39
people who didnt go to college in the first place cant complete, can they?
yeah so the people who haven't completed is everyone else, including people who didn't attend college at all, i.e. 1-the probability
167-47 / 167
interesting
ok
so
47/167
now what
oh wait
i got it
120/167
thank you!!
/close
.close
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What is the units digit of the following product? 8433165483x946621539x5514381138
The units digit is the rightmost digit of every number
Isn't it the digit which only appears once?
No
Consider the number 324
That's the same as 3 * 100 + 2 * 10 + 4 * 1
So 3 is the hundreds digit, 2 is the tens digit, and 4 is the ones digit, or the units digit
Just ignore everything except the rightmost digit in each of the 3 numbers
Just multiply those together and the rightmost digit of that will be the answer
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If you added up all the factorials of the whole numbers from 0! to 100!, what would be the unis digit of the sum?
try writing out some factorials, up to like 12 lmao
try to find some sort of pattern so do the sum of a few smaller ranges
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how do i find the nth term for this sequence?
Do u see the pattern
the pattern is decreasing
first to second is +8/15
second to third is +8/35
so idk how
It's better to look at the pattern of numerator and denominator seperately
It's easier then
then what to do from there ?
Do u see the pattern
Ohk
An AP is a sequence where the difference between any 2 consecutive term is constant
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is this how youre supposed to do ghost points with this boundry condition??
is this like obscure math or something?
@flint wasp Has your question been resolved?
@flint wasp Has your question been resolved?
@flint wasp Has your question been resolved?
@flint wasp Has your question been resolved?
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.reopen
is this a glitch on desmos?
no problem
this doesn't do anything in an already closed channel that wasn't yours
What is "this"
like is the derrivative it gave wrong?
did i write it out wrong?
the green graph and the black one should match if i did it right
and i did it like 3 times
use a derivative calculator
actually it works for me
lol
disable the green function
the black function going under it
the vertical lines might be a bug, idk
i havent graphed trig functions in a while lol
by hand
I mean use desmos
to check if the graphs are the same
because sometimes you can simplify trig functions and the answer might look different
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can someone help me
what's your problem
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
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alright
i need help taking the derivative here
my first idea is to take out 331.3 as a constant and then work with (1+c/273.15)^1/2
then power rule and chain rule here
do you know the derivative of the square root of a function?
no id just rewrite it
you're correct
okay
so its
1/2(1 + c/273.15)^-1/2 * d/dx (1 + c/273.15)
so working with the right side
d/dc, variable here is c , not x
we have d/dc(1) + d/dc(c/273.15)
yeah mb
now the derivative of the fractional is where i seem to be struggling in my calculations
i simply cant wrap my head around the rule
i havent used it enough
becase d/dc of 1 is 0
so were just left with d/dc (c/273.15) to solve
and like how you said in the other channel, d/dc(c/273.15)) is (1/273.15)*d/dc(c) =1/273.15
well yeah i tried that and i got the wrong awnser
c/273.15 is the product of
c and 1/273.15
i checked with my calc using d/dx function and got the wrong awnser, maybe i put it in wrong..
so i can choose my constant
?
oh wait
thats a dumb question
c is never constant
alright
so when i type it in
im getting 1.29
when the correct awsner should be
.54
this is where im confused
thats the issue this whole time
in case you'd want to compare
this is .54
with c = 60 yup
the plus one was the issue
i had it right in the very beginning before i even asked the question
i guess i just need to be careful
dont miss numbers
lawl
preciate ur time bro
means alot
.close
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how do i do this efficiently?
39 43 and 45
we dont need to go through the answer, but i feel like it would be guess and check to see what works after you get the derrivative
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so far i took the derivative so it would be f'(t)=-2cos(t)-2cos(2t)
to evaluate, would i have to use a double angle formula on the second half?
Yes
once i have 2cos^2(t)-1=cos(t), how would i solve for t?
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I just have a quick little question, when a matrix is in standard form, online i see it written as $ax + by + cz + d = 0$ and $ax + by + cz = d$. Which side is d actually positive on?
Raforawesome
I know its ridiculous to use a channel for this but i legit cant find the answer anywhere 😭
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mh..
?
sorry can u explain that?
yes ...because they are coprime there exists some x,y integers s.t. xc+yn=1 right ?
yes
so..
$(a-b)c\equiv0 \implies (a-b)xc\equiv x0 \stackrel{bezout}{\iff} (a-b)(1-yn)\equiv 0$
but now by using $1-yn\equiv 1$ you get the claim
is it clear to you ?
everg
so currently all I have is n is divisible by (a-b) and I factored out a c
everg
a-b is divisble by n*
yea
so you are done
Like this right? n | c(a - b)
but don't you start with ac = bc modn?
yes i start from that (and gcd n,c=1)
and i end up to "a-b is divisble by n"
or "a=b mod n"
so start with this, then add the property at the end?
what's property ?
bezout
ok
so by bezouts idenity it would be cx + ny = 1?
cause all I have now is n divided (a-b) times c
idk what to do past that
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is f(x) = x_1 x_2 convex? ive done some work on it and shown it is not convex but my proof is really bad idk if its right so i wanna know if it is convex or not
@fallen whale Has your question been resolved?
i don't understand your function
have you tried finding f''(x)?
no i used this, if this holds then it is convex
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Find Horizontal Asymptote for the following function
$\dfrac{5x-5}{x^2+4}$
Qstn?
RecRio
Usually what I'd do for this is take the coefficents but that gives me a weird answer
*wrong answer
so I take L.C of numerator and denominator and get my H.A at 5
by dividing the two
isnt it 0
beacuse bottom is x^2
and top is 5x
if u plug like a big number 100000000000000000000000000
Are you in algebra or calculus class?
the bottom one is gonna be come very big while the top is gonna be a lot smaller
basical it apphroaches 0
As x becomes huge, the -5 means very little
You are always welcome to open your own help channel via #❓how-to-get-help
i did
Many many people can help with calc
so essentially just 5x/x^2
so basically 5x-5 is kinda just saying 5x
ok yeah that makes sense
but what I've done for limits so far is with a given limit, is this just the opposite?
So instead of x²+4, you can just approximate it as x²
So, putting it together, $\frac{5x-5}{x^2+4}$ is close to saying $\frac{5x}{x^2}$ for very big $x$
SWR
But you can simplify that to $\frac{5}{x}$
SWR
And for very large x, you should know that its asymtope is 0.
oh okay
my teacher did it in a
weirder way
@potent igloo
this made no sense so
Rule is to divide all terms by highest degree term
so by x^2?
Yes
5x/x^2 gives. you 5/x
ok that makes sense
but why is there
an x^2
on the outside
You're pretty much factoring out x^2 in the numerator and denominator
oh righttt
ok
ok cool
rest of the steps make sense
in what cases would you do this though
instead of the normal L.C of largest degree/L.C of largest degree
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How to turn 3y+12=6x into slope intercept form?
I don’t know the first step. If I should -6x on both sides or divide by 3 or idkkk
Do you know what slope intercept form looks like?
Y=mx+b
Yes, so the first step would be to isolate y
Do you know how you do that with this question?
Divide by 3?
Yep now you need to get y by itself
So you have y + 4 = 2x now, how can you get y by itself from that
Nice yeah that's it
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Do you know about AGP series?
It may have another name as the name AGP is commonly used in JEE
These are my notes
try this formula
@steep vine Has your question been resolved?
I don't know how to apply this one here
Hmm
Wait a min
I'm gonna look for a study material
Hey
Do you understand Hindi?
If you do understand
👉Previous Video: https://www.youtube.com/watch?v=fj5dwSSoGT8
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=======================...
this explains the Concept
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Great
No problemo
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<@&286206848099549185>
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I was wondering if I am meant to do chain rule for those square roots or product rule
@tribal idol Has your question been resolved?
Is this implicit differentiation
yes
Convert the other square root to an index as well and then use the chain rule when you implicitly differentiate y
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hummmm, what would i be solving for then? i dont think there is a y prime i can make
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im stuck at finding probabilities
@latent trout Has your question been resolved?
If I remember correctly, then if f is joint pmf of two rv X and Y, then f(x,y)=P(X=x, Y=y)
So you'll have to go case-by-case to find the joint pmf. N ranges from 1 to 3, and X1 ranges from 0 to 3
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what does it mean by position vector
is it like
expressing it in terms of 'i' and 'j'
yeah
,calc (5*sqrt(2) + 5) * sqrt(2)
Result:
17.071067811865
yep
ok now i need uh
help with checking answer
i got c for this, is this correct?
I got A for this, is this correct?
I got C for this, is this correct?
ping me when reply pls
@brittle crow Has your question been resolved?
@brittle crow Has your question been resolved?
yep
just draw a diagram
the river is flowing west
the boat is going north
whats the resultant vector
yeah
and for B
would answer be 72+270?
i found 72 by doing arc tan(12/-4)
(rounded up)
and then uh + 270 cause its in that last quadrant
and it asks for BEARING
so yeah
yeah
wait
for (c)
if we're travelling 500m
and we are going 12km an hour
that means
6km in 30 minutes
1km in 5 minutes
500m in 2.5 minutes
so answer is 2.5 minutes?
we have to account for the river flow tho
you need to know the magnitude of the resultant vector
yeah then you just divide by the distance
i got 25.3 for this
time
wait no i fucked up
its distance divided by velocity
not velocity divide by distance
velocity is still the magnitude of the resultant vector
yep
oh alr
and that should be it for your problem
wait to clear things up for me, why did we find magnitude of resultant vector
because we want to know how fast the boat is going when its flowing through the river
and velocity of the river current is 4km/h
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yes
wait doesn't ] mean that it ends there?
and ( means it doesnt?
or like
idk
what do they mean
i forgot
So (a, b) means all the numbers between a and b excluding a and b
And [a, b] includes a and b
why other way around
In order for f(x) to be -2, x has to be 7. But x is less than 7 so x cannot be 7
But 7 is in the range of f(x) since f(-2) = 7
and -2 is in the domain of f(x)
domain = all the values of x
range = all the values of f(x)
-2 is in the domain, but 7 is in the range
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do make it equal to 0
then I just solve for x
which I could find the roots which would be the interval.
if so, then i dont really know how to get x on its own.
you can't solve for x just by algebraic means
@pastel heart Has your question been resolved?
and you're not really using ivt
