#help-39

1 messages · Page 263 of 1

sonic patrol
#

cool

stoic imp
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this part it gets fuzzy

sonic patrol
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if A is defined using some inequalities, you can break it up by setting 1 of them to an equality

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but yeah in general this is probably the hardest step

stoic imp
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.

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So, A is defined using the inequalities $y \geq 0$ and $2y + x^2 \leq 9$

jolly parrotBOT
#

Renato

sonic patrol
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mhm

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for the interior of A, you need these both to be strict

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so $y > 0$ and $2y + x^2 < 9$

jolly parrotBOT
#

Pseudo (Cat theory #1 Fan)

stoic imp
#

2y < 9 - x^2
0 < y < (9-x^2)/2

stoic imp
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So, if we say $B = {(x, y) \mid y = 0 \land 2y + x^2 \leq 9}$, then $B = {(x, 0) \mid -3 \leq x \leq 3$

jolly parrotBOT
#

Renato

stoic imp
#

this is the interior

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but the inequalities are not strict (?)

sonic patrol
stoic imp
#

the boundary of $A$ is $C = {(x, \frac{9 - x^2}{2}) \mid -3 \leq x \leq 3}$

jolly parrotBOT
#

Renato

sonic patrol
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well the boundary of A is B u C actually

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$\partial A = B \cup C$

jolly parrotBOT
#

Pseudo (Cat theory #1 Fan)

stoic imp
stoic imp
stoic imp
stoic imp
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its like, B and C are partitions of A

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like disjoint subsets of A

stoic imp
stoic imp
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or what?

stoic imp
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then, one of B or C is the interior of A, and the other is the boundary of A

sonic patrol
jolly parrotBOT
#

Pseudo (Cat theory #1 Fan)

sonic patrol
#

Both B and C are part of the boundary of A

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Neither is the interior

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If you sketch what B and C look like you’ll see what I mean

stoic imp
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how do I sketch this?

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B and C

stoic imp
stoic imp
stoic imp
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the interior of A here is the system

  1. y = 0
  2. 2y+x^2 = 9
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correct?

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that is, x^2 = 9

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so from that we get that either x = 3 or x = -3 are the interior points

stoic imp
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to me it looks like a curve but

sonic patrol
sonic patrol
#

It might help if you use desmos

stoic imp
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the boundary of A is x^2 = 9 yes or no?

stoic imp
sonic patrol
#

Check this out

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B is the flat part of the boundary of A

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C is the curved part

stoic imp
sonic patrol
#

That’s what I sent you

stoic imp
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right?

sonic patrol
#

Yes

stoic imp
stoic imp
sonic patrol
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B is just (x, 0) for -3 <= x <= 3

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So it’s the flat part on the x axis

stoic imp
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what about C

sonic patrol
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It’s the curved part of the boundary of A

stoic imp
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is like -x^2

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-x^2 + something <= 0

sonic patrol
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Yeah it’s (x, (9 - x^2/2)

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For -3 <= x <= 3

stoic imp
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wait

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how did we found B and C

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knowing that A is this

sonic patrol
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.

stoic imp
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yeah so B is y = 0, x^2 <= 9

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no wait

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no, that's correct

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B = {y = 0, x^2 <= 9}

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2y + x^2 <= 9
2y <= 9 - x^2
y <= (9-x^2)/2
y >= 0
0 <= y <= (9-x^2)/2

pearl pondBOT
#

@stoic imp Has your question been resolved?

#
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pearl pondBOT
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exotic gale
#

I don't see how the answer is not 2

pearl pondBOT
exotic gale
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i only see triangle ABC and triangle DEC as isosceles

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and there is obvi no equil triangles too so yeah

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can someone please tell me what im doing wrong?

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i already checked all the 7 triangles, unless im missing one idk

kindred plank
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lemme think,what's awnser 2?

exotic gale
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yeah i got 2

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it was wrong tho

boreal marlin
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what are the isoceles triangles you've found?

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I can tell you're missing a few

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you might've missed ∆ABD being isoceles

exotic gale
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how

boreal marlin
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find all the individual angles

exotic gale
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ok

#

.osvloe

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.solve

#

.close

pearl pondBOT
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vast berry
#

what does C^infinity(R) mean?

pearl pondBOT
summer imp
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It's the set of smooth functions from R to R.

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So it's telling you that d/dx maps smooth functions to smooth functions.

plush bramble
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smooth being differentiable, infinitely many times

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polynomials, exponentials, logarithms, trig functions for example

vast berry
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wait C^n means differentiable n times right

summer imp
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It means differentiable n times with continuous derivatives

vast berry
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oh yeaa

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smooth implies infinitely many continuous derivstives?

summer imp
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Well if any nth derivative exists implicitly the nth derivative is differentiable, so continuous.

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So it's enough to just say smooth implies any order derivative exists.

pearl pondBOT
#

@vast berry Has your question been resolved?

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stoic imp
pearl pondBOT
warm current
pearl pondBOT
# stoic imp
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
stoic imp
#

well 2

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I did started using cylindrical coordinates

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(x,y,z) = (rcos(♡), y, rsin(♡))

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and simplified the inequalities of the region D

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1 <= r^2(cos^2(♡) + sin^2(♡)) <= 16

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1<= r^2 <= 16

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rsin(♡)<=rcos(♡)

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and

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0<=y<=sqrt(r^2(cos^2(♡)+sin^2(♡)))
0 <= y <= sqrt(r^2)

stoic imp
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I get

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1<= r^2 <= 16
rsin(♡)<=rcos(♡)
0 <= y <= sqrt(r^2)

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everything good so far? @warm current

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I have a cheat sheet of the common quadric surfaces

warm current
stoic imp
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what am I missing here?

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I might need some more help with this one

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if possible handholding

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is that okay?

warm current
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What are your definite bounds for r and y?

stoic imp
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I am assuming r is in between [1,4]

warm current
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Why 1?

warm current
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Oh i missed the 1 there

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Yes

stoic imp
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and y I am assuming

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is between 0 and r

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aka [0,r]

warm current
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Yes

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Theta is really the challenging one

stoic imp
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is r positive then

warm current
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Try graphing $\sin\theta$ and $\cos\theta$ to figure out your bounds

jolly parrotBOT
warm current
stoic imp
warm current
stoic imp
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help

warm current
#

You can either use the unit circle, or you can use $\sin=1-\cos^2$

jolly parrotBOT
stoic imp
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at 45 deg

stoic imp
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sin = 1 - cos^2?

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that's too advanced for me

warm current
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Oops i meant sin^2

stoic imp
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ohh

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pyt ident

warm current
stoic imp
stoic imp
warm current
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Good. That's one. You just need the other

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Where else on the unit circle is sin=cos?

stoic imp
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0 <= pi/4 + 2kpi < 2pi

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0 <= 1/4 + 2k < 2

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0<= 2k < 2 - 1/4

warm current
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Where is k coming from?

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I think you are overthinking this

stoic imp
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let me use soh cah toa

warm current
#

You just need to know for which $\theta$ in $[0,2\pi)$ is $\sin\theta\le\cos\theta$

stoic imp
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3pi/4

jolly parrotBOT
warm current
stoic imp
#

I figured by soh cah toa I think

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I don't know unit circle by heart

stoic imp
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knowing the graphs of sin and cos

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also quick question dude

stoic imp
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they keep alternating

stoic imp
#

sir

warm current
stoic imp
stoic imp
stoic imp
#

It feels like I am missing something here

warm current
#

Think of what polar coordinates are doing. Normally you are within the bounds of 0 to 2pi

stoic imp
#

theta or ♡ is in between [0,2pi)

stoic imp
#

which one is above or below

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idk if I am explaining myself

warm current
#

The graph tells you which one is less than the other

stoic imp
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in between the intersections, in first case sine is above cosine

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in second case cosine is above sine

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and in third case sine is above cosine

warm current
#

Sorry i was doing it backwards

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You want just section 2

stoic imp
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alright

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but

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how do I find the interval for section 2

stoic imp
#

you here?

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basically all of this 3 sections are in between 0 and 2pi, correct?

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@warm current

pearl pondBOT
#

@stoic imp Has your question been resolved?

stoic imp
#

.close

pearl pondBOT
#
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stoic imp
pearl pondBOT
jolly parrotBOT
#

Renato

lilac quartz
#

Can you rewrite the integtal in terms of limit?

stoic imp
#

this?

lilac quartz
#

now can you compute inner integral?

stoic imp
#

also please ping me

quiet tendon
# stoic imp is hard

try splitting up the numerator, doing a u-sub for the first integral, and maybe doing a comparison for the second integral

stoic imp
#

what u sub

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@quiet tendon

quiet tendon
#

what's the first integral you get?

stoic imp
#

can you ping me

quiet tendon
#

@stoic imp when you split up the numerator, you'll get two different integrals. the first one could be evaluated with a u-sub, the numerator looks similar to the derivative of the denominator

stoic imp
quiet tendon
#

okay, try comparing to something like x^3 / (x^4 + 4)

lilac quartz
#

Do you know this?

stoic imp
#

perfect

stoic imp
quiet tendon
#

mmhm so does it converge or diverge

stoic imp
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i don't know yet

quiet tendon
#

do you know how to integrate that smaller one?

stoic imp
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no need to integrate

quiet tendon
#

i mean the point is to compare to something that you know how to integrate (or at least something you know converges/diverges)

lilac quartz
#

$\frac{x^3}{x^4 + x^4} = \frac{1}{2x} \leq \frac{x^3 +5}{x^4 +4}, x \geq 2$

stoic imp
#

when p >=1

jolly parrotBOT
#

dotdoc

lilac quartz
#

you could also use this,

compute the improper integral of 1/2x

stoic imp
#

what

stoic imp
#

is what you mean

#

?

lilac quartz
#

you can always find an “a” above such that the inequality holds for all values larger than a

stoic imp
lilac quartz
#

oops sorry

stoic imp
lilac quartz
#

you have to take care of the integral from 1 to 2

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but it doesn’t matter since they diverge

lilac quartz
#

and add little part (don’t compute but it exists)

stoic imp
#

x^3 / 5x^4 works

stoic imp
stoic imp
#

with the inequality proof

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x^3 <= x^3 + 5 true always

lilac quartz
#

for all x >=1 yes

stoic imp
#

x^4 >= 4 ?

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only when x >= 2

stoic imp
#

but we are close

lilac quartz
stoic imp
#

let me think

stoic imp
lilac quartz
#

5x^4 >= x^4 + 4 for all x>= 1

stoic imp
#

yes

lilac quartz
lilac quartz
stoic imp
#

4x^4 - 4 >= 0

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x^4 - 1 >= 0

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x^4 >= 1

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x >= 1 <=> x^2 >= x >= 1

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@lilac quartz

#

we can use transitivity

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x >= 1 <=> x^4 >= x^3

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x>= 1 <=> x^3 >= x^2

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x >= 1 <=> x^4 >= x^3 >= x^2 >= x >= 1 <=> x^4 >= 1

lilac quartz
#

for all x>1, (we can apply
montonicity of powers in this range)

x^4 >= 1 iff 4x^4 >= 4 iff 5x^4 >= x^4 + 4

lilac quartz
#

basically adding to an inequality is always safe

#

the key step is montonicity in [1,inft)

for any a,b in [1,infy)
a < b implies a^n <= b^n

for any n in N

lilac quartz
stoic imp
#

help

lilac quartz
#

$\frac{1}{5x} = \frac{x^3}{5x^4} \leq \frac{x^3 +5}{x^4 +4}, x \geq 1 \implies \frac{1}{5x} <= \frac{x^3 +5}{x^4 +4}$

stoic imp
# lilac quartz you are done, use this

the issue is that the 1/x^p idk how it works because for integrals with an infinity as bound diverges but for regular definite improper integrals it converges

#

p>=1

jolly parrotBOT
#

dotdoc

lilac quartz
#

apply improper integral to last inequality

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or what’s the improper integral from 1 to infy of 1/5x?

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does it converge or diverge?

stoic imp
lilac quartz
#

“harmonic series”

stoic imp
#

this is a nice little summary i just found

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is confusing because sometimes they do sometimes they dont depending on the bounds

lilac quartz
stoic imp
#

alright let's see

lilac quartz
#

the whole point of this exercise is computing smaller integrals

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you can’t avoid that

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you would be pushing something like log to infy

stoic imp
lilac quartz
#

gg

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now push the limit

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what do you get?

stoic imp
#

who the fuck knows at this point

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unsure

lilac quartz
#

what what?

stoic imp
#

unsure what the range of ln is

lilac quartz
stoic imp
#

what?

lilac quartz
#

forget about the limit part

what’s integral 1 to t 1/5x?

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definite

stoic imp
#

its just

lilac quartz
#

just?

stoic imp
#

1/5 × ln|t) - 1/5 × ln1

lilac quartz
#

what’s ln(1)?

stoic imp
#

who knows what the domain of ln is

stoic imp
lilac quartz
#

what’s your domain of integration?

stoic imp
#

no?

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,calc ln(1)

jolly parrotBOT
#

The following error occured while calculating:
Error: Undefined function ln

lilac quartz
#

bruh

stoic imp
lilac quartz
#

it’s 0

#

ln(1)

stoic imp
lilac quartz
#

1/5 × ln|t)

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now push this limit

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to infy

stoic imp
#

yes

lilac quartz
#

what do you get?

stoic imp
#

i don't know the range of ln

lilac quartz
#

you should check then

stoic imp
#

but i presume the supremum of the range

lilac quartz
#

,w plot ln x ;x>= 1

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nvm check yourself

stoic imp
lilac quartz
#

or you should know at this point that it shoots to infy

stoic imp
#

,w lim n to infty of ln(n)

lilac quartz
#

good

#

so the smaller integral diverges

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so is the bigger one

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wohlah

#

byee

stoic imp
lilac quartz
#

i have lecture in 15 mins

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ggs

stoic imp
#

what u studying

lilac quartz
#

psychology

stoic imp
#

oh sht, gl

lilac quartz
#

lel

#

honestly, where are you still stuck?

stoic imp
#

finding upper bounds proving etc

lilac quartz
#

find bounds of?

stoic imp
#

compari

rough forge
lilac quartz
lilac quartz
#

you just showed int f diverges

stoic imp
#

shit is tuff

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b) part i mean

lilac quartz
#

gl

stoic imp
#

. clo S e

#

. close

#

.close

pearl pondBOT
#
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kind forum
#

I don't understand the derivation

pearl pondBOT
kind forum
#

Why is there w_0 all of a sudden

#

The Eq 9.18e mentioned by the book is the reciprocal rule of complex number

#

Ohhh w_0 is 1/RC

#

Nvm

#

.close

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tender egret
#

I want to find the average(expected?) cost of random restart hill climbing

tender egret
#

My confusion begins with how we can even define cost

languid plover
#

please provide question

tender egret
#

And secondly how it extends to n dimensions

languid plover
#

do it... do it now!!!

tender egret
#

That is the question

languid plover
#

oh

#

It would be more helpful if htere was a scenario

#

give me more info here

tender egret
#

And thirdly to find cost for having some x% confidence interval

languid plover
#

easy peasy

#

give me values to work with

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and ill help u out

tender egret
#

What.

#

Theres no values involved here

languid plover
#

It's more helpful if you give me an actual framed question with a scenario and values instead of a general question about a generic procedure

#

I'll give it a shot but trust me it'll be more difficult

tender egret
#

But it is in fact a general question about a generic procedure

languid plover
tender egret
#

Simplifying it will kill it's essence

languid plover
#

understood

tender egret
languid plover
#

alright then

#

good luck

tender egret
#

Reiterating:
I want to find the average(expected?) cost of random restart hill climbing
My confusion begins with how we can even define cost
And secondly how it extends to n dimensions
And thirdly to find cost for having some x% confidence interval

#

<@&286206848099549185>

tardy reef
#

like the reason you actually restart is to check whether you got stuck at a local maxima

tender egret
#

After each restarts there will be a cost required to reach the local minima righ

#

Right

tardy reef
#

sure

#

but thats not relevant to the reason you restart

tender egret
#

I know

#

You restart in order to make sure you reach global maxima

tardy reef
#

and also, the initial steps are too quick, the time taken to converge depends on the behaviour in the small neighbourhood

tender egret
#

That's why I'm talking about finding an average cost

tardy reef
#

wait, I might have been a bit confused. Am i correct assuming that the direction of movement is influenced by how much improvement is there? like would you be moving in the direction of climb by a fixed amount or would that be influenced by how much the improvement is?

#

would my $\vec{x}n - \vec{x}{n-1}$ be same as my $\vec{x}k - \vec{x}{k-1}$

jolly parrotBOT
#

βαχτϵρ10Φρ4γ

pearl pondBOT
#

@tender egret Has your question been resolved?

tardy reef
# tender egret I don't know myself <:blobcry:971797574916907028>

well, no matter, what you are looking for is to cover a reasonably large subset of your domain over which you randomly start. so, I dont think there is any point in looking at a cost to random restarts. the aim is to be exhaustive, so you should not look at ways to reduce efforts here. The only reason you restart is that you dont end up missing the maximum of this unknown function.

pearl pondBOT
#

@tender egret Has your question been resolved?

pearl pondBOT
#
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pearl pondBOT
#

Please don't occupy multiple help channels.

tardy reef
#

<@&268886789983436800>

pearl pondBOT
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zinc pewter
#

God damn lance

#

speedy

tardy reef
#

lol I thought you did the work and lance just lanced

pastel umbra
#

(oh shit that's actual cinema here lol)

pearl pondBOT
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hollow oxide
#

Is this channel available?

pearl pondBOT
rotund ferry
hollow oxide
#

Oh okay

rotund ferry
hollow oxide
#

Got it

#

Multiplication/Division in Different Bases in this problem I need to multiply the following but I'm stuck on problem d. Which is B12twelve×83twelve?

cedar sentinel
#

are you stuck on all the digits?

toxic lichen
#

are you expected to do it in dozenal?

#

or do they expect you to convert to base ten first

#

kinda unclear from this question in isolation how you would be meant to proceed

#

aside from this, do you know the algorithm for multiplication in base ten?

hollow oxide
#

They're expecting us to do it in Bases from base 2-12 this one is just base 12

toxic lichen
#

ok

#

so you are expected to stay in base twelve throughout, got it

hollow oxide
#

From what I've known base 10 numbers are broken down to ones, tens, hundreds, thousands, and so on.

toxic lichen
#

so they are

#

do you know how to do multiplication if both numbers are in base ten?

#

yes or no

hollow oxide
#

No

toxic lichen
#

so uhh. hm.

#

if i asked you to work out

  731
*  43
-----
#

and these are just regular base ten numbers

#

would you know how to do it?

hollow oxide
#

Kinda

#

not really

#

I know 1×3=3

toxic lichen
#

so you can't do multiplication of multi digit numbers even in base ten?

hollow oxide
#

yes?

toxic lichen
#

wait a minute

#

how were you able to do letters a-c

#

can you show me the entire worksheet

toxic lichen
#

sure does

#

but op is having a bigger issue

#

she seems unable, by her own account, to do long multiplication at all

warm dagger
#

;-;

toxic lichen
#

@hollow oxide can you take a photo of the whole worksheet please

warm dagger
#

Welp good luck on this one Ann

hollow oxide
#

Okay

toxic lichen
#

mmmm not what i was looking for.

cedar sentinel
toxic lichen
cedar sentinel
#

aka the actual paper itself

hollow oxide
#

I’ve done a to c but not d unfortunately

toxic lichen
pastel umbra
#

!show is a wonderful blessing in this server; it says the following:

pearl pondBOT
#

Show your work, and if possible, explain where you are stuck.

toxic lichen
#

brb

hollow oxide
toxic lichen
#

ok look at part b

#

you do know the algorithm for multiplication

#

you know that you need to multiply each digit of the first number with each digit of the second

#

yes?

hollow oxide
#

Yes

toxic lichen
#

yes so

#

same idea here

#

now you just need to write down all the single digit dozenal multiplications that you will need

#

then proceed in the exact same way

void glen
#

she is having problem with the letters it seems?

toxic lichen
void glen
#

ok

hollow oxide
#

I think I have to multiply by 3 in the ones place for problem d.

3 × 2 = is 6

3 × 1 = 3

3 × B = 3 × 11 = 33¹⁰ = 2(12) + 9 = 29¹² but I have to write 9 and carry the 2.

#

Next I need to multiply times 8 which is the twelve place

#

8×2=16¹⁰ =14¹² I need write 4 and carry 1

8×1=8, plus carry 1 = 9

#

Shoot

#

I'm stuck

#

I don't know what to do next..

cedar sentinel
#

never do this kind of math without writing it down

#

you risk confusion and chunking too big of an operation

hollow oxide
#

Okay

cedar sentinel
#

your first round of multiplication looks correct though. write that down first, then do the second round separately

hollow oxide
#

I think 8 × B = 8 × 11 = 88¹⁰ = 74¹²

#

So 8 × B12 = 7494¹² (shifted one place left) = 74940¹²

#

I get 2936¹²+74940¹²=

cedar sentinel
#

whoa whoa

#

why are we multiplying the two intermediate results?

hollow oxide
#

You had to?

cedar sentinel
#

you don't.

#

even in base 10

hollow oxide
#

No the problem is Identifying the place values in base 6

cedar sentinel
#

base 6?

hollow oxide
#

And base 12

cedar sentinel
#

ok, this algorithm works on any base

#

and no, multiplication of the two intermediate results here is not what should be done

#

let's just take a simple example to show why

#

suppose you're asked to multiply 123 with 13

#

in base 10*

hollow oxide
#

Like 6⁰ = 1

6¹ = 6

6² = 36

#

The place values are from right to left

#

I think?

cedar sentinel
#

that does not justify the multiplication of the two intermediate results.

#

again, I'm about to show you why

hollow oxide
#

No

#

I'm good

cedar sentinel
#

sure then

#

what's your final answer then?

#

wait a sec

#

you added the intermediate results in this problem.

hollow oxide
#

Yes

cedar sentinel
#

so why are you switching to multiplication now? adding is the correct step here

cedar sentinel
hollow oxide
#

Oh wait I think I mistakenly added a multiplication sign by mistake

cedar sentinel
#

...that was my entire question

#

but ok, confusion cleared

hollow oxide
#

Sorry

cedar sentinel
#

yes, that would be the correct step to proceed

hollow oxide
#

I just don't the smallest mistakes I make

#

notice*

#

The answer is 77876¹²

cedar sentinel
#

I'm more surprised that you didn't double check when I pointed it out the first time, but it worked out in the end

cedar sentinel
#

check.

#

specifically, your third digit seems to be wrong

#

every other digit is correct

hollow oxide
#

Wait no it's

cedar sentinel
#

(also pedantic note, but don't indicate bases with superscripts. those are reserved for exponents)

hollow oxide
#

77676¹²

cedar sentinel
#

there we go

#

more correctly notated as $77676_{12}$

jolly parrotBOT
#

Tairin

cedar sentinel
#

but yes, well done

pearl pondBOT
#

@hollow oxide Has your question been resolved?

#
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hollow oxide
#

Does any know numeration systems unit. That is Egyptian, Roman, Babylonian, and Mayan numerals. It will also include converting between different bases and adding, subtracting, multiplying, and dividing in other bases as well.

So I'm hoping if anyone is aware of these kinds of subjects in math and helping me out?

glass meadow
#

@hollow oxide

hollow oxide
#

A review on these math subjects

#

I just want to go over the numeration systems and numerals and I do want to go over different basses also

#

I desperately need the help I can get

glass meadow
#

These channels aren't for reviewing an entire topic

#

Feel free to ask specific questions

hollow oxide
#

Oh...

glass meadow
hollow oxide
#

Nevermind then

glass meadow
#

I mean you can also keep this channel and wait for someone who would be willing to go through an entire topic

#

I'm not

#

Still, I'm happy to answer specific questions

pearl pondBOT
#

@hollow oxide Has your question been resolved?

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bronze warren
#

hi im having some trouble with ODEs and the Lipchitz condition. Whilst i get that its essentially sets a 'speed limit' as to how a function grows im not understanding why we let y vary and not x in a multivariate function.
So say f(x,y)
then lipchitz condition says that

|f(x,y2) - f(x,y1)| <= K|y2 - y1| y2,y1 E D

I'm also having trouble seeing how this links with ODEs

if someone could clear this up for me that would be amazing!

pearl pondBOT
#

@bronze warren Has your question been resolved?

snow sail
bronze warren
#

thanks boss

#

bruh i dont have perms for real complex analaysis

pearl pondBOT
#

@bronze warren Has your question been resolved?

pearl pondBOT
#

@bronze warren Has your question been resolved?

pearl pondBOT
#
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quick venture
#

How do I solve the sum of moment equation to get theta?

plush bramble
#

you can isolate tan(t) = some number then use inverse tangent

#

arctan(tan(t)) = t

#

theta is written as $\theta$, not $\varnothing$

jolly parrotBOT
#

riemann

quick venture
#

ok

#

i did tan^-1(1/0.4)

#

which isnt the answer

plush bramble
#

what is than^1 mean

#

show your number here

quick venture
#

arctan

plush bramble
#

and show the answer

quick venture
#

ok

#

tan^-1(1.0.4004)=68.17

pearl pondBOT
#

@quick venture Has your question been resolved?

#
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pearl pondBOT
#
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hard chasm
#

Ayo how do i do 6

pearl pondBOT
hard chasm
#

Im familar with the idea of these questions but whats the formula

#

Whats the radius have to do with this

#

And am i basing this on the formula for volume of a cylindar, or which formula do i derive?

#

Oh wait

#

Yea i feel like sum is wrong here

#

Wait no dr/dt cuz the radius is constant

#

Wait na im lost af

#

.close

pearl pondBOT
#
Channel closed

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velvet ruin
hard chasm
#

Yea i gpted it

velvet ruin
hard chasm
#

Its about the idea of once part of the equation goes to 0

#

Since its a constant

#

Like dr/dt is 0

#

Which confused me

velvet ruin
hard chasm
#

Lemme see if i can do # 7

hard chasm
#

I think i got it one sec

velvet ruin
#

Alright 👌

hard chasm
#

Nah les go i got the answer right

#

Its basically like

#

At one point u have to derive using the product or quotient rule

#

And one part of it is 0

#

I think atleast

velvet ruin
#

Well, you have to relate things first and usually everything given should help you find out which formula to use

#

You have to establish first what you're looking for.

#

Since you're going with related rates problems, it usually involves formulas from basic geometry and it's on you to construct it in a way that the given of the problem would somehow relate to each other

hard chasm
#

Yea

#

Its mainly just these geometric shape formulas

#

And we did some triangle work but i didnt get to that review yet

#

But like 2 cars goes in directions that makes a right angle

#

Or a guy walking away from a light making a shadow

velvet ruin
#

You should be good to go as long as you know your geometry formulas and you know what you're looking for

pearl pondBOT
#
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pearl pondBOT
hard chasm
#

Some how i got 1/0.333 as my answer which is defo off cuz my entire r term cancelled out

#

Imma redo my work rq

velvet ruin
hard chasm
#

Oh

#

I forgot to solve for g’(f)

#

Dang its still wrong

tardy reef
#

did you put r in terms of h in your volume expression?

hard chasm
#

Wym

tardy reef
#

coz to me it looks like you didnt do anything to r till the very end

hard chasm
tardy reef
velvet ruin
hard chasm
tardy reef
velvet ruin
tardy reef
#

now replace r with h

#

like properly according to their relationship

hard chasm
#

One sec im confused

#

Like my first step, i need to isolate h?

tardy reef
#

no

leaden wadi
pearl pondBOT
tardy reef
#

you have this right?

hard chasm
#

Yea

tardy reef
#

use it

hard chasm
#

Oh

tardy reef
#

pls dont hand out answers like that

hard chasm
tardy reef
velvet ruin
hard chasm
#

So

tardy reef
#

yea

#

and now you should differentiate wrt time

hard chasm
#

Ah ok thanks

#

And why do u do this

#

Like in the future when should i know

tardy reef
#

coz you got this expression here

#

and can you tell me what you did to the dr/dt?

hard chasm
#

It = 0

tardy reef
hard chasm
#

Derivtive of the constant i thought

tardy reef
# hard chasm It = 0

yea, and obv thats not the case coz the radius is also changing with time as the volume changes

hard chasm
#

If r = 2/3

tardy reef
#

well, in that case why is your dh/dt not 0?

hard chasm
#

Yea your right

#

I forgot a cone radius changes

tardy reef
#

but you didnt realize that

#

so its better if you do this substitution as soon as possible

hard chasm
#

Am i dumb

#

Did i forget how to differentiate

#

I ended up with this

hard chasm
#

Idk if im supposed to have them

leaden wadi
#

At this point in Calculus, you have not been taught how to evaluate multiple variables. Because there are three variables in the equation for the volume of a cone, you need to eliminate one of them. You can do that by using substitution which was provided to you by the relation h = 12r.

hard chasm
#

I remember my teacher going over cones but i passed out during that lesson

hard chasm
leaden wadi
hard chasm
#

Am i meant to solve for dr/dt?

#

I swear the question asks for dh/dt

leaden wadi
#

Yes, it does ask for dh/dt.

#

And it gives you dV/dt.

#

That it your hint that you need to eliminate the r variable somehow.

hard chasm
#

Do u mind if we start over and go step by step

#

Feel like im not close at all

tardy reef
# hard chasm Idk if im supposed to have them

if you did sub h earlier, then you shouldnt have any dr/dt's. But in case you didnt, you could still do dr/dt = d(h/12)/dt and end up with dr/dt = 1/12 * dh/dt and that would work too

hard chasm
#

Oh i see where i messed up

#

I subbed in 12r for h

#

But i think i should sub in h/12 for r

#

Would be easier

tardy reef
#

eithere way is fine tbh

#

but yea, r = h/12 is a more direct route

hard chasm
#

Dang now i gotta derive this

#

Huge thing

tardy reef
hard chasm
#

Right

tardy reef
#

just switch up r and h and from there you are back on route

tardy reef
hard chasm
#

Idk if ive ever seen

#

Quotient rule and power rule at same time

#

Its just 2(h/12’h

#

?

tardy reef
#

quotient rule?

hard chasm
#

Oh

#

Nvm

tardy reef
#

why do you need that here?

hard chasm
#

Its just all big product rule

tardy reef
#

there is just one small chain rule, nothing else tbh

hard chasm
#

But idk ive never seen examples with a quotient and chain rule

#

Normally just like (x+q)^2

#

Got it

#

Gpt

#

.close

pearl pondBOT
#
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pearl pondBOT
#
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sharp smelt
#

I think I'm having a brainfart

pearl pondBOT
sharp smelt
#

Like I'm unable to sketch the region

#

would this be right

void sorrel
#

Almost, but not quite I think

#

What's the non-zero area of f?

sharp smelt
sharp smelt
#

$\int_{0}^{0.5} \int_{y}^{1-y} 8xy dxdy$

void sorrel
#

Oops, I meant like the region, not the numerical area

#

Just to sketch it

sharp smelt
#

I see

jolly parrotBOT
void sorrel
#

So I would just begin by sketching 0 < y < x < 1

sharp smelt
#

got mt mistake

#

tq

#

I'll close this now

#

.close

pearl pondBOT
#
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sharp smelt
pearl pondBOT
sharp smelt
#

So the formula here ie E(XY)-E(X)E(Y)

#

$\int_{0}^{1} \int_{0}^{1-y} 2xydxdy - \int_{0}^{1}\int_{0}^{1-x} 2ydydx \int_{0}^{1} \int_{0}^{1-y} 2xdxdy$

#

This feesls wrong

jolly parrotBOT
sharp smelt
#

.close

pearl pondBOT
#
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pearl pondBOT
#
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dapper kraken
#

find all $x$ such that
$$\tan(x)=\tan(x+10^\circ)\tan(x+20^\circ)\tan(x+30^\circ)$$

dapper kraken
#

topic is using symmetry??

#

honestly i have no idea where to start here

hollow sonnet
#

degrees?

dapper kraken
#

oh yea

jolly parrotBOT
#

ihave<skissue>

tropic saddle
#

well symmetry makes me think that you should either sub u=x+15 or u=x+20

#

but dunno

hollow sonnet
#

also might be helpful to approach this casewise

#

where 0<x<90, 90<x2<180, etc

dapper kraken
#

i mean bound it by 360 first ig

hollow sonnet
#

ye

#

oh wow that's an interesting solution

#

half an inkling of an idea

dapper kraken
#

huh

hollow sonnet
#

no idea how tf that happened

pearl pondBOT
#

@dapper kraken Has your question been resolved?

pearl pondBOT
#

@dapper kraken Has your question been resolved?

#
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dapper kraken
#

gtg sleep now, sorry

pearl pondBOT
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sharp smelt
pearl pondBOT
sharp smelt
#

cov(X,Y)=0, unless I'm tripping?

#

okay, I'm lost

pearl pondBOT
#

@sharp smelt Has your question been resolved?

sharp smelt
#

.close

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pearl pondBOT
prime bramble
#

<@&268886789983436800>

pearl pondBOT
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fossil drum
#

is there an intuitive way to think about why being prime implies irreducibility in an integral domain

fossil drum
#

a = bc

#

a = atc if a | b

#

thus tc = 1 by cancellation

#

hmmmmm

#

like proof makes sense but not really getting it intutively

deep coral
#

Why do these chats go on for so long? I'm new, and this isn't just one question right?

fossil drum
fossil drum
# sharp smelt

thats literally the same book im using for my probability class lol and I was just working on that problem not too long ago

toxic lichen
#

we have 50 channels for this sort of real-time help and they're rotated in and out

toxic lichen
# pearl pond

when the bot posts this message it means the channel is up for grabs and whatever follows is a new question

static helm
#

at least that’s my take on it

mortal imp
fossil drum
#

hm what do you mean by that

mortal imp
#

It just seems messed up cause if all the symbols and all

fossil drum
#

the proof makes perfect sense but Im having trouble picturing it

mortal imp
#

The statement is provable by definition of prime numbers itself

static helm
fossil drum
# static helm what do you mean “picturing it”?

like conceptualizing it, like the way I started to think about it was we have a = bc and that a is prime so we know a breaks up b or c into pieces, say it breaks up b into pieces evenly, then there exists some element t such that a = atc but from these elements live inside an integral domain which has a structure such that we know 1 = tc. Maybe im having trouble conceptulizing why cancellation is being held, like in some diagrams we can imagine things as having some circular path, say the cyclic ring generated by an element. I was wanting to have a pictoral view of this proof similar to that where I could maybe diagram it

#

let me go refresh on integral domains and cancellation

pulsar flax
#

integral domains are exactly the rings where you have cancellation

static helm
pulsar flax
#

they are not positive integers

static helm
#

🫠

#

c and t both have magnitude 1 and thus c is unit

fossil drum
#

gonna take me a while I need to review back up on rings for a better understanding of their structure thanks for the help!

#

.close

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#
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rustic atlas
#

Let $E$ be the space of bounded real sequences with the infinite norm, $F \subset E$ be the set of convergent sequences and $G \subset E$ the set of sequence which converge to $0$.
$$\begin{enumerate}
\item Does there exist a linear bijective continuous map $F \rightarrow G$ which has a continuous inverse (homeomorphism)
\item Does there exist a linear bijective isometry $F \rightarrow G $
\end{enumerate}$$

jolly parrotBOT
#

bloubbloub
Compile Error! Click the errors reaction for more information.
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rustic atlas
#

stuck on the first one

#

I tried to express each element of G as the limit of linear conbinations of $(\delta_k)_n$ ($=1$ if $k=n$ and $0$ otherwise)

jolly parrotBOT
#

bloubbloub

rustic atlas
#

I'm not even sure if it exists

pearl pondBOT
#

@rustic atlas Has your question been resolved?

thin remnant
#

I think that can help get u started in a direction

rustic atlas
jolly parrotBOT
#

bloubbloub

rustic atlas
#

I don't think so actually

#

neither of them are compact

rustic atlas
#

wait

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F is connected so if G was open and closed it would either be F or the empty set, which it isn't

#

so the argument I gave should work right?

#

<@&286206848099549185>

pearl pondBOT
#

@rustic atlas Has your question been resolved?

pearl pondBOT
#

@rustic atlas Has your question been resolved?

plucky python
#

G is closed in F, but G is open in G

plucky python
plucky python
#

futher hint: ||what's a very crude way to take a sequence that converges to l and make it converge to 0?||

plucky python
pearl pondBOT
#

@rustic atlas Has your question been resolved?

pearl pondBOT
#
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minor tapir
#

hi can someone tell me if I did this correctly please?

pearl pondBOT
#

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brittle tinsel
#

sin(t) is not 1 - cos^2(t)

#

try using double angle formulas instead

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minor tapir
#

is my approach erong

pearl pondBOT
minor tapir
#

I think im tripping so hard

median swan
# minor tapir I think im tripping so hard

The limits of integration in basically all of the steps are wrong, but the calculations seem right. For the limits in the first line what are the allowed values for x in the original function?

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#

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rustic atlas
pearl pondBOT
#

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pearl pondBOT
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hearty fiber
#

Can anyone please help solve this

pearl pondBOT
proper nova
#

wth

hearty fiber
#

Wont this be correct instead?

proper nova
#

🙏

hearty fiber
#

I used the area identity to solve this but im getting two values of m but there is only 1 correct answer

acoustic latch
#

Hi guys I need help in math

proper nova
#

!occupied

pearl pondBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

hearty fiber
proper nova
hearty fiber
#

Area of shaded region is given i believe

proper nova
#

ah

#

i see it now

hearty fiber
#

As answer is x+y=2 in answer key so m=-1 only

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#

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eager jewel
pearl pondBOT
hollow sonnet
#

where are you stuck at?

eager jewel
#

like idk where to start

#

im thinking its an infinite gp kind of situation?

hollow sonnet
#

first, let's find the probability of P(A) and P(C)

#

is it stated how many sides are in this die

#

if not, we assume the numbers are from 1-6

eager jewel
#

yes 1-6

hollow sonnet
#

1 2 3 4 5 6
which of these are prime?

eager jewel
#

235

hollow sonnet
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so, what's the probability that rolling a dice gives a prime number?

eager jewel
#

1/2

hollow sonnet
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yes

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how about numbers that are neither prime nor composite?

eager jewel
#

only 1 right

hollow sonnet
#

(hint, there are only 2 numbers which satisfy this property. one of them is not on the dice, the other is 1)

hollow sonnet
#

do you know how to do the rest?

eager jewel
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uh no

hollow sonnet
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P(A) is true for 3 numbers

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P(C) is true for only one number

eager jewel
#

yes

hollow sonnet
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P(A)/P(C)=3/1

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do you still understand this part

eager jewel
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its not

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ans isnt 3

hollow sonnet
#

whats the ans then

eager jewel
#

9

golden bramble
eager jewel
#

i had put 3 only in the exam tho

hollow sonnet
eager jewel
golden bramble
#

Maybe it can help to consider it on a per-turn basis

eager jewel
#

P(A) = 1/2 + (1-1/3)(1-1/6)(1/2) + ....?

hot timber
eager jewel
#

cause 1/2 probability of getting A in first roll

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then for 2nd role we shouldnt get B on first roll and shouldnt get C in first roll

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so (1-1/3)(1-1/6)

golden bramble
#

but also A can't get it