#help-39
1 messages · Page 263 of 1
this part it gets fuzzy
if A is defined using some inequalities, you can break it up by setting 1 of them to an equality
but yeah in general this is probably the hardest step
Renato
mhm
for the interior of A, you need these both to be strict
so $y > 0$ and $2y + x^2 < 9$
Pseudo (Cat theory #1 Fan)
2y < 9 - x^2
0 < y < (9-x^2)/2
but
So, if we say $B = {(x, y) \mid y = 0 \land 2y + x^2 \leq 9}$, then $B = {(x, 0) \mid -3 \leq x \leq 3$
Renato
no this is the boundary
the boundary of $A$ is $C = {(x, \frac{9 - x^2}{2}) \mid -3 \leq x \leq 3}$
Renato
Pseudo (Cat theory #1 Fan)
what is B and C then
B is the interior
oh wait, you are saying the boundary of the region A is the union of the interior of the region A with what?
its like, B and C are partitions of A
like disjoint subsets of A
what about the interior of A?
I think you meant to say the interior of A is B ∪ C
or what?
no wait, A is a region, and B and C are partitions of this region (pairwise disjoint subsets of A, called B and C)
then, one of B or C is the interior of A, and the other is the boundary of A
You can break up $A = \text{Int}(A) \cup B \cup C$
Pseudo (Cat theory #1 Fan)
Both B and C are part of the boundary of A
Neither is the interior
If you sketch what B and C look like you’ll see what I mean
so B ∪ C is the boundary of A
ah, here you said it
one second, miss
the interior of A here is the system
- y = 0
- 2y+x^2 = 9
correct?
that is, x^2 = 9
so from that we get that either x = 3 or x = -3 are the interior points
I am trying to understand what the interior of the region A is first
to me it looks like a curve but
Nope
The interior of region A should be 2D
It might help if you use desmos
wait, I will pull up my calculator
@stoic imp https://www.desmos.com/calculator/emvaw6evyv
Check this out
B is the flat part of the boundary of A
C is the curved part
what am i looking at
You want the intersection of those shaded regions
That’s what I sent you
Yes
how
.
It’s the curved part of the boundary of A
.
yeah so B is y = 0, x^2 <= 9
no wait
no, that's correct
B = {y = 0, x^2 <= 9}
2y + x^2 <= 9
2y <= 9 - x^2
y <= (9-x^2)/2
y >= 0
0 <= y <= (9-x^2)/2
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I don't see how the answer is not 2
i only see triangle ABC and triangle DEC as isosceles
and there is obvi no equil triangles too so yeah
can someone please tell me what im doing wrong?
i already checked all the 7 triangles, unless im missing one idk
lemme think,what's awnser 2?
what are the isoceles triangles you've found?
I can tell you're missing a few
you might've missed ∆ABD being isoceles
how
find all the individual angles
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what does C^infinity(R) mean?
It's the set of smooth functions from R to R.
So it's telling you that d/dx maps smooth functions to smooth functions.
smooth being differentiable, infinitely many times
polynomials, exponentials, logarithms, trig functions for example
wait C^n means differentiable n times right
It means differentiable n times with continuous derivatives
Well if any nth derivative exists implicitly the nth derivative is differentiable, so continuous.
So it's enough to just say smooth implies any order derivative exists.
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
well 2
I did started using cylindrical coordinates
(x,y,z) = (rcos(♡), y, rsin(♡))
and simplified the inequalities of the region D
1 <= r^2(cos^2(♡) + sin^2(♡)) <= 16
1<= r^2 <= 16
rsin(♡)<=rcos(♡)
and
0<=y<=sqrt(r^2(cos^2(♡)+sin^2(♡)))
0 <= y <= sqrt(r^2)
I got stuck
I get
1<= r^2 <= 16
rsin(♡)<=rcos(♡)
0 <= y <= sqrt(r^2)
everything good so far? @warm current
I have a cheat sheet of the common quadric surfaces
Yeah so far you are doing fine
what am I missing here?
I might need some more help with this one
if possible handholding
is that okay?
What are your definite bounds for r and y?
I am assuming r is in between [1,4]
Why 1?
is r positive then
Try graphing $\sin\theta$ and $\cos\theta$ to figure out your bounds
SWR
first I need you to tell me when does sin and cos intersect
You need to figure this out
help
You can either use the unit circle, or you can use $\sin=1-\cos^2$
SWR
at 45 deg
ok great
sin = 1 - cos^2?
that's too advanced for me
Oops i meant sin^2
Radians btw
how does that
pi/4
Good. That's one. You just need the other
Where else on the unit circle is sin=cos?
let me use soh cah toa
You just need to know for which $\theta$ in $[0,2\pi)$ is $\sin\theta\le\cos\theta$
3pi/4
SWR
Yup. You have your bounds
I think this will be the hard part
knowing the graphs of sin and cos
also quick question dude
but
am I missing something here?
I know but I don't get why this doesnt include the intervals when cosine is on top
It feels like I am missing something here
Think of what polar coordinates are doing. Normally you are within the bounds of 0 to 2pi
yes
theta or ♡ is in between [0,2pi)
but how do you know
which one is above or below
idk if I am explaining myself
Using the graph you did
The graph tells you which one is less than the other
yes but for example
in between the intersections, in first case sine is above cosine
in second case cosine is above sine
and in third case sine is above cosine
sir
you here?
basically all of this 3 sections are in between 0 and 2pi, correct?
@warm current
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Renato
Can you rewrite the integtal in terms of limit?
this?
now can you compute inner integral?
try splitting up the numerator, doing a u-sub for the first integral, and maybe doing a comparison for the second integral
what's the first integral you get?
@stoic imp when you split up the numerator, you'll get two different integrals. the first one could be evaluated with a u-sub, the numerator looks similar to the derivative of the denominator
i just need to use comparison test for improper integrals
comparison test approach please
okay, try comparing to something like x^3 / (x^4 + 4)
Do you know this?
this is smoller
mmhm so does it converge or diverge
do you know how to integrate that smaller one?
i mean the point is to compare to something that you know how to integrate (or at least something you know converges/diverges)
$\frac{x^3}{x^4 + x^4} = \frac{1}{2x} \leq \frac{x^3 +5}{x^4 +4}, x \geq 2$
we know 1/x^p integral diverges
when p >=1
dotdoc
you could also use this,
compute the improper integral of 1/2x
what
you can always find an “a” above such that the inequality holds for all values larger than a
1/x diverges
oops sorry

you have to take care of the integral from 1 to 2
but it doesn’t matter since they diverge
using this you might estimate the impropert integral from 2 to infty
and add little part (don’t compute but it exists)
x^3 / 5x^4 works
we need to prove this is lesser
great idea but help me
with the inequality proof
x^3 <= x^3 + 5 true always
for all x >=1 yes
would be better if we can find something like this that works for x>=1
but we are close
this works
let me think
then we get 1/5 , int from 1 to infinity of 1/x
5x^4 >= x^4 + 4 for all x>= 1
yes
yep
you might want to prove this
4x^4 - 4 >= 0
x^4 - 1 >= 0
x^4 >= 1
x >= 1 <=> x^2 >= x >= 1
@lilac quartz
we can use transitivity
x >= 1 <=> x^4 >= x^3
x>= 1 <=> x^3 >= x^2
x >= 1 <=> x^4 >= x^3 >= x^2 >= x >= 1 <=> x^4 >= 1
for all x>1, (we can apply
montonicity of powers in this range)
x^4 >= 1 iff 4x^4 >= 4 iff 5x^4 >= x^4 + 4
great
basically adding to an inequality is always safe
the key step is montonicity in [1,inft)
for any a,b in [1,infy)
a < b implies a^n <= b^n
for any n in N
is proven
now wat
you are done, use this
help
$\frac{1}{5x} = \frac{x^3}{5x^4} \leq \frac{x^3 +5}{x^4 +4}, x \geq 1 \implies \frac{1}{5x} <= \frac{x^3 +5}{x^4 +4}$
the issue is that the 1/x^p idk how it works because for integrals with an infinity as bound diverges but for regular definite improper integrals it converges
p>=1
dotdoc
apply improper integral to last inequality
or what’s the improper integral from 1 to infy of 1/5x?
does it converge or diverge?
who the fuck knows at this point
“harmonic series”
this is a nice little summary i just found
is confusing because sometimes they do sometimes they dont depending on the bounds
just write out the limit definition of this
and compute the integral push the limit and see
alright let's see
the whole point of this exercise is computing smaller integrals
you can’t avoid that
you would be pushing something like log to infy
what what?
unsure what the range of ln is
what?
its just
just?
1/5 × ln|t) - 1/5 × ln1
what’s ln(1)?
who knows what the domain of ln is
0 ig
what’s your domain of integration?
The following error occured while calculating:
Error: Undefined function ln
bruh
1 to t
ye i just reme
yes
what do you get?
i don't know the range of ln
you should check then
but i presume the supremum of the range
or you should know at this point that it shoots to infy
,w lim n to infty of ln(n)
don't leave
what u studying
psychology
oh sht, gl
finding upper bounds proving etc
find bounds of?
doing side quests atp
set f:= 1/5x, g:= x^3+ 5/(x^4 +4)
a := 1
gl
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I don't understand the derivation
Why is there w_0 all of a sudden
The Eq 9.18e mentioned by the book is the reciprocal rule of complex number
Ohhh w_0 is 1/RC
Nvm
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I want to find the average(expected?) cost of random restart hill climbing
My confusion begins with how we can even define cost
please provide question
And secondly how it extends to n dimensions
do it... do it now!!!
That is the question
And thirdly to find cost for having some x% confidence interval
It's more helpful if you give me an actual framed question with a scenario and values instead of a general question about a generic procedure
I'll give it a shot but trust me it'll be more difficult
But it is in fact a general question about a generic procedure
what is random restart hill climbing
Simplifying it will kill it's essence
okay ill help u now
understood
If you don't know this im not sure you can help me.
Reiterating:
I want to find the average(expected?) cost of random restart hill climbing
My confusion begins with how we can even define cost
And secondly how it extends to n dimensions
And thirdly to find cost for having some x% confidence interval
<@&286206848099549185>
I am not sure you can even define an associated cost with the restarts
like the reason you actually restart is to check whether you got stuck at a local maxima
After each restarts there will be a cost required to reach the local minima righ
Right
like how many iterations you take to stably achieve the extreme?
sure
but thats not relevant to the reason you restart
and also, the initial steps are too quick, the time taken to converge depends on the behaviour in the small neighbourhood
That's why I'm talking about finding an average cost
Could you elaborate
wait, I might have been a bit confused. Am i correct assuming that the direction of movement is influenced by how much improvement is there? like would you be moving in the direction of climb by a fixed amount or would that be influenced by how much the improvement is?
would my $\vec{x}n - \vec{x}{n-1}$ be same as my $\vec{x}k - \vec{x}{k-1}$
βαχτϵρ10Φρ4γ
@tender egret Has your question been resolved?
I don't know myself 
well, no matter, what you are looking for is to cover a reasonably large subset of your domain over which you randomly start. so, I dont think there is any point in looking at a cost to random restarts. the aim is to be exhaustive, so you should not look at ways to reduce efforts here. The only reason you restart is that you dont end up missing the maximum of this unknown function.
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<@&268886789983436800>
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lol I thought you did the work and lance just lanced
(oh shit that's actual cinema here lol)
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Is this channel available?
Yeah, you just claimed it
Oh okay
You can read this @hollow oxide
Got it
Multiplication/Division in Different Bases in this problem I need to multiply the following but I'm stuck on problem d. Which is B12twelve×83twelve?
are you stuck on all the digits?
are you expected to do it in dozenal?
or do they expect you to convert to base ten first
kinda unclear from this question in isolation how you would be meant to proceed
aside from this, do you know the algorithm for multiplication in base ten?
They're expecting us to do it in Bases from base 2-12 this one is just base 12
From what I've known base 10 numbers are broken down to ones, tens, hundreds, thousands, and so on.
so they are
do you know how to do multiplication if both numbers are in base ten?
yes or no
No
so uhh. hm.
if i asked you to work out
731
* 43
-----
and these are just regular base ten numbers
would you know how to do it?
so you can't do multiplication of multi digit numbers even in base ten?
yes?
wait a minute
how were you able to do letters a-c
can you show me the entire worksheet
Wait does b stand for 11?
sure does
but op is having a bigger issue
she seems unable, by her own account, to do long multiplication at all
;-;
@hollow oxide can you take a photo of the whole worksheet please
Welp good luck on this one Ann
mmmm not what i was looking for.
with your answers to a) to c), please.
i was looking for this but uncropped to show the entire page!
aka the actual paper itself
I’ve done a to c but not d unfortunately
show us HOW you did a-c
!show is a wonderful blessing in this server; it says the following:
Show your work, and if possible, explain where you are stuck.
brb
ok look at part b
you do know the algorithm for multiplication
you know that you need to multiply each digit of the first number with each digit of the second
yes?
Yes
yes so
same idea here
now you just need to write down all the single digit dozenal multiplications that you will need
then proceed in the exact same way
she is having problem with the letters it seems?
let her say it
ok
I think I have to multiply by 3 in the ones place for problem d.
3 × 2 = is 6
3 × 1 = 3
3 × B = 3 × 11 = 33¹⁰ = 2(12) + 9 = 29¹² but I have to write 9 and carry the 2.
Next I need to multiply times 8 which is the twelve place
8×2=16¹⁰ =14¹² I need write 4 and carry 1
8×1=8, plus carry 1 = 9
Shoot
I'm stuck
I don't know what to do next..
never do this kind of math without writing it down
you risk confusion and chunking too big of an operation
Okay
your first round of multiplication looks correct though. write that down first, then do the second round separately
I think 8 × B = 8 × 11 = 88¹⁰ = 74¹²
So 8 × B12 = 7494¹² (shifted one place left) = 74940¹²
I get 2936¹²+74940¹²=
You had to?
No the problem is Identifying the place values in base 6
base 6?
And base 12
ok, this algorithm works on any base
and no, multiplication of the two intermediate results here is not what should be done
let's just take a simple example to show why
suppose you're asked to multiply 123 with 13
in base 10*
that does not justify the multiplication of the two intermediate results.
again, I'm about to show you why
sure then
what's your final answer then?
wait a sec
you added the intermediate results in this problem.
Yes
so why are you switching to multiplication now? adding is the correct step here
unless you mistakenly put the multiplication sign when you meant an addition sign?
Oh wait I think I mistakenly added a multiplication sign by mistake
Sorry
yes, that would be the correct step to proceed
I'm more surprised that you didn't double check when I pointed it out the first time, but it worked out in the end
hm. I got a slightly different answer
check.
specifically, your third digit seems to be wrong
every other digit is correct
Wait no it's
(also pedantic note, but don't indicate bases with superscripts. those are reserved for exponents)
77676¹²
Tairin
but yes, well done
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Does any know numeration systems unit. That is Egyptian, Roman, Babylonian, and Mayan numerals. It will also include converting between different bases and adding, subtracting, multiplying, and dividing in other bases as well.
So I'm hoping if anyone is aware of these kinds of subjects in math and helping me out?
A review on these math subjects
I just want to go over the numeration systems and numerals and I do want to go over different basses also
I desperately need the help I can get
These channels aren't for reviewing an entire topic
Feel free to ask specific questions
Oh...
Or I guess you can ask in https://discord.com/channels/268882317391429632/326138737606262786... not really sure what the appropriate channel would be
Nevermind then
I mean you can also keep this channel and wait for someone who would be willing to go through an entire topic
I'm not
Still, I'm happy to answer specific questions
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hi im having some trouble with ODEs and the Lipchitz condition. Whilst i get that its essentially sets a 'speed limit' as to how a function grows im not understanding why we let y vary and not x in a multivariate function.
So say f(x,y)
then lipchitz condition says that
|f(x,y2) - f(x,y1)| <= K|y2 - y1| y2,y1 E D
I'm also having trouble seeing how this links with ODEs
if someone could clear this up for me that would be amazing!
@bronze warren Has your question been resolved?
in case you dont get what you need here, you might try #real-complex-analysis or #odes-and-pdes
@bronze warren Has your question been resolved?
@bronze warren Has your question been resolved?
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How do I solve the sum of moment equation to get theta?
you can isolate tan(t) = some number then use inverse tangent
arctan(tan(t)) = t
theta is written as $\theta$, not $\varnothing$
riemann
arctan
and show the answer
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Ayo how do i do 6
Im familar with the idea of these questions but whats the formula
Whats the radius have to do with this
And am i basing this on the formula for volume of a cylindar, or which formula do i derive?
Oh wait
Yea i feel like sum is wrong here
Wait no dr/dt cuz the radius is constant
Wait na im lost af
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Have you figured it out?
Yea i gpted it
Number 6 should be related rates if I'm not mistaken.
Its about the idea of once part of the equation goes to 0
Since its a constant
Like dr/dt is 0
Which confused me
Does it still confuse you?
Lemme see if i can do # 7
Alright 👌
Nah les go i got the answer right
Its basically like
At one point u have to derive using the product or quotient rule
And one part of it is 0
I think atleast
Well, you have to relate things first and usually everything given should help you find out which formula to use
You have to establish first what you're looking for.
Since you're going with related rates problems, it usually involves formulas from basic geometry and it's on you to construct it in a way that the given of the problem would somehow relate to each other
Yea
Its mainly just these geometric shape formulas
And we did some triangle work but i didnt get to that review yet
But like 2 cars goes in directions that makes a right angle
Or a guy walking away from a light making a shadow
You should be good to go as long as you know your geometry formulas and you know what you're looking for
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Can u help with 8?
Some how i got 1/0.333 as my answer which is defo off cuz my entire r term cancelled out
Imma redo my work rq
Hello, let me solve it rq
did you put r in terms of h in your volume expression?
Wym
coz to me it looks like you didnt do anything to r till the very end
Like i didnt subsitute?
gimme the expression for volume in terms of only h
It should be 0.72cm/h
I lowkey dont know what that means
no, you didnt stubstitute before differentiating
Like what bacter said, you should first get the volume of a cone and express it in terms of h
you have v = 1/3 * pi * r^2 * h
now replace r with h
like properly according to their relationship
no
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you have this right?
Yea
use it
Oh
pls dont hand out answers like that
Right into the formula?
yes
My bad, didn't know. Will reflect on this.
It = 0
coz by some magic you seem to have put it 0
Derivtive of the constant i thought
yea, and obv thats not the case coz the radius is also changing with time as the volume changes
If r = 2/3
Ohh
well, in that case why is your dh/dt not 0?
like here you could have also subbed in h = 12r to calculate dr/dt in terms of dh/dt
but you didnt realize that
so its better if you do this substitution as soon as possible
I lowkey got a bunch of dr/dt
Idk if im supposed to have them
At this point in Calculus, you have not been taught how to evaluate multiple variables. Because there are three variables in the equation for the volume of a cone, you need to eliminate one of them. You can do that by using substitution which was provided to you by the relation h = 12r.
Does this look right
I remember my teacher going over cones but i passed out during that lesson
And thats = to dv/dt
Not for this problem.
Yes, it does ask for dh/dt.
And it gives you dV/dt.
That it your hint that you need to eliminate the r variable somehow.
if you did sub h earlier, then you shouldnt have any dr/dt's. But in case you didnt, you could still do dr/dt = d(h/12)/dt and end up with dr/dt = 1/12 * dh/dt and that would work too
Oh i see where i messed up
I subbed in 12r for h
But i think i should sub in h/12 for r
Would be easier
is it really, coz its like 1 step from here
just switch up r and h and from there you are back on route
yep, this is correct
Idk if ive ever seen
Quotient rule and power rule at same time
Its just 2(h/12’h
?
quotient rule?
why do you need that here?
Its just all big product rule
there is just one small chain rule, nothing else tbh
But idk ive never seen examples with a quotient and chain rule
Normally just like (x+q)^2
Got it
Gpt
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I think I'm having a brainfart
I'm getting -2/3 💀
what's wrong
$\int_{0}^{0.5} \int_{y}^{1-y} 8xy dxdy$
wai
So I would just begin by sketching 0 < y < x < 1
oh
got mt mistake
tq
I'll close this now
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So the formula here ie E(XY)-E(X)E(Y)
$\int_{0}^{1} \int_{0}^{1-y} 2xydxdy - \int_{0}^{1}\int_{0}^{1-x} 2ydydx \int_{0}^{1} \int_{0}^{1-y} 2xdxdy$
This feesls wrong
wai
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find all $x$ such that
$$\tan(x)=\tan(x+10^\circ)\tan(x+20^\circ)\tan(x+30^\circ)$$
degrees?
oh yea
ihave<skissue>
well symmetry makes me think that you should either sub u=x+15 or u=x+20
but dunno
huh
no idea how tf that happened
@dapper kraken Has your question been resolved?
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gtg sleep now, sorry
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is there an intuitive way to think about why being prime implies irreducibility in an integral domain
a = bc
a = atc if a | b
thus tc = 1 by cancellation
hmmmmm
like proof makes sense but not really getting it intutively
Why do these chats go on for so long? I'm new, and this isn't just one question right?
thats literally the same book im using for my probability class lol and I was just working on that problem not too long ago
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yk how factors of a prime are 1 and itself, kinda of just a proof of that. Assume it was the product of 2 numbers, you have now proven that one of those numbers is 1, and the other is the prime
at least that’s my take on it
I think the proof mentioned is itself intuitive
hm what do you mean by that
It just seems messed up cause if all the symbols and all
the proof makes perfect sense but Im having trouble picturing it
The statement is provable by definition of prime numbers itself
what do you mean “picturing it”?
like conceptualizing it, like the way I started to think about it was we have a = bc and that a is prime so we know a breaks up b or c into pieces, say it breaks up b into pieces evenly, then there exists some element t such that a = atc but from these elements live inside an integral domain which has a structure such that we know 1 = tc. Maybe im having trouble conceptulizing why cancellation is being held, like in some diagrams we can imagine things as having some circular path, say the cyclic ring generated by an element. I was wanting to have a pictoral view of this proof similar to that where I could maybe diagram it
let me go refresh on integral domains and cancellation
integral domains are exactly the rings where you have cancellation
if a = atc then 1 = tc and since t and c are positive integers, both t and c must equal 1
they are not positive integers
gonna take me a while I need to review back up on rings for a better understanding of their structure thanks for the help!
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Let $E$ be the space of bounded real sequences with the infinite norm, $F \subset E$ be the set of convergent sequences and $G \subset E$ the set of sequence which converge to $0$.
$$\begin{enumerate}
\item Does there exist a linear bijective continuous map $F \rightarrow G$ which has a continuous inverse (homeomorphism)
\item Does there exist a linear bijective isometry $F \rightarrow G $
\end{enumerate}$$
bloubbloub
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stuck on the first one
I tried to express each element of G as the limit of linear conbinations of $(\delta_k)_n$ ($=1$ if $k=n$ and $0$ otherwise)
bloubbloub
I'm not even sure if it exists
@rustic atlas Has your question been resolved?
A homeomorphism preserves metric properties of the two spaces
Think about a few general key properties of metric spaces and see if they coincide for F and G
I think that can help get u started in a direction
would it work if I did something like this:
define $\phi: u \in F \mapsto \lim_{n \rightarrow \infty} u_n \in \mathbb{R}$. $\phi$ is continuous for the infinite norm. Then $G = \phi^{-1} ({0})$ so $G$ is not open in $F$ whereas $F$ is open in itself so they can't be homeomorphic?
bloubbloub
wait
F is connected so if G was open and closed it would either be F or the empty set, which it isn't
so the argument I gave should work right?
<@&286206848099549185>
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but i mean our topology is in G right?
G is closed in F, but G is open in G
anyway for the first part you have some good ideas
||hint: ^ limit map is cts as you said||
futher hint: ||what's a very crude way to take a sequence that converges to l and make it converge to 0?||
(also btw the existence of part ii strongly suggests ||the answer to the first part is yes, cus otherwise if the answer to the first part is no that immediately implies the answer to the second part is no||)
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hi can someone tell me if I did this correctly please?
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is my approach erong
I think im tripping so hard
The limits of integration in basically all of the steps are wrong, but the calculations seem right. For the limits in the first line what are the allowed values for x in the original function?
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I mean I could substract the limit from the sequence but that wouldn't be bijective
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Can anyone please help solve this
Wont this be correct instead?
what do they mean by area of 4 lines when these 4 lines only make a triangle (y = 0 makes no sense of role)
🙏
I used the area identity to solve this but im getting two values of m but there is only 1 correct answer
Hi guys I need help in math
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the language is kinda ambiguous took me some time to understand it too 😅
how do you understand it?
Look at this graph i drew
Area of shaded region is given i believe
I used the area Identity and im getting 2 values of m can you help me understand how do I eliminate 1
As answer is x+y=2 in answer key so m=-1 only
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where are you stuck at?
first, let's find the probability of P(A) and P(C)
is it stated how many sides are in this die
if not, we assume the numbers are from 1-6
yes 1-6
1 2 3 4 5 6
which of these are prime?
235
so, what's the probability that rolling a dice gives a prime number?
1/2
only 1 right
(hint, there are only 2 numbers which satisfy this property. one of them is not on the dice, the other is 1)
uh no
yes
whats the ans then
9
Have to consider turn order
i had put 3 only in the exam tho
damn
yes this is what i need help with
Maybe it can help to consider it on a per-turn basis
P(A) = 1/2 + (1-1/3)(1-1/6)(1/2) + ....?
Yeah that’s what I was thinking as well
cause 1/2 probability of getting A in first roll
then for 2nd role we shouldnt get B on first roll and shouldnt get C in first roll
so (1-1/3)(1-1/6)
but also A can't get it


