help-38

[trim jolt]

Channel closed

Closed by @dapper lance

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful zenith]

idk where to begin tackling the problem

[dapper swift]

Do you need permutations or combinations?

[graceful zenith]

both right?

[dapper swift]

Nope, you only need to use one of those two

Can the students be distinguished apart in the same group, or can they not?

[graceful zenith]

they can't

[dapper swift]

Yeah so you need combinations

Cause the order doesn't matter

[graceful zenith]

wait wouldn;t it just be 10C4

[dapper swift]

Nope, you're still choosing 6 students

Also from the question, student A can be selected but student B cannot

And student B can be selected while student A is not

[graceful zenith]

alr

[dapper swift]

And of course students A and B could both not be selected

[dapper swift]

This is the easy part

So yeah the 'permutations' is actually just multiplying by 1 number

[graceful zenith]

alr

ok so u can't select 2 particular students

so 8 options

and we're choosing 6

so 8C6?

[dapper swift]

Yes, this is the case when A and B are both not selected

Wait I think that's just the answer sorry

[graceful zenith]

alr

[dapper swift]

Wait no

[dapper swift]

Yeah okay you need these two cases too

[graceful zenith]

alr

[graceful zenith]

8C5 x 2?

[dapper swift]

Should be (ways to select B) - (ways to select B and A)

Yeah so if B has to be included, then it's 1 * 9 choose 5

But then if B and A have to be included, it's 1 * 1 * 8 chose 4

[graceful zenith]

alr

[dapper swift]

Yeah it helps to break the problem up into smaller and smaller cases

[graceful zenith]

yea

[dapper swift]

Well I guess I lied when I said you don't need perms
You're technically using perms but then you're just multiplying by 1

[graceful zenith]

lol

alr tysm

i got 140

and i checked and its right

[dapper swift]

Wait I think I'm undercounting

Oh wait no

[dapper swift]

Ayyyyyy

(I did 56 + 28 + 28 accidentally haha)

Yes now I get 140

[graceful zenith]

ye

thx

.close

[trim jolt]

Channel closed

Closed by @graceful zenith

Use .reopen if this was a mistake.

[dapper swift]

No worries

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flat wing]

can someone help explain this question

[flat wing]

since i dunno if im reading it wrong or if the answer is qrong

because why when t = 0 x^. is = 0

when the question says when t = 0 the velocity is u

[trim jolt]

@flat wing Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense rover]

is this correct

[dense rover]

sorry for bad handwriting

[zinc dove]

No, dy/dx should be 3x^2-3

Power rule

All minimums and maximums have a derivative of 0 but not all points with derivative 0 are mins or maxs

[dense rover]

okay, but it would still = 1?

because sqrt of 1 = 1

i think

[vernal warren]

Could be negative or positive 1

[dense rover]

oh right, so does this mean i have to redo everythign else?

[vernal warren]

No do the same with -1

[dense rover]

ohh right, so i have 2 answers

[trim jolt]

@dense rover Has your question been resolved?

Channel closed

Closed by @dense rover

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid kiln]

Ransik

[ionic pendant]

chain rule applies

[trim jolt]

Channel closed

Closed by @sand bison

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west whale]

What is the average distance between a surface S and the origin (0,0,0) ?

[west whale]

which formula do i use for this ?

the surface is a parametrized surface btw

do i use this: integral integral sqrt(x^2+y^2+z^2) dS ?

[trim jolt]

@west whale Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west whale]

What is the average distance between a surface S and the origin (0,0,0) ?

[west whale]

which formula do i use for this ?
the surface is a parametrized surface btw
do i use this: integral integral sqrt(x^2+y^2+z^2) dS ?

[edgy willow]

yea divided by integral of 1

[west whale]

what

why ?

[edgy willow]

as in the surface area

like how for an average you divide by the number of items, for calculus stuff you divide by the number of points basically

[west whale]

ok but

i dont have a number of points

[west whale]

is this good ?

[edgy willow]

here's an example from something else

[west whale]

hmm

ok

[edgy willow]

like if your surface is twice as big your integral would be twice as much even if the average is the same

so you just divide to take that into account

[west whale]

so i divide by the surface area

[edgy willow]

ya

[west whale]

ok could i ask you something else too ?

[edgy willow]

sure

[west whale]

a is a positive constant

the question is : for which a is the center of mass above z=1 and the density is constant

it's also mentioned that solving this problem directly is not recommended

i tried and it's near impossible to simplify the M_xy / m

what other method could we try ?

[edgy willow]

yea you have to hope there's some symmetry that cancels things

[west whale]

i assumed that x and y are symetric

i tried to find z^-

[edgy willow]

like if it was a helix curling up the z axis you don't really care where the curve is and can just look at the k-arrow values

I'm trying to figure out what this surface even looks like but there's something with how the v cycles from 0 to 4pi and goes all around

[west whale]

it looks like a screw or the helicopter that leonardo da vinci invented i think

[edgy willow]

chances are you'll be able to reduce it to a 1-dimensional avk and just integrate that

do you have a picture?

[west whale]

how do i do that

let me geogebra it

quite glamorous

[edgy willow]

ok cool I got this

so like a helix but you draw towards the axis

[west whale]

ig

[edgy willow]

so the symmetry is that if you just look in the z-direction, it's all the same amount of mass at every height

[west whale]

hmm

[edgy willow]

like it might as well just be a straight line up

[west whale]

yhea

i thought about that intuitivly

[edgy willow]

there's probably a way of writing it in cylindrical coordinates or whatever

but now it's av*k center of mass above 1

[west whale]

changing a means squeezing it or extending it

[edgy willow]

just find how high the line goes in terms of a, and the center of mass is halfway

[west whale]

yhea

ok ill try that

[west whale]

for the previous question, why does doing that integral work ?

integral integral sqrt(x^2+y^2+z^2) dS ?

[edgy willow]

do you know that sqrt(x^2+y^2+z^2) is 3d distance

[west whale]

yhea

i came up with this

but it was a guess

[edgy willow]

in general for averages you add up each item times its value and divide by the number of items

integral of that sqrt adds up all the distances basically

[west whale]

my issue is with dS

[edgy willow]

like how center of mass is integral of the mass

[west whale]

yhea ok ill just apply it

alr

thank you very much

[trim jolt]

@west whale Has your question been resolved?

Channel closed

Closed by @west whale

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell basalt]

need help with this please

[low gazelle]

What does it mean for a quadratic to be a perfect square?

[shell basalt]

well a perfect square is like

x^2-4

which simplifies to (x+2)(x-2)

two solutions?

or two rational solutions that just have opposite signs

idk

[low gazelle]

A perfect square is something that can be written in the form a^2. In the case of quadratics it would be a quadratic that can be written as (ax+b)^2

[shell basalt]

Minus... Minus... my bad

[shell basalt]

oh thats what u mean

like 4

is 2^2

16 is 4^2

[low gazelle]

ye

[shell basalt]

yeah i knew that idk why i forgot it

[low gazelle]

An example of a quadratic would be x^2+4x+4=(x+2)^2

[shell basalt]

yep

[low gazelle]

There is something special about the solutions of an equation of this form. Do you know what it is?

[shell basalt]

uh

this particular equation or just any equation in the form of ax^2+bx+c

[low gazelle]

Any quadratic that is a perfect square, i.e. it can be written as (ax+b)^2

[shell basalt]

one solution

[low gazelle]

Exactly

[shell basalt]

oh this whole time i was thinking of DOPS

idiot

so i couldnt fathom why the answer was to set the discriminant = 0

because that means 1 solution not two

[low gazelle]

Ah yeah

[shell basalt]

its always the most simple mistakes

So I just set the discriminant = 0 and solve for P right

[low gazelle]

Yeah

[shell basalt]

alright thank you

[low gazelle]

np

[shell basalt]

.cvlose

.close

[trim jolt]

Channel closed

Closed by @shell basalt

Use .reopen if this was a mistake.

[rugged latch]

@low gazelle started and about to finish volume 3 today

[low gazelle]

Damn bro im still on volume 2

How long does it take you to read a volume

[rugged latch]

not sure, i havent timed myself

but im a very fast reader so

and plus ive read a ton of ln's in the past

so

[low gazelle]

I see. This is my first ln so im quite slow

[rugged latch]

dont u notice how we see a lot more of his personality in the ln?

[rugged latch]

ah

like in the anime, it just seems like hes some stoic, cunning mastermind

but in the ln, he actually has normal emotions

[low gazelle]

I forgot a lot about the anime but it does seem like he has way more personality

[rugged latch]

yea like he gets nervous around girls, and embarassed in front of the class sometimes

never woulda expected that when watching the anime

[low gazelle]

Yeah he just like me - the smart manipulator part

[vagrant marsh]

#discussion ?

[rugged latch]

its fine this channels closed

[vagrant marsh]

_>

[rugged latch]

lol

idk if thats a good trait to have

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[magic saddle]

Please help me solve this cyclic quad question (geometry)

[main tusk]

i cant help with this btu help what is this 😭

[magic saddle]

wdym 😭😭

[main tusk]

this is why i hate geometry

[marsh forum]

to start find angle EBD

and angle AEB

[magic saddle]

is angle AEB isosceles?

[marsh forum]

hint:- AED=90

[magic saddle]

90-36?

[marsh forum]

yes

how you can angle EAB

*now

[magic saddle]

would AEB be 108 degrees?

[marsh forum]

how?

90-36

[magic saddle]

54 x 2

[marsh forum]

where did 54 come from

[magic saddle]

90 - 36

[marsh forum]

so angle AEB is just 54 deg

[magic saddle]

ohh right

so AEB is 54

so now i find EAB?

[marsh forum]

next find angle EBD

and EAB

then use properties of cyclic quads

sorry got to go now, I can't help anymore

[magic saddle]

thats okay! thank you

.close

[trim jolt]

Channel closed

Closed by @magic saddle

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone mauve]

for the first one

we have pivots

but 1's above

using RREF we can make it clear?

[1,00],[0,1,0],[0,0,1] after RREF?

[stark pilot]

you'd need column operations too

but its fine

you can ignore them

[lone mauve]

so for the first one it's C?

for the second it's A?

[stark pilot]

yeah

[lone mauve]

yeah, I think I see it now

second is A

[stark pilot]

nope

second is also c

[lone mauve]

oh

even with the zero vector?

[stark pilot]

wait

nevermind

[lone mauve]

can it be both A and B for second?

yeah that first one messes things up

because same scalar will apply to x and z

so it won't be able to span full R^3

even if they are linearly dependent

it doesn't span R^3

i understand that correctly?

[stark pilot]

does the 0 vector mess up the linear independence though

I think it does

according to the definition

[lone mauve]

hmmm

[stark pilot]

so both A and B

[lone mauve]

right

this one is a bit more tricky

same thing? that zero vector causes A?

but in this case it's the fourth vector, so a bit different

[stark pilot]

A and B

[lone mauve]

incorrect

maybe in this case it does span?

the 0 vector is just extra?

[stark pilot]

what

the site is tripping

[lone mauve]

should i use RREF to check for A?

or is it already obvious

with that third column

[lone mauve]

it spans R^3

[stark pilot]

oh

brain fart

i thought 1st and 2nd vector were dependent

sorry

[lone mauve]

np

[trim jolt]

@lone mauve Has your question been resolved?

Channel closed

Closed by @lone mauve

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steel spruce]

Can I have some help making sense of this picture for the question?

[steel spruce]

I believe the general solution it asks for would be
200 = x1 + x2
40 = x1 - x3 -x4
60 = x4 + x5
100 = x2 +x3 - x5
is that all I have to do for i)
and then put this into a matrix
to know its shape, I could rref it, right?

[trim jolt]

@steel spruce Has your question been resolved?

[steel spruce]

<@&286206848099549185>, I would like guidance for the right step

[supple copper]

That looks like it makes sense

[steel spruce]

so that is for i

ii is putting it into a matrix and rref right?

[supple copper]

Yeah

Just for your information I have not learned about these 2 things together

I know about networks and LA but not how they interact

So I’m just going off intuition here

[steel spruce]

This goes from

to this

Due to having 3 piviots, could I say the shape is a plane in R^5

How can I find iii) <@&286206848099549185>

[trim jolt]

@steel spruce Has your question been resolved?

[steel spruce]

Could I have some help <@&286206848099549185>

[molten vine]

What with

Ok

Hold up 1 sec

Welll,ll I’m afrad you need to learn this sorry

[steel spruce]

.close

[trim jolt]

Channel closed

Closed by @steel spruce

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac hawk]

Is it possible to solve for n without the use of a calculator?

[knotty locust]

yes

[rough goblet]

yep

[lilac dagger]

Yes (triple confirmation is better than double)

[rough goblet]

xD

[knotty locust]

https://tenor.com/view/star-wars-episode1-the-phantom-menace-qui-gon-jar-jar-binks-gif-22129926

[lilac hawk]

could you please show me how i can do that? thanks 👍

[lilac dagger]

Take the log of both sides

[lilac hawk]

without a calculator 😭 ?

[lilac dagger]

Whoops

In that case

Since the base of all the numbers are the same

You can ignore them

So

4n=3+1

and solve for that

[lilac hawk]

simplifying right side gives u 30 and 3^1 isnt 30 which is the answerr to this??

[lilac dagger]

Welp that didn’t work

Then in that case you’re still gonna need log

So your answer will be something like

4log(3^1/5) or something

[lilac dagger]

I must be tripping I swear that worked before…

You can still solve for n it will just be in log form, not decimal form

[trim jolt]

@lilac hawk Has your question been resolved?

[lilac dagger]

Combine the right hand side

And take log base 3 of both sides

Then divide by 4

That’s your answer

[lilac hawk]

Could i get an answer without a log in it??

[lilac dagger]

I don’t think so

It’s like how your answer could be sqrt(2)

Is the simplest you can go without a calculator

It’s still a value that you can use

I guess you can try waiting for someone else but I don’t think you can get rid of the log

[lilac hawk]

alright thank you

.close

[trim jolt]

Channel closed

Closed by @lilac hawk

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[regal bough]

differentiate it first

[regal bough]

f'(1) x f'(-1/2) = -1

use that expression

product of perpendicular slopes is always -1

[sacred wing]

is that differentiation right?

[regal bough]

f'(x) is derivative, yes

[sacred wing]

so i js sub in 1 and -1/2

[regal bough]

yeah

into x

did u get it?

[sacred wing]

think so nearly done

[regal bough]

once done, type .closed to allow other users to use the channel

[sacred wing]

so after i get both values they both have to times to equal -1?

[regal bough]

yes

[sacred wing]

thanks so much

.closed

[regal bough]

jus .close

mbmb

[sacred wing]

.close

[trim jolt]

Channel closed

Closed by @sacred wing

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[supple saffron]

good

[dapper swift]

What

[trim jolt]

@supple saffron Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pastel ingot]

can anyone tell me the all factors of 105

[wraith hinge]

Do you know what factors Are?

[shrewd ridge]

there's 8

just start naming them and stop when you have 8

[pastel ingot]

yeah but i cannot solve this one

[wraith hinge]

What I would do is take their LCM

You know the long division method

[dapper swift]

What is a number that divides 105?

We're looking for the prime factorisation

[wraith hinge]

Yeah this

[pastel ingot]

ok done i have solve it

[wraith hinge]

Prime factorisation not LCM, my bad

[cosmic meadow]

Could you tell us the solution?

[pastel ingot]

yeah the factors of 105 : 1,3,5,7,15,21,35 and 105

[dapper swift]

Nice, that's all correct

[dapper swift]

You can get there from 3 * 5 * 7 = 105

Then, choose one number out of the following numbers to multiply together:
1, 3
1, 5
1, 7

[dapper swift]

There are 2 choices each so 2^3 = 8 in total

Or 8 factors

[pastel ingot]

i see

[dapper swift]

Yeah if you do competition maths

A similar argument shows you that if you have (p1)^a * (p2)^b * (p3)^c * ....

Where p1, p2, p3 are prime numbers

And a, b, c are integers which are positive or 0

Then the number of factors is (a + 1)(b + 1)(c + 1)(d + 1)....

[trim jolt]

@pastel ingot Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zealous sigil]

Hi, I was hoping someone could help me with this. Is the number of elements in the set A x B always the number of elements in A multiplied by the number of elements in B even if we have empty sets in there etc.? Thanks!

[dapper swift]

Yes, the number of elements in the Cartesian product is equal to that

You include the empty set separately ofc

[zealous sigil]

Alright, I just wanted confirmation. Thanks so much. Have a great day.

[dapper swift]

Yes it's just this

Npnp

Have a great day too

[zealous sigil]

Hi, are you still there

I just wanted to confirm something else

If that's okay

[dapper swift]

Ok that's fine

[zealous sigil]

What would something like this be?

Is it like this? But I swear this doesn't even really make any sense

[dapper swift]

https://math.stackexchange.com/questions/997196/cartesian-product-and-the-empty-set

So the Cartesian product would have the second entry being the empty set

[zealous sigil]

So like this?

[dapper swift]

No, you need the empty set symbols

[zealous sigil]

So like this?

[dapper swift]

${(2, {\emptyset}), {3, {\emptyset})}$

[solid kiln]

south
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[zealous sigil]

Because I keep seeing stuff like this

So I was confused

[dapper swift]

Well yeah that's a bit of a notational shorthand

{{∅}, {∅}} = ∅

Only for the empty set

[dapper swift]

Wait I don't think this is right, let me check

Ah right it is

[dapper swift]

Yeah okay the Cartesian product of any set with the empty set is the empty set itself

[zealous sigil]

Because I actually just wanted to know the number of elements in the cartesian product of these 2 sets

Because I wanted to know if this would still be no. of elements in first set * no. of elements in the second set

Or something else because of that empty set in there

[trim jolt]

@zealous sigil Has your question been resolved?

[trim jolt]

@zealous sigil Has your question been resolved?

[trim jolt]

@zealous sigil Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac ridge]

Hi i have no clue how to continue

[lament plaza]

continue what

i think you should continue living

dont give up

[lilac ridge]

The picture is slowly sending AH

[lament plaza]

i see

dont kys tho

[marsh forum]

AH?

[lilac ridge]

No i never intended to 🤧🤧

[lament plaza]

expression ig

[lilac ridge]

Yeah expression

[lament plaza]

https://tenor.com/view/fist-bump-pewdiepie-pewds-later-bro-fist-gif-18807132

[lilac ridge]

Sorry

Oh finally

[lament plaza]

too many radicals

i give up on life

[lilac ridge]

Nooo

[marsh forum]

!original , please

[trim jolt]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[lament plaza]

yes

original ques pls

[lilac ridge]

Okay. I don't know how to continue

[shrewd vessel]

was this the question you asked earlier?

[lament plaza]

do you have the original ques

[lilac ridge]

Yes.

It didn't worked that way you told me

[lament plaza]

ohh

do we have to simplify it ?

[lilac ridge]

Aha yes

[lament plaza]

i fuckin hate radicals

imma try tho

[lilac ridge]

Do i look like i like em? I hate them to be honest

[lament plaza]

my idea is to assume rt x to be a and rt y to be b

just to make it more nicer

[lilac ridge]

What? To change letters?

[lament plaza]

yes

so i dont have to play with radicals

nd just deal in cubes and squares

See if i can find an indentity

[lilac ridge]

I cant write this all again its painful

[lament plaza]

https://tenor.com/view/youre-a-fucking-disappointment-soldier-boy-jensen-ackles-the-boys-im-so-disappointed-in-you-gif-26161747

[lilac ridge]

Okay. I will rewrite.

I will put x as o and y as p

Is that ok?

[lament plaza]

yes anything ur choice

but beware

its just an idea i have
im trying too
its not looking so promising

[lilac ridge]

Okay

[lament plaza]

Phony PHONY

I GOT IT

omg

is the answer 3sqrty

[shrewd vessel]

okay those arrows were terrible but I hope you can see that they are arrows, those are steps where you made mistakes

[lament plaza]

she made a mistake when she tried dealing with it as radicals

[shrewd vessel]

I felt the errors raised from cancelling factors in numerator and denominator tbh

I mean sure rewritting the letters would be nicer

[lilac ridge]

Lemme se

[lament plaza]

💀

i think i got it tho
my method was beautiful

[lament plaza]

it was better before

[lilac ridge]

Hm

[lament plaza]

$( frac{ x sqrt{x} - y sqrt{y} }{x - sqrt{x} sqrt{y} } - frac { x- y} {sqrt x + sqrt y} )( frac{sqrt{x} sqrt{y} + 2x }{3x})^{-1}$

[solid kiln]

Singularity

[lament plaza]

😭

[lilac ridge]

So i should like not multyply them

I don't get it

[lament plaza]

did you follow what i said?

it makes it so much more easier

[shrewd vessel]

[lament plaza]

do you want me to post my working?

[lilac ridge]

Aha i think i see

But if you want, show me

[lament plaza]

no need if you got it

[lilac ridge]

Sure

[lament plaza]

but did you get it tho

[lilac ridge]

I even started writing it for you

[lament plaza]

goated

[lilac ridge]

Okay

Thank you both

.close

[trim jolt]

Channel closed

Closed by @lilac ridge

Use .reopen if this was a mistake.

[lament plaza]

answer should be 3 rt y

thats what i got ??
do you have the key?

[lilac ridge]

Yes that's the jey

Key

[lament plaza]

nice

[lilac ridge]

You know stuff,respect

[lament plaza]

it was trivial the subsitution part

advice : whenver you see long ass radicals try to substitute it

are you freshmen by any chance or lower?

[lilac ridge]

.reopen

[trim jolt]

✅

[lilac ridge]

I go to highschool ah

[lament plaza]

i k (it says in ur roles)

but are you highschool freshmen or soph or smth

[lilac ridge]

I am not a freshman

But i am third year yea

. close

. close

.close

[trim jolt]

Channel closed

Closed by @lilac ridge

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[reef plaza]

How would one work out the standard deviation of the sum of two six sided dice

[marsh sigil]

calculate all possible results of both dice

[reef plaza]

yes

[marsh sigil]

all the combinations: 1&1 = 2, 1&2 = 3, ....6&6 = 12

[reef plaza]

produce a table of counts

[marsh sigil]

yes

[reef plaza]

But i need a formula

of som,e sort

[marsh sigil]

oh ez

[reef plaza]

coz for 2 six sided dice its easy

but i have 10 10-sided dice

that becomes a little harder

[marsh sigil]

oh formula for all?

whats the formula for 6?

[reef plaza]

i ddint use one

[marsh sigil]

hmmmmmm

[reef plaza]

its okay

i found one

[marsh sigil]

oh show me pls

im curious

[reef plaza]

https://math.stackexchange.com/questions/2686063/standard-deviation-for-sums-of-fair-dice-given-the-number-of-dice-and-the-numbe

couldnt have derived that

to save my life

[marsh sigil]

yes, 2 fractions in a root

oof

[trim jolt]

@reef plaza Has your question been resolved?

Channel closed

Closed by @reef plaza

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp hemlock]

Given is the function f with 𝑓(𝑥) = 2𝑥 3 - 9𝑥 2 + 12𝑥 - 5. Let its graph be K. Show that K and the straight line g with 𝑔(𝑥) = 4.5𝑥 - 3.25 touch at the point x = 0.5.

Pic is the solution.

I just inserted 0,5 in both functions, why do they derivate here also? THanks in advance:=)

[trim jolt]

Please don't occupy multiple help channels.

@sharp hemlock Has your question been resolved?

[limpid dawn]

If they really touch and not intersect then they also have the same slope

at x = 0.5

g is basically tangential to K at x = 0.5

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zealous canopy]

does anyone know if there is a formula that you can use to calculate the stability of electron orbitals?

[zealous canopy]

.close

[trim jolt]

Channel closed

Closed by @zealous canopy

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

how would i sketch the polar curve of this polar equation on an x-y axis

this has to do with polar coordinates

[nimble stone]

x=rcos(theta), y=rsin(theta) r^2=x^2+y^2
if youre sketching in the x-y plane, make use of those

[wraith hinge]

ok then

[nimble stone]

its at the origin when theta is 0, its at the origin a total of 4 times

what do you think

[wraith hinge]

yea i thought about this and i believe its the third one that loops

[nimble stone]

which is the third one

[wraith hinge]

actually wouldnt it be the 2nd onen that has two mini circles and then one big circle

cuz that touches the origin

[nimble stone]

the third one never even goes to the origin

the second one is the one id go with

[wraith hinge]

ok then thank u

[trim jolt]

@wraith hinge Has your question been resolved?

Channel closed

Closed by @serene matrix

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brave cloak]

How do I do the part circled

[brave cloak]

So far I've done:

z^k = cos(ktheta) + isin(ktheta)
z^-k = cos(ktheta) - isin(ktheta)

that solves the first two parts

no idea where to even begin with the third part

[vernal briar]

Add these two equations together

[brave cloak]

2cos(ktheta) = z^k + z^-k

would that count?

it's meant to be in terms of z, but that includes k in the powers?

Hm, apparently you're right according to the marks scheme

I guess it's just bad wording or I don't understand how "in terms of" works

[vernal briar]

Well k is a positive integer

cos(ktheta) is going to have to depend on k aswell obviously

Because it has k in it aswell

You're supposed to think of k as a constant

[brave cloak]

Ah, fair enough

ty for the help

.close

[trim jolt]

Channel closed

Closed by @brave cloak

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt mulch]

$y=t+2$

[solid kiln]

Civil Service Pigeon

[burnt mulch]

$-3<t<3 \implies -1<t+2<5 \implies -1<y<5$

[solid kiln]

Civil Service Pigeon

[trim jolt]

Channel closed

Closed by @late island

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[left aspen]

hey guys I have a question

[left aspen]

so we calculated I3 and I1 from the second and third formulas

And I have a question

Why can't I replace I_3 in the second formula with the thing that we calculated (-4I_2 + 10j)?

When I did, I got I_2 but when I applied I_2 back to that I_3 formula (and we have to know the value of I_3) I got infinity

[trim jolt]

@left aspen Has your question been resolved?

[left aspen]

<@&286206848099549185>

[trim jolt]

@left aspen Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

Is this right?

[edgy willow]

V is right, SA I'm not sure what your method is, like where 11+24 comes from, I get a different number

[hollow basalt]

yeah for sa i got another number too

i got 24 * 24 * 4+(24 * 24-11 * 11) * 2+24 * 11 * 4 = 4270

[wraith hinge]

Ok thanks guys

[hollow basalt]

moment 😑

[wraith hinge]

.close

[trim jolt]

Channel closed

Closed by @novel geyser

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[heavy geyser]

correct me on this because i made a mistake

How is this G, i got F because

y = 3/5x +b
4 = 3/5(-6) + b
4 = -18/5 +b
2/5 = b

y = 3/5x + 2/5

[heavy geyser]

i checked the key and it said it was G

[weary cobalt]

that is so goofy

wait thats not even right

parallel lines have the same slope

so m would be 3/5

and then u just substitute the point into the equation and solve for b

[heavy geyser]

i did that

[shrewd vessel]

your mistake is when you went from the third line to the fourth line

[heavy geyser]

i added 18/5 to 4

[shrewd vessel]

which is?

[weary cobalt]

4 = 3/5(-6) + b
4=-18/5 + b
4 + 18/5 = b
20/5 + 18/5 = b
b = 38/5
y= 3/5x + 38/5

[heavy geyser]

it was a typo 💀

LMAO

my bad yall

😔

[shrewd vessel]

hehe no worries, everyone makes mistakes

[heavy geyser]

atleast i was doing my method correctly

phew

.close

[trim jolt]

Channel closed

Closed by @heavy geyser

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen marsh]

Kinda bizarre question for an intro proofs class:

A self-descriptive sequence (SDS) is a sequence of 10 integers 0-9 where the index of a number indicates how many instances of the index number appear in the sequence. The first number in the sequence is at index 0, the second number is at index 1, and so on. For example, an SDS with a 7 at index 1 indicates that there are 7 instances of the number 1 in the sequence.

We are supposed to prove that no SDS can exist. I reasoned through it in class starting from index 9 and worked down from there. However i'm at a loss for how to prove it. all I know is that we're supposed to use cases.

[trail ingot]

the elements in the sequence need to sum to 10 right

[keen marsh]

no

there can be repeats

oh wait

i'm dumb

yeah the sum couldn't exceed 10

[trail ingot]

it needs to be exactly 10

else it's not a 10 length sequence

[keen marsh]

yeah

i'm just trying to figure out what my "cases" for the proof would be

i have an inkling that it'd be a fixed 0

but i'm not sure

[trail ingot]

yea maybe something to do with 0s

[trail ingot]

by this for example, if there are no zeros the only possibility is 1,1,...,1

which is not self-descriptive

[keen marsh]

yeah

if they're all 0s it woulnd't be self descriptive either

index 0 must not be 0 in any case

because that's not self descriptive

[trail ingot]

ok me has an idea

ugh the index starting at 0 is a pain for what i'm about to describe

let's just look at the last index. say it's 2 (or larger than 2). then there must be two 9s elsewhere. so the sum is too big

so the last index can only be 0 or 1

similar with any index 5 or greater

those only have 2 possibilities

index 3 and 4 can't exceed 3

actually we can get tighter bounds than this

but do you see what i mean?

[trim jolt]

@keen marsh Has your question been resolved?

[trail ingot]

ok upgrade to my idea

can you see why this is true?
if S is a self-descriptive sequence then we can't have S_9 > 0

the intuition is basically: an element being nonzero has a large consequence on the sum of the elements

if you make index 5 a 2, then you need to put 2 other 5s in the sequence, which is already too big

and those 5s even force other numbers to show up which makes it even bigger

[trail ingot]

ok spoiling this: say you make index 9 a 1. then a 9 has to show up elsewhere. if it's not at the zero index, then other numbers need to show up and the sum is too big. if it is at the zero index, you don't have room for 9 0s (there is already a 1 and a 9, so only 8 left)

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[trail ingot]

.reopen

[trim jolt]

✅

[trail ingot]

index 9 being greater than 1 is impossible since the sum immediately exceeds 10 in that case

so this forces S_9 = 0

it is easy to say S_8 <= 1 because if S_8 >= 2 then the sum of the elements is at least 2 + 8 + 8 (S_8 is at least 2, and at least two 8s need to show up)

it can also be argued S_8 can't be 1 (so must be 0)

and that S_7 must be 0

ok i may have just thought of a way to streamline this

[trail ingot]

ignore this i'll argue better

S_9 is necessarily 0

FUCK nvm this is not better

[trim jolt]

@keen marsh Has your question been resolved?

[trail ingot]

this works but it's pretty awful, there's probably a more elegant argument

[trim jolt]

Channel closed

Closed by @keen marsh

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo jasper]

hi

like i know the vertex will be 1,3

But my problem is

lets say i said my x is 0

or m y x is 2

how do i get the y

2, ?

1, ?

Like do i just plug it and solve?

becuz that isnt working fo rme

plz someone

[zinc dove]

yes

[echo jasper]

i beg

Ok

I show

my work

[zinc dove]

👍

[echo jasper]

oh

i see

2,1

[zinc dove]

lol

[trim jolt]

@echo jasper Has your question been resolved?

[trim jolt]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow flax]

My homework has asked me to prove that sin(x)^6 + cos(x)^6 = 1-3sin(x)^2cos(x)^2. I tried starting on the right side, and have managed to use proof by desmos to get it to (1+3cos(x)^4-6cos(x)^2sin(x)^2+3sin(x)^4)/4. How do I move forward from here?

[hollow flax]

what? could you explain further

[verbal stream]

Maybe a^3+b^3 formula will be helpful have you tried that

[hollow flax]

no, what would that be?

oh, it's just the standard factorisation of that

[verbal stream]

yeah that's what I meant

[hollow flax]

give me a minute I've been doing this for the last few hours and my head's hurting a bit and being slower than usual lol

wait so since (sin(x)^2+cos(x)^2) is one of the factors, doesn't that mean that sin(x)^6+cos(x)^6 = (1)(sin(x)^4-2sin(x)^2cos(x)^2+cos(x)^4)?

[verbal stream]

it's just -sin(x)^2cos(x)^2

sin(x)^4-sin(x)^2cos(x)^2+cos(x)^4

do you see how you can finish it now

[hollow flax]

right, got it confused with the a^2+b^2 for a second, sorry

[hollow flax]

I think so?

sin(x)^4-sin(x)^2cos(x)^2+cos(x)^4=(1+3cos(x)^4-6+3sin(x)^4)/4 would then be the next step?

no wait, my signs are wrong somewhere
or I just got rid of (sinxcosx instead of the actual pythagorean identity)

4sin(x)^4-4sin(x)^2cos(x)^2+4cos(x)^4=sin(x)^2+cos(x)^2+3cos(x)^4-6cos(x)^2sin(x)^2+3sin(x)^4 is correct though

[trim jolt]

@hollow flax Has your question been resolved?

Channel closed

Closed by @hollow flax

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith hinge]

yo

[wraith hinge]

help

the sum of all numbers 1 to 50 is approximately what?

whats to formal

[delicate belfry]

Arithmetic sum.

[wraith hinge]

?

[delicate belfry]

Are you familiar with sequences?

[wraith hinge]

ye

[delicate belfry]

Then the sum formula for an arithmetic sequence.

[wraith hinge]

kk

[trim jolt]

@wraith hinge Has your question been resolved?

Channel closed

Closed by @dull yarrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[finite path]

hi! does anyone have any tips on determining the path of a rose? for example, if given r=6sin(5θ), sketch/highlight 0 ≤ θ ≤ pi/2, how would i determine that without a graphing calculator? do i just have to memorize the path of every rose?

[finite path]

the graph:

[wraith hinge]

Well sin(5theta) = 0 for theta = nπ/5

So in general for theta in [0,2π), you have the set of values S = {0, π/5, 2π/5,..,9π/5, 10π/5}

And going from kπ/5 to (k+1)π/5 for 0≤k≤n means going through one loop of the rose counterclockwise

So pairing elements of S in the form (kπ/5, (k+1)π/5), you get 5 pairs so 5 loops

And the amplitude is 6, so the whole graph you plot will be inscribed in a circle of radius 6, with the tips of the petals touching the circle

Use the same logic for theta in [0,π/2]

[finite path]

OHH i never thought about it that way, thank you!

[trim jolt]

@finite path Has your question been resolved?

Channel closed

Closed by @finite path

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo jasper]

would the x int

be 2,0?

[near vessel]

nope

what did you tried

to get (2,0)

[echo jasper]

I know a rule it is like get rid of the y for the X intercept

I tried something dumb like i removd the 6 and 1

-2/-x = 2 , 0

like when i try to get the y i got red of -2 and -x and got 0,6

[near vessel]

thats not how you are supposed to do it

[echo jasper]

Oh

[near vessel]

but this is right

[echo jasper]

Oh ok

[near vessel]

alright lets rewrite the function

,,y=\frac{6-2x}{1-x}

[solid kiln]

Renz

[near vessel]

you said for x-intercepts, we want to make y zero

thats correct

[echo jasper]

Yes

[near vessel]

so we make our y 0

,,0=\frac{6-2x}{1-x}

[solid kiln]

Renz

[echo jasper]

Oh

[near vessel]

now, how do you think we can remove that fraction

[echo jasper]

6-2x=0
1-x=0?

[near vessel]

almost there

[echo jasper]

oh

[near vessel]

we multiplied both sides by 1-x to remove the denominator

and we are left with

,,0 =6-2x

[solid kiln]

Renz

[echo jasper]

ah

[near vessel]

lets move 6 to the left side

,,-6=-2x

[solid kiln]

Renz

[near vessel]

then x must be?

[echo jasper]

x= 3,0

[near vessel]

x=3

correct

but if you want to get the x-intercept

just add a 0

(3,0)

like that ^

[echo jasper]

Ok

Thnx very much for this steps

[near vessel]

youre welcome

[echo jasper]

.close

[trim jolt]

Channel closed

Closed by @echo jasper

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[toxic flicker]

Anyone know how to do this, I've currently tried taking log base x of both sides

[light karma]

then?

[vernal warren]

isnt log base 4 better?

[light karma]

yeah

then assume log base 4

as u

then solve quadratic

[toxic flicker]

Lemme try that

[long sonnet]

u can write the 2 in the exponent as log(16) base 4 and combine it with log(x) base 4 as log(16/x)base 4

should make calculations easier

[toxic flicker]

I actually got to that place previously by taking log base x from both sides and rewriting the left as log(16/x) base 4 = log pi base x but I'm still a bit confused on where to go

Idk how to proceed by taking log base 4

[long sonnet]

leaving everything in terms of log base 4 will be better right

[toxic flicker]

Yep

[long sonnet]

after taking log base 4 you'll get log(16/x)*log x=log pi

[toxic flicker]

Sry can you explain how taking log base 4 of (x^(log base 4 (16/x))) gives us log(16/x)*log(x)

Ik how to proceed from there tho

[long sonnet]

log x^n=n*log x right?

[toxic flicker]

Yep

[long sonnet]

same way

[toxic flicker]

Oh

Ty

[long sonnet]

even in this eqn you write log pi base x as log pi base 4/log x base 4 and reach the same step

[long sonnet]

np

[toxic flicker]

.close

[trim jolt]

Channel closed

Closed by @toxic flicker

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[echo jasper]

uh

[echo jasper]

log32^(2)

so it will be

32^x=2?

df?

[lusty delta]

if you mean this, then yes

[echo jasper]

yes

So will be like fraction answer?

[lusty delta]

is correct

[echo jasper]

oh

thats the answre like that?

evaluated?

[lusty delta]

it's a fraction

[echo jasper]

oh

hm

how do i go about this i never reach this scenario before

32^ (fraction) = 2

_o

[lusty delta]

so if we have 32^x = 2

in this case it may be more clear if we take 1/x power of both sides

resulting in 32 = 2^(1/x)

[echo jasper]

Ok

[lusty delta]

(also in text logarithms are normally written as "log_32(2)" or "log base 32 of 2" or smth)

[echo jasper]

oh ok

[wraith hinge]

Please after you done here, take a look at my channel. I have a test tmrr: https://discord.com/channels/268882317391429632/903486480985489478

[trim jolt]

Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, so advertising can quickly turn into spam.

[wraith hinge]

Okay. sorry.

[echo jasper]

.close

[trim jolt]

Channel closed

Closed by @echo jasper

Use .reopen if this was a mistake.

[trim jolt]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid mirage]

How do I get help?

[left oriole]

#❓how-to-get-help

[trim jolt]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[last falcon]

Can someone tell me whether im correct or not? Im still trying to figure out the ( and [ and i know their meaning but shpuld i include or not

[last falcon]

For example -2 here

if i include it its gonna be zero so i should delete this one and include it right?

[near vessel]

you got the [] and () switched

when you substitute 3 on the equation, it becomes undefined since (x-3) is in the denominator

subbing in 3 in x-3 makes it 0, making the whole denominator 0

which makes the function undefined

meaning, you should use parentheses like this for the interval from 3 to inf like this (3, inf)

same goes for -4

-4 isnt included in the solution set

because when you substitue -4, denominator becomes 0, making it undefined

so you use () for it like this (-inf, -4)

[last falcon]

hm so i shouldnt include zeros right?

also one more question while ur here

[near vessel]

it depends

[last falcon]

sometimes some numbers have both positive and negative numbers

[last falcon]

on what

[near vessel]

alright leme clarify what i said

you made intervals right?

[last falcon]

yep

[near vessel]

and you tested some numbers between those intervals

right?

[last falcon]

yes

[near vessel]

you gotta test the zeroes as well

test -4, test -2, test -1, and test 3

if they equal undefined, then that root isnt included in the solution set

if the equal zero, then that root is included in the soultion set

[last falcon]

how can they be equal to undefined

[near vessel]

since the inequality is $f(x)\ge0$

[solid kiln]

Renz

[last falcon]

mhmh

[near vessel]

when a division of zero occurs

for example

1/0, 2/0, 3/0

[last falcon]

oh for rational ones?

[near vessel]

they all equal undefined

[last falcon]

okay

but in this case we got none right?

[near vessel]

in this case

[last falcon]

in the question i sent

[near vessel]

-4 and 3 makes the function undefined

[last falcon]

oh right

yeah

[near vessel]

try putting -4 and 3 here

it makes it undefined

[last falcon]

yes

[near vessel]

therefore it isnt included

[last falcon]

oh got it

[near vessel]

so

what should be the answer

[last falcon]

okay