#help-36

1 messages · Page 82 of 1

fringe root
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nope

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im like

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clueless rn

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my brain is in overdrive

cold gorge
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Learn exponent rules.

fringe root
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it would be

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what?

cold gorge
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If you learn exponent rules now, you'll surely be able ti simplify this.

fringe root
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dam

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i just asked for help

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mb gang never again

cold gorge
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It's the right way to study.

fringe root
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i asked for help doe

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like

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i want the stes

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steps

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so i can study them

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but yea u right

cold gorge
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If you know the rules and still stuck, I'd give you the steps.

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But it's kind of meaningless rn.

fringe root
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but i know the exponent rules

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im stuck at this

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i never said i dont know the rules

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u just assumed i dont know them

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are u not gonna help?

cold gorge
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You do?

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Nice, do you know what's (a/6)^2

fringe root
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yea

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a/12

cold gorge
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yeah

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Might wanna learn those rules still.

fringe root
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ok

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narrow chasm
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Can someone give me a hint on how to approach this?

narrow chasm
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It seems that the fact that they're deg n and that the relation holds for n+1 numbers is supposed to help but I cannot find a way to utlilise it.

scarlet sequoia
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let f = a0 + ... + anx^n

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suppose that g = 0 for now

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and big hint: try to show that $\int_0^1f^2(x)dx = 0$

celest plaza
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B

soft zealotBOT
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rafilou2003

celest plaza
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person is seated on a Ferris wheel with a radius of 90 feet. The center of the Ferris wheel is 97 feet above the ground, and it completes one revolution every 98 seconds. Assume the person is at the 3 o'clock position and the wheel is moving clockwise. Create an equation to represent this situation as a function of time F(t).

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celest plaza
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Says wrong

scarlet sequoia
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this is occupied

scarlet sequoia
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@narrow chasm Has your question been resolved?

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tulip coyote
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There are 601 integers from 200 to 800, if you're including 200

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While 800 - 200 = 600, you'd be missing out on counting the 200 if you didn't add one

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For an easier example, try out how many integers there are from 5 to 10: {5, 6, 7, 8, 9, 10}
You can see that there are six numbers there, yet 10 - 5 = 5, so you've missed one there...

trail crest
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How i look at it. There are n numbers from 1...n and there are k numbers from 1...k so n - k are numbers from k + 1 to n (you removed first k numbers ) . Add 1 for k and thats numbers from k to n inclusive (n - k + 1)

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@tranquil pine Has your question been resolved?

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@tranquil pine Has your question been resolved?

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tranquil pine
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Does there exist the word "linear bijection" or is the linear unnecessary

tiny gorge
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yes it exists

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and there are bijections that are not linear, so if you mean linear bijection then "linear" is necessary

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bijection just means a map (function) that is one-to-one and onto

tranquil pine
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Ok thanks the I ll have to add it up

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topaz yacht
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topaz yacht
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is this a valid solution for this question

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@topaz yacht Has your question been resolved?

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@topaz yacht Has your question been resolved?

rancid idol
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@topaz yacht Has your question been resolved?

topaz yacht
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@topaz yacht Has your question been resolved?

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gray trench
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I understand that delta x would turn out to be 1, so it'd be 1/3, but what would I use for the other values?

gray trench
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Would it be the y-values at every 1 interval?

celest crane
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Yes.

gray trench
# celest crane Yes.

Thanks, I realize these are probably really obvious things to discern, but I'm not very confident in the realm of calculus like this...

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Lemme go get to work

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For the y-values that aren't super exact, would I estimate?

celest crane
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Yes.

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You could probably round them to within 0.5's.

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Or even keep them as integers.

gray trench
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I have another question on a more conceptual one I think?

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Should I try working the problem out with what info I have first? Or is there something I should know that makes this problem easier to answer?

celest crane
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Dusting off my hat on this one. Error approximations for numerical evaluations was one of my Achille's Heels. 🙂

gray trench
celest crane
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You are given M so to speak.

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Yes, you are given M.

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You are also given a and b as well as |E_s|.

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This should just be straighforward substitution and mathing.

gray trench
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So, it should work out to be

.00001 = 1/180n M

... What's M? I forgot what M stands for in regards to error approximations. I know there's a way of determining it from the base function, but my teacher didn't really explain it very well.

celest crane
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For Simpson's Rule, M is the maximum value of |f^(4)|.

gray trench
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2xe^x^2?

celest crane
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You don't need to calculate anything, the value is given to you.

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f^(4)(x) <= 76e

gray trench
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Oh.

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Goodness gracious I need to pay more attention to what the problem gives me

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.00001 = 1/180n (76e)

celest crane
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It's not necessarily paying attention. I found it always comes down to understanding, or lack of understanding, the information that is given. The only thing that fixes that is practice. Come back to this problem in a day or two and see if you remember how to solve it.

gray trench
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I think I'm struggling with having that time to process and understand with the pace my class is going at... I don't mean to deflect blame since I knew what I was signing up for, but still, tough.

celest crane
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For the Trapezoidal Rule, M = f''(x), and for Simpson's Rule, M = f^(4)(x).

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College calculus?

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Or high school?

gray trench
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161 wasn't nearly as bad

celest crane
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Yeah, college-level Calculus, in particular engineering, tends to be fast paced.

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My only recommendation is to solve and understand the practice problems, if any, several times.

gray trench
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Understood.

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I think part of my frustration also comes from the fact that, I'm a Bio major.

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And I really don't understand how this'll come in handy later, buuuut I shall do it nonetheless.

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For .00001 = 1/180n (76e) however, by the way

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I divide by 76e on both sides and then multiply by 180n right?

celest crane
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For problems you find especially difficult, write notes as you are trying to solve it.

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Literally, every single thought process.

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This is what I often did.

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Never erase your mistakes. Write notes in red that explains what you did wrong.

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Here I showed what I did wrong and explained in blue what the mistake I made was and what I should have done.

gray trench
# celest crane

I used to write a lot of notes and whatever the instructor would say last semester on harder problems I found difficult to understand

celest crane
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That way when I look back on it, I don't have to guess what I did.

gray trench
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But there isn't much my professor currently says that I do understand that would help me if I wrote it down, so uh, I've been pretty reliant on myself.

gray trench
celest crane
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If you look back on an old math problem and you have no clue what you did, you need to add notes to it.

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Preferably using different colored pens.

gray trench
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I can usually understand what I did without notes, but it would help with the clarity if I did start adding them.

celest crane
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I always used orange for things like identities and formulas; blue for comments and references; and red for mistakes,

gray trench
celest crane
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It helps out a lot.

gray trench
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Also, in regard to the .00001 = 1/180n (76e), i got something that didn't make much sense.

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I divided by 76e first, and then after that I multiplied both sides by 180n.

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I got I think a six digit figure in the end

celest crane
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76e is a relatively large number.

gray trench
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Isn't that the value for M though?

celest crane
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Yes.

gray trench
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And it says I need the value for n, and n ended up as that aforementioned six digit number.

celest crane
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One moment, let me make a graph.

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You can see that M adds a lot of error.

gray trench
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Indeed.

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So, how do we fix that error? What lets us get to that n value?

celest crane
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If I were a betting man, I would say this problem is there to highlight the occasional drawback to using Simpson's Rule.

gray trench
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Is it the fact that n has to be even?

... I don't know many drawbacks to using Simpson's, my professor only highlighted its usefulness over Trapezoidal approximation.

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The only thing she said was that "Simpson's is a bit more difficult but garners a closer answer"

celest crane
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I don't know if Calculus textbooks still mention this, it was just a single two sentence paragraph in my old textbook, but many occasions in the real world in which you will need to integrate an expression are not suitable for evaluating an anti-derivative. The problems in your textbook are intentionally easily integrable.

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In reality, you would almost always rely on software to do the calculations for you though.

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But if you had to do some math by hand, you would likely rely on Simpson's Rule to do the calculation.

gray trench
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I suppose that makes sense, but then why have you solve for n then?

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I feel like they could've made the problem a word one if they wanted to convey that.

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Especially since I'm still stuck on that one equation still lol.

celest crane
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It's to develop your understanding of how to approach this type of problem. One of the major differences between job classes is that you either don't need to solve any problems and just do tasks, the job requires some knowledge that is well-established and you just need to familiarize yourself with that information, and jobs that require you to know how to solve a problem on your own. The pay scale for each type of job increases exponentially in the respective order.

gray trench
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Fair enough I suppose. It's why I'm here after all, to push forward my understanding!

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Is my equation still correct though?

celest crane
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To the best of knowledge, n is a large number.

gray trench
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.00001 = 1/180n (76e)

When solved for n, n becomes

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114771.899

celest crane
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I got the same.

gray trench
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Wow, that's a gross number. Let's see if it's correct

celest crane
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Round it.

gray trench
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so 114772

celest crane
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Yes.

gray trench
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Wow, it said it was wrong

celest crane
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Hmm.

gray trench
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Rough, that was my last attempt for the problem too. Ah well.

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I'll ask my professor in person about it.

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There's one more I need to do and then I'm done for today.

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... I need to find out what n would be again

celest crane
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I think it was the (b-a)^3.

gray trench
celest crane
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Well, n divides the interval into equal-sized partitions.

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Hmm, nevermind.

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I was thinking incorrectly about that.

gray trench
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I assume I use Simpson's for this next one, yes?

celest crane
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Yes.

gray trench
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Okay, so then delta x would be 4

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4/3

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Now just, need N.

celest crane
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Ahh, I know what we did wrong. It was supposed to be h^4, not h^2.

gray trench
celest crane
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And I forgot to raise n to a power.

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Which would result in n = 18.4 or 19.

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Which makes a lot more sense.

gray trench
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Definitely seems more correct.

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What about this next one? How would I find n?

celest crane
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n is given by the subscript.

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You need 12 partitions.

gray trench
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... Oh, that's what it represents.

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So it'd end up being

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8-4 = 4

4/12

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turns into 1/3 / 3

celest crane
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Yes.

gray trench
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1/9 (1/4^5 +1 + 4(1/(13/12)^2 +1 ... etc

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.. That's a lot of partitions

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I wish there was a more easier way of writing them all down

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I might save this one for later, I'm getting sleepy and it seems like a much longer problem.

celest crane
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I don't think you need to write out the entire function, just write f(4), f(4 1/3), ...

gray trench
celest crane
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Yeah, with Calculus you'll find there is a lot of gruntwork.

gray trench
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my second and fourth year are free

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But yeah, this is rough

final saddleBOT
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@gray trench Has your question been resolved?

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past nebula
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past nebula
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pls ping me when you reply

inland kettle
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@past nebula use a^b - b^2

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factorize

past nebula
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oh ok

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thanks

inland kettle
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!done

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past nebula
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wait how

inland kettle
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??

past nebula
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can you explain how to do it

inland kettle
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a is 3^1001 + 4^1002

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and b is 3^1001 - 4^1002

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@past nebula the identity of a^b - b^2?

past nebula
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?

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what's an identity

inland kettle
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sighs

past nebula
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😭

inland kettle
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do you know how to factorize a^2 - b^2

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that's the identity

past nebula
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yeah

inland kettle
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okay

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use that!

past nebula
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(a+b)(a-b)

inland kettle
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yes

past nebula
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oh ok

inland kettle
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use that here

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we have two squares

past nebula
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yeah?

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oh ok

inland kettle
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also one more thing
(x + y)^2 + (x - y)^2 can be expanded, you can use that too

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if you want

past nebula
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k

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thanks

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👍 👍 👍

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tranquil pine
#

guys how do I calculate the uncertainty of the average value of the three values

$$x \pm \Delta x$$
$$y \pm \Delta y$$
$$z \pm \Delta z$$

soft zealotBOT
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Alison Burgers

signal vector
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Their uncertainty will also be averaged

tranquil pine
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are you sure?

signal vector
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Yes

tranquil pine
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A solution I found online said something different actually

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they said that I should be adding up the fractional uncertainties/percentage uncertainties

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as in:

$$\frac{\Delta x}{x} + \frac{\Delta y}{y} + ...$$

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and then divide that by 3

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and then multiply with the average

soft zealotBOT
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Alison Burgers

signal vector
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When you add two values, how do you get the uncertainty of their sum?

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You just add their uncertainties

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Same goes for 3 values

tranquil pine
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OH i see

signal vector
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The average of the three values is the sum of the three values divided by 3, so their uncertainty will also just be averaged

tranquil pine
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gotcha

signal vector
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I have no clue why you'd take this fractional thing

tranquil pine
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I think I was confusing it with multiplication of values with uncertainties 😓

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Really sorry

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thanks for the help btw

signal vector
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Nah nah all good

tranquil pine
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have a good day

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oak scarab
#

Not sure how to begin

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cyan kayak
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@oak scarab hint, take (x - r)(x - s) and expand it out. This should give you two coefficients. You'll have x^2 + bx + c. Where b is something involving the sum of r and s, and c being something involving the product.

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If we set 0 = x^2 + bx + c, and we multiply it by some value a we get 0 = ax^2 + abx + acx

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For this question you have a and r as givens, additionally, you know ab = -5 and ac = 1.

oak scarab
cyan kayak
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If you have (x-r)(x-s) = 0 then your roots are r and s

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You know r, one of the roots. And you can find s using the coefficients.

oak scarab
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I think the method my teacher taught was a bit different. I was taught that let Alpha and Beta be the roots. Then Alpha + Beta = -b/a and Alpha x Beta = c/a .

cyan kayak
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Then using s you can find a

oak scarab
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Yep I see what you mean now

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I think I'm good now thank you!

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valid anvil
#

Can anyone help me prove this

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valid anvil
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Using only this prop axiom and deduction lemma

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@valid anvil Has your question been resolved?

valid anvil
#

I will go to ask in advanced math instead

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tranquil pine
#

hi i have an issue with volume of a parallelopiped

tranquil pine
#

my teacher said that it was vector A cross vector B dot vector C

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i'm not sure if it makes sense to me

errant dawn
errant dawn
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then the volume V is given by the absolute value of the scalar triple product |A ⨯ B ⋅ C|.

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This method is based on vector algebra and is an alternative approach to calculating the volume of a parallelepiped.

tranquil pine
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but why is it that, i dont understand where it comes from

errant dawn
tranquil pine
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is there a derivation or something of the sort that i can have a look at

errant dawn
#

u want video's that I recommend for u?

tranquil pine
junior token
tranquil pine
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yes, the magnitude is the area of the parallelogram enclosed by the vectors

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AHHH

tranquil pine
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perpendicular to the plane which cintains the vectors

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contains*

junior token
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(geometrically)

tranquil pine
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product of magnitude of a vector with the projection of another vector along it

junior token
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So you can put all of that together by considering that the dot product projects C onto A x B

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Giving the height of the parallelepiped

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The base is given by the magnitude of A x B

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And the volume of the parallelepiped is the base times the height

tranquil pine
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ahh

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i think i understand

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thank you

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i appreciate it

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tranquil pine
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.reopen

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tranquil pine
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im sorry were you typing something

junior token
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There’s also the determinant

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which can also be interpreted as the volume of that parallelepiped

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is that why you originally asked?

tranquil pine
tranquil pine
junior token
tranquil pine
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interpretation of volume of a parallelopied as a determinant?

junior token
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Then, the determinant of this matrix is the volume of the parallelepiped

tranquil pine
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ohhh

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i'll keep that one in mind too

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thank you so much

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enjoy your day:)

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junior token
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sterile kestrel
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sterile kestrel
#

i dont know what to do this question

static plinth
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let’s say x is the amount of time it takes for the smaller one to fill the tank

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the time it takes for the larger one to fill the tank would be x-10 right

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what can we do with this information to solve for x

sterile kestrel
#

idk

static plinth
#

have you done these types of problems before?

sterile kestrel
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no

static plinth
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i see

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you don’t have any formulas written down right

sterile kestrel
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i think smaller tap + larger tap=75/8

static plinth
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close

sterile kestrel
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or 1/smaller + 1/larger

static plinth
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yep

sterile kestrel
#

?

#

oh

#

then we will have the equation

static plinth
#

1/smaller + 1/larger = 8/75

#

yep

sterile kestrel
#

after reciprocal

static plinth
#

and we also drew connections between smaller and larger

sterile kestrel
#

ohk

static plinth
#

we can solve for x here

sterile kestrel
#

thx

static plinth
#

yw

sterile kestrel
#

.close

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robust knoll
#

Can anybody help me understand this calc 3 problem?

Find the line of intersection between the planes 2x + 4y - z = 7 and y + z = 2

I understand how to find the direction of the intersecting line, thats just getting the vectors normal to the planes (coefficients) and taking the cross product

I was mainly trying to understand how to get the shared point that the vector should go through, when i searched it up on the internet it said to plug in a random value z = 0 to get rid of a term and then solve for the x and y points from there, but i don't quite understand if or why that works

final saddleBOT
#

@robust knoll Has your question been resolved?

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ancient monolith
final saddleBOT
ancient monolith
#

i worked out magnitude by working resultant force of x and y

#

then doing pyhtagoras

#

but when doing my triangle

#

the angle i worked out was the wrong 1

#

it was the other angle

#

idk how im suppose to know which it is

weary scaffold
#

its for a right angle triangle

ancient monolith
#

it is a right

#

angle

#

working out the resultant for x and y

#

then doing pythagoros

weary scaffold
ancient monolith
dense coral
ancient monolith
#

and i got the correct angle but wrong way

weary scaffold
dense coral
ancient monolith
#

let me send a picture gimmme a sec

dense coral
#

i find it it very useful to define a coordinate system, then write down [left/right] and [up/down] for the resultant x and y components

ancient monolith
dense coral
#

then draw the resultant force triangle using those as legs

#

can you tell me your resultant x component and y component?

ancient monolith
#

the anwser is 68.7

#

but in the exam i would write 21

ancient monolith
#

for x andy

dense coral
#

it's not right actually

#

you've wrote the resultant x component as the y component and vice versa

#

30cos30 - 25cos50 = 14.24 N [right]

ancient monolith
dense coral
#

yeah you did

ancient monolith
#

oh i did

#

k i got the anwser

#

thx alot lol i made a silly mistake

#

.close

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#
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raw flint
#

find U2 + U1

final saddleBOT
raw flint
#

I will use a simple base to make them vectors
U1: (3,2,1,-4),(1,0,0,-1)
U2: (1,1,1,0),(1,0,-1,2)

#

what now?

final saddleBOT
#

@raw flint Has your question been resolved?

raw flint
#

<@&286206848099549185>

#

please tell me if something is unclear and I would try to explain it better hmmCat

#

<@&286206848099549185>

final saddleBOT
#

@raw flint Has your question been resolved?

raw flint
#

.close

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bleak hinge
#

Can somebody help me with this?

final saddleBOT
dense coral
#

what're you stuck on in this problem?

#

,rotate

bleak hinge
#

I’m really bad at binary

soft zealotBOT
odd rivet
#

do you know how binary works?

bleak hinge
#

Not really

dense coral
#

@bleak hinge how would you write the number 581 in base 10?

#

if you had to write it in powers of 10?

dense coral
#

i should have been clearer with my words

bleak hinge
#

Is this right?

trail crest
#

Not really

#

You can see that by coefficients

dense coral
#

no, trinity is giving an answer to my question i believe

trail crest
#

Oh

dense coral
#

in which case, she's right

bleak hinge
#

Sorry I just prefer to write it

dense coral
#

now, you just want to do the same thing but in base 2 for your number

#

since 581 meant 5*10^2 + 8*10^1 + 1*10^0, we see that the digits are just the coefficients of the powers of 10

#

it works the exact same in base 2

#

but instead of powers of 10, you have powers of 2

#

the digits are still the coefficients

bleak hinge
#

Is this right?

dense coral
#

unfortunately, no

#

here, let me give you another base 10 number

#

and i think you'll see where you went wrong

#

10305

#

try writing that in terms of powers of 10

bleak hinge
#

Ok one second

dense coral
#

right, but it would be more accurate to write

1*10^4 + 0*10^3 + 3*10^2 + 0*10^1 + 5*10^0

#

that is also the key to writing your binary number in terms of powers of 2

#

each digit is a coefficient for a power of 2

#

including 0s

bleak hinge
#

Wouldn’t your more accurate one turn out to be 11,911?

bleak hinge
#

Nevermind saw were I went wrong there sry

#

But I’m still super confused with the og question

dense coral
#

with what specifically?

#

base 2 isnt really that different from base 10

#

you just cant have the coefficients be anything other than 0 and 1

bleak hinge
#

Just the way it’s worded

dense coral
#

well, it's asking you to first write the number as powers of 2

bleak hinge
#

Like does it want me to convert the binary than put it into powers of 2?

dense coral
#

then find out what that is in base 10

dense coral
#

you've been given a binary number already

bleak hinge
#

I mean I thought 10110111 in binary was 183

dense coral
#

when i gave you a base 10 number, you didnt have to convert it to anything to write it in terms of powers of 10

#

when they give you a base 2 number, you dont have to convert it to anything to write it in terms of powers of 2

dense coral
#

they are two representations of the same thing

#

the question wants you to show how to convert between the two

bleak hinge
dense coral
#

why not?

bleak hinge
#

How do I write 10110111 as powers of 2?

dense coral
#

the same way i wrote 10305 as powers of 10

#

you need to keep the 0s as coefficients for some powers

dense coral
#

i think you may have missed that?

bleak hinge
#

I don’t understand coefficients

dense coral
#

for the number 10305

#

i wrote 1*10^4 + 0*10^3 + 3*10^2 + 0*10^1 + 5*10^0

#

1 is the coefficient of 10^4, 0 is the coefficient of 10^3, 3 is the coefficient of 10^2, etc

#

notice how the coefficients are the same as the digits

#

1 is the "ten-thousands" digit, 0 is the "thousands" digit, 3 is the "hundreds" digit, etc

#

it is very much the same in binary

bleak hinge
#

Like this?

dense coral
#

but "ten-thousands" really means 10^4, which is a power of 10

bleak hinge
dense coral
#

in binary, the only difference is that you'll have powers of 2

bleak hinge
#

But in powers of 2?

dense coral
#

there's 8 digits in the number

#

you missed the 2nd one to the right

#

and that offset all the other ones

bleak hinge
#

Oh the 10

dense coral
#

no, the 2nd to the right

#

1*10^0 is good

#

but then you've written 1*10^2

#

you missed 1*10^1

bleak hinge
#

That’s what I meant

dense coral
#

oh i see

#

my bad lol

bleak hinge
#

Like the 10 in the number

dense coral
#

issue is that its not 10

#

theres no "tens" place in binary

#

theres the "2^1" place

bleak hinge
#

I mean with the 1*10^1 it’s 11

#

Y know what I mean right?

dense coral
#

1*10^1 = 10

#

in base 10

bleak hinge
#

I mean the part I was missing was 1*10^1

dense coral
#

oh wait, i've missed that

#

you wrote it in powers of 10, when they want you to write it in powers of 2

bleak hinge
#

Yeah I realized that

dense coral
bleak hinge
#

But can you help me make it with powers of 2?

dense coral
#

wdym

#

the number you're given is not a base 10 number

#

it is a base 2 number

bleak hinge
#

How can I make 10110111 as powers of 2?

dense coral
bleak hinge
#

Not really

dense coral
#

let me give you a non-binary number, but not base 10

#

here's a base 16 number

51

#

since it's in base 16, each digit represents a coefficients of powers of 16

#

so this number is 5*16^1 + 1*16^0

#

NOT "51"

#

as in the base 10 number

bleak hinge
#

Isn’t 5*16 80?

dense coral
#

yes

bleak hinge
#

I thought you were doing the number 51

#

Not 81

dense coral
#

huh?

bleak hinge
#

Oh wait I kinda get it know

#

Since it’s base 16 it’s 516^1 because of the 5 and 116^0 cause of the 1?

#

Sorry don’t know why the stars disappeared

dense coral
#

yes, the digits of a number in any base represent the coefficients of the expansion of the number in terms of powers of the base

#

in base 31, the number "10" is given by

1*31^1 + 0*31^0

#

which you can see is equal to the base 10 number 31

bleak hinge
#

Ok

#

So how do I do this part

dense coral
#

again, as i've said before, each digit is a coefficient of a particular power of 2

#

i've given you examples in bases 16, 10, and 31

#

it is no different in base 2

bleak hinge
#

I just don’t get it with a longer number

dense coral
#

why? theres nothing different about a longer number

#

you just have a larger expansion to do

#

here's a "long" number in base 3:

2010102

#

thats equal to 2*3^6 + 0*3^5 + 1*3^4 + 0*3^3 + 1*3^2 + 0*3^1 + 2*3^0

#

each digit is a coefficient for a power of 3

#

starting from 3^0 on the right, and ending with 3^6 on the left

bleak hinge
#

But what’s the base I have since it’s also asking me to convert to base 10 in standard form

dense coral
#

you can convert to base 10 standard form after having written out the number as powers of 2

dense coral
bleak hinge
#

That’s not what I’m asking

dense coral
#

i see, then what are you asking?

bleak hinge
#

How do I know what the base of the number is

dense coral
#

binary

#

means 2

#

bi = 2

#

base 3 is trinary

bleak hinge
#

So the base is 2?

dense coral
#

yes

#

i didnt realize you didnt know that mb

bleak hinge
#

Like I said before I’m really bad at binary

dense coral
#

fun fact, base 16 is called "hexadecimal"

#

so theres not really a "standard" naming convention as far as i know

#

people just say base x

#

2,3, 10 and 16 are major exceptions afaik

#

they are "binary", "trinary", "decimal", and "hexadecimal" respectively

#

so if you see those words, you automatically know the base

#

actually i lied

#

base 12 also has a name, and is somewhat common to see

#

"duodecimal"

#

all the other bases have names too, but i never see them used so yeah

bleak hinge
#

So is this right?

#

,rotate

soft zealotBOT
dense coral
#

why does 2^0 have a coefficient of 0?

#

the farthest right digit is 1

bleak hinge
#

Mb fixed it

#

,rotate

soft zealotBOT
dense coral
#

yeah that's it

#

now to convert it to base 10, just compute that sum as you normally would

bleak hinge
#

So

#

182

#

,rotate

soft zealotBOT
bleak hinge
#

This is the entire question?

dense coral
bleak hinge
#

Oh wait yeah

#

So it’s 1x10^2 + 8x10^1 + 3 x 10^0?

dense coral
#

iirc, standard form just means to write the number normally

bleak hinge
#

I know

#

But

#

Thanks so much for keeping up with me

#

You helped me so much

dense coral
bleak hinge
#

,close

dense coral
#

its .close

bleak hinge
#

.close

final saddleBOT
#
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tranquil ledge
#

I just need help understanding stuff

final saddleBOT
tranquil ledge
#

in algebra 1

loud sundial
tranquil ledge
#

Could it be?

#

Are you my helper?

loud sundial
#

Just post the question and someone will help

#

Beating around the bush just makes it take longer for you to get said help

tranquil ledge
#

Oh

#

I apologize

loud sundial
#

no worries catthumbsup

#

Just post the question

tranquil ledge
#

idk if my answer is right on the first two questions

final saddleBOT
#

@tranquil ledge Has your question been resolved?

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clear crown
#

i don't get the logic here

final saddleBOT
trail crest
#

I guess II. is like sides

clear crown
#

yea seems like it

#

what are others thought

#

<@&286206848099549185>

final saddleBOT
#

@clear crown Has your question been resolved?

final saddleBOT
#

@clear crown Has your question been resolved?

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buoyant mesa
#

Hi everyone. Im having a little trouble with the first step in differentiating the following function using the "product rule".

buoyant mesa
#

In the first step, I want to isolate v and u where, (see formula above)
Is anyone able to help me in baby steps

#

<@&286206848099549185>

final saddleBOT
#

@buoyant mesa Has your question been resolved?

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twin wing
final saddleBOT
twin wing
#

so 4 hours to unload a moving truck for nathan

#

6 hours for iris to unload a tuck

#

would it not take them 10 hours together?

#

wait thats not an option lol

#

maybe if they work together, we can average out?

vital crag
#

No because Nathan could do it faster by himself

twin wing
#

true

final tangle
#

consider first finding how fast they each are in Trucks/hour

twin wing
#

uh what would i do

#

1/4=.25

trail crest
twin wing
#

lol you must like physics

#

if a resistor is in parallel, wont you add the resistors

#

and then divide by amount of resistors added

#

im pretty sure

trail crest
#

No you add in series. But in parallel its $\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}$

soft zealotBOT
#

casework

twin wing
#

i havent taken electronics in a minute

#

aH YES

#

okay

trail crest
#

Im pretty sure if you just plug in 4 and 6 you would actually get a correct answer

#

Not sure though

twin wing
#

so 1/10=.1

#

which is simply again just 10

#

here's the choices

final tangle
#

how are you getting 1/10

twin wing
#

1/r+1/r2

trail crest
final tangle
#

that's not how adding fractions work

twin wing
#

resistors

#

physics

final tangle
#

$\frac 1a + \frac 1b \redneq \frac{1}{a+b}$

soft zealotBOT
#

ℝαμΩℕωⅤ

twin wing
#

hm ok

#

common denominator then?

trail crest
#

Yes

twin wing
#

lowkey i dont understand the relationship between a parallel resistor with my question

#

can we do a different approach tbh

#

im not going to look at my gre question and instantly think RESISTORS

#

tbh

final tangle
#

consider first finding how fast they each are in Trucks/hour

twin wing
#

1 truck/ 4 hours

#

which is 1/4=.25

final tangle
#

and then what about iris

trail crest
twin wing
#

1/6=.16

twin wing
final tangle
#

keep it as a fraction

#

don't round unnecesily

twin wing
#

ok 1/4+1/6

trail crest
#

||You can always look at it like a capacitor but in series||

twin wing
#

which is 6/24+4/24

#

which is 10/24

final tangle
#

now with consistent units, of trucks/hour
you can add them to see how fast they unload together

twin wing
#

which is 2.4

#

and .4*60=24

#

so 2 hours 24 minutes

final tangle
#

now read carefully what the question is asking for

twin wing
#

so b

#

4 hours 38 minutes

#

??

#

becuase they are unloading 2?

final tangle
#

48, not 38

twin wing
#

ye

#

mistypes

#

but is that right

#

b?

trail crest
#

Looks right

twin wing
#

tyy

#

.close

final saddleBOT
#
Channel closed

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trail crest
#

The parallel operator

    ‖
  

{\displaystyle \|}

(pronounced "parallel", following the parallel lines notation from geometry; also known as reduced sum, parallel sum or parallel addition) is a mathematical function which is used as a shorthand in electrical engineering, but is also used in kinetics, fluid mec...

final saddleBOT
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After 15 minutes, feel free to ping <@&286206848099549185>.
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mellow crystal
#

im not sure how to go about this

final saddleBOT
trail crest
#

Does it tell you the thickness of a box?

mellow crystal
#

no

trail crest
#

Or is this just show how you would do it

mellow crystal
#

they only told me what’s on the photo

trail crest
#

Any ideas?

mellow crystal
#

no 😭

trail crest
#

Well you can at least tell me how many pieces of paper does one box have

mellow crystal
#

2500

trail crest
#

Lets say box is thick x cm

#

How thick is 1 sheet of paper

mellow crystal
#

i’m not sure

trail crest
#

Well if 1 sheet of paper is thick y mm how thich are 2 sheets of paper?

mellow crystal
#

2mm

#

2?

#

?

final tangle
#

no

mellow crystal
#

please help

final tangle
#

how are you getting 2mm

mellow crystal
#

guessing

#

i didn’t understand what that person was asking

final tangle
#

if there are 3 apples in a box, how many apples are in two boxes?

mellow crystal
#

6

final tangle
#

and how did you reach that value?

mellow crystal
#

😭😭😭

#

3 x 2

final tangle
#

yes

#

same idea applies here

#

the thickness isn't known,
so we're using a variable to represent that

mellow crystal
#

so?

final tangle
#

1 sheet of paper is thick y mm how thick are 2 sheets of paper?

#

same idea applies here

mellow crystal
#

what’s thick y mm ??

final tangle
#

mm is the unit

#

y is a variable representing some unkown quantitiy

#

because you aren't given the numerical value

mellow crystal
#

oh okay

#

2 y

final tangle
#

yes

#

now lets go back to the first part

how many pieces of paper does one box have
2500
Lets say box is thick x cm
How thick is 1 sheet of paper

mellow crystal
#

1cm?

final tangle
#

no

#

how are you getting 1cm

mellow crystal
#

so a box has 2500 sheets of paper and the box is thick x cm, we don’t know the thickness of the paper because we don’t know the thickness of the box right?

final tangle
#

we don't know the numerical values
hence why we're intrducing the variable x to represent that

#

we'll get an expression with x
so that if/once we get the numerical value, we could plug that in the get the individual thickness

#

apply the same ideas as you would if you had a numerical value

#

if i gave you a numerical value for the thickness of the box,
e.g. 5000cm (don't worry about the unrealistic size)
and there are 2500 sheets
how would you determine the thickness of a sheet?

mellow crystal
#

2500/5000?

final tangle
#

no

#

you're dividing the wrong way

mellow crystal
#

5000/2500

#

damn

final tangle
#

yeh

mellow crystal
#

x/2500?

final tangle
#

yes, that'll be for one sheet

mellow crystal
#

2x/2500

final tangle
#

yes

#

that fraction can be simplified

mellow crystal
#

x/1250

final tangle
#

yes

#

we'll get an expression with x
so that if/once we get the numerical value, we could plug that in the get the individual thickness
and that describes how you'd be able to get an estimate

#

measure the box, then divide by 1250

mellow crystal
#

oh thank u so much ❤️

#

/close

final tangle
#

!done

final saddleBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

mellow crystal
#

/.close

#

HELP

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primal relic
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when you're trying to integrate a composition function with the substitution rule, does du cancel out with dx?

primal relic
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like isn't du just du/dx and then you multiply that with dx per the chain rule, so it's just du?

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I just want to clarify, I suppose

final tangle
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du/dx = stuff
du = stuff dx

primal relic
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is du not the same thing as du/dx

final tangle
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it is not

primal relic
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what is stuff referring to?

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oh like the derivative of u

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but I thought du just meant the derivative of u

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and that derivatives are rates of change

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@primal relic Has your question been resolved?

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@primal relic Has your question been resolved?

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@primal relic Has your question been resolved?

naive tapir
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ancient hatch
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When do I isolate the radical while solving radical equations, and when do i not?

ancient hatch
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here, i had to completely isolate the radical (including the coefficient)

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but it wasn't the case with this one?

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i get a diff answer when if i don't do it the right way

warm python
ancient hatch
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how does that work..?

warm python
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say n=x^2

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then you don't have to square both sides

ancient hatch
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I'm sorry my slow self does not understand

warm python
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if $n=x^2$

soft zealotBOT
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Why am. I here

warm python
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then you simply have to solve $25+10x=\sqrt{3}x$

soft zealotBOT
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Why am. I here

ancient hatch
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this is what i got, but I don't think it's right?

warm python
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why did you square both sides?

ancient hatch
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to get rid of the radical. do i not have to do that?

warm python
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you simplt have $5=x(\sqrt3-1)$

soft zealotBOT
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Why am. I here

ancient hatch
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where is the 1 coming from?
I'm so sorry, this is new to me, so it's taking time

warm python
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I subtracted one from both sides and then factorised

rancid hound
ancient hatch
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ohhhhhh i get it now

warm python
ancient hatch
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hold on, is this wrong then?

rancid hound
ancient hatch
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how do i solve it now?

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cuz i don't think i can divide both sides by x?

warm python
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Divide both sides by $\sqrt3-1$

soft zealotBOT
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Why am. I here

ancient hatch
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ahhh got it

warm python
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Now you have found x, you can find n from it too

ancient hatch
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thank you so much both of you!!!!

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rough wyvern
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why does it calculate the 2nd derivative too? to find candidates for extreme value, do we derive until we cant anymore?

formal trail
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the sign of the second derivative at critical point tells us whether it's a maximum or minimum

rough wyvern
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so the first derivative is to find candidates of extreme value and the 2nd derivative is used to determine whether its a max or min. ?

formal trail
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yes

rough wyvern
formal trail
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a critical point is a point where the first derivative is equal to 0. A critical point can be a maximum, a minimum, or neither. the only points that can be maxima or minima are critical points

rough wyvern
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got it

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thank yu!

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wanton pine
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A force of 7.5x10^-4 N north acts on a charge at point P in an electric field of strength 6.0x10^-5 NC^-1 north. Calculate the magnitude and sign of the charge.

wanton pine
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i can work out the magnitude

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but im not sure of the sign of the charge

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@wanton pine Has your question been resolved?

formal trail
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what is the relationship between the electric field and the electric force?

open shore
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F=qE

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If a charge moves upwards due to a. Electric field going up, just means positive charge

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The definition of a north electric field line is that a positive charge moves north if placed in that field

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errant steeple
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1/r ∂u/∂θ=-∂v/∂r proof Cauchy–Riemann ?

errant steeple
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potent turret
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Is it true that P(A = True | B = True) = 1 - P(A = True | B = False)? Assume the events A and B can only have two outcomes.

unique aspen
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for example, suppose i rolled two dice completely independently

P(first one is a 6 | second one is a 6) =/= 1 - P(first one is a 6 | second one is not a 6)

potent turret
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I should rephrase to avoid the XY problem.
So far, I have P(H), P(not H), P(C|H). I am trying to find P(H|C). I thought Bayes' Theorem would be useful here, namely the extended form:

P(A|B) = P(B|A)*P(A) / (P(B|A)*P(A) + P(B|not A)*P(not A))

I wanted to use the extended form because I don't know P(B) for the regular form.
The reason I asked my initial question is because I'm having trouble finding P(B|not A).

unique aspen
# potent turret I should rephrase to avoid the XY problem. So far, I have `P(H)`, `P(not H)`, `...

i'm not sure it's possible.

for example, suppose i rolled two dice completely independently. let H be the event the first one is a 6, C be the event the second one is a 6.

then P(H) = 1/6, P(H') = 5/6, P(C | H) = 1/6.

and P(H | C) = 1/6.

but now suppose i rolled two dice, but: the second one magically has a 1/6 chance of rolling a 6 if the first one rolls a 6, but 0 chance of being 6 if the first one isn't 6.

and again let H be the event the first one is a 6, C be the event the second one is a 6. then:

then P(H) = 1/6, P(H') = 5/6, P(C | H) = 1/6

but P(H | C) = 1.

so precisely because we don't know P(C | not H) from the information given; in the first case it's 1/6, in the second case it's 0, which makes all the difference

final saddleBOT
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@potent turret Has your question been resolved?

potent turret
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Here's a screenshot of the full problem I'm trying to solve.

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And here's some assumptions I've made.

unique aspen
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yeah that'd be helpful to have since the start

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ah

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ok

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it's because it must either be a hurricane or a tropical storm

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there's no third possibility

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so you know P(H) = 0.69, P(C | H) = 0.08, P(C | T) = 0.2

then P(H | C) = P(C | H)P(H)/(P(C | H)P(H) + P(C | T)P(T))

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just use that

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@potent turret

potent turret
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Are you implying that in this case, P(C|T)*P(T) is equivalent to P(C|not H)*P(not H)?

unique aspen
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yes

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it's implicit in the question

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otherwise, as we see, it's impossible to get an answer

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the question implies 'either T or H will happen'

potent turret
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That makes sense. I failed to recognize that H and T had that relationship.

potent turret
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burnt fjord
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Solve the matrix equation: A(B+X)^-1*A^-1 = A^2*C, when A={{2,-3},{1,2}}, B=1/7*{{2,-4},{-1,-12}} and C=1/7*{{2,3},{-1,2}}

burnt fjord
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I know I should simplify the left side as much as possible but not sure how to go about it

barren hound
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$A(B+X)\inv A\inv = A^C$ ?

soft zealotBOT
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hayley!

barren hound
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or do you mean $A\inv C$ on the right

soft zealotBOT
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hayley!

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burnt fjord
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austere spire
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im reading a discrete math book and got to this part:

austere spire
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can someone help me understand how, in the part where it says "sometimes people use a method that they believe....... they perfrom the following steps: [shows steps]", it's seen as invalid argument?

dense coral
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you have not shown that the original statement is true however

austere spire
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from the first example they gave, how can the original statement be proved, this statement:

dense coral
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start with one side, and show it must be equal to the other

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I’d recommend starting from the right

austere spire
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yea but that is what they did in the first example, this:

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but the book said that's invalid

dense coral
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no, this is assuming the statement is true in the first place and deducing a true statement at the end

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doing this doesn’t mean the initial statement is true

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you need to start on one side, and keep making steps until you get the other

austere spire
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yea but in the first sentence, it said this:

dense coral
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yes, that’s fine too

austere spire
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like u transform the left hand side first

dense coral
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key word is independent

austere spire
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then the right hand side

austere spire
dense coral
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Nowhere did they say you can assume the statement true and then perform manipulations

dense coral
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there’s an equality sign throughout

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which does not make it independent

austere spire
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sorry can you show me how it would look like if they were transformed independently

dense coral
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okay, let me get some paper

austere spire
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btw this is how the book proved the same statement previously