#help-27
1 messages · Page 103 of 1
Yea that what I wa stuck on it was so much
in that case time to reach topmost point is u/g
Can I just use the formula that u said September better then all of this work?
i mean think about it...every second..your velocity u is decreased by g
I am pretty sure I can use this formula it’s me finding the answer still
u can for objective why not
mcq
Is this objective?
Ohhhh
Ok so I need to do time formula then the deltax formula
no
Ok what do I do then
just show how u get to the short cut
start with equation 3
youre all god
goood
Eq 3 is this?
the three equasons of moson
bro my phone died
learn from physicswallah sir
yea
dam
do you understand hindi?
then stick with khanacademy imo
def
not better than khanacademy
neh tutorials point lectures better
pradeep kshetrapal sir explains it more intuitively than sal
no way
pradeep kshetrapal sirs lectures r not jee lectures
conceptual
ofc they do
oh, idk then mb
also theres this:
https://youtube.com/playlist?list=PLMnHwrPjHwJW3p0mB9l4OKDprqMw3gN2f&feature=shared
am i doing good
Bro I honsotly don’t understand all of this
Just am I dong this correct
🔰Click Here To Enroll in NEXUS ENGLISH Batch for Free & Get Access to Class Notes & Other things: https://physicswallah.onelink.me/ZAZB/widie96h
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Let's delve into th...
So now I gotta finish it and find deltax
What
Omg
I don’t no anymore bro
I am fried
No bro
I need to finish this
And I am so bad at this
bro u need to watch an entire lecture series
I do
health more important...u need sleep
Yea
i gave him two english playlists
pw and tutorials point
Look September
Look
Let’s start from here
Yes but wait cuz you are in a step that idk where
Ok from here where I go
September 1 enjoyer
September 1 enjoyer
Ok
September 1 enjoyer
What is thissss
September 1 enjoyer
September 1 enjoyer
What is u
I am here rn
Omg you said multiply with the 2 and square it
That is what I did
September 1 enjoyer
Bro I am having dificulty knowing what that is
Can we just go with what I have
And tell me where to go with that
Cuz I did what you asked
Multiply by 2 and square
Look
Omggggg
Bruuhhhhhh
What’s vo
Yea I did that good
Ok
September 1 enjoyer
September 1 enjoyer
Ok
September 1 enjoyer
Why is the 19.6 positive
After moving the -225 or before
September 1 enjoyer
September 1 enjoyer
It was originally 225 then when I moved it to the other side it became -225
Ok so 19.6/225
-11.5
September 1 enjoyer
September 1 enjoyer
-11.5 time 1 is the same
September 1 enjoyer
Thank you god
Yea
Alr fixed
U see them?
Alr ws bro
Your a legend and the rest of the people who were here
Thanks bro
Ok now 7b
And 8
D
XD
u did
8 u did
Idk why there was square root I think it’s weird
Alr that’s enough for today
I what u mean by case
Case as in part
So all of that is part b
But u just said max height with is 7a
What u me a
Yes
But we don’t have to do know
Now
We can take a break
U k ow what I mean
Ok let’s do that
Bruh first day tom
Dam
So all of this is 7b?
Dam bro
Bruh
U right
Alr ima look at it
We can continue this in dm if u want and close this
Yea
Bruh
What
Omg
Right
But we can do that at dm to
?
Bro I did
alr
September 1 enjoyer
September 1 enjoyer
September 1 enjoyer
How u get that
This
For v I put 0?
O
Yes
Whatttgf
We are finding t
September 1 enjoyer
So we don’t put anything for t
September 1 enjoyer
Wait wait
Nah bro I get it I am just tired
Oh I remember
Wait
T = 1.53
Really
Ok
September 1 enjoyer
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Omg again
So vf and vo are 0
U still here?
If you have to go that’s ok we can talk later
Ok
Why not later today
Cuz this is gonna be on a test
Okay I guess
try to do earlier if u can
Ok
Alr thanks for everything
Cya later
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How do you prove this equation?
I looked at the worker solution but I don't understand how cos theta was converted into '2cos²theta/2 -1'
whats cos2x
Wait, I remember why I forgot about the other cos double angle identity. Thank you for confirming 👍
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how to approach this?
help no?
turn one of the solutions in to y = f(x) the sub it into the other one
simultaneous equations by substitution
@bitter stream Has your question been resolved?
@bitter stream Has your question been resolved?
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hello, i need help with getting the X cords from a position from a direction,
basically ive got the direction (ref1) that is a X Y value ranged from 0,0 to 1,1 (ex: 0.5,0.2 / 0.2,0.8) and a position from a object from that direction that ranges from inf,inf to 0,0
what i want to achive is place get that position onto a object position based on the direction (ref2) where Y turns into the difference in position ahead and X turns onto the difference in position sideways
i was able to get the Y factor by multiplying it (ref3) but im unable to get the X factor which requires the direction to be inverted (-1,0 to -0,1 / 0.5,0.25 to -0.5,-0.75) for that to work and i cannot find a way to do it
this is some example values where p is the position d the direction and s the final position
i wanna turn the direction onto a reversed direction where it gives the remaning value for the side position but i cannot find a relation with the values to get that reversed direction
and thats where im stuck at
@swift grotto Has your question been resolved?
@swift grotto Has your question been resolved?
@swift grotto Has your question been resolved?
@swift grotto Has your question been resolved?
sure why not
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Why is it 2.5 instead of 1.5
At the end of 2016, there were 180
2.5 represents the total
150%+original total=250%
Aka2.5
oh 150% more
i see
i just converted 150% to 1.5
from intuition
makes sense
ty
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A gambler decides to keep betting on red at roulette, and stop as soon as she has won a total of five bets.
\begin{center}
a) What is the probability that she has to make exactly $8$ bets before stopping?
\end{center}
sadkid
!status
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6. None of the above
2
So the way that I approached this problem was
According to the question the gambler would have stopped on the 8th bet exactly, which means that she won her 5th bet on the 8th try which is fixed
Which means we're left with ([],[],[],[],[],[],[],[W])
Now we know that we win a total of 5 bets, which means that we get 4 wins to distribute along the 7 remaining positions
So we can use the formula to get: P(4 wins out of 7 games) + P(Winning 1 game)
my problem is I don't know how to find the actual probabilities
of successes or failures
since they were not given in the problem
red and black are like H and T right
the simplest assumption is 50% red
so this problem is identical to 5 coin tosses?
yeah
well until 5 heads
or whatever
this seems reasonable to me
,w roulette probability red
I tried googling it and it did this:
o green
It's weird that they didn't give it in this problem
well solve it in general then
then u have to ask your professor
okay 👍
finding the answer in terms of their answer is proactive tho
yeah I did
can you check my answer?
$\binom{7}{4} \cdot P(Win)^4 \cdot P(Lose)^3 \cdot P(Win)$
sadkid
I could've sworn \choose was a thing
this is what id get to
it is, \binom :p
you can write it better
lose = 1-win

but yea
oh yeah lol
well bing chilling
thanks for all the help @timber pebble @topaz axle
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$\left(\frac{1+\sin{\theta}-\cos{\theta}}{1+\sin{\theta}+\cos{\theta}}\right)^{2}$
yajatk07
half angle properties?
i simply used a+b+c whole square on both num and denom, then did some simplification like making 2sinthetacostheta as sin2theta
but i got stuck
i did used
which one?
tan
where did tan came from?, did i did something wrong?
Dyssrupt
similarily the cos one
automatic
yeah
not the same case with mine then
ookay
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1, 20, 300, 4 000, 50 000, 600 000, 7 000 000, . . . how would i express this in set builder notation
10^(x - 1)
and it should be x in N
x * 10 ^(x-1)?
do i have to say where x is not equal to 0 ?
@restive river Has your question been resolved?
you have to say it in your version with Z
{ x * 10 ^(x−1) | x in Z , where x not equal to 0}
looks good
does it have to be formatted that way
like could you do {x in Z | expression, where x not equal to 0}
i don;t think so
i've always seen it starting with expression
oh right, it doesn't make sense that way
like the word where
oh i dont know how to not use where 😦
{ x * 10 ^(x−1) | x in Z , x > 0}
i'm trying to find something that looks like it's the one true way
there isn't one true way in general, i just mean so it looks like it couldn't be something else
no okay that looks best
x in N?
i would hate that
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Im having trouble with v2 in specific i am unsure as to how to convert it into row echelon form
I managed to do it with v1 because it was pretty straightforward
I try multiplying r1 by 1/3 but the 4/3 is really hard to work with
youd just do the same steps as v1
like the same steps
just calculate it on v2 with a calculator or smth
dont we have to turn the matrix into row echelon form
yes
but the matrix is the matrix with [a b c] as columns
itd be like $\alpha \vec{a} + \beta \vec{b} + \gamma \vec{c} = v_i$
nadav
so the system of equations would be $[\vec{a} \vec{b} \vec{c}] \vec{s} = v_i$
nadav
bad spacing but still that matrix is the one being reduced
youre just applying the reduction operations on different v_i
Got it let me try
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Can anyone please help solve? I am just running in circles
Calc II and I have not learned the limit chain rule
Another try...
I keep getting ln(lnx) which even if approaching from 0+ I feel is undefined because the first ln yield -inf and the 2nd ln then is UD
So it must be that my logic is incorrect or my method is incorrect
I'm thinking of two ways. If you want a convincing argument that the limit is 1, then you can see that in the first image you posted, ln(ln(x)) goes to -infinity much slower than 1-x goes to 0. Hence one could argue that ln(L) = 0 so that L = 1.
If you want a more rigorous approach, then starting from your first image again, write $$(1-x)\ln(\ln x) = \frac{\ln(\ln x)}{\frac{1}{1-x}}$$
Azyrashacorki
Then apply LHR
@sweet thorn Has your question been resolved?
Ah, I think I se my issue...
When I put the left side under 1 I don't have to recheck the limit because it is the same 'form' underneath I guess...
and yeah I also just noticed that while doing a different problem and comparing to the notes exactly, so problem solved, thank you!
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why do you cross the direction vectors of the line with the distance from the point and the position vector of the line
because the plane must contain both the vector direction and the difference between the position vector and the line
so you cross them to find the normal vector
right ok
that makes sense
why isnt the coord we use
wait
why cant we use
any other point
on the plane
do we have to use 9,0,-1
if we do that cross
well that one is given so you know for sure that it's on the plane
any other point would still work
if it's on the plane then yeah
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(L/n) (x)
L(x) x²-14x+49
N(x) x+7
Are you familiar with polynomial long division?
Nope, teacher just straight up said here's your assignment
Is this for an Algebra 2 class or somewhere around there
just curious are you sure you copied all the +'s and -'s correctly?
Yes
yeah if that’s the case I imagine the teacher is expecting polynomial long division
Do u want me to send you a screenshot of the TV screen
I told you here
That's for L-M
No
What
Yes
Do L(x)/N(x)
That one
I was saying that either L(x) or N(x) has a sign error
But how????
I never said it was for L -M
If you do L/N, where N(x) = x - 7
So $\frac{x^2 -14x+49}{x - 7}$ factor the numerator and cancel
dldh06
I literally told you that
I asked the same channel for multiplication, subtraction and addition, i got all of it understood but this division thing i don't understand
That sign is x-7
Yes
Then what did I say about N(x)
To factor it
@fleet moat just check your messages
The numerator
I never said factor N(x)
The numeratkr
So it's most likely an error?
And that's what I mean, you aren't reading what was told to you
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
And don't do the work for people
😈
I'm tryna understand how he got the answer so i can answer the other numbers with division sign
And I'm telling you right here what to do
Don’t do what I did
Can you factor the numerator
You should delete that so OP doesn't copy that wrong method

.
I can't
If you don't know how to factor, I suggest you review that as those problems had to apply that
I also mentioned this
Why is x outside the parentheses?
Yes / is divide
$\frac{(x -7)^2}{(x-7)}$
dldh06
Cancel stuff out
What do you cancel
Well you have x - 7 in the numerator and one in the denominator, it's identical
Like 3/3 = 1
I don't get what you are trying to say
dldh06
Or $\frac{20}{5}$
dldh06
I dont
You should look into that. There is a lot of concepts that are applied and it seems like you are lacking that knowledge to complete this task
Do you have the link to YouTube on how i can
You can google, can't you?
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wehres my mistake
right equation is transformed g(x)
left equation is g(x) which im trying to transform
below is my work
however when I graph it there's some mistake
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if the number y + 7z is even for integers y, z. can the number 7z - 7y ever be odd?
i need to consider a few cases right
not really
because y +7z is odd only if they have the same parity
and addition or subtraction of 2 numbers of same parity always returns even
here do you mean 7z - 7y instead?
wait
nevermind
think I got it figured out
i was talking about what was given
assuming 7z - 7y is odd (should) leads to a contradiction right
yes but u wont get anywhere with that
y+7z is even only if they are both odd or both even
did u get this
yup
after that u just put same condition there
alright so y + 7z even => y, z have the same parity. alright.
then if they have the same parity, then 7z - 7y should also be an even number, thus assuming 7z - 7y is odd leads to a contradiction
isn't that right?
that's where i wanna get
yes
no need asume
because they have same parity
u can directly say its always even
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if we have numeric value of acceleration, displacement, and FINAL velocity, and we need to find time, can we use 2nd eq of motion here, only problem here is i think we use 2nd eq when we have INITIAL velocity not final
$u$
yajatk07
$v$
yajatk07
yes 2nd equation is for initial
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yeah ik
do u want help tho? or u got this
nah thanks, i got it now, it was the only confusion ty
ok, gl
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i did the problem again and got log(x^3/y10^2)
would that be correct
logx^3-logy-log10^3+log10
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Well
You know the formula for n terms in a GP yes?
a * r^n-1
@restive river
And you know how GPs work
Yes
Yes
n'th term*
Well
Clearly you know the formula for sim of infinite terms
a/1-r
All you need to do is
Equate it to your values
33.25 = a/1-r
And 7.98 = ar^1
Change subject and make this a = …
Then insert it here
Could you start the process so it would be easier to understand?
You will get a quadratic equation
Hence “possible values “
Okay Thanks wait let me try it
Sorry for h ttg e lage response i was doing other wuestion
No problem
Ok so I made
The equation
Into 7,98/r/1-r
=33.25
But idk how to put this into a gdc
Could you take a picture of this? @restive river
@restive river Has your question been resolved?
Oh okay tysmm @young crane
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Let A,B be a subset of X, show that:
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
!show
Show your work, and if possible, explain where you are stuck.
(this has been asked on MSE: https://math.stackexchange.com/questions/3582854/power-set-proof?noredirect=1, the first question in this post, answered in the first answer)
@restive river Has your question been resolved?
oh thanks!
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so we know when objects are in freefall they have an acceleration of 9.81m/s^2
and we know after how much time both of the balls hit the ground
lol
sure
first we need to find the amount of time you brother was running for from when you let go of the balloon
so we need to find the time from whenn you released it and it hit your brother
you drop the balloon from rest
the brother is runnning at 2.65m/s^2
1s
so the distance from the window to your brother is 6.35-1.25 which is 5.1
the brother is at a constant speed meanwhile the ballon droppinng in free fall is using the gravitational acceleration
the formula for the time here is
t = sqrt(h/a)
if im not mistaken
so we find the. time by plugginng in the values there
a = v/t = (s/t)/(t/1) = s/t^2
a = s/t^2
a/s = 1/t^2
s/a = t^2
sqrt(s/a) = t
i got roughly 0.788 ;-;
wait
i misstyped
why 2s?
well the book is probably right
soo
i guess the time is 1.2 around
go to an available help channel
ok
1 catagory above this onne
so yeah as we were sayinng
v=s/t
s=vt
s=2.65m/s*1.02
since were dealing with consistent velocity
yeah i forgot earlier that the formulas for finding time and distance in acceleration and velocity are different ;-;
yoooooooo
thank you
you too
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Laito
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Can someone explain how I'm wrong
"b" or the intercepted part of y-axis is also different in both lines
The way I saw it is that since the line f is going down slope must be negative and y intercept is 4 so must be positive
Still don't understand
b is the y-intercept of g(x)
Except that b is a variable so it could be either positive or negative
It doesn't have to be positive
But it can be right...?
Well yes it can be but by looking at the graph, line g cuts the negative part of y axis so it's negative
Aren't we looking for line f?
Yes but line g's equation is given so we're basically comparing both lines
Like checking whether the signs of the slope and the intercepted part of y axis are similar or not if they're similar we just leave it the way it is if they're not we change the sign of the variable
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I’m blanking rn so what’s my next step here
how'd you get your denominator
your numerator should be the denominator
Oh crap yeah
Ok so I’ve switched them
Now what
Waaait
Would I manually plug in 4+h for x and that gives me the y then I can just solve the equation to prove the aroc to be h+13
what's $y$ when $x=4+h$ ?
riemann
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@gilded nova Has your question been resolved?
Yes
It's not intuitive
But fuck it, doesn't matter for your question
i multiple it with 60 right
0.67 hours * 60min = 40min
okk

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So the first sentence gives you the information needed to find the distance covered
Can you calculate that?
careful
if im not wrong
that time is in minutes
oh ok
the speed is in km/hr
so 48 hours
nonoononono
40 minutes is not 48 hours lol
40 minutes is definitely less than an hour
oh so I should convert km into m
no
focus on the time
i want you to turn it into hr
what is 40min in terms of hour
So you have 40minutes, right? There are 60 minutes in 1 hour
*not
So to convert, you get
ok i'll let you do it
I completely forgot 
OMG
hahaha
yea
at 72km/hr
yea
so the triangle is saying to find distance, you multiply the time it took, and the speed
72km/hr * (2/3hr)
oh ok
$72\frac{km}{hr} * \frac{2}{3} hr$
TooManyCooks
As you can see, the hr cancels
Yes
oh ok
So, now you know the total distance traveled
The problem is now giving you a different scenario
What if you drive faster?
So instead of 72, you drive 80
It's asking for t. You can use the triangle again
soo 80km/hr * 2/3hr?
oh
that's what you're looking for
ohh
Yeah that's it
Good job
So now it's asking what the diffrence in time is
You just subtract the previous time to the new time
but its a decimal
ohh
then you can convert using 60min/1hr
oh ok tysm
@silver fjord i got 0.06
how do i change that into time
also so sorry for tagging u
No I prefer it.
I lose track of the threads I go to
SO that .06666667 hrs
you need that in minutes
yea
$(\text{time in hr}) \frac{60min}{1 hr}$
TooManyCooks
so i do 0.067 60min/1hr
i got 4.02
if you do it exactly, without using decimals, it should be exactly 4
that's why I wanted you to work with fractions
oh ok
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after solving i got 50/7 but apparently thats not correct?
@fervent viper Has your question been resolved?
I guess I made a wrong step somewhere
Do i need to find derivitage of top and bottom first off?
All you need is the fact that $\lim_{x\to0} \frac{\sin(a x^2)}{x^2} = a$
TooManyCooks
So, the sin^2 does not make a difference?
This was my thoguht process
splitting it apart
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so I recalculated this thing like 3 times but I keep getting the same answer
but it says most of them are wrong so idk what's up
How did you calculate them?
well just trig
for f2 I took the arctan of 12/5 and used that angle to find the x and y components
for f1 i'm assuming the x component is negative since it's pointing left
that's been the case for previous problems anyway
I mean this is correct so maybe you messed up the angles
Show your work, and if possible, explain where you are stuck.
Sobbing
Yeah, show work 😭
I've got a similar answer
Your magnitude makes no sense
How is the magnitude less than a single component
I got the exact same answer
perhaps you need to neglect any negatives for some reason?
I can try...
nope, still wrong
what did you put this time?
no I just got rid of the negative in front of 321 lol
Brandon H#1125
yeah, that makes no sense
<@&286206848099549185> can you guys provide any input on this? Maybe something is being overlooked in our calculations?
@shrewd skiff Has your question been resolved?
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can someone confirm this is wrong
this is the answer key and i think it's wrong
how come is it -2log base 10 of (x+3)
bruh
it's -2 log base 10 of x
it should just be x not x+3 for sure
np
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i can try