#help-27

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restive river
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Okay maybe this question is a bit too excel-y, but I am just looking to understand the Math behind it.

Here is the gist of it; there is a concept called cannibalisation in accounting, which is the number of customers that would transition from using an old product to a new product you just introduced (Think about Coca-cola and diet cola, for example)

This example I have here mentions a scenario of someone selling regular umbrellas and then introducing wide umbrellas to their sales; you know that 25% of the customers would end up transitioning to purchasing wide umbrellas, which ends up giving you a larger profit than when you had only just sold the regular umbrellas (You will be earning 1,150 instead of 1,000)

My question is relating to how they calculated the maximum cannibalisation rate, which is the percentage of how many customers could transition from buying your old product to your new product without giving you less profit than if you had only sold the regular umbrellas

restive river
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The way they calculated that is by taking the profit you got from your wide umbrellas (400) and divided it by the contribution margin of your regular umbrellas (10) and then further divided that by the sales of your regular umbrellas (100)

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I can't quite seem to understand why those calculations make sense?

arctic field
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cryingLaughing you're actually here

restive river
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idk where to ask okay xd

devout snowBOT
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@restive river Has your question been resolved?

restive river
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<@&286206848099549185>

dull otter
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hmmmm

devout snowBOT
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@restive river Has your question been resolved?

restive river
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Yes typed that wrong

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I meant the profit you would be earning from that

dull otter
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40%

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BECR = Total contribution of new product/total contribution of old product

dull otter
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n stands for new product

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e stands for old product

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one second forgot somethin

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@restive river

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and your question is basically asking,

Why does this big formula equal this other simpler formula?

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Well, if you recall

Contribution = S(F-V) where S is the sales, F is the fixed price and V are the variable prices

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it should be easy to figure this out

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ill leave this up to you

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@restive river any minute now...

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it should click

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and you should go like "ohhhhh"

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any minute now

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the answer is like

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right there

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this is gonna be us

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ill be drake and you will be lil yachty

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lixera any minute now...

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you may even close this channel instantly

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since the answer

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is right there

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it makes total sense

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super easy to understand

dull otter
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you just need to figure out why they are equal

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thats the question you asked

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any minute now...

dull otter
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its just a matter of notation

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and rewriting...

dull otter
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and i mean the picture i sent

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explains it all...

devout snowBOT
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@restive river Has your question been resolved?

dull otter
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@restive river any minute now...

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tame bay
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how to solve (-1-sqr2)^2 ? learning basic geometry (9th grade) and im not the proficient with square roots

tame bay
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yeah i do mean that

formal haven
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if so just multiply it out

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like you were multiplying (a+b)^2

tame bay
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oh like foil it?

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okay thanks that helped a lot didnt think about that

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restive river
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how can i prove that AE is a diameter?

devout snowBOT
restive river
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nvm

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restive river
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if we have an improper intergral that is a discontinuous integrant, how do i know if it approaching from the left or right

warped relic
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Hmm

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Example on what you mean?

restive river
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for this improper intergral, how did we know it was approaching 3 from the left in the limit

warped relic
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Okay so

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We observe the function

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And we find the locations of our undefined points within our bounds

restive river
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yup so when x = 3

warped relic
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Yepp

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So when x = 3, the function is undefined

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Now x=3 is exactly the upper bound

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And if we drew a diagram, we will see that we will need to approach x = 3 from the left

restive river
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so like for a lot of improper intergrals, its best to visualize the graph

warped relic
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Yep

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Later on with enough experience, you'll see that upper bounds need to be approached from the left

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And lower bounds need to be approached from the right

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But you will need experience to have that in your mind

restive river
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experience because it doesnt apply to all cases correct?

warped relic
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Experience so that it makes sense to you :)

devout snowBOT
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@restive river Has your question been resolved?

restive river
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nothing makes sense to me in math 💀

warped relic
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Aww

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Math needs a bit of focus and a good ol' cup of your favorite drink and a bit of time to solve the problems you have for homework

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And it's all a game of using rules to your advantage

restive river
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im not giving up

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ever

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on that topic, could i ask about the comparrison test as well

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for improper intergrals

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it is confusing me

warped relic
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Oh sure :)

restive river
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for instance this example

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rugged kiln
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If 20 / 5 = 4 groups each containing 5 parts. That means that 4 = 20 parts.

So if you multiply 4 x 5 = 20. You are actually multiplying 20p x 5p = 100p.

20 = 100p

So multiplication doesn’t seem to be “reverting” division it just seems to increase it.

How am I wrong?

cosmic trail
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4 groups of 5 = 20 parts

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not 4 = 20 parts

wooden zodiac
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You just said 4 is groups

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Groups !=parts

rugged kiln
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So each group contains 5 parts

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Since there are 4 groups, there are 20 parts

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So if I were to multiply, 4 x 5, it wouldn't be inverting it, it's just increasing it's already set quantity

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So how is multiplication inverse to division?

cosmic trail
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what do you mean it wouldn't be inverting it

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20/5 = 4
4 x 5 = 20

rugged kiln
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You're dividing 20 into 4 groups. But there's still 20 in the total of the groups

cosmic trail
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yes

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4 groups of 5 makes 20

rugged kiln
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So if I multiply 4 (Which still has 20 in it) by 5 it would give you 100

cosmic trail
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each group has 5 in it

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so if you're multiplying 20 by 5 you're multiplying each group by 5

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20x5 = 4x5x5

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like fucktalogist said, you're treating the group as a part, which it isn't

rugged kiln
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Why?

cosmic trail
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because 1 =/= 5

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group = 5

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part = 1

rugged kiln
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But wouldn't the "new" 1 become some sort of unit? Since we divided 20 into 4 groups. The 1 represents 5 parts no?

cosmic trail
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1 group represents 5 parts

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1 does not represent 5

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you can not just drop terminolgoy like that

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which is how you get 20= 100

rugged kiln
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But isn't that how division is defined? 20 is divided into 5 equal groups of 4

cosmic trail
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yes..

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that doesn't validate what you said

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or contradict what I said

rugged kiln
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But the result will be 4, and in each one there will be 5

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Since 20 is divided into 4 groups, and the groups in total all contain 20, which would give you 5 in each group. And each 1 thereafter would represent 1 group

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And each group, represents 5

cosmic trail
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I don't understand your problem

rugged kiln
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Where does the 5s in each group go

nova idol
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if there are 20 people

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and group A, B, C, D

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in group A there are 5 people

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in group B there are also 5 people

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same for C and D

rugged kiln
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So there are 4 groups of 20 people. So in total there are 20 people

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Every 1 represents a group with 5 people in it

nova idol
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what

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no

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there are 4 groups with 5 people each

rugged kiln
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So every group has 5 people in it

nova idol
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yes

rugged kiln
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So 1 (5) + 1(5) + 1(5) +1(5) = 4(20)

nova idol
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incorrect

rugged kiln
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why

nova idol
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ab + ab + ab + ab = 4ab

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= 4(1)(5) = 20

rugged kiln
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No its not multiplication

nova idol
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it is

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1(5) = 1*5=5

rugged kiln
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Yeah my bad: 1 (people in group 5) + 1(people in group 5) + 1(people in group5) +1(people in group 5) = 4(people in group20)

nova idol
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Why is there a one there

rugged kiln
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The 1 represents each group

nova idol
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It’s still multiplying

rugged kiln
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4 groups with 5 people inside it

nova idol
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Yes

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4*5

rugged kiln
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20 / 5 = 4

nova idol
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=20

rugged kiln
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20 / 5 = 4
(5 people in 4 groups.)

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20 / 5, is 20 divided into four groups. In each group there is a portion of 20

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Which is 5

rugged kiln
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So there are 4 groups, with 5 inside each of them. Meaning there is 20 in total.

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So if I were to multiply those 4 groups with 5 inside of each of them, times 5, it would give you 100

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since the 4 groups represent the value of 20

wooden veldt
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sure, thats just 20*5

rugged kiln
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So if 20 / 5 = 4 groups each containing 5 parts. That means that 4 = 20 parts.

nova idol
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since 4*5 = 20

nova idol
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20 is the number of parts

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you cant just say 4 = 20

rugged kiln
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And inside each group, there are 5 parts

nova idol
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you can however say 4 groups = 20 parts

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yes

rugged kiln
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20 / 5 = 4 . Aren't you already saying that in this expression? Since its 20 divided evenly into 4 groups of 5

nova idol
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yes

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but 4 is not just a number, it has context

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4 is the number of groups

rugged kiln
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So if were to multiply this, it would be 4 groups, 5 times. Each group, has 5 in it.

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So it would give you 100 parts, and 20 groups of groups

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It wouldn't give you 20 parts

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So meaning, the 20 you started dividing with. And the 20 you ended up with after multiplying. Is not of the same value

cosmic trail
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4 groups = 20 parts
multiply both sides by 5
20 groups = 100 parts, each group has 5 in it by definition

20 x 5 = 100

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please tell me what is not clear in these steps

rugged kiln
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Yes so. If we have 20/5(5) You would get 100 parts and not 20 parts

cosmic trail
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what?

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20/5 x 5 is not 100

rugged kiln
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Since 20/5 = 4 groups. And each groups has 5 parts. Meaning it has 20 parts

cosmic trail
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pause stop typing

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I don't understand what your confusion is

rugged kiln
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So if you were to multiply 4 groups 5 times, you would get 100 parts

cosmic trail
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just tell me explicitly so I can help you faster

rugged kiln
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So 20/5(5) is equal to 100

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The 20 you start with, is not the same as you end up with

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The first 20 is parts, the one you end up with is groups

cosmic trail
rugged kiln
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20/5 = 4 groups, each group has 5 parts

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so 20/5 = 20 parts

cosmic trail
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no

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20/5 = 4 parts

rugged kiln
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how

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But we're putting 20 into 4 groups, each with 5 of the 20

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So each 1 has 5 in it

cosmic trail
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yes

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20 /5 represents the size of one fifth of 20

rugged kiln
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so 20/5 = 20 parts

cosmic trail
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is 20 one fifth of 20

rugged kiln
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No, it'd be 20 parts and 20 in total for the 4 groups

wooden veldt
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the value of 20/5 is "how many groups are there, when we split 20 parts into groups of 5?"

rugged kiln
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There are 5 groups, each with 4 in them

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But 20 is still there

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Since each group has 4

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5 groups is not = 5

wooden veldt
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20 parts / 5 groups = 4 parts per group

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(4 parts per group) * 5 groups = 20 parts

rugged kiln
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But 4 parts per group (which there are five) is 20

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4 parts per group. There are 5 groups, So the value of this is 20

wooden veldt
rugged kiln
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But there are already 5 groups

wooden veldt
rugged kiln
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I already watched this

wooden veldt
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you need to go and watch all these videos and do the whole course pretty much

rugged kiln
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And I am

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Well fine

rugged kiln
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.close

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edgy owl
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can someone help me go about wrapping my head around this problem? It's an optimization problem. As far as I understand I need to get the height of the rod in terms of r, but in order to do that I need the volume, which I don't have.

edgy owl
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It just to me doesn't seem like enough information to find the length, I know that the rods have a maximum height of 1 but I don't see how that could be relevant

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I can also post the answers if needed

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any help is appreciated!

wooden veldt
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i think you want to express the volume of the cylinder in terms of the height of the rods

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and then maximise that with respect to the height of the rods

edgy owl
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how would I be able to do that for V = pi r^2 h? Wouldn't volume already be isolated?

wooden veldt
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let R be the rod length

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you know that h = R

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and you can determine the radius of one of the circles (r) in terms of R

edgy owl
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How would the rod length help find the radius of one of the circles though? Aren't they both independent of each other?

wooden veldt
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because the length of the rods and the circumferences of the circles must add up to 4m

edgy owl
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ahhh I thought that the circles would be a constant and weren't made up of the bendable rod aswell.

I wrote an equation like this: 4 = 4R + 2C where C is the circumference

Then subbed in C = 2pi r

then isolated for r and got (1-R)/pi = r

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am I on the right track or no?

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so V(R) = pi((1-R/pi)^2)R?

wooden veldt
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yes yes

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now maximise V(R) wrt R

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within some constraints on R that you've already mentioned

edgy owl
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ah got it! Thank you so much for your help

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devout snowBOT
woven radishBOT
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LeftySam

devout snowBOT
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@tidal haven Has your question been resolved?

woven radishBOT
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LeftySam

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LeftySam

devout snowBOT
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@tidal haven Has your question been resolved?

restive river
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Hello, can you please define functions in simple terms

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@tidal haven

woven radishBOT
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LeftySam

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LeftySam

restive river
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um

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more simpler terms?

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i mean how would you explain functions to a complete newbie

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like a high schooler

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i do have some kind of a source to understand this but, i wanted to understand it in more layman terms

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thank you for your time

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aight thank you

devout snowBOT
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@tidal haven Has your question been resolved?

devout snowBOT
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@tidal haven Has your question been resolved?

woven radishBOT
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LeftySam

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LeftySam

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LeftySam
Compile Error! Click the errors reaction for more information.
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LeftySam

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green gulch
#

James wants to design an optimal weekly time table which satisfies the following requirements over a time period of 9-10 months:
•Number of periods per week: 13
•Subject A: 156 lectures.
•Subject B: 148 lectures.
•Subject C: 181 lectures.

green gulch
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How do i make the most optimal time table

green gulch
azure patio
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maybe finding the hcf would help

green gulch
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Give me a sec

green gulch
azure patio
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do we have to make the timetable for 9 months or 10months??

green gulch
# azure patio hmm

But like they have mentioned a range 9-10 months so i think can we manupulate the values a bit?

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Of the lectures i mean

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So that it fits perfectly

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Acc according to the needs

azure patio
green gulch
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Yes

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They stated that there are 148 lec of B, so 3.7 lec -4.1 lecs

azure patio
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get the natural number between them

green gulch
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Yes for optimal we should take average right?

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3.9

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Which is roughly 4

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For subject A its stated that there are 156 lec so: 3.9 to 4.333

azure patio
green gulch
azure patio
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so optimal one here means that you can watch 4 complete lectures per week of subject b

green gulch
azure patio
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sum of per week lectures of each subject should be 13

green gulch
azure patio
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cuz how will you manage to watch exactly 4.1 lectures

green gulch
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True

azure patio
green gulch
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For C: 4.52-5.02

azure patio
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ya

green gulch
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Which means 5

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Right?

azure patio
green gulch
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And 4+4+5=13

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Okay so that works out

azure patio
green gulch
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Now how do i optimally arrange these in a week

azure patio
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or else number of lectures per day would also be given

green gulch
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But isnt the range given?

azure patio
azure patio
green gulch
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If it is there has to be limited number of lectures that a person can watch per day

azure patio
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yes of courese

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as he watches only 13 lectures a week

green gulch
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They said 13 lec a week so per day it should be 13÷6

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7*

azure patio
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but how he manages to watch them is not given

green gulch
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So i should report weekly readings right?

azure patio
green gulch
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Alright, got it!

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Thanks!

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restive river
#

Hey can you help me with Question 6) I can translate it from German, it says

Given is the Point P (1 -2 1) and the point Q (13 13 17)
a) Calculate the midpoint M of the line segment PQ
b) Calculate an equation of the plane that is perpendicular to PQ and passes through M."

devout snowBOT
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@restive river Has your question been resolved?

long fog
restive river
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yeah

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The midpoint between the point of PQ

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I think I have a way but im not sure if its right

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My Idea is

M = 1/2 * (P + Q)

woven radishBOT
long fog
restive river
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ah

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okay thank you

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so

M = 1/2*(P+Q)
M = 1/2*(14,11,18)
M = (7, 5.5, 9)

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so that leaves the b)

woven radishBOT
long fog
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god dyslexia

restive river
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is X a stand in for M ?

long fog
restive river
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okay thanks

devout snowBOT
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coral tulip
devout snowBOT
coral tulip
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1 and 2

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Just give hints for both questions

magic pine
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for 1, what is the diameter of the complete circle?

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for 2, find the area of the non shaded region to find the area of the shaded region

devout snowBOT
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@coral tulip Has your question been resolved?

magic pine
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@coral tulip can you elaborate on what you’re still unsure about

coral tulip
magic pine
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oh

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i misunderstood the question

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no the complete circle would be the full circle let me take another look

coral tulip
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Ok

magic pine
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ok i’m actually not sure how to do that one

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there’s probably an easy geometric trick

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do you happen to have the answer?

coral tulip
magic pine
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is it 2?

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it’s more of a guess than anything but i’m curious

coral tulip
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No its 13

magic pine
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ok then i’m not super sure how to do it sorry

coral tulip
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Ok

magic pine
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focus in the top left of the rectangle

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find the area under the shaded section

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it should be a triangle with base of 4 and height of 3/2

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you have 4 of those, and then 2 rectangles with base 4 and height 5/2

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the sum of all of those gives you the unshaded area

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is the answer 6?

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to make sure i’m not spouting off wrong stuff

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weary granite
#

i need df(A, b, λ) / dλ for a propagation of uncertainty

devout snowBOT
#

@weary granite Has your question been resolved?

devout snowBOT
#

@weary granite Has your question been resolved?

devout snowBOT
#

@weary granite Has your question been resolved?

devout snowBOT
#

@weary granite Has your question been resolved?

devout snowBOT
#

@weary granite Has your question been resolved?

coral tulip
magic pine
# coral tulip 15

ok yeah you should have 2 triangles with base 4 and height 1.5, 2 triangles with base 3 and height 2.5, and 2 rectangles with base 4 and height 2.5
summed up you get 6 + 7.5 + 20
the area of the whole rectangle is 8*5
so the shaded area is 40 - 33.5 = 13/2
so p + q = 15

#

sorry for the mixup, i was thinking it was a square for some reason

devout snowBOT
#

@weary granite Has your question been resolved?

frosty cradle
#

!help

devout snowBOT
devout snowBOT
#

@weary granite Has your question been resolved?

nova idol
#

.close

devout snowBOT
#
Channel closed

Closed by @nova idol

Use .reopen if this was a mistake.

devout snowBOT
#
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ancient nova
devout snowBOT
echo sandal
#

Still need help I can help

ancient nova
#

yes

#

ty

echo sandal
#

Ok

#

Lemme write it out

#

Wait

#

You learnt ratios right?

#

@ancient nova

ancient nova
#

yes

echo sandal
#

Okay

#

Ok I got it

ancient nova
#

👍

echo sandal
#

So basically you find what one cup to one glass is

#

Can you find? The ratio of what one cup is to one glass

ancient nova
#

yes

echo sandal
#

Then find

ancient nova
#

isit 3 : 4 or smt

echo sandal
#

Is so basically one cup is 0.75 of a glass

ancient nova
#

mhm

echo sandal
#

So take the

#

24 then calculate it as cups

#

So the 24 glasses is how many cups

#

You know how to find?

ancient nova
#

yes

echo sandal
#

Answer?

ancient nova
#

isit 32

echo sandal
#

Yes

#

Then just add the 32+19

#

Then 72 - (32+19)

#

That’s ur answer

#

Got it?

ancient nova
#

yes

#

tysm

echo sandal
#

Np have a nice day

#

What grade are you?

long fog
ancient nova
#

11

echo sandal
#

Wtf

#

I learned that shit in 6

ancient nova
#

😭 idk i think so

#

cus i dont use grade in my country

echo sandal
#

Year?

ancient nova
#

no

long fog
echo sandal
#

Rly?

echo sandal
long fog
echo sandal
#

India?

#

I’m Sg

long fog
#

Sg?

echo sandal
#

Singapore

#

Shits hard

long fog
#

same

echo sandal
#

Wait i got it right tho yea

#

Like I did it correct catthumbsup

devout snowBOT
#

@ancient nova Has your question been resolved?

#
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devout spruce
devout snowBOT
devout spruce
#

Need help with this one

#

Completely lost

jagged lily
#

Hi.

devout spruce
#

Hello

jagged lily
#

Ok, so…

#

Alright where are you in your calculations currently?

devout spruce
#

Tbh I just don't know

jagged lily
#

Ok.

devout spruce
#

It's random

#

Sry

jagged lily
#

Do you seriously need help to voice call, cause I can work swiftly with that,

#

or do you want me to explain it?

devout spruce
#

Sry

devout spruce
jagged lily
#

Did you figure it out already?

devout spruce
#

?

#

No

jagged lily
#

Do you want help?

devout spruce
#

Yh pls

jagged lily
#

Ok so,

#

Pull up the picture again.

devout spruce
devout spruce
jagged lily
#

So, how would we work with this?

#

We could just add the lengths,

devout spruce
#

24

#

18

jagged lily
#

Label the length and width,

devout spruce
#

K

jagged lily
#

We can label the inner rectangle as ABCD for now,

#

And label the outer rectangle as 1234

#

Rectangle ABCD has length 18 and width of 12

devout spruce
#

Hm

jagged lily
#

And

#

Rectangle 1234 has length 30 and width 24

#

All you need to do is find out if the ratio is the same, and that is how you solve it.

devout spruce
#

216:720

jagged lily
#

Not multiplying,

#

Find out in fraction form.

devout spruce
#

Oh

#

Hmm?

jagged lily
devout spruce
#

Oohhhhh

#

👍👍👍👍👋

jagged lily
#

You should have some basis on this now.

#

You’re welcome 🙂

devout spruce
#

Thx

#

.close

devout snowBOT
#
Channel closed

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#
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terse remnant
#

QUESTION

devout snowBOT
terse remnant
#

what is (sin45˚) (sec60˚) equals to??

pseudo basin
#

what's troubling you with this expression?

terse remnant
#

idk how to solve it

#

i need help with solving it

magic sun
#

use scientific calculator

terse remnant
pastel pasture
#

do you not know the values of sin 45 and sec 60?

pastel pasture
#

you really should

terse remnant
#

cmon bro

magic sun
#

I wonder if your teachers taught this?

terse remnant
#

i just started out with trigonometry

pastel pasture
#

there's really not much that can be done here

terse remnant
pastel pasture
#

you need to memorize the values

terse remnant
#

im self learning

pastel pasture
#

ah

magic sun
#

you should start on angle measures

terse remnant
#

you guys ARE my teachers

pastel pasture
#

look up a table with the angles

#

and memorize that

terse remnant
pastel pasture
#

its how it starts in trig opencry

terse remnant
#

but i can just use a science calc to solve it?

pastel pasture
#

i suppose

terse remnant
#

if so what do i put in the calc do i just put sin45˚ sec 60˚?

pastel pasture
#

tbf you need only the values of sin and you can derive everything else quickly

magic sun
#

yes you can. And even without one you can as long as you know their values

terse remnant
terse remnant
#

does sec have a value?

magic sun
#

raise cos to -1

#

sec and cos are reciprocals

terse remnant
terse remnant
pseudo basin
#

you don't need a calculator btw

#

45 and 60 degrees are special angles

terse remnant
#

special?

pastel pasture
pseudo basin
#

whose trig values should be on instant recall

pastel pasture
#

because if you start with

#

$\cos^{-1} x$

magic sun
#

Cos X = 1/sec(X)
Sec X = 1/cos(X)

pseudo basin
#

like the multiplication table

terse remnant
woven radishBOT
#

NEONPerseus

magic sun
#

no that's different

pastel pasture
#

I'm just gonna get a bingo slot

#

yes

magic sun
#

That inverse

tropic current
# terse remnant does sec have a value?

just memorize the 30, 45, 60 and 90 values of each trig. sec, cosec and cot are reciprocals of cos, sin and tan anyways so u don't need to memorize that much. it will become instant as u practice anyways

magic sun
#

(cos X)^(-1)

Not cos^(-1) x

devout snowBOT
#
Channel closed

Closed by @terse remnant

Use .reopen if this was a mistake.

pastel pasture
#

if you're star

devout snowBOT
#
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forest lily
devout snowBOT
forest lily
#

Hello

vernal monolith
#

where are you stuck?

forest lily
#

is this = ?

#

2x*

vernal monolith
#

should have been 3 instead of 3³, other than that it seems correct

#

nah nvm its correct

forest lily
#

how do I proceed from there

#

?

vernal monolith
#

isolate terms with exponents on one side

#

and use the fact that (a^2x) = (a^2)^x

forest lily
#

so

vernal monolith
#

then take log base a (there is x instead of a in your question)

#

on both sides

forest lily
vernal monolith
#

you can group 25^x and 40^x together since they have the same exponent

forest lily
#

so it's (1000)^x

vernal monolith
#

you can type that as 10^3x if you would'd like

#

take log base 10 on both sides, then it should be over

forest lily
#

ahhhh

#

alright

#

thank you

vernal monolith
#

np

forest lily
#

.close

devout snowBOT
#
Channel closed

Closed by @forest lily

Use .reopen if this was a mistake.

#
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proud nimbus
#

option A correct ans ?

devout snowBOT
proud nimbus
dull otter
proud nimbus
#

thanks

#

.close

devout snowBOT
#
Channel closed

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devout snowBOT
#
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rich barn
devout snowBOT
rich barn
#

can some one please help me understand this question

#

specfically the first part

#

the criteria for indepence is E[XY]=E[X]E[Y]

#

as i have written

#

and it meets it for this question

acoustic vault
#

it meets what?

devout snowBOT
#

@rich barn Has your question been resolved?

rich barn
acoustic vault
#

independance -> E[XY]=E[X]E[Y]

#

not the other way around

#

so in the 1st part they use contrapositive logic

#

not (E[XY]=E[X]E[Y]) -> not (independance)

#

they did it for X^2 and Y^2 though but its the same

rich barn
#

E[X]=0

#

E[Y]=0

acoustic vault
#

yes, so using E[XY] is inconclusive

#

in terms of dependancy

rich barn
#

why is it inconlusive

#

it meets the requirement

acoustic vault
#

do you understand that logic doesnt necessarily go both ways?

#

independance -> E[XY]=E[X]E[Y]

rich barn
acoustic vault
#

this means that IF it is independant that implies the E[XY] part

#

but if the E[XY] part is true it doesnt mean that it is independant

#

the arrow only goes one way

#

not both ways

#

independance -> E[XY]=E[X]E[Y]

rich barn
#

still not following

acoustic vault
#

ok lets generalise then

#

A -> B

#

lets say A is you are in texas

#

and B that you are in usa

#

its clear that A->B right?

#

but B->A is not true

rich barn
#

yes

#

and yes

acoustic vault
#

its the same here

rich barn
#

ok so E[XY]=E[X]E[Y] for independence

#

but if E[X]E[Y}=E[XY]

#

its not indepence

acoustic vault
#

its inconclusive. you cant say anything

#

it can be dependant or independant

rich barn
#

like the texas and us example it amkes sense

#

but the this is math

#

it like saying 2=2*1

acoustic vault
#

yes but only one way has been proven to be true.

#

nooo

#

always be careful

#

when looking at theroems

#

$A\rightarrow B$ and $A\Leftrightarrow B$

woven radishBOT
#

Køter

acoustic vault
#

are very different things

rich barn
#

ok

#

bu we are not dealing with arrows here

#

we are dealing with = sign

acoustic vault
#

you are not dealing with =

rich barn
#

this is my chat

acoustic vault
#

you are dealing with an arrow

round crest
#

Sorry for interruption

rich barn
#

please delete and exit and open a new one for yourself

acoustic vault
#

independance -> E[XY]=E[X]E[Y]

#

this is what the theorem states correct?

rich barn
#

yes

#

and E[XY]=0

#

and so does E[X] and E[Y]

acoustic vault
#

yes so its inconclusive because the arrow goes only one way

#

the E[XY]=E[X]E[Y] part is true

#

but we cant conclude the LHS of the arow is true

#

because it only goes right

rich barn
#

what is the LHS of the arrow

acoustic vault
#

independance

#

in english it would usually be written

#

'if X and Y are independant then E[XY]=E[X]E[Y]'

rich barn
#

ok so shouldnt this apply to E[X^2Y^2]=[X^2]*E[Y^2]

acoustic vault
#

it does aswell but here they used contrapositive logic

#

so lets go back to our texas and usa example

#

do you agree that if you are NOT in usa then you are NOT in texas?

acoustic vault
#

so $A\rightarrow B$ is logically equivalent to $not B \rightarrow not A$

woven radishBOT
#

Køter

rich barn
#

yes

acoustic vault
#

in this case they showed NOT E[X^2Y^2]=E[X^2]E[Y^2]

#

so this implies NOT independant

rich barn
#

i must be missing something

#

i stil dont ge it

#

okay back to texas =usa

#

example

acoustic vault
#

not =

#

its ->

rich barn
#

ur talking about sets and subsets

#

so usa is a set

#

texas is a sub set

acoustic vault
#

not necessarily

#

just think of them as events

rich barn
#

that is why usa and texas example makes sense

#

If i calculate E[XY] to be 2

acoustic vault
#

ok i mean if we assume it goes both ways your example right?

rich barn
#

and I calculate E[X]=2 and E[Y]=1

#

then E[XY]=E[X]E[Y]?

acoustic vault
#

yes

rich barn
#

so they are so they are independent?

acoustic vault
#

no

#

for the 10th time

#

E[XY]=E[X]E[Y] does not IMPLY independancy

#

independancy IMPLIES E[XY]=E[X]E[Y]

#

lets even look at your exmaple

#

if its not intuitive

#

you have E[XY]=E[X]E[Y]

rich barn
#

i thnk it get it

#

let me summarise

acoustic vault
#

but $E[X^2Y^2]\neq E[X^2]E[Y^2]$

woven radishBOT
#

Køter

acoustic vault
#

so which one do we trust?

rich barn
acoustic vault
#

by your logic it would be both independant from the first result and dependant from the 2nd right?

#

$E[XY]=E[X]E[Y]$ and $E[X^2Y^2]\neq E[X^2]E[Y^2]$

woven radishBOT
#

Køter

acoustic vault
#

which do we trust then?

rich barn
#

give me a min

#

are we going along with "If i calculate E[XY] to be 2" & "E[X]=2 and E[Y]=1"?

acoustic vault
#

no the problem you sent in you found that

#

$E[XY]=E[X]E[Y]$ and $E[X^2Y^2]\neq E[X^2]E[Y^2]$

woven radishBOT
#

Køter

rich barn
#

to me there both contradicotry

#

however my notes talked about the first one

#

so im going to go with the first one alhtough u have rpeatedl told me its wrong

acoustic vault
#

but the 1st one according to YOUR logic. should show independance

#

and the 2nd one according to YOUR logic should show dependance

#

but it obviously cant be both

#

so there is nothing wrong with the problem

#

its your logic

rich barn
#

so your saying just becauseE[XY]=E[X]E[Y]

#

it doesnt mean that its independent

acoustic vault
#

exactly!

rich barn
#

all that it means is that it could be

#

so I would have to do E[X^2*Y^2]=E[X^2]E[Y^2]

#

and that would tell me whether its independent or not?

acoustic vault
#

if it was equal then it doesnt tell you anything either

#

its only because you found a case that wasnt equal

rich barn
#

i see

#

and also correct me if im wrong but E[XY]=E[X]E[Y] is not enough in this case because its dealing with non linear(sinusoidal) functions?

acoustic vault
#

it is never enough

#

let me give you an intuitive example

#

monday -> rains

#

i task you with finding out whether its monday or not

#

when can you actually get any good information?

#

if its raining or not raining?

rich barn
acoustic vault
#

well no, because it can also rain on a tuesday or any other day

#

so you cant actually say its monday

rich barn
#

ohhw ait i read tht wrong

acoustic vault
#

just because its raining

rich barn
#

so when its not raining because then i know its definetly not monday

acoustic vault
#

yes

rich barn
#

when its raining it could be any day of the week

#

but it always rains on monday

#

that is certain

acoustic vault
#

so here you look for when $E[XY]\neq E[X]E[Y]$ so you can know for sure that its not independant

woven radishBOT
#

Køter

rich barn
#

so when its not raining you know that definetly not monday

acoustic vault
#

yes exactly

rich barn
#

ok i get it

acoustic vault
#

and obviously if X^2 and Y^2 are independant so are X and Y

rich barn
#

thank you

acoustic vault
#

np

devout snowBOT
#

@rich barn Has your question been resolved?

#
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restive river
#

may i get explanation on this question

devout snowBOT
weak cove
#

that seems like the proper setup to me

#

What are you struggling with?

restive river
#

i dont get how to probably start with this qs

weak cove
#

did you make that setup in blue inking there?

#

that's a good start

#

What would happen if you performed that matrix multiplication on the left, leaving the results in terms of "a" and "b", what would the two components you get be?

restive river
#

i have been watching a video and i didnt get what theyve done here, i mean y a and b has to be written?

weak cove
#

What they have done where?

restive river
#

the equation is xa = (4 -2)

weak cove
#

Yes

#

can I point out a few things that might help you?

restive river
#

yes

weak cove
#

The matrix on the left is a 1x2 matrix

lusty sapphire
#

Are you familiar with matrix multiplication in general?

weak cove
#

and the matrix "X" is unknown in dimensions, but the matrix A is 2x2

restive river
#

I am

weak cove
#

so you have to decide "X"s dimensions

#

what size matrix, multiplied from the left times a 2x2 will produce a 1x2 matrix

#

if you don't know, a m x n matrix times a n x m matrix will produce a m x m matrix. Additionally n must equal n for the multiplication to be possible

restive river
#

is this is how ive to think on it?

weak cove
#

Yes this is a good way to begin approaching this question

#

let me know when you decide what dimensions "X" should be

restive river
#

okay then I need to do these kinds of questions

lusty sapphire
restive river
#

thank you

weak cove
#

true

restive river
#

.close

devout snowBOT
#
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visual urchin
#

How would I set this up

devout snowBOT
visual urchin
#

Ik we are solving limit

#

.close

devout snowBOT
#
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lucid mulch
devout snowBOT
lucid mulch
#

do I have to integrate this whole thing for p3

nova idol
#

Bro what else could you do

lucid mulch
#

no clue

nova idol
#

It integrates nicely

lucid mulch
#

i just dont wanna integrate that

#

it looks so hard

nova idol
#

It’s not at all hard

#

set u = x-2

lucid mulch
#

the issue is the algebra

#

cuz its not indefinite

#

i dont want to do all that work if its not even right

nova idol
#

It takes like 2 min

lucid mulch
#

ok ok il do it

nova idol
#

You could be waiting here for a while

lucid mulch
#

i cant integrate t

lucid mulch
#

it was pretty easy ngl

#

do you know what part D is tho

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I think it would be the same

restive river
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why do you think its the same?

lucid mulch
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because P4(x) is an approximation of f(x)

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so it would be slightly different

restive river
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approximation

restive river
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it depends on f

lucid mulch
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tysm

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.close

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wet zinc
#

Hi! I've got a question about map colouring. The question is:
Consider a map where each country may consist of up to $k$ disconnected regions. For example, Russia has a region bordering Poland and Lithuania that is disconnected from the rest of the Russian mainland. Prove that the minimum number of colours needed to colour such a map is no larger than $6k$. We require that all disconnected regions of a country be coloured by the same colour.

I've tried approaching it with induction on $k$, or induction on the number of countries, but neither approach really seems to lead anywhere.

woven radishBOT
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Roberto Tan

wet zinc
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<@&286206848099549185>

sand dove
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!status

devout snowBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
wet zinc
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1

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tried a couple things but haven't managed to find anything substantial that might indicate I'm on the right track

sand dove
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Have you tried recurrence?

wet zinc
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No I haven't, how do you use that in this context? I know about recurrence in the context of algorithms mostly

sand dove
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Try to prove the statement $P_k$ : "For any map with any number of countries having at most $k$ disconnected regions, then this map can be coloured with at most $6k$ different colours" for any $k\in \bN *$

woven radishBOT
#

rafilou2003

sand dove
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(by recurrence)

wet zinc
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I don't really know what you mean by using recurrence. I know recurrent functions: e.g. fibonacci where $F_n = F_{n-1} + F_{n-2}$, but that evaluates to a number. How do you use recurrence on a logical statement instead of a function that evaluates to a number?

woven radishBOT
#

Roberto Tan

wet zinc
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As for the statement $P_k$: $P_1$ holds because of the four-colour theorem obviously, but I wouldn't know where to start using $P_k$ to prove $P_{k+1}$, or even just how to show that $P_2$ holds. I considered for example first treating all regions of a country as different countries, but then the "merging procedure", where you have to make sure each country gets the same colour for all its regions, is not at all straightforward as far as I can see

woven radishBOT
#

Roberto Tan

sand dove
# woven radish **rafilou2003**

Basically, how recurrence proof works :
Step 1) Prove the very first statement of the list, here it is $P_1$ (called initialisation).
Step 2) Prove that for any $k\in \bN$, if $P_k$ is true then $P_{k+1}$ is true

woven radishBOT
#

rafilou2003

wet zinc
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Ah I know this concept as induction

sand dove
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ah

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yeah so proof by induction

wet zinc
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But yeah I tried using induction, but couldn't figure out how to do the inductive step

sand dove
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you did the induction on the number of disconnected regions, and not the number of countries right?

wet zinc
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Yeah so assume that $P_k$ holds. Then, consider a map with countries where each country has at most $k+1$ disconnected regions. Then, for each country with $k+1$ disconnected regions you could remove one region, and use $P_k$ to get a valid colouring for that map

woven radishBOT
#

Roberto Tan

wet zinc
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But then how do you add the $k+1$st regions for all those countries back in

woven radishBOT
#

Roberto Tan

sand dove
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Well, consider the map formed only by all of the regions you removed

wet zinc
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Yeah that has a valid colouring by the four-colour theorem

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So by using four colours you could colour that map

sand dove
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ah I see

wet zinc
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That makes sense, but the problem is that all the disconnected regions of a country have to have the same colour

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So yeah not sure how to do the inductive step

devout snowBOT
#

@wet zinc Has your question been resolved?

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@wet zinc Has your question been resolved?

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molten hollow
devout snowBOT
molten hollow
#

why can't we use this formula in this question

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i suppose it's because of the x in the integrated function but

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i'm not really sure why we can't just set x as a constant and still proceed with this formula

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therefore my question is when does this formula not work

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<@&286206848099549185>

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btw this is the answer

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@pale ingot

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left relic
#

Dream is trying to rizz up some girls. Each time Dream tries to rizz up a girl, there is a $0.01$ percent chance of the girl getting together with him. If Dream tries to rizz up $50$ girls, what is the probability that he will get together with at least $1$ girl? Assume that each girl's decision is independent from every other girl.

woven radishBOT
#

LukeyThePookie

left relic
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I tried doing casework with 1 girl, 2 girls, 3 girls, and so on, but that would take very long

weak cove
#

Lets not troll

#

.close

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astral beacon
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weary void
#

lol

devout snowBOT
#

@astral beacon Has your question been resolved?

astral beacon
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.close

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frail igloo
devout snowBOT
frail igloo
#

pls don't laugh at me

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for det(-3A) and det(A^T) i am unsure why i'm wrong

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although 3^T seems pretty laughable to me

main gull
frail igloo
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yea i just read that

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i'm rushing. i should stop flooding the channels.

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thank you.

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.close

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frail igloo
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okay so maybe i do need help

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i'm aware that

main gull
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.reopen

devout snowBOT
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main gull
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Where n is the size of the matrix

frail igloo
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omg

main gull
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Times by the det

frail igloo
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so

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-3^2 * 3?

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that doesnt seem right

main gull
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Well you need parentheses around -3

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But that's right

frail igloo
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ohhh

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so 27

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lol thank you ._.

main gull
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.close

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restive river
#

can someone help?

devout snowBOT