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Okay maybe this question is a bit too excel-y, but I am just looking to understand the Math behind it.
Here is the gist of it; there is a concept called cannibalisation in accounting, which is the number of customers that would transition from using an old product to a new product you just introduced (Think about Coca-cola and diet cola, for example)
This example I have here mentions a scenario of someone selling regular umbrellas and then introducing wide umbrellas to their sales; you know that 25% of the customers would end up transitioning to purchasing wide umbrellas, which ends up giving you a larger profit than when you had only just sold the regular umbrellas (You will be earning 1,150 instead of 1,000)
My question is relating to how they calculated the maximum cannibalisation rate, which is the percentage of how many customers could transition from buying your old product to your new product without giving you less profit than if you had only sold the regular umbrellas
The way they calculated that is by taking the profit you got from your wide umbrellas (400) and divided it by the contribution margin of your regular umbrellas (10) and then further divided that by the sales of your regular umbrellas (100)
I can't quite seem to understand why those calculations make sense?
you're actually here
@restive river Has your question been resolved?
<@&286206848099549185>
hmmmm
@restive river Has your question been resolved?
the amount of sales is 400?
you can represent this by this
n stands for new product
e stands for old product
one second forgot somethin
@restive river
and your question is basically asking,
Why does this big formula equal this other simpler formula?
Well, if you recall
Contribution = S(F-V) where S is the sales, F is the fixed price and V are the variable prices
it should be easy to figure this out
ill leave this up to you
@restive river any minute now...
it should click
and you should go like "ohhhhh"
any minute now
the answer is like
right there
this is gonna be us
ill be drake and you will be lil yachty
lixera any minute now...
you may even close this channel instantly
since the answer
is right there
it makes total sense
super easy to understand
right here...
you just need to figure out why they are equal
thats the question you asked
any minute now...
in case you dont understand the formula...
its just a matter of notation
and rewriting...
you gotta look at the big picture...
and i mean the picture i sent
explains it all...
@restive river Has your question been resolved?
@restive river any minute now...
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how to solve (-1-sqr2)^2 ? learning basic geometry (9th grade) and im not the proficient with square roots
do u mean simplify
yeah i do mean that
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how can i prove that AE is a diameter?
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if we have an improper intergral that is a discontinuous integrant, how do i know if it approaching from the left or right
for this improper intergral, how did we know it was approaching 3 from the left in the limit
Okay so
We observe the function
And we find the locations of our undefined points within our bounds
yup so when x = 3
Yepp
So when x = 3, the function is undefined
Now x=3 is exactly the upper bound
And if we drew a diagram, we will see that we will need to approach x = 3 from the left
so like for a lot of improper intergrals, its best to visualize the graph
Yep
Later on with enough experience, you'll see that upper bounds need to be approached from the left
And lower bounds need to be approached from the right
But you will need experience to have that in your mind
experience because it doesnt apply to all cases correct?
@restive river Has your question been resolved?
nothing makes sense to me in math 💀
Aww
Math needs a bit of focus and a good ol' cup of your favorite drink and a bit of time to solve the problems you have for homework
And it's all a game of using rules to your advantage
im not giving up
ever
on that topic, could i ask about the comparrison test as well
for improper intergrals
it is confusing me
Oh sure :)
@restive river Has your question been resolved?
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If 20 / 5 = 4 groups each containing 5 parts. That means that 4 = 20 parts.
So if you multiply 4 x 5 = 20. You are actually multiplying 20p x 5p = 100p.
20 = 100p
So multiplication doesn’t seem to be “reverting” division it just seems to increase it.
How am I wrong?
So each group contains 5 parts
Since there are 4 groups, there are 20 parts
So if I were to multiply, 4 x 5, it wouldn't be inverting it, it's just increasing it's already set quantity
So how is multiplication inverse to division?
You're dividing 20 into 4 groups. But there's still 20 in the total of the groups
So if I multiply 4 (Which still has 20 in it) by 5 it would give you 100
each group has 5 in it
so if you're multiplying 20 by 5 you're multiplying each group by 5
20x5 = 4x5x5
like fucktalogist said, you're treating the group as a part, which it isn't
Why?
But wouldn't the "new" 1 become some sort of unit? Since we divided 20 into 4 groups. The 1 represents 5 parts no?
1 group represents 5 parts
1 does not represent 5
you can not just drop terminolgoy like that
which is how you get 20= 100
But isn't that how division is defined? 20 is divided into 5 equal groups of 4
But the result will be 4, and in each one there will be 5
Since 20 is divided into 4 groups, and the groups in total all contain 20, which would give you 5 in each group. And each 1 thereafter would represent 1 group
And each group, represents 5
I don't understand your problem
Where does the 5s in each group go
in the group...
if there are 20 people
and group A, B, C, D
in group A there are 5 people
in group B there are also 5 people
same for C and D
So there are 4 groups of 20 people. So in total there are 20 people
Every 1 represents a group with 5 people in it
yes
what
no
there are 4 groups with 5 people each
So every group has 5 people in it
yes
So 1 (5) + 1(5) + 1(5) +1(5) = 4(20)
incorrect
why
No its not multiplication
Yeah my bad: 1 (people in group 5) + 1(people in group 5) + 1(people in group5) +1(people in group 5) = 4(people in group20)
Why is there a one there
The 1 represents each group
It’s still multiplying
4 groups with 5 people inside it
20 / 5 = 4
=20
20 / 5 = 4
(5 people in 4 groups.)
20 / 5, is 20 divided into four groups. In each group there is a portion of 20
Which is 5
Yes
So there are 4 groups, with 5 inside each of them. Meaning there is 20 in total.
So if I were to multiply those 4 groups with 5 inside of each of them, times 5, it would give you 100
since the 4 groups represent the value of 20
sure, thats just 20*5
So if 20 / 5 = 4 groups each containing 5 parts. That means that 4 = 20 parts.
No
4 is the number of groups
20 is the number of parts
you cant just say 4 = 20
And inside each group, there are 5 parts
20 / 5 = 4 . Aren't you already saying that in this expression? Since its 20 divided evenly into 4 groups of 5
So if were to multiply this, it would be 4 groups, 5 times. Each group, has 5 in it.
So it would give you 100 parts, and 20 groups of groups
It wouldn't give you 20 parts
So meaning, the 20 you started dividing with. And the 20 you ended up with after multiplying. Is not of the same value
4 groups = 20 parts
multiply both sides by 5
20 groups = 100 parts, each group has 5 in it by definition
20 x 5 = 100
please tell me what is not clear in these steps
Yes so. If we have 20/5(5) You would get 100 parts and not 20 parts
Since 20/5 = 4 groups. And each groups has 5 parts. Meaning it has 20 parts
So if you were to multiply 4 groups 5 times, you would get 100 parts
what do you disagree with in these steps
just tell me explicitly so I can help you faster
So 20/5(5) is equal to 100
The 20 you start with, is not the same as you end up with
The first 20 is parts, the one you end up with is groups
how are you getting that
how
But we're putting 20 into 4 groups, each with 5 of the 20
So each 1 has 5 in it
so 20/5 = 20 parts
is 20 one fifth of 20
No, it'd be 20 parts and 20 in total for the 4 groups
the value of 20/5 is "how many groups are there, when we split 20 parts into groups of 5?"
There are 5 groups, each with 4 in them
But 20 is still there
Since each group has 4
5 groups is not = 5
But 4 parts per group (which there are five) is 20
4 parts per group. There are 5 groups, So the value of this is 20
yes thats what this says
But there are already 5 groups
I already watched this
you need to go and watch all these videos and do the whole course pretty much
Ill go watch it fully. But thanks, I think after this I might be getting closer
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can someone help me go about wrapping my head around this problem? It's an optimization problem. As far as I understand I need to get the height of the rod in terms of r, but in order to do that I need the volume, which I don't have.
It just to me doesn't seem like enough information to find the length, I know that the rods have a maximum height of 1 but I don't see how that could be relevant
I can also post the answers if needed
any help is appreciated!
i think you want to express the volume of the cylinder in terms of the height of the rods
and then maximise that with respect to the height of the rods
how would I be able to do that for V = pi r^2 h? Wouldn't volume already be isolated?
let R be the rod length
you know that h = R
and you can determine the radius of one of the circles (r) in terms of R
How would the rod length help find the radius of one of the circles though? Aren't they both independent of each other?
because the length of the rods and the circumferences of the circles must add up to 4m
ahhh I thought that the circles would be a constant and weren't made up of the bendable rod aswell.
I wrote an equation like this: 4 = 4R + 2C where C is the circumference
Then subbed in C = 2pi r
then isolated for r and got (1-R)/pi = r
am I on the right track or no?
so V(R) = pi((1-R/pi)^2)R?
yes yes
now maximise V(R) wrt R
within some constraints on R that you've already mentioned
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LeftySam
@tidal haven Has your question been resolved?
@tidal haven Has your question been resolved?
um
more simpler terms?
i mean how would you explain functions to a complete newbie
like a high schooler
i do have some kind of a source to understand this but, i wanted to understand it in more layman terms
thank you for your time
aight thank you
@tidal haven Has your question been resolved?
@tidal haven Has your question been resolved?
LeftySam
LeftySam
LeftySam
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
LeftySam
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James wants to design an optimal weekly time table which satisfies the following requirements over a time period of 9-10 months:
•Number of periods per week: 13
•Subject A: 156 lectures.
•Subject B: 148 lectures.
•Subject C: 181 lectures.
is it linear programming?
How do i make the most optimal time table
???
maybe finding the hcf would help
I am getting 1 as a hcf
hmm
do we have to make the timetable for 9 months or 10months??
But like they have mentioned a range 9-10 months so i think can we manupulate the values a bit?
Of the lectures i mean
So that it fits perfectly
Acc according to the needs
that means we can have 36 to 40 weeks
get the natural number between them
Yes for optimal we should take average right?
3.9
Which is roughly 4
For subject A its stated that there are 156 lec so: 3.9 to 4.333
basicaly you get a range that for lecture of b you can watch between 3.7 to 4.1 lectures per week
Average is 4.1 here
so optimal one here means that you can watch 4 complete lectures per week of subject b
But there i have to make a weeky timetable too
Oooh hmm yes
yes
sum of per week lectures of each subject should be 13
Average is 4.1 which is rougly 4
you need not take average
cuz how will you manage to watch exactly 4.1 lectures
True
thats why prefer to choose a natural number between the range
For C: 4.52-5.02
ya
yes
ya
Now how do i optimally arrange these in a week
ig the ques just asked to arange it week wise
or else number of lectures per day would also be given
But isnt the range given?
yes
and with help of it we figured weekly lecture goals of each subject
If it is there has to be limited number of lectures that a person can watch per day
but how he manages to watch them is not given
So i should report weekly readings right?
yes
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Hey can you help me with Question 6) I can translate it from German, it says
Given is the Point P (1 -2 1) and the point Q (13 13 17)
a) Calculate the midpoint M of the line segment PQ
b) Calculate an equation of the plane that is perpendicular to PQ and passes through M."
@restive river Has your question been resolved?
are you having difficulty finding mid point
yeah
The midpoint between the point of PQ
I think I have a way but im not sure if its right
My Idea is
M = 1/2 * (P + Q)
fäf
good
ah
okay thank you
so
M = 1/2*(P+Q)
M = 1/2*(14,11,18)
M = (7, 5.5, 9)
so that leaves the b)
fäf
god dyslexia
is X a stand in for M ?
X=(x,y,z)
okay thanks
@restive river Has your question been resolved?
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for 1, what is the diameter of the complete circle?
for 2, find the area of the non shaded region to find the area of the shaded region
@coral tulip Has your question been resolved?
@coral tulip can you elaborate on what you’re still unsure about
Complete circle is the one which is inside the largest semi circle?
oh
i misunderstood the question
no the complete circle would be the full circle let me take another look
Ok
ok i’m actually not sure how to do that one
there’s probably an easy geometric trick
do you happen to have the answer?
Yes
No its 13
ok then i’m not super sure how to do it sorry
Ok
How do we do this?
focus in the top left of the rectangle
find the area under the shaded section
it should be a triangle with base of 4 and height of 3/2
you have 4 of those, and then 2 rectangles with base 4 and height 5/2
the sum of all of those gives you the unshaded area
is the answer 6?
to make sure i’m not spouting off wrong stuff
@coral tulip Has your question been resolved?
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i need df(A, b, λ) / dλ for a propagation of uncertainty
@weary granite Has your question been resolved?
@weary granite Has your question been resolved?
@weary granite Has your question been resolved?
@weary granite Has your question been resolved?
@weary granite Has your question been resolved?
15
ok yeah you should have 2 triangles with base 4 and height 1.5, 2 triangles with base 3 and height 2.5, and 2 rectangles with base 4 and height 2.5
summed up you get 6 + 7.5 + 20
the area of the whole rectangle is 8*5
so the shaded area is 40 - 33.5 = 13/2
so p + q = 15
sorry for the mixup, i was thinking it was a square for some reason
@weary granite Has your question been resolved?
!help
Please read #❓how-to-get-help
@weary granite Has your question been resolved?
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Still need help I can help
yes
👍
So basically you find what one cup to one glass is
Can you find? The ratio of what one cup is to one glass
yes
Then find
isit 3 : 4 or smt
Is so basically one cup is 0.75 of a glass
mhm
So take the
24 then calculate it as cups
So the 24 glasses is how many cups
You know how to find?
yes
Answer?
isit 32
passed out
11
Year?
no
surprising
Rly?
Wait then what do you use
I probably did this in uni
Sg?
same
@ancient nova Has your question been resolved?
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Hi.
Hello
Tbh I just don't know
Ok.
Do you seriously need help to voice call, cause I can work swiftly with that,
or do you want me to explain it?
Sry
It's ok
Did you figure it out already?
Do you want help?
Yh pls
This
K
We can label the inner rectangle as ABCD for now,
And label the outer rectangle as 1234
Rectangle ABCD has length 18 and width of 12
Hm
And
Rectangle 1234 has length 30 and width 24
All you need to do is find out if the ratio is the same, and that is how you solve it.
216:720
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QUESTION
what is (sin45˚) (sec60˚) equals to??
what's troubling you with this expression?
well
idk how to solve it
i need help with solving it
use scientific calculator
but idk how to
do you not know the values of sin 45 and sec 60?
nope
cmon bro
I wonder if your teachers taught this?
i just started out with trigonometry
there's really not much that can be done here
i dont have one
you need to memorize the values
im self learning
ah
you should start on angle measures
you guys ARE my teachers
ok
its how it starts in trig 
but i can just use a science calc to solve it?
i suppose
if so what do i put in the calc do i just put sin45˚ sec 60˚?
tbf you need only the values of sin and you can derive everything else quickly
yeah
yes you can. And even without one you can as long as you know their values
oh
ohh
does sec have a value?
i see
ok
special?
honestly just say reciprocate
whose trig values should be on instant recall
Cos X = 1/sec(X)
Sec X = 1/cos(X)
like the multiplication table
oh
NEONPerseus
no that's different
That inverse
just memorize the 30, 45, 60 and 90 values of each trig. sec, cosec and cot are reciprocals of cos, sin and tan anyways so u don't need to memorize that much. it will become instant as u practice anyways
(cos X)^(-1)
Not cos^(-1) x
i see thanks
thanks
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Hello
where are you stuck?
should have been 3 instead of 3³, other than that it seems correct
nah nvm its correct
so
?
you can group 25^x and 40^x together since they have the same exponent
so it's (1000)^x
you can type that as 10^3x if you would'd like
take log base 10 on both sides, then it should be over
np
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option A correct ans ?
yes
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can some one please help me understand this question
specfically the first part
the criteria for indepence is E[XY]=E[X]E[Y]
as i have written
and it meets it for this question
it meets what?
@rich barn Has your question been resolved?
the requirement E[XY]=E[X]E[Y]
independance -> E[XY]=E[X]E[Y]
not the other way around
so in the 1st part they use contrapositive logic
not (E[XY]=E[X]E[Y]) -> not (independance)
they did it for X^2 and Y^2 though but its the same
do you understand that logic doesnt necessarily go both ways?
independance -> E[XY]=E[X]E[Y]
i dont know what you mean by that
this means that IF it is independant that implies the E[XY] part
but if the E[XY] part is true it doesnt mean that it is independant
the arrow only goes one way
not both ways
independance -> E[XY]=E[X]E[Y]
still not following
ok lets generalise then
A -> B
lets say A is you are in texas
and B that you are in usa
its clear that A->B right?
but B->A is not true
its the same here
like the texas and us example it amkes sense
but the this is math
it like saying 2=2*1
yes but only one way has been proven to be true.
nooo
always be careful
when looking at theroems
$A\rightarrow B$ and $A\Leftrightarrow B$
Køter
are very different things
you are not dealing with =
this is my chat
you are dealing with an arrow
Sorry for interruption
please delete and exit and open a new one for yourself
yes so its inconclusive because the arrow goes only one way
the E[XY]=E[X]E[Y] part is true
but we cant conclude the LHS of the arow is true
because it only goes right
what is the LHS of the arrow
independance
in english it would usually be written
'if X and Y are independant then E[XY]=E[X]E[Y]'
ok so shouldnt this apply to E[X^2Y^2]=[X^2]*E[Y^2]
it does aswell but here they used contrapositive logic
so lets go back to our texas and usa example
do you agree that if you are NOT in usa then you are NOT in texas?
so $A\rightarrow B$ is logically equivalent to $not B \rightarrow not A$
Køter
yes
in this case they showed NOT E[X^2Y^2]=E[X^2]E[Y^2]
so this implies NOT independant
lol
i must be missing something
i stil dont ge it
okay back to texas =usa
example
ok i mean if we assume it goes both ways your example right?
yes
so they are so they are independent?
no
for the 10th time
E[XY]=E[X]E[Y] does not IMPLY independancy
independancy IMPLIES E[XY]=E[X]E[Y]
lets even look at your exmaple
if its not intuitive
you have E[XY]=E[X]E[Y]
but $E[X^2Y^2]\neq E[X^2]E[Y^2]$
Køter
so which one do we trust?
what are my optios?
by your logic it would be both independant from the first result and dependant from the 2nd right?
$E[XY]=E[X]E[Y]$ and $E[X^2Y^2]\neq E[X^2]E[Y^2]$
Køter
which do we trust then?
give me a min
are we going along with "If i calculate E[XY] to be 2" & "E[X]=2 and E[Y]=1"?
no the problem you sent in you found that
$E[XY]=E[X]E[Y]$ and $E[X^2Y^2]\neq E[X^2]E[Y^2]$
Køter
to me there both contradicotry
however my notes talked about the first one
so im going to go with the first one alhtough u have rpeatedl told me its wrong
but the 1st one according to YOUR logic. should show independance
and the 2nd one according to YOUR logic should show dependance
but it obviously cant be both
so there is nothing wrong with the problem
its your logic
exactly!
all that it means is that it could be
so I would have to do E[X^2*Y^2]=E[X^2]E[Y^2]
and that would tell me whether its independent or not?
if it was equal then it doesnt tell you anything either
its only because you found a case that wasnt equal
i see
and also correct me if im wrong but E[XY]=E[X]E[Y] is not enough in this case because its dealing with non linear(sinusoidal) functions?
it is never enough
let me give you an intuitive example
monday -> rains
i task you with finding out whether its monday or not
when can you actually get any good information?
if its raining or not raining?
if its raining
well no, because it can also rain on a tuesday or any other day
so you cant actually say its monday
ohhw ait i read tht wrong
just because its raining
so when its not raining because then i know its definetly not monday
yes
when its raining it could be any day of the week
but it always rains on monday
that is certain
so here you look for when $E[XY]\neq E[X]E[Y]$ so you can know for sure that its not independant
Køter
so when its not raining you know that definetly not monday
yes exactly
ok i get it
and obviously if X^2 and Y^2 are independant so are X and Y
thank you
np
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may i get explanation on this question
i dont get how to probably start with this qs
did you make that setup in blue inking there?
that's a good start
What would happen if you performed that matrix multiplication on the left, leaving the results in terms of "a" and "b", what would the two components you get be?
i have been watching a video and i didnt get what theyve done here, i mean y a and b has to be written?
What they have done where?
the equation is xa = (4 -2)
yes
The matrix on the left is a 1x2 matrix
Are you familiar with matrix multiplication in general?
and the matrix "X" is unknown in dimensions, but the matrix A is 2x2
I am
so you have to decide "X"s dimensions
what size matrix, multiplied from the left times a 2x2 will produce a 1x2 matrix
if you don't know, a m x n matrix times a n x m matrix will produce a m x m matrix. Additionally n must equal n for the multiplication to be possible
is this is how ive to think on it?
Yes this is a good way to begin approaching this question
let me know when you decide what dimensions "X" should be
okay then I need to do these kinds of questions
You can generalize this more. A m x r matrix multiplied by an r x n matrix will produce an m x n matrix
thank you
true
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How would I set this up
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do I have to integrate this whole thing for p3
Bro what else could you do
no clue
It integrates nicely
the issue is the algebra
cuz its not indefinite
i dont want to do all that work if its not even right
It takes like 2 min
ok ok il do it
You could be waiting here for a while
i cant integrate t
alr I got 1
it was pretty easy ngl
do you know what part D is tho
I think it would be the same
why do you think its the same?
approximation
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Hi! I've got a question about map colouring. The question is:
Consider a map where each country may consist of up to $k$ disconnected regions. For example, Russia has a region bordering Poland and Lithuania that is disconnected from the rest of the Russian mainland. Prove that the minimum number of colours needed to colour such a map is no larger than $6k$. We require that all disconnected regions of a country be coloured by the same colour.
I've tried approaching it with induction on $k$, or induction on the number of countries, but neither approach really seems to lead anywhere.
Roberto Tan
<@&286206848099549185>
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
tried a couple things but haven't managed to find anything substantial that might indicate I'm on the right track
Have you tried recurrence?
No I haven't, how do you use that in this context? I know about recurrence in the context of algorithms mostly
Try to prove the statement $P_k$ : "For any map with any number of countries having at most $k$ disconnected regions, then this map can be coloured with at most $6k$ different colours" for any $k\in \bN *$
rafilou2003
(by recurrence)
I don't really know what you mean by using recurrence. I know recurrent functions: e.g. fibonacci where $F_n = F_{n-1} + F_{n-2}$, but that evaluates to a number. How do you use recurrence on a logical statement instead of a function that evaluates to a number?
Roberto Tan
As for the statement $P_k$: $P_1$ holds because of the four-colour theorem obviously, but I wouldn't know where to start using $P_k$ to prove $P_{k+1}$, or even just how to show that $P_2$ holds. I considered for example first treating all regions of a country as different countries, but then the "merging procedure", where you have to make sure each country gets the same colour for all its regions, is not at all straightforward as far as I can see
Roberto Tan
Basically, how recurrence proof works :
Step 1) Prove the very first statement of the list, here it is $P_1$ (called initialisation).
Step 2) Prove that for any $k\in \bN$, if $P_k$ is true then $P_{k+1}$ is true
rafilou2003
Ah I know this concept as induction
But yeah I tried using induction, but couldn't figure out how to do the inductive step
you did the induction on the number of disconnected regions, and not the number of countries right?
Yeah so assume that $P_k$ holds. Then, consider a map with countries where each country has at most $k+1$ disconnected regions. Then, for each country with $k+1$ disconnected regions you could remove one region, and use $P_k$ to get a valid colouring for that map
Roberto Tan
But then how do you add the $k+1$st regions for all those countries back in
Roberto Tan
Well, consider the map formed only by all of the regions you removed
Yeah that has a valid colouring by the four-colour theorem
So by using four colours you could colour that map
ah I see
That makes sense, but the problem is that all the disconnected regions of a country have to have the same colour
So yeah not sure how to do the inductive step
@wet zinc Has your question been resolved?
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why can't we use this formula in this question
i suppose it's because of the x in the integrated function but
i'm not really sure why we can't just set x as a constant and still proceed with this formula
therefore my question is when does this formula not work
<@&286206848099549185>
btw this is the answer
@pale ingot
@molten hollow Has your question been resolved?
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Dream is trying to rizz up some girls. Each time Dream tries to rizz up a girl, there is a $0.01$ percent chance of the girl getting together with him. If Dream tries to rizz up $50$ girls, what is the probability that he will get together with at least $1$ girl? Assume that each girl's decision is independent from every other girl.
LukeyThePookie
I tried doing casework with 1 girl, 2 girls, 3 girls, and so on, but that would take very long
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Where did I go wrong?
lol
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pls don't laugh at me
for det(-3A) and det(A^T) i am unsure why i'm wrong
although 3^T seems pretty laughable to me
yea i just read that
lmao
i'm rushing. i should stop flooding the channels.
thank you.
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✅
You realize that says k^n, right
Where n is the size of the matrix
omg
Times by the det
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can someone help?