#help-26
1 messages · Page 119 of 1
Practice definitely helps. And not being afraid to be wrong as well. Learning how not to approach a problem is worthwhile information.
hard problems
and messy problems
those help a lot
and error problems
but to be able to understand the topic is better and what it does
Never erase your mistakes. Make notes on why your approach was incorrect so that you can understand them when you look back on it later. If you don't understand your notes when you look back on them later, that means you need to make better notes.
true true
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short question, what is 3√2 × 2√2?
12
ye ik its 12
but
i mean
give me in other form
like 18√2 + 2√2 is 20√2
18^2 - 2√2 = 16√2
what about 3√2 × 2√2?
is it 6√2?
6(√2)^2 ig?
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I need help with √6(3√6 - 5√6)
hey again
got it
3(√6)² - 5(√6)²
then 3(6) - 5(6)
lastly -12
I literally forgot the thing that someone answer from me before 💀💀
this one
kinda confuse because its just √6
ahhh I see
tyty
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am also sending my working just a minute
so the probability that the second ball drawn is blue will be;
and the probability that the first ball will be blue GIVEN that the second is also blue will be:
and for some damn reason, that similifies to give probability as '1', which is incorrect. Why is it incorrect? 
your numerator gives only the probability that the first ball is blue
ya but we have to find out the probability that the first ball drawn is blue, given that the second is blue as well
Which formula are your referencing for the second picture?
so ur denominator is the probability of the second ball being blue regardless of whatever the first ball was
and ur numerator is the probability of only the first ball being blue
a sample space isn't a probability, this message is gibberish
well I do know that i have to use baye's theorem
ig am not applying it correctly
tho i dont rlly tend to use those formulas, i find it much easier to use tree diagrams for these questions instead of set theory based calculations
but u got my point anyways
no i didn't
the denominator is the probability of the second ball drawn being blue, regardless of what the first ball was
and the numerator is the probability of the first ball being blue, regardless of what the second ball was
and i divided them
alright, so now you need to recall how conditional probability is defined
idk where'd i go wrong :o
because your numerator is incorrect
ohh
If you were to now multiply by P(Second|First) you'd then be using Bayes'
So like your intuition is good, but you are missing this factor
altho i must say, that this is the reason why i still dont get i had to multiply p(second/first)
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necesito ayuda con esta tarea de matematicas
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@jaunty dawn Has your question been resolved?
@jaunty dawn Has your question been resolved?
@jaunty dawn Has your question been resolved?
Thank you! 🙂
pretty crazy surface
yeah, but pretty too 🙂
where did you find the equation?
Was on a homework of my calculus course. The tasks were rather formal but i wanted to know what this thing looked like 🙂
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why is there only 1 answer
is it possible to use the property ab = cd or bd = ac
can you do this
what do u want me to do with that
its already solved
oh the arrows
hmm
no u cant
A is already connected to D
you cant break that connection and force it to C
like u cant change pre-existing sides is what im saying
the sides that already existed were AB and AD
cant change those
@nocturne oracle
if it wasnt given, then yes, you could get another solution
its not up to me to say this
ask ur teacher
also, the diagram looks kinda off
in terms of the labeling of the points
ok thx just wanted to make sure 2 answers is a possible outcome
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Question: A study was conducted to determine how the concentration of cough medicine changes over time in the bloodstream. It was found that the concentration decreased by 15% each hour for a patient who received a 10𝑚𝑔 dose.
Determine a general equation to represent the amount of the drug remaining in their system, 𝐴, as a function of 𝑡, the number of hours since the dose was administered.
Am I using the exponential growth/decay formula to answer this?
yes
what is your initial amount
10
so what is your Ao
no
Ao is "A naught"
and my A is unknown
wait how about my n value
yea
0.15
so lets say i have 1
yea
0.85
dont think so
I kept trying to figure out my n
decreased by 15% each day
not each hour
and t is in hours
then u would need it but
I got 8.5 as my final answer
you cant disturbute the 10(.85)
because
.85 is rasied to t
like thats ur equation
u cant mutiply 10 x .85
because 10 isnt raised to t aswell
yea I ended up subbing 1 into t for some reason
part 2 of the question asks after how many hours will a person have 1mg of the drug remaining in their system, round to tenth of hour
could you do it and check answer with mine
ok
what did u get
what did u do first
oh
ye
ye
you just a(t)=1
say
or i see what u did, it doesnt really matter
idk if i would directly state a(t)=1 but it doesnt really matter
I see
I have lost marks before for doing some extra stuff
I may just leave it out come assessments
thank you propus that is 2/2
👍
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The first question of the page asks to simplify the expression
@bronze atlas Has your question been resolved?
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So for this question i think the right answer but ive seen people answer this question they get 5.77 and i get 4.57 so i'd like to know what im doing wrong
Use opposite interior angles theorem to figure out the degree of angle R
why not?
oh so thats why that line is there
mhm
Ok, dumb question if for interior triangle we only have 1 angle how can we get the rest
do i build another triangle with that 70?
or would it be half of 70?
nope
given PQ and RS are parallel since they run north south,
we know that the angle PQR = angle QRS
using alternate interior angles
and we know that PQR = 25, so QRS equals 25
ok im not great this yet give me a sec to process
So this basically
but 70 is still not the angel of either
uh
not really
gimme a sec
the smaller angle is 25
larger one is 70
it’s not very accurate to scale but it gets the image across
mhm
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Help me with this one
!15m
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Sorry but this was eating my mind
$$\frac{1}{\sqrt{27}}^{2-\frac{\log_{5}{13}}{2 \log_{5}{9}}}$$
$$\frac{1}{\sqrt{27}}^2 \cdot \frac{1}{\sqrt{27}}^{-\frac{\log_{5}{13}}{2 \log_{5}{9}}}$$
$$\frac{1}{\sqrt{27}}^2 \cdot \sqrt{27}^{\frac{\log_{5}{13}}{2 \log_{5}{9}}}$$
$$\frac{1}{\sqrt{27}}^2 \cdot \sqrt{27}^{\frac{1}{2} \cdot \frac{\log_{5}{13}}{ \log_{5}{9}}}$$
using the property $\frac{\log_{c}{b}}{\log_{c}{a}}=\log_{a}{b}$
$$\frac{1}{\sqrt{27}}^2 \cdot \sqrt{27}^{\frac{1}{2} \cdot \log_{9}{13}$$
$$\frac{1}{27} \cdot \sqrt{27}^{\frac{1}{2} \cdot \log_{9}{13}$$
Skill_Issue
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does this make sense?
🍑
Does it make any difference
wdym?
Like taking -1 common from the power of 1/√27
The sign of both will change and 1/√27 will become √27
$$\frac{1}{\sqrt{27}}^{2-\frac{\log_{5}{13}}{2 \log_{5}{9}}}$$
$$\frac{1}{\sqrt{27}}^{-(\frac{\log_{5}{13}}{2 \log_{5}{9}}-2)}$$
like this??
Skill_Issue
wont make a diffrence, it would still lead to the same result
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✅
?
the channel is already reopened
Huh
I'm trying to figure out why it's 3/8 and not 3/4
Also witching hours here
So I'll be slow, but I'm working on it
Good
Don't let the bed bugs bite
Low key kinda rude
Like I said
I'm working on it
Partially
The 3/8 is right
They just left out a 1/2 in the previous ones
Gimme a sec, I'll rewrite it for you
Normally I'd use latex, but I'm not going to do that on my phone, so you'll have to deal with handwriting
If someone else could check my work, that'd be appreciated
Fairly sure it's right, but like I said, it's the witching hour for me
Hmmm
Can you check my process
Ooo
I got it
I was making a mistake
Thanks @ripe spoke
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Hi
can anyone help me solve this problem?
it gives me the answer
but i dont know why or how we solve it
or even get the equation
its algebra 2
<@&286206848099549185>
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How do I find the vector that is perpendicular to (2, 1, 2)?
There are a lot
I've tried a dot product with an unknown vector, and setting it to 0
but I get 2a_1 + a_2 + 2a_3 = 0
3 unknowns
that gives you an equation for all possible answers to this question
How does one find the a_i 's that makes this equal to 0?
With complex numbers, I remember that multiplying by i gives a perpendicular complex number
But this is a 3 dimensional vector
you can set any 2 of them to be any number you choose, then solve for the third
yeah that works
cool, thanks guys
is there a trick to divied any numbers very fast
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no just division
what I do is find the factors of the numerator and denominator
then cancel
for example: 20/4 = 5*4/4 = 5
the 4's cancel
can you give another example with 63 divied by 9
63 = 9 * 7
9*7/9 = 7
you should be familiar with the multiples of numbers 1 to 9
7th grade?
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It takes 4 hours 30 minutes in total for a boat to travel in water direction and against water direction on a 40km long river. Given the time traveling in water direction for 5km is equal to the time traveling against water direction for 4km. Calculate the river's flow velocity
not sure how to approach this, i let x = boat time to travel in water direction and y = boat time to travel against water direction
so i got x + y = 4.5
but not sure for the rest
actually, the wording might be pretty poor
ill do the research myself
.close
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what graph do i use for this
<@&286206848099549185>
probably a stratified histogram
wouldn't that result in having too many things to stratify?
yea i cant think of any other options though
other than to just homogenize the years
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Yeah, it is
There is a u sub to solve the second term
So a negative goes out the front
I guess u don’t necessarily have to do that, I think most people do it in their head, but that’s the theory anyways
What do you u sub
(1-y)
Can you show me how to do it i cant get it
d/dx (1-y) = -1
Then you just have the integral of -1/u
= -ln(u)
= ln(1/u)
=ln(1/(1-y))
Then do the first term
And add it to this one^^
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when they ask me for the time complexity here
I get that the best case 1 and worst case is n
but how do I figure out which notations to use
@balmy quartz Has your question been resolved?
Afaik you just say it's O(whatever you get in the worst case)
yeah but O() means upper bound not worst case

I don't see how whose two contradict each other
Are you saying 1 > n can happen?
best case <= worst case
Worst case is always the upper bound and vice versa
an upper bound can be worst case best case or average case from what I understand they arent related
I didn't say upper bound is unique
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Hello!
I am new here. I have a question regarding conic sections--> parabola.
Find the locus of the middle points of chords of a parabola y^2=4ax which subtend right angle at the vertex.
(Let middle points be ( h,k). I solved T=S1)
T here is the trick we apply by replacing x^2 as xx1 and y as (y+y1)/2. It basically a transformed equation of the given parabola (lets say A). S1 is the same as A but x is x1 and y is y1.
Thank you
Please tag me while typing
what's the question?
what are you having trouble with
I was solving the above question. Got stuck after one step. I will send till where I could solve.
Find the locus of the middle points of chords of a parabola y^2=4ax which subtend right angle at the vertex.
(Using T=S1. Terms explained above)
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Are these right?
@peak thorn Has your question been resolved?
<@&286206848099549185>
Yeah, these are
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Perform the calculations -16(decimal 10)+ -9(decimal 10) by converting the numbers to 6-bit two’s complement binary numbers before adding them. Indicate whether the sum overflows 1 6-bit result. While the result I get after the addition is 1100111 which is 7 bits, I'm not sure if this counts as overflow, because you can still write it using 6 bits as 100111. So I'm confused on whether or not that's overflow.
@vale portal Has your question been resolved?
uh
you should check your addition again
or your binary representation of 16 and 9
as another way to think about it
if i have 6 bits, with 1 sign bit, then i have 5 bits to use for my integers
what's the largest number i can form with 5 bits?
@vale portal Has your question been resolved?
31 right? so the range would be -32 to 31 using 6 bits? i’ve checked my addition and don’t see anything wrong, for -16 and -9 I got 110000 and 110111 respectively
oh sorry
I somehow read positives instead of negatives lmfao
uh
yes the addition is fine
yeah so you get 1100111
when you add two negatives using twos complement that you wouldn't expect to overflow, such as -16 + -9 = -25 > -32, you will have two set sign bits being added
now if the result was to overflow, I hope you've seen that you'll end up with a number that is positive, because the sign bits of the result is 0 instead of 1
and if it doesn't overflow the resulting sign but is still a 1
so when you take 1100111 and drop the most significant bit, you end up with 100111 which you can verify is -25
I hope that was an intuitive enough explanation as to what happens when two negatives overflow, you just end up with a 10 as the two leading bits, then the 1 gets dropped
okay so if it was to overflow, you would have two as the leading bits, when you remove one you’d be left with zero, making the result positive and getting a result that isn’t -25, but in this case the resulting sign bit is a one, and if you drop the most significant bit it’s still a one and would still turn out to be -25, so it’s not overflow?
yep
Just to clarify "dropping msb" meaning you have a 6bit register and obviously 7 bits doesn't fit
@vale portal Has your question been resolved?
yeah so you just remove it if it doesn’t fit right
yep
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!noping
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oh my bad
Goshdarn swr what a standup lad
sorry about that
@strange nexus Has your question been resolved?
no
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we were studying polynomials in class today
and sir gave us a problem that is (4x/y)*y a polynomial
and sir said yes and no both
it is a polynomials if y is not equal to 0 and it is not a polynomial is y is equal to 0
but my question is that if y = 0 won't the whole equation become 0
and 0 is an integer thus a polynomial
dividing by 0 is not defined so the entire expression would not be defined
let you substitute y only outside of bracket then wont it be (4x/y)*0
multiplying anything in this world by 0 is 0
@noble laurel
🫡
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since the heat energy is on the products side the reaction is exothermic
so the enthalpy will be negative
(giving off heat)
of enthalpy change
ohhhh
sry i meant the
use the q (the heat involved in reaction, make sure its in kJ and not J)
and divide it by the moles of products
why?
because enthalpy is q/mol?
wait sry what is q?
it's just the heat
ohhh ok thank u!
so in ur case 86 kJ
ok thx
and divide by the moles of wtvr
my exam is in 40 minutes
ofc ofc
😭
nooo american
The current time for nutgun. is 12:15 PM (AWST) on Fri, 24/05/2024.
wait how will i draw the second one..
yes, 12 am 😭
just draw the molecules w their bonds bro
is benzene c6h6
were u supposed to memorize these
yes
bro😭
@autumn plaza Has your question been resolved?
BRO IM IN THE UBER RN
helo me why does he have the 2 fromt windows open my hair is ruined
moment before disaster
this looks so australia
you will be okay my friend just breathe
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im kinda confused on why some dot products are (a, b) . (c, d) = ac + bd and some say (a, b) . (c, d) = ac + ad + bc + bd
different for cartesian and position vectors?
- (a, b) · (c, d) = ac + bd
- (a + b) · (c + d) = a · c + a · d + b · c + a · d
the first is the definition of a dot product and a, b, c, d are numbers
the second is an identity that follows from the first and a, b, c, d, are vectors.
here a and b are vectors (note the arrows over them)
and they are added
it is not (3a, 4b) · (5a, 6b)
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a pool get filled up with 2 pipes. Using the first pipe only the pool get filled up in 6 hours less time then using the second pipe only. They started filling up the empty pool with both pipes. But after 5 hours they stopped the first pipe. Because of this filling up the pool took 3 hours more. How many hours dose it take to fill up the pool fully with both pipes
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We can replace only 2 digits of the number right?
@lyric grove Has your question been resolved?
<@&286206848099549185>
we can replace more than two digits
but they have to be in the same places yes
so like the number is *008*2*1 and we make all stars the same digit
ohh
okay
so they are asking for a number, which yields 8 primes when its digits are replaced?
@long stirrup
sure
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How do I do this??
interesting
oh okay
you first find the probability that the numbers are all different
and then you can divide by 6
Why divide by 6??
Do you have any idea in advance?
I thought I would need to find how many ways I can draw 3 tickets where the first is higher than the second which is higher than the third and divide this by how many total ways to draw 3
So total ways to draw 3 is 10^3
hmm
How about we just pick 3 tickets out of the bag simultaneously?
Because there is only one result that fits the requirement
For instance, when you pick out 1 2 and 3
Only 123 fits the requirement and 321 231 132 312 213 don’t
that also works
there's 10c3 ways to pick
But it says he replaces the tickets in the bag
,calc (9/10)(8/10) / 6
10(9)(8) / 6 / 10^3
Results:
0.12
0.12
10c3 ways to pick correctly, 10^3 ways to pick at all
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Wait I’m confused he replaces the ticket so how come it’s 10c3 ways to pick correctly?
because he cant pick the same ticket twice, we eliminate the possibility
10c3 chooses 3 numbers that are different
But he could pick 3 of the exact same numbers for example?
that's the number of ways to pick 3 numbers that go a > b > c
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hi! so i am doing this calculus 1 course and we are currently reviewing some parts of functions. I got this question:
f(x)=e(sqr(5+x)) and i found its domain correct. (it's [-5, \inf)) anyways now i am required to find the inverse of the function and i did
ln(x) = \sqr(5+y)
-> ((ln(x))^2 -5 = y
but apparently this form is not accepted.
is my answer correct, and if yes; how should i type this in?
<@&286206848099549185>
How can i help you.
my question is literally written there
ok
f −1 (x)=(ln(x)) 2−51Start with the function 𝑓(𝑥)=𝑒5+𝑥f(x)=e 5+x2Replace f(x) with y : 𝑦=𝑒5+𝑥y=e 5+x3Take the natural logarithm of both sides: ln(𝑦)=5+𝑥ln(y)= 5+x4Square both sides: (ln(𝑦))2=5+𝑥(ln(y)) 2=5+x5Solve for x : 𝑥=(ln(𝑦))2−5x=(ln(y)) 2−56Replace y with x to find the inverse function:𝑓−1(𝑥)=(ln(𝑥))2−5f −1 (x)=(ln(x)) 2−5
So nope
what do you mean by this form is not accepted?
This article gives more information about math syntax errors in Grasple.
this is an edx course
they use a third party thing to decide whether answers are right or not
because it is { 1,2} u { 3,4}
it asks for the inverse function though
inverse function of
$$f(x)=e^(\sqrt(5+y))$$
whatever it is
ghiolimer
did you try to x = ln(y)^2-5 ?
consider that √(5+y) being exponiental of e
ln(y) = √(5+x) i guess
hold on let me share the full question
hold on a sec
@abstract cobalt thx for helping her.
the first part is green
where function is shared
now we should find the inverse function
What did you input as your final answer
ln(x) squared - 5
i tried 2 ln(x) -5 as well
doesnt accept both
I mean send a photo of how you typed it in
hold on i did 2*ln(x)-5 again and it said incorrect
lemme send the explanation to you
leave this channel pls
this channel is busy with math not ur weird actions
lol
( \ln(x)^2 \neq \ln(x^2) )
shsgd
So you can’t move the 2 to the front
no i did 2* ln(x)
not ln(x)^2 = ln(x^2)
as i know from logarithms you can move the exponiental in front of the logarithm
That’s only true if the exponent is tied to the term inside the log
Not to the log itself
oh wait how
like can you give an example?
The inverse is ln(x)^2 -5
let me try again i refreshed the page
that was my initial answer btw
yep got it
its correct
now it worked
Probably a syntax error the first time
i think i used multiple paranthesis that was the problem
i did (ln(x)^2)
anyways
thanks for the help y'all
appreciate it
👍
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rip
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how should i proceed with it
what auxiliary function shall i suppose
i get the initial inequality by diving the given equation by f'(x) . it becomes (f(x)+f''(x))/f'(x)<0
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it was multiple
I just got option A
are u from india?
Don't know how to solve the rest
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cam someone give me the solution of this math
(2^-2/x)^-1 =?
please
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Fraction 1/x
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Hello. My question is, can I have an example algebra problem? I don't know how to get one.
Uhm... any?
what kind of algebra? Like abstract algebra or like elementary algebra?
Oh, abstract!
almost give you high school algebra problem lol
if it that kind of algebra, maybe discuss that in #book-recommendations or #advanced-algebra maybe?
What do I ask?
like, what you have asked here. I think people are more active there for advanced-level stuff. Most of the problems are easily accessible from the books.
Got it!
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hi! I have a probability question
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
so I have some trouble distinguishing whether to use product rule, permutation, combination..etc
Permutation is where order matters, comb is where order does not matter
how do you know when to use product rule, I know its when the objects are distinct?
yea but in all these 3 cases, the objects are distinct? Actually, when should I use product rule?
Think about the product rule like this:
Say you have 10 friends and you want to choose any 3 of them and make them stand in a row. In how many ways would be able to do that
10C3 for the number of ways you could select them
and
3P3 for the number of ways the could stand in a row
And if you multiply 10C3 and 3P3 you would get the total number of ways of doing this
Does that make sense?
so its for questions where they dont specify whether order matters?
wait, 10C3?
whats C?
Combination
Combination is a way of selecting a number of things from a group of things, where the order of choosing does not matter
ohh i see i see
ok
so its applying product rule twice
I mean
no
like twice whther its permutations or combinations?
Could you rephrase?
so in this example, 10 times 3 for the number of ways to select the friends
and then for the 3 friends, its 3!
so 30 times 3!=180
but why cant you just do smth like this:
No not 10 times 3
10! / (10-3)! * 3!
It is the same thing
Im getting confused because Im using permutation formula for the whole thing..as in using only this formula to solve the problem, but I think you are not supposed to? so you would apply combination formula, then permutation formula?
Im still not understanding what you did for the first question, do you mean 10! / (10-3)! * 3! for the number of ways to select the friends, then you multiply that by 3! for the different ordering?
10!/ [ (10 - 3)! * 3!] for the combination
3! for the permuation
Net is 10!/(10-3)! -> Which as you stated is the same as 10P3
Each type of cereal is a distinct item
We have 10 cereals 5 oatmeals and 4 pancake mix
When we are selecting
If we say 19C3
In one of those cases
We could be selecting 3 pancake mixes and no oatmeal and cereal
In the question its stated we want one of each
Do you have a solution for that?
so product rule is used when you dont want to have a combination with an object from the same group(in our case, the group is oatmeal, pancake,..etc)
What does this mean?
I was trying to do smth like this
Basically but there arent only 10 "choices" for the first object
We want to choose 3 cereal out of 10
Let me make the question a bit easier
You have 3 unique shelves. You have 10 boxes of cereal, how many ways could you arrange it
10 choose 3 (so combinations) and then 3! for the different ordering of the cereal
3 times 5 ways to choose the cereal
3 times 5?
I'll list them out😅
This was correct
Answer this that way
Ah my bad
Yup!
So so now if we had 3 shelves
5 boxes of oatmeal and 10 boxes of cereal
And we have to put 1 of each per self
This result
Does that make sense?
ok
This is the selection part yes
We multiply this with the permutation
3!
Wait sorry
No actually yea
this
Sorry yea my bad
Remove the 3!'s
We need to multiply 3! for each self
We arent arranging the boxes of cereal individually if that make sense
We are arranging each self
Still wouldnt the result be the same
Let me solve it once 1 sec
It seems correct
Do you have the answer?
@cold moon
Ahh
My bad
The question is saying
3 shelves where we arrange each of them
Its not 10C3
We only need to choose one of each
I get it now, yea you multiply 4x5x9 if you want shelves to have one of each
like you cant have OOP for example
4 * 5 * 10
And then we can arrange them in 3! ways
and then 3! is just permutation, n=3, k=3 but 0! = 1 so this formula just gives 3!
Yup
4 * 5 * 10 * 3! = 1200
I thought the question said there were 3 shelves with 3 items each
Np
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So I had a question on a sequences and series test that was about finding number of plants planted among 2 years intervals. Every two years, the plants planted increased by 3%. In 2010, 500 were planted. We were told to find the trees planted in all 2 years intervals from 2010-2020. The hint was that the 500 was 2010-2012. How many terms was I supposed to find?
There would be 5 terms
2010-2012
2012-2014
14-16
16-18
18-20
so i find t1 (500) to t5? because we must model with a geometric sequence
Summation of t1 through t5 yes
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I made up a "sequence", but each term in the sequence actually has multiple numbers. Is there a name of this type of thing?
Still a sequence, just not using members of R
Worth seeing the Lp spaces, where each member of the sequence is itself a sequence
I used the word "entry" to describe a term of the sequence, do you think that is fine? The only downside I can think of is that it may be confused by an individual number.
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