#help-26
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it seems like it's even harder
ill think about it but i have another question
f continuous
is that obvious that g(x)=f(x)-x=0 has at least one root?
@sweet shard
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what was that part?
like the 3/4 part
oh wow
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found the first eigenvalue
unsure what to do next
Find the second one
idk how
Roots of charpoly
i got there but don't think i did it right...
show your work
i think i found what i did wrong
imma try working through it again
cool got it
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Can someone please explain to me how after substituting they were able to Get the next step please
I have to go in a minute but you can try substituting it yourself
note that they distribute with the second X_i in the summation
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Help please
These are the two equations I have
For profit for both stores
Store 1: profit=0.20x-x
X being the cost
And store 2: profit=0.35x-x
I don’t know if I’m doing this incorrectly
<@&286206848099549185>
@rancid rock Has your question been resolved?
@rancid rock Has your question been resolved?
I got it
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I'm stuck
you didnt find dx/du, you just plugged in x into dx
yea
So it becomes this
OldBiscuit
yes

i thought it was 1/(x²-3) lol
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my tutor was working on this with me, and they kinda botched the explanations
can someone help explain the work she did for me?
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i think its false
A1 = 1 A2 = 1 2 A = 1 2 3
so A1 and A2 are p subsets of A
and A1 is p subset of A2
what function are you using for your example?
f(x) = x/x
but i think thats wrong lol
just realized x/x isnt a function
but im still sure its wrong
f(x)=1 is a function
it is?
Yes
hm ok then my counterexample works right?
cause f(a1) = 1 and f(a2) = 1 therefore they not proper subsets
indeed
please dont forget the brackets {}
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Wanted to ask if I’m right on these
@modern epoch Has your question been resolved?
<@&286206848099549185>
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Hey, this is quite basic but I would really like for someone to verablly explain this part from Serge Lang's "Basic Mathematics" to me. Also, the "proof left as an exercise (N10)" didn't ring any bells. I would appreciate some help.
Basically, I don't understand the correlation between -(ab) = (-a)b = a(-b) and (-1)(-1) = -(1(-1)) = -(-1) = 1
Sorry for my lack of LaTeX knowledge
can you send me a link by any chance?
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@delicate spoke Has your question been resolved?
hey sorry if I'm keeping the channel for too long, I just want to learn what the author meant exactly
@delicate spoke Has your question been resolved?
@delicate spoke Has your question been resolved?
right
Imagine you are playing a video game, in the game you have 2 types of boxes, boxes with +2 points and boxes with -2 points.
3*2=6, meaning you have gathered 3 boxes of +2 points each. 3*(-2)=-6, meaning you have gathered 3 boxes of -2 points each. (-3)*2=-6, meaning you have gotten rid of 3 boxes of 2 points each. And now to (-3)*(-2)=6, think of it as you getting rid of 3 boxes of -2 points each, which is a positive thing.
its not showing my miltiply sign but you get it
hmm yeah I get it
hey, surround your message in `` signs so it will show the *'s
thanks for the explanation
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any more info?
That’s it
then I'd say it can't be determined
hmm
I thought it was D too
Because they didn’t give the number of students
But that’s not right
if there were an even number of students you would have 82+88+90/3 for all 3
,calc (82+88+90)/3
Result:
86.666666666667
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I still don’t understand
Answer choices:
A) a is larger
B) b is larger
C) both are equal
D) no relationship
,calc (82+88+90)/3
Result:
86.666666666667
this would be the arithmetic mean of all 3 classes if the number of students were equal in all 3
but the actual arithmetic mean they told you is 86
Køter
A little but not really
ok i will create hypothetical example
Ok
Ok
class 1 had average of 50
meanwhile class 2 has average of 100
you should be able to see that the actual mean is gonna be alot closer to 50 right?
becasue the 10 people weigh more
if there was also 10 people in class 2 with average 100
the average over both classes would be (100+50)/2 =75
Yes
so here its the same
if you assume there are equal people in all 3 classes
the mean should be 86.67
but they told you its lower
Yeah
which means that class 1 with the avg of 82 had to have weighed more
Yeah I thought it was B because the average is higher
It’s 90 for the average and so I thought that weighed more
Confused with this part
Yes
good observation, that's a tricky one
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when calculating a surface integral of vector field how do I know if the cross product of the 2 unit vectors is are the right order
@crisp raptor Has your question been resolved?
I guess what you can do is do it for a point
And see if it point outwards of the surface
Choose a point
so just testing for a few points?
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can someone help me with this
B from A
think about anglesin a triangle
what
@buoyant girder Has your question been resolved?
200
no they do not
180
it's 1 80
Fun fact, a triangle inscribed on a sphere has sum of angles more than 180°
@buoyant girder Has your question been resolved?
bruh
Perhaps I can help?
First use the sum of the angles in the triangle to solve the angle at point A
Specifically the angle inside the triangle
Then use that and the fact that you have that vertical line and you would then know 2 of the angles that make that part at point A to solve for the bottom angle at point A (not inside triangle)
I think that should give you enough information to solve the problem
Please let me know if you’d like me to walk through it a bit more
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this is part of an induction proof. From the requirement we know that $\sum_{i=1}^{2^n} 1/i \geq 1 + 1/n$
What I dont get is why we know that $\sum_{i=2^n + 1}^{2^{n+1}} 1/i = \sum_{i=1}^{2^n} 1/(2^n +i)$
Can someone explain why this is equal ?
barış
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Very wordy but I’ll try to break it down
I understand that Judy=6.2+M
M=mean
M=total/25
Judy=6.2+(total/25)+10
Recalculated average: 10(total)/25
Am I on the right track?
I tried breaking it down
I followed until the recalculated average...
Hmm okay
If each student gets 10 points, the average goes up by 10
But in the question it says that only judy got 10 points right?
(Total+10)/25
yes
Yes but why is it asking for recalculated
It’s asking Judy’s score how much bigger than recalculated
Because the avereage has changed, and judy's score has changed, so the difference has changed
(Judy's new score) - (Recalculared average) = Recalculated difference
Yes
So you only need to substitude
So is it not +10 for recalculated
Since only Judy got 10 points
That was my confusion
hmm
So recalculated avg = old avg + 10
25(10)/25 right?
right
Yes that’s what I thought
For each student
But in this case it’s only judy
So it would just be (total+10)/25
correct
Just substitude what you already know
(Judy's new score) - (Recalculared average) = Recalculated difference
You need to find recalculated difference
Hope that total will just cancel out
It's very simple
try again
(Judy's new score) = 16.2 + Total/25
(Recalculared average) = Total/25 + 10/25
Substract
@rancid rock
Ohhhh I see what you did
You put 25 under total and 10
Okay it would be 16.2+10/25
16.2 - 10/25
Yes
15.8
Correct
That would be the answer
👍
Thank you!!
You are welcome
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Is it true that the function $\lim_{x \to 2} \frac{x^2-4}{x-2}$ has no vertical and horizontal asymptotes?
Bennxy
Correct
The limit part makes the expression equal to a number
But the function inside the limit does have no asymptotes
You can graph it on Desmos to see it
Yeah I saw that it was a linear line
It appears that way at least
But wasn't sure if it did or didn't has a asymptote
Asymptotes you can tell visually
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3.2 west
to find the angle isnt it tan^-1(-0.6/-3.2)
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can someone help me somve these?
now for a i understand that the ∩ in both A and B, i i wrote my answer as {x E Z^2} but it was wrong
this is the answer
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Hi!
I was wondering if anyone could help me find the apothem of a pentagon easily.
I have been struggling and not been able to wrap my head around it.
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How to find 1% of 689
That is simply one hundredth of 689
@cursive gazelle Has your question been resolved?
689 * 1/100
Who invented %?
The concept of percentage was not developed by any person. The percentage concept originated throughout History. In Ancient Rome, Mathematical calculations were expressed in fractions of 100. This concept later originated in Percentage.
(I didnt type that) i copied and pasted
Who invented %?
Huh?
here
@cursive gazelle Has your question been resolved?
why
idk bro
@cursive gazelle Has your question been resolved?
because its just convenient, especiallly for our decimal number system
Whyyyy
what the dude said
yea
1/100 of a dollar is a cent
1/250 is like a fraction of a cent
things like that make hundreths more usable
No
He’s got a point
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Struggling with calculus question
which 1
@karmic anchor Has your question been resolved?
You don't know where to start?
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how can i prove that the series cos(n) diverge?
can i say that cos(n) doen't tend to 0 so it can't be convergence
The series as in $\sum_{n=1}^{\infty} cos(n)$?
GarlicBredFries
Use the Nth term test
wdym?
i wanna prove that the series diverge but if the sequence don't tend to 0, it's a sufficient condition to show that the series diverge
what is "the series"
is it this?
yes
@woeful depot Has your question been resolved?
yes, by ntt
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I am currently stuck on a section of this question
this helps solve this
so I got
now I know what to do, you just multiply the numberator by the number
but what do you get when you multiply pi and pi?
2pi or pi^2
nvm
I got it
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hello there
iam currently over getting the percentage of my marks calculated but it gives me a wrong result
anyone might can help me find my issue?
best mark 1 = 100%
worst mark 6 = 0%
Percentage = (1 - (AverageMark) / (6 - 1)) * 100
Percentage = (6 - (AverageMark) / (6 - 1)) * 100
change that to a 6
can you give me an explanation of why? would like to understand the background too
well you're rescaling your values to be out of 6-1 = 5
6 - (the worst mark 6) = 0
6 - (the best mark 1) = 5
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Can anyone please explain from where Z did come to the range f(x) ?
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i need help with this problem, it's completing the square
i think its abt maximizing
ohh okay
Do you know about maxima and minima
no
this might help
you just need to maximise the performance and find at what stress level does such performance occur
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What is happening at at the marked row?
Or why is it simplified like that?
<@&286206848099549185>
factor out f(1,s)
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F doesn’t share a similar plane
This makes no sense i thought planes could only be 2d?
Why are two points on opposite sides the same plane?
But don’t they have to be on like the same shape?
(assume ofc that the points are not on the same line)
Oh wait… does that mean the whole 3d thing is the plane itself?
I was thinking of 2d planes maybe
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How do i get question c
@vital mauve Has your question been resolved?
think about the forces "cancelling" each other out if theyre in opposite directions
but notice that one direction has more force than the other
how much more force is going to the right compared to the left
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I don't see how such a function can be possible?
How can it have a point of inflection and be consistently decreasing?
How can it have a point of inflection and be consistently decreasing?
why don't you think that's possible?
what's your understanding of what an inflection point is
The point at which concavity changes. Or the second derivative = 0
and how exactly would that prevent the function from being consistently decreasing
I can't visualise how the concavity would change if it is only decreasing.
-x^3
Alright, but now that does not meet the requirement that g(x)>0 for all x
that's left as an exercise for you
i'm merely giving a simple example of how what you though was impossible is very possible
you can use a similar idea
and also note that you can have y=0 as an asymptote
and you're not required to give an equation, just sketch something
That function is not consistently decreasing though. f(x) = -x^3
f'(x) = -3x^2
Given x = 0: f'(0) = -3(0)^2 = 0
And one of the requirements is that it must be <0
It excludes 0.
Oh
and you're not required to give an equation
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Two numbers are chosen from 1, 3, 5, 7, 9,…, 151 and multiplied together in all possible ways. The number of ways that will give the product a multiple of 5 is ___.
Either at least one of the selected number should be a multiple of 5 or both of them should be a multiple of 5.
Numbers in 1,3,5,...,151 which are divisible by 5 are 5,15,25,...145
Oh, nevermind
I found my mistake
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Hello i'm trying to find the anti derivative of this
but on the last line 4pi^2/4 is wrong right?
it should be 4pi^2/2
correct?
why would it be 4pi^2/2
why do you think
4x^2 is 4pi^2/2 when x=pi/2
(pi/2)^2= pi^2/4?
yes...
you may need a quick review of algebra
also that
-7 - pi^2 at the end is very poorly written
c= -7pi^2??
no
its supposed to be -7 - pi^2
but the stroke through the 7 merged with the - sign
when i have a fraction with power
the denominator is multiplied or power
you should review your exponent laws
I will but can you tell me
do the review first
shouldn't take more than 5 minutes to take a look at the list of 10 or so laws
(x/y)^n= x^n/y^n
yes
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should it be 3y + 3xy
6 is the solution to df/dxy
but then it should be /2! right?
because its a 2nd order term
wait a sec i may have flawed my understanding
wait a sec.... u dont half the xy term
i had forgotten this fact
that was a close one
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how do i plot a 4 point moving average?
The first three were done for you.
For the first one, it took these four numbers
And found the average: 319
Then it moved over by 1 and found the average of these four numbers:
And so one
Oh I see
For the first 3 points, it looks like just the actual points were plotted, since there are not enough points for a 4-point average
Same for the last 3 points
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llookign through this
i dont think it is correct
but i need someone to veiirfy
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it's correct 👍
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first do u.v
The dot product results in a scalar
then do the resultant vector dot product with u
so I would answer b) as (#,#,#)?
yes
ahh OK
they want <> instead of ()?
yes
i guess
ty
do you have a "special character" picker or something
fixed
bro dot product always results in a scalar
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Is the function x^2ln(x) continous at x = 0 and why?
domain of log is $(0,\infty)$
bettim
@flint star Has your question been resolved?
So since f(0) is undefined, the function is not continuous at x = 0?
yep
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what is 32 as a power of 2
no, we won't give you the answer.
write out the first few powers of two yourself.
can u help
and i dont know it
you said you know your powers of 2
i forgot
write them out here where i can see them
where
in this chat
2 1, 2 2, 2 3
...
lmao
do you know what the words "power" or "exponent" mean?
yep
Alternative suggestion: divide 32 by 2 and its resultant as well until you get a non-zero remainder or a value of 1, and then count the amount of 2's you divided with that process
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can someone help me with this question thx
Please don't occupy multiple help channels.
d-d-dont make two channels
sorry i couldnt find the last one 😦
ok
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Can someone help me solve this for x
Show your work, and if possible, explain where you are stuck.
Well first notice that u can write $7+\sqrt{48}$ and it's conjugate as whole squares
ItzKraken2
So u can remove the square root
i dont get it
ItzKraken2
Can u find a and b by comparing this to $a^2 +b^2 + 2ab$
ItzKraken2
@drifting wind
Where can I implement this
Should already be a helpful hint.
how did you find that rearrangement
Idk I have practice ig
did you just see it?
We had an entire chapter dedicated to surds this year
These are small numbers, and smart students in Asia (and elsewhere) probably have been trained with these toy problems when they are studying surds. 😂
Bruh
Well I gtg, bye
There is no take-over in this server i guess, ppl just pick up whtever channel they are interested. 😂
am in asia
have not been trained with this
Hmm true
Country and class?
hk and this isn’t in hkdse pretty sure
Ah, I see. Am in India
Pre-calculus classes in China will know this coz I have seen like Chinese or Japanese vid with such example.
those were probably olympiad problems
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hey
i have this pyramid
we have a local coordinate system where the z axis goes from S to M
x and y are parallel to the other 2 sides i marked in blue
the origin is in the point S
I need the rotation matrix when rotating around omega
any tips?
Context:
I am calculating the rotational energy for which i need some weird tensor and also some other stuff for which i need this matrix
if x y and z basis vectors are normalized then this should be true, maybe that helps
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Standard equation of ellipse is $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$
KN
And then the other one I've seen is $\frac{y^2}{a^2} + \frac{x^2}{b^2} = 1$
KN
What's the difference?
I guess its kinda dumb. Like I always just remembered it as when a > b or b > a, whichever variable (x or y) it was under, then we called the length of it as the semi -major axis
hmm ok
i see
ty
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What is the relationship between SVD and diagonalization?
what is the covariance matrix they talk about?
In probability theory and statistics, a covariance matrix (also known as auto-covariance matrix, dispersion matrix, variance matrix, or variance–covariance matrix) is a square matrix giving the covariance between each pair of elements of a given random vector. Any covariance matrix is symmetric and positive semi-definite and its main diagonal co...
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How do I synthesize ibuprofen from isobutylbenzene pls help
Dont ping until 15 mins
Can u help
also <@&268886789983436800> seems a little not-math
this is clearly a math question. #kchchch
take the derivative
do I integrate by parts
no just take the derivative
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😂
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Can anyone help me to check my answer? (Circular Measure Add Math)
Question 2b
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Yo I was wondering what should I do to practice my 4u exam. I already finished the cambridge and mastering mathematics and I was hitting trial papers but my partial fractions are weak. I was wondering if you had any advice
Please don't occupy multiple help channels.
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,w cube root of 169
,w cube root of 27

,w how many terms of 3 , 3/2,3/4 are need to be sum of 3069/512
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I will go there. @sweet shard thanks for suggesting but i am now uploading my question wait
Radius of convergence?
How to find it
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im doing imporper integrals
we are looking at the integral over f(x) from a to b
if lim[x->a]f(x) or lim[x->b]f(x) exists, then the improper Integral exists.
Is this statement true?
that sounds so wrong
f =1/x
like if we look at f(x)=1/x^2
then the improper integral from 0 to 1 does not exist right?
That works too
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$\int_{0}^{1}\frac{1}{x\cdot\sqrt{-\ln(x)}}dx$
~Martin
that is the improper integral i am looking at
i already got the value with the bounds being 1/e and 1
this one doesn't exist afaik
any ideas on how to prove that?
u sub?
if i would try u sub, then i get integral from 0 to infinity of 1/sqrt(u) du
afaik, a) should be correct (even though i should quote some stuff from my script)
for substitution, my u has to be continuosly differentiable on [0,1].
u=-ln(x)
u'=-1/x
which is continuous on (0,1] but not [0,1] so i don't think that b) is done correctly
i tried comparing f to other functions but that did not work
I think it’ll be sufficient to just substitute the substitution back in and show that the limit doesn’t exist when x -> 1
The bottom half is correct
oh it is?
This statement is about the integrand, not its antiderivative
so we don't need u, u' to be continuous on [0,1] but just on (0,1)?
,w int 0 to 1 of (x * sqrt(-log(x)))^(-1)
you can just keep it 0 to 1 and plug u = -ln(x) back in and evaluate the limit too
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is it possible to prove that for all x there exists some a and n such that this is true
Do you know the sum of 3^n?
this looks odd
btw are you sure the summation is meant to run from 0 to n and not from 0 to n-1?
$\sum_{n=0}^m 3^n = \frac{3^{m+1}-1}{2}$
Oğuzhan
Yeah it's odd
yeah it’s meant to run from 0 to n
anyway i believe this is asking whether for any x it is possible to append some 1's to the ternary representation of x+1 to yield a power of two
which i am not convinced it is, but it sounds very nontrivial to prove
$2 \cdot 3^n \cdot x + 3^{n+1} - 1 = 2^{a+1}$
Oğuzhan
wouldnt it be $1 + \frac{1 - 3^n}{1 - 3}$
Fulgebunt
n+1 not n
$3^n (x + 1) = 2^a$
Oğuzhan
my instructor has told me that it’s true
Hmm
But if x = 0, there is no integer solution?
Or x = 1
If I expanded it correctly
ah wait i have the domain of x wrong
Oh
a and n can be any positive integer but x must be greater than 4
Still, I don't think it works for any x value
x=0; n=0,a=0 and x=1;n=0,a=1 work, no?
Yeah true
Kind of an edge case
It can't work for all integers nor positive integers
$3^nx + \sum_{i=0}^n 3^i = 2^a$\
$3^nx + \frac{3^{n+1} - 1}{2} = 2^a$\
$2\cdot 3^nx + 3^{n+1} - 1 = 2^{a+1}$\
$3^n(2x + 3 - 1) = 2^{a + 1}$\
$3^n(x+1) = 2^a$
I don't see an error
oh it cant be true for any even integer right
It can't be true for any, except for this edge case
Oğuzhan
Fixed something*
why do you take the -1 inside brackets
perhaps my instructor was trying to trick me
a or n should be 0
Oh my god yes thanks
(2x+3)3^n=1+2^(a+1)
ah
My apologies I'm exhausted
Yeah now it seems possible
$3^n(2x + 3) - 1 = 2^{a + 1}$\
$b = a + 1$\
$3^n(2x + 3) - 1 = 2^b$
Oğuzhan
my instructor has said that proving this was useful towards the collatz conjecture
Hmm
its for x greater than 4
I know
just getting a grip
But this same argument would show x=5 is not possible...
nvm
@feral comet Has your question been resolved?
Alright I looked at it again and solving this is pretty much solving collatz so I stop
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I've read this paragraph in my textbook like 10 times and still have no idea what it means
could someone explain what unbiased estimates are please
unbiased = reflective of "reality" or of the population.
biased = not reflective of the population
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is this solution correct? it doesn't check if we actually get a 9 does it
if the largest number is 9, you can't select anything more than 9
so just take out 10 to 15
so now you have 1 to 9 to work with, and you pick 7 things, all with replacement
count that, and also count that picking 7 things from 15 things with replacement
divide the first with 2nd
and what it seems from where that the solution is correct
why did you put (8/15)^7?
also how is this binomial distribution 💀
oh got it how
these people never told properly what is the actual random variable working here
💀
@oak sequoia Has your question been resolved?
But we aren't ensuring that we select at least 1 9
the correct is what they marked
if you exclude 9 your probability is 0 lmao
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✅
I'm not saying exclude 9, what I'm saying is there is a change you end up selecting let's say 1 7 times
But we end up counting that in our case
can't help it, need to attempt all questions to access the bonus questions 💀
,w (3/5)^7

