but in that case you should have typed d/dx ( -8cos(-4x-3))
#help-23
ruby pelican
ruby pelican
ignore this, im not sure exactly what you did but its wrong
ruby pelican
yes thats correct
pine tulip
The inequality x^2<a in x:
a: It's impossible for a<1
b: Its possible for each a>0, and -a<x<a
c: Its possible for a<0
d: its doable for every a
e: every answer above is false
pine tulip
a is false because if we take a=0 then the inequality is possible
but why is b false? a>0 works
-a<x<a, means for example x=1/a right?
and if a>0 then it works
pine tulip
Thats what i thought too
but the correct answer is E
and just like you, i dont understand why
narrow bronze
...A high school question that is designed wrongly...
Where did your question come from?
narrow bronze
entrance test... how sacrilegious to have a question in such an important test designed wrongly...
narrow bronze
...I don't quite get what it means.
Do you mean that "For every a>0, there exists x such that -a<x<a"?
narrow bronze
Then it is wrong.
x = 0.9, a = 0.82
pine tulip
Then it is wrong.
x = 0.9, a = 0.82
Could you explain better?
narrow bronze
x = 0.9, so x^2 = 0.81, which satisfy the inequality x^2 < a
but x > a
lean otter
Hi, I'm not sure how to do this question - it is about Trigonometry and proving. I'm not very familiar with the rules and I've tried some methods as a test
- sending pic
safe radishBOT
Hi, I'm not sure how to do this question - it is about Trigonometry and proving....
lean otter
primal slate
are you familiar with these identities?
safe radishBOT
@lean otter Has your question been resolved?
lean otter
are you familiar with these identities?
yeah i used it there
lean otter
what is 1 - sin^2(x)?
cosec^2x?
primal slate
nope
lean otter
i mean cos^2x
lean otter
sin^2x/cos^2x
primal slate
and that is?
lean otter
is it tan^2x?
primal slate
are you familiar with these identities?
try using the second identity
lean otter
secant^2x - 1 (proven)
primal slate
yup
dense void
Can someone answer this question please
safe radishBOT
Can someone answer this question please
dense void
,rotate
flat frigateBOT
lean otter
uhhhh
peak estuary
modulo? division with remainder?
lean otter
ok so uhh
a % b
what it does is
a - math.floor(a/b)*b
math.floor means round down to the nearest whole number
i have no idea what you would call that or if its even a thing in math
peak estuary
you get the remainder after you divide a by b
so 27%5=2 because 2 is the remainder when you divide 27 by 5
peak estuary
and 27-floor(27/5)*5=27-5*5=27-25=2
lean otter
thank you
safe radishBOT
@lean otter Has your question been resolved?
wraith temple
safe radishBOT
wraith temple
Idk how to do the triangle
delicate sierra
Idk how to do the triangle
ok first of all, what are the properties of a triangle with all 3 sides of equal length?
wraith temple
Idk man it's second term and I learn this in first term
lean otter
Idk man it's second term and I learn this in first term
all angles are equal
and since the sum of the angles add up to 180
every angle is 60 degree
wraith temple
So j is 60??
lean otter
no
sum of angles on a straight line = 180 degrees
so u see
60 + (81 + j) = 180
do u understand the above?
wraith temple
So then 180-60=j?
lean otter
no
j = 180 - 60 - 81
wraith temple
I forgot to add in the 81
lean otter
angles on a straight line = 180 degree
we have 60 and 81 and we just need j
thats all
wraith temple
=39
wraith temple
So for the above one you mean the one with 3d on it if yes then no Idk how to do
wraith temple
can u find out the other unknown?
Give me a sec to do it
wraith temple
Give me a sec
lean otter
do u understand the above?
i meant the equation i wrote 60 + 81 + j = 180
wraith temple
This correct??
wraith temple
i meant the equation i wrote 60 + 81 + j = 180
Yes
wraith temple
How to do this one too
lean otter
This correct??
yup right
wraith temple
Hey @lean otter what grade you in
lean otter
Hey <@456226577798135808> what grade you in
8th this month I will be promoted to 9th
wraith temple
I'm in secondary next mouth exam
Secondary 2 to be exact
Ok about the other photo I uploaded how to do it
lean otter
How to do this one too
d + e = d + f
e = f
g = 3d
wraith temple
d + e = d + f
e = f
g = 3d
Uhhhh pls explain cause I've forgotten how to do everything in first term
lean otter
3d + d + d = 180
wraith temple
?? Why there 2 d's
wraith temple
Oh sorry I didn't see the second b
wraith temple
Ohhhhhh I get it now almost there's 2 d's and the d is facing f and then e
This correct??
Hello??@lean otter
Anyone there??
lean otter
u didnt find the values
wraith temple
??
lean otter
u just wrote g = 3d
e = d
f = d
u gotta find the numeric values as well
3d + d + d = 180
find the value of d and hence the others
wraith temple
Uhhhhhhh
Bro you gotta explain to me maths isn't my specialty
@lean otter you on a laptop or something??
lean otter
3d + d + d = 180
do u know how to rearrange and find the value of an unknown
3d + d + d = 180
5d = 180
dividing both sides by 5
d = 36
wraith temple
Ohhhhhh ok I get it now you add the d's to the 3d and then divide it to 180 right?
lean otter
yes
add the d(s) to get 5d and then just divide both sides by 5 to get d = 36
d = 36
g = 3d
e = d
f = d
just replace d for 36 to find the other ones
wraith temple
Do I need to explain the g can I just write g=36 or will marks be deducted in the exam?
lean otter
g is 3 times the value of d
wraith temple
Especially Maths
wraith temple
So 3d is 36 so 36x3 = to 108
lean otter
Yes
lean otter
no
lean otter
Asian
wraith temple
I'm guessing that your 10-20 years old right you don't need to say exactly how old you are if you don't wanna
wraith temple
Same man I turned 14 last mouth
Hahahahaha
A 14 year old teaching a 14 year old it's uncanny ain't it
wraith temple
Ok anyways continue with the question
wraith temple
How to do that??
<@&286206848099549185>
Like this??
Is this how I do it??
Hello??
obtuse plover
What’s ur question
obtuse plover
R u trying to find Angle A
wraith temple
I'm trying to get all the angles but I'm not good at maths and my exams are coming
Wait
obtuse plover
Ok well for these problems u wanna start in 1 area first where u can easily get an angle
wraith temple
I took a photo of the wrong sorry
obtuse plover
Lol aight
obtuse plover
Rotate it on ur camera roll
wraith temple
obtuse plover
Ok which one
obtuse plover
K
So I recommend in the places with all right angles, u label them 90
So it can become more numerically clear
wraith temple
Ok done
obtuse plover
K
Now is there any place where u can easily figure out an angle?
Like any complimentary or supplementary
wraith temple
p+90+3p=180
obtuse plover
How did u go from p+3p to p+p?
wraith temple
Idk the guy that was helping me before did it something like this
obtuse plover
Nah u can’t do that
wraith temple
Oh
wraith temple
So then 2p=30
P=30 divide by 2
p=15??
lean otter
Idk the guy that was helping me before did it something like this
Lmao
Seriously u should atleast check what I did on that one before just saying that
obtuse plover
So then 2p=30
P=30 divide by 2
p=15??
No
obtuse plover
U have to add p + 3p
wraith temple
Seriously u should atleast check what I did on that one before just saying that
Nope
lean otter
Sure but that will just make u look worse at math u should not just tell things u not sure about
Anyways Stephen go ahead
It's gonna take. A while to get the algebra right with him lol
wraith temple
Sure but that will just make u look worse at math u should not just tell things ...
I'm sorry man
lean otter
It's alr
obtuse plover
What did u get @wraith temple
wraith temple
Do I divide 90 by 4 ?
obtuse plover
Well did u get that 4p = 90?
wraith temple
Yup
obtuse plover
Then yes
wraith temple
obtuse plover
Why u confused?
wraith temple
Angles can have the dot thing?
wraith temple
Yeah that
wraith temple
8th
obtuse plover
U haven’t learned decimals?
wraith temple
Give me a sec
Ok I'm back
Yes I've learned decimals but that was first term and now I'm one week away from my exams
obtuse plover
Well decimals should be in ur head no matter when and where lol
They’re everywhere
wraith temple
Ok lmao
obtuse plover
Anyways back to the problem
Yes decimals can be in the answer
Now that u have solved for p, write out all the angles that u can
wraith temple
Ok does q=67.5??
obtuse plover
Try it urself
wraith temple
This one??
wraith temple
I don't have the foggiest clue how to do it
obtuse plover
What do the angles of a triangle add up to
wraith temple
a+70+90??
wraith temple
Now I did
obtuse plover
Ok now figure out the other angles that u can given the given angles
wraith temple
obtuse plover
Do u know how to solve for the third angle of a triangle
obtuse plover
Well what’s the sum of the angles of a triangle
wraith temple
?????
obtuse plover
Ok dude here’s my recommendation
Get a good nights sleep, wake up, and review these concepts
Khanacademy has many great resources
Some of the concepts u don’t know are crucial to these problems and solving them
wraith temple
Khanacademy has many great resources
Wut that
worn shadow
its a website
obtuse plover
Just search it up
obtuse plover
Yea np
safe radishBOT
@wraith temple Has your question been resolved?
slim vine
how do we know that to find the second angle we have to look in the second quadrnt here?
safe radishBOT
how do we know that to find the second angle we have to look in the second quadr...
glass carbon
how do we know that to find the second angle we have to look in the second quadr...
sin(π - x) = sin(x)
stray socket
That
Or you can think of it as the y axis being sine and the x axis being cosine
So you wanna look for when sine (y) is positive
stray socket
Just quadrant 1 and 2
glass carbon
Generally solution to the equation:
$$\sin(x) = a$$
where $-1 \leq a \leq 1$ is:
$$x=\arcsin a +2\pi n \vee x = \pi - \arcsin a + 2\pi n$$
$$n \in \mathbb{Z}$$
stray socket
generally
flat frigateBOT
Modus
stray socket
Or you can think of it as the y axis being sine and the x axis being cosine
This would be a lot easier to visualize
If you're not familiar with the funny symbols
glass carbon
generally I mean it always works, but visualizing is also a way, np.
slim vine
so when finding the second angle u just want to figure out what other quadrant is positive
stray socket
Where sine or cosine is whatever sign
slim vine
whatever sign?
slim vine
when would u need to find negative
stray socket
Whenever the angle is more than π radians (or coterminal to such angle)
Like uh
Let's say arcsin(-2/7)
And you wanna find solutions to that between 0 and 2π
slim vine
u mean like if the first angle is negative?
stray socket
Not necessarily. Sine will be negative whenever the angle is more than 180 degrees (between 180 and 360, that is)
But it could be negative, like -30 degrees, but that's the same as 330 degrees
So let's say (and assume angle measures from here on will be in degrees because I'm too lazy to toggle between my Greek and English keyboard just for pi) you have $\arcsin{(x)} = 280$, for $x\in[0, 360]$
flat frigateBOT
Umbraleviathan
slim vine
oh tsym ill try unerstand it
safe radishBOT
@slim vine Has your question been resolved?
twin falcon
safe radishBOT
twin falcon
need some help with part c
sacred wren
well, what did you get for A and B?
twin falcon
well, what did you get for A and B?
sacred wren
if b is true, then c must be true for the same reason, right? C is just B with an extra specifying condition
sacred wren
just realized what you were asking
nvm
how would h(z) work? if the domain is Y, then it can't take elements from Z
sacred wren
I'll level with you: I don't know the exact definitions of injective, surjective, and bijective off the top of my head, as I haven't studied them. I just noticed that B says (h o g is surjective) implies (g is surjective), and C is saying (h o g is surjective) AND (h is injective), which seems that all the necessary and sufficient conditions for g being surjective are there
looks like surjectivity means that the range of a function is the same as its codomain, meaning there aren't any leftover elements in the codomain that aren't mapped to
sacred wren
so if h o g is surjective, then that means that all elements of Z are mapped to, which shouldn't change just because all the elements of X map to something. I think it's supposed to show that injectivity doesn't get in the way of surjectivity
you might be caught up in thinking something must be different, when really there's no difference at all
twin falcon
yeh what youre saying makes sense
sacred wren
you could draw a mapping with multiple elements in each set and see if that helps
h o g is h(g(x)), right?
twin falcon
yes
sacred wren
so just work your way inside out. We know that every element of the codomain of h is the image of at most one element of the domain, and we know that every element of the codomain of the composite function is the image of at least one element of the domain, so that seems to imply that h o g is bijective
twin falcon
if h o g is bijective, how does that prove that g is surjective
tbh i dont really know
wait
i just thought of something
but idk if its completely wrong or if im on the right track
take a look at this
sacred wren
we know that h being injective means that every element in Z is attached to no more than one element of Y, but h(g) must give every element of Z an element (because it's surjective), and it can only get elements from Y (because it has to go through h)
twin falcon
sacred wren
that may work. give it a try
twin falcon
h(y) = z works for injective functions right
sacred wren
yes
vagrant sand
is it possible for a function to not be a pdf?
safe radishBOT
is it possible for a function to not be a pdf?
vagrant sand
for the probability P(X > Y), what would be the bounds?
quasi bison
yes
vagrant sand
lets say x: 0 < x < inf and y: 0 < y < 2
quasi bison
what's O?
vagrant sand
zero i mean sorry
quasi bison
are those two questions of yours related?
vagrant sand
no
quasi bison
$P(X>Y) = \int_0^2 \int_y^{\infty} p_{X,Y}(x,y) \dd{x} \dd{y}$
flat frigateBOT
Ann
quasi bison
this is probably what you're looking for for the second question
vagrant sand
as long as i follow that format for the bounds i should be fine?
quasi bison
idk what you mean by "that format" but... yes? i guess?
quasi bison
what do you mean?
you want to integrate over those pairs (x, y) which satisfy x > y
in case it was not clear: $\int_0^2 \paren{\int_y^{\infty} p_{X,Y}(x,y) \dd{x}} \dd{y}$.
flat frigateBOT
Ann
vagrant sand
why is your second integral y to infinity
i thought i made the x bound 0 to inf
and y bound 0 to 2
quasi bison
that would integrate over the entire support of the random vector (X,Y).
and you'd get 1, definitionally.
what you told me about X and Y was that X takes values in (0, +infty) and Y takes values in (0,2) and you wanted to calculate P(X > Y).
did i misunderstand you or is my understanding correct?
vagrant sand
it is correct
vagrant sand
ok ic
quasi bison
do you have anything else left to ask?
vagrant sand
so for bound like 0 < x < 2 and 0 < y < 5, the first integral bounds would be 0 5 and the second integral bound would be y 2
right?
quasi bison
that's if you want to do it like int[..., ...] int[..., ...] dx dy yes
sometimes it is convenient to do it the other way around
should usually be obvious when that is the case
vagrant sand
alright ty
safe radishBOT
@vagrant sand Has your question been resolved?
vagrant sand
that's if you want to do it like int[..., ...] int[..., ...] dx dy yes
for someting like this P(X > .5 | Y < .5), would it be .5 to inf and y to .5?
safe radishBOT
@vagrant sand Has your question been resolved?
vagrant sand
one for the numerator and one for the denominator
its not double?
like joint
im saying is the bounds correct though?
quasi bison
dunno, probably? don't care enough to check.
whole bay
Can someone please help me solve the following issue.
safe radishBOT
Can someone please help me solve the following issue.
tame charm
You don’t need the centroid to figure out if they’re collinear right
whole bay
Here is the information we already have:
A(1, 1, 1)
B(1, 0 , 2)
C(2, 0, 1)
whole bay
You don’t need the centroid to figure out if they’re collinear right
How can I find it out then?
tame charm
Do you know what collinear means?
whole bay
Yes.
tame charm
So how do you think you could find that out
safe radishBOT
@whole bay Has your question been resolved?
whole bay
@tame charm wdym?
tame charm
Collinear means they lie on the same line
Maybe this is hard to think about in three dimensions
How would you figure it out with two dimensions?
eg are (5,6) and (7,8) collinear? What about (-3,7) and (-6,14)?
tame charm
How did you figure that out
whole bay
graph
tame charm
Can someone please help me solve the following issue.
Ok, so can you graph these ones?
glass carbon
Do line passing through two points and check if 3rd lies on it
tame charm
@whole bay okay so graphing won’t work
Let’s say you couldn’t graph in two dimensions either
tame charm
eg are (5,6) and (7,8) collinear? What about (-3,7) and (-6,14)?
How would you answer this?
whole bay
I still dont know.
tame charm
How do you think you could figure it out?
safe radishBOT
Available help channel!
lean otter
Good YouTube video that covers all of pre calculus 10?
safe radishBOT
Good YouTube video that covers all of pre calculus 10?
lean otter
And if provided, any times ?
spice grove
You see, I don't know what the 10 means as we don't have it that way. But
You're looking for something like this?
lean otter
You're looking for something like this?
Yeah something in the grade 10 level
I’m entering that in September
spice grove
https://youtu.be/eI4an8aSsgw
Should suffice.
livid dove
Need help integrating this, i try the parametrisation method but i cant integrate it
safe radishBOT
Need help integrating this, i try the parametrisation method but i cant integrat...
@livid dove Has your question been resolved?
livid dove
<@&286206848099549185>
safe radishBOT
@livid dove Has your question been resolved?
livid dove
.close
safe radishBOT
safe radishBOT
Available help channel!
safe radishBOT
queen parcel
It's looking for the magnitude of the complex number given
|z| = magnitude of z
That's the magnitude of the complex number given
Find its magnitude
|z| = sqrt(x^2 + y^2) if z = x + iy
close
z = x + iy = 6 + 8i
Not sure how screaming helps but /s
If z = 6 + 8i = x + iy, what are x and y?
Note that x and y are both real numbers
You're overthinking it
hardy lion
yes
queen parcel
Sorry could you speak a bit louder please? Can't hear you
safe radishBOT
safe radishBOT
Available help channel!
smoky grail
h
plucky elk
<@&286206848099549185>
Don't ping without a question and not before 15 minutes
plucky elk
<@&268886789983436800> troll
mint flax
do you know what the difference quotient is
mint flax
but you have no idea what you're talking about
you need to start paying attention in class
the difference quotient is $\frac{f(x+h)-f(x)}h$
flat frigateBOT
gmod
mint flax
do you know what to do from here?
smoky grail
so h=2??
void parcel
how should i do this one?
safe radishBOT
how should i do this one?
nova creek
If C is on the x axis, how can the point be written?
nova creek
What can we say about the x or y values if the point is on the x axis?
void parcel
oh y is 0
void parcel
yes
nova creek
So, with this as C, what's the length of AC?
void parcel
root{(-2-x)2+(6-0)2}
nova creek
And what's BC?
void parcel
root[(9-x)2+(3-0)2]
nova creek
Set those equal to each other and solve for x
void parcel
didnt get it
nova creek
Show your work
nova creek
,rotate
flat frigateBOT
nova creek
Then what?
void parcel
uh idk
nova creek
Set those equal to each other and solve for x
.
void parcel
i didnt understand what u meant by "set those equal to each other"
root{(-2-x)2+(6-0)2}=root[(9-x)2+(3-0)2]
like this?
nova creek
Yes
void parcel
okay
nova creek
Because AC = BC
nova creek
It's not really "cancelling out," but you can square both sides, effectively doing the same thing
analog frigate
safe radishBOT
analog frigate
im soo confused how to fidn the angle to be cut
light shoal
well the smaller angle depicted (to the right of the angle to be cut) is the same as the one where the upper diagonal dotted line intersects the x axis, right?
analog frigate
yea???
light shoal
and then the one complementary to that is inside the 7.5/11.0 triangle, so you can compute it
analog frigate
so u would divide those two
light shoal
opposite over adjacent yea
light shoal
which angle is 0.6818
light shoal
0.6818 is just 7.5/11
that's the tangent of some angle
you have to take the arctangent to get the angle
analog frigate
uhhh
safe radishBOT
@analog frigate Has your question been resolved?
alpine tiger
confused on how to do this
safe radishBOT
confused on how to do this
alpine tiger
so what im doing here is that
$$g'(x)=(\sqrt{f(x)})'$$
flat frigateBOT
meek
alpine tiger
which means that id get $g'(x)=\frac{f'(x)}{2\sqrt{f(x)}}$
flat frigateBOT
meek
alpine tiger
now to evaluate $g'(3)$, i just substitute all of the x's for 3s?
flat frigateBOT
meek
stray socket
Yeah
alpine tiger
okay well here's the problem so
stray socket
They show you what f'(3) is too, assuming that the blue line is tangent to f(x) at x = 3
flat frigateBOT
meek
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
stray socket
**meek**
Compile Error! Click the <:errors:504266556054962196> reaction for more...
So instead of the -1, you'd have $\frac{-2}{3}$
flat frigateBOT
Umbraleviathan
flat frigateBOT
meek
stray socket
Yeah
alpine tiger
and that's the answer?
stray socket
Yeah
alpine tiger
hm weird
bc the answer key has this
and i usually cross reference it to make sure im like
stray socket
That's the same thing
stray socket
They just rationalized it
stray socket
Tbh, they're mathematically equivalent
stray socket
If you're not required to simplify, I'd leave it as $\frac{\left(-\frac{2}{3}\right)}{2\sqrt{2}}$
flat frigateBOT
Umbraleviathan
safe radishBOT
safe radishBOT
Available help channel!
mystic barn
I don't see how this is wrong
safe radishBOT
I don't see how this is wrong
mystic barn
my first try I put 1/10x+15/2 and 10.02
misty panther
well first of all your equation was wrong
misty panther
whats the derivative of sqrt(x)
mystic barn
whats the derivative of sqrt(x)
yeah it/s 1/2sqrt(x)
that's correct I just double checked
and then we plug in x and get 1/10
that's our m
y is 5 and we just solve for y with point slope formula
don't see any issues
thin bridge
why +
safe radishBOT
safe radishBOT
Available help channel!
normal summit
A and B are directly proportional to 7 and 9 and their sum is 70
normal summit
ik its easy but im shit at math so
safe radishBOT
safe radishBOT
Available help channel!
white oak
safe radishBOT
worthy hemlock
Did you draw a diagram?
white oak
Yea
worthy hemlock
Can you post your work?
worthy hemlock
What about the equation you used?
white oak
Ok
worthy hemlock
How did you plug in the numbers?
worthy hemlock
How did you get that?
worthy hemlock
Like asking for work means all the steps you did, from start to finish
worthy hemlock
I forgot the square root
This is probably the issue
worthy hemlock
Did you do sqrt(45.59671740697059)?
white oak
Yea
I am in degrees since I didn’t learn rad yet
I got that
@worthy hemlock does it work on all triangles?
worthy hemlock
Yes
worthy hemlock
No, please stop pinging me
upbeat prairie
safe radishBOT
upbeat prairie
I’m supposed to find the zeroes of this function. I found the real solution, but how do I find the imaginary solutions??
lean otter
factor
stray socket
There's no imaginary solution lol
Im@blind
potent roost
There's no imaginary solution lol
Im@blind
huh?
upbeat prairie
i ran it through symbolab and it said that there were two
potent roost
there are
upbeat prairie
im just not sure how to get there
potent roost
you can convert it to euler ig
stray socket
You know what, I did a slight mistake
upbeat prairie
you can convert it to euler ig
euler?
stray socket
that seems overkill
stray socket
You have the sum of two cubes
This
potent roost
I find it easier than sum of cubes lol
$$-8 = 8e^{i\pi} = x^3$$
$$x = 2e^{i\pi/3}$$
upbeat prairie
then just convert back to a+bi form
oh ok. i dont think ive learned that yet
potent roost
then just factor
spice grove
Well, it's easier to work with Euler's formula. But if you don't know you don't have to do that.
stray socket
Euler's formula works nicely yeah
spice grove
Just factor like everyone here is saying.
stray socket
Except I haven't been taught a formal teaching on it and only found it from YouTube recommendations
But factor
You have the sum of cubes
spice grove
Except I haven't been taught a formal teaching on it and only found it from YouT...
It's fun, and useful. Check out more on it!
stray socket
Also I decided for fun, trying something new, and I got $x = e^{\log_{3}(-8)}$
flat frigateBOT
Umbraleviathan
stray socket
Which I'm not sure if that will result in the complex root you would get from factoring
potent roost
nvm
stray socket
The i goes outside the root
potent roost
yup just the i is outside
spice grove
Yeah.
upbeat prairie
.close
safe radishBOT
safe radishBOT
Available help channel!
terse socket
Guys how do v differentiate this eq considering x and v and t are variables, rest all are constant
safe radishBOT
Guys how do v differentiate this eq considering x and v and t are variables, res...
terse socket
I believe chain rule has to be used but I'm confused in how it has to be applied
obtuse jackal
if they depend on each other, then in this case you can rewrite it as x(v) * v = a t(v) + b
that way you make explicit that they're functions of v and what rules to use
terse socket
I dint get u
quasi bison
where did this equation come from
terse socket
Wait btw x is position vector v is velocity and t is time
terse socket
where did this equation come from
It’s part of a larger problem
quasi bison
yes it's fine i asked for it
terse socket
The middle question
quasi bison
right, so you got from this that $x \dot{x} = at + b$
flat frigateBOT
Ann
terse socket
No it’s xv not xx
quasi bison
$\dot{x}$ is the time derivative of $x$
flat frigateBOT
Ann
terse socket
Ohh
quasi bison
and $\ddot{x}$ is the second time derivative a.k.a. acceleration a.k.a. what we're looking for
flat frigateBOT
Ann
quasi bison
(we cannot call it a since that letter is already in use)
differentiating this again gives you $x\ddot{x} + \dot{x}^2 = a$
flat frigateBOT
Ann
terse socket
Ok so while differentiating it the second time I ran into trouble
flat frigateBOT
Ann
terse socket
Guys how do v differentiate this eq considering x and v and t are variables, res...
. I had to derivate this to get accelerattion
safe radishBOT
@terse socket Has your question been resolved?
indigo flame
Hello
safe radishBOT
@indigo flame Has your question been resolved?
safe radishBOT
safe radishBOT
Available help channel!
topaz sluice
safe radishBOT
topaz sluice
<@&286206848099549185> its been 15 mins but i posted it in another channel
i need help with this question as I don't get a single thing of what this question is trying to tell me and I do not know how to figure it out
@ me when you reply to this
idle parrot
Do you see that the locus of such points will be a rectangular area
topaz sluice
yes
topaz sluice
ok so first draw the locus point that is the same distance of CD and AB
grizzled cloud
topaz sluice
i mean
topaz sluice
sorry i meant WZ
topaz sluice
oh yeah now i get it
idle parrot
Oops yeah I didn’t see u wrote it
topaz sluice
its just i didnt understand the part of where 2cm came in
i got some other questions i need help with
can you help me with them as well?
idle parrot
Sure
topaz sluice
its all the 8 questions that i have struggles with
i'll send them 1 by 1 when i have completed each question
i think its AC than to AB and closer to B than to C?
wait
ill send them all actually
idle parrot
Hey is it test?
idle parrot
Ohh
topaz sluice
the last screenshot goes with the 2nd to last screenshot
alright that is all of them
topaz sluice
can we start with this one first?
topaz sluice
oh
topaz sluice
yeah thats what i think its just the other 2 gaps im lost
nah it's wrong
dw we can skip that
topaz sluice
what about this one?
idle parrot
Ig here we can use distance formula *
Lets say the point C (0,a)
Distance AC = Distance BC
$\sqrt{(3-0)^2 + (2-a)^2} = \sqrt{(5-0)^2 + (4-a)^2}$
flat frigateBOT
Deep.
idle parrot
Get it?
safe radishBOT
@topaz sluice Has your question been resolved?
safe radishBOT
safe radishBOT
Available help channel!
rancid slate
safe radishBOT
safe radishBOT
@rancid slate Has your question been resolved?
junior jacinth
safe radishBOT
junior jacinth
How do I express this as an entire radical
upbeat ridge
What does that mean
junior jacinth
Theses ones with divisions in them reallly trip me out
junior jacinth
What does that mean
idk how to explain that
upbeat ridge
Rewrite them in power fractions
junior jacinth
what do you mean?
upbeat ridge
(x/a)^(b/c)
junior jacinth
so 2/3^4/3?
upbeat ridge
Where did the 4 come from
upbeat ridge
You probably meant 4(2/3)^(1/3)
junior jacinth
sorta, just wondering where the 1 came from
stoic dune
It doesn't work. We're leaving off the exponent on the 4, and the exponent 1/3 is not the same as a √
junior jacinth
Hard to tell but I don’t think it’s the root that has the power
yes no, definitely not the root
junior jacinth
It doesn't work. We're leaving off the exponent on the 4, and the exponent 1/3 i...
The 4 doesn’t have an exponent
junior jacinth
😂
stoic dune
Oh mb, then I did misread
upbeat ridge
Do you know why there is a 4 as a coefficient?
junior jacinth
sooo then does anyone know the answer?
upbeat ridge
Yes...
junior jacinth
the 4 is not being cubed
upbeat ridge
Which means only numbers that can has the power of 3 can come out
upbeat ridge
the 4 is not being cubed
???
junior jacinth
good lord
it’s 11 pm, I can’t do this
let’s say for example
We were asked to find the entire radical of 2^3 root 9
upbeat ridge
$4\left(\frac{2}{3}\right)^{\frac{1}{3}}=\left(4^{3}\cdot\frac{2}{3}\right)^{\frac{1}{3}}$
Understand?
flat frigateBOT
AirToastie
junior jacinth
1: where did the root symbol go, was it canceled out?
2: where did the 1 on the exponent come from?
cedar rover
$x^{\frac{a}{b}} = \sqrt[b]{x^a}$