#help-23

1 messages · Page 450 of 1

sonic sail
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and even a smaller value of b

novel magnet
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bruh 😆

sonic sail
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you reach instantaneous velo when b=12

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when the secant line becomes a tangent line

novel magnet
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ye but if i put 12 for b the equation will become undefined

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because it would be divided by 0

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right?

sonic sail
#

the idea is to use smaller and smaller values of b so that you can find out what the slope of tangent line is without actually caring about the tangent line

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you can still make b smaller than 12.0001

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what if b=12.0000001 or b=12.00000000000000000000001

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then you should have an idea what the slope would be right

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look at the last three slopes

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they are all negative and if you go top to bottom the number increases yet it doesnt go above 0

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do you think the number they approach is above zero

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if not what is the greatest number less than any number greater than zero

novel magnet
#

inifnite 0

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:/

sonic sail
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thats impossible

novel magnet
sonic sail
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theres no decimal with a infinite number of zeros and ending at 1

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but the slope can go much higher than that

sonic sail
novel magnet
#

no

sonic sail
#

0.01 is greater than zero

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so is 0.000000001

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so is 0.000000000000000000001

novel magnet
#

yes

sonic sail
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so what is the greatest number less than any positive number

novel magnet
#

-0.01

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-0.000001

sonic sail
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but -0.000001 is greater than that

novel magnet
#

yes

sonic sail
#

so is -0.000000000000000001

novel magnet
#

bruh

sonic sail
#

there are infinitely many numbers greater than -0.01 and -0.000001

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youre forgetting one simple number

novel magnet
#

hmm

sonic sail
#

think of integers

novel magnet
#

-1

sonic sail
#

but -0.01 is greater than that

novel magnet
#

;-;

sonic sail
#

im sure you can think of nonnegative integers yes

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nonnegative literally means not negative

novel magnet
#

1

sonic sail
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so either positive or ?

novel magnet
#

well

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it would be onluy positive

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numbers

sonic sail
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but 1 is a positive number

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0.000001 is less than that

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we need a number that isnt positive nor negative

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to satisfy the condition

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not negative cos you can always find a number slightly greater than the negative number you choose

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not positive cos you can always find a number slightly less than the positive number you choose

novel magnet
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0

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then

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i cant think of any other numbers

sonic sail
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yes

novel magnet
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how would 0 make sense tho

sonic sail
#

any stationary object has a zero instanteneous velocity

novel magnet
#

hmm

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roght

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right*

sonic sail
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its a bad idea to find slope of tangent line using that method generally speaking

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sometimes the table doesnt include a value that is way greater or less than all other values in table

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so your answer could be very far from the right one

novel magnet
#

okay

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so to find the answer we'd rather use the equation right

sonic sail
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theres a thing in calculus called limits

novel magnet
#

s(tf)-s(ti)/tf-ti

sonic sail
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and that table is maybe precursor to limits and derivatives

novel magnet
#

ill show u the full question

sonic sail
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is this test

novel magnet
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no lol

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its a hw

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u think i can talk in discord in a test

sonic sail
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oh hw

novel magnet
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ye

sonic sail
#

the keyword was there actually

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next to answer box

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integer

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Type an integer or a decimal

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if it was a decimal you could still go smaller or larger than the one you choose

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but if it was an integer it would be more definite

novel magnet
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so it would be 12

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or am i dumb asf rn

sonic sail
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you dont need to use equations here

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youre asked to use the table

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the interval [12 b] becomes single point 12 when b=12

novel magnet
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ye

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its 12

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lmao its late at night

sonic sail
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that represents instantaneous velo

novel magnet
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i needd sleep

sonic sail
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but 12 isnt the instantaneous velo

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what you said earlier is

novel magnet
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:/

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0

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?

sonic sail
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yes

novel magnet
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wait hold on

sonic sail
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did you type those values in by yourself

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the -8

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-1.6 etc

novel magnet
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i did

sonic sail
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look at your answer for b

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you said that object has 0 instantaneous velo when t=12

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and your answer 0 for c agrees with that

novel magnet
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oh right

sonic sail
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when the interval becomes single point t=12

novel magnet
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okay i see it now

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wait, instantaneous velocity means the average velocity when t approaches 0 right?

sonic sail
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no

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average velo is taken between two points in time

novel magnet
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oh

sonic sail
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instantaneous velo is taken at a single point in time

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thats why its called instantaneous

novel magnet
#

oookk

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alright

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i get it now

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ty

safe radishBOT
#

@novel magnet Has your question been resolved?

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safe radishBOT
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lean otter
#

I get to know that, for a series which is defined as $\sum_{n=1}^\infty f(n)$ only converges if $\lim_{n\to\infty} f(n) = 0$.
So, my doubt is that, why is this method not working in case of $\sum_{n=1}^\infty \frac1n$? The limit $\lim_{n\to\infty} \frac1n =0$. So according to this method, the series must converge but that's not true.

flat frigateBOT
plucky elk
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Example: I will bring an umbrella out only if it is raining

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Maybe an english analogy isn't too helpful

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Just think in terms of (statement 1) and (statement 2)

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As well as implications

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(statement 1) is "the series converges"

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(statement 2) is "the limit of the sequence is zero"

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Which implies which? Or do they imply each other?

lean otter
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Yeah, they imply each other

mortal meteor
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the fact, that the series converges implies that the f(n) converge to 0 but no the other way around

plucky elk
lean otter
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Yes

plucky elk
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so one implication is incorrect

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which one?

lean otter
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I didn't understand

plucky elk
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(statement 1) is "the harmonic series converges"

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(statement 2) is "the limit of 1/n converges to zero"

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does (statement 2) imply (statement 1) ?

lean otter
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These both statements are incorrect

plucky elk
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are you guessing?

lean otter
lean otter
lean otter
# flat frigate

That method is usually used to test for divergence rather than testing for convergence

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When a limit is non zero of the summand, the given series diverges

plucky elk
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right, it's not a test for convergence because the implication is false

lean otter
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Yes ^

plucky elk
lean otter
#

Exactly

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Due to the harmonic series case

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Because it's inconclusive whether the series really diverges or not

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When we're finding the limit, the last term is never equal to 0 in this case, but rather approaches 0. Due to this, the harmonic series very very very slowly shoots off to infinity.

#

Ohh

safe radishBOT
#
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lean otter
#

what power of 4 is $4^{36}\cdot2^{18}$

safe radishBOT
flat frigateBOT
#

crabbo

lean otter
#

i have to compute $\log_{1/4} (32^{-18})$

flat frigateBOT
#

crabbo

crisp lodge
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well

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you're not wrong

thin bridge
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why do you have to compute that monstrosity

crisp lodge
#

it will give you the answer, perhaps exponent rules will ease the process ?

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hint, can you write 2^2 in powers of 4?

lean otter
crisp lodge
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Now, can you apply the same exact method to the exercise ?

lean otter
#

$4^{36}\cdot 4^6$

flat frigateBOT
#

crabbo

lean otter
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4^42 is the answer

thin bridge
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where's 4^6 coming from

lean otter
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2^18=(2^2)^6=4^6

thin bridge
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where's (2^2)^6 coming from

lean otter
#

exponent laws

thin bridge
#

what exponent law are you applying to get from
2^18 to (2^2)^6

lean otter
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(2^a)^b=2^(a*b)

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u there?

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i was using @crisp lodge's hint, thats all

plucky elk
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what are a and b?

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and what's a * b ?

thin bridge
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how exactly are you applying

(2^a)^b=2^(a*b)
to get from
2^18 to (2^2)^6

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(would really like NOT to have to keep asking these follow questions)

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(i'm strongly implying that you done a algebraic mistake and expect you to find it)

lean otter
#

9

plucky elk
# lean otter 9

can you explain with more than just a number? we can't help you if you're not clear

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
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golden lark
safe radishBOT
golden lark
#

I found the answer to a relatively easily, but I truly do not understand what b means? I'm super confused by the wording. Anyone get it?

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like what material? how thin is it?

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i've taken calculus already so maybe i'm overcomplicating? but wouldn't this need more info and some kind of integral?

#

.close

safe radishBOT
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cerulean stream
#

If I have an item in a vending machine and I put in $1 then how do I calculate how many Q, D, N I get back? If the item was $0.15 then I would get back $0.85. How would I calculate the amount I get back of each coin?

inland ivy
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Are you assuming the least number of coins possible

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Or in other words the maximum number of quarters

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Then the max number of dimes

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Etc

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Rather than having 15 dimes when you could separate it into 6 quarters

cerulean stream
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Yes it would be the least number of coins

inland ivy
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You could probably use some fancy remainder/modulus stuff

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quarters = floor(money/0.25) would be the first step

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Where floor gets rid of the decimals

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Then you could say
dimes = floor((money Mod 0.25)/0.1)

cerulean stream
#

Ok thank you very much

inland ivy
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And finally you could say nickels = floor((money Mod 0.1)/0.05)

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I think that should all work

viscid zealot
#

Can anyone help me prove this

stray dew
inland ivy
#

You wouldn't really say that's inherently computer science would you?

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I'd call that just like logical statements

safe radishBOT
#

@cerulean stream Has your question been resolved?

stray dew
inland ivy
#

It also falls under many other things

#

Addition falls into computer science

safe radishBOT
#
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safe radishBOT
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lean otter
#

How do I solve this limit when denominator is 0?

graceful tiger
#

you can use l'hopital

lethal musk
#

there are many ways to solve this limit

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did you study l'hopital rule?

graceful tiger
#

AM INTERESTED IN KNOWING OTHER WAYS PLEASE

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oops sorry caps

lethal musk
#

you can search in youtube

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you will find a lot of proofs

graceful tiger
#

it works with l'hopital

lethal musk
#

geometric proofs

graceful tiger
#

am avoiding those tbh

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i SUCK when it comes to trigonometric functions

lethal musk
#

no geometric proofs

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you see the lengths

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wait

graceful tiger
#

yes

lean otter
lethal musk
#

I will send you a video

graceful tiger
#

yes please

graceful tiger
lean otter
#

youll get better

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you said you suck

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the only way to improve is to practice

lethal musk
#

at 20:25

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it's a very nice and intuitive proof

lean otter
#

ok thnx 🙏

#

.close

safe radishBOT
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vagrant pawn
#

in questions like these, how do you know which value to make (k+1) when proving by induction?

vagrant pawn
#

like it's unclear to me why one would assume the A(n) case then prove A(n+1) instead of for example like A(t) and then proving A(t+1)

broken yew
#

You realise...

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t is a dummy variable inside that integral

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That statement has no dependence on t.

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The only thing it has dependence on is n.

vagrant pawn
#

oh.

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alright

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what if i were to attempt to prove something like this?

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would the statement depend on k?

merry swift
#

From the statement it doesn't seem like any of these variables are necessarily integers at all, so induction might not be useful. What's theorem 1.8?

vagrant pawn
vagrant pawn
vagrant pawn
merry swift
#

yeah

vagrant pawn
#

but just for the sake of understanding, if k were to be an integer, I would prove A(k+1) right?

merry swift
#

if k was from an inductive set, you could prove the base case and prove that A(k) implies A(k+1)

plain hedge
#

I might move this to this chat idk

merry swift
#

well this chat is taken so if you wanna move to a question channel take one that isn't

safe radishBOT
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plain hedge
safe radishBOT
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mortal ore
#

when we say that a matrix is linearly independent

mortal ore
#

are we looking at rows or columns?

worthy hemlock
#

You can look at both

mortal ore
#

ok

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at now row/col should be constructible from other rows/cols, right?

worthy hemlock
#

Yes

mortal ore
#

thank you @vagrant pawn

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other than checking rows/cols, is there a better way to see if a matrix is linearly independent ? @worthy hemlock

worthy hemlock
#

Not that I can think of

mortal ore
#

does determinant of a sub matrix mean something?

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for this application

worthy hemlock
#

Determinant can help you determine if the matrix is invertible

mortal ore
#

oh yeah, 0 means not invertible

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.close

safe radishBOT
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night temple
#

Given( 5, h ) is one of the solution for the simulataneous equation h(x-y)=x+y-1=hx^2-11y^2 . Find h

night temple
#

someone can help me to solve this pls

#

<@&286206848099549185>

plucky elk
#

Did you plug in the point?

safe radishBOT
#

@night temple Has your question been resolved?

safe radishBOT
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tacit sky
#

Hi guys can anyone help me out with this 2 questions i have no idea how to do this, do show me the steps too how to calculate thank you

thin bridge
#

which part of q3 did you get stuck on?

wispy shard
flat frigateBOT
safe radishBOT
#

@tacit sky Has your question been resolved?

safe radishBOT
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next gulch
safe radishBOT
next gulch
#

,rotate

flat frigateBOT
next gulch
#

i need some help plugginn this into excel

#

im not sure what im doing wrong here

thin bridge
#

copy and paste the input here
place it in between ` `
to keep the *

next gulch
#

SQRT((2*N32/(2*M32)^2+((2*I22*J22)/(I22)^2)))

thin bridge
#

SQRT((2*N32/(2*M32))^2+((2*I22*J22)/(I22))^2)

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should work

next gulch
#

let me try

carmine dew
#

wow

next gulch
#

thank you so much

thin bridge
#

note that there are colour codes to indicate which parentheses are paired

next gulch
#

E44*SQRT(2*E22*F22/(E22)^2+(N32/2*M32)^2)

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so i would imagine this is correct in relation to this

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,rotate

flat frigateBOT
thin bridge
#

what happens when you enter that into excel

next gulch
#

i get a value but it is not close to what it should be

thin bridge
#

show me the colours of the parentheses you see in the formula bar

next gulch
#

maybe i have to bracket E22 and F22?

thin bridge
#

in what you currently have
for the term on the left, only (E22) is being squared instead of whole fraction
and for the term on the right,
N32 is being divided by 2 and then multiplied by M32 (i.e. B/2 * C = BC/2 which isn't what you wanted)

#

you also used E22 for both y and A

next gulch
next gulch
thin bridge
#

parentheses around whatever is supposed to be squared

thin bridge
#

theres still an issue for the right term

next gulch
#

yeah

#

that would fix it

#

i believe

thin bridge
#

yes

next gulch
#

my value does look a lot better now

#

i just have to be careful dividing

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but ty for the help again !!

#

thats all i needed for this lab calculations

#

.close

safe radishBOT
#
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lean otter
#

In complex analysis, when do we change the bounds of separated integrals if there are more than one contour?

flat frigateBOT
#

Cüneyt

#

Cüneyt

lean otter
#

is it going to be like

#

$\int_{0}^1 zdz+\int_0^1 zdz$ or $\int_{0}^1 zdz+\int_1^2 zdz$

flat frigateBOT
#

Cüneyt

safe radishBOT
#

@lean otter Has your question been resolved?

lean otter
#

<@&286206848099549185>

#

im afk I'll be back

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
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ruby phoenix
#

hi how can i solve this limit pls

safe radishBOT
split ether
#

No time to check this but what I'd try first it decomposing the fraction into two fractions, one having sqrt(2x + 1) - x on nominator and the other having -(sqrt(1 - 2x) - x) on nominator

ruby phoenix
#

thanks. i ll try this

humble venture
#

i'd do binomial expansion until the x^2 term

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on both of them

ruby phoenix
#

how

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i dont get it

humble venture
#

generalised binomial

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if you haven't learnt it then whatever

ruby phoenix
#

we still didnt do that

humble venture
#

yea ignore then

split ether
ruby phoenix
crisp lodge
#

a maclaurin expansion might be relevant?

ruby phoenix
#

its not smth i know

split ether
#

How about L'Hopital's rule?

ruby phoenix
#

same

#

😪

crisp lodge
ruby phoenix
#

what do you think of this?

#

please anyone

safe radishBOT
#

@ruby phoenix Has your question been resolved?

ruby phoenix
#

no

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i guess this limit is really hard

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to solve

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without advanced methods

final loom
#

Lmao

#

Hey!

#

1 - (- 1 ) = 0?

ruby phoenix
#

thanks !

#

that was a mistake

#

🥳

final loom
#

Lewl

#

Just rationalize num, denom tbh

#

what you're doing is no good

ruby phoenix
#

did you get to the result by rationalizing ?

safe radishBOT
#

@ruby phoenix Has your question been resolved?

ruby phoenix
#

anyways im closing this because i just solved it

#

it was unfortunately really hard for yall 🤣🤣🤣😂😂😂😂 losers

#

.close

safe radishBOT
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tacit berry
#

hi

safe radishBOT
tacit berry
#

I don't understand the step with partial fraction in this video (timestamp included)

#

How does it work?

lean otter
#

I have no clue how to do the base case for this problem. What interval on the reals do I choose for a sequence of n numbers between those reals?

#

I included my attempt but I don’t think it’s right

pulsar condor
tacit berry
#

thanks @Mosh, that helped

#

.close

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queen cave
#

How do i recognize a difference of squares easily?

queen cave
#

is it just when i see x^2 and something that could be squared?

inland ivy
#

x^2-something that can be square rooted

#

For a whole number

#

So for example x^2-9 which is x^2-3^2

split ether
#

Anything can be represented as a square of a number (as long as that anything is not negative)

#

You can use difference in squares even in x^2 - 2

queen cave
queen cave
#

oh wait hold up

split ether
#

I said x^2 - 2

queen cave
#

wait so thats the squared number?

#

just 2??

split ether
#

(x - sqrt2)(x + sqrt2)

queen cave
#

ah i see

#

.close

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vestal seal
safe radishBOT
vestal seal
#

I got w+7^2

#

(w+7)^2

pulsar condor
#

how did you get that?

oak summit
#

Almost

vestal seal
#

I moved the 7 over first

pulsar condor
#

right, giving w-7=-sqrt(g)

vestal seal
#

uh

#

if i move the 7

#

wouldnt it be w+7

pulsar condor
#

You subtract 7 from both sides

#

cause 7 is positive

vestal seal
#

oh the 7 is positive

#

ic ic

pulsar condor
#

yes

#

7, not -7

vestal seal
#

no i always thought of it like

#

going backwards from bidmas

#

and just

#

moving things over

#

if it was

#

g-7 or 7-g

#

i thought it was the same thing

#

but anyways

#

so it would be w-7?

#

= square root of g

pulsar condor
#

=-sqrt(g)

#

the sqrt(g) is negative.

vestal seal
#

so I add

#

square root of g

#

to both sides?

pulsar condor
#

sure, won't help you get g= though

vestal seal
#

should I

#

square root the whole

#

left

#

side

pulsar condor
#

Then you'd have complex numbers.

#

$(w-7)^2=(-\sqrt{g})^2=g$

flat frigateBOT
vestal seal
#

so what should I do

#

mosh

pulsar condor
#

read what I just wrote

#

and you'd see the answer.

#

you square both sides to get rid of the sqrt

vestal seal
#

is there

#

any other way of writing that

pulsar condor
#

why?

vestal seal
#

site wont accept certain answers

#

g = ?

pulsar condor
#

g=(w-7)^2...

#

again, read what I wrote

vestal seal
#

ive legit just tried that

pulsar condor
#

don't know what to tell you then.

thin bridge
#

try
g=(7-w)^2

vestal seal
#

worked

#

.close

safe radishBOT
#
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lean otter
#

At 9:02-9:30 in this vid is there a way to solve the limit of the piecewise function algebraicly? It seems more mathematical to me if done algebraicly than from plain observation.

https://m.youtube.com/watch?v=riXcZT2ICjA

crisp lodge
#

x->-a x->+a

#

-a +a denote direction of approach not sign of number

safe radishBOT
#

@lean otter Has your question been resolved?

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lean otter
safe radishBOT
lean otter
#

the solution says make the substitution a=x+y
b=y+z
c=z+x

#

i do see how it unfolds

#

but the idea of substitution doesnt make sense

weak dirge
#

In mathematical optimization, the method of Lagrange multipliers is a strategy for finding the local maxima and minima of a function subject to equality constraints (i.e., subject to the condition that one or more equations have to be satisfied exactly by the chosen values of the variables). It is named after the mathematician Joseph-Louis Lagra...

lean otter
#

oh im not asking for another way

#

i just wanna know why and how this substitution works

#

seems kinda abstract

weak dirge
#

It might have to do with the satisfying condition

#

I’m not entirely sure though

#

Wait I think I see it

#

Do you know how to solve this?

#

Yeah it’s really just a very creative solution

#

I personally don’t think I would come up with it

#

But it works very well

lean otter
weak dirge
#

So if you substitute it in the satisfying condition

#

You get x+y+z=1

#

Which you can use to substitute on the denominator

lean otter
#

ik how it works out

weak dirge
#

Okay idk what you’re asking then

lean otter
#

like this substitution doesnt make sense

weak dirge
#

How does it not make sense

lean otter
#

like how are we even allowed to do this
a=x+y
b=y+z
c=z+x

#

like the way all of them are constrained

weak dirge
#

I mean fundamentally you can substitute for whatever you want, the important part is that there are three independent variables

lean otter
#

they arent independent

#

they all are constrained

weak dirge
#

Define constrained

lean otter
#

that they depend on a condition

#

more like tied to a condition

weak dirge
#

Yeah but like they’re independent? In terms of the equation?

#

If you make a matrix it should be evident

lean otter
#

they arent independent thats what makes this wierd

#

x+y=1-z

weak dirge
#

The three sets of equations for abc are independent

lean otter
weak dirge
#

Independent may not be the right word I’m still in bed

#

Theyre just not dependent

#

It’s still R3

lean otter
#

what isnt dependent?

weak dirge
#

Abc<->xyz

#

On what

#

Clearly not each other

lean otter
#

x+y+z=1

#

if one changes the other changes as well

weak dirge
#

Are we talking about the satisfying condition or the substitution

lean otter
#

now im saying that x,y,z are dependent variables

weak dirge
#

Regarding the substitution, they are not which is what makes it possible

#

No matter what 3 variables you have, you can perform this substitution

#

The question is just the question, obviously an R3 span is a trivial

lean otter
#

swagthink and i lost u there

safe radishBOT
#

@lean otter Has your question been resolved?

#
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solar dock
safe radishBOT
solar dock
#

I got to the second matrix, how do i solve for h i dont understand

#

if rank A is equal to Rank C, why is h = 2 wrong and 7-2h = 0 right?

drowsy moss
#

The rank of A is not 2?

solar dock
#

oh ye i kinda choked now i understand where are tring to to get the entire second row 0 so it can be a consistent matrix

#

.close

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shy moss
#

i need help on this question

safe radishBOT
shy moss
plucky elk
#

Do you have any equations or expressions so far?

shy moss
#

no

plucky elk
#

Let x be the number Roxy is thinking of

shy moss
#

ok

plucky elk
#

4x < 40

#

So can you narrow that down?

shy moss
#

one min let me write that down

#

yep i wrote it down

#

ok and now what can our second expression be

#

@plucky elk hello...

#

<@&286206848099549185>

plucky elk
#

Can you narrow down the values for x?

#

Write down a similar inequality for the next sentence

shy moss
#

well we just need to divid them right

#

ok

plucky elk
#

Divide what?

shy moss
#

4 and 40

plucky elk
#

Ya

shy moss
#

so we can find what 1 x is

#

also one question

#

why did you right this downn <

#

????

#

for the expression

plucky elk
#

"less than 40"

shy moss
#

oh ok

#

thanks

#

also 1 x is 10

#

right

#

so that means rory is thinking of 10

#

?????????

#

@plucky elk

plucky elk
shy moss
#

wait i dont understand that

#

????

plucky elk
#

Do it in steps

#

"Four times Rory's number"

#

Is 4x

#

"the answer is less than 40"

shy moss
#

oh ok

plucky elk
#

Is 4x < 40

shy moss
#

ya but would you have to divid it

#

even thouh its less than 40

plucky elk
#

When you divide inequalities, they stay inequalities

shy moss
#

right???

plucky elk
#

4*3 < 40 turns into 3<10 when you divide by 4

shy moss
#

wheere did you get 3

#

@plucky elk

plucky elk
#

Stop pinging me

shy moss
#

ok

plucky elk
#

I'm just pointing out you keep the inequality

#

Instead of turning it into an equation like you did

plucky elk
shy moss
#

wait one question

#

ok

#

so now the equation is 4 <10 ?

#

or more

plucky elk
#

4x < 40 and divide by 4

shy moss
#

so we would write 4x<10

plucky elk
shy moss
#

cause we divided like you said

plucky elk
#

Divide BOTH sides by 4

#

Start here 4x < 40

shy moss
#

oh so 40 and 4

#

so this is what i got 1<10

plucky elk
shy moss
#

oh ok

#

sorry

plucky elk
#

4x divided by 4 is ?

shy moss
#

1x

plucky elk
#

Good

shy moss
#

oh so now do we dived

plucky elk
#

1x < ?

shy moss
#

10

#

?

plucky elk
#

Yes

shy moss
#

ok

plucky elk
#

Can you read the next equation and come up with an inequality?

shy moss
#

so now we have gotten 1x<10

#

what does inequality mean

#

??

plucky elk
#

Something with a less than or greater than sign

#

x<10, 4x<40 are both inequalities

shy moss
#

ok so for example x>23

#

like that

plucky elk
#

Yup

shy moss
#

ok

#

thanks for the meaning

#

ok so do we divied

#

?????????

#

1x<10

plucky elk
#

Yea. 1x is the same as x because 1 times any number is itself

#

Can you read the next sentence and come up with an inequality?

shy moss
#

ok the nest sentence is that if the number is multipled by 7 it is larger than 50

#

so now for our inequality it is

#

..

#

7x=50

#

right or no

plucky elk
#

No, but close

shy moss
#

7x<50

plucky elk
#

"greater than"

#

< is less than

#

> is greater than

shy moss
#

yes so would that mean 7x>50

plucky elk
#

Yes

#

Guess what the next step is

shy moss
#

we need to divid

plucky elk
#

By what number

shy moss
#

7 and 50

#

??????

plucky elk
#

Slow down

#

Before, we divided by 4

#

Because it isolated x to one side of the inequality

#

4x < 40, divide both sides by 4, x < 10

#

7x > 50, divide both sides by ?, x > ??

shy moss
#

7x7

#

cause 7x7 s 49

#

and that is close to 50

plucky elk
#

Well if you divide 7x by 49, you get x/7 > 50/49

#

What does that tell you about x?

#

You want to isolate x on one side of an inequality

shy moss
#

so you put it to the other side

plucky elk
#

You can save a step and divide by 7

#

7x > 50, divide both sides by 7, x > ??

shy moss
#

wait so what should i write in my notebook

plucky elk
#

write whatever you understand

#

If you don't understand ask a question

shy moss
#

ok thanks

#

so we would 7x<49

#

right

plucky elk
#

You got that from reading the problem

shy moss
#

yes

#

but you said we need to divide by 7

plucky elk
#

Ask yourself how can you isolate x

#

Right. Divide 7x > 50 by 7

#

BOTH sides

shy moss
#

oh ok

plucky elk
#

Always both sides

shy moss
#

1x>7

plucky elk
#

We don't want to change anything about the inequality

shy moss
#

ok

plucky elk
#

50/7 = 7.1...

shy moss
#

what 7.1

#

???

#

how

plucky elk
#

Plug into your calculator

shy moss
#

ok

#

do we need a calculater

#

or can i write on my paper

plucky elk
#

Just understand that 50/7 is not equal to 7

shy moss
#

OK

#

sorry caps

plucky elk
#

So this is close enough to being right

shy moss
#

yes

#

7.1

plucky elk
#

I mean 1x > 7

#

What do you know about 1x?

#

To simplify a little more

shy moss
#

its basicly x

plucky elk
#

Correct

#

Summarizing you know x < 10 and x > 7

shy moss
#

yep

plucky elk
#

Can you review your notes to confirm

shy moss
#

ok

#

one min

#

ok yep its right

plucky elk
#

Do you know what a whole number is?

shy moss
#

one min let me sharpen my pencil

shy moss
#

ok back

#

so how can we but 7.1 to a whole number

plucky elk
#

You only need that x is larger

shy moss
#

yep

#

it says that

plucky elk
#

For whole numbers, x>7 is the same as x>7.1

shy moss
#

mmm

#

cause we dividdd it

plucky elk
shy moss
#

welll there is no number that they can go

plucky elk
#

Okay maybe just one at a time

#

What's a whole number that's less than 10?

#

Any

small aspen
#

@shy moss Your about me is terrifying

shy moss
#

ok?

#

um riemanna so like we where saying 1 2 3 4 5 6 7 8 9 are whole number

#

s

plucky elk
#

Now of those, how many also satisfy x>7

shy moss
#

7

plucky elk
#

7 is not greater than 7

shy moss
#

8

plucky elk
#

7 is equal to 7, but not greater than 7 and not less than 7

plucky elk
shy moss
#

9

plucky elk
#

That's all of them

shy moss
#

8 and 9

plucky elk
#

I think you can do the rest of the problem

shy moss
#

one last question

#

what should we do 8 and 9

plucky elk
#

Read and interpret

shy moss
#

i dont understand

#

can you explan me

#

<@&286206848099549185>

#

.close

safe radishBOT
#
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glad lava
#

Quick question: The identity element in the permutation group $S_n$ is just
1,2,...,n on both rows, right?

flat frigateBOT
#

beeswax

frigid geyser
#

assuming by that you mean the permutation that maps the top row to the bottom row, yes

glad lava
#

Thanks!

#

.close

safe radishBOT
#
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pastel hamlet
#

@fading raft I forgot the rest of the problem lol

pastel hamlet
#

For the first one I got 2 and the second one I got 1

fading raft
#

So the first one reads as

pastel hamlet
#

ah wait I messed it up

fading raft
#

What is the value the function x approaches as x approaches 1 from values less than 1

pastel hamlet
#

first one should be 3

fading raft
#

yh

pastel hamlet
#

f(1) = 2(1) + 1

#

second one I got 1

fading raft
#

good

pastel hamlet
#

since it's from the right

fading raft
#

whats the third

pastel hamlet
#

and the last one does not exist

lean otter
#

Limit does not exist

fading raft
#

why

pastel hamlet
#

they're not equal

lean otter
#

Because right hand limit ≠ left hand limit

pastel hamlet
#

^

fading raft
#

good

pastel hamlet
#

awesome 😄

#

thanks again!

lean otter
#

👍

pastel hamlet
#

.close

safe radishBOT
#
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safe radishBOT
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amber hemlock
#

Can I get help for this ^

safe radishBOT
safe radishBOT
#

@amber hemlock Has your question been resolved?

safe radishBOT
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verbal night
#

What is x+x^2=122872

safe radishBOT
red glen
verbal night
#

What’s the answer?

red glen
verbal night
#

Hmm

#

Not really

#

But I know you plug the numbers in the formula

red glen
#

Yes

verbal night
#

Am I close?

#

I’m stuck on the x + x^2 = 122872 part

red glen
#

$\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

flat frigateBOT
#

BrownMunde

red glen
verbal night
#

What do we plug in for b

red glen
verbal night
#

Is this what it’s suppose to look like

#

Then do we add and subtract -1 from -61435.5

red glen
#

,w solve (x^2+x-122872=0)

flat frigateBOT
verbal night
#

Now what

stable bobcat
#

Wait

#

Do you know what b, a and c mean in that quadratic formula?

verbal night
#

nope

stable bobcat
#

You know

#

That

red glen
#

Then this is tough

stable bobcat
#

X²+x=7272727 can be wrote as

#

X²+x-727722=0

#

Right?

verbal night
#

Oh

#

Kind of

stable bobcat
#

So follow me here

#

We always need to put our everything on one side

#

And the 0 on the other

verbal night
#

I thought my version was ok too

stable bobcat
#

Well we don't use that

verbal night
#

Ok

stable bobcat
#

Always put your equation and make it equal 0

#

Now what we do next it

#

Think of the equation as

#

ax²+bx+c

#

For example

#

5x²-3x+2

#

here a is 5 b is -3 and c is 2

#

In your case, x² is multiplied by 1,

#

X also multiplied by 1

#

And c is the number itself which is -122872

#

Got it?

verbal night
#

Yes

#

But why is it negative

stable bobcat
#

a is the coefficient of the square, b is the coefficient of the variable and c is the constant

stable bobcat
#

In the original equation

verbal night
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Nvm

#

I see

stable bobcat
#

The minus belongs to the coefficient not the x

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So always, write your equation in that shape and leave 0 alone

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And then get your a b and c

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ax²+bx+c=0

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And plug the numbers in the formula

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This formula is equal to x

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Got it?

verbal night
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Yes

stable bobcat
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You should try on some other equation to make sure.

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I wouldn't say it's hard

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Just requires some practice.

verbal night
#

Ok ok, I got you

stable bobcat
#

Sweet

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Note that every quadratic equation gives two different solutions

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Obviously

verbal night
#

Alright I see

#

X=350 or x=-351

safe radishBOT
#

@verbal night Has your question been resolved?

verbal night
#

.close

safe radishBOT
#
Channel closed

Closed by @verbal night

Use .reopen if this was a mistake.

verbal night
#

.reopen

safe radishBOT
#

verbal night
#

Did my other work and now I’m back to this

oblique goblet
#

What’s the problem?

verbal night
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I’m not sure where to plug in the 350 or -351

red glen
oblique goblet
#

I think it’s x + 22000, not x + 22

verbal night
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Fuck

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I read wrong

oblique goblet
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Rip

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But yeah you have the right idea, set up the quadratic, find the x values, and then like @red glen said, use the positive root because distance can’t be negative

verbal night
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And then I plug in the positive solution to the x values then I get my answer?

oblique goblet
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Yeah exactly

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You have the exact process, just read the problem wrong (I do that all the time too, don’t sweat it)

verbal night
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Oh ok thank you man

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Thanks to everyone who helped

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I have learned so much in the span of a couple of hours

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.close

safe radishBOT
#
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safe radishBOT
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lean otter
#

I don’t understand how to solve these special angles

safe radishBOT
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mystic hemlock
#

lim
x→−2+

safe radishBOT
mystic hemlock
#

Can anyone help me what does + stand for?

lean otter
mystic hemlock
#

But it has effect on modules yes?

lean otter
lean otter
mystic hemlock
#

No i mean |x+2| when -2+

lean otter
#

ohh for |x+2| it does affect sign

#

at -2+ its (x+2)
and for -2- its -(x+2)

mystic hemlock
#

Okay thanks a lot

#

.close

safe radishBOT
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mystic hemlock
#

.reopen

safe radishBOT
#

mystic hemlock
#

Sorry but one more question

#

lim
x→0−

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When it is like this and in 1/x how can i solve it?

lean otter
#

and for 0+ its +infinity

mystic hemlock
#

But when it is 1+ we can solve it yeh?

lean otter
#

yeah

mystic hemlock
lean otter
mystic hemlock
#

What if it is 0?

lean otter
#

then answer is 0

mystic hemlock
#

.close

safe radishBOT
#
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verbal night
#

Can someone walk me through this problem

safe radishBOT
crisp lodge
#

Have you tried anything so far?

#

Is there anything specific that you don't understand ?

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@verbal night Has your question been resolved?

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lean otter
safe radishBOT
lean otter
#

Where did I screw up?

final loom
lean otter
final loom
#

:p