help-23

[desert juniper]

however, the answer sheet saying only positive 2 is incomplete

[cunning epoch]

either way i ddint know what to do with exponents in an equation so worth some effort lol

[fresh wasp]

It says +/-

[desert juniper]

i read what he said

[fresh wasp]

Yea on the 4 question not the second

Read the problem he put

.

[cunning epoch]

im looking at and for some reason my answer sheet says 3x^2 but the question sheet is 3x^1/2

[fresh wasp]

Huh show

[cunning epoch]

could jsut be a typo

[fresh wasp]

Uh no it couldn’t be because your answer is right for the problem the other one is right for that problem

[cunning epoch]

Question sheet

[fresh wasp]

Weird

[cunning epoch]

Answer sheet

[fresh wasp]

Well tell the teacher then

[cunning epoch]

It's just a sample thing from a billion years ago lol

[fresh wasp]

Your answer is right according to the problem sheet tho

[cunning epoch]

oke well thats good ill havbe to wrok on exponents in equations

[empty gyro]

This says $3x^2$, but the problem you were doing said $3x^{1/2}$. that's the issue

[flat frigate]

SWR

[fresh wasp]

Yea he said that

[empty gyro]

Oh oops. Mb

[fresh wasp]

You good then?

[cunning epoch]

i think theres one more thing i need some clarity on

[fresh wasp]

Ok

[cunning epoch]

when you have 2 different variables in an equation

[fresh wasp]

Yea

[fresh wasp]

You need to get rid of one so you can solve for x or y

[cunning epoch]

trying to solve x+2y =5

[fresh wasp]

You can use substitution or elimination

You have to use both equations

[cunning epoch]

so would i combine like terms in both?

[fresh wasp]

You can do it two ways do you know either of them?

[cunning epoch]

giving me x^2 + 5y^2 =12

[fresh wasp]

Um no you can’t do that

[cunning epoch]

im a little rusty lol

[fresh wasp]

So you can do substitution or elimination I like substitution better

[empty gyro]

(I like subtracting both equations, but it all works fine)

[fresh wasp]

Ok so for the first problem solve for x

[fresh wasp]

I hate subtraction in any manner 😭

[cunning epoch]

Trying to solve x

[fresh wasp]

um no

so the first part is right you do subtract by 2y

but that stays seperate

so you get x = 5-2y

[cunning epoch]

ah ic

[fresh wasp]

o so now yu plug in what you just got (5-2y) for the x in the other equation

and you should get (5-2y) + 3y = 7

ok?

[cunning epoch]

yep that makes sense

[fresh wasp]

perfect

so just solve for y

can you do that?

[cunning epoch]

i can try my darndest lol

can i combine 2y and 3y as like terms even tho one is in a bracket?

[fresh wasp]

yes since there is no sign or anything around the bracket just pretend like its not there, it just shows we plugged in

also youre combining -2y and 3y not 2y and 3y

[fresh wasp]

so -2 +3 is?

[cunning epoch]

1

[fresh wasp]

yes so its 1y not -1y

otherwise it looks great

[cunning epoch]

ah i thoght the substitution would stay

[fresh wasp]

huh

[cunning epoch]

i think what im struggling with the most is that it seems like BEDMAS has just gone out the window lol

[fresh wasp]

BEDMAS?

PEMDAS?

[cunning epoch]

yeah tomato tomatoe

[fresh wasp]

lol

pemdas hasnt gone anywhere

[cunning epoch]

canadian we learn brackets exponents here lol

[fresh wasp]

oh

we say parentheses

[cunning epoch]

i geuss its more so all the tiny rules i ahve to remeber

[fresh wasp]

yea well if nothing is around the brackets they just go away

so

like you can put anything you want in brackets it wont change anything

[cunning epoch]

okay fair enough

[fresh wasp]

ok so now i have

is that what you got?

[cunning epoch]

i think where i get confused is the 5-2y wouldnt that turn into 3y which you would still have to add the other 3 y making 6y?

[fresh wasp]

why would 2y become 3 y

[cunning epoch]

because the minus 5?

5-2=3

[fresh wasp]

the 5 is a constant not a coefficent or variable

the variables are seperate

like varibales can have coeffiencents such as like 2 or 3 like 2y or 3y but 5 is a constant

[cunning epoch]

ok i c

but the 2y is not negative?

[fresh wasp]

we never combine coefficents and constants thats why when you solve for a variable the constant is on the other side

[fresh wasp]

it is

thats why its -2y + 3y

[cunning epoch]

ah ic

and if get 1 y then its written as just y?

[fresh wasp]

so for the brackets, why its important to include those when substrituting as liek say the second equation was 2x, it would then be 2(5-2y), but if its just x dont worry about it

[fresh wasp]

yes, the 1 isnt written its assumed that y is 1y and x is 1x

just like earlier when i showed you 4 is actually 4^1

[cunning epoch]

oke cool

question wants to know what y and x is tho

[fresh wasp]

yes we just solved for y

did you get that far?

[cunning epoch]

yep

so now just plug the value of y into the first equation?

[fresh wasp]

ok so now we plug y into one of the equations and solve for x i chose the first one

[cunning epoch]

epic

so how did you know to only get to x=5-2y before jumping to solve the next equation

[fresh wasp]

youre substuting, you can chose either variable to solve for in either equation, i chose the first because i wanted to and i chose x because then you dont have to divide out the coefficent

[cunning epoch]

okay cool

[fresh wasp]

Like you could solve for y in the first or the second but that is much more work because you’ll get a fraction and form experience i know you don’t like those 😭

Ok so did you solve for x?

[fresh wasp]

Yessss

Good job

[cunning epoch]

thank you! 😃

[fresh wasp]

If you want to try doing the second one I’ll be here if you get stuck

[cunning epoch]

Perfect ty

Trying my hand at this one

[fresh wasp]

Thank you

Yea there are fractions in that one 🥲

Have fun ❤️

[small knot]

lmk if u need help

[small knot]

i get what you mean with this, although it does become kind of intuitive after a good bit of practice

for example with the brackets, i like to think that they bring everything together into one term, so (a+2y) is one single number, but of course intuitively you can tell that if you subtract 2y from (a+2y) you are left with a

[cunning epoch]

okay well if thats the case in regards to 7x=2y-6 could i not just subtract 2y so im left with -6?

[fresh wasp]

um no

that has to stay

y is a variable so you cant combine variables and a constant

[fresh wasp]

yessss

so now substitute

[fresh wasp]

You forgot the +3

And you can’t take something out of parentheses to do subtraction

[cunning epoch]

okay if i multiply 7 by 3.5x and subtract 4x from 12 im left with

24.5x=8x?

[fresh wasp]

You still need the +3

[fresh wasp]

When you distribute the 7 it is multiplied by the 3 and 3.5x

[cunning epoch]

okay so i should have 21+24.5x=12-4x

[fresh wasp]

Yes but 12 -4x

[cunning epoch]

so 8x on the right?

so i have 21+24.5x=8x

[fresh wasp]

Huh

Um no?

It’s 12- 4x

[cunning epoch]

so why multiply the 3.5x by 7 but you cant subtract 12 from 4x

[fresh wasp]

12 is a constant

4x is a variable and coeffiencent

they cannot be combined

7 is being multiplied by 3.5x

[cunning epoch]

so would i subtract 12 from both sides then?

[fresh wasp]

huh

why

just get the xs on the same side

[cunning epoch]

to isolate the variable

[fresh wasp]

yes

[cunning epoch]

so once the variables are out of brackets you can add them together regardless of what side of the equal sign they are on?

currently i have 9+3.5x=4x

[fresh wasp]

um no

where are you getting 9 + 3.5 x from

[cunning epoch]

i subtracted 12 from the right

[fresh wasp]

why?

[cunning epoch]

idk seemed like the next logical step

at least to me

[fresh wasp]

what did you have before that

[cunning epoch]

21+3.5x=12-4x

[fresh wasp]

why didnt you multiply the 7 by 3.5x?

[cunning epoch]

because its a variable and not a constant

[fresh wasp]

you cant add or subtract from a variable but you can multiply or divide

[cunning epoch]

yeah i think ive hit a wall

i got 21+24.5x=12-4x

[fresh wasp]

there

yesss

[cunning epoch]

so wouldnt i subtract 12 from 21?

[fresh wasp]

yes

depends what side you do i put x on the left side

[cunning epoch]

yeah so that gives me 9+24.5x=12-4x

[fresh wasp]

you left the 12 there tho

[cunning epoch]

ah mb so

9+24.5x=-4x

[fresh wasp]

yesss

then move 24.5x to the right side

[cunning epoch]

what operation would i use to do that?

[fresh wasp]

subtraction?

its the same thing

[cunning epoch]

so i got 21=12-4x-24.5x

combining like terms gives me 21=12-28.5x

[fresh wasp]

you kept the 12 why

oh nvm

[cunning epoch]

im not sure what to do with it

[fresh wasp]

are you going to subtract 12 then?

[cunning epoch]

so subtracting the 12 gives me 9=28.5x

[fresh wasp]

yesss

then divide by 28.5 to get x alone

[cunning epoch]

yep that gives me 0.315

[fresh wasp]

i got -18/57

[fresh wasp]

oops the 9 is negative

[cunning epoch]

21-12 is 9 no?

[fresh wasp]

uh oops let me see

[cunning epoch]

answer sheet is saying y=4 and x=3

[fresh wasp]

wtf

[cunning epoch]

i still have 3=3.5x as my y

This is the answer sheet

[fresh wasp]

Bro

That’s a different problem

😭

[cunning epoch]

i stg my college sucks man

all these practice problems were made by some drunk guy in the 80s 😭

[fresh wasp]

I can tell

[fresh wasp]

Yes

[cunning epoch]

so far i have y=3+3.5x

i appreciate the help but i think im just getting frustrated at this point ill have to try again tomorrow

[fresh wasp]

youre weclome

im sorry its frustrating i hope it goes well you can always dm 🙂

[cunning epoch]

thank you appreciate it!

[fresh wasp]

!done

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[cedar ginkgo]

Tightrope: 4(-7.6)+3 1/2(100+5)

[cedar ginkgo]

I know that I can hop -7.6 4 times but I dont know how many time I should hop 105 since hopping 3 or 4 times makes your answer wrong.

[visual pond]

Can you show the original problem

[safe radish]

@cedar ginkgo Has your question been resolved?

[cedar ginkgo]

Wait.

@visual pond

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[cloud pond]

If you had two choices
Choice A: 100% chance for 100
Choice B: 10% chance to get 600 and 90% chance to get 50, 20 people who make this choice get 50000 except there are like a million participants
You get to pick and recieve the rewards 7 times
What would yield the most

This is seriously not an important question and I'm only here cause I couldn't figure out how to count it

[modern dagger]

The chance of choosing B 7 times in a row and not getting the 600 is 47,8%

because 0,9^7

I don't understand the last part, about the 20 people

[cloud pond]

Oh yeah no maybe ignore that part cause this is just me agonizing over a gacha game

So it's probably negligible

[modern dagger]

I actually love gambling so I would go for the 7 times B in a row

It's favorable that you will get the 600 + 300

[cloud pond]

Hmm yeah true

Okay got it thanks 👍

[toxic stratus]

,w 0.1600 + 0.950

[flat frigate]

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[toxic stratus]

higher EV

[modern dagger]

What is that?

[toxic stratus]

https://en.wikipedia.org/wiki/Expected_value

[cloud pond]

But doesn't standard deviation only work with large amounts of data

Like I considered using that but uh

[toxic stratus]

nobody mentioned standard deviation

[modern dagger]

Bro elaborate a bit please

[cloud pond]

Wait f sorry

[modern dagger]

You're just dropping pictures and links

[cloud pond]

I graduated like six months ago and forgot everything

[modern dagger]

Bruh

[cloud pond]

Lol true I don't understand any of it

[modern dagger]

Me too

[toxic stratus]

do you know any probability?

[cloud pond]

I.. did?

Last year

Not sure anymore

[toxic stratus]

did you learn expected value?

[cloud pond]

Umm yeah I think I did but I forgot

🥹

Sorry

[toxic stratus]

it's the mean

[cloud pond]

Ohhhhh

[toxic stratus]

long term average

[cloud pond]

Ohhhhhhh okay I think I get it

[toxic stratus]

choice B will give you 5 more each time overall in the long run

but only if you do it many times

you can calculate exact probabilities of getting each outcome

[cloud pond]

Ohh wait that's all it took to count it 💀

Okay thanks that makes a lot of sense

[modern dagger]

That's smart

So how did you calculate it?

[toxic stratus]

you just take the weighted average

[modern dagger]

Okay

[toxic stratus]

90% * 50 + 10% * 600

[cloud pond]

I forgot the basic formula damn 😭

Thanks for reminding me, I'm sorry to all my math teachers

[modern dagger]

Yeah thanks @toxic stratus

[toxic stratus]

,w Table[{C(7, n)0.9^n0.1^(7-n), 50n + 600(7-n)}}, {n, 0, 7}]

probabilities and how much you get listed out

oh wait its 7

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[cloud pond]

OH YES WAIT I NEEDED EXACTLY THAT

Yet another thing I learned how to do but forgot

[toxic stratus]

hmm lets see

so if you go for A

you get 700 guaranteed

i wonder if we can minimise variance

,w sum n=0 to 6 of C(7, n) 0.9^n 0.1^(7-n)

[flat frigate]

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[cloud pond]

Mmmm yeah I don't really get it but the chance for B was enough for me I think

Tysm I would've died forever on this

[toxic stratus]

52.17% of getting more if you only go for B

[cloud pond]

Damn alright that's good for me

OHHH THAT'S WHAT IT MEANS

Thank you so much ugh I love you stranger 🫶

[toxic stratus]

,w Table[{100n, 50*(n-1) + 600*(n-(n-1))}}, {n, 0, 7}]

[flat frigate]

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[toxic stratus]

,w Table[sum k=0 to (n-1) of C(n, k) 0.9^k 0.1^(n-k), {n, 0, 7}]

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[toxic stratus]

meh

[safe radish]

@cloud pond Has your question been resolved?

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[lean otter]

could someone explain how q1.q2=1 in the antisymmetric proof

[lean otter]

oh i got it

.close

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[humble spear]

This is what I've tried

[plucky elk]

Add and subtract 1 from the numerator

That works too I guess if you can L'Hopital

[humble spear]

Like this?

[humble spear]

I know how to lhop but I don't know how I would use it here since it's not a fraction

[plucky elk]

n = 1/(1/n)

[latent zealot]

Prove that a circle is not a polyhedral convex set

Can help me?

[plucky elk]

!occupied

[safe radish]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[humble spear]

ok i'll try doing it one sec

I got lny = -(n^2 + n)

what do I do now?

[safe radish]

@humble spear Has your question been resolved?

[humble spear]

Isn't it approaching to e^-infinity here

The answer key says e^-1 did I do anything wrong?

[undone burrow]

you haven't done chain rule on the top term

[humble spear]

I fixed it but still have to get rid of that n somehow

oh wait

isn't it 0 because 1/inf = 0

then the limit would be 1

but the answer key says e^-1

im stuck again

[undone burrow]

you did that bottom calculation wrong

but yea, after that, you take the limit

[humble spear]

how did I do it wrong

I don't see it

[undone burrow]

where did the n in the numerator go?

[humble spear]

oops

so its -(n/(n+1))

but isn't inf/inf+1 uncertain

?

oh wait I just have to divide both by n

alr solved it now thx

[undone burrow]

nice, np!

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[timid yew]

g(x)=(2x-1)²-7 and h(x)=6-12x

The area of ​​the region bounded by the curves g(x) and h(x) located to the left of the Y axis is
(A) 36
(B) 38
(C) 40
(D) 42
(E) 44

[timid yew]

Can someone tell me where to start?

[limpid gust]

Isn't that just an integral?

[timid yew]

Why is it an integral?

[limpid gust]

Because you use an integral to find the area under curves no?

[timid yew]

So I must study integral first then?

Alright then

.close

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[molten hawk]

Can someone verify

[molten hawk]

P1 never wins if P2 adjusts to P1’s move

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[plucky oyster]

i don’t understand number 5

[smoky nacelle]

try to complete the square

[desert pasture]

factor out the 1/3, that may help

[plucky oyster]

ookie

like that..?

or do i put the 1 in the bracket as well-

[wet frost]

You could, but you definitely shouldn't 😁

[plucky oyster]

what-

i don’t get it ;-;

[plucky oyster]

how-

i’m sorry i don’t really understand how factorizing works

[smoky nacelle]

you could

[smoky nacelle]

try to write it as a complete square $\pm$ other stuff

[flat frigate]

Percy

[dry wadi]

try include the 1, and u then can use cross method to facotrize

[plucky oyster]

nvm i got it alrdy

thx tho :>

.close

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[jaunty pelican]

brp

[jaunty pelican]

bro

[smoky nacelle]

!nohi

sigh.

https://nohello.net/en/

[vagrant ice]

!da2a

[safe radish]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[jaunty pelican]

ah mb

[smoky nacelle]

he didnt even ask to ask he just went bro

[hasty wagon]

do you have any math questions you wanna ask?

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[pseudo carbon]

How to do 9(e)?

How come is AE ?

[desert juniper]

-2FA = 2AF

[pseudo carbon]

Yea I also did that

Then dk wut to do next 😭

[desert juniper]

you start in A, and move AB. where are you currently?

[pseudo carbon]

Point B

[desert juniper]

you're now at B, and you move AF. where are you now?

[pseudo carbon]

O

Move again? To reach E right?

[desert juniper]

you're at O, and move AF again

[pseudo carbon]

Yeah so E now

[desert juniper]

so you're now at E, correct

so what was your total movement?

[pseudo carbon]

Yeah so AE make sense now

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[wet frost]

$x^2 - (2a + 5)x + a^2 + 3a = 0$

[flat frigate]

asm

[wet frost]

Find all values of a so that the equation's product of roots = 4

I found that when a = 1 the product of roots is 4

But not sure how I can find every value

[quick crater]

do you know vieta?

uhh lemme find the actual name of it

[wet frost]

Yea

[vagrant ice]

Vieta's formulas, sum and product of roots

[wet frost]

Yea I do

[vagrant ice]

so that means a^2 + 3a = 4

you can solve this quadratic!

[wet frost]

Let me think this through really quick

You surely get the answers, but I don't get why we make it equal to 4

Is it because a^2 + 3a is considered a constant?

$x^2 - 2ax - 5x + a^2 + 3a$

[flat frigate]

asm

[wet frost]

From what I see, we treat it as a constant

So that c/a = 4/1

[quick crater]

yes

[wet frost]

Alright

thanks for the help 👍

.close

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[vagrant ice]

yes, a^2 + 3a is the term independent of x

so it is the constant

[wet frost]

Yea I see, it was cool to spot that

[vagrant ice]

if you had a quadratic in a, so where you had say 2a^2 + ...
that's a different story

[safe radish]

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[abstract mountain]

help

[abstract mountain]

If ${2x^{\frac{1}{4}}} - {2x^{-\frac{1}{4}}} = 3$
find x

clue : Let ${x^{\frac{1}{4}}}$ \to t

[flat frigate]

someone.
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[abstract mountain]

so does x^-(1/4) is -t?

[junior raven]

nope

what does the negative exponent mean

[abstract mountain]

oh wait no irealisez

[abstract mountain]

ohh

the 2^-3 = 1/2^3?

so

x^-1/4

= 1/t?

soo 2t - 2/t = 3

[junior raven]

yup

[abstract mountain]

aight whats the next step

[junior raven]

you tell me

[abstract mountain]

wait

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[abstract mountain]

.reopen

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✅

[abstract mountain]

@junior raven ill dm u, gtg

[junior raven]

stay in the server

i can respond here

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[fiery obsidian]

Hello can someone help me for this exercise, I don’t understand nothing 🙁

[azure delta]

Do you understand what 1a is asking?

[fiery obsidian]

No

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[dawn hedge]

why did we use midpoint here?

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[stone barn]

Hi I’m trying to do question 1b and I’m not sure what the bounds would be cus I know for the first equation it would be 6 to 8 but not sure about the other one

[gilded vault]

the other one would be from 0 to 6, but since itt is below the x-axis it would be negative

so you can either think of it as

[stone barn]

Alright

[gilded vault]

$\int_6^8f(x)-\int_0^6f(x)$

or

[flat frigate]

Arnavutköy

[stone barn]

So the equation would be negative then

?

[gilded vault]

$\int_6^8f(x)+\int_6^0f(x)$

[flat frigate]

Arnavutköy

[gilded vault]

yes you negate the integral since it is below the x-axis

[stone barn]

Ok thank you

This I what I done for the first one, does it look right?

Just realised I forgot to write the little dx for the integral

[flint fiber]

Are you referring to the left triangle?

[stone barn]

Yes

[flint fiber]

You're partially correct but it should be int from 0 to 6 of (0-(x-6))dx

[stone barn]

What do you mean?

Ohhh

Okay

Is my answer correct or is that wrong too

[flint fiber]

Its supposed to be like this

Its important to use strips so you wont be confused

[stone barn]

Okay got it ty

[flint fiber]

And then just add it to the integral of the other triangle then you're done

[stone barn]

Im doing the right triangle but it doesn’t look right , I think I done something wrong idk what

[flint fiber]

6² is 36 and divide it by 2 will result to 18

Then 18-36 is -18

-16 - (-18) = 2

[stone barn]

Ohh yeah

[flint fiber]

What did you get on the first triangle?

[stone barn]

For some reason I got -54

[flint fiber]

My mistake here, you are correct. Though the answer would only differ by a sign

You should get -18

[flint fiber]

This is correct but you only made a mistake in squaring 6

[stone barn]

Is it 18

[flint fiber]

It should be like this

[stone barn]

Whys it negative

[flint fiber]

I made a mistake on writing the integral, yours was correct

[flint fiber]

And it should logically be negative since it is below the x axis

[stone barn]

Oh yeah I know

It’s just when adding it together it’s supposed to be positive that why I’m asking

Since u can’t have negative area

At least that’s what I was told

[flint fiber]

So the answer should be -18+2 = -16

[flint fiber]

Geometrically, its not possible to have a negative area. In integration, having a negative area only means that most of the region are found below the x axis

[stone barn]

I mean the textbook says the answer is 20

Just confused on how I’m supposed to get 2

From the other one

[flint fiber]

If that's the case, then your textbook literally 'takes' the value of the area so technically speaking, the first triangle has 18 as its area and triangle 2 hand 2 as its area, combining that will result to 20

[flint fiber]

From the other triangle, weve already solved that its area is 2

[flint fiber]

This

[stone barn]

Ohh okay

Im gonna try c

[flint fiber]

Sure, goodluck

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[icy crypt]

Hey what needs to change to the kalman matrices if i also want a smoothed version of x_k-1|k

[obtuse plover]

bro im sorry this cant be math

[icy crypt]

.close

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[lean otter]

what did i do wrong here?

Force X has a magnitude of 1230lb, and force y has a magnitude of 1480lb. they act on a single point at an angle of 45° to each other. find the magnitude of the equilibrium and the angle between the equilibrium and the 1230 lb force.

i got the magnitude correct at 2505.5, but the angle incorrect, stating 24.7° when it was supposed to be 155.3°

[icy lance]

thats fine, its just the obtuse angle between them

you have the acute one between them

no problem there

[lean otter]

so what i should’ve done is taken the angle i got from my calculation and subtracted it from 180 to get the obtuse angle

but im confused on how i should know whether it’ll be an obtuse or acute angle for the correct answer

[icy lance]

either is fine in my opinion unless it asks for specifically the obtuse or acute

[lean otter]

it didn’t ask it only said to find the angie between the two

[icy lance]

then you dont need to worry about which one

24.7 is alright

[lean otter]

but it was marked incorrect

[icy lance]

on what?

[lean otter]

on the sample test i took

[icy lance]

mathematically, youre fine with either, if they wanted to obtuse one they should really say that

on a proper paper it would be specified if wanted

you could probably contest that if it really came up honestly

[lean otter]

i’ll just take it into account of the test. thankfully it’s unproctored so i can refer to my notes and the questions are the same with substituted numbers

i’ll just have to remember to subtract 180 from the answer i get

[icy lance]

or write both if its dubious

but any decent marker should accept it

[lean otter]

thanks for the help

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[rain dagger]

how do i do binom in word

[rain dagger]

\binom{n}{2} no work

[rustic goblet]

,, \binom{n}{k}

[flat frigate]

fallenstars

[rustic goblet]

you need the amsmath package

[plucky elk]

https://letmegooglethat.com/?q=binomial+coefficient+Microsoft+word

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[short niche]

hello, i need held with a polynom division, f(x)=x^3+4x^2+x-6

[plucky python]

what are you trying to divide this by

[short niche]

thats the problem my teacher didnt give me anything

i have to factorise it

[plucky python]

ah ok

by the rational root theorem, you should test all of the (positive and negative) divisors of 6

[short niche]

like 3 and 2 and 1?

and the negavtives of that

thank you so much

have a nice night

.close

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[sinful stump]

Hello can i get help with a math question it has me stuck

[sinful stump]

A doctor places an overweight man on a strict diet to reduce his weight from 200 kg to 80 kg. If he loses 3% of his weight every week, how long will it take him to reach his target weight.

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[rigid gazelle]

i need help with something please

[safe radish]

Please don't occupy multiple help channels.

[shell badge]

Why do you have 2 channels dawg

Close this one

[plucky elk]

.close

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[devout tinsel]

Help need with fractions ( never learned them since i've been out of school for 6 years )

[icy lance]

anything specific?

[devout tinsel]

i just need to know the basics

[icy lance]

https://youtu.be/GvLIEiqxS6s?si=LA7JtvXI4Bh9ZD18

perhaps this?

[devout tinsel]

heres something else..

how do i find a fraction as a decimal?

[icy lance]

that would go into division methods

eg 1/2 is 1 divided by 2, which is 0.5

i can get you another video for that though, theres a method called the 'bus stop method' though i dont know if thats its official name

[devout tinsel]

i just need to know something because i heard pre-algebra is mostly fractions and halves and stuff

[icy lance]

https://youtu.be/pDs4a4ijqh0?si=zLYVtTzaSo7EfXsx

this covers the method i mentioned

though it writes it a bit differently than i do

[devout tinsel]

wait

whats the thing for uneven fractions isn't it keep change flip?

[icy lance]

please dont tell me you mean mixed numbers

ill start crying

[devout tinsel]

i dont know im confused aswell but i dont know how to do fractions because of how i've been taken out

[icy lance]

are you speaking about how you can (evilly) write something like 5/2 as 2 1/2

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@devout tinsel Has your question been resolved?

[devout tinsel]

i need to watch videos

that u sent me

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[devout tinsel]

.close

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[sour plume]

I can't seem to figure out how to continue on with this question:
Let ABC be an acute scalene triangle with orthocentre H. The altitudes from B and C intersect the angle bisector of ∠BAC at D and E respectively. The tangents to the circumcircle of triangle DEH at D and E intersect at X.
Prove that BX = CX.

[sour plume]

This is the diagram that I have

<@&286206848099549185>

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[sour plume]

I think I might as well close the channel atp

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[scarlet elbow]

$x^2 -7x + 6 = 0$

[flat frigate]

Simon James B

[scarlet elbow]

i tried to solve this but i am doing something wrong

so here we can calculate delta right?

[gentle edge]

What happened?

I need to find value of x?

[scarlet elbow]

yes

by using Δ

[gentle edge]

Oh

[dapper nacelle]

you could factorise too

[gentle edge]

Nvm I don't know that

[scarlet elbow]

no problem

[scarlet elbow]

yes but i am asked to use Δ

[dapper nacelle]

by delta you mean the discriminant right

[scarlet elbow]

yes that is the discriminant

[dapper nacelle]

yea that'll work

[scarlet elbow]

$Δ = b^2 + 4ac$

right?

[flat frigate]

Simon James B
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dapper nacelle]

b²-4ac

[scarlet elbow]

OH

here is my mistake

i said it is + not - so my delta was 73

Δ = $b^2 - 4ac \newline 49 - 24 = 25$

[flat frigate]

Simon James B
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[dapper nacelle]

looks alright

[scarlet elbow]

ok

now we find x1 and x2?

[dapper nacelle]

yes

[scarlet elbow]

x1 = -b + square root delta/ 2a ?

[dapper nacelle]

yep

[scarlet elbow]

and x2 = -b - square root delta /2a

so x1 = (7+5)/2 = 6

x2 = (7-5)/2 = 1

[dapper nacelle]

yea thats right

[scarlet elbow]

oh

My mistake was in the formula lol

thanks

.close

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[rustic dawn]

im trying to workout question 1b, and i dont think my proof is correct, i think i made a mistake but im not sure how to prove it correctly. Does anyyone know how to prove it?

[rustic dawn]

<@&286206848099549185>

[hardy monolith]

!15m

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[rustic dawn]

<@&286206848099549185>

damn im so cooked

[hardy monolith]

!show

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[forest sequoia]

Hi, can someone explain me how we got the two inequalities please?

Where E([a,b],R) is the set of the step functions

[plucky elk]

how do you define integral

[forest sequoia]

like this

where Ck is the value of phi on ]Xk-1 ; Xk[

[forest sequoia]

Is it correct?

[peak estuary]

draw a picture

[forest sequoia]

a picture of what?

[peak estuary]

two step functions

[forest sequoia]

like that?

[peak estuary]

yes

and now compare areas

[forest sequoia]

you mean which functions has the biggest area?

[forest sequoia]

i don't understand where it's going

[peak estuary]

integrals are essentially areas, yes?

[forest sequoia]

yes

[peak estuary]

what function are you integrating on the left

what area do you get

is it less area than if you integrated the red or green function on their own?

[forest sequoia]

i will pick the red one

i think

[forest sequoia]

the green function has the biggest area no?

[peak estuary]

the red function is sometimes higher than the green one

(remember that below the x axis means that the area counts as negative)

[forest sequoia]

Yes, sorry

So the bigest is still the green one no?

I mean if we suppose that they both goes to infinity

[peak estuary]

you are integrating from a to b

anyway, the point isnt about red vs green

its about red and green vs min(red,green)

[forest sequoia]

i feel stupid

i don't get it

the biggest aera is the red here, no?

[peak estuary]

can you draw in another color the function min(phi,psi) ?

[peak estuary]

if you now compare black vs green, which has bigger area?

what about black vs red

[forest sequoia]

the black has always the smallest aera, no?

[peak estuary]

yes

[forest sequoia]

just like what we want to prove

[peak estuary]

and thats what the first inequality is saying

[forest sequoia]

yes

but how can we prove it formally?

[peak estuary]

write down phi and psi both as linear combinations of the common intervals

and frankly after that just write it out

[forest sequoia]

honestly I dont know how to do that

but anyway thank you for your help!

.close

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[peak estuary]

so you have x_i for phi and y_i for psi

define z_i which are where min(phi,psi) changes from one to the other

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[lucid trout]

why he consider in the last phrase points when x + y = n, if the question don't even say that these points are going to be coloured?

the question only says that points (x,y) such that x + y < n are going to be coloured

or am i wrong?

[brave wolf]

It's okay

it's proof by induction

at that point, they're proving it for n + 1

so at that point, all points (x, y) such that x + y < n + 1 are colored

and that includes x + y = n, which is basically the edge of colored triangle

[lucid trout]

hmm i think i got it

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[last snow]

What would be the appripriate symbol of "Samanlogd tidni?"

[final loom]

Σf

And the first entry should be 1 not 2

[last snow]

that is 40

[thin bridge]

cf

[last snow]

@thin bridge but hlutfallstidni tidni?

[final loom]

f%

[last snow]

but samanlögð hlutfallstíðni?

@final loom @thin bridge

<@&286206848099549185>

[final loom]

Cf%

[last snow]

.close

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[deft solstice]

hi, i have a quick theoretical question.
is it possible to determine the steepness of the curve by just finding the secant and drawing a paralel?
in this image i mean the secant between p1 and p2

German help would be much appreciated, though i'll understand english

[autumn kite]

the steepness of the curve varies

[deft solstice]

i mean it like this if it help to understand my perspective

ask me questions for more info if it helps you help me

[autumn kite]

if h is very small
its basically slope of the curve at the point x

[pure agate]

It seems like you are asking about the Mean Value Theorem.

[deft solstice]

i mean if you keep getting closer to the middle point going paralel to the secant, you will eventually touch the curve

is that touching point the slope?

[autumn kite]

if the points are very close to each other, it becomes a tangent

[deft solstice]

oooh

[autumn kite]

and hence the slope of the curve at that point

[deft solstice]

yeah makes sence

[queen ingot]

you need to take a limit though
if you just choose a secant, it could have a different slope

[queen ingot]

this one is parallel, but if you choose another secant it won't be parallel

[deft solstice]

okay thanks, i was basically asking how to approach a tangent and didn't see it

bruh

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[visual swan]

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[timid yew]

If f(x) = (1-x)/(2x) and (f • g)(x) = 7x, then g(x) is...

[timid yew]

How to find g(x)

[plucky python]

you could plug in g(x) for x and then solve the equation (1-g(x))/(2g(x))=7x for g(x)

[timid yew]

Thanks

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[ember haven]

from the data all i could think for an approach was to take a=2sinx

[runic tinsel]

instead of giving a counterexample for AB

i took the transpose of AB which is just BtAt, and since Bt = B and At = A, so traponse of AB = BA

and then I said BA may or may not equal AB

because commutative property doesnt exist for matrices

is my proof right? or should I tackle this with counterexample

[ember haven]

bro this is occupied

[runic tinsel]

we clicked on the same time lmao

[ember haven]

copy this to another channel

[runic tinsel]

ye

[loud wren]

huh?

which one of you needs help here?

[runic tinsel]

we clicked on the same time

he can go first its fine

[loud wren]

lmfao

[ember haven]

this

[loud wren]

why is it saying sum of a

aren’t there 5 variables

[ember haven]

it means a+b+c+d+e

its the notation

[loud wren]

that’s not good notation

anyways

[ember haven]

yeah

this reminds me of complex numbers

but i cant think through it

[loud wren]

there is some statistics here

i need to rack my brain

[ember haven]

stats???

<@&286206848099549185>

ong 😭

aint gettin no help today 😭

.close

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[loud wren]

this comes directly from the fact that they're equal diagonals, no?

its some theorem im forgetting

yeah

maybe with a contradiction.

assume that ABCD is isosceles and prove that it cannot be possible for this trapezoid to not be isoceles

this makes the most logical sense

[azure delta]

There's no point to that. If you can do that, you can prove it directly.

[loud wren]

i was just proposing something

[azure delta]

Fair enough

[queen ingot]

let the center be P

triangle ABP is similar to triangle CDP

you should be able to show they're isoceles

i think

[azure delta]

Yeah because BP+kBP=AP+kAP

For proportionality constant k

As soon as BP=AP, you can SAS as you wanted from the beginning

[queen ingot]

i have spoilers

do you want hints?

[azure delta]

Each of those is one of the two diagonals

[queen ingot]

oh yeah that works

you can do it this way too

[flat frigate]

lin.fei

[queen ingot]

yes

[flat frigate]

lin.fei

[queen ingot]

👍

what's cpct?

ok

sounds good

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[lofty wadi]

anyone mind explaining how this works?

[torpid fable]

Is there a given polynomial?

seems like some context might be missing

[torpid fable]

For this method of factoring we are making a guess that $5x^2+14x-3=(ax+b)(cx+d)$ for some integers $a,b,c,d$. If this is the case then we have $5x^2+14x-3=(ax+b)(cx+d)=acx^2+adx+bcx+bd$. This must mean we have $5x^2 = acx^2$ which implies $5 = ac$ and $-3 = bd$. Since we are guessing that $a,b,c,d$ are integers we look at how 5 and -3 can factor into integers. Then we basically just check all possible combinations until one of them works.

[flat frigate]

謎の男

[torpid fable]

If it is not of that form then too bad so sad and you need to use a different method

[lofty wadi]

what other methods can i use? 😭

[oak coral]

Do you want to know how to factorize this polynomial?
First multiply the coefficient of x^2 with the constant number.
In this case, 5x-3=-15.
Now, you have to find two numbers such that their product will be -15 and sum will be 14.
The two numbers are 15 and -1.
15x-1=-15 and 15+(-1)=14.
So,
5x^2+15x-1x-3
Take the common factor out.
5x(x+3)-1(x+3)
(5x-1) (x+3)

[torpid fable]

Completing the square or the quadratic formula work no matter what

[oak coral]

Yup.

[torpid fable]

but this method is good for being quick and also just shows why factorization of integers is a useful tool

[oak coral]

Quadratic formula would be the easiest option.

[lofty wadi]

omg wait i genuinely understand now

i just had to like sit and think for a minute

tysm

[oak coral]

<3

[lofty wadi]

@oak coral Sorry for bothering again, what would you mean by taking out the common factor?

[oak coral]

The multiplication sign and X looked the same so I wrote it down.

You write the common factor outside the bracket and remaining stuff inside.

You can check if it’s correct by multiplying it.

[lofty wadi]

omg actually tysm

[oak coral]

You can check if your common factor was correct by multiplying again.

[lofty wadi]

that actually makes it so much easier and digestable

[oak coral]

I think you’ll understand better if you look up a video on how to factorize quadratic polynomial.

[lofty wadi]

ill def look into it

ty!!

[oak coral]

No probbie! <3

[safe radish]

@lofty wadi Has your question been resolved?

[safe radish]

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[hexed igloo]

hi

[hexed igloo]

can somon help maxima minima two variablesd

[low canyon]

!da2a

[safe radish]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[hexed igloo]

i need esxplaination

dont bot a speciic question

[viscid gyro]

Are you talking about how to find maxima or minima on a function?

[hexed igloo]

yea

[viscid gyro]

https://byjus.com/jee/maxima-and-minima-in-calculus/

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@hexed igloo Has your question been resolved?

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[lean otter]

What is happening to me today😣😅. Someone help me again pls

[safe radish]

Show your work, and if possible, explain where you are stuck.

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[lean otter]

I don’t know where to begin

I don’t get it??

[final loom]

The inverse of composition? Or how to use the Hint

[lean otter]

The what now?

[final loom]

Nvm that

In the question, it says: h(x) = fg^{-1} (x). Do you know how to compute inverse of g(x)?

[lean otter]

Is the inverse like divide by 2 and minus 1?

[rich elm]

i think some ppl call it an analytical form of g(x)? (im not rly sure if thats the universal term)

[lean otter]

I know inverse of f(x) is minus x divided by 2 minus 1

[final loom]

Yes

So what's the inverse of g(x), following the same method you did to find inverse of g(x)

[lean otter]

Minus x^2 / 2 -1 ??

[final loom]

No no

[lean otter]

oh

[rich elm]

can you show your working?

[lean otter]

Well I don’t understand the question itself

Ok actually, give me a mins I’ll try something

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[earnest rain]

,rccw

[earnest rain]

This is not the result im supposed to get

Should be 7/48etc

[final loom]

!original

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[earnest rain]

Asks to calculate the volume of it

[hard crest]

doesn't it ask for the centroid?

[final loom]

It says to not use integrals

Try to realize what solid it is