help-23

[safe radish]

Channel closed

Closed by @halcyon light

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bleak sandal]

11b

I did this

[royal kiln]

,rotate

[bleak sandal]

11ei

Mean

So sorry it's 11e

[royal kiln]

Rotate your images, man

,rotate

[bleak sandal]

So sorry

[bleak sandal]

,rotate

[thin bridge]

express sin(theta) in terms of x

[bleak sandal]

But isn't it wrong

[thin bridge]

isn't what wrong

[bleak sandal]

Like it's not the same as ans key

[thin bridge]

did you

express sin(theta) in terms of x

your expression isn't in terms of the original varialbe
so work is incomplete

[royal kiln]

I got (1/4)sin(arctan(x/2)) + C

Not sure how to make that look like your posted solution

Oh...hmm

[thin bridge]

draw a triangle

[safe radish]

@bleak sandal Has your question been resolved?

[royal kiln]

@bleak sandal

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[clear tiger]

it is (1,3) and 2root5

[obsidian oracle]

do you want your answer to be checked?

[clear tiger]

yea to see if im doing it right

[faint seal]

Yes that’s right

[clear tiger]

k thank you

also

apart of the same question

is (3+7)/(1+3) right to get the gradient

[obsidian oracle]

when you got (x-1)^2 + (y-3)^2 = 20 I directly go for (x-1)(3-1) + (y-3)(7-3) = 20

to get the equation of tangent

So I think gradient is rather (3-7)/(1-3) if you were going for it

[clear tiger]

ah ok

and that gradient would be for the normal?

so reciprical it to get gradient for tangent

[obsidian oracle]

yeah

[clear tiger]

does it matter if its (3-7)/(1-3) or (7-3)/(3-1)

[obsidian oracle]

but I think " (x-1)(3-1) + (y-3)(7-3) = 20" is already the equation the question wanted

[obsidian oracle]

+/+ or -/-, choose

they're both positive

[clear tiger]

sorry could you explain that a bit more

[obsidian oracle]

well

what's the difference between 4/2

and -4/-2

[clear tiger]

so aslong as i use the same signe for both its fine

but i get diffrent gradients doing (3-7)/(1-3) and (3+7)/(1+3)

[obsidian oracle]

well yeah

you gotta subtract x to the center of the circle

and same for y

you either do 3 - 7 or 7-3

but you gotta find the difference of coordinates between the center of the circle

and the point where the tangent goes through

that's for the normal

then the gradient for tangent is -1/what you found

[clear tiger]

ah

so only - not +

[obsidian oracle]

yeah

[clear tiger]

makes sence now

thank you

🫡

.clos

.close

[safe radish]

Channel closed

Closed by @clear tiger

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[edgy vine]

would love some help on this i am very stuck

[obsidian oracle]

do you know the formula for n choose k?

[edgy vine]

yes

the one with factorials?

[obsidian oracle]

yeah

[edgy vine]

i am unsure how to maniplulate them to get this however

[obsidian oracle]

start with writing the formula and we'll try to see how we can transform it

[edgy vine]

i am quite confused on what to do next

[obsidian oracle]

so

if you write the factorials as a product

like 5! = 5*4*3*2*1

[edgy vine]

yeah

[obsidian oracle]

check out how n! and (n-k)! cancel some of their terms together

and what are we left with

[obsidian oracle]

?

[edgy vine]

is this what you meant

[obsidian oracle]

no I don't think so

just write for example

[edgy vine]

im a bit confused on how things will cancel out

[obsidian oracle]

n! = n(n-1)(n-2)...(n-k+1)(n-k)(n-k-1)...2*1

and (n-k)! = (n-k)(n-k-1)...2*1

[edgy vine]

ahhhhhhh i see

[obsidian oracle]

so what are we left with when we do n!/(n-k)!

[edgy vine]

is this correct

hello?

@obsidian oracle im still a little confused

[obsidian oracle]

the last line is correct

it's exactly this

so every factor of the numerator looks like n-j where j is between 0 and k-1

all we need is to argue why n-j is equivalent to n

and use product rule with equivalences

[edgy vine]

whats product rule with equivalences

[obsidian oracle]

if a ~ b and c~d, then ac ~ bd

[edgy vine]

ah ok

[obsidian oracle]

so for example

n+1 ~ n

1/(n+2) ~ 1/n

so (n+1)/(n+2) ~ n/n = 1

[edgy vine]

im still confused on where the n^k will come from

ahhhhh wait i got it

@obsidian oracle i have the n^k/k! part but where then does the bit inside the brackets come from \

hello?

.close

[safe radish]

Channel closed

Closed by @edgy vine

Use .reopen if this was a mistake.

[obsidian oracle]

equivalence is the same as

f ~ g is defined as f = g + o(g)

[edgy vine]

ahhhh

[obsidian oracle]

of course

you can develop the product

like

you will get (1 + o(1)) if you do equivalences

but if you want (1+ O(n^-1))

it would be better to write n(n-1)(n-2)...(n-k+1) and expand

to see that it's n^k + ...n^(k-1) + ...

so it's n^k + O(n^(k-1))

[edgy vine]

ah ok

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split moss]

If $\alpha = 30$ degrees and $\beta = 45$ degrees and the masses are equal, friction equal, which block is moving?

[flat frigate]

Baby Einstein

[knotty pier]

If one moves then other also moves

As they are connected by string

[split moss]

Yes, but depending on the data I have, which one moves first

The angles are different, maybe one should move first

[lime dust]

I think you want to ask, towards where the masses move?

[split moss]

Yes

[knotty pier]

Where do u think there is more force?

[split moss]

Where is the angle 45°?

Idk

[knotty pier]

Yes

And y do u think so?

Try resolving the weight vector

[split moss]

Do the tensions have to be the same?

[knotty pier]

Yes

Same string

So same tension

[safe radish]

@split moss Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith parcel]

Two crickets, Adonis and Basilio, always jump forward; Adonis only jumps 1 cm or 8 cm and Basilio only jumps 1 cm or 7 cm. They cover any distance in as few jumps as possible. For example, Adonis covers 16 cm with just two jumps of 8 cm each, while Basilio needs four jumps, two of which are 7 cm and the other two are 1 cm. On the other hand, to cover 15 cm, Adonis needs eight jumps, one of 8 cm and seven of 1 cm, while Basílio needs only three jumps, two of 7 cm and one of 1 cm. Indicating by A(d) and B(d), respectively, the number of jumps that Adonis and Basílio take to cover d centimeters, we have A(15) = 8, B(15) = 3, A(16) = 2 and B(16) = 4.

[wraith parcel]

question :

Find the largest number d such that B(d) = A(d).

Don't worry about the words, it is portuguese but doesn't matter

i am struggling with this

What happened

[lean otter]

p = 8p/8

q = 7q/7

[dreamy elk]

$$\frac{d-p}{8}+p = \frac{d-p}{8} + \frac{8p}{8} = \frac{d-p+8p}{8}=\frac{d+7p}{8}$$
similarly with $\frac{d-q}{7}+q$.

[flat frigate]

Crystopher

[wraith parcel]

hmm, i didn't understand very well

where did this 8p/p come from

i thought it would be like p/1

[dreamy elk]

$p = 1\cdot p = \frac{8}{8}p = \frac{8p}{8}$

[flat frigate]

Crystopher

[wraith parcel]

ok

gotcha

[wraith parcel]

so that is what is called algebraic manipulation

[dreamy elk]

or just plain old fraction addition/subtraction.

[wraith parcel]

alright then

[wraith parcel]

but that is weird because I could do 9/9 too instead of 8/8

in the end would be the same thing?

[dreamy elk]

yes and no, we pick $\frac{8p}{8}$ since the denominator in $\frac{d-p}{8}$ is 8, when adding/subtracting fractions we look for their common denominator, when adding $ \frac{d-p}{8} + \frac{8p}{8}$ the common denominator is 8, so the sum is easily performed. If we instead pick $\frac{9p}{9}$ it should still be the same thing but the process becomes harder than it needs to be:
$$ \frac{d-p}{8} + \frac{9p}{9} = \frac{9}{9}\cdot\frac{d-p}{8} + \frac{8}{8}\cdot\frac{9p}{9} =$$
$$\frac{9(d-p)}{9\cdot 8} + \frac{8\cdot 9p}{8\cdot 9} = \frac{9d-9p)}{72} + \frac{72p}{72} =$$
$$\frac{9d-9p + 72p)}{72} = \frac{9d+63p}{72} = \frac{9d}{72} + \frac{63p}{72} = \frac{d}{8} + \frac{7p}{8} = \frac{d+7p}{8}$$

[flat frigate]

Crystopher

[wraith parcel]

ohh that really makes sense

awesome

that's all, thank you

have a great day

.close

[safe radish]

Channel closed

Closed by @wraith parcel

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grave ridge]

Why does it give me a plane in x,y if it wants me to find the image of S

oh because its asking to find S under the given transformation so its really asking for R

.close

[safe radish]

Channel closed

Closed by @grave ridge

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[olive vault]

calculate the limit:

[empty gyro]

What is q?

[olive vault]

a rational number

[empty gyro]

Can it be 0?

Can't it be negative?

[olive vault]

yes any rational

[safe radish]

@olive vault Has your question been resolved?

[olive vault]

.close

[safe radish]

Channel closed

Closed by @olive vault

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse lichen]

^

[safe radish]

Channel closed

Closed by @patent gazelle

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sinful iris]

How do i approach this?

[somber stream]

Take log both side

[sinful iris]

i did

then log(10) is 1

right?

[terse lichen]

is it log(x+1) or log(x) + 1

[sinful iris]

log(x+1)

[terse lichen]

assuming the same for log(x+7)?

[sinful iris]

yup

i mean that's in parenthesis so

log(x+7)/4

[terse lichen]

could be (log(x) + 7) / 4

[sinful iris]

answers are 10 and 0,0001

says the book

so whichever gives that, i just dont know how to go on

[terse lichen]

hmm

[terse lichen]

the 4 isnt inside the log yeah?

[sinful iris]

i dont think so

[terse lichen]

right

damn how do you even solve this

[sinful iris]

lmao

i tried photomath and it gives me the graph

😭

[terse lichen]

you sure 10 and 0.0001 are the answers?

cause i tried plotting every single possibility and dont see it

[sinful iris]

i mean there's a possibility the book got it wrong

[terse lichen]

not gonna lie the notation is kinda garbo

[sinful iris]

how did you solve it

[terse lichen]

go on desmos lol

then plot the graphs and look at the intersections

[sinful iris]

oh oh

it gave me

the answer

i was wrong

it's log(x) + 1

and the other one is log(x)+7 / 4

[terse lichen]

oh lol

then yeah it should be pretty easy to solve

just a quadratic equation

[sinful iris]

yup

i got it

ty

[celest edge]

Hello

[sinful iris]

.close

[safe radish]

Channel closed

Closed by @sinful iris

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[safe radish]

@worldly mango Has your question been resolved?

[quiet plume]

I assume $\cong$ means congruent.
Remember that SAS means that we know the triangles have two sides with the same length, with an equal angle between them.

Is that the case for the first problem? What sides do these triangles have in common, if any?

[flat frigate]

Azyrashacorki

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly mango]

.close

[safe radish]

Channel closed

Closed by @worldly mango

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hasty oasis]

Hi how to do this https://cdn.discordapp.com/attachments/1022663861637238794/1259753131332603914/Screen_Shot_2024-07-07_at_11.09.01_PM.png?ex=668cd407&is=668b8287&hm=7a374cdddb037c9aec0f2b76ffb6623394da31533449c463420d12b080c76160&

[hasty oasis]

this is solution https://cdn.discordapp.com/attachments/1022663861637238794/1259753205403877437/Screen_Shot_2024-07-07_at_11.09.20_PM.png?ex=668cd419&is=668b8299&hm=79aa16065e62e46712337f12ea70253e4ee38f7ea07da239920ee9dc187b7b91&

[safe radish]

@hasty oasis Has your question been resolved?

[hasty oasis]

fuck no

so useless

.close

[safe radish]

Channel closed

Closed by @hasty oasis

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[edgy vine]

hello could i please have help with part e, i have done the other parts

[edgy vine]

this is what i have done so far

.close

[safe radish]

Channel closed

Closed by @edgy vine

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brittle badge]

DC = CF
ABCD Is a parallelogram
Prove that BG:BC = 2:3

[brittle badge]

Hey guys, So I figured out that CBA Is congruent To BCF, CBA Is congruent To ADC, BFC is congruent To ADC

So AD = BC = BF

CF = CD = BA

But now I am stuck, How can I prove that BG:BC = 2:3?

[safe radish]

@brittle badge Has your question been resolved?

[brittle badge]

<@&286206848099549185>

[nova forum]

it is not enough that ABCD is a parallelogram, is it not stated that the triangles it is made up of are regular

2.11/3.16 = 0.6677215

@brittle badge

[brittle badge]

mhm

what am I seeing here

[nova forum]

same diagram but different dimensions to show that the triangles have to be regular

[brittle badge]

what you mean regular?

like equal to congruent other?

[nova forum]

all sides of equal length

[brittle badge]

oh

right

but its not stated

[nova forum]

well it should be

[brittle badge]

wait so what should I do?

[nova forum]

do we know trig

[brittle badge]

trig?

oh

no

[nova forum]

so just ratios

[brittle badge]

by similar triangles?

[nova forum]

well whatever we can find using that yes

CE * 2 = BF

[brittle badge]

how did you know that?

[nova forum]

ratio pairs inside the BDF triangle

[brittle badge]

mhm

[nova forum]

or since DE connects two regular triangles' points it halves their bases

[brittle badge]

But what does DE has to do with BC And BG?

[nova forum]

EF defines BG

[brittle badge]

oh right

[nova forum]

so we need to show where E is on AC

[brittle badge]

alright

whats the next step

[nova forum]

look at trapezoid EBFC

[brittle badge]

is it a trapezoid?

but cf is parallel to be?

[nova forum]

by regularity of the triangles, they give parallel lines, otherwise we wouldn't be able to assert the ratio pairs to show that

[brittle badge]

right

[nova forum]

what do you know about the diagonals of that trapezoid

how do you get to know something about them

[brittle badge]

That they are equal

Oh but only in isosceles trapezoide

[nova forum]

not from just being a trapezoid no

[brittle badge]

oh really

[nova forum]

we can calculate the length in relation to BF

[brittle badge]

wait so the diagonals are equal?

[nova forum]

they aren't

[brittle badge]

oh

right

[nova forum]

do you know how to get BE as a ratio of AB

[brittle badge]

no

[nova forum]

pythagorean

[brittle badge]

oh

right

x:2?

did you get it from the pythagorean?

[nova forum]

that is from ABCD being a parallelogram

[brittle badge]

oh right AC = X so AE = X:2

[nova forum]

its diagonals halve each other

[brittle badge]

Yeah

[nova forum]

so calculate BE

[brittle badge]

alright

root 3x:2?

@nova forum

[nova forum]

root(3)/2 * x

x is outside the root

[brittle badge]

oh

[nova forum]

now here

[brittle badge]

So eb = BF

[nova forum]

no BF = AB

[brittle badge]

Now do the same thing

oh

[nova forum]

from the regular triangles again

[brittle badge]

mhm

[nova forum]

so calculate EF

[brittle badge]

alright\

mhm

Wait the Pythagorean is root(3)/2 * x + x squared = EF squared right?

or root(3)/2 * x +EF squared = X squared

Where is the 90 degrees at?

[nova forum]

all 3 are squared by default, you want one side to be not squared so the other side ends up being two squares under a square root

[nova forum]

right angle is at B

[brittle badge]

So it isn't right

[nova forum]

no

[brittle badge]

wdym one side to be not squared

[nova forum]

(root(3)/2 * x)^2 + x^2 = EF^2

you take the root of both sides

sqrt(EF^2) = EF

[brittle badge]

yeah

[nova forum]

sqrt((sqrt(3)/2 * x)^2 + x^2) = EF

[brittle badge]

alright i will calculate

how can you even calculate sqrt((sqrt

[nova forum]

it is squared first

[brittle badge]

What should i do at this point

wdym?

[nova forum]

(sqrt(3)/2 * x)^2 = 3 * x^2 / 4

care for the parentheses

you take the root of the whole left side

[brittle badge]

Wait what with the EF?

You stated it for X?

[nova forum]

ratios yes

[brittle badge]

Oh

[nova forum]

but there is a different approach if you know about similar triangle rules

[brittle badge]

I know more about similar triangle

[nova forum]

okay then we use that instead

[brittle badge]

Alright

Yeah

[nova forum]

consider those

[brittle badge]

Ok BGF = EGC

Like g1 = g2

And

mhm

[nova forum]

if two triangles are similar and we know the ratios on one side pair then we know it for the others

EC * 2 = BF

[brittle badge]

Yeah

[nova forum]

from ABCD being a parallelogram

[brittle badge]

Yeah

But its not helping

[nova forum]

so CG : BG = ?

it is

[brittle badge]

How?

[nova forum]

same ratio as EC : BF

because they are similar

the triangles

[brittle badge]

But we don't know that they are similar yet

We need to prove it

[nova forum]

they have an equal angle

at G

[brittle badge]

Yeah

[nova forum]

you know that

[brittle badge]

But we need one more

Yeah

[nova forum]

and CE and BF are parallel

[brittle badge]

Yeah

Ohhh

[nova forum]

so every angle is equal

[brittle badge]

Yeah

[nova forum]

and we got there

[brittle badge]

I forgot that they are parallel

Okay so

[nova forum]

ABFC is also a parallelogram

[brittle badge]

Yeah

And ABCD

[nova forum]

yes

so ratio of one side is 2 : 1

so it is the same for the rest

[brittle badge]

Right

[nova forum]

consider BC

[brittle badge]

2:1?

[nova forum]

CG * 2 = BG, as we just proved

so BC = CG * 3

[brittle badge]

How

But you said

CG * 2= BG

OHH

BC

[nova forum]

BC = CG + BG

[brittle badge]

Yeah

[nova forum]

with those two you have the ratio you wanted

[brittle badge]

Yeah

2:3

right

thanks @nova forum

[nova forum]

np

[brittle badge]

I appreciate it a lot

.close

[safe radish]

Channel closed

Closed by @brittle badge

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

.open

[lean otter]

What is the necessary condition to find the composite function of two functions?

[main mural]

there are no conditions, no?

or you mean domain/range wise

[lean otter]

Idk it's a question in my book

I am confused as well

[lean otter]

probably

[main mural]

i guess for an even n, x^n <= a?

but idk

[main mural]

do you understand how to prove the composition?

[lean otter]

nope

This is where I am stuck

[rotund wolf]

u messed up

x is getting raised to the power n

and you have a root n

a - a + x^n

so then root n(x^n)

x

okay maybe that was too confusing

i can rephrase things if you want

[lean otter]

Ye..

Yes please

[rotund wolf]

so you are subbing every instance of x with root n(a - x^n)

its like saying that you have f(x) = x^2

so f(sqrt(2)) = sqrt(2)^2

which should be 2 right

[lean otter]

Rt

Soo

[rotund wolf]

,rotate

[rotund wolf]

this is how it should look

[lean otter]

Ye ye I got this when u said it the first time

I just don't know what to do after that 😭

[rotund wolf]

ok lets say that you have 3^3

and i ask you to find its cube root

what would you say

[lean otter]

3

[rotund wolf]

yeah

so lets say that you have x^n

and i ask you to find its nth root

[lean otter]

X

[rotund wolf]

yeah

[lean otter]

:0

[rotund wolf]

same thing here

[lean otter]

Wow

Ty

[rotund wolf]

all g

[lean otter]

Wait

Lemme try to do it again

Did I do it right?

[rotund wolf]

,rotate

[rotund wolf]

yeah you did it right

[lean otter]

Thank you :D

I am stuck here too

[rotund wolf]

whats the question lol

[lean otter]

Oh 😭 mb

12 A

Wait it's loading

[rotund wolf]

,rotate

[rotund wolf]

woah is this hindi

[lean otter]

Nope

😭

Just another language with the same script

[rotund wolf]

is the question correctly typed

cause its quite ambiguous

am i to interpret it as k(x) * g(x)

where k and g are evaluated pointwise

[lean otter]

I think it's
(kog(x))

but I am not sure

[rotund wolf]

well it completely changes the question if not

[lean otter]

Wait

Ye idk

😭

[rotund wolf]

well i will assume that its the composition cause it fits thematically as well not being amboiguous

so you have 3 * K(2x+5) = 2x+5

right

[lean otter]

Mhm

[rotund wolf]

so what is this K(2x+5)

[lean otter]

(2x+5)/r

Ig?

[rotund wolf]

yes

so you have 3 * (2x+5)/r = 2x+5

i kinda just gave the answer away

but what must r be

should be straightforward

[lean otter]

Ye

So

what's next

[rotund wolf]

its what i said

find r

[lean otter]

that's what the question asked

Idk how to

[lean otter]

I did it till here

But like I couldn't get it

[rotund wolf]

ok lets say that you were in a test

best thing to do is guess and check if you can't understand the algebra here

first try this and then ill tell you how it works algebraically

[lean otter]

Try what

[rotund wolf]

try different values of r

to see if the two sides equal each other

[lean otter]

Ahh

Alr

[rotund wolf]

,rotate

[rotund wolf]

yup

nice job

[lean otter]

I mean it's easy to tell what could be the value of r but how do I solve it

[rotund wolf]

now to do this algebraically

[lean otter]

😭

[rotund wolf]

divide both sides by 2x + 5

[lean otter]

Wiatt

[rotund wolf]

one important thing with this is to make sure that x can't be equal to -5/2 cause then you will be dividing by 0

2x + 5 can be thought of as a number right

its the same thing as dividing both sides of the equation by like 7 for example

anyways, after doing this, you get 3/r = 1

and thus, r = 3

[lean otter]

Yupp

Sorry my internet was acting up earlier

[rotund wolf]

allg

does it make sense?

[lean otter]

Yup

It does

[rotund wolf]

nice

one last thing

just to itch my curiosity, what language is that script from

[lean otter]

Ahaha

Nepali

[rotund wolf]

ah okay

was wondering if it was that

[lean otter]

What

Hindi and Nepali both use devanagari script so yes it's common to mistaken it for hindi

[rotund wolf]

learn something new everyday

okay i need to go rn, gl with your maths

[lean otter]

alr

,rotate

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

If 2f(x) + f(1/x)=4x+2/x then find the value of f^-1(4).

<@&286206848099549185>

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh walrus]

just solve?

[marsh walrus]

.

[lean otter]

how?

[marsh walrus]

im asking

so you can do gaussian elimination

thats the most rudimentary

[lean otter]

somehow I'm getting y=-564/133

[lean otter]

I haven't been taught that

[marsh walrus]

what have you been taught

[lean otter]

some kind of multiplication-cross method

is that gaussian elimination

[summer jetty]

can't you use substitution method?

[lean otter]

yeah I got y=565/136

[summer jetty]

substitute it into second eq, and you'll get the value of x, and then z

[safe radish]

@lean otter Has your question been resolved?

Channel closed

Closed by @stuck garden

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[serene spindle]

Hi! Could someone help me solve question A? I’ve no idea how to solve it and I already tried looking at markov chain examples. Thank you! ^^

[solar hazel]

what if there are an odd number of trucks at A

[solar hazel]

overlooking that... you start with a_0 + b_0 trucks. do you know what the states are here?

[patent kite]

in question a you only have to find the markov matrix that represent the probabilities of transition every month. There are only 4, the possibility that a truck that is in A stays in A, the probability that a truck is in A goes to B, and the same for B

so I've understood that the Markov matrix is [ 1/2 1/2 , 1 0]

but I don't know if this is correct

because then when I try to do question B, I'm not able to solve

[serene spindle]

@solar hazel thats the only thing i know

[patent kite]

and I don't know if it's because I haven't computed the Markov matrix well, or if my problem is that I don't know how to do question b

[solar hazel]

not sure that matrix is right

[patent kite]

"more than two months in a row" confuses me

but I don't have another number or probability to do another thing

[solar hazel]

this question is pretty janky honestly

[patent kite]

for me the matrix is this one

but then, not able to solve question b

so don't know what am I doing wrong

please someone help 🙏🏻

[lethal vortex]

<@&286206848099549185>

[patent kite]

thanks @lethal vortex 🙏🏻

[solar hazel]

what are the states that you are transitioning between here?

[patent kite]

4 different possibilities of states, a truck that is in A and stays in there, a truck that is in A and goes to B (the exercise says that every month 0.5 of the tracks in A stays there and the other half goes to b) and then, the trucks that are in B that goes to A, and the ones that stay in B

but the exercise says that the trucks are not in there more than two months in a row, and the Markov matrix is of every month

bur I've considered that every month all the trucks that are in B, go to A

because I don't have more information

[patent kite]

here (I know it's all ugly) you can see the diagram and the Markov matrix H

[solar hazel]

yea i can think of two ways to interpet that part, idk which it is lol

[patent kite]

the one that allows to solve the next question, because with mine I can't (but maybe it's because I'm doing it wrong, it's a lot of possible)

that's why I need that someone helps me to open my mind 🤣🤣

[solar hazel]

well i would think there should be a_0 + b_0 + 1 states:
0 trucks at A
1 truck at A
...
a_0 + b_0 trucks at A

this question is too janky for me though lol

[patent kite]

is the one that was in my first call exam, almost most of the class failed, and tomorrow we have the second call 🥲🥲

I'm too desperate and no one can help me to solve this

[solar hazel]

😭

[lethal vortex]

i can chatgpt math it for u if that helps

[patent kite]

i used it, but nothing makes sense

because in question b chatgpt uses pi number I don't know for what, and I should solve it with an eigenvector

[solar hazel]

don't do this

[safe radish]

@serene spindle Has your question been resolved?

[patent kite]

please help

[safe radish]

@serene spindle Has your question been resolved?

[zinc hornet]

What part are you stuck on

[patent kite]

the whole exercise, if you read this you'll now my doubts

[patent kite]

.

[patent kite]

.

[patent kite]

.

[patent kite]

.

[safe radish]

@serene spindle Has your question been resolved?

[rotund wolf]

for the transition matrix, how about [1/2 1/2; 1/2 1/2]

we know that after two months, we have to transition between state A to state B right

and the probability that the given month is the second months (cause it reoccurs) or the first months would be 1/2 each

cause there are two states, first or second month

and they are equally as likely

so ig its not a horribe assumption to make that they each have a 0.5 probability of occuring

also, the second part deals with calculating the eigenvalues or something like that (havent learnt it yet)

but i was trying to learn it from this video

https://www.youtube.com/watch?v=i3AkTO9HLXo&list=PLM8wYQRetTxBkdvBtz-gw8b9lcVkdXQKV

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber shore]

given the equation x^2 + bx + c =0; knowing that 24b + c = -523; and the 2 solutions (x1;x2) are positive integers. Find x1 and x2

[limber shore]

id even know how to start... pls help

umhm

sry there was no "a"

[safe radish]

@limber shore Has your question been resolved?

[limber shore]

.close

[safe radish]

Channel closed

Closed by @limber shore

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

how to draw graph easily?

[fathom adder]

What do you have to start ?

[lean otter]

that mean sir?

[fathom adder]

Do you have a function ?

To graph

[lean otter]

sir want learn it

[fathom adder]

Ok ic

[lean otter]

i am in grade 11

so, and i am new to discord

[drowsy moss]

there's not an easy answer to that. It depends a lot on what math you already know. There are whole chapters of textbooks devoted to graphing a function

[fathom adder]

Its not the same tips while a trig function or a polynomial

[lean otter]

sir wait a moment

the graph of a function of the form y=+-(x+b)^2+c

[fathom adder]

Ok so it depends of the sign

At the front

Ok so you take -b and the c ok ?

So youre function is a quadratic so it will be like a parabola

And we have a point M(-b , c) which is the minimum of the parabola if its a plus in front, otherwise it will be the maximum of the parabola if its a minus

[fathom adder]

Thats how you graph it

[lean otter]

could you please teach it

in the most easiest method

[limber shore]

it d be easier to understand if u take away the plus or minus sign..

[drowsy moss]

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:vertex-form/v/vertex-form-intro

[fathom adder]

You can expend the square and calculate some values of the funtion, put the point on the graph, I cant see how this can be easier since you dont know b and c

[fathom adder]

This is the most easiest way for this form @lean otter ngl

[lean otter]

that means plus or minus

[drowsy moss]

Take the graph x^2, a parabola with a vertex at the point (0,0).
if you have (x+b)^2 + c, then you've moved the vertex of the parabola to (-b, c) which shifts the whole graph left/right -b and up/down c
if you have -(x+b)^2 + c, then you've moved the vertex of the parabola to (-b, c) which shifts the whole graph left/right -b and up/down c and flipped the parabola to open downwards

[limber shore]

ye that means 2 diagram

hard to illustrate clearly

[fathom adder]

They are "symétrique" by the x axis

[limber shore]

wth ahh word

[fathom adder]

Symetrical ? Its how to say it ?

[limber shore]

prolly idk..

[safe radish]

@lean otter Has your question been resolved?

Channel closed

Closed by @swift plank

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert iron]

bro wtf

you could've wrote it in the other channel

[hot urchin]

Thought you wanted it considering it looked like you were already in the channel before I got there.

[desert iron]

what's your question

[hot urchin]

I was told the factors of 6 must add to make 2 and multiply to make itself. 

Proposal 1 through implied logic: I am assuming this is a very efficient method that checks somehow whether or not the problem will multiply and add -before- you actually add or multiply it in binomial form, is this true?

Clearer:

Are they checking if any factor adds to 2x and multiplies to itself before actually converting to binomials because its more efficient and checks if the result after conversion would get the desired result?```

[desert iron]

I don't understand anything at all ?

[hot urchin]

Interesting...

Tell me something hamdy

Do you also not understand other people's questions?

[hot urchin]

This isn't a hard question hamdy. I could answer this in less than 15 seconds.

[desert iron]

ha????????????

[hot urchin]

Yes or no

I don't care what your personal ability is either.

[desert iron]

bro I was tryna help

donno why are being dramatical

[hot urchin]

Yes, and I am asking a very simple question.

I am not, I asked that to determine where m y explanation might be flawed or what causes that error.

Oh wait...

I could've just used my own knowledge to answer that tbh.

Hamdy take a break I'll just ping the helpers.

[desert iron]

alright

[hot urchin]

Thank you.

[desert iron]

👍

[hot urchin]

<@&286206848099549185>

.close

[safe radish]

Channel closed

Closed by @hot urchin

Use .reopen if this was a mistake.

[hot urchin]

I was told the factors of 6 must add to make 2 and multiply to make itself. 

Proposal 1 through implied logic: I am assuming this is a very efficient method that checks somehow whether or not the problem will multiply and add -before- you actually add or multiply it in binomial form, is this true?

Clearer:

Are they checking if any factor adds to 2x and multiplies to itself before actually converting to binomials because its more efficient and checks if the result after conversion would get the desired result?```

[remote oyster]

Your question doesn't make any sense

[lean otter]

speak in non "👆 🤓" terms please

[remote oyster]

Best way you could have phrased this, thanks

[hot urchin]

Would you be able to describe the reasons why it does not make sense?

[lean otter]

ikr this is a math server but come on

[remote oyster]

Yes, it is true that the factors of 6, being 1, 2, 3, and 6 add to 12. Which is 2*6.

Which means 6 is a perfect number

I just don't understand what you're trying to say so I'mma just let someone else help

[oak atlas]

aint this just saying b from x^2+bx+c=0 has to equal the sum of some factors of c.

[remote oyster]

Technically the sum of factors of a*c but oh well—

[oak atlas]

nah you right, i fixed myself i think

[remote oyster]

The property that 6 is a perfect number is not a "method" but a fact of the number itself.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hot urchin]

I'm still here you know

[hot urchin]

Just processing everything.

[remote oyster]

Ah

[hot urchin]

Cuz the only way you wouldn't of understood that is because well.

Proposal A: my guess was wrong meaning you didn't understand because it was just wrong

[lean otter]

only type .close when you don't have any more questions 😭

[hot urchin]

I needed a schism between that convo and this one because nothing constructive was mentioned.

[remote oyster]

No

There was no method mentioned

[hot urchin]

Yes thank you for agreeing with me.

The reason you didn't understand was because it was a proposal regarding how it worked based on what was implied

So you being confused isn't confusion

You just said no without realizing it.

[remote oyster]

Okay.

[hot urchin]

Q: Can you further describe the operations in question (why they must add and multiply to create the values mentioned) before I form another proposal?```

https://youtu.be/P8W2M0jq2Qs?si=c29QD5k8VHb6TfhN

Timestamp: 1:51

[remote oyster]

Okay one second

[hot urchin]

Q: How does checking if they add and multiply check if they can be factored?```

[remote oyster]

that is better phrasing

thank you

[hot urchin]

Thank you for telling me which phrasing was correct.```

[remote oyster]

okay so, the factored form of a polynomial like that is:
(x + n)(x + m) = 0
so when you do FOIL, you get:
x^2 + mx + ax + mn = 0
x^2 + (m+n)x + mn = 0

so you need to find 2 values, m and n that work for the a and b coefficients

[hot urchin]

Thinking . . .```

Identified understanding:

You add after multiplying the binomials using the factors listed checking if they work.```

Q: Is it far simpler than I thought, and they are simply running through all the binomial combinations on the right side by multiplying and adding?```

Q2: Is what they're doing faster than multiplying and then adding? Are they using a method that checks if that will work even before they do that?```

[hot urchin]

❔️

[remote oyster]

they're using a method to see if they can factor it

[remote oyster]

aka they're trying to make it look like the first line here

[hot urchin]

CONCEPTUAL BASE INTEGRITY FAILURE```

Thank you.

.close

[safe radish]

Channel closed

Closed by @hot urchin

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet steeple]

sry if u saw my quesiton already but i had to step away. anyway i wanted to know if the approach i took to solve this problem was right? This is the prompt.

[scarlet steeple]

the question is: Which diver hits the water first, and by how much?

these are the steps i took but i think something is off.

[safe radish]

@scarlet steeple Has your question been resolved?

[quiet plume]

It's right, and you found your way there in the end, which is the most important for computational problems like these, but you made this harder than it needed to be.

The best way is to see that if diver A starts out with 1.8 velocity upwards from the board, by the time he reaches the board again his velocity will be -1.8 downwards.

Then it's just a matter of computing the times from the point where diver B jumps : diver A will have downwards initial velocity of 1.8 and diver B won't have any, both are going 3m down. This avoids you having to compute so many subresults.

[safe radish]

@scarlet steeple Has your question been resolved?

[scarlet steeple]

ahh i see

thank you so much that's very helpful

[safe radish]

Channel closed

Closed by @scarlet steeple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

help

[lean otter]

so i got a question

so for tangent of wtv number tangent of 10 degrees can u divide it since it would be like a number

but tangent of a variable you can't since you are trying to find that variable?

[stoic dune]

You can divide tan(θ) always.

Well, unless it's 0 I guess

[lean otter]

but u can do it if it has a specific degree and not a variable right?

[stoic dune]

Unless tanθ is 0, you can always divide by it

Variable doesn't matter

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic cove]

hello

[arctic cove]

could someone help me with a fractional algebra problem

idk how to solve this one

[safe radish]

@arctic cove Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glass field]

nvm

.close

[safe radish]

Channel closed

Closed by @glass field

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[abstract crane]

Can someone please explain why we divide into different cases?

[worldly mango]

bruh

[safe radish]

@abstract crane Has your question been resolved?

[abstract crane]

<@&286206848099549185>

[left gyro]

do you know what the convolution integral would be to begin with

it doesnt look like youve tried that yet

[abstract crane]

Yeah, the above is just the solution

just trying to understand the solution

I'm just confused why 0 < s < 1 and 1 < s < 2

[left gyro]

this is the first step they did

[abstract crane]

yeah, i think thta makes sense

actually

why isn't it integral from 0 to 2

since maximum is 2

[left gyro]

the integral is dx2

the integral isnt dy or anything

that integral is going from x2=0 to x2=1

[abstract crane]

okay

makes sense

[left gyro]

now you know (in advance) that 0 < y < 2

you can think this because y at a minimum is 0 and at a maximum is 2

[abstract crane]

yeah

[left gyro]

so off the bat, you have a concern here

this is a bit broad

its not necessarily between 0 and 1

maybe y is big and x2 is small, and you get a number higher than 1

maybe y and x2 are similar numbers, and you get a number close to 0

[abstract crane]

hmm

[left gyro]

this is a concern because fX1 as you saw is a piecewise

[abstract crane]

yeah okay

[safe radish]

@abstract crane Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn magnet]

How do you express sqrt(i) in cartesian (a+bi=z) and polar (r cis (theta)) form? I'm really stuck on how sqrt (i) works

[rotund wolf]

so you can represent sqrt(i) = x + iy

square both sides

after equating the real and imaginary coefficients, you get that 2xy = Im(i) and x^2 - y^2 = Re(i)

now solve for x and y

you will get the cartesian equation

after finding it in cartesian form, should be easy enough to get it in polar form

but i guess if you wanted to do it faster

you could convert i to its euler form

(e^(i*pi/2))^1/2

so it will become e^(i*pi/4)

and from there, should be easy enough to convert to polar form

[thorn magnet]

Thanks a lot, didn't realise it was that simple 👍

[safe radish]

If you are done with this channel, please mark your problem as solved by typing .close

@thorn magnet Has your question been resolved?

Channel closed

Closed by @thorn magnet

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[safe radish]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[left finch]

Hello, I have this equation https://i.imgur.com/ZryEJ8i.png, which I need to solve for a or b.

[left finch]

Wolfram gives me this solution, although it looks weird to me: https://www.wolframalpha.com/input?i2d=true&i=solve+D%3D1.3Divide[\(40)Power[\(40)a*b\(41)%2C\(40)0.625\(41)]\(41)%2C\(40)Power[\(40)a%2Bb\(41)%2C\(40)0.25\(41)]\(41)]+for+b

And I don't know if it's matter of converting this answer to something readable or the formatting of original question is not good.

It's for strict practical purposes only, don't need the step-by-step solution, just final equation. Thank You in advance.

[safe radish]

@left finch Has your question been resolved?

[covert yoke]

@left finch what Wolfram Alpha is telling you is that the solution is related to the roots of a particular quintic.

The quintic in question as a function of x is:

815730721 a^5 x^5 - 100000000 D^8 x^2 - 200000000 a D^8 x - 100000000 a^2 D^8

The large coefficients are, respectfully, 13^8 and 10^8

13^8 a^5 x^5 - (10D)^8 (x^2 + 2 a x + a^2)

This quintic does not have a solution using only the familiar elementary operations.

The fact that it is a quintic comes from 0.625 being used in the problem, this is 5/8. And the 13 and 10 comes from the 1.3. essentially we raise both sides to the 8th power to clear the fractions in the exponent

[left finch]

Alright, so the solution is impossible due to large numbers generated during resolving?

[covert yoke]

No, it's due to the quintic

And it's not "impossible" just the answer will need to use different things than +-/*√

And you might be better off not using an exact representation

What is the intended application?

[left finch]

There is that equation for "equivalent diameter of a rectangular tube" on this site: https://www.engineeringtoolbox.com/equivalent-diameter-d_205.html. Its practical application is better for me when I have "a" and "D" and try to solve "b".

Hence my efforts to convert it.

[covert yoke]

Ah, I figured it was fluid mechanics lol

[left finch]

^^

[covert yoke]

Ok, so my suggestion is use Newton's method instead to get a numerical solution.

Or just use a CAS of some sort to solve on a case by case basis

Solving for a and b is good to be heinous and not worth the effort.

Rectangular tube though. Are you doing nuclear? If so, awesome. I'm nuke too.

[left finch]

Ok, I was hoping it will be easier - just generate new equation and put it to Excel. No problem though, I can use the original one.

Nukes? No. More trivial - injection molds.

[covert yoke]

Ah, reactors commonly use rectangular channels.

[left finch]

Didn't know that, interesting.

Anyways, thanks for Your time.

[covert yoke]

You're very welcome.

[covert yoke]

I found this link

https://www.mrexcel.com/board/threads/to-solve-a-6-order-polynomial-equation-in-excel.1138456/

Might help you with this

[left finch]

Thanks.

[safe radish]

@left finch Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[noble scaffold]

hello, I need help with this exercise pls: Prove by applying definitions and/or properties that: If mcd(a, b) = 1, a | c and b | c -> ab | c

[noble scaffold]

I was able to pose this:
Hypothesis 1: 1 = k1.a + k2.b.
Hypothesis 2: a.k3 = c,
Hypothesis 3: b.k4 = c
Thesis: c = a.b.k5

I don't know how to continue

[turbid crag]

gcd?

[noble scaffold]

yes

[noble scaffold]

mcd is gcd in spanish

[turbid crag]

ok

if you write $c=ka$, then $k$ is an integer. what do you get from $b|c$?

[flat frigate]

nameless individual

[noble scaffold]

b.k4 = c

[turbid crag]

I don't understand the notation here

[noble scaffold]

k4 is only an integer -

[turbid crag]

sure

can you plug in $a|c$ as well?

[flat frigate]

nameless individual

[noble scaffold]

is not this?

a.k = c

[turbid crag]

so b.k4=a.k

what can we say about the relation about $b$ and $k$?

[flat frigate]

nameless individual

[safe radish]

@noble scaffold Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hallow moss]

Okay so i see this question here

[hallow moss]

Wait issue with discord sending pics

41

Im pretty sure that this question ūs wrong or smth if i understand it

[cold aurora]

,rotate

[hallow moss]

Cause lets say n = 3
2^3 + 1 = xy

9 = xy

X and Y can be either 9, 1 or 3 3