#help-23

1 messages · Page 250 of 1

ripe cove
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also here n is odd

proper vortex
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And since the options are with the ≠ sign

ripe cove
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if i remember correctly

ripe cove
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you got it :)

proper vortex
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That's what I dont get

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Sorry

ripe cove
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no see

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with d option

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you dont remove pi/2

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3 pi /2

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which is 270

proper vortex
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Ahan

ripe cove
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so now u got it :D

proper vortex
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Thank you!!!

ripe cove
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you are welcome :)

proper vortex
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Can I dm I have a bunch of questions

ripe cove
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it's my pleasure to help ppl

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yeah ofc

proper vortex
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Similar ones

ripe cove
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sure, but i would suggest trying them out first

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now that you know the method

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if you still encounter some problems I am here for ya

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do .close to close this

proper vortex
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.close

safe radishBOT
#
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safe radishBOT
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polar fossil
#

can I just say, for all n O_n = the set of real numbers?
cuz the real numbers are open and they are a subset of themselves
and a set's infinite intersection with itself is simple itself so thats just R again and R is also closed and nonempty? this seems like cheating

solar hazel
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yea

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maybe an oversight from the question writer

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a more realistic version of the question would be to require the set containments to be proper

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but as stands that is definitely not what was asked

polar fossil
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so I'm technically correct, my favourite type of correctness

solar hazel
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i would not even call it technically

safe radishBOT
#

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tough zephyr
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How would you go about proving these

safe radishBOT
tough zephyr
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for i) would it be equal since u*(v x w) = 4 and w*(u x v) = -4, and then the det of each one is equal since its oppositve of each other? For the other two I'm not sure where to begen. Expect for ii im not sure if it has to do with cross product being communitative.

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For iii) Im not sure what the property/ thereom for this is and how I can prove it to be T or F.

dreamy elk
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i) Let $a = u, b=v, c = w$, then it matches, meaning by this that i) is false.

flat frigateBOT
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Crystopher

tough zephyr
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I see so the determinant has nothing to do with it, it just following the property

dreamy elk
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for ii) you can use the following algebraic properties of cross product:

dreamy elk
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for iii) try to recall when two vectors are orthogonal to each other.
Hint :
||It has to do with the dot product||

dusk nova
dreamy elk
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I see, that's possible, the result of cross product is orthogonal, but I found it simple with dot anyways.

dusk nova
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in fact if u think about it, | |w| |v + | |v| |w is exactly the angle bisector vector of w and v and so the rest is trivial

safe radishBOT
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@tough zephyr Has your question been resolved?

tough zephyr
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I see thank you guys

safe radishBOT
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opal steeple
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119 students took a test. We know that the highest score was 98% and that to place in the top 30 students, a student had to score 62%. The mean score was 48%. Assuming a normal distribution, what rank would you expect a student that scored 28% to place?

safe radishBOT
opal steeple
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so that i could then use the normal distribution to find out the probability of a person getting 28%

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but the standard deviation i get doesn't seem to be correct when i enter it into desmos, because it tells me that the probability of a student scoring above 62% is around 23% and not 30

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should be 0.3 or very close

safe radishBOT
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@opal steeple Has your question been resolved?

rough storm
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I think you are overcomplicating it

opal steeple
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i'm not sure how else i'd go about it

rough storm
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try to think about going from the distribution you have N(.48,sigma), to a standard normal distribution N(0,1). there's a function called an inversecdf as well, which basically extracts a z-value given a probability<z

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do you see how this helps?

rough storm
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if you're getting it from top 30, the top 30 doesn't mean top 30 percent

safe radishBOT
#

@opal steeple Has your question been resolved?

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hasty cairn
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What did I do wrong solving $$ \int{sin^{-1}x dx} $$

flat frigateBOT
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Nerdy_Coder

kind forge
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dammit is there no way to make it rotate the right message

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,rotate

flat frigateBOT
hasty cairn
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Uhh wait it was bad oh no sorry

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Uhh there’s my work

obtuse plover
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Is it possible for you to space out your work a little more

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It’s tough to read that

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Like write vertically instead of horizontally, but occupy more space

supple shore
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ye a bit difficult to read

hasty cairn
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Hold on how much space because I did space out my work more

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As you can see bigger letters and more space

hasty cairn
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This is the old work

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new work

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See how letters are bigger and more space

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somehow this is not enough so how much more space

gusty trench
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the integral in question is 1/sin^2?

hasty cairn
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sin^-1 x dx

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h is the integral

gusty trench
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that denotes arcsin right

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not 1/sin

hasty cairn
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yea

gusty trench
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you might have evaluated the integral of x/sqrt(1-x^2) incorrectly

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of course you've still cramped everything together in your work so it's hard to follow exactly what you did

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but you have the right idea, if u = 1 - x^2 then -2xdx = du so dx = du / (-2x), then your integral becomes -1/2 * u^(-1/2) du which becomes -u^(1/2) which becomes -sqrt(1-x^2)

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yeah that's the part that's off

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you should be getting x*arcsinx + sqrt(1-x^2) + C

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,w integrate arcsinx

flat frigateBOT
hasty cairn
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Is this what you guys expect of me?

obtuse plover
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I mean, im sure your teachers will probably appreciate it too

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It’s easier to follow along if the work is not difficult to read

hasty cairn
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cool

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didm’t know there was a standard

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Is there a problem with the way I separate problems?

safe radishBOT
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@hasty cairn Has your question been resolved?

full marsh
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Yea

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How can i help you

hidden lynx
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what in the Egyptian scripture

safe radishBOT
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@hasty cairn Has your question been resolved?

hasty cairn
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Did I get it right now?

hasty cairn
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<@&286206848099549185>

#

.close

safe radishBOT
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copper shadow
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I am trying to solve question six but when I tested one even number and 2 odd numbers this results in z^2 being equal to an even number. How can I prove the proof then?

empty gyro
hardy lion
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consider the remainder when dividng by 4

icy sonnet
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x,y,w are evens ⇒ z even:
this one should be simple

z even ⇒ x,y,w evens
you can use contraposition
meaning one of x,y,w is odd implies z is odd

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not sure if this is exactly whats asked of you tho

solar hazel
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there is no way you found a solution with one of w,x,z even and the other 2 odd because that implies you found a square that's 2 mod 4

safe radishBOT
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@copper shadow Has your question been resolved?

copper shadow
copper shadow
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Assuming I need to make 8 cases right?

icy sonnet
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yeah

copper shadow
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Ok

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lone arch
#

How do you solve the system \begin{align} x_1^2 + (x_2 - 7)^2 + (x_3 - 8)^2 &= 20 \ (x_1 - 2)^2 + (x_2 - 5)^2 + x_3^2 &= 20 \ x_1 + x_2 &= 7\end{align} which is essentially \begin{align*} x_1^2 + x_2^2 + x_3^2 - 14x_2 - 16x_3 &= -93 \ x_1^2 + x_2^2 + x_3^2 - 4x_1 - 10x_2 &= - 9 \ x_1 + x_2 = 7?\end{align*} Subtracting the first from the second, we get \begin{align*} x_1^2 + x_2^2 + x_3^2 - 14x_2 - 16x_3 &= -93 \ 8x_2 + 16x_3 &= 84 \ x_1 + x_2 &= 7\end{align*}

flat frigateBOT
lone arch
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Though that's not very helpful either

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@obtuse jackal Since you just typed, is there an approach you'd use over doing what I did here?

obtuse jackal
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no

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I never really studied quadratic forms

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so I don't know how quadratic systems and the potential theorem for solving them

lone arch
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The system is correct, it's given in the solutions too

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They just don't say how they solve it

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They will end up with two solutions, involving square roots

obtuse jackal
# flat frigate **Kepe**

the bottom 2 express x2 with x1 and x3
Then the top one is a quadratic in x1 and x3, so express x3 as a function of x1
Then maybe the bottom 2 let you solve for x1 ?
Seems painful to brute force it that way

lone arch
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8(7 - x1) + 16x3 = 84 so - 8x1 + 16x3 = 28

obtuse jackal
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another silly option is to take it as a linear problem with 6 variables, get a 3D kernel and then see which points verify x4 = x1², x5=x2², x6=x3²

lone arch
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And then in the solutions he was like "screw it, I'll just enter this into WA"

lone arch
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There is x1, x2, x3 involved and only two equations

obtuse jackal
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if x3 = f(x1) and x2 = g(x1, x3), then x1 + g(x1, f(x1)) = 7 is an equation in x1

lone arch
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Btw, one solution turns out to be $(x_1, x_2, x_3) = \Big(1 - \frac23 \sqrt 2 \mid 6 + \frac23 \sqrt 2 \mid 4 - \frac 13 \sqrt 2\Big)$

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Which is surprisingly nice?

flat frigateBOT
obtuse jackal
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could definitely be worse

lone arch
obtuse jackal
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who knows

lone arch
# obtuse jackal who knows

Would you continue trying to search for something here or just conclude the author didn't intend this? The topic is kinda completely different (analytic geometry; planes, lines, mirroring along them, ...) and this exercise belongs to one of the easier ones

obtuse jackal
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if it's the only nontrivial quadratic system in the book yeah it's weird

lone arch
obtuse jackal
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what about after?

lone arch
obtuse jackal
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what was the original problem?

lone arch
# obtuse jackal what was the original problem?

A plane contains the points P(2, 5, 0), Q(0, 7, 8) and R(0, 5, 4). First, set up a coordinate equation of the plane. Now, the plane gets rotated by 90° along the line PQ and this generates another plane F. Determine the coordinate equation of F (which turned out to be x1 + x2 = 7). Now, the point R goes over to another point R' during this rotation. Determine possible coordinates of R'

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The Ansatz is to let R' = (x1, x2, x3)

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And then set up these equations

obtuse jackal
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2 solutions for clockwise and anticlockwise right?

lone arch
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|PR'| = |PR|

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|QR'| = |QR|

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And it needs to lie on the plane

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So x1 + x2 = 7

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Then, you get these 3 equations above (after squaring the first two so the square roots vanish)

lone arch
obtuse jackal
obtuse jackal
#

oh nvm

safe radishBOT
#

@lone arch Has your question been resolved?

safe radishBOT
#
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lean otter
#

How do I solve this?

Calculate how many elements are included in the sequence 3, 6, 12, 24, ... if the sum of the numbers in the sequence is 196605.

tardy pivot
#

This is a geometric sequence

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There is a formula for the sum of a geometric series, which you should memorise if u havent

lean otter
#

can you send it to me

tardy pivot
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BANG

lean otter
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Thank you

#

Imma search it up and come back if I need any further help. This is the first time I have seen the formula.

tardy pivot
#

kk

lean otter
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how do I know when I should use the geometric sequence

tardy pivot
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when the nth term takes the form ar^(n-1)

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your sequence takes the form 3(2)^(n-1)

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3(2)^(1-1) = 3, 3(2)^(2-1) = 6 etc

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when each term is multiplied by a number to get to the next term

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that is a geometric sequence

lean otter
#

I see

#

I will look more into it

#

thank you

#

.close

safe radishBOT
#
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fallen pier
safe radishBOT
desert pasture
#

,rotate

flat frigateBOT
fallen pier
#

Q1 idk what to do

desert pasture
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1a?

fallen pier
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Yeah

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Do I sub -b into both equations

desert pasture
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are you familiar with viteas formula?

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or the relation between the roots of a quadratic and the coefficents ?

fallen pier
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Not rlly 😭

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Ik a bit

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Is alpha and beta the roots

desert pasture
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yes

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wait, I'll type it out

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consider $ax^2+bc+c=0$

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

desert pasture
#

then $\frac{-b}{a} = \alpha + \beta$

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

desert pasture
#

and $\frac{c}{a} = \alpha \beta$

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

fallen pier
#

Ok I get the rule but how do I apply it

desert pasture
#

$\alpha + \beta =\frac{6}{5}$

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

desert pasture
#

$\alpha\beta = \frac{-56}{5}$

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

fallen pier
#

So simultaneous equation?

desert pasture
#

$\alpha + \gamma = \frac{14}{3}$

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

desert pasture
#

I think so

fallen pier
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Wait what's gamma

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Oh the root of q x

desert pasture
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the second root of the equation 3x^2-14x+a

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alternatively

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find the roots of the first equation

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and substitute them into equation 2

fallen pier
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So I could quadratic equation first one

desert pasture
#

yes

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,w 5x^2-6x-56=0

desert pasture
#

oo

#

this helps a lot

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do it by yourself

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and use the fact that equation 1 has only one integer root

fallen pier
#

So b =4

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Ohh

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Do I polydivide

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Or solve for gamma

desert pasture
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no

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you know the integer root now

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use that

fallen pier
#

Does a=8

desert pasture
#

,w 3(4)^2-14(4)+a=0

fallen pier
#

Tysm 🙏🙏🙏

#

Polynomials is so hard for me😭

safe radishBOT
#

@fallen pier Has your question been resolved?

safe radishBOT
#
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bronze pilot
safe radishBOT
bronze pilot
#

I only know about the angles inside, which is n-2 x 180
so it has 6 sides so its 720 in total , now I dont know what to do

#

☠️

thin bridge
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what are the sizes of each angle in a regular hexagon

bronze pilot
thin bridge
#

yes

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and from there you can apply basic angle sums

bronze pilot
#

1 sec

bronze pilot
thin bridge
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if you're referring to <TSW, yes

bronze pilot
#

oh yes TSW mb

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dang sorry I still can't see what am I supposed to do after this

thin bridge
#

angle around a point / in a revolution to get reflexW

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and then angle sum for
STUMVW

bronze pilot
#

soo 360-50 ? for the rest of W ?

thin bridge
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yes

bronze pilot
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so how do we know the angle sum for STUMVW? we don't have the value of x yet

thin bridge
#

count the number of sides

bronze pilot
#

oh I thought the formula only works on a regular polygon ?

thin bridge
#

not limited to regular shapes

bronze pilot
#

dang I see so its n-2
6-2
4x180
720-(100+120+120+30+310)

#

40

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so x is 40

#

ty

#

tysm 😭

safe radishBOT
#

@bronze pilot Has your question been resolved?

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cerulean crane
#

Do you have a math question

thin bridge
#

<@&268886789983436800> non-math self promo

warped roost
#

.close

safe radishBOT
#
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craggy sundial
#

how to be better at math

safe radishBOT
desert pasture
#

practice

light shoal
#

practice

lime dust
#

Studying and working.

empty gyro
craggy sundial
#

studying never helped, cause i never understand

lime dust
#

Studying helps you understand

proud belfry
desert pasture
#

ask for help here

lime dust
#

That is what studying means

desert pasture
#

and online too

proud belfry
#

like wym by that

prisma karma
craggy sundial
#

like in general never really understood almost anything in math😭

prisma karma
empty gyro
lime dust
#

That is vague

proud belfry
prisma karma
prisma karma
craggy sundial
empty gyro
#

that's pretty rough

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but the world is a cruel place and doesn't care

craggy sundial
empty gyro
#

So it's on you to try harder now

craggy sundial
#

im so behind it feels hopeless

prisma karma
prisma karma
craggy sundial
empty gyro
prisma karma
craggy sundial
#

thank you i feel motivated

gentle edge
#

@craggy sundial i reccomend after you learn basic addition subtration and stuff focus a lot on fractions

#

fractions are very confusing at the start but very usefull later

empty gyro
#

It won't be easy, but if you care and try and really put in the work, you can do it

craggy sundial
empty gyro
#

So do you have fraction questions?

craggy sundial
#

im doing dualingo math

#

it got fractions

empty gyro
#

i didn't even know they did math

proud belfry
#

Do khan academy imo

thin narwhal
#

its new

empty gyro
#

khan academy is the popular reccomendation here

craggy sundial
prisma karma
craggy sundial
craggy sundial
prisma karma
gentle edge
#

@craggy sundial is say watch indian guys on youtube

proud belfry
proud belfry
gentle edge
thin narwhal
#

just start at the point where you got lost

gentle edge
thin narwhal
#

or a little before the point you got lost

prisma karma
proud belfry
empty gyro
craggy sundial
#

i also got summer school if i fail am going to dash 2☠️

gentle edge
prisma karma
#

honestly if you have a grade 5,6 question and u search your question on the web, thered be a indian guy on youtube who explains it

craggy sundial
#

i been trying youtube for a while i never got anywhere so ill try active recall and actual practise, cause i always watch youtube video but it be completely different outcome when the test comes cause i get like 50-60

prisma karma
craggy sundial
#

yess ok thank you

safe radishBOT
#

@craggy sundial Has your question been resolved?

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supple bramble
#

can someone expalin this proof to me my brains not working

supple bramble
#

heres how they defined it

#

nvm i understand now

#

.close

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supple bramble
#

.reopen

safe radishBOT
#

supple bramble
#

.close

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odd widget
#

Really struggling with these critical point and absolute extrema problems. (Sample problem I'm trying to follow along with and my notes forthcoming). Thanks in advance for helping make this make more sense...

odd widget
#

Sample problem I'm trying to follow along with.

#

My scratch so far.

#

I'm wondering if my f'(x) is wrong, but I don't see any mistakes in my quotient rule. Did I simplify it too far?

rough storm
flat frigateBOT
#

🫎 Moosey 🫎

rough storm
#

there's more

odd widget
#

Argh. That'd do it. Thanks. Let me see if I can recalc and figure it out now

#

Oh jeez.

#

This homework is killing me lol.

rough storm
#

well no, that's it actually yea

#

so $f^{\prime}(x)=\frac{6x^2-1}{(6x^2+1)^2}$

flat frigateBOT
#

🫎 Moosey 🫎

rough storm
#

and you can't simplify it further

odd widget
#

That fixed it! I got it figured out! Thank you for your help 🙂

rough storm
#

np!

odd widget
#

.close

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safe belfry
#

pls help

safe radishBOT
safe radishBOT
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@safe belfry Has your question been resolved?

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lavish gyro
safe radishBOT
lavish gyro
#

(a) and (d)

#

In A i am getting that it converges

#

it will be less than 2/n^2

#

but I am unsure if it is true as the sign changes

#

also (d)

#

I could prove that |u_n| is divergent

rough storm
#

i feel like |u_n| will go to 0

lavish gyro
rough storm
#

in d

#

you can do some comparison test stuff yea

lavish gyro
#

i am confused as it is oscillating

rough storm
#

use alternating series test

lavish gyro
#

I did

#

nothing useful

#

i am not able to compare them

rough storm
#

in d?

lavish gyro
#

yeah i know this

#

but i am unable to get the 2nd argument, like unable to show that it is decreasing or increasing

#

brain lag

rough storm
#

you could use lhopitals and f'(x)<0

lavish gyro
#

umm wait

#

i dont know this why f'(x)<0

rough storm
#

to say a function is decreasing on an interval is to say f'(x)<0 on that interval

lavish gyro
#

oh

#

yeah

rough storm
#

oh wait

lavish gyro
rough storm
#

infinity/infinity

#

but

#

if you instead divide numerator and denominator by |n|

lavish gyro
#

yeah i did that

#

i did condition 1

#

didnt require lhopitals

rough storm
#

condition two just requires you show f'(x)<0

lavish gyro
#

yeah, i now see that

rough storm
#

or in this case u'(n)<0 for all n>=1

lavish gyro
#

In (a), is what i did good?

#

but i fear that sign changes affect it

#

how to tackle sin functions while testing different series

#

@rough storm just curious, which grade are you in

rough storm
#

i've graduated uni

lavish gyro
#

ok damn

rough storm
#

for the sin(ntheta) one

lavish gyro
#

@rough storm wait i think in (a), I can check the absolute value and if that converges, the orginal series also converges

#

is this correct?

rough storm
#

use complex formula for sin(ntheta)

lavish gyro
rough storm
#

if original sum diverged you could use complex formula for sin(ntheta)

lavish gyro
#

like how should i then try to prove that it diverges or converges

rough storm
lavish gyro
#

I am not comfortable with complex, with time i will be

rough storm
#

i just noticed your book mentioned complex numbers

lavish gyro
#

?

rough storm
#

no

#

i just saw this part KEK

lavish gyro
#

oh yeah, but i am uncomfortable like it takes me time to do stuff with complex numbers

#

I have less exposure

rough storm
#

it would be helpful to get comfortable with them, especially if you're going further with math/stem

lavish gyro
#

I am doing maths from a physics book so it is haphazard

lavish gyro
rough storm
#

aight

lavish gyro
#

thank you

rough storm
#

np

lavish gyro
#

@rough storm which book would you recommend for calculus, that is not too hard

rough storm
#

i didn't really use any books, but i heard stewart is pretty universal. there are resources pinned in #book-recommendations as well

#

pauls online math notes is pretty concise resource to refer to

safe radishBOT
#

@lavish gyro Has your question been resolved?

kind tinsel
#

the youtube channel professor leonard has some lectures on calc 1

#

and paul’s online math notes has supplements for calc 1 that aren’t so textbook-y

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bronze pilot
#

TOQ and POR is a straight line

safe radishBOT
bronze pilot
#

:

#

I know that both of the Y's are ( 180 - 72 ) most likely because a straight line is 180

#

apart from that, I don't know anything else or what to do

rough storm
#

use vertical angles

#

on TOP and QOR

#

you know angle POR because it is supplementary with QOR

#

use vertical angles again

#

:3

#

@bronze pilot

rough storm
#

,calc (180-72)

flat frigateBOT
#

Result:

108
bronze pilot
#

Oh sorry I was away for a second

bronze pilot
rough storm
#

huh

#

no

bronze pilot
# rough storm

alright I can see that, but I don't see a line like this tho or am I just blind

rough storm
#

angles TOP and ROQ are vertical angles

#

what is angle TOP

#

what is angle TOQ

bronze pilot
#

60 and 72

#

oh

#

so x is 12

safe radishBOT
#

@bronze pilot Has your question been resolved?

rough storm
#

now, you know angle POQ is supplementary to angle QOR, this means POQ=180-72

#

and you know POQ and ROT are vertical angles

safe radishBOT
#
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magic tusk
safe radishBOT
magic tusk
#

why is 1/f(x)

#

drawn like that

#

especially that one near parabola

#

this bit

#

i thought 1/f(x) would need to start at the turning point

#

but it clearly didnt

#

i know its following the asymptotes of x = 3 and x = -1

#

but in an exam, how would i sketch it

#

where would i start it from

#

ohh

#

if parabola is under the x-axis, that has to be under the x-axis

#

thats a rule i learnt

#

rightt

#

but like

#

why does it start from the turning point

#

makes no sense

#

.close

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#
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faint seal
#

$\int\frac{a\cos x+b}{(a+b\cos x)^2} dx$

safe radishBOT
flat frigateBOT
#

kheerii

faint seal
#

$\int\frac{a\cos x +b}{b\sin x}\cdot \frac{b\sin x}{(a+ b\cos x)^2} dx$

desert pasture
#

maybe double angle indentities ?

lavish gyro
#

divide by b^2

#

and take it as a trig func

faint seal
#

$$\int \frac{b\sin x}{(a+b\cos x)^2} dx = \frac1{a+b\cos x}+C$$ and $$\frac{d}{dx}\left(\frac{a}{b}\cot x+\csc x\right)=-\left(\frac{a}{b}\csc^2 x+\csc x\cot x\right)$$ so we get $$\frac{a\cos x +b}{b\sin x(a+b\cos x)} +\frac1{b}\int\frac{a\csc^2 x+b\csc x\cot x}{a+b\cos x} dx$$

flat frigateBOT
#

kheerii

#

kheerii

faint seal
desert pasture
#

cos(x) in terms of tan(x/2_

faint seal
#

that seems tedious

desert pasture
#

it should work

faint seal
#

$$\int\frac{a\csc^2 x+b\csc x\cot x}{a+b\cos x} dx=\int\frac{a+b\cos x}{\sin^2 x(a+b\cos x)} dx = -\cot x + C$$ so the final answer I get is $$\frac{a\cos x +b}{b\sin x(a+b\cos x)} -\frac{\cot x}{b}+C=\frac{\sin x}{a+b\cos x}+C$$

#

but this doesn't match wolframalpha, I don't think?

#

WAIT IT DOES

#

I can't even simplify a fucking trigonometric expression

#

jeez

#

okay but still, is there a better method for this?

flat frigateBOT
#

kheerii

mortal ingot
faint seal
mortal ingot
#

It seems scary, just that.

eternal carbon
eternal carbon
#

usually when you have numerator/(something)^2 that's a good thing to try

faint seal
#

oh yeah

#

the squared denominator

#

should have been a giveaway

#

hmm

desert pasture
# flat frigate **kheerii**

$\int \frac{a\left(1-\tan^2\left(\frac{x}{2}\right)\right)+b}{\frac{\left(1+\tan^2\left(\frac{x}{2}\right)\right)}{\left(a+\frac{b\left(1-\tan^2\left(\frac{x}{2}\right)\right)}{1+\tan^2\left(\frac{x}{2}\right)\left(\right)}\right)}}dx$

#

helps a bit IMO

flat frigateBOT
#

ƒ(Why am. I here)=I don't know

faint seal
#

yeah

#

that will work

#

thanks

#

.close

safe radishBOT
#
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glass field
#

how

safe radishBOT
glass field
final halo
#

Context?

dark cargo
#

send the full problem

#

hm wait they just multiplied sides with cuberoot p

glass field
spice wing
dark cargo
#

is this ctpcm

glass field
glass field
dark cargo
#

parts of it

glass field
#

which parts?

dark cargo
#

like the first half + the last two chapters

glass field
#

oh

#

im currently at like the 14th page

#

so can u help me in the future incase im confused a bit?

dark cargo
#

put your questions here somone will help you out

glass field
dark cargo
#

im not necessarily always free to help.

glass field
#

oh

#

okay then

dark cargo
#

also since i assume your prepping for olys you might want to ask stuff like this in the oly server.

dark cargo
#

idk it might just be useful if your prepping for olys

#

also, off topic

glass field
#

k

#

.close

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#
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haughty yarrow
#

how to divide equally among 3 people who paid different amounts?

lapis current
haughty yarrow
lapis current
#

(person 1)/(total money paid) * (money to be paid)

#

similarly for person 2 and person 3

haughty yarrow
# lapis current (person 1)/(total money paid) * (money to be paid)

Sorry I don't understand 😔
Imma rephrase it
Let's say A,B,C are friends
A paid 300 that has to be divided by 3
B paid 400 that also has to be divided by 3
C paid 100 that as well has to be divided by 3 at the end of the day
So what's the best method to find out who has to pay how much to whom

safe radishBOT
#

@haughty yarrow Has your question been resolved?

safe radishBOT
#

@haughty yarrow Has your question been resolved?

buoyant shadow
haughty yarrow
buoyant shadow
#

800/3 is 266

#

C pays 166, and the other take from it

#

i can;t explain it

#

there's nothing interesting happening

#

in real life you wouldn't try to track who pays to whom, you would take money from people who owe it, and then people who are owed woult take money from this pile

safe radishBOT
#

@haughty yarrow Has your question been resolved?

haughty yarrow
buoyant shadow
#

i don't understand what you're talking about

safe radishBOT
#

@haughty yarrow Has your question been resolved?

safe radishBOT
#
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safe radishBOT
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sacred wagon
#

?

safe radishBOT
#

@sacred wagon Has your question been resolved?

sacred wagon
#

.close

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white yew
#

can you please check over my work tell me if my answer is correct?

lean otter
#

yeah u good

white yew
#

.close

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wheat stag
#

How do I do this

safe radishBOT
wheat stag
#

I don’t know how I would solve this, I’m stumped

prisma karma
wheat stag
#

What is u

prisma karma
wheat stag
#

Oh ok

#

So u mean if f(x) but a different x equals the surd fraction

wheat stag
#

Yh i think i could solve that

#

That’s not too bad

prisma karma
#

but its hard to understand the question when x is all over the places

#

😂

wheat stag
#

Yh true

#

lol

robust forum
#

you can see under which values of x - f(x)=(1+sqrt(2))/2, then state that the said value is equal to x^2-4 and solve for x

wheat stag
#

Oh ok

#

Ok ty

#

Makes sense

#

.close

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#
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robust ocean
#

How to take the derivative of this

safe radishBOT
#

Please don't occupy multiple help channels.

robust ocean
#

?

#

But it’s a lot

#

Like product rule two times

#

Sûre

junior smelt
#

(that handwriting bleakcat)

robust ocean
#

Sorry about that

lean otter
#

the derivative is 0

#

wheres the variable

robust ocean
#

This looks very complex

lean otter
#

WHY ARE U EXPLAINING PASCALS TRIANGLE

#

Just do the product rule twice

#

they both take the same time to do tbh

#

was v’ given or did u have to work it out bcs it looks wrong ngl

#

might just be me seeing things

#

wait nvm i was reading it as 60s

#

all good

#

u done killed her off

robust ocean
#

.close

safe radishBOT
#
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frigid ocean
#

How would I answer if the CFG is regular?

safe radishBOT
placid oak
#

try write a regular expression for it

#

ah, actually, this will always generate at least 1 a

frigid ocean
#

Ah okay, so that’s sort of the thought process. You just try and write a regular expression?

placid oak
#

yeah

#

but in this case, it'd be a+ (+)^*

frigid ocean
#

Okay, I wasn’t sure if there were any smart methods you could use to see directly this can be

placid oak
#

where the first + matches 1 or more of the character

placid oak
#

or any other closure properties of regular languages

#

just try reduce it to a known non-regular language

frigid ocean
placid oak
#

as in, you know regular languages are closed under intersecction

#

so you can show that a language X is nonregular by intersecting it with a regular language Y, and showing that X n Y is non-regular

#

or with any other operation that regular languages are closed under

#

whether this is helpful or not will depend heavily on the given language

frigid ocean
#

Ahh, okay thanks I will go watch a video upon this cause I don’t remember intersecting languages, but it sounds needy

placid oak
#

I had an example somewhere

frigid ocean
#

What do you reckon? Is it easier to just try and write a regular expression and come to a conclusion that way

placid oak
#

maybe I can dig it up

placid oak
frigid ocean
placid oak
#

can't find the one I was thinking of, but these are good examples as well

frigid ocean
placid oak
#

A is always on the left of the +

frigid ocean
#

Oh yes, I see

placid oak
#

so the language consists of a non-empty string of as followed by a (possibly-empty) string of +s

#

actually this feels like you should be able to construct a DFA for it now

frigid ocean
#

I also drew the parse trees for a and b) and they were on the left as you said

placid oak
#

(NFA, but same thing)

#

yeah, this language doesn't really require "counting" per se, so it feels like it should be regular

frigid ocean
#

So it’s because the P production has the non-terminal A as a left recursive that it will appear on the left side, right?

placid oak
#

yeah

frigid ocean
#

And so it would just be a+(+)+

placid oak
#

* for the last one

#

since you can have zero +s

frigid ocean
#

Like one or more a followed by one or more +

#

Ohhh Tessa

#

Because it also derives epsilon

#

P

placid oak
#

yeah

frigid ocean
#

Very nice thank you so much for helping

#

♥️

placid oak
#

kind of annoying that they made + an alphabet symbol as well 😅

#

but yeah, that regex works

#

I just forgot what symbols were valid regex characters

frigid ocean
#

Yeah, exactly when I wrote that one above as well I was like that looks weird😭😭

#

a+(+*)

#

Would that be valid?

#

a++*

placid oak
#

if I were writing it on paper, I would just underline the alphabet + or something

#

make it clear that it's a different symbol

frigid ocean
#

Even this? It’s just weird when the plus is now an alphabet symbol

#

Yeah, I agree

#

I will do that as well

#

How would you use the plus symbol in normal regex?

#

How does it know that it’s the symbol and not the one or more occurrences?

placid oak
#

if you mean using them as in on a computer, you can escape characters with a backslash

frigid ocean
#

So a+(\+)*

#

Would be a valid syntax on a computer

placid oak
#

a+\+*

frigid ocean
#

Wait, my backslash disappeared

placid oak
#

yeah, backslash is also a control character in markdown

#

so you need to escape the backslash in plain text on discord

#

i.e. double backslash

frigid ocean
#

😂😭gotcha it’s just hard doing backticks on an iPad

placid oak
#

the brackets aren't strictly necessary

#

they'd just capture the second group

frigid ocean
#

Yeah, makes sense. I just thought it was easier to read, but I see.

#

Anyway, thank you again for helping♥️

placid oak
#

no worries

#

use .close if you're done with the channel

frigid ocean
#

yees 🫶

#

.close

safe radishBOT
#
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gleaming oriole
#

what is a null hypothesis?

safe radishBOT
gleaming oriole
#

"The null hypothesis in statistics states that there is no difference between groups or no relationship between variables."

#

but what does that actually mean

#

in a problem like,,

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"A computer company claims that the lifespan of its batteries is 2.7 years. The population standard deviation is 0.85 years. A sample of 25 batteries was tested, and their mean lifespan was 3.1 years. Using a 95% confidence level, determine if the company's claim is correct."

#

how would i use the concept?

safe radishBOT
#

@gleaming oriole Has your question been resolved?

gleaming oriole
#

<@&286206848099549185>

safe radishBOT
#

@gleaming oriole Has your question been resolved?

safe radishBOT
#
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#
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little glacier
#

diophantine equations: is there a more efficient way to calculate this?

little glacier
#

this is part of a puzzle game i play called KTaNE

#

the context isnt too important, but what i want is to find the most efficient way to calculate those 4 equations

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and i believe that matrices are what can be used, the problem being, i dont know how matrices work or how to rephrase an equation to be a matrix multiplication problem.

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my best guess would be to have this matrix

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but when evaluating it with an example

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it does not output the same

#

this setup outputs 3/4 correct ones, but fails at the last

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OG MT GOSH

#

THATS GENIUS

#

how do i close

#

.close

safe radishBOT
#
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#
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sterile egret
safe radishBOT
sterile egret
#

5 as the minimum but because of it being a “corner” it doesn’t qualify

light shoal
#

it does qualify, doesn't it?

sterile egret
#

We’ve tried it beforehand and it hasn’t worked, we assumed it was because technically the slopes before and after don’t follow the rule

light shoal
#

there's no "hollow circle" at the point (5,0), so i assume that point is included in the graph

#

it would be both a local minimum and a global minimum

#

the real question is how did you get 4.99 for the maximum?

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and what is the actual value of the function at x=0? it isn't shown in the graph

sterile egret
#

It’s a hole

light shoal
#

well then how can you talk about the max or min on the interval [0,8]

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if the function is not defined at x=0

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in fact it won't even have a global max

sterile egret
#

Idk man I didn’t make the thing, it’s been really annoying bc it’s contradictory

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But wouldn’t the absolute max just be a number incredibly close to 0?

light shoal
#

so it's telling you that you are wrong if you put 2 and 5 for the second question?

light shoal
#

the supremum would be 5 but there is no actual max

sterile egret
#

X=0

light shoal
#

the function never takes on the value 5 but it takes on arbitrarily close values as x approaches 0

sterile egret
#

Marked it as incorrect :/

light shoal
sterile egret
#

Damn😔😔

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Thank you anyways tho

light shoal
#

sure, gl

sterile egret
#

/close

#

.close

safe radishBOT
#
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safe radishBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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hazy field
#

What is the exponential function for my example on the bottom right? Use (0,4) to plug into f(x)=abxto find a, then use your newly found a ANDf(x)=abxAND (1,12) to figure out the final exponential equation.

hazy field
obtuse plover
#

What have u tried

hazy field
#

I haven’t tried because I’m stuck on where I’m inputting the numbers

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It gives the formula

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But I’m not sure how to input the numbers into the formula to find my answer

#

Like where I plug in (0,4)

obtuse plover
#

f(x) = ab^x

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(0,4) is a point

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Are u familiar with points on a graph

hazy field
#

Yes

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For sure

obtuse plover
#

So just plug in that point into the equation

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y = f(x)

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y = ab^x

hazy field
#

Y=ab^4?

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would that be correct?

obtuse plover
#

The point (0,4) is in the form (x,y)

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Remember how to plot points on a graph?

hazy field
#

Yes

obtuse plover
#

(x-coordinate,y-coordinate)

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so we have

hazy field
#

Y=ab^0?

obtuse plover
#

Yes, but we also know the value of y

hazy field
#

yes it would be 4

obtuse plover
#

Right, so what’s the equation

hazy field
#

4=ab^0?

obtuse plover
#

Yes

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Now simplify

hazy field
#

4=ab

obtuse plover
#

Why ab?

#

What’s b^0 equal to

hazy field
#

I’m not sure

obtuse plover
#

Any number to the power of 0 is 1

hazy field
#

Ohhhh

#

so 4=a?

obtuse plover
#

Yes

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So now u can put that in our original equation

#

What’s our new original equation

hazy field
#

12=4b^1

obtuse plover
#

Ok now what

hazy field
#

if b^0 is 1 what is b^1

obtuse plover
#

Try to figure it out urself

#

Say x = 11

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what’s 11^3?

#

@hazy field

hazy field
#

1331

proud belfry
obtuse plover
hazy field
#

121

obtuse plover
#

And then what’s 11^1

hazy field
#

just 11

obtuse plover
#

Yea

hazy field
#

Okay

obtuse plover
#

Any number to power 1 is itself

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Did u see the pattern btw

#

11^3 = 1331

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1331/11 = 11^2

hazy field
#

Yes

obtuse plover
#

11^2 = 121

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121/11 = 11^1

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11^1 = 11

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11/11 = 11^0

hazy field
#

so 3=b?

obtuse plover
#

Yea

hazy field
#

Okay thank you very much

#

Danimal profile is cool

obtuse plover
#

Dude

#

Thanks

hazy field
#

😂

obtuse plover
#

Appreciate it

hazy field
#

peacw

obtuse plover
#

Not many people recognize it

hazy field
#

✌️

obtuse plover
#

Pce

hazy field
#

It’s funny

#

Danimals underrated 🤬

obtuse plover
#

Lol

#

U know gogurt

#

U remember those

#

Gogurt was peak

#

Except when it splattered all over u

hazy field
#

Literallyy

#

The movie collabs on the gogurts

#

Idk what happened to mid 2010’s snacks

obtuse plover
#

Bro r u early gen z

hazy field
#

they just dissapeared i swear

#

2007

#

😬

obtuse plover
#

Ah ok I’m 03 lol

#

Still cool

obtuse plover
#

Alr cya

hazy field
#

✌️

#

.close

safe radishBOT
#
Channel closed

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safe radishBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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robust ocean
#

What did I do wrong

safe radishBOT
cyan monolith
#

the second derivative is less than 0 for concave downards

robust ocean
#

Wdym

cyan monolith
#

f''(x)<0 meanwhile the interval you have checked for is the first derivative

#

take the derivative again and then check the interval where its negative that will give concavity

robust ocean
#

Yea isn’t it the first derivative

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Fuck

#

Bro

cyan monolith
#

no first derivative gives you increasing and decreasing tendency lol

robust ocean
#

What’s is wrong with me

cyan monolith
#

its fine i made mistakes like this as well XD

robust ocean
#

Thanks man

cyan monolith
#

no probs

robust ocean
#

.close

safe radishBOT
#
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safe radishBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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lean otter
#

What "level" of probability do i need to tackle this question?

old chasm
#

I think the bare minimum is combi

#

like, you can do a random walk on graph too but I don't think you need to go that far

#

I have not solved this so I might not be like... know what you really need. But I think it is combi. You want to solve the equation x + y = 7 (well, you have to do 7 hops) where you want to count how many solution y is 1 or something ...

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but with ordered

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I don't know...

dreamy elk
#

Another way is considering different orderings of numbers 1 through 7, like (1,3,2,5,4,6,7). How many right and left hops does the rabbit do in this ordering (you can read it as rabbit starts as 1, then hops to 3 , then to 2 and so on)?. Then how would a ordering representing only one left hop look like?

old chasm
#

My train of thought at first is like, you have to do 7 hops to reach all the stones. Let x be the number of right hop and y be the number of left hop. We want to find the non-negative integer solution for x + y = 7

#

the order does not matter... but why I think this would overestimate :/

lean otter
old chasm
#

and counting number of that solution will yields the probability

#

well will yields you two number to make probability

lean otter
old chasm
#

ok ... 6

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same idea but 6

lean otter
#

i am a bit dull in probability rn so correct me if i am wrong, but in our case, y MUST be 1 right?

old chasm
#

yes...

lean otter
#

i think i need to revise probability

old chasm
#

but that would oversimplified the positional-wise

#

like RRLRRR would be the same as RRRRRL

lean otter
#

is this a hard question?

dreamy elk
#

Depends on the perspective you want to give it, but then again so are most combinatoric problems.

lean otter
#

so 6! total ways

#

now we only want one left hop

lean otter
dreamy elk
old chasm
#

you can't really do left turn on the first one

dreamy elk
#

Now we want amount orderings representing only one left hop.

lean otter
#

i was thinking, for just one left hop i would do all hops - all right hops

#

but i am sure it is VERY wrong

#

includes more than one left hop

dreamy elk
#

Yes, that's the problem, you also count 2, 3, etc. left hops doing that.

#

We can consider some ordering, then we can read from left to right. For each number, we look at the next one. If the next is higher than the current, then the rabbit made a right hop, else it made a left hop.
For instance, in (1,3,2,4,6,5,7) we begin on 1:

  • 1, next is 3, right hop
  • 3, next 2, left hop
  • 2, next 4, right hop,
    And so on, there would be 4 right hops and 2 left hops in this case.
lean otter
#

if we make a left hop on 3, how do we reach 2..