#help-23
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And since the options are with the ≠ sign
if i remember correctly
We could have chosen d too tho
That's what I dont get
Sorry
Ahan
so now u got it :D
Thank you!!!
you are welcome :)
Can I dm I have a bunch of questions
Similar ones
sure, but i would suggest trying them out first
now that you know the method
if you still encounter some problems I am here for ya
do .close to close this
.close
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can I just say, for all n O_n = the set of real numbers?
cuz the real numbers are open and they are a subset of themselves
and a set's infinite intersection with itself is simple itself so thats just R again and R is also closed and nonempty? this seems like cheating
yea
maybe an oversight from the question writer
a more realistic version of the question would be to require the set containments to be proper
but as stands that is definitely not what was asked
so I'm technically correct, my favourite type of correctness
i would not even call it technically
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How would you go about proving these
for i) would it be equal since u*(v x w) = 4 and w*(u x v) = -4, and then the det of each one is equal since its oppositve of each other? For the other two I'm not sure where to begen. Expect for ii im not sure if it has to do with cross product being communitative.
For iii) Im not sure what the property/ thereom for this is and how I can prove it to be T or F.
i) Let $a = u, b=v, c = w$, then it matches, meaning by this that i) is false.
Crystopher
I see so the determinant has nothing to do with it, it just following the property
for ii) you can use the following algebraic properties of cross product:
it does if u want
for iii) try to recall when two vectors are orthogonal to each other.
Hint :
||It has to do with the dot product||
cross product is more appropriate for formulating an argument for iii)
I see, that's possible, the result of cross product is orthogonal, but I found it simple with dot anyways.
in fact if u think about it, | |w| |v + | |v| |w is exactly the angle bisector vector of w and v and so the rest is trivial
@tough zephyr Has your question been resolved?
I see thank you guys
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119 students took a test. We know that the highest score was 98% and that to place in the top 30 students, a student had to score 62%. The mean score was 48%. Assuming a normal distribution, what rank would you expect a student that scored 28% to place?
!status
What step are you on?
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7. None of the above
well I had a look around and found this: https://statproofbook.github.io/P/norm-cdf so I subbed in my values as mu=0.48, x=0.62 and set it equal to 1 - 30/119 in order to find the std dev
The Book of Statistical Proofs – a centralized, open and collaboratively edited archive of statistical theorems for the computational sciences
so that i could then use the normal distribution to find out the probability of a person getting 28%
but the standard deviation i get doesn't seem to be correct when i enter it into desmos, because it tells me that the probability of a student scoring above 62% is around 23% and not 30
should be 0.3 or very close
@opal steeple Has your question been resolved?
I think you are overcomplicating it
i'm not sure how else i'd go about it
try to think about going from the distribution you have N(.48,sigma), to a standard normal distribution N(0,1). there's a function called an inversecdf as well, which basically extracts a z-value given a probability<z
do you see how this helps?
why would it be around 30%?
if you're getting it from top 30, the top 30 doesn't mean top 30 percent
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What did I do wrong solving $$ \int{sin^{-1}x dx} $$
Nerdy_Coder
,rotate
dammit is there no way to make it rotate the right message
,rotate
Is it possible for you to space out your work a little more
It’s tough to read that
Like write vertically instead of horizontally, but occupy more space
ye a bit difficult to read
Wait write vertically?
Hold on how much space because I did space out my work more
As you can see bigger letters and more space
This is the old work
new work
See how letters are bigger and more space
somehow this is not enough so how much more space
the integral in question is 1/sin^2?
yea
you might have evaluated the integral of x/sqrt(1-x^2) incorrectly
of course you've still cramped everything together in your work so it's hard to follow exactly what you did
but you have the right idea, if u = 1 - x^2 then -2xdx = du so dx = du / (-2x), then your integral becomes -1/2 * u^(-1/2) du which becomes -u^(1/2) which becomes -sqrt(1-x^2)
yeah that's the part that's off
you should be getting x*arcsinx + sqrt(1-x^2) + C
,w integrate arcsinx
Is this what you guys expect of me?
I mean, im sure your teachers will probably appreciate it too
It’s easier to follow along if the work is not difficult to read
cool
didm’t know there was a standard
Is there a problem with the way I separate problems?
@hasty cairn Has your question been resolved?
what in the Egyptian scripture
@hasty cairn Has your question been resolved?
Did I get it right now?
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I am trying to solve question six but when I tested one even number and 2 odd numbers this results in z^2 being equal to an even number. How can I prove the proof then?
Are you sure z is still an integer in that case?
consider the remainder when dividng by 4
x,y,w are evens ⇒ z even:
this one should be simple
z even ⇒ x,y,w evens
you can use contraposition
meaning one of x,y,w is odd implies z is odd
not sure if this is exactly whats asked of you tho
there is no way you found a solution with one of w,x,z even and the other 2 odd because that implies you found a square that's 2 mod 4
@copper shadow Has your question been resolved?
Ye just realized it's not
I need to solve by case
Assuming I need to make 8 cases right?
yeah
Ok
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How do you solve the system \begin{align} x_1^2 + (x_2 - 7)^2 + (x_3 - 8)^2 &= 20 \ (x_1 - 2)^2 + (x_2 - 5)^2 + x_3^2 &= 20 \ x_1 + x_2 &= 7\end{align} which is essentially \begin{align*} x_1^2 + x_2^2 + x_3^2 - 14x_2 - 16x_3 &= -93 \ x_1^2 + x_2^2 + x_3^2 - 4x_1 - 10x_2 &= - 9 \ x_1 + x_2 = 7?\end{align*} Subtracting the first from the second, we get \begin{align*} x_1^2 + x_2^2 + x_3^2 - 14x_2 - 16x_3 &= -93 \ 8x_2 + 16x_3 &= 84 \ x_1 + x_2 &= 7\end{align*}
Kepe
Though that's not very helpful either
@obtuse jackal Since you just typed, is there an approach you'd use over doing what I did here?
no
I never really studied quadratic forms
so I don't know how quadratic systems and the potential theorem for solving them
Yeah, though this is in a high school book so I guess we don't need any of that. The solutions just say "the solution to this system is [...]". This system arises from "mirroring" a point on a plane with given conditions
The system is correct, it's given in the solutions too
They just don't say how they solve it
They will end up with two solutions, involving square roots
the bottom 2 express x2 with x1 and x3
Then the top one is a quadratic in x1 and x3, so express x3 as a function of x1
Then maybe the bottom 2 let you solve for x1 ?
Seems painful to brute force it that way
x2 = 7 - x1
8(7 - x1) + 16x3 = 84 so - 8x1 + 16x3 = 28
another silly option is to take it as a linear problem with 6 variables, get a 3D kernel and then see which points verify x4 = x1², x5=x2², x6=x3²
I think at this point the author just didn't really think the system was going to turn out like this
And then in the solutions he was like "screw it, I'll just enter this into WA"
How will the bottom two let me solve for x1
There is x1, x2, x3 involved and only two equations
if x3 = f(x1) and x2 = g(x1, x3), then x1 + g(x1, f(x1)) = 7 is an equation in x1
Btw, one solution turns out to be $(x_1, x_2, x_3) = \Big(1 - \frac23 \sqrt 2 \mid 6 + \frac23 \sqrt 2 \mid 4 - \frac 13 \sqrt 2\Big)$
Which is surprisingly nice?
Kepe
could definitely be worse
Maybe in the end, there really is some nice cancellation or something?
who knows
Would you continue trying to search for something here or just conclude the author didn't intend this? The topic is kinda completely different (analytic geometry; planes, lines, mirroring along them, ...) and this exercise belongs to one of the easier ones
if it's the only nontrivial quadratic system in the book yeah it's weird
Yeah it is, there has been nothing like this before
what about after?
Nope, neither
what was the original problem?
A plane contains the points P(2, 5, 0), Q(0, 7, 8) and R(0, 5, 4). First, set up a coordinate equation of the plane. Now, the plane gets rotated by 90° along the line PQ and this generates another plane F. Determine the coordinate equation of F (which turned out to be x1 + x2 = 7). Now, the point R goes over to another point R' during this rotation. Determine possible coordinates of R'
The Ansatz is to let R' = (x1, x2, x3)
And then set up these equations
2 solutions for clockwise and anticlockwise right?
Yeah, probably, though we don't really need to think about it when setting up the equations. We just make sure the distances are still the same
|PR'| = |PR|
|QR'| = |QR|
And it needs to lie on the plane
So x1 + x2 = 7
Then, you get these 3 equations above (after squaring the first two so the square roots vanish)
So yeah, I think the topic doesn't have to do much with solving quadratic systems or anything like that..
other simplification: do R1 <- R1 - R3² to make the only square be x3²
Though then we have x1x2
oh nvm
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How do I solve this?
Calculate how many elements are included in the sequence 3, 6, 12, 24, ... if the sum of the numbers in the sequence is 196605.
This is a geometric sequence
There is a formula for the sum of a geometric series, which you should memorise if u havent
I haven't
can you send it to me
Thank you
Imma search it up and come back if I need any further help. This is the first time I have seen the formula.
kk
when the nth term takes the form ar^(n-1)
your sequence takes the form 3(2)^(n-1)
3(2)^(1-1) = 3, 3(2)^(2-1) = 6 etc
when each term is multiplied by a number to get to the next term
that is a geometric sequence
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,rotate
Q1 idk what to do
1a?
are you familiar with viteas formula?
or the relation between the roots of a quadratic and the coefficents ?
ƒ(Why am. I here)=I don't know
then $\frac{-b}{a} = \alpha + \beta$
ƒ(Why am. I here)=I don't know
and $\frac{c}{a} = \alpha \beta$
ƒ(Why am. I here)=I don't know
Ok I get the rule but how do I apply it
$\alpha + \beta =\frac{6}{5}$
ƒ(Why am. I here)=I don't know
$\alpha\beta = \frac{-56}{5}$
ƒ(Why am. I here)=I don't know
So simultaneous equation?
$\alpha + \gamma = \frac{14}{3}$
ƒ(Why am. I here)=I don't know
I think so
the second root of the equation 3x^2-14x+a
alternatively
find the roots of the first equation
and substitute them into equation 2
So I could quadratic equation first one
oo
this helps a lot
do it by yourself
and use the fact that equation 1 has only one integer root
Does a=8
,w 3(4)^2-14(4)+a=0
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I only know about the angles inside, which is n-2 x 180
so it has 6 sides so its 720 in total , now I dont know what to do
☠️
what are the sizes of each angle in a regular hexagon
120 right? 720 divided by 6
1 sec
alr I've wrote it down , just to be sure, the angle of S , its 90 , so the one on the left is 30 right? 120-90
if you're referring to <TSW, yes
soo 360-50 ? for the rest of W ?
yes
so how do we know the angle sum for STUMVW? we don't have the value of x yet
count the number of sides
oh I thought the formula only works on a regular polygon ?
not limited to regular shapes
dang I see so its n-2
6-2
4x180
720-(100+120+120+30+310)
40
so x is 40
ty
tysm 😭
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Do you have a math question
<@&268886789983436800> non-math self promo
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how to be better at math
practice
practice
Studying and working.
studying never helped, cause i never understand
Studying helps you understand
What do you mean you never understand
ask for help here
That is what studying means
and online too
like wym by that
you need to find good resources that are thorough in their explanation
like in general never really understood almost anything in math😭
and if u r stuck at any point seek help here
Then you need to ask questions about what you don't understand
That is vague
do you understand addition? Well then atleast theres some things you understand
take your time to understand the concept will help,
it might take hours before things click
yee but i started detriorating in grade 5 when i changed countries and then grade 6 covid and from then on things have been lagging
yes ill do this👍
So it's on you to try harder now
im so behind it feels hopeless
you should go to the first point where you are starting to get lost, and go from there
dont feel rushed by the schedule that school goes at, if u take ur time its not too hard to catch up
i can relate
bet in this discord i can ask math questions right
as many questions as you want, so long as you follow the rules
yeah this is what help channels is for
thank you i feel motivated
@craggy sundial i reccomend after you learn basic addition subtration and stuff focus a lot on fractions
fractions are very confusing at the start but very usefull later
It won't be easy, but if you care and try and really put in the work, you can do it
ye i was so lost in grade 5 cause of fractions
So do you have fraction questions?
i didn't even know they did math
its new
khan academy is the popular reccomendation here
ye they do math
maybe they consider first order logic as a language 
lol i just learnt they had one when tryna login to do music
ye alr where should i start
keep multiple resources just in case one resource is unclear, i suggest ur school textbook, khan and what u r using right now
@craggy sundial is say watch indian guys on youtube
grade 5 or 6 math course
Username checks out
bruh
just start at the point where you got lost
but still indian ppl know how to teach
wdym?
or a little before the point you got lost
but indian guys on youtube do be somewhat clear though
yes but its unhelpful advice
This sounds like a good start if you have fraction trouble
https://www.khanacademy.org/math/arithmetic/fraction-arithmetic
gotchu ye ill do that
i also got summer school if i fail am going to dash 2☠️
some indians guys on youtube focus on the basic and progressivly get harder
honestly if you have a grade 5,6 question and u search your question on the web, thered be a indian guy on youtube who explains it
i been trying youtube for a while i never got anywhere so ill try active recall and actual practise, cause i always watch youtube video but it be completely different outcome when the test comes cause i get like 50-60
well if you have any question in any concept u can always come here. u just gotta make sure u 100% understand the concept with 0 gap in knowledge
yess ok thank you
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can someone expalin this proof to me my brains not working
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Really struggling with these critical point and absolute extrema problems. (Sample problem I'm trying to follow along with and my notes forthcoming). Thanks in advance for helping make this make more sense...
Sample problem I'm trying to follow along with.
My scratch so far.
I'm wondering if my f'(x) is wrong, but I don't see any mistakes in my quotient rule. Did I simplify it too far?
$(-1)(6x^2+1)=-6x^{2}+\mathbf{-1}$
🫎 Moosey 🫎
there's more
Argh. That'd do it. Thanks. Let me see if I can recalc and figure it out now
Oh jeez.
This homework is killing me lol.
🫎 Moosey 🫎
and you can't simplify it further
That fixed it! I got it figured out! Thank you for your help 🙂
np!
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@safe belfry Has your question been resolved?
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(a) and (d)
In A i am getting that it converges
it will be less than 2/n^2
but I am unsure if it is true as the sign changes
also (d)
I could prove that |u_n| is divergent
i feel like |u_n| will go to 0
in A or D?
i am confused as it is oscillating
use alternating series test
yeah i know this
but i am unable to get the 2nd argument, like unable to show that it is decreasing or increasing
brain lag
you could use lhopitals and f'(x)<0
to say a function is decreasing on an interval is to say f'(x)<0 on that interval
oh wait
lhopitals for condition 1 right?
condition two just requires you show f'(x)<0
yeah, i now see that
or in this case u'(n)<0 for all n>=1
In (a), is what i did good?
but i fear that sign changes affect it
how to tackle sin functions while testing different series
@rough storm just curious, which grade are you in
i've graduated uni
ok damn
for the sin(ntheta) one
@rough storm wait i think in (a), I can check the absolute value and if that converges, the orginal series also converges
is this correct?
use complex formula for sin(ntheta)
that also works
ok in this case it does converge but what if it diverged?
if original sum diverged you could use complex formula for sin(ntheta)
like how should i then try to prove that it diverges or converges
I am not comfortable with complex, with time i will be
i just noticed your book mentioned complex numbers
oh yeah, but i am uncomfortable like it takes me time to do stuff with complex numbers
I have less exposure
it would be helpful to get comfortable with them, especially if you're going further with math/stem
I am doing maths from a physics book so it is haphazard
I havent decided, I just gave my 10th boards in India
aight
thank you
np
@rough storm which book would you recommend for calculus, that is not too hard
i didn't really use any books, but i heard stewart is pretty universal. there are resources pinned in #book-recommendations as well
pauls online math notes is pretty concise resource to refer to
@lavish gyro Has your question been resolved?
probably better to learn from lectures than from books at this level
the youtube channel professor leonard has some lectures on calc 1
and paul’s online math notes has supplements for calc 1 that aren’t so textbook-y
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TOQ and POR is a straight line
:
I know that both of the Y's are ( 180 - 72 ) most likely because a straight line is 180
apart from that, I don't know anything else or what to do
use vertical angles
on TOP and QOR
you know angle POR because it is supplementary with QOR
use vertical angles again
:3
@bronze pilot
they can't both be 180-72
,calc (180-72)
Result:
108
Oh sorry I was away for a second
So x = 90-60 = 30?
alright I can see that, but I don't see a line like this tho or am I just blind
@bronze pilot Has your question been resolved?
yes
now, you know angle POQ is supplementary to angle QOR, this means POQ=180-72
and you know POQ and ROT are vertical angles
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why is 1/f(x)
drawn like that
especially that one near parabola
this bit
i thought 1/f(x) would need to start at the turning point
but it clearly didnt
i know its following the asymptotes of x = 3 and x = -1
but in an exam, how would i sketch it
where would i start it from
ohh
if parabola is under the x-axis, that has to be under the x-axis
thats a rule i learnt
rightt
but like
why does it start from the turning point
makes no sense
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$\int\frac{a\cos x+b}{(a+b\cos x)^2} dx$
kheerii
$\int\frac{a\cos x +b}{b\sin x}\cdot \frac{b\sin x}{(a+ b\cos x)^2} dx$
maybe double angle indentities ?
$$\int \frac{b\sin x}{(a+b\cos x)^2} dx = \frac1{a+b\cos x}+C$$ and $$\frac{d}{dx}\left(\frac{a}{b}\cot x+\csc x\right)=-\left(\frac{a}{b}\csc^2 x+\csc x\cot x\right)$$ so we get $$\frac{a\cos x +b}{b\sin x(a+b\cos x)} +\frac1{b}\int\frac{a\csc^2 x+b\csc x\cot x}{a+b\cos x} dx$$
how?
cos(x) in terms of tan(x/2_
that seems tedious
it should work
$$\int\frac{a\csc^2 x+b\csc x\cot x}{a+b\cos x} dx=\int\frac{a+b\cos x}{\sin^2 x(a+b\cos x)} dx = -\cot x + C$$ so the final answer I get is $$\frac{a\cos x +b}{b\sin x(a+b\cos x)} -\frac{\cot x}{b}+C=\frac{\sin x}{a+b\cos x}+C$$
but this doesn't match wolframalpha, I don't think?
WAIT IT DOES
I can't even simplify a fucking trigonometric expression
jeez
okay but still, is there a better method for this?
kheerii
Ono what is this
what?
It seems scary, just that.
better method? yeah guess it's a quotient rule
usually when you have numerator/(something)^2 that's a good thing to try
$\int \frac{a\left(1-\tan^2\left(\frac{x}{2}\right)\right)+b}{\frac{\left(1+\tan^2\left(\frac{x}{2}\right)\right)}{\left(a+\frac{b\left(1-\tan^2\left(\frac{x}{2}\right)\right)}{1+\tan^2\left(\frac{x}{2}\right)\left(\right)}\right)}}dx$
helps a bit IMO
ƒ(Why am. I here)=I don't know
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how
Context?
Multiplying both sides with 3√p
is this ctpcm
yes
have u read it?
parts of it
which parts?
like the first half + the last two chapters
oh
im currently at like the 14th page
so can u help me in the future incase im confused a bit?
put your questions here somone will help you out
cuz i think that being explained by a person whose read the book will be easier
im not necessarily always free to help.
also since i assume your prepping for olys you might want to ask stuff like this in the oly server.
is that better?
idk it might just be useful if your prepping for olys
also, off topic
ping me in #discussion if you want to ask smt else.
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how to divide equally among 3 people who paid different amounts?
you mean , you give more to the person who paid more?
Like person a paid 100, person 2 paid 200, person 3 paid 300
Now We have to split the correct amount according to the person /3
How do we do it?
(person 1)/(total money paid) * (money to be paid)
similarly for person 2 and person 3
Sorry I don't understand 😔
Imma rephrase it
Let's say A,B,C are friends
A paid 300 that has to be divided by 3
B paid 400 that also has to be divided by 3
C paid 100 that as well has to be divided by 3 at the end of the day
So what's the best method to find out who has to pay how much to whom
@haughty yarrow Has your question been resolved?
@haughty yarrow Has your question been resolved?
C pays 34 to A, then C pays 133 to B
Pls explain
800/3 is 266
C pays 166, and the other take from it
i can;t explain it
there's nothing interesting happening
in real life you wouldn't try to track who pays to whom, you would take money from people who owe it, and then people who are owed woult take money from this pile
@haughty yarrow Has your question been resolved?
But this method isn't the most efficient one
So r u saying there isn't a better method than this?
i don't understand what you're talking about
@haughty yarrow Has your question been resolved?
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Nah ur good lol i was just thinking too much
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?
@sacred wagon Has your question been resolved?
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can you please check over my work tell me if my answer is correct?
yeah u good
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How do I do this
I don’t know how I would solve this, I’m stumped
firstly can you solve f(u)=(1+sqrt 2)/2?
What is u
solve for u (variable), i don't want to use x, as it will be confusing
yeah
you can see under which values of x - f(x)=(1+sqrt(2))/2, then state that the said value is equal to x^2-4 and solve for x
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How to take the derivative of this
Please don't occupy multiple help channels.
(that handwriting
)
Sorry about that
theyre all numbers?
the derivative is 0
wheres the variable
Oh no sorry it is the letter s not 5
This looks very complex
WHY ARE U EXPLAINING PASCALS TRIANGLE
Just do the product rule twice
they both take the same time to do tbh
was v’ given or did u have to work it out bcs it looks wrong ngl
might just be me seeing things
wait nvm i was reading it as 60s
all good
u done killed her off
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How would I answer if the CFG is regular?
try write a regular expression for it
ah, actually, this will always generate at least 1 a
Ah okay, so that’s sort of the thought process. You just try and write a regular expression?
Okay, I wasn’t sure if there were any smart methods you could use to see directly this can be
where the first + matches 1 or more of the character
another way is to find another language such that intersecting it with this given language is non-regular
or any other closure properties of regular languages
just try reduce it to a known non-regular language
Reduce it to a known nonregular language? I’m not sure I follow?
as in, you know regular languages are closed under intersecction
so you can show that a language X is nonregular by intersecting it with a regular language Y, and showing that X n Y is non-regular
or with any other operation that regular languages are closed under
whether this is helpful or not will depend heavily on the given language
Ahh, okay thanks I will go watch a video upon this cause I don’t remember intersecting languages, but it sounds needy
I had an example somewhere
What do you reckon? Is it easier to just try and write a regular expression and come to a conclusion that way
maybe I can dig it up
yeah, for simpler languages, trying a regex is easier
Yes, that would be nice if it’s not too much of a hassle
can't find the one I was thinking of, but these are good examples as well
But isn’t it also because you can infinitely go between a+ and then the terminal plus and back to A and you can keep doing this, which you can’t describe using regular language or am I completely wrong?😂
A is always on the left of the +
Oh yes, I see
so the language consists of a non-empty string of as followed by a (possibly-empty) string of +s
actually this feels like you should be able to construct a DFA for it now
(NFA, but same thing)
yeah, this language doesn't really require "counting" per se, so it feels like it should be regular
So it’s because the P production has the non-terminal A as a left recursive that it will appear on the left side, right?
yeah
And so it would just be a+(+)+
Like one or more a followed by one or more +
Ohhh Tessa
Because it also derives epsilon
P
yeah
kind of annoying that they made + an alphabet symbol as well 😅
but yeah, that regex works
I just forgot what symbols were valid regex characters
Yeah, exactly when I wrote that one above as well I was like that looks weird😭😭
a+(+*)
Would that be valid?
a++*
if I were writing it on paper, I would just underline the alphabet + or something
make it clear that it's a different symbol
Even this? It’s just weird when the plus is now an alphabet symbol
Yeah, I agree
I will do that as well
How would you use the plus symbol in normal regex?
How does it know that it’s the symbol and not the one or more occurrences?
if you mean using them as in on a computer, you can escape characters with a backslash
a+\+*
Wait, my backslash disappeared
yeah, backslash is also a control character in markdown
so you need to escape the backslash in plain text on discord
i.e. double backslash
😂😭gotcha it’s just hard doing backticks on an iPad
Yeah, makes sense. I just thought it was easier to read, but I see.
Anyway, thank you again for helping♥️
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what is a null hypothesis?
"The null hypothesis in statistics states that there is no difference between groups or no relationship between variables."
but what does that actually mean
in a problem like,,
"A computer company claims that the lifespan of its batteries is 2.7 years. The population standard deviation is 0.85 years. A sample of 25 batteries was tested, and their mean lifespan was 3.1 years. Using a 95% confidence level, determine if the company's claim is correct."
how would i use the concept?
@gleaming oriole Has your question been resolved?
<@&286206848099549185>
@gleaming oriole Has your question been resolved?
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diophantine equations: is there a more efficient way to calculate this?
this is part of a puzzle game i play called KTaNE
the context isnt too important, but what i want is to find the most efficient way to calculate those 4 equations
and i believe that matrices are what can be used, the problem being, i dont know how matrices work or how to rephrase an equation to be a matrix multiplication problem.
more context: https://ktane.timwi.de/HTML/Diophantine Equations.html
my best guess would be to have this matrix
but when evaluating it with an example
it does not output the same
this setup outputs 3/4 correct ones, but fails at the last
OG MT GOSH
THATS GENIUS
how do i close
.close
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5 as the minimum but because of it being a “corner” it doesn’t qualify
it does qualify, doesn't it?
We’ve tried it beforehand and it hasn’t worked, we assumed it was because technically the slopes before and after don’t follow the rule
there's no "hollow circle" at the point (5,0), so i assume that point is included in the graph
it would be both a local minimum and a global minimum
the real question is how did you get 4.99 for the maximum?
and what is the actual value of the function at x=0? it isn't shown in the graph
It’s a hole
well then how can you talk about the max or min on the interval [0,8]
if the function is not defined at x=0
in fact it won't even have a global max
Idk man I didn’t make the thing, it’s been really annoying bc it’s contradictory
But wouldn’t the absolute max just be a number incredibly close to 0?
so it's telling you that you are wrong if you put 2 and 5 for the second question?
to 5 you mean?
the supremum would be 5 but there is no actual max
X=0
the function never takes on the value 5 but it takes on arbitrarily close values as x approaches 0
Marked it as incorrect :/
cursed problem
sure, gl
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What is the exponential function for my example on the bottom right? Use (0,4) to plug into f(x)=abxto find a, then use your newly found a ANDf(x)=abxAND (1,12) to figure out the final exponential equation.
What have u tried
I haven’t tried because I’m stuck on where I’m inputting the numbers
It gives the formula
But I’m not sure how to input the numbers into the formula to find my answer
Like where I plug in (0,4)
Yes
Y=ab^0?
Yes, but we also know the value of y
yes it would be 4
Right, so what’s the equation
4=ab^0?
4=ab
I’m not sure
Any number to the power of 0 is 1
Yes
So now u can put that in our original equation
What’s our new original equation
12=4b^1
Ok now what
if b^0 is 1 what is b^1
1331
if b^0=1 then b^1 is B
And what’s 11^2
121
And then what’s 11^1
just 11
Yea
Okay
Any number to power 1 is itself
Did u see the pattern btw
11^3 = 1331
1331/11 = 11^2
Yes
so 3=b?
Yea
yes I just was confused with the “b”
Okay thank you very much
Danimal profile is cool
😂
Appreciate it
peacw
Not many people recognize it
✌️
Pce
Lol
U know gogurt
U remember those
Gogurt was peak
Except when it splattered all over u
Bro r u early gen z
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What did I do wrong
the second derivative is less than 0 for concave downards
Wdym
f''(x)<0 meanwhile the interval you have checked for is the first derivative
take the derivative again and then check the interval where its negative that will give concavity
no first derivative gives you increasing and decreasing tendency lol
What’s is wrong with me
its fine i made mistakes like this as well XD
Thanks man
no probs
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What "level" of probability do i need to tackle this question?
I think the bare minimum is combi
like, you can do a random walk on graph too but I don't think you need to go that far
I have not solved this so I might not be like... know what you really need. But I think it is combi. You want to solve the equation x + y = 7 (well, you have to do 7 hops) where you want to count how many solution y is 1 or something ...
but with ordered
I don't know...
Another way is considering different orderings of numbers 1 through 7, like (1,3,2,5,4,6,7). How many right and left hops does the rabbit do in this ordering (you can read it as rabbit starts as 1, then hops to 3 , then to 2 and so on)?. Then how would a ordering representing only one left hop look like?
My train of thought at first is like, you have to do 7 hops to reach all the stones. Let x be the number of right hop and y be the number of left hop. We want to find the non-negative integer solution for x + y = 7
the order does not matter... but why I think this would overestimate :/
well i do know combinatorics
and counting number of that solution will yields the probability
well will yields you two number to make probability
dont you have to do 6 hops ?
1 to 2
2 to 3
3 to 4
4 to 5
5 to 6
6 to 7
so youre saying x + y = 6
i am a bit dull in probability rn so correct me if i am wrong, but in our case, y MUST be 1 right?
yes...
i think i need to revise probability
but that would oversimplified the positional-wise
like RRLRRR would be the same as RRRRRL
is this a hard question?
i did read this
Depends on the perspective you want to give it, but then again so are most combinatoric problems.
youre right, solving probability after a lot of time
That's the amount of total orderings, since 1 is always 'locked on' the first position.
yes that is what i meant
you can't really do left turn on the first one
Now we want amount orderings representing only one left hop.
i was thinking, for just one left hop i would do all hops - all right hops
but i am sure it is VERY wrong
includes more than one left hop
Yes, that's the problem, you also count 2, 3, etc. left hops doing that.
We can consider some ordering, then we can read from left to right. For each number, we look at the next one. If the next is higher than the current, then the rabbit made a right hop, else it made a left hop.
For instance, in (1,3,2,4,6,5,7) we begin on 1:
- 1, next is 3, right hop
- 3, next 2, left hop
- 2, next 4, right hop,
And so on, there would be 4 right hops and 2 left hops in this case.
if we make a left hop on 3, how do we reach 2..
