#help-23 | Mathematics | Page 208

timid scroll Feb 23, 2024, 1:51 PM

#

yeah but they did that through

#

and I dont understand this^

#

and have been drawing it by hand

dusk gate Feb 23, 2024, 1:51 PM

#

Those values in brackets are your x and y values at the point where a line drawn from the origin intersects the circle

#

They are where sin and cos come from

timid scroll Feb 23, 2024, 1:52 PM

#

oh

#

I understand what you mean / nop nvm- ill stick to drawing lol, but in this case yes i understand bc lucky case? / i dont get it in depth

#

yes ?

dusk gate Feb 23, 2024, 1:53 PM

#

Yes, because the x value is negative here

#

from pi/2 to 3pi/4

#

x is -, y is +

#

So.. can I ask, and sorry if this is a dumb question, but...

#

You realize that the (m pi) / n numbers are replacing the usual 120 degrees or whatever, right?

timid scroll Feb 23, 2024, 1:55 PM

#

go for it

#

Yes

#

But i still dont use the diagram

#

I like to draw it out

dusk gate Feb 23, 2024, 1:56 PM

#

That's fine!

#

Ok!

#

So have you noticed a pattern in the pi/ number sequence yet?

timid scroll Feb 23, 2024, 1:56 PM

#

no

dusk gate Feb 23, 2024, 1:57 PM

#

If you convert all those fractions to a fraction with a denominator of 12, you're just incrementing by 1 pi / 12 each time

#

Though they skip 1 pi / 12, 5 pi / 12, and some others

#

The ones within 15 degrees of the x and y axes

timid scroll Feb 23, 2024, 1:58 PM

#

blobwg

#

having a bit trouble understanding, sorry

#

I dont like pi

#

I like fractions and degrees in some cases

#

thats about it

dusk gate Feb 23, 2024, 1:59 PM

#

Heh.. irrational numbers used in fractions are ironic

#

But take pi / 6 for instance

#

that's the same as 6 pi / 12

timid scroll Feb 23, 2024, 2:00 PM

#

it is?

dusk gate Feb 23, 2024, 2:00 PM

#

Yep.. it's just reduced

timid scroll Feb 23, 2024, 2:00 PM

#

ok yeah

dusk gate Feb 23, 2024, 2:00 PM

#

12 pi / 12 = pi

timid scroll Feb 23, 2024, 2:01 PM

#

It just looks like
1/6 and 1/2 for me

dusk gate Feb 23, 2024, 2:01 PM

#

with trig, just don't forget pi

#

If you don't bring pi, the whole family gets mad at Thanksgiving

timid scroll Feb 23, 2024, 2:02 PM

#

its fine ill just not show up

dusk gate Feb 23, 2024, 2:02 PM

#

yeah, lame, sorry

timid scroll Feb 23, 2024, 2:02 PM

#

no its fun

dusk gate Feb 23, 2024, 2:02 PM

#

So

#

Take a look at pi / 3

timid scroll Feb 23, 2024, 2:03 PM

#

If I may ask sorry to interupt

#

dusk gate Feb 23, 2024, 2:04 PM

#

np

timid scroll Feb 23, 2024, 2:04 PM

#

This is how I do it,
and you can see +5/13 aka +22.6

#

Is Obtuse

#

Based on the drawing

#

Now

#

#

Can I make this into what I showed?

dusk gate Feb 23, 2024, 2:05 PM

#

negative 5/13 can be obtuse

#

ggg

timid scroll Feb 23, 2024, 2:06 PM

#

sadthink wym

dusk gate Feb 23, 2024, 2:06 PM

#

and negative 5 / negative 13 can be obtuse

timid scroll Feb 23, 2024, 2:06 PM

#

ggg

dusk gate Feb 23, 2024, 2:06 PM

#

but 5 / 13 is acute

timid scroll Feb 23, 2024, 2:06 PM

#

its a sin graph

dusk gate Feb 23, 2024, 2:07 PM

#

Trouble is, in Quadrant 3, sin and cos are both negative (negative 5 / negative 13) and so you end up with a positive value

dusk gate Feb 23, 2024, 2:07 PM

#

timid scroll its a sin graph

Yep

timid scroll Feb 23, 2024, 2:07 PM

#

0, 180, 360 ect

dusk gate Feb 23, 2024, 2:07 PM

#

Right

timid scroll Feb 23, 2024, 2:07 PM

#

dusk gate Trouble is, in Quadrant 3, sin and cos are both negative (negative 5 / negative ...

oh

#

Fuck me

#

So basically I have to learn it

#

Circle diagram

dusk gate Feb 23, 2024, 2:07 PM

#

Just like in Quadrant 2 and 4, one of the values is negative

#

So you end up with a negative number... but you don't know which one it was, without more input

timid scroll Feb 23, 2024, 2:08 PM

#

Yeah But its asking for if Sin B is obtuse

#

90 --> 180

#

So I think we can ignore all other quadrants no?

dusk gate Feb 23, 2024, 2:09 PM

#

reading

#

So, elsewhere, the problem limits you to Q II?

#

90 to 180?

timid scroll Feb 23, 2024, 2:09 PM

#

yes

dusk gate Feb 23, 2024, 2:09 PM

#

Gotcha!

#

Then yes

timid scroll Feb 23, 2024, 2:09 PM

#

timid scroll

90 to 135

#

But I dont know what values to take in

#

#

I guess I can do this

#

and then I would have to put it into the
Pi/2 < Theta/2 < 3Pi/4

dusk gate Feb 23, 2024, 2:11 PM

#

Hold up

#

not quite

#

tan theta doesn't = 1/3

#

tan theta / 2 = 1/3

timid scroll Feb 23, 2024, 2:11 PM

#

so 2/3?

#

Tan Theta = 2/3 ?

dusk gate Feb 23, 2024, 2:12 PM

#

1/6

timid scroll Feb 23, 2024, 2:12 PM

#

hmm

dusk gate Feb 23, 2024, 2:12 PM

#

1/3 divided by 2/1

timid scroll Feb 23, 2024, 2:12 PM

#

ok

#

OHHH

dusk gate Feb 23, 2024, 2:12 PM

#

or.. sorry..

#

that's the outcome

#

the cross multiplication is what you have to undo to get the value of theta

#

x / 2 = 1/3

#

multiply both sides by 2

#

So yes, you're correct: 2/3

timid scroll Feb 23, 2024, 2:13 PM

#

:3

#

And then what range do I use

dusk gate Feb 23, 2024, 2:14 PM

#

In what context?

#

snaps fingers

#

Ok, I see what you're asking

#

tan = sin/cos right?

timid scroll Feb 23, 2024, 2:16 PM

#

Yes

dusk gate Feb 23, 2024, 2:16 PM

#

tan is also the slope of your line

#

y / x

#

rise / run

timid scroll Feb 23, 2024, 2:17 PM

#

sully

#

Are we over complicating it

#

Ohhhh

dusk gate Feb 23, 2024, 2:17 PM

#

Nope.. trust me, this will make everything easier

timid scroll Feb 23, 2024, 2:17 PM

#

Okie doki

#

But I smell the circle diagram

#

bleakcat

dusk gate Feb 23, 2024, 2:18 PM

#

Yep

#

timid scroll Feb 23, 2024, 2:18 PM

#

Oh god*

#

Wait no I might learn something

#

I understood gradient part

#

If gradient is negative it’s negative

#

If positive it’s positive

#

But how do you do it for a cos graph

dusk gate Feb 23, 2024, 2:19 PM

#

Yes... take a look at 2pi / 3

#

That's a negative slope, isn't it?

#

the orange line

timid scroll Feb 23, 2024, 2:20 PM

#

No idea

#

I guess so

dusk gate Feb 23, 2024, 2:20 PM

#

I mean, just looking at a line on a graph, you can see if the slope is negative or positive

#

from left to right, if you're going downhill, the slope is negative

#

if you're going uphill, the slope is positive

timid scroll Feb 23, 2024, 2:20 PM

#

So here you just look at the circle?

#

Also does it vary with sin cos and tan

#

The quadrants no?

dusk gate Feb 23, 2024, 2:21 PM

#

And do some simple math, but yeah

timid scroll Feb 23, 2024, 2:24 PM

#

#

Other version

#

:3

#

One day, if im chained up in a room and forced to learn Circle Diagram

#

I might

#

Anyways

#

Thank you for the help and ofc your patience

#

with me refusing everything

#

blobsweat

dusk gate Feb 23, 2024, 2:25 PM

#

np.. trying to think of the best way to get from here to there

timid scroll Feb 23, 2024, 2:26 PM

#

I like to divert conversations

dusk gate Feb 23, 2024, 2:26 PM

#

hard to do, when they're dividing theta by 2

timid scroll Feb 23, 2024, 2:26 PM

#

dusk gate hard to do, when they're dividing theta by 2

How so?

dusk gate Feb 23, 2024, 2:26 PM

#

at least, quick/visually

timid scroll Feb 23, 2024, 2:26 PM

#

Just throw it in the calc no

#

and then draw the graph

#

and voila

dusk gate Feb 23, 2024, 2:26 PM

#

Well, because if we do that, then we don't actually understand what's going on under the hood

timid scroll Feb 23, 2024, 2:27 PM

#

thonkzoom

#

Its fine'

dusk gate Feb 23, 2024, 2:27 PM

#

So, let me ask you this - where does tan theta = sqrt(3)?

#

How would you go about that?

timid scroll Feb 23, 2024, 2:28 PM

#

Ok ezier than before

#

so thats 60

#

what range?

dusk gate Feb 23, 2024, 2:28 PM

#

What do you mean by range?

timid scroll Feb 23, 2024, 2:28 PM

#

dusk gate Feb 23, 2024, 2:29 PM

#

normally, domain is the limit of your x values, range is the limit of your y

timid scroll Feb 23, 2024, 2:29 PM

#

whats the question acc

#

I dont know what im supposed to do

#

You want the angle?

#

60?

dusk gate Feb 23, 2024, 2:29 PM

#

Yeah, it's just 60

timid scroll Feb 23, 2024, 2:29 PM

#

ok

#

done?

dusk gate Feb 23, 2024, 2:29 PM

#

Almost.. trying to see your thought process

timid scroll Feb 23, 2024, 2:29 PM

#

So

#

What I did is

#

I grabbed calcualtor

dusk gate Feb 23, 2024, 2:29 PM

#

LOL

timid scroll Feb 23, 2024, 2:30 PM

#

Tan ^-1 ( sqrt(3))

#

you might be looking for a question like this @dusk gate ?

#

and here, the magic trick is the numbers

#

A-B

#

So find 2 common numbers than make 15

#

45 and 30

dusk gate Feb 23, 2024, 2:31 PM

#

1/2 divided by sqrt(3)/2 = sqrt(3)

timid scroll Feb 23, 2024, 2:31 PM

#

Yeah but i sadly dont have a circle image at hand yk

#

Maybe, I should try converting people from Circle diagram with drawing it by hand

dusk gate Feb 23, 2024, 2:32 PM

#

Right, but depending on what you want to do and what classes you end up in... if you're already into this, then you're going to end up having to learn that circle diagram 😉

#

spoiler alert

#

But on the plus side

#

Once you recognize where those numbers come from...

timid scroll Feb 23, 2024, 2:33 PM

#

yeah

dusk gate Feb 23, 2024, 2:33 PM

#

timid scroll Feb 23, 2024, 2:33 PM

#

oh no

#

Not that

#

I saw that before

dusk gate Feb 23, 2024, 2:33 PM

#

at 60, x = 1/2

timid scroll Feb 23, 2024, 2:33 PM

#

is that the Y axis?

#

1/2?

dusk gate Feb 23, 2024, 2:33 PM

#

No, it's the x

#

with the brackets

timid scroll Feb 23, 2024, 2:33 PM

#

x?

dusk gate Feb 23, 2024, 2:34 PM

#

The dashed line is just to show where the x value comes back to the x axis

#

what you're measuring is the 1/2 of the x axis

#

(plus another 1/2 = 1, which is the radius of the circle)

timid scroll Feb 23, 2024, 2:34 PM

#

hmmm

#

So it goes from 60 to 120?

#

60 -> 360

dusk gate Feb 23, 2024, 2:35 PM

#

I think you're confusing the specific requests in your problems with the very general nature of the Unit Circle as a whole

#

cos 60 = 1/2

#

that's it

#

nothing more

timid scroll Feb 23, 2024, 2:35 PM

#

nvm

dusk gate Feb 23, 2024, 2:36 PM

#

eh?

timid scroll Feb 23, 2024, 2:36 PM

#

Idk u siad 1 = 360

#

I just need a bit more time into this topic

#

before i can understand

#

/ find patterns

timid scroll Feb 23, 2024, 2:36 PM

#

dusk gate I think you're confusing the specific requests in your problems with the very ge...

what you said

#

is absolutely correct

dusk gate Feb 23, 2024, 2:37 PM

#

When your problem is asking for the range, what's it asking for, exactly?

#

put "range" into your own words

timid scroll Feb 23, 2024, 2:38 PM

#

no clue,
I think the maximum value of something or only value available

#

To this question

dusk gate Feb 23, 2024, 2:39 PM

#

hmm

timid scroll Feb 23, 2024, 2:39 PM

#

lol

#

But i also think of it as

#

its going to simplify this question

#

somehow

#

anyways

#

in general i have no flipping clue what im doing 99% of the time

#

Since i started trig

#

i just remmeber formats of questions

dusk gate Feb 23, 2024, 2:42 PM

#

That's fair

timid scroll Feb 23, 2024, 2:44 PM

#

whats cos 2X

#

exactly

#

if x = 3

#

is it cos (2 x 3)

#

Or cos (3) + cos (3)

#

or 2 x cos (3)

#

becuase sometimes its
cos (2 x 3)

dusk gate Feb 23, 2024, 2:44 PM

#

2*3

#

The first one

timid scroll Feb 23, 2024, 2:45 PM

#

ah ok

dusk gate Feb 23, 2024, 2:45 PM

#

2 cos x would be 2 x cos 3

#

cos^2 x would be cos 3 * cos 3

timid scroll Feb 23, 2024, 2:45 PM

#

hmm

#

cos (3) + cos (3)

#

is it just that

#

or

dusk gate Feb 23, 2024, 2:45 PM

#

2 cos (3)

timid scroll Feb 23, 2024, 2:45 PM

#

right

dusk gate Feb 23, 2024, 2:46 PM

#

or, since multiplication and addition are cousins

#

cos (2 * 3)

timid scroll Feb 23, 2024, 2:46 PM

#

yeah,
you know logs?
I dont use them at all i just ln all the time lol

dusk gate Feb 23, 2024, 2:46 PM

#

Yep.. natural log, base e

timid scroll Feb 23, 2024, 2:46 PM

#

also whats fun is

ln -3 = x ln-3

#

but as long as you know its positive x value

#

you can just do ln -3

#

ln 3 = x ln-3

#

same goes for this

#

lol

#

I do that too

#

and it kills everyone

#

to see it

#

these are the things i spot in math

dusk gate Feb 23, 2024, 2:48 PM

#

o.O

#

you.. can't take the ln of negative numbers

timid scroll Feb 23, 2024, 2:48 PM

#

yeah thats true

dusk gate Feb 23, 2024, 2:48 PM

#

Are you taking the absolute value?

timid scroll Feb 23, 2024, 2:48 PM

#

you just force it to become positive

timid scroll Feb 23, 2024, 2:48 PM

#

dusk gate Are you taking the absolute value?

Idk? im finding x

dusk gate Feb 23, 2024, 2:49 PM

#

oh - yes.. you'll see ln used with the absolute value signs all the time

timid scroll Feb 23, 2024, 2:49 PM

#

another thing is I dont know the names for anything

#

:3

dusk gate Feb 23, 2024, 2:50 PM

#

That'll come with time

timid scroll Feb 23, 2024, 2:51 PM

#

#

Like this

#

Anywyas

#

Im going to leave you to it

#

thank you very much for the time

#

Was fun

#

Talking to you

#

: p

dusk gate Feb 23, 2024, 2:52 PM

#

Did your question get answered?

timid scroll Feb 23, 2024, 2:52 PM

#

yes

dusk gate Feb 23, 2024, 2:52 PM

#

tan theta/2?

timid scroll Feb 23, 2024, 2:52 PM

#

-3

#

hype

dusk gate Feb 23, 2024, 2:53 PM

#

ok!

#

Best of luck - thanks for the chat!

timid scroll Feb 23, 2024, 2:55 PM

#

Thank you for the fun!

#

Have a good rest of your evening

#

!

#

.close

safe radishBOT Feb 23, 2024, 2:55 PM

#

Channel closed

Closed by @timid scroll

Use .reopen if this was a mistake.

safe radishBOT Feb 23, 2024, 3:10 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timber violet Feb 23, 2024, 3:30 PM

#

100 balls of 6 different colours in n boxes, any two balls of the same colour in different boxes are distributed in such a way that they are placed in boxes. For any two boxes, there is one of these 6 colours such that neither of the two boxes has a ball painted in that colour. What is the smallest possible value of n?

safe radishBOT Feb 23, 2024, 3:30 PM

#

timber violet 100 balls of 6 different colours in n boxes, any two balls of the same colour in...

timber violet Feb 23, 2024, 3:30 PM

#

i have an solution i want it to be checked

#

.close

safe radishBOT Feb 23, 2024, 3:37 PM

#

Channel closed

Closed by @timber violet

Use .reopen if this was a mistake.

safe radishBOT Feb 23, 2024, 3:56 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

drifting ridge Feb 23, 2024, 4:03 PM

#

can i get help?

safe radishBOT Feb 23, 2024, 4:03 PM

#

drifting ridge can i get help?

drowsy citrus Feb 23, 2024, 4:15 PM

#

To find the average integrate the function and divide it by total time.

safe radishBOT Feb 23, 2024, 4:20 PM

#

@drifting ridge Has your question been resolved?

drifting ridge Feb 23, 2024, 4:22 PM

#

drowsy citrus To find the average integrate the function and divide it by total time.

how would you do that

drowsy citrus Feb 23, 2024, 4:23 PM

#

integrate h(t) from 1 to 4 and divide it by 3 (the total time)

drifting ridge Feb 23, 2024, 4:26 PM

#

drowsy citrus integrate h(t) from 1 to 4 and divide it by 3 (the total time)

how do i do that

drowsy citrus Feb 23, 2024, 4:26 PM

#

It's simple integration of the function

drifting ridge Feb 23, 2024, 4:26 PM

#

can you do it visualised

drowsy citrus Feb 23, 2024, 4:27 PM

#

You can use the internet for that. Just go type integral calculator, input this function, specify the values and divide the the result by 3. That should do it.

drifting ridge Feb 23, 2024, 4:27 PM

#

because i dont use english terms

drifting ridge Feb 23, 2024, 4:33 PM

#

drowsy citrus You can use the internet for that. Just go type integral calculator, input this ...

is this right

drowsy citrus Feb 23, 2024, 4:34 PM

#

Okay, now find the area under the curve from A to B

#

Also, I hope you know how to do the second part of it.

drifting ridge Feb 23, 2024, 4:38 PM

#

drifting ridge Feb 23, 2024, 4:38 PM

#

drowsy citrus Also, I hope you know how to do the second part of it.

how do i do that

#

i only have for the first year no?

drowsy citrus Feb 23, 2024, 4:41 PM

#

#

I was simply saying this

#

This should yeild a value of 5.1 metres. Divide it by 3 due to duration being from year 1 to year 4.

#

That'll give you 1.7 metre average height.

drifting ridge Feb 23, 2024, 4:54 PM

#

drowsy citrus

i havent used this

#

#

but isnt this right for a

drowsy citrus Feb 23, 2024, 4:54 PM

#

The website is called integral-calculator.com

drifting ridge Feb 23, 2024, 4:54 PM

#

drowsy citrus Feb 23, 2024, 4:56 PM

#

Okay, first off, why are you using the AB line ? There's no need for it. Remove it. Then find the area under the red curve from A to B.

drifting ridge Feb 23, 2024, 4:57 PM

#

drowsy citrus Okay, first off, why are you using the AB line ? There's no need for it. Remove ...

because you want the average growth

#

and the line determines that

drowsy citrus Feb 23, 2024, 4:59 PM

#

Ummm.... nope. The line isn't actually helping here.

#

Okay let's try to understand it practically.

#

Average is the addition of all values over a span divided by the length of that span itself.

#

But since the values in this cases are infinitely many (a continuous function has infinitely many values), all these values will be added and divide by the length of the span (4-1=3). So the net addition of these infinite values ends up becoming the integration of the function from 1 to 4.

#

This integration is also the area under the red curve, but this has nothing to do with the AB line.

drifting ridge Feb 23, 2024, 5:09 PM

#

.close

safe radishBOT Feb 23, 2024, 5:09 PM

#

Channel closed

Closed by @drifting ridge

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

exotic charm Feb 23, 2024, 5:13 PM

#

what does this little x mean

safe radishBOT Feb 23, 2024, 5:13 PM

#

exotic charm what does this little x mean

exotic charm Feb 23, 2024, 5:14 PM

#

this is the function btw

plucky elk Feb 23, 2024, 5:22 PM

#

partial derivative with respect to x

safe radishBOT Feb 23, 2024, 5:29 PM

#

@exotic charm Has your question been resolved?

exotic charm Feb 23, 2024, 5:38 PM

#

plucky elk partial derivative with respect to x

thx

#

wb fxy

#

does that mean partial derivative wrt to y and then x

#

or partial derivative wrt to x then y

plucky elk Feb 23, 2024, 5:40 PM

#

exotic charm wb fxy

https://tutorial.math.lamar.edu/classes/calciii/highorderpartialderivs.aspx

exotic charm Feb 23, 2024, 5:41 PM

#

wow they sure like to make it confusing

#

xy = differentiate wrt to y then x

#

then y not call it yx 😠

restive niche Feb 23, 2024, 5:43 PM

#

Because composing things happens in the opposite direction to how we read; you go from right to left when composing things

#

Unless you're a Hebrew reader

safe radishBOT Feb 23, 2024, 5:44 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shell kiln Feb 23, 2024, 5:47 PM

#

safe radishBOT Feb 23, 2024, 5:47 PM

#

shell kiln

shell kiln Feb 23, 2024, 5:47 PM

#

what does this mean?

ripe plover Feb 23, 2024, 5:49 PM

#

shell kiln

there basically asking you to use a trig function that contains the sides used in the diagram

shell kiln Feb 23, 2024, 5:50 PM

#

is the answer for a. sin 70 (a)

#

?

ripe plover Feb 23, 2024, 5:50 PM

#

like the first part, a is the hyp and x is the opp so sin70

#

yep

shell kiln Feb 23, 2024, 5:50 PM

#

k and this?

ripe plover Feb 23, 2024, 5:51 PM

#

same thing but just replace the variable with the number and if you have a calculator find the value

shell kiln Feb 23, 2024, 5:51 PM

#

find the value for x and correct to two decimal places thats all right?

ripe plover Feb 23, 2024, 5:52 PM

#

yeah

shell kiln Feb 23, 2024, 5:52 PM

#

k thx bro

ripe plover Feb 23, 2024, 5:52 PM

#

np

shell kiln Feb 23, 2024, 5:52 PM

#

.close

safe radishBOT Feb 23, 2024, 5:52 PM

#

Channel closed

Closed by @shell kiln

Use .reopen if this was a mistake.

safe radishBOT Feb 23, 2024, 6:07 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tame horizon Feb 23, 2024, 6:14 PM

#

how do I recover the basic variables in the final primal dictionary given the dual solution? Full problem is atttached:

safe radishBOT Feb 23, 2024, 6:14 PM

#

tame horizon how do I recover the basic variables in the final primal dictionary given the du...

#

@tame horizon Has your question been resolved?

safe radishBOT Feb 23, 2024, 7:04 PM

#

@tame horizon Has your question been resolved?

safe radishBOT Feb 23, 2024, 7:34 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

strong bison Feb 23, 2024, 7:36 PM

#

I need help

#

safe radishBOT Feb 23, 2024, 7:36 PM

#

strong bison I need help

twilit spindle Feb 23, 2024, 7:37 PM

#

the solution of any polynomial are the x-intercepts

strong bison Feb 23, 2024, 7:38 PM

#

twilit spindle the solution of any polynomial are the x-intercepts

So is it 2?

twilit spindle Feb 23, 2024, 7:40 PM

#

strong bison So is it 2?

catthumbsup

strong bison Feb 23, 2024, 7:41 PM

#

twilit spindle <:catthumbsup:614540188747563008>

I have another question

#

twilit spindle Feb 23, 2024, 7:43 PM

#

"narrowness" is determinted by the magnitude of the leading coefficient

strong bison Feb 23, 2024, 7:47 PM

#

twilit spindle "narrowness" is determinted by the magnitude of the leading coefficient

I don’t get to

#

It

twilit spindle Feb 23, 2024, 7:47 PM

#

for number 2, what's the number in front of the x^2 term?

strong bison Feb 23, 2024, 7:51 PM

#

twilit spindle for number 2, what's the number in front of the x^2 term?

4

twilit spindle Feb 23, 2024, 7:53 PM

#

strong bison 4

and for number 3?

strong bison Feb 23, 2024, 7:55 PM

#

twilit spindle and for number 3?

1/5

twilit spindle Feb 23, 2024, 7:55 PM

#

which is larger?

strong bison Feb 23, 2024, 7:56 PM

#

twilit spindle which is larger?

4?

twilit spindle Feb 23, 2024, 7:56 PM

#

so then quadratic 2 is narrower than quadratic 3

strong bison Feb 23, 2024, 7:58 PM

#

twilit spindle so then quadratic 2 is narrower than quadratic 3

Ohhh

twilit spindle Feb 23, 2024, 7:59 PM

#

now can you repeat that for all of them? :)

safe radishBOT Feb 23, 2024, 8:13 PM

#

@strong bison Has your question been resolved?

safe radishBOT Feb 23, 2024, 8:28 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dark rock Feb 23, 2024, 8:37 PM

#

Hey, wanted help integrating
(x+2)/(2x+1)dx

safe radishBOT Feb 23, 2024, 8:37 PM

#

dark rock Hey, wanted help integrating (x+2)/(2x+1)dx

dark rock Feb 23, 2024, 8:38 PM

#

Tried splitting the integral:
S x/(2x+1)dx + 2 S dx/2x+1

#

the second one is no problems, but the first one is being annoying 🙂

eternal carbon Feb 23, 2024, 8:40 PM

#

dark rock Hey, wanted help integrating (x+2)/(2x+1)dx

the “splitting the integral” idea you have can be a place to start
you want to split the integral if a way such that you’re left with a rational function you know how to integrate directly, and a constant

dark rock Feb 23, 2024, 8:42 PM

#

yeah, but by doing so i think im mucking up the first integral, im making it worse

safe radishBOT Feb 23, 2024, 8:57 PM

#

@dark rock Has your question been resolved?

#

Channel closed

Closed by @dark rock

Use .reopen if this was a mistake.

safe radishBOT Feb 23, 2024, 9:16 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

halcyon light Feb 23, 2024, 9:19 PM

#

safe radishBOT Feb 23, 2024, 9:19 PM

#

halcyon light

halcyon light Feb 23, 2024, 9:19 PM

#

So I set up (2m+1)^2

#

expanded it

#

and showed it wasent divisible by three

#

however, the mark scheme shows this

#

does it have to be this way

#

or is my way also good

#

#

like how dyu even know 3k+1 is an odd integer

vast obsidian Feb 23, 2024, 9:21 PM

#

halcyon light however, the mark scheme shows this

This is what you did or is this the mark scheme?

halcyon light Feb 23, 2024, 9:21 PM

#

thats the mark scheme

vast obsidian Feb 23, 2024, 9:21 PM

#

It's good anyway

halcyon light Feb 23, 2024, 9:21 PM

#

i said what i did above

vast obsidian Feb 23, 2024, 9:21 PM

#

halcyon light and showed it wasent divisible by three

Idk how exactly you did that

halcyon light Feb 23, 2024, 9:22 PM

#

erm

#

i got 4m^2 +1

#

and like if i divide thos terms by three

#

i dont get whole integers

#

wait....

#

thats not right is it

#

that could return a whole integer

drowsy citrus Feb 23, 2024, 9:22 PM

#

No no

vast obsidian Feb 23, 2024, 9:22 PM

#

It's not immediately clear why it should be right

drowsy citrus Feb 23, 2024, 9:23 PM

#

@halcyon light the approach is correct only

halcyon light Feb 23, 2024, 9:23 PM

#

wdym the approach

drowsy citrus Feb 23, 2024, 9:23 PM

#

2m+1 approach

halcyon light Feb 23, 2024, 9:23 PM

#

oh yeah

#

i expand that

#

4m^2+1

#

then what would i do

#

oh wait

#

is expanding it wrong too?

halcyon light Feb 23, 2024, 9:24 PM

#

drowsy citrus <@417062541332840448> the approach is correct only

idk where ur supposed to go from there

vast obsidian Feb 23, 2024, 9:24 PM

#

halcyon light 4m^2+1

Where is the mixed term?

halcyon light Feb 23, 2024, 9:24 PM

#

fk

#

forgotten

#

ahhhh

#

4m^2+4m+1

#

ok

vast obsidian Feb 23, 2024, 9:24 PM

#

Yes

#

Tbh I wouldn't go on from here. The fact that the integer is odd doesn't really help you at all. It is enough to know that it is an integer not dividable by 3. The part that it is odd doesn't give you any helpful info

#

So there isn't really a point in introducing the k as you did

halcyon light Feb 23, 2024, 9:27 PM

#

i didnt introduce the k

#

the mark scheme did

halcyon light Feb 23, 2024, 9:27 PM

#

halcyon light 4m^2+4m+1

is this like

#

not right then?

vast obsidian Feb 23, 2024, 9:27 PM

#

Yeah, they introduced it as 3k +1 or 3k +2

#

That makes totally sense

halcyon light Feb 23, 2024, 9:28 PM

#

it dosent for me

#

N has to be an odd integer

#

if N = 3k+1

#

then its even no?

#

well like

#

it can be even

#

if i subbed in k = 1

#

i would get 10

vast obsidian Feb 23, 2024, 9:28 PM

#

Yes

vast obsidian Feb 23, 2024, 9:28 PM

#

halcyon light i would get 10

You would get 4

halcyon light Feb 23, 2024, 9:29 PM

#

ahhh

#

i meant 3

#

ohhhhh

vast obsidian Feb 23, 2024, 9:29 PM

#

But as I said the statement doesn't require that N is odd

halcyon light Feb 23, 2024, 9:29 PM

#

wait no

halcyon light Feb 23, 2024, 9:29 PM

#

halcyon light

it says here

#

N is an odd integer

vast obsidian Feb 23, 2024, 9:30 PM

#

Yes, but as I said the statement is also true for any arbitrary integer not dividable by 3

drowsy citrus Feb 23, 2024, 9:31 PM

#

halcyon light however, the mark scheme shows this

This quite feels wrong.

#

You guys mind if I help ?

halcyon light Feb 23, 2024, 9:31 PM

#

please haha

vast obsidian Feb 23, 2024, 9:31 PM

#

If you can show the statement for any integer that is not dividable by 3 you have showed it as well for the extra condition for n being odd

halcyon light Feb 23, 2024, 9:32 PM

#

I get that but

#

i dont get how does 3k+1 and 3k+2 cover any integer

#

wait

vast obsidian Feb 23, 2024, 9:32 PM

#

Any integer that is not dividable by 3

halcyon light Feb 23, 2024, 9:32 PM

#

or do i....

#

oh

#

right

#

ah i think i got it

#

thanksssss

vast obsidian Feb 23, 2024, 9:33 PM

#

You're welcome

halcyon light Feb 23, 2024, 9:33 PM

#

drowsy citrus This quite feels wrong.

im very curious though lol

drowsy citrus Feb 23, 2024, 9:34 PM

#

We know the number has to be odd == 2k+1. And it should not be a multiple of 3 n!=3(2k+1). This means n=3(2k+1)+2 or n=3(2k+1)+4

#

Now do whatever you want to do with this data.

#

PS: think and tell why n!=3(2k+1)+1 or 3(2k+1)+3

halcyon light Feb 23, 2024, 9:36 PM

#

oh wait

#

no i dunno

#

u havent proven

#

it cant equal that

vast obsidian Feb 23, 2024, 9:38 PM

#

drowsy citrus This quite feels wrong.

That's not wrong though. They showed a stronger version of the statement and the weaker version follows immediately. No point in making extra cases

drowsy citrus Feb 23, 2024, 9:38 PM

#

3k+1 is simply not odd, buddy.

halcyon light Feb 23, 2024, 9:39 PM

#

wait yeah i was thinking that as well

drowsy citrus Feb 23, 2024, 9:39 PM

#

Take k=1. One should not create ambiguity in the solution.

halcyon light Feb 23, 2024, 9:39 PM

#

but i was thinking they covered 3k+2

drowsy citrus Feb 23, 2024, 9:39 PM

#

If it's in a question, it works. But not in solution.

halcyon light Feb 23, 2024, 9:39 PM

#

which means if u have the same k value for both

#

then that covers both even and odd

#

inevitably

halcyon light Feb 23, 2024, 9:40 PM

#

drowsy citrus Take k=1. One should not create ambiguity in the solution.

is that right?

#

like

#

they did the 3k+2 as well

#

which would give u an odd number

#

yeah but then

#

if u plugged that into the 3k+1 u get even

drowsy citrus Feb 23, 2024, 9:42 PM

#

halcyon light they did the 3k+2 as well

You can consider two equations for the same number, right.

#

My case stands better foolproof.

#

Rather than 3k+1, it just gives you half of all possible cases of odd integers not divisible by 3. The other one igves the other half.

halcyon light Feb 23, 2024, 9:44 PM

#

drowsy citrus We know the number has to be odd == 2k+1. And it should not be a multiple of 3 ...

how does this prove that its not divisble by 3

drowsy citrus Feb 23, 2024, 9:44 PM

#

Check it no. You'll understand.

halcyon light Feb 23, 2024, 9:45 PM

#

i dont get it

#

to me u just assumed the statemet ur trying to prove is true

#

my brains prob gna explode

drowsy citrus Feb 23, 2024, 9:51 PM

#

See my first step was 2k+1 is always going to be odd. And if you multiply 3, an odd number, with 2k+1, another odd number, you'll always get an odd number as the answer. This number IS a multiple of 3 : 3(2k+1). 3(2k+1)+2 will always be odd and also not a multiple of 3

safe radishBOT Feb 23, 2024, 10:01 PM

#

@halcyon light Has your question been resolved?

halcyon light Feb 23, 2024, 10:02 PM

#

drowsy citrus See my first step was 2k+1 is always going to be odd. And if you multiply 3, an ...

Oh ok

#

Thx for ur input

#

.close

safe radishBOT Feb 23, 2024, 10:02 PM

#

Channel closed

Closed by @halcyon light

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

simple patio Feb 23, 2024, 10:18 PM

#

If I have two planes in a system in 3D. How would I get the solution to the system in a systematic way using uh pivots?

safe radishBOT Feb 23, 2024, 10:18 PM

#

simple patio If I have two planes in a system in 3D. How would I get the solution to the syst...

simple patio Feb 23, 2024, 10:21 PM

#

I just reasoned about the answer and that’s not enough apparently

#

Should I know concepts such as ”reduced row echelon form”?

safe radishBOT Feb 23, 2024, 10:43 PM

#

@simple patio Has your question been resolved?

safe radishBOT Feb 23, 2024, 10:58 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wide cloud Feb 23, 2024, 11:11 PM

#

anyone know why this wont work.

safe radishBOT Feb 23, 2024, 11:11 PM

#

wide cloud anyone know why this wont work.

#

@wide cloud Has your question been resolved?

safe radishBOT Feb 24, 2024, 12:07 AM

#

@wide cloud Has your question been resolved?

safe radishBOT Feb 24, 2024, 1:22 AM

#

@wide cloud Has your question been resolved?

wide cloud Feb 24, 2024, 1:48 AM

#

.close

safe radishBOT Feb 24, 2024, 1:48 AM

#

Channel closed

Closed by @wide cloud

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 3:48 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

verbal oasis Feb 24, 2024, 4:04 AM

#

safe radishBOT Feb 24, 2024, 4:04 AM

#

verbal oasis

verbal oasis Feb 24, 2024, 4:04 AM

#

How do i do this question?

#

what i have so far is equating S2n

#

that the 2 middle terms equate to s+l

hot thistle Feb 24, 2024, 4:05 AM

#

do you know the usual formula for the sum of the first n terms

hot thistle Feb 24, 2024, 4:06 AM

#

verbal oasis that the 2 middle terms equate to s+l

can you show this in writing

verbal oasis Feb 24, 2024, 4:07 AM

#

hot thistle do you know the usual formula for the sum of the first n terms

ye n/2 * (2a + (n-1)*d)

verbal oasis Feb 24, 2024, 4:07 AM

#

hot thistle can you show this in writing

wdym

hot thistle Feb 24, 2024, 4:08 AM

#

verbal oasis ye n/2 * (2a + (n-1)*d)

so what would this be for the first 2n terms

verbal oasis Feb 24, 2024, 4:08 AM

#

it simplifies to 2an+2dn^2-dn

#

if i did it right

hot thistle Feb 24, 2024, 4:09 AM

#

yes, but im going to not factor the (n) [\frac{2n}{2}(2a + (2n - 1)d) = n(2a + 2nd - d)]

flat frigateBOT Feb 24, 2024, 4:09 AM

#

maximo

verbal oasis Feb 24, 2024, 4:10 AM

#

so i just need to prove a+l = 2a + 2nd -d

hot thistle Feb 24, 2024, 4:10 AM

#

what is a + l

verbal oasis Feb 24, 2024, 4:10 AM

#

uh the sum of the first and last numbers

hot thistle Feb 24, 2024, 4:10 AM

#

why the first and last

verbal oasis Feb 24, 2024, 4:11 AM

#

i thought the sum of the middle 2 terms would be equal to the first and last

hot thistle Feb 24, 2024, 4:11 AM

#

yeah it does
if you can just say that then yes that is what you need to do

#

otherwise just find an expression for the two middle terms and show their sum is the thing in the parentheses

verbal oasis Feb 24, 2024, 4:12 AM

#

how would u find the expression for the two middle terms

#

i thought about n/2 but that just finds one singular middle term

hot thistle Feb 24, 2024, 4:12 AM

#

im aware, im saying that if they are writing a proof and they want to just say that, they should make sure it is known ahead of time

hot thistle Feb 24, 2024, 4:13 AM

#

verbal oasis i thought about n/2 but that just finds one singular middle term

suppose you have 4 terms
the middle 2 are the 2nd and 3d
suppose you have 8
the middle 2 are the 4th and 5th
generalize this and you'll see you need the (n/2)-th and (1 + (n/2))-th terms

verbal oasis Feb 24, 2024, 4:14 AM

#

hot thistle suppose you have 4 terms the middle 2 are the 2nd and 3d suppose you have 8 the ...

oh i c

#

what if u have an odd number of terms tho

#

or does that not apply since the series goes on forever

#

ah

#

ok thank you for your help guys

#

i understand the question now :)

#

.close

safe radishBOT Feb 24, 2024, 4:17 AM

#

Channel closed

Closed by @verbal oasis

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 4:32 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silver flare Feb 24, 2024, 4:38 AM

#

how do I convert this function to a solow model function so that it only has K?

Screenshot_2024-02-23_at_11.38.24_PM.png

safe radishBOT Feb 24, 2024, 4:38 AM

#

silver flare how do I convert this function to a solow model function so that it only has K?

#

@silver flare Has your question been resolved?

safe radishBOT Feb 24, 2024, 5:23 AM

#

@silver flare Has your question been resolved?

safe radishBOT Feb 24, 2024, 5:53 AM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

lean otter Feb 24, 2024, 5:59 AM

#

thonk channel not deleted with original message getting deleted

#

.close

safe radishBOT Feb 24, 2024, 5:59 AM

#

Channel closed

Closed by @tropic oriole

Use .reopen if this was a mistake.

lean otter Feb 24, 2024, 5:59 AM

#

wtf

plucky elk Feb 24, 2024, 6:05 AM

#

yea mod bans do that. that's why 99.99% of time they close them

safe radishBOT Feb 24, 2024, 6:07 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean otter Feb 24, 2024, 6:12 AM

#

Hello can someone help me out

safe radishBOT Feb 24, 2024, 6:12 AM

#

lean otter Hello can someone help me out

lean otter Feb 24, 2024, 6:12 AM

#

Let me post the question

#

Give me one second

#

Okay so

#

By the comparison theorem

#

I have to determine whether this is divergent or convergent

#

Im having trouble finding a function to compare it to

plucky elk Feb 24, 2024, 6:16 AM

#

compare highest powers of numerator and denominator

lean otter Feb 24, 2024, 6:18 AM

#

Okay

#

1/sqrtx?

#

Or 1/x^3/2

#

@plucky elk

plucky elk Feb 24, 2024, 6:25 AM

#

neither

#

you can safely ignore the -x in the denominator

restive niche Feb 24, 2024, 6:30 AM

#

What you sent was correct

#

Idk why you deleted it

lean otter Feb 24, 2024, 6:30 AM

#

1/x?

restive niche Feb 24, 2024, 6:30 AM

#

Yeah

lean otter Feb 24, 2024, 6:33 AM

#

Okay so now I have to figure out whether or not the given integral is less than or greater than 1/x

#

And then whether the comparison converges or diverges

#

(x+1)/sqrt(x^4-x) >= 1/x

#

1/x diverges

#

So the original integral diverges

#

Is that the proper way to work through this problem

#

.close

safe radishBOT Feb 24, 2024, 6:51 AM

#

Channel closed

Closed by @tender axle

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lilac relic Feb 24, 2024, 7:14 AM

#

hello, can someone explain to me how to figure out:

log abc (abc are inside a square root)

safe radishBOT Feb 24, 2024, 7:14 AM

#

lilac relic hello, can someone explain to me how to figure out: log abc (abc are inside a s...

lilac relic Feb 24, 2024, 7:15 AM

#

my notes are not satisfactory to be of any help

plucky elk Feb 24, 2024, 7:15 AM

#

lilac relic hello, can someone explain to me how to figure out: log abc (abc are inside a s...

$\log(\sqrt{abc})$ ?

drowsy citrus Feb 24, 2024, 7:15 AM

#

Figure out what ?

flat frigateBOT Feb 24, 2024, 7:15 AM

#

riemann

lilac relic Feb 24, 2024, 7:15 AM

#

ye

#

no brackets tho

#

I just want an explanation on how to do it

#

I don't want an answer

drowsy citrus Feb 24, 2024, 7:17 AM

#

Write the square root as $abc^{(1/2)}$. Then take the 1/2 outside. And then split the $\log(abc) = \log a+\log b+ \log c$

flat frigateBOT Feb 24, 2024, 7:18 AM

#

Solomaniac

lilac relic Feb 24, 2024, 7:19 AM

#

okay... I think I understand

#

.close

safe radishBOT Feb 24, 2024, 7:19 AM

#

Channel closed

Closed by @lilac relic

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 7:34 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lilac relic Feb 24, 2024, 7:55 AM

#

here's another

log (x^2 + x + 3) = log 9 + log (x - 1)

safe radishBOT Feb 24, 2024, 7:55 AM

#

lilac relic here's another log (x^2 + x + 3) = log 9 + log (x - 1)

lilac relic Feb 24, 2024, 7:55 AM

#

I might have done it wrong because I've ended up factorising it and I can't make 10 out of 120

#

as far as I can see

potent seal Feb 24, 2024, 7:56 AM

#

Could you show your work

lilac relic Feb 24, 2024, 7:56 AM

#

ok

#

(x^2 + x +3) = 9*(x-1)
(x^2 + x + 3) = 9x-9
x^2 + x + 3 = 9x - 9
x^2 + x + 12 = 9x
x^2 + 10x + 12

10 * 12 = 120
5 * 25
4 * 30
6 * 20
8 * 15
10 * 12

terse lichen Feb 24, 2024, 8:00 AM

#

9x is positive on the right

#

if you move it to the left it will be negative

#

you added instead of subtracted

lilac relic Feb 24, 2024, 8:01 AM

#

oh?

terse lichen Feb 24, 2024, 8:01 AM

#

x^2 + x + 12 = 9x
x^2 + 10x + 12 = 0

lilac relic Feb 24, 2024, 8:01 AM

#

that could be my problem then

terse lichen Feb 24, 2024, 8:01 AM

#

see the problem?

lilac relic Feb 24, 2024, 8:02 AM

#

yes

#

I'll fix that and see what happens

thin bridge Feb 24, 2024, 8:03 AM

#

also why are you considering the value of bc

lilac relic Feb 24, 2024, 8:09 AM

#

thin bridge also why are you considering the value of bc

wdym

lilac relic Feb 24, 2024, 8:10 AM

#

terse lichen x^2 + x + 12 = 9x x^2 + 10x + 12 = 0

I'm still having problems

#

10 * 2

thin bridge Feb 24, 2024, 8:10 AM

#

how are you getting the -10x

lilac relic Feb 24, 2024, 8:11 AM

#

I'm not getting -10x

#

I'm getting positve

thin bridge Feb 24, 2024, 8:11 AM

#

misead something

#

where's 10 * 2 coming from

lilac relic Feb 24, 2024, 8:11 AM

#

just trying to factorise the last part

thin bridge Feb 24, 2024, 8:12 AM

#

continue from

x^2 + x + 12 = 9x

lilac relic Feb 24, 2024, 8:12 AM

#

now it's x^2 + 10x +2

thin bridge Feb 24, 2024, 8:12 AM

#

is incorrect

lilac relic Feb 24, 2024, 8:12 AM

#

yes

lilac relic Feb 24, 2024, 8:15 AM

#

thin bridge continue from > x^2 + x + 12 = 9x

but now I'm getting x^2 + 10x + 12 again

#

which is weird

thin bridge Feb 24, 2024, 8:15 AM

#

show work

#

also equations don't become expressions

lilac relic Feb 24, 2024, 8:16 AM

#

lilac relic here's another log (x^2 + x + 3) = log 9 + log (x - 1)

so am I doing this question wrong?

thin bridge Feb 24, 2024, 8:16 AM

#

continue from
x^2 + x + 12 = 9x

lilac relic Feb 24, 2024, 8:16 AM

#

cause I thought it would be easier if I got rid of the log

thin bridge Feb 24, 2024, 8:16 AM

#

stuff upto that line is valid

#

recall basic principles such as doing the same thing to both sides of the equation
consider what you could do to 9x to get 0
and do that to both sides of the equation

lilac relic Feb 24, 2024, 8:19 AM

#

so

x^2 - 8x + 12?

terse lichen Feb 24, 2024, 8:19 AM

#

yes

thin bridge Feb 24, 2024, 8:20 AM

#

also equations don't become expressions

#

= 0

lilac relic Feb 24, 2024, 8:20 AM

#

x^2 - 8x + 12 = 0

#

I've spent the whole day working and my mind is a bit fried so that's why I keep making mistakes I think

#

I still can't get good number out of it

I've tried

2 x 48
3 x 32
4 x 24
6 x 16
8 x 12

none of them match to make -8

#

you know what

#

I might just stop

#

thanks for the help

#

.close

safe radishBOT Feb 24, 2024, 8:26 AM

#

Channel closed

Closed by @lilac relic

Use .reopen if this was a mistake.

lilac relic Feb 24, 2024, 8:26 AM

#

.reopen

thin bridge Feb 24, 2024, 8:26 AM

#

lilac relic I still can't get good number out of it I've tried 2 x 48 3 x 32 4 x 24 6 x ...

the issue is you're considering bc

safe radishBOT Feb 24, 2024, 8:26 AM

#

✅

thin bridge Feb 24, 2024, 8:26 AM

#

why are you considering products that multiply to bc or -bc

#

i.e. why are you multiplying the 8 to the 12

lilac relic Feb 24, 2024, 8:27 AM

#

oh, well then I might have been treating this questions as the wrong type of factorising question

#

the simple ones are when you go middle * end number

thin bridge Feb 24, 2024, 8:28 AM

#

no

left gyro Feb 24, 2024, 8:28 AM

#

to factor ax^2 + bx + c,

lilac relic Feb 24, 2024, 8:28 AM

#

but it could be in this case 1 * 12

left gyro Feb 24, 2024, 8:28 AM

#

you multiply a * c

lilac relic Feb 24, 2024, 8:28 AM

#

yeah

left gyro Feb 24, 2024, 8:28 AM

#

you do not multiply b * c

thin bridge Feb 24, 2024, 8:28 AM

#

you're confusing ac with bc

left gyro Feb 24, 2024, 8:28 AM

#

so to factor 1x^2 - 8x + 12,

#

you multiply 1 and 12 together

#

to get 12

#

now you consider what numbers add to -8 and multiply to 12

#

in other words, two numbers G and H that:
G + H = -8
G * H = 12

lilac relic Feb 24, 2024, 8:30 AM

#

yes I understand the factorising

left gyro Feb 24, 2024, 8:30 AM

#

and its already enough to go through possible numbers for G and H

lilac relic Feb 24, 2024, 8:30 AM

#

cause there's two ways to do it that I'm aware of

left gyro Feb 24, 2024, 8:31 AM

#

which are?

thin bridge Feb 24, 2024, 8:34 AM

#

no

lilac relic Feb 24, 2024, 8:34 AM

#

I'm not finished

#

I misclicked

thin bridge Feb 24, 2024, 8:34 AM

#

its already wrong

#

that's why i'm saying no as there's no need to contune

lilac relic Feb 24, 2024, 8:36 AM

#

?, lol. I need to speak to my teacher about this. it seems that I've forgotten how to factorise properly.

thin bridge Feb 24, 2024, 8:36 AM

#

as mentione by us, at no point should you be multiplying b by c

lilac relic Feb 24, 2024, 8:36 AM

#

okay

#

because of ax^2 + bx + c

#

it's just that I always used to factorise like that and I got it right. unless I'm remembering wrong

thin bridge Feb 24, 2024, 8:37 AM

#

when factorising
ax^2 + bx + c
you can consider the pair of values that
multiply to ac
and sum to b
to determine how to split the middle bx term
for monic quadratics, the value of a is just 1

#

so you'd just be looking for the pair of values that multiply to c and sum to b

lilac relic Feb 24, 2024, 8:39 AM

#

yeah like for 8x^2 + 10x - 3 = 0

you would go 8 times -3

#

then it would be 8x^2 + 12x - 2x -3 = 0

#

then 4x(2x+3) - 1(2x+3) = 0

thin bridge Feb 24, 2024, 8:40 AM

#

yes

lilac relic Feb 24, 2024, 8:40 AM

#

etc etc

#

that in my understanding was just the way to factorise when there was a number before the x^2

#

but it seems like that isn't the case

thin bridge Feb 24, 2024, 8:40 AM

#

it is

lilac relic Feb 24, 2024, 8:41 AM

#

wait what did I just say?

thin bridge Feb 24, 2024, 8:41 AM

#

1x^2 - 8x + 12,
the number in front of the x^2 just isn't -8

lilac relic Feb 24, 2024, 8:41 AM

#

yes

#

yes

thin bridge Feb 24, 2024, 8:41 AM

#

the same approach is applicable if you use 1 for the value of a

lilac relic Feb 24, 2024, 8:43 AM

#

ye

thin bridge Feb 24, 2024, 8:43 AM

#

given the quadratic is nicely factorisable, the above method you outlined will work.

lilac relic Feb 24, 2024, 8:45 AM

#

oh I think what I did before actually for questions such as x^2 +7x + 12 was to just use the c term to find out the factorising

#

not b and c

#

that's why I'm getting confused

#

because 3 and 4 make 12. 3+4 make 7

thin bridge Feb 24, 2024, 8:46 AM

#

yes

lilac relic Feb 24, 2024, 8:46 AM

#

then (x+3)(x+4)

#

yeah

#

lol, oh well.

#

well thank you chaps for clearing that up and helping me. I've had a bit of a moment

#

I should have just looked further into my notes book

#

I'll close it down

#

.close

safe radishBOT Feb 24, 2024, 8:49 AM

#

Channel closed

Closed by @lilac relic

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 9:04 AM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

void spruce Feb 24, 2024, 9:07 AM

#

a committee of 5 is to be chosen from 6 men and 8 women. find how many committees are possible, if
i) the committee will consist of 3 men and 2 women
ii) there is at least one woman on the committee

safe radishBOT Feb 24, 2024, 9:07 AM

#

void spruce a committee of 5 is to be chosen from 6 men and 8 women. find how many committee...

lean otter Feb 24, 2024, 9:09 AM

#

i) 5C3×6C2

magic junco Feb 24, 2024, 9:10 AM

#

!nosols

safe radishBOT Feb 24, 2024, 9:10 AM

#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lean otter Feb 24, 2024, 9:12 AM

#

For second one use the same formula as 1 work out for the possibilities of different combinations possible for atleast one woman. For example 8C1 × 6C4 is the possibility of choosing one woman rest all men. Similarly do for 2,3...3,2...4,1...5,0

safe radishBOT Feb 24, 2024, 9:22 AM

#

@void spruce Has your question been resolved?

#

Channel closed

Closed by @void spruce

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vestal fable Feb 24, 2024, 9:43 AM

#

safe radishBOT Feb 24, 2024, 9:43 AM

#

vestal fable

vestal fable Feb 24, 2024, 9:44 AM

#

how can i make that little triangle point toward my cursor

#

ignore the programming part just give me a formula or smthing

#

ping me replying

safe radishBOT Feb 24, 2024, 10:09 AM

#

@vestal fable Has your question been resolved?

turbid swan Feb 24, 2024, 10:12 AM

#

vestal fable ping me replying

isn't it already aiming at your mouse?

#

or you want it to rotate about a fixed point

vestal fable Feb 24, 2024, 10:12 AM

#

yea

#

it should rotate to cursor

turbid swan Feb 24, 2024, 10:13 AM

#

the simplest way I'd think is calculating the tangent to angle between the mouse pos and the centre of the screen but since it's computers they're likely to mess up for π/2

spark bridge Feb 24, 2024, 10:14 AM

#

you can use atan2

#

i think it has support for weird cases

turbid swan Feb 24, 2024, 10:14 AM

#

wow is that even a thing?

spark bridge Feb 24, 2024, 10:15 AM

#

https://en.wikipedia.org/wiki/Atan2

Atan2

In computing and mathematics, the function atan2 is the 2-argument arctangent. By definition,

    θ
    =
    atan2
    ⁡
    (
    y
    ,
    x
    )
  

{\displaystyle \theta =\operatorname {atan2} (y,x)}

is the angle measure (in radians, with

    −
   ...

vestal fable Feb 24, 2024, 10:15 AM

#

sorry i dont know any geometry

spark bridge Feb 24, 2024, 10:15 AM

#

most programming languages have atan2 implemented

#

in a library

turbid swan Feb 24, 2024, 10:15 AM

#

i think the one they're using is js or ts since it's web

vestal fable Feb 24, 2024, 10:15 AM

#

js

turbid swan Feb 24, 2024, 10:15 AM

#

and they're the craziest bunch of languages

vestal fable Feb 24, 2024, 10:16 AM

#

so what do i do with atan2

turbid swan Feb 24, 2024, 10:16 AM

#

just do what i said but use atan2 instead of atan

#

define a fixed position for the arrow thing, get your mouse position and calculate the angle between them

safe radishBOT Feb 24, 2024, 10:46 AM

#

@vestal fable Has your question been resolved?

vestal fable Feb 24, 2024, 11:12 AM

#

turbid swan define a fixed position for the arrow thing, get your mouse position and calcula...

hello

#

i tried somethings

#

didnt work

#

i have like 0 geometry knowledge

#

i dont even know what tangent is

safe radishBOT Feb 24, 2024, 12:17 PM

#

@vestal fable Has your question been resolved?

pulsar pecan Feb 24, 2024, 1:49 PM

#

vestal fable i dont even know what tangent is

you can try starting from here https://youtu.be/g8VCHoSk5_o?si=F5C4Ft_xmWjriWZY

YouTube

The Organic Chemistry Tutor

Trigonometry

This video tutorial provides a basic intro into trigonometry. It explains how to evaluate trigonometric functions like sin, cos, and tan using soh cah toa and right triangle trigonometry. It explains how to use reference angles and coterminal angles to evaluate trig functions such as sec, csc, and cot.

Access Full-Length Premium Videos: ...

▶ Play video

vestal fable Feb 24, 2024, 1:49 PM

#

oh forgot about here

#

my problem is resolved

vestal fable Feb 24, 2024, 1:50 PM

#

pulsar pecan you can try starting from here https://youtu.be/g8VCHoSk5_o?si=F5C4Ft_xmWjriWZY

and i will check this out

#

.close

safe radishBOT Feb 24, 2024, 1:50 PM

#

Channel closed

Closed by @vestal fable

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 3:50 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#

lean otter Feb 24, 2024, 3:57 PM

#

I want to say D3

dapper venture Feb 24, 2024, 3:58 PM

#

what are the rules for the game

#

connect 4?

safe radishBOT Feb 24, 2024, 4:12 PM

#

@lean otter Has your question been resolved?

lean otter Feb 24, 2024, 4:13 PM

#

dapper venture connect 4?

yea

dapper venture Feb 24, 2024, 4:15 PM

#

if you play D3 blue will play E3

buoyant shadow Feb 24, 2024, 4:15 PM

#

it doesn't say connect 4

#

why are you so certain @lean otter

lean otter Feb 24, 2024, 4:16 PM

#

buoyant shadow why are you so certain <@456226577798135808>

i editted out

lean otter Feb 24, 2024, 4:16 PM

#

dapper venture if you play D3 blue will play E3

ohhhh shit

#

i didnt see that

lean otter Feb 24, 2024, 4:17 PM

#

dapper venture if you play D3 blue will play E3

so its e3?

buoyant shadow Feb 24, 2024, 4:17 PM

#

interesting

#

it's d3

dapper venture Feb 24, 2024, 4:18 PM

#

wait I don't think you can win

buoyant shadow Feb 24, 2024, 4:18 PM

#

yeah, you can't win

#

so d3 makes sense

hybrid wedge Feb 24, 2024, 4:19 PM

#

dapper venture wait I don't think you can win

Can it be a draw?

dapper venture Feb 24, 2024, 4:20 PM

#

no

#

you must play B6,E3 or F2 to block

#

then blue plays B3, we must play B2, and D3 is unstoppable

lean otter Feb 24, 2024, 4:25 PM

#

@buoyant shadow @dapper venture @hybrid wedge

#

The question is specifically:

#

What should you move to avoid losing the game

#

im pretty sure the move is E3

#

no that doesnt work

dapper venture Feb 24, 2024, 4:27 PM

#

you eventually loses

lean otter Feb 24, 2024, 4:27 PM

#

as wherewolf stated

dapper venture Feb 24, 2024, 4:27 PM

#

blue plays B3

lean otter Feb 24, 2024, 4:28 PM

#

dapper venture blue plays B3

how does that end in loss

#

if blue B3 I B2

dapper venture Feb 24, 2024, 4:28 PM

#

then D3

lean otter Feb 24, 2024, 4:28 PM

#

A3

hybrid wedge Feb 24, 2024, 4:28 PM

#

A3?

dapper venture Feb 24, 2024, 4:28 PM

#

both A4 and D6 needs to be blocked

#

A4 and D6 connects 4

hybrid wedge Feb 24, 2024, 4:29 PM

#

Yeah i forgot D6

dapper venture Feb 24, 2024, 4:29 PM

#

oh A3 mb

lean otter Feb 24, 2024, 4:29 PM

#

or maybe the question is all about just one move ?

#

that would be silly tho

lean otter Feb 24, 2024, 4:30 PM

#

dapper venture both A4 and D6 needs to be blocked

wait huh

dapper venture Feb 24, 2024, 4:31 PM

#

I meant A3

lean otter Feb 24, 2024, 4:31 PM

#

the line

#

Green E3

#

Blue B3

#

Green B2

#

Oh wait

#

yep

#

Blue D6 ends the game

#

B3 is just wining for blue after stopping to to form diagonal connect 4

#

yea its over at that move technically

#

cause it forces b2

#

i think the answer is E3 still

#

how do you have to enter the answer tho ?

#

forces a game that doesn end after one more move

safe radishBOT Feb 24, 2024, 4:34 PM

#

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

lean otter Feb 24, 2024, 4:35 PM

#

lean otter forces a game that doesn end after one more move

yeah

#

bruh

#

ok

safe radishBOT Feb 24, 2024, 4:39 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

safe radishBOT Feb 24, 2024, 4:58 PM

#

flat frigateBOT Feb 24, 2024, 4:58 PM

#

amine-50
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vague token Feb 24, 2024, 4:58 PM

#

$ Suppose ( |A|_1 ) (the first norm of matrix ( A )) is found to be ( 3 ). Now, how can I find the first norm of ( A^{-1} ) without explicitly calculating ( A^{-1} )?

safe radishBOT Feb 24, 2024, 4:59 PM

#

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

vague token Feb 24, 2024, 5:00 PM

#

.close

safe radishBOT Feb 24, 2024, 5:35 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vocal terrace Feb 24, 2024, 5:36 PM

#

hey, how would you model that function? it kinda looks like a shifted hyperbola but then there's the negative x values that would act differently

safe radishBOT Feb 24, 2024, 5:36 PM

#

vocal terrace hey, how would you model that function? it kinda looks like a shifted hyperbola ...

vocal terrace Feb 24, 2024, 5:37 PM

#

same question goes for this function

#

thanks guys

#

I mean I don't need a perfect fit, just a function it resembles

safe radishBOT Feb 24, 2024, 5:56 PM

#

@vocal terrace Has your question been resolved?

safe radishBOT Feb 24, 2024, 6:11 PM

#

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hidden drift Feb 24, 2024, 6:25 PM

#

safe radishBOT Feb 24, 2024, 6:25 PM

#

hidden drift

hidden drift Feb 24, 2024, 6:26 PM

#

hi how can i get the value of m knowing the vertex is those two points given there

left gyro Feb 24, 2024, 6:28 PM

#

do you have any more information about m and n

#

or about k(x)

#

rn you wont be able to solve for the values of m and n

icy lance Feb 24, 2024, 6:28 PM

#

i think its doable

left gyro Feb 24, 2024, 6:29 PM

#

yea I made a mistake, its doable

left gyro Feb 24, 2024, 6:31 PM

#

hidden drift

remember that:
vertex's x-coordinate = -b/(2a)
then enter in the information the problem has:

vertex's x-coordinate = -1/2
a = m
b = -1

-1/2 = -(-1)/(2m)

this gives you an equation to solve for m

left gyro Feb 24, 2024, 6:31 PM

#

hidden drift hi how can i get the value of m knowing the vertex is those two points given the...

editing the post to say "two points" instead of "one point" does not change the fact htat there is only one point in the problem

hidden drift Feb 24, 2024, 6:33 PM

#

left gyro editing the post to say "two points" instead of "one point" does not change the ...

oh i didnt edit that part

hidden drift Feb 24, 2024, 6:34 PM

#

left gyro remember that: vertex's x-coordinate = -b/(2a) then enter in the information the...

oh i get it

#

so like -b/2a = -1/2

left gyro Feb 24, 2024, 6:34 PM

#

yea

hidden drift Feb 24, 2024, 6:36 PM

#

in this equation b already has a negative in front

#

that would make it postive right?

safe radishBOT Feb 24, 2024, 6:51 PM

#

@hidden drift Has your question been resolved?

#

Channel closed

Closed by @hidden drift

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 8:42 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

placid garnet Feb 24, 2024, 9:00 PM

#

Hello, my question is rather simple i just want to know the theory behind to why when you want to find the shortest path between two points like here you subtract with eachother (OQ -OP) Why is that done?

safe radishBOT Feb 24, 2024, 9:00 PM

#

placid garnet Hello, my question is rather simple i just want to know the theory behind to why...

placid garnet Feb 24, 2024, 9:01 PM

#

if something is unclear because its written in swedish ask!

harsh nova Feb 24, 2024, 9:01 PM

#

Do you know how vectors add?

#

In R^2, how would you add two vectors?

#

After answering that

#

You can draw some two vectors x,y in R^2

#

Then figure out how to reach Oy from Ox

placid garnet Feb 24, 2024, 9:05 PM

#

Ahhhh i know how to solve now

#

thanks

#

.close

safe radishBOT Feb 24, 2024, 9:06 PM

#

Channel closed

Closed by @placid garnet

Use .reopen if this was a mistake.

safe radishBOT Feb 24, 2024, 9:21 PM

#

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hard mortar Feb 24, 2024, 9:24 PM

#

how do I solve this: $$L=\lim _{a\to \infty }\int _a^{a+1}\frac{x+1}{\sqrt{x^2+1}}dx$$

safe radishBOT Feb 24, 2024, 9:24 PM

#

hard mortar how do I solve this: $$L=\lim _{a\to \infty }\int _a^{a+1}\frac{x+1}{\sqrt{x^2+1...

flat frigateBOT Feb 24, 2024, 9:24 PM

#

TubyconB

dusk gate Feb 24, 2024, 9:27 PM

#

#

You'll still have to solve the integral of 1/sqrt(x^2+1), but that's a textbook integral, so...

hard mortar Feb 24, 2024, 9:29 PM

#

dusk gate

it's a limit

dusk gate Feb 24, 2024, 9:29 PM

#

L'Hopital

hard mortar Feb 24, 2024, 9:29 PM

#

I don't think finding the antiderivative will help

dusk gate Feb 24, 2024, 9:29 PM

#

😉 Missed the "lim" at the front, lol

hard mortar Feb 24, 2024, 9:29 PM

#

np

dusk gate Feb 24, 2024, 9:30 PM

#

So you end up with infinity/infinity...

hard mortar Feb 24, 2024, 9:30 PM

#

but yeah I haven't really encountered that kind of integral before

dusk gate Feb 24, 2024, 9:30 PM

#

take the derivative of the numerator and the denominator separately

#

if you still have an indeterminate form, do it again

#

rinse, repeat until it becomes evident that the limit converges or diverges

hard mortar Feb 24, 2024, 9:31 PM

#

I am supposed to solve this one with an inequality

dusk gate Feb 24, 2024, 9:32 PM

#

But after the first iteration, it should be evident that the limit is (probably) 0

mint flint Feb 24, 2024, 9:32 PM

#

hard mortar I don't think finding the antiderivative will help

what whynot

dusk gate Feb 24, 2024, 9:32 PM

#

Since the fraction is bottom-heavy

#

Ehh.. or is it.. looks closer

hard mortar Feb 24, 2024, 9:33 PM

#

mint flint what whynot

I am supposed to find an inequality here somewhere

dusk gate Feb 24, 2024, 9:33 PM

#

No.. use L'Hopital's Rule

#

you have the indeterminate form of infinity/infinity

mint flint Feb 24, 2024, 9:33 PM

#

but there's an integral

hard mortar Feb 24, 2024, 9:33 PM

#

I am not supposed to solve the integral for this

dusk gate Feb 24, 2024, 9:34 PM

#

hard mortar I am not supposed to solve the integral for this

That depends on whether or not the limit converges or diverges

hard mortar Feb 24, 2024, 9:34 PM

#

yeah the point is to find something along the lines of (something) <= (the integral function)

dusk gate Feb 24, 2024, 9:34 PM

#

If the limit is undefined, then there will be no solution

#

i.e., if the limit explodes off to infinity, then the area under the curve is infinite

mint flint Feb 24, 2024, 9:35 PM

#

hard mortar yeah the point is to find something along the lines of (something) <= (the integ...

ah

hard mortar Feb 24, 2024, 9:35 PM

#

hard mortar yeah the point is to find something along the lines of (something) <= (the integ...

after doing that, I can find the limit of (something) as x approaches infinity

#

and it that is equal to infinity

#

then the integral limit will equal infinity too

#

I think

mint flint Feb 24, 2024, 9:35 PM

#

mmm

#

well

#

just from looking at it

#

the integrand will approach y=1

#

so wouldn't that make the area limit also 1

dusk gate Feb 24, 2024, 9:36 PM

#

If a is approaching infinity, you first have to ask... what is a?

hard mortar Feb 24, 2024, 9:37 PM

#

mint flint so wouldn't that make the area limit also 1

I don't know, just started integrals

mint flint Feb 24, 2024, 9:37 PM

#

im not using any integral techniques here

dusk gate Feb 24, 2024, 9:37 PM

#

They kinda shit on you right out of the gate, didn't they

hard mortar Feb 24, 2024, 9:37 PM

#

I haven't been taught that integrals find the area under a curve yet

mint flint Feb 24, 2024, 9:37 PM

#

oh

dusk gate Feb 24, 2024, 9:37 PM

#

hard mortar I haven't been taught that integrals find the area under a curve yet

o.O

#

Oh...

mint flint Feb 24, 2024, 9:37 PM

#

why dont they teach you that...

#

before they give u these problems

hard mortar Feb 24, 2024, 9:37 PM

#

because you don't need to know that

#

apparently

mint flint Feb 24, 2024, 9:38 PM

#

hm

dusk gate Feb 24, 2024, 9:38 PM

#

ehhh

mint flint Feb 24, 2024, 9:38 PM

#

so what do you know about integrals

#

i mean you have to know something righ

#

to do this problem

hard mortar Feb 24, 2024, 9:38 PM

#

yeah I know how to solve them

#

sometimes

mint flint Feb 24, 2024, 9:39 PM

#

this problem would be really easy if not for all these restrictions 😭

hard mortar Feb 24, 2024, 9:39 PM

#

flat frigate **TubyconB**

but the point of this is to find an inequality

#

from the function inside the integral

#

maybe a minimum and maximum value

#

then integrate the inequality

#

what confuses me is the limit

dusk gate Feb 24, 2024, 9:40 PM

#

Hold up

#

infinity + 1 is just infinity

#

the limit is in terms of a, not x

#

the integral is a red herring

mint flint Feb 24, 2024, 9:41 PM

#

but the problem is that gives you inf-inf

#

which is indeterminant

#

bc of how u evaluate integrals

dusk gate Feb 24, 2024, 9:42 PM

#

mint flint but the problem is that gives you inf-inf

What's the limit of any function as it approaches infinity?

mint flint Feb 24, 2024, 9:42 PM

#

??

#

what

dusk gate Feb 24, 2024, 9:42 PM

#

Look at his original problem

mint flint Feb 24, 2024, 9:42 PM

#

i am

dusk gate Feb 24, 2024, 9:43 PM

#

if this were the limit as x approaches infinity, that would be one thing

#

But this isn't

mint flint Feb 24, 2024, 9:43 PM

#

right

#

so?

#

it is in terms of a

dusk gate Feb 24, 2024, 9:43 PM

#

infinity + 1 = infinity

#

unless I'm horribly forgetting my limit rules

#

everything to the right of this section is pretty much irrelevant

mint flint Feb 24, 2024, 9:44 PM

#

i mean

#

i guess i see what ur saying

dusk gate Feb 24, 2024, 9:44 PM

#

since the limit is not in terms of anything found in the function

mint flint Feb 24, 2024, 9:44 PM

#

i just checked with a graphing calculator tho and that method doesnt work

dusk gate Feb 24, 2024, 9:45 PM

#

There is no "a" in the function

mint flint Feb 24, 2024, 9:45 PM

#

because the fact that a is part of an integral implies that you have to subtract the as