help-23

[lean otter]

👌

[vernal zephyr]

a factor??

i will sometime for sure

[lean otter]

yes

u should

💀

[vernal zephyr]

why do i get an indian vibe from you

[lean otter]

whaaattttttttt

[vernal zephyr]

usually indians have pfps from google

idk

[lean otter]

no actually why do u

ur pfp from google

cant tell me thats actually u

r u indian

[tight void]

well yeah but it includes 1 and itself

[vernal zephyr]

forgive me if im wrong!!!!!!

[lean otter]

penguin pfp from google

is penguin indian

penguin r u indian

[tight void]

my parents are from the middle east

maybe Asian?

idk

[lean otter]

yh thats asian

[vernal zephyr]

no i mean this kind of pfps in which like there are people

[lean otter]

but u was born int he states?

[vernal zephyr]

like someone elses

[tight void]

yeah ofc

[lean otter]

ohh fair

[vernal zephyr]

picture

[lean otter]

im pakistani

[vernal zephyr]

and you put it on ur acc

[lean otter]

born there but havent been back in 16 yrs now

[vernal zephyr]

🤯

[tight void]

alana are your parents proud of you

be honest

[lean otter]

oh, theres a reason i have this one

[vernal zephyr]

i think you rlly are my sister

[tight void]

ong

[lean otter]

its a weird topic

[vernal zephyr]

IM PAKISTANI TOOOOOO

[lean otter]

ew

nah im jp

[tight void]

it's a yes or no answer

[lean otter]

not for me

[tight void]

alana is indian fr

[vernal zephyr]

IM A JAPANESE TOO

[lean otter]

dang...

[vernal zephyr]

THEN IM AN INDIAN TOO

[tight void]

aight guys

[lean otter]

jp mean just playing

also

this

is for math help

gtfo

[tight void]

I'm going to dip

please close this channel @vernal zephyr

.close

[vernal zephyr]

yk what guys

[lean otter]

if u wanna know the answer, js dm me haha

[vernal zephyr]

i like you two

[tight void]

accept my fq

AYO?

[lean otter]

wow, i didnt get a fq

[tight void]

close this channel this instant

[vernal zephyr]

never had sucha convo on discord

[lean otter]

im offended

[vernal zephyr]

ever before

[tight void]

wym

[lean otter]

nah now i aint accepting

too late

crying fr

[tight void]

one time

my roommate waited for me to open the door and shouted when I opened it

[lean otter]

i have em everyday

[tight void]

like in my face

was p scary

[lean otter]

i woulda smashed the door in his ugly ass face

break his nose

[tight void]

and I WOKE UP so surprised

anyway

[lean otter]

im jk, i woulda started crying

[vernal zephyr]

again guys

dyk eachother

[tight void]

.close please

[tight void]

alana is my sister

[lean otter]

i told u

crush

carrots

[vernal zephyr]

.close

[safe radish]

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[tough monolith]

hello can someone check this for me to see if it is correct

[tough monolith]

i just wanna make sure

[eternal carbon]

hm.. i do not get that answer

[tough monolith]

wym

like it doesn't make sense or my answer is wrong

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[tough monolith]

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[plush seal]

how would i go about solving this?

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[plush seal]

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[pearl pollen]

Does this make sense?

Or the boy and the girl counts as 1 group?

[wheat blade]

I think you need to change 2! because you need to count all the possibilities for the first place and for the second place

[pearl pollen]

It's not 2!

since there's just 2 ways to count the possibilities

[wheat blade]

No

[pearl pollen]

Can you explain?

They do not count as 1 group right

[wheat blade]

On how many ways can you choose who to put on the first place?

[pearl pollen]

BG GB?

yeah there's 2

Wait

[wheat blade]

It need to be BG

[pearl pollen]

Oh so just 1 way?

[wheat blade]

You have 5 boys

[pearl pollen]

4

You mean?

[wheat blade]

Yes, sorry

You have 4 boys so there is 4 ways for a boy to be on the first place

[pearl pollen]

Ohh and 5 ways for girls to be placed?

[wheat blade]

I don't know if I am translating right english is not my first language

[wheat blade]

Yes

[pearl pollen]

Ohh so 2880?

[wheat blade]

How did you get that number

[pearl pollen]

5!4!

💀

[wheat blade]

No

There is 5 ways to place one boy on the first place

Do you get that?

[pearl pollen]

Yes

[wheat blade]

Ok

[pearl pollen]

4 ways?

[wheat blade]

4

Sorry

And there is 5 ways to place a girl on the second place

[pearl pollen]

Hmm okay

[wheat blade]

That is 5*4

Now you have 7 places left and 7 people, but now it doesn't matter the order of them, so there is 7! ways

5×4×7!

[pearl pollen]

100800?

[wheat blade]

Yes

[pearl pollen]

Thank you

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[pearl pollen]

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[idle cave]

The first screenshot is the question

Second is the answer

I can’t for the life of me understand how the conclusion to the loop invariant problem involves a double factorial

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[true violet]

Need help for this

[safe radish]

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[brave heath]

I need asap

!help

[safe radish]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[shadow glade]

!original

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[brave heath]

No. 5

[shadow glade]

so is it given the figure is a rhombus?

[hidden mist]

Ok wow u missed the most important info buddy

I thought there was nothing else in the given part

[shadow glade]

if you're trying to help people out, no reason to be passive aggressive...

[hidden mist]

Nah I just clarified my point

of why I couldnt help

now that its given its a rhombus

[brave heath]

The no. 5 figure is already given so I thought the other part is not important

[hidden mist]

we know its sides are equal

u can use that to prove that the two triangles are congrunt

[shadow glade]

you don't really need to know anything other that for squares and rhombuses their diagonals bisect the angle

so angle ABD and CBD are congruent

[hidden mist]

I did that in my school

and got told its a 4 mark question use square to prove they are congruent and then show that both eq are equal

Aint my fault-

and yeah tho thats the easiest trick

[shadow glade]

@brave heath is that making sense?

[brave heath]

Still kinda confused

Formula will make it easy for me though

[hidden mist]

what formula u talking about

The diagonals of a rhombus bisect each vertex angle

[brave heath]

Like how to get the x, example I mean will make it easier

[shadow glade]

so theres this idea that in a square or rhombus (presumbaly this is a rhombus) a diagonal will bisect the angle (i.e. split the angle ABC in half)

[hidden mist]

so the angle is divided into two both the parts are equal

[shadow glade]

so the two blue angles would be congruent

[brave heath]

Okie

[shadow glade]

ok, but if you DIDN'T know that already, you could also consider these triangles:

[brave heath]

Sooo 3x + 10 = 2x+20?

[hidden mist]

right

[shadow glade]

can you see why those triangles would be congruent?

[brave heath]

So 10?

Is this right? Or it needs to have m/_BDA?

Which one?

[safe radish]

@brave heath Has your question been resolved?

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[half kernel]

why is this wrong

i did it my self then asked the ai

so it says vertically by a factor of 1/9 so the its (1/9)y and then the ex is streachted by 1/7 so its 7x and the y is down 8 so its (1/9)y-8

.close

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[heady bay]

how do i solve this when it doesnt have a denominator of 12

[heady bay]

using the half angle formula if 7pi/8 is denoted as theta i can set it up but im stuck here:

cos(theta/2) = +- sqrt((1 + cos(theta))/2)

wait i think i set it up wrong

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[bold nimbus]

How to do number 2

[bold nimbus]

I require a solution LOL

[brazen parrot]

are u doing the same thing as me

[bold nimbus]

Idk

Thats insane

[fringe ginkgo]

HELP PLEASE 😦

[lean otter]

syl is 90 deg

[bold nimbus]

Yes then I just minus right?

[lean otter]

yeah

[bold nimbus]

Thats how the solution works?

Thats it?

[lean otter]

from pi

[brazen parrot]

from pi!?!?!?!?!?!

[bold nimbus]

Wait what

How to formukate it

[lean otter]

pi radians

of nvm

[brazen parrot]

yeah u have 90 degrees and then u just use property of sum of angles in triangle = 180

[lean otter]

its in degree lol

[vapid cypress]

use cosine rule

[bold nimbus]

So likee

[fringe ginkgo]

i dont know how 😦

[bold nimbus]

90+37?

[shadow glade]

!occupied

[safe radish]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[brazen parrot]

180 - (90+37) to get last angle

[lean otter]

pi = 180 deg my bad

[bold nimbus]

Wait

Let me do it and send it to you

[brazen parrot]

ok

or u can be like 180 = x + 90 + 37

[fringe ginkgo]

i need answer 😭

[bold nimbus]

The value of 37 is YSL?

Right?

[shadow glade]

so open a channel, it takes 2 seconds

[fringe ginkgo]

how

[brazen parrot]

yes

[bold nimbus]

Wait frr

Hold up

[brazen parrot]

its given in the diagram

[shadow glade]

^ can you not read @fringe ginkgo literally just sent you a link

now stop filling up this other person's channel plz

btw the key thing here since it wasn't explained in detail is that a tangent and the radius that meet at the same point on the circumference of the circle (Y) are always going to form a right angle

[bold nimbus]

Hold up

Holy smokes like this?

[brazen parrot]

omggg genius

[bold nimbus]

Let me cook

[brazen parrot]

wow u have very neat handwriting

[bold nimbus]

Anyways thanks LOL

[bold nimbus]

Is this sarcasm or real

I got confused a bit

[brazen parrot]

NO IT IS NEAT

[bold nimbus]

This is embrassing

[brazen parrot]

u havge not seen mine

[bold nimbus]

I still need help even getting a 99 grade in my report card

Lmao 💀💀💀

Skill issue to me

[bold nimbus]

Woah

Let me examine that

What grade u are?

[brazen parrot]

10

[bold nimbus]

Same 💀

Wait Asian or nah?

[brazen parrot]

half

[bold nimbus]

Genius

[brazen parrot]

why ask? 😅😅

[bold nimbus]

Idk tbh LOL

[brazen parrot]

ARE U?

[bold nimbus]

Yes

Filipino

[brazen parrot]

what asian

ohh PEK PEK LAND

[bold nimbus]

What even is a pek pek land

😭😭😭

[brazen parrot]

i have filipino friends

putang ina mo pek pek mohan mo mataba mo

[bold nimbus]

Dont say those 😭😭😭

[brazen parrot]

😔😔

[bold nimbus]

Pek pek is the genitals of a girl

Kike the under

[brazen parrot]

oh.

[bold nimbus]

Like*

YES

[brazen parrot]

ok.......................

[bold nimbus]

BRO NAH YOUR FRIENDS ARE BAD INFLUENCE LMAOO

[brazen parrot]

😭😭😭

[bold nimbus]

LOL

IKR

Let me add you fr fr

You might help me at the future

😉

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[spiral mirage]

my working:

move the in on the right

in(2x^2+x)=2

e^2=2x^2+x

this is the answer

what is going on here

[lean thorn]

remember that e is a constnat

so it's just the quadratic equation

[idle widget]

Yeah I think this is right

That’s what he did lol

[lean thorn]

I read his statement as that this is the answer but how did we get there? Hence the "what is going on here?"

[idle widget]

Ohhh I see

lol I missed his “what is going on here” mb

I thought he was just asking for verification lol

[lean thorn]

no worries fam

[idle widget]

Like he said this is just quadratic equation

[spiral mirage]

it is indeed the quadratic, forgot I could do that. thanks :)

.close

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[fleet vessel]

Given the derivative f'(x) = -((2xy)/(x^2+3y^2)) and the point (2,1), do I simply plug in the x and y values (2 and 1 respectively) in order to find the slope of the line at that point?

[fleet vessel]

Or, rather, to find the slope of the tangent line at that point.

[lean otter]

Yeah Just do it

Derivatives like these typically appear when derivatives of an equation implicitly

Example: find the derivative of $x^2+y^2=25$

[flat frigate]

Danty ⛧

[lean otter]

In this case derivatives on both sides and we isolate f'(x)

Getting $f'(x)=\frac{-x}{y}$

[flat frigate]

Danty ⛧

[lean otter]

To find the slope of the tangent line At a specific point , simply replace

[fleet vessel]

Awesome, thanks for the info! A few clarifying questions for you:

A derivative is an instantaneous rate of change. Is this not the same thing as a slope? Both are rates of change?

[lean otter]

This is an important question

The derivative of a function has two important interpretations: the derivative as a rate of change and the derivative as the slope of the curve at a point

The derivative as a rate of variation refers to the fact that the derivative is a relationship between the variation of two quantities, that is, given a quantity y and a quantity x We can know how fast the quantity y is changing in relation to the quantity x which is also changing

The interpretation of the derivative as the slope of the curve at a point gives us information about how the function is behaving, that is, it tells us where the function is heading.

In any case, the derivative is a rate of variation, but the way we analyze it reveals different information.

[fleet vessel]

Amazing, excellent information here! I really appreciate the help! I'll have to keep reading up haha

Lots to learn!

[lean otter]

Good studying!

[fleet vessel]

Thank you!

.close

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[timid scroll]

Where did they get this from?

[safe radish]

@timid scroll Has your question been resolved?

[fallen thunder]

get what?

x = 0? is one of the coordinate axes

[timid scroll]

Y = -0.5

Hia kanna kun

wiat

[fallen thunder]

,, \cos \qty(0 - \frac{2\pi}{3}) = \cos \qty(\frac{-2\pi}{3})

[flat frigate]

kanna

[fallen thunder]

then use the fact that cos(-x) = cos(x)

cos(-2pi/3) = cos(2pi/3)

i'm guessing you know how to find cos(2pi/3) lol

[timid scroll]

yeah

oh yeah

no im just not thinking

atm

;-;

I want food

BUT

Im proud do say idk what the fak they doin or how to do this

[fallen thunder]

it's just trig lol

idk what else to say

[timid scroll]

Ok but I dont understand

The question

I guess

Or what im looking at

a bit of the whole package ig

[fallen thunder]

what do you not understand

do you know how to solve cos(theta) = 1?

arccos(cos(theta)) = arccos(1)

the reference angle is then just arccos(1)

cos is periodic so it repeats every 2pi

[timid scroll]

i found about arccos' existance yesterday

Oh ok

then I think i can figure it out

Thanks kanna

[fallen thunder]

[timid scroll]

how have you been btw

[fallen thunder]

i'm good lol

[timid scroll]

.close

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[inner scaffold]

I find approximation for Apery`s constant
Apery Constant:

[inner scaffold]

My approximation:

It is good or bad?

[waxen light]

anything with < 1% error is good

[inner scaffold]

Okay

[eternal carbon]

depends on level of precision you are looking for...

[waxen light]

What i use π=3=e=√g=√10

[inner scaffold]

1+1≈∞

[waxen light]

anythimg greater than 1 is ≈infinty

ngl

[inner scaffold]

I try to find better approximation

.close

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[willow fossil]

I understand part a but not part b. When i put the values given in the solution i get a different angle for x. If you get the solution answer can you take pic of working and explain how u get it
Image
Image

[willow fossil]

I understand part a but not part b. When i put the values given in the solution i get a different angle for x. If you get the solution answer can you take pic of working and explain how u get it
Image
Image

[lean otter]

Sorry, can you be more specific? You’re using the identity you obtained in (a) for (b)

[willow fossil]

Yes, but the problem is with the working in 8b. if you look at the working for 8b it says to test 90 and 270. why is that?

i understand why x can be 306 though because you take arccos and then minus arctan 3 to get x=306

[lean otter]

look at the initial equation

$\cos(x) - 3\sin(x) = 3$ is true when $\cos(x) = 0$ AND $\sin(x) = -1$, do you agree?

[flat frigate]

45

[lean otter]

so it's not true when x = 90* but it IS true when $x = 270*$

[flat frigate]

45

[willow fossil]

Yep i agree

but when do i know to just check for 90 and 270

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[lyric apex]

Just a general Linear Algebra question. Sometimes finding Eigenvalues is really difficult when you get crazy polynomials. But i've seen people just using (A- λI) = 0 to finding the Eigenvalue really quickly. But i don't quite get how.

[lyric apex]

And i'm sorry but i dont really have an example of it

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[dense wadi]

how can this be wrong

[dense wadi]

even a calculator shows its rigth

[compact pelican]

Remember that the particle has negative velocity at the start. I think you have to compute the backwards distance PLUS the forward distance to get total distance traveled

They don't cancel out because driving west 5 miles and then driving east 5 miles isn't the same as not driving at all

[lean otter]

also distance is asked not displacement

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[sudden sparrow]

can someone solve 4 step by step so i can understand it?

[thin bridge]

solve for you, no
guide you through it, yes

[magic junco]

Fact

!status

[safe radish]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[sudden sparrow]

i am at 1

[magic junco]

okay, do you know how to find the gradient of a line?

[sudden sparrow]

y2-y1/x2-x1

[sudden sparrow]

right?

[magic junco]

yes

There an another one

When you find a line, you can instantly find it

[sudden sparrow]

what do you mean find a line?

do you mean the equation

like this one

[safe radish]

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[sudden sparrow]

@magic junco

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[vital steppe]

Is it possible to add some open sets to a Tychonoff topological space $X$ without losing this property?

[flat frigate]

Milo

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[vital steppe]

<@&286206848099549185>

[plucky elk]

maybe try asking in #point-set-topology and be more clear about what "this property" refers to

[safe radish]

@vital steppe Has your question been resolved?

[vital steppe]

I meant being Tychonoff

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[crimson nexus]

.

I need help with this problem

[crimson nexus]

I'm confused what T one-to-one and onto is

[plucky elk]

https://textbooks.math.gatech.edu/ila/one-to-one-onto.html

[crimson nexus]

Then Would a) be it is one-to-one because it is linearly independent and b) its not onto because it is linearly independent

<@&286206848099549185>

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[peak estuary]

what is linearly independent and why does that matter

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[sour mica]

Trying to solve for 17, on the calculator I get -1

but when I try and do the math I get

cos(pi/3) cos(2pi/3) - sin(pi/3) sin(2pi/3)
cos(60) cos(120) - sin(60) sin(120)
1/2 * -1/2 - sqrt(3)/2 * sqrt(3)/2
-1/4 - sqrt(9)/4
-1 - sqrt(9)/4

-sqrt(3) - sqrt(3)/4 being the solution i find

[last wren]

okay well first of all, cos(120) = -1/2

and sin(120) is not 1/2

[sour mica]

wait what

is 120 not equavilant to 30 when solving it on that triangle thing?

not sure what its called

[tame raft]

no

30 is equivalent to 150

60 is equivalent to 120

sin(x) = sin(180 - x)

[sour mica]

ohhh its flipped isnt it...

okay thank you that makes more sense

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[urban sentinel]

I want to pick up some maths to help me reason about some maths when programming or atleast have a base to learn more. I found a book called Programmer’s Introduction to Mathematics by Jeremy Kun. What do you guys think about this book?

[urban sentinel]

its also a bit hard to argue for a longer more intense book since in my experience many areas of maths aren't really used in software engineering so it just becomes lost and forgotten knowledge for myself.

this is the contents list.

[plucky elk]

help channels are for math problems, not book recommendations

good thing there's#book-recommendations

[urban sentinel]

fair, I read #❓how-to-get-help and understood math questions as any kind of math question

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[quartz wasp]

How many verexes dose a prism have if the edges number is 7 more then the vertexes

[abstract crown]

a prism is like a 2d shape, extended 3d so...

Let sides of shape = s

number of vertexes = 2s (one set of vertices for each side)
number of edges = 3s (for each side and to connect)

And if edges - vertices = 7
3s - 2s = 7
so s=7
so vertices = 2s = 14

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[abstract crown]

lol youre welcome

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[vestal bridge]

let A be MxN matrix, and define U = {X nxk matrix | AX = 0 mxk matrix} a vector space
prove that dim(U) = kdim(N(A))

[vestal bridge]

anyone pls

[pastel sinew]

hold on

let $A\in\text{Mat}{m\times n}$, define vector space $U={ X\in\text{Mat}{n\times k}\ \vert\ A\cdot X = 0\in\text{Mat}_{m\times k}}$. Prove that $\text{dim}(U)=k\text{dim}((n(A))$

[flat frigate]

🇵🇸Mína🔆

[pastel sinew]

i'm not sure the last part I got right, your notation is a bit confusing

what does the N(A) mean in your case?

@vestal bridge

[vestal bridge]

N(A) all the x s.t Ax=0, x is vector

Null(A)

[pastel sinew]

oh, the null space!

well, the nulity of A is, as you said, the dimension of the space of vectors which go to zero when multiplied by A

this U space is similiar to the nullity

[vestal bridge]

ye ive already proven its a vector space

[pastel sinew]

only that it's not a space of columns, but a space of k-columned matrices

[vestal bridge]

just trying to figure out why its dimension is k times Null(A)

let X be in U, so each coulumn of X makes A*C_i = 0

Thus the columns of X belongs to the Null(A)

[pastel sinew]

exactly

but you can find a basis of such columns

[vestal bridge]

but im not certain on how to continue from there

Yes let {v1...vp} be basis for Null(A)

[pastel sinew]

make a linearly independent set of k columns

[vestal bridge]

for X?

ohhhhhhhh

wait i think i got it

i thinnk it's smth like that

v1 has k options to be in, v2 also,...vp, so k + k + k... p times

just need to prove it's linear indepndent and done

[pastel sinew]

you can create a set of k linearly independent matrices of ones and zeros, which when multiplied into the basis vectors of your nullity(A) will still yield a zero vector. of which there can be k

yeah!

[vestal bridge]

ye

ty

[pastel sinew]

you got this!

you're welcome!

[vestal bridge]

now just need to show it's linear independent

correct?

i guess by negation it'll be the easiest

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[clever ridge]

How do I find angle of a?

[clever ridge]

I really need help please

[abstract crown]

lol i explained to you in depth and you ignored me

#help-11 message

[clever ridge]

hey sorry about that i was in class and my laptop died on me

i am home now

i saw what you wrote but hoe am i supposed to solve?

i need the actual angle of a

[clever ridge]

do you mind continuing to help?

[abstract crown]

i gtg sleep now

sorry mate. try follow what i wrote there though

[clever ridge]

ok thx. i am still not sure ewhat to do

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[clever ridge]

@abstract crown is the angle 5sin(45) + 10sin(a)?

or is that something else

im not sure what that is from

[clever ridge]

can u please just help me finish this problem?> i know you were helping before but i was in another class i couldnt respond to you

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[safe radish]

@violet mango Has your question been resolved?

[empty gyro]

Okay, let's break it down

Do you know how to express "all rainy days are bad"

For the people and umbrellas above
@violet mango what is this?
Show the whole problem

[violet mango]

tahts the above problem

[violet mango]

not sure

all R --> {bad}

?

@empty gyro

[empty gyro]

As an example, if $\bZ$ is the set of all integers, then we can say "all integers are even" (this is false, but just an example) as $\forall(z\in\bZ)(z\text{ is even})$

[flat frigate]

SWR

[violet mango]

A(r e R)(r is Bad)

all elements r in R is bad

is that correct notaion?

[empty gyro]

yes it is

How would you say "two people share the same umbrella"

[violet mango]

p1,p2 --> (u1)

?

[empty gyro]

(hint: what was your english translation for f is one-to-one?)

[empty gyro]

This means absolutely nothing

[violet mango]

every person in the set is assigned a unique umbrella

[empty gyro]

Yes. So what would be the negation of that statement?

[violet mango]

every person is assigned to same umbrella

[empty gyro]

No this is not opposite.

[violet mango]

2 people map to same umbrella

[empty gyro]

yes

More precisely, "at least 2"

[violet mango]

so at least 2 people map to same u

isnt it f(p1) = f(p2) --> p1 = p2

[empty gyro]

This is one-to-one (assuming you mean for every p1, p2 in P)

[violet mango]

p1 != p2 —-> same umbrella

[violet mango]

f: f(p1) = f(p2) --> A(r e R)(r is Bad)

[violet mango]

.close

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[manic shadow]

BDA=35°

BEC=__°?

is it 17.5°?

[dusk gate]

So, I can't see all of the problem description.. is AB || DC?

AD || BC?

[manic shadow]

yes that is correct

and BD = 12dm

[dusk gate]

BDA is not 35

[manic shadow]

wat

[dusk gate]

BDC is 35

Right idea... wrong side of the line

[manic shadow]

Oh right i forgot to add that this is a rectangle

i... dont get it

it looks the same

[dusk gate]

Sure.. but when a line intersects two parallel lines, it creates matching angles on opposite sides of the intersection

[manic shadow]

wait so that means bad≠bdc?

[dusk gate]

hold up.. when you're using the 3 point reference, which angle is in the middle of your 3 letters?

[manic shadow]

E

or if that is not the answer then i have no clue

[dusk gate]

sketching

[manic shadow]

oh wait no sorry i dont have any idea what the 3 point reference is

[dusk gate]

I think we have a communication error 😉

[manic shadow]

indeed

[dusk gate]

The angle BDA is the angle that starts at point B, goes to point D, and then goes to point A

[manic shadow]

oh

yeh then it is E?

[dusk gate]

So BDA is not the same as BAD, and that is not the same as DBA

We can ignore E when we're just passing through it

in a straight line

[manic shadow]

oh nice

[dusk gate]

So when you said BDA = 35, I thought you were talking about this angle

Is that not what you meant?

[manic shadow]

it is not

[dusk gate]

Gotcha

ok

So.. ABD is 35

[manic shadow]

i think i am starting to understand something maybe not

so it should be ABD then

[dusk gate]

So, you're looking for BEC?

[manic shadow]

oh yes

i am looking for no wait

[dusk gate]

This one?

[manic shadow]

CBE

[dusk gate]

Ahh, that's even easier...

Since you know it's a rectangle, you know that EBA + CBE = ___

[manic shadow]

OH SO IT REALLY IS NOT EQUAL

[dusk gate]

Nope

[manic shadow]

oh

yeh i have no idea how to start

Oh 35°

[dusk gate]

You've got EBA... that's 35

[manic shadow]

oh that was eba?

[dusk gate]

you know it's a rectangle, so all the angles in a rectangle (ignore the two diagonals... we're talking about the ones around the perimeter

[manic shadow]

i thought it was dba

[dusk gate]

DBA = EBA

[manic shadow]

oh

[dusk gate]

When we talk about DBA, we're ignoring E as we pass through it

they're the same thing, because the angle we're talking about is that angle at B

The other points are just for reference so we know which sides we're using to make the angle

[manic shadow]

oh i see

[dusk gate]

So if you're looking for CBE...

Because this is a rectangle, you know ABC = ___

[manic shadow]

70°?

[dusk gate]

All the angles in a rectangle are perpendicular with each other (ignore the diagonals in this example)

Which means they're all 90

[manic shadow]

whats perpendiucalr

cular*

[dusk gate]

it means they meet at a right angle

[manic shadow]

does it mean they intersect?

[dusk gate]

Yes, they intersect at 90°

So you get 90° on both sides

(or all 4 sides, if the vertical line goes all the way through)

[manic shadow]

i think i should first ask what a right angle is...

[dusk gate]

A right angle is a 90° angle

90° = perpendicular = right angle

They're all different ways of saying the same thing

[manic shadow]

is it like an L

[dusk gate]

Yep

[manic shadow]

oh

Oh rectangles has 4 of those innit

[dusk gate]

Yes!

So you know the sum of ABE and CBE = 90

And ABE (or EBA, or DBA, etc.) is already known

[manic shadow]

Oh

[dusk gate]

90 - 35 = ?

[manic shadow]

55?

OH WE SUBTRACT THE SUM OF THE RIGHT ANGLE?

[dusk gate]

Easy peasy

[manic shadow]

oh

so if its a right angle then that means its a 90° so we take that information to our current information which is 35° and then subtract 90-35?

[dusk gate]

Yep

[manic shadow]

oh

Oh damn

oh tyvm

[dusk gate]

np

[manic shadow]

.close

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[clever ridge]

Can someone please help me with b and c?

[dapper venture]

Calculate the x and y components of the forces

You can do it by drawing right triangles

[clever ridge]

ok so make a right triangle in the middle where it has the dotted line?

[clever ridge]

im honestly really not sure what that is we didn't even go over this in class

is this right for a ?

ok so W + N + F = 0

[clever ridge]

Idk what F and N stand for?

nvermind i found a similar question in my book it seems really easy @dapper venture

Would you mind just helping me distinguish which part is b and c? @dapper venture

I guess c is the last thing I wrote but I’m not sure if I did B anywhere

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[static flame]

Im trying to make a Venn Diagram of different types of Ordinary Differential Equations. Is there anything that looks off here? Im having trouble trying to figure out some edge cases

[static flame]

or I guess this is technically an Euler Diagram

still for the purpose of showing subset relations

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[static flame]

.close

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[desert pasture]

,rotate

[empty gyro]

We can't help you with exams

[toxic plover]

V²=u²+2gh

[wraith viper]

it’s not an exam

well it was an exam

but i already did it

[toxic plover]

Ok

[empty gyro]

!status

[safe radish]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[wraith viper]

1

[light shoal]

can you show what you did

[wraith viper]

i’d show you what i did

okay but it literally makes no sense

i just guessed : -(

[light shoal]

that's ok, it will still help to see your thoughts

[empty gyro]

,rccw

[wraith viper]

it’s kinda all over the place, idet it makes sense looking back but i was just trying to get an answer down

[light shoal]

your t is correct (approximately)

how did you get 92.12 meters/second?

[wraith viper]

i have no idea

this was from a few weeks ago so sorry i forgot a bit of it

[toxic plover]

Just use V²-u²=2gH

[wraith viper]

but yeah… idk where i got that

[light shoal]

you can just use s'(t) = 9.8t, plug in your t

[wraith viper]

so plug in ~ 81.2 into t?

and get 795 mps

[light shoal]

no, 81.2 is t^2

t is 9.04

[wraith viper]

oh so sqrt it

[light shoal]

yea

[wraith viper]

and it’s 88.6?

[light shoal]

yep

so you were off by a bit, not sure what went wrong there

[wraith viper]

oh that’s a lot easier than i thought

[light shoal]

did you get partial credit at least?

[wraith viper]

uhhh

i don’t think so

[light shoal]

harsh

[wraith viper]

it’s combined with B

and i got 4/16 for that entire proboem

problem

[light shoal]

yea but it says 6 points for A
i would have given you at least 3 points

[wraith viper]

so that’s more of an algebra problem then

i think that’s what threw me off was how easy it was

[light shoal]

there's calculus underlying it, but they gave you the formulas to use so you only needed to use algebra, yea

[wraith viper]

ty for the help, i appreciate it a lot

[light shoal]

sure

[wraith viper]

/close

idk how to close this

[spice furnace]

type .close

[wraith viper]

.close

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[wraith viper]

ty

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[viral lava]

Hey how do I go about solving 3 part c

[viral lava]

Would it be something similar to this?

I'm just stuck because I'm not sure if I'm even doing it right

[frozen marlin]

!15m

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[viral lava]

sorry its been 13 mins hasnt it mb

<@&286206848099549185>

[frozen marlin]

is fine lmao

jesus chr7st

i'd help but taylor series r my weak point

[viral lava]

oh nah its no problem its taking me ages too lol

[frozen marlin]

lol

[viral lava]

<@&286206848099549185>

.close

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[teal escarp]

Hi

[teal escarp]

$\sum_{n=1}^{\infty}\frac{n5^n}{(2n+3)\ln{n+1}}$

[flat frigate]

Ñøïr

[teal escarp]

I am asked to find the convergence with ratio test

$\lim_{n\to\infty}\frac{(10n^2+25n+15)\ln{n+1}}{(2n^2+5n)\ln{n+2}}$

[flat frigate]

Ñøïr

[teal escarp]

I couldnt evaluate this

When I try to do l'hopital ln doesnt disappear cause of the multiplier

And it looks even uglier that way

Am probably sure its 5

.close

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[timid scroll]

Stupid question inbound

[timid scroll]

I’m guessing 1- x^2 All that rooted

Does not equal to 1-x

Anyways what did I do wrong here

[turbid swan]

c²=1-x²
c=1-x
what

[timid scroll]

No?

Is it illegal or something

[turbid swan]

it's a sin

[timid scroll]

Ok so

Cos = square root(1- Sin^2 theta)

What about that

[turbid swan]

hm yeah

well can you explain what you were trying to conclude? were you attempting to prove that identity?

[timid scroll]

I’m trying to cancel out theta

And make y= x

[turbid swan]

oh like the locus of x and y related?

[timid scroll]

No clue what locus is

But I’m beginner

[turbid swan]

well you wanna establish a relationship between x and y right?

[timid scroll]

At school

Yeah

[turbid swan]

alright

[timid scroll]

Something like this

[turbid swan]

yeah i see

[turbid swan]

what you did was incorrect because of the rooting

[timid scroll]

Ok so all i have to do is

y= 2x (Squareroot (1-x^2)

and then do I expand it ?

how do i do that

[turbid swan]

it's correct even that way because all we want is to eliminate theta

[timid scroll]

Yeah

thats true

[turbid swan]

but a square root is generally avoided so I'd say you square both sides

[timid scroll]

but how would I make it intiger form

If I may ask

[turbid swan]

but that's just a personal preference

[timid scroll]

No thats true ^

[turbid swan]

what do you mean? x and y are variables we don't know if they're integers or fracs

[timid scroll]

$Power[y,2]=4Powerx,2$

[flat frigate]

Equity

[timid scroll]

sry how would I make the equation intger

Like that?

and then expand

yeah

[turbid swan]

yeah just i said, i can see that's just your equation plus squared both sides and then they've clubbed the x² and y² terms

[turbid swan]

i suppose you mean integer powers of the x and y?

[timid scroll]

Yeah i guess

I just wanted to remove the root

So it looks nicer

Also as practice

: 3

[turbid swan]

yes

[timid scroll]

thank you

: )

Quick question

How do I combine y= 2sin and 1 -2sin^2

[turbid swan]

is 1-2sin² = x?

[timid scroll]

Can I do

y^2 = 4 sin^2
y^2 = 2(2sin^2)

Does that work?

y^2/ 2 = 2sin^2

and then sub it into

(x-1)/3 = cos2A cos2A -> 1- 2Sin^2 A

[turbid swan]

you should weite sin²(theta) in terms of y and then expand cos(2theta) in terms of sin²theta

yes that seems it

[timid scroll]

Is this the same as

(2x-8 )/ -3 = y^2

[turbid swan]

yeah

take the negative sign from denominator and 2 from numerator out

[timid scroll]

amazing

thank you man

a lot

amaizng

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[timid scroll]

How can I do this,
Its not very straight forward for me

With the range

and the Tan Theta/2 = 1/3 or -3

I would know how to do it if it looked like

Tan (A) = 1/3 and -3

Could someone help, thank you

[restive niche]

It can't be and, tan(A) can only have one value

[timid scroll]

No yeah sorry

I mean like

I would know how to find if its 1/3 or -3

But it looks a bit different

than im used to

and also the range

does that mean

Tan = 2/3
Tan = -3?

[restive niche]

The explanation is given in the last 2 lines

[dusk gate]

Start by realizing that tan = sin/cos, and that cos and sin are your x and y values, respectively

[restive niche]

π<theta<3π/2, so π/2<theta/2<3π/4

[timid scroll]

Yeah but I dont get the quadrants bit,
I usually draw it out

and I also dont get the range

like this

And then I see what cos 4/5 and cos -4/5 is

and then i draw it

[restive niche]

If an angle is between π/2 and 3π/4, the tangent of that angle will be negative, so they concluded that tan(theta/2)=-3

The other option was 1/3, which is positive