help-23

[merry sleet]

,w 62*0.87/(2tan(5°))

[fresh birch]

Oh bruh

How’d I forget to do that

Lemme continue and see what I get one sec

[flat frigate]

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[fresh birch]

Ok so

I’m getting abt 312.6

@merry sleet

[merry sleet]

this was my initial answer

[fresh birch]

This

Yeah

So how come you’re getting a different result now

[merry sleet]

because its not exactly 62 and 0.87

its missing decimals

[fresh birch]

Yeah

[merry sleet]

its close

[fresh birch]

So mine’s right

Right?

[merry sleet]

308 is close to 312

[fresh birch]

Yeah ik but

[merry sleet]

yes its good

my initial answer was

[fresh birch]

This is my answer

Ok, great

Could I ask u another one if u have time?

[merry sleet]

go

[fresh birch]

It’s much easier

I have 7 in total

Kk

Gimme one sec

#4

I’m gonna solve it as well

[merry sleet]

in the case of a square an apothem is just half the side

so its easy peasy

[fresh birch]

So I got 2352

[merry sleet]

,w 3*14^2

[flat frigate]

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Requested by Benjamin#3570

[fresh birch]

Oh

I got 2352

[merry sleet]

how

whats the side of your square?

[fresh birch]

28 sqrt3

[merry sleet]

cant you just see that if you add two apothems you get the whole height of the square?

so its the side?

[fresh birch]

I don’t think u can do that

[merry sleet]

so the side is 2*apothem

for a square

i'm pretty sure you can

[fresh birch]

So, I got 14 sqrt3 for the base of the triangle

So I just multiplied that by 2 and got 28 sqrt3

[merry sleet]

yeah but its wrong

[fresh birch]

How

Ohh wait

One sec

Lemme try again

Wait nvl

I don’t get it

[merry sleet]

tan(45) = 1 right?

,w tan(45°)

[flat frigate]

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[fresh birch]

Yeah

[merry sleet]

so the base = apothem

so the side = 2*apothem

as i said earlier

[fresh birch]

I’m not sure that’s right bc I used a 45-45-90 triangle shortcut

[merry sleet]

you know way too many formulas

whats this shortcut?

[fresh birch]

OH

Wsit

Sorry

Ik what you’re saying

I messed up the shortcut

Lemme try again one sec

[merry sleet]

a 45 45 90 triangle has 2 sides of the same length

since its isosceles

so i'm pretty sure i'm right

(i would bet my life on it)

[fresh birch]

Lmao I got 196 sqrt 3

[merry sleet]

for what?

[fresh birch]

The area

Bc look

The apothem is half the side length

Right?

[merry sleet]

you forgot to multiply the sqrt twice

[fresh birch]

Wdym?

[merry sleet]

the answer is (14 sqrt(3))²

which is

[fresh birch]

I don’t see how tho

Bc

[merry sleet]

14²* sqrt(3)²

[fresh birch]

The base of the triangle is 7 sqrt 3

Right?

[merry sleet]

yeah ok

[fresh birch]

Ok so

[merry sleet]

so the side is 14sqrt(3)

[fresh birch]

Right

And so now

All u need to do is square that

[merry sleet]

yeahj

exactly

[fresh birch]

Nvm

You’re right

[merry sleet]

yeah

[fresh birch]

It’s 588

[merry sleet]

thats what i thought

[fresh birch]

Lmao

[merry sleet]

come on

[fresh birch]

Idk how I messed that up

[merry sleet]

squaring a square root

[fresh birch]

Yeah, I wasn’t paying attention

[merry sleet]

100% of your mistakes is you not multiplying the right thing

[fresh birch]

Yeah

[merry sleet]

by innatention

[fresh birch]

Lol

[merry sleet]

also

why do this whole base of triangle thing

for a square

[fresh birch]

It’s the way I was taught

So idk

There’s a test tmrw

Could I send another one?

[merry sleet]

here

EG = CB right?

[fresh birch]

Yeah

[merry sleet]

and FG = EG/2

and FG is the apothem

[fresh birch]

Yeah

[merry sleet]

i mean this whole thing is good for when you have a 79 gon

but for simpler cases just do it the regular way

there are shorcuts in simple cases

w/e

one more

[fresh birch]

Ah, I see

I can send it?

It’s #5

I’m working on it rn

[merry sleet]

,w 51212*cos(pi/5)*sin(pi/5)

[flat frigate]

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[merry sleet]

i think this is a better formula

Ngon:

n*radius²*cos(pi/n)*sin(pi/n)

[fresh birch]

Kk

I’ll try that

[merry sleet]

if you just have to give a result use that

to give an explanation i meant*

[fresh birch]

Kk

[merry sleet]

,w lim(n*cos(pi/n)*sin(pi/n))

[flat frigate]

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[merry sleet]

yeah its good

[fresh birch]

Alr yeah so

I got abt 342.4 as my answer

[merry sleet]

do you see how i got this formula?

[fresh birch]

I think so

I’ll use it either way

Was my answer correct?

[merry sleet]

see for yourself

[fresh birch]

Ok great

[merry sleet]

maybe as a side exercise i'm giving you, try to find a formula that just depends on the apothem now

and from n

[fresh birch]

Kk

[merry sleet]

if you go back to this drawing

the angle on the top is equal to pi/n

and y is the apothem

once you have the area of that

just multiply by 2n

because a ngon is made of 2n of these triangles

[fresh birch]

Oh I see

That makes sense

I’ll just use that formula from now on

[merry sleet]

thats how i did it but starting from the radius

try to do a formula for the apothem

essentially area depending on y

knowing that the top angle is pi/n

it shouldnt be hard

heres the answer i think ||2n*a²*tan(pi/n)||

[fresh birch]

Yeah that’s actually similar to what I was thinking

I’ll just use that

[merry sleet]

try it on the example we got of the square

to verify

it works

[fresh birch]

Kk

[merry sleet]

,w 4*(7sqrt(3))^2*tan(pi/4)

its wrong 😦

[fresh birch]

Oh

Lol

[merry sleet]

oh its only n

not 2n

actually

[fresh birch]

Oh ok

[merry sleet]

because the area of a triangle is base*apothem/2

[fresh birch]

I see

[merry sleet]

but to make a slice its 2 apothems

so they cancel out

and there are n slices

[fresh birch]

Oh that makes sense

[flat frigate]

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[merry sleet]

yay

[fresh birch]

Alr then

Yess

Ok I’ll use that then

[merry sleet]

basically the method is to compute the area of one triangle

and then multiply

by the number

of triangles

but you can get really quickly an answer

with the formula

[fresh birch]

Got it

I’ll just do that then

Thx sm

I’ve got 2 other q’s if u don’t mind

[merry sleet]

be careful if you need to explain

and not just give the answer

your teacher probably wont accept this formula out of the blue

[fresh birch]

Yeah

I’ll explain it

[merry sleet]

ok

so lets finish

[fresh birch]

Kk

So for 6

I got abt 10.9

[merry sleet]

,w sqrt(36*12)*pi/6

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[merry sleet]

yes

[fresh birch]

Yes

Ok great

So now

7

[merry sleet]

whats m<ABC

[fresh birch]

I don’t think I’m right but

The measure of

[merry sleet]

the angle

ok

[fresh birch]

Yeah

So I got abt 1108.5

But I highly doubt I’m right

[merry sleet]

,w cos(pi/6)3240

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[merry sleet]

yes

[fresh birch]

Oh wow

Didn’t expect that lol

[merry sleet]

did you calculate it the same way as me?

[fresh birch]

Yes

[merry sleet]

its just base*height

[fresh birch]

Yeah

Alr so

I think that’s all for now, thank u so much!!

For all the help

Rlly appreciate it

[merry sleet]

.close

[safe radish]

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[fresh birch]

So

[fresh birch]

@merry sleet

I’m actually stuck on #9 here

Could u help?

I’m getting abt 17.4

But that’s not right

<@&286206848099549185>

[glacial moat]

what formula did you learn for area of a regular octagon?

@fresh birch

[pastel verge]

google it

[fresh birch]

,rotate

[fresh birch]

This is what I did

[merry ember]

Find the area of one of the triangles using the angles and radius and then multiply by 8

[fresh birch]

That’s what I did

[glacial moat]

What value did you get?

[fresh birch]

Abt 2. Smth

@glacial moat

[glacial moat]

I got 11.3

I might've done something wrong honestly I haven't done these types of questions that much

[fresh birch]

Kk

What abt #19

@glacial moat

How’s it 100-25(pi)/100

And not 25(pi) + 100

[glacial moat]

So what would the blue region be?

in area?

yo? @fresh birch

[fresh birch]

Yeah

Srry didnt get the notif

Yeah so the blue region

What would it be and y

[glacial moat]

What about the red region can you say the area?

[fresh birch]

Yeah, it’s abt 44%

It’s just this one I’m stuck on

[glacial moat]

44% ? I didn't get that

[fresh birch]

O

Well it’s the right answer

[glacial moat]

The total area is 100 right?

of the whole figure

blue region + red region

oh nvm it counts the white semicircles too

So the blue region would just be the red region substracted from the 10x10 square

[fresh birch]

Yh

So what abt #19

@glacial moat

[glacial moat]

Well you know the area of the red region right?

so just subtract that from the 10x10 square

and divide it by area of whole figure

[safe radish]

@fresh birch Has your question been resolved?

[fresh birch]

What’d u get?

Cuz the answer’s supposed to be abt 21%

But I keep getting like abt 12%

What r u getting?

@glacial moat

[fresh birch]

According to Photomath

<@&286206848099549185>

[safe radish]

@fresh birch Has your question been resolved?

[grim plover]

@fresh birch do you know the blue area?

[fresh birch]

Well that’s what I need help w/

100-25(pi)

[grim plover]

I see

[fresh birch]

For the numerator I think

But idk what the denominator would be

[grim plover]

Can u tell me what blue region + red region =?

[grim plover]

First find all the areas then move onto the probability

[fresh birch]

Ok so

It’s 100-25(pi)

For the numerator, right?

@grim plover

[grim plover]

Where did u get that..?

Oh

Yes

It is

For the denominator blue region + red + white

[fresh birch]

Ok yeah so that’s exactly what I did

I got like

25(pi)+100

[grim plover]

Yes

[fresh birch]

So isn’t the answer abt 12%?

[grim plover]

So u have $\frac{100-25pi}{100+25pi}$

[flat frigate]

ItzKraken2

[grim plover]

Let me see

[fresh birch]

Kk

[fresh birch]

Yh

[grim plover]

Yes it's 12%

Or 3/25 (as a fraction)

[fresh birch]

I think Photomath’s wrong then

Bc it says 21%

[grim plover]

What did u type into photomath?

[fresh birch]

Nothing

I took a pic of it

And the textbook came up

[grim plover]

Huh

Ah

It's not considering the white portion

[fresh birch]

Yeah

But y not?

It should

I think it’s wrong tbh

Sometimes Photomath’s wrong

@grim plover

[grim plover]

Yes

[fresh birch]

Plz help me w/ #13

@grim plover

<@&286206848099549185>

[grim plover]

Same question?

Also I Amma send a video for 13 that's related to the question

That shaded things called a geometric lens

[fresh birch]

Ok, plz do send it

[grim plover]

Crap I can't find it

[safe radish]

@fresh birch Has your question been resolved?

[quiet linden]

First find the area of the square

Then subtract the area of the quarter of the circle

You'll find the white area by that

Then subtract the area of the quarter of the circle by that white area

[wise blaze]

Then youll find the shaded area

[safe radish]

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[safe radish]

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[foggy knot]

Just having trouble understanding chain rule I need step by step of chain rule

[indigo flame]

For the first question just see (u-2) as a new variable and differentiate it with respect to it

Then times d/du (u-2)

The times d/dx u=1/(2x+1)

[granite idol]

dy/dx = (dy/du) * (du/dx)

[indigo flame]

If u want I can show uthe proof

[foggy knot]

yes please

[indigo flame]

Since writing in latex is a bit time consuming

I will just wrote it on paper

And send it

Or you can just search on the net

Maybe you search first

I show u if you can’t find one that you know

[mystic lake]

Does anyone know how to solve this

[fair hound]

1-sin²(alpha) = cos²(alpha)

[indigo flame]

Wait the channel is occupied

[uneven veldt]

!help

[safe radish]

Please read #❓how-to-get-help

[indigo flame]

,rotate

[foggy knot]

Sorry if I kinda waste your time I'm at here now my question is where did -4x come from(idk if this is correct)

[indigo flame]

It is correct

[foggy knot]

Can you explain how it got the (-4x-1)^2

my mind is like where did x come from, theres no x on top

[indigo flame]

(1/(2x+1))-2

maybe you should try simplifying that part

[foggy knot]

I feel so dumb I get it now

Ok how do I close this

[indigo flame]

Use .close

[foggy knot]

Thanks for the help and sorry if I was kind dumb XD

.close

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[fathom oriole]

Hi, can anyone pls help me factorize this expression?

[fathom oriole]

Idk how to do it without fractions

[earnest wagon]

Factoring means taking stuffs common, what do you see common in it

[fathom oriole]

a^2 and b?

[earnest wagon]

You miss the common thing of 20 and 35

Isn't 5 common?

[fathom oriole]

Oh

I see

[earnest wagon]

20-35=5(4-7)

Yeah so basically a^2, b and 5 are common stuffs

Can you the rest after taking common?

[fathom oriole]

I don't get this, what does it have to do with the problem?

[earnest wagon]

It's basically the same thing

For example, if you're asked to factorize ab-a, you will take a common, which will give a(b-1)

After taking common all that remains is writting the remaining stuff inside bracket

[fathom oriole]

Ok

So outside of the brackets I'll have a^2b5(4-7)?

[earnest wagon]

Nope

They were prior examples I gave and so they are not necessarily the answer of "outside the bracket"

Just take the idea and work towards the solution from new beginning

[fathom oriole]

Ok

[earnest wagon]

Also I never said (4-7) is outside the bracket

You clearly see the parenthesis..

[fathom oriole]

${a^2}b5(4-7ab)$ is this the solution then?

[flat frigate]

Doctor beak

[earnest wagon]

Yup

[fathom oriole]

Thx

[earnest wagon]

This is the solution

Welcome

[fathom oriole]

.close

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[fathom oriole]

.reopen

[safe radish]

✅

[fathom oriole]

Just to check if I got the point

This should be factoraized

As

${4a^2}{b^2}({9a^2}-3)$

[flat frigate]

Doctor beak

[earnest wagon]

No you can factorize 12

[fathom oriole]

Oh

Right

[earnest wagon]

Or rather that "under brakcet" can further be factorized into 3

[fathom oriole]

So instead

${12a^2}{b^2}({3a^2}-1)$

[flat frigate]

Doctor beak

[earnest wagon]

Yes

[fathom oriole]

Ok, thx

.close

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[misty summit]

I'm trying to show the second property of a group action

namely f . (g . A) = fg . A

my question is, a composition of permutations in S_n (i.e. f(g(A)) is the same as a product of permutations fg(A) right?

because if f and g were functions then clearly f(g(x)) =/= fg(x)

but I'm not sure about permutations

[safe radish]

@misty summit Has your question been resolved?

[safe radish]

@misty summit Has your question been resolved?

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[pastel verge]

Work?

[wraith prism]

What do you mean?

[pastel verge]

Where is your working

[wraith prism]

What?

I want to understand how to solve this question

[steep dove]

do you know what bounded means

[wraith prism]

Yes of course

Upper limit and lower limit exist

[steep dove]

yeah

you dont need to worry much about lower limit since a_n will always be positive

[wraith prism]

Wdym rearranging?

[steep dove]

so 0 is lower limit

[wraith prism]

May I ask why?

I want to know how 0

[steep dove]

can you specify

what are you asking why about

[steep dove]

this?

[steep dove]

or this?

[wraith prism]

An will be positive how?

[steep dove]

well, once you solve for a_{n+1}, it should be clear why it will always be positive

[wraith prism]

I see sure. What should we do now?

How to get an+1?

[steep dove]

how would you solve a normal equation

[wraith prism]

I will put y left side and all other things right side then put 0,1,-1 or find roots by different methods

[steep dove]

you dont need to find roots

just solve for y

https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-solving-equations

[wraith prism]

7 videos in it.

What do you mean by solve for y?

A general solution?

[steep dove]

reciprocal both sides

[steep dove]

then multiply by 4

[wraith prism]

That's what I said above

U can say Don't find roots only seperated

[steep dove]

yeah

well anyway

[wraith prism]

Hmm fine

So what next

[steep dove]

now that you have that, you can simplify the right side

common denominator stuff

make it a single fraction instead of a double fraction

[safe radish]

@wraith prism Has your question been resolved?

[safe radish]

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[twin solar]

can somebody please tell me how can i convert this system of
$$
y'''+xy''-y'-ln(x)y=13e^x
$$
int first order linear system?

[flat frigate]

marejak023

[wraith prism]

.open

[still charm]

this just looks painful

[safe radish]

@twin solar Has your question been resolved?

[twin solar]

what?

[tall bough]

Mr. Gamer gave his opinion that your question looks painful, which may refer to it being hard or annoying.

[twin solar]

oh, well this topic is really not hard, I am just bit lost on how to do it, but nothing horrible haha

[safe radish]

@twin solar Has your question been resolved?

[safe radish]

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[earnest wagon]

Is $$\frac{x^{4}+3}{x^{2}+1}$$ a polynomial?

[flat frigate]

Calamity

[earnest wagon]

I did a long division, remainder was 4 and quotient=x^2-1

[peak estuary]

nonzero remainder => no

[earnest wagon]

Ohh

Okay thanks

.close

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[mighty yarrow]

You're not wrong, this is very poorly worded. Technically speaking their answer is the closest number to the true value which can be expressed as the sum of two 10-adic rationals, but the typical interpretation of "answer to two decimal places" is "with accuracy on the order of $10^{-2}$" I'd just talk to the teacher and ask what they want you to do

[flat frigate]

OnlyAnalysis

[worthy hemlock]

Because you didn't apply proper rounding rules

[mighty yarrow]

I think his issue is with the definition of "two decimal places"

They didn't e.g. say "two significant digits"

[worthy hemlock]

It's a website, it treated 4.90 = 4.9

[mighty yarrow]

Yeah dldh is right then

[worthy hemlock]

That's the answer if you don't round

[mighty yarrow]

they want you to round to the nearest hundreth

[worthy hemlock]

But because it asked for 2 d.p. and applying proper rounding rules 4.89796, that equals 4.90

Two d.p indirectly means to round to 2 d.p

[mighty yarrow]

If you want a reason beyond appealing to rounding rules, 4.90 is closer to the true value than 4.89 so it's a better estimate

[worthy hemlock]

Not really, it's common knowledge/sense

[mighty yarrow]

This is the spirit behind the rounding rule

[safe radish]

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[mighty yarrow]

yo what's up?

yep

sorry went adk for a sec

You want the closest number to the "true solution" that can be written as a sum of integer multiples of 10^{-2}

There is one other convention

in the rare case when you have a terminating decimal of the form $a.bc5,$ your number is equidistant to $a.bc$ and $a.b{(c+1)}.$ note I've assumed $c < 9.$ In this case you always round up

I.e. we choose $a.b{(c+1)}$

[flat frigate]

OnlyAnalysis

[mighty yarrow]

If $c = 9$ this will force us to carry terms

[flat frigate]

OnlyAnalysis

[mighty yarrow]

in other words: if the digit below the .ab is 5,$ always round up

[safe radish]

@lean otter Has your question been resolved?

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[cursive vault]

Does anyone know how to solve for this limit?

[cursive vault]

I know the answer is 1 but I don't know how to get to it

[clear blade]

divide everything by x^2 (the highest degree term in both the numerator and denominator)

that's one way to see it

but it's easier if you learn the general rule for limits of rational functions based on the degree of the numerator and denominator

[cursive vault]

yea that's the method that's proposed but every other limit question ive done so far hasn't used this method

i was wondering if i could solve it by simplifying instead or something

[clear blade]

this is a common method when taking the infinite limit of a rational function

[stoic dune]

Different limit questions have different methods

• x going to infinity?
• Rational function?
• Numerator and denominator have the same degree?

Divide by the highest degree of x.

[clear blade]

or if degree of denominator is greater

[cursive vault]

alrighty, ill learn this new method then

.close

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[stoic pilot]

Can anyone give this a better explanation lol

skipped a couple of steps there id say

[merry sleet]

E = Y-XB?

B is a matrix? a vector? a scalar?

give some context pls

[stoic pilot]

ah sorry

[stoic pilot]

Y and B are vectors, but X is a matrix

[merry sleet]

ok

the ' is for derivative?

[stoic pilot]

transpose

[merry sleet]

ok

[stoic pilot]

X and Y are constants

[merry sleet]

so developp the product first

and then you can take the derivative no?

[stoic pilot]

Wdym by develop the product

you can't like foil it can you

[merry sleet]

well its multiplications and additions

like distribute

[stoic pilot]

oh I get it lol

oml

[merry sleet]

Y'Y - B'X'Y - Y'XB +B'X'XB

something like this

[stoic pilot]

(Y-XB)^T * Y - (Y-XB)^T * XB

[merry sleet]

come on you could have distributed all at once

[stoic pilot]

waitwaitwait

[merry sleet]

oh maybe you dont know the rules for transpose

(A+B)' = A'+B'

(AB)' = B'A'

[stoic pilot]

😅😅

its been a while

[merry sleet]

and (aA)' = aA'

[stoic pilot]

yeah I kinda forgot that was a thing

[stoic pilot]

remembered that

[stoic pilot]

thought that there was no way to convert it haha

that makes much more sense

tyy

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[delicate bison]

Hello

[delicate bison]

I have a question i dont know how to solve n1 and n2

[stray socket]

!status

[safe radish]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[delicate bison]

1

[stray socket]

Find the slope between J and K

[delicate bison]

Ok

1 sec

I got -1

[stray socket]

No

[delicate bison]

How do u do it then

[stray socket]

You should be familiar with the slope formula

[delicate bison]

Isnt it like

Y2-y1 over x2-x1

[stray socket]

Yeah

[delicate bison]

Oh i thought the 3 was a negative

Mb

Its -5

Nvm i got it thanks tho

[safe radish]

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[novel perch]

Is about proofing if the equation for those sets is correct

I dunno if my notations are alright

I kinda don't have any examples or solutions 🙄

Is the stuff I am doing here correct?

[safe radish]

@novel perch Has your question been resolved?

[granite idol]

looks right

[safe radish]

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[mild brook]

I went as far as to reach 6^3+n = 1

cant go any further

[wise blaze]

6^2=36

[tall bough]

yes

[vapid anvil]

$6^2 = 36$

[flat frigate]

ColdTee

[peak estuary]

for which power k is a^k=1

that said, you didnt simplify correctly

[mild brook]

Ahhh

does it become

(6^2)^3+2n = 6^6+4n

for the numerator

?

[tall bough]

yes

[mild brook]

uhuh

and does it become 6^6+3n/6 = 1?

[tall bough]

no

[peak estuary]

please use correct brackets

[mild brook]

no?

[peak estuary]

in the exponent

6^(6+4n)

[mild brook]

sorry

first time here lol

hm

so it’s not what i said

what would it be?

6^(6+3n) = 6?

[tall bough]

no

[tall bough]

without 6

on denominator

[mild brook]

what about

6^(6+4n) = 6^(n)

[tall bough]

ok

[mild brook]

6 = n - 4n?

[wise blaze]

$\frac{6^{6+4n}}{6^n}=6^{6+3n}$

[flat frigate]

MochaOhwelp

[peak estuary]

remember that $\frac{a^b}{a^c} = a^{b-c}$

[flat frigate]

Denascite

[mild brook]

so sorry

i forgot to mention

my textbook is very weird

and it isnt american

so things are worked differently

the answer is -2

[wise blaze]

yes

its right

btw $x^0=1$

[mild brook]

what about x?

[flat frigate]

MochaOhwelp

[wise blaze]

x can be all real number except 0

[peak estuary]

nonzero

[earnest wagon]

0^0≠1

[wise blaze]

i forgor that

[mild brook]

may i ask more questions?

[pastel verge]

Maybe

[mild brook]

am i allowed?

[pastel verge]

Maybe

[peak estuary]

dont ask to ask

[pastel verge]

Just ask

[mild brook]

Okay

I ended up with 4/3 - 2/9

which simplifies to 10/9

however

it’s wrong

[pastel verge]

Left side is wrong

[mild brook]

isnt 3/2^(-2) just 2^(2)/3?

[peak estuary]

why did you move the 3 down in the first fraction

[mild brook]

negative indices

[peak estuary]

only for the 2

[worthy hemlock]

The 3 doesn't have one

[mild brook]

Oh wait

Im stupid

it should be

3 • 2^(2)

right?

[pastel verge]

Yes

[peak estuary]

yes

[mild brook]

and it becomes

[pastel verge]

Same pinch

[mild brook]

12 - 2/9

which becomes

108/9 - 2/9

which equals 106/9

what about

this question?

would it become

7^(1-x)/4^(1-x) = 4/7

and then wouldnt the powers cancel out?

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[sweet thicket]

use proportional relationship

[desert marsh]

i'm 13 by the way

[desert marsh]

whats that?

[sweet thicket]

wait if u are 13 let me send u something that will help u understand then but read it okay

[desert marsh]

sure

@sweet thicket

hello?

[desert marsh]

oh this is ratio

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[serene kraken]

i got lost with numbers

[severe smelt]

we also know K,M are elements of the set {0,1,...,9} since we have this set up like a subtraction problem

[serene kraken]

okay i really got lostt here

can u pleas solve it on the pic

[ionic kraken]

no they have to have the same base to cancel

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[random mural]

does this part fit with the zero otherwise or on the pdf?

[plucky elk]

theta is positive for all of your questions

[random mural]

ahh okay thank you

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[serene kraken]

8th

anyone have an idea to solve it?

[safe radish]

@serene kraken Has your question been resolved?

[serene kraken]

<@&286206848099549185>

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[serene kraken]

13th

[thin bridge]

you were aware that completing the square was helpful here
you've successfully converted your quadratic expression to vertex form
you should pretty much know how to get the min from this already

[serene kraken]

do i have to make the x=0?

[thin bridge]

no

[serene kraken]

okay help me what should i do next

[thin bridge]

recall your notes,
think about why you even tried to approach this with completing the square

and/or what information the vertex form gives you about a quadratic expression

[serene kraken]

i solve it thank u

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[jolly epoch]

This getting me crazy, I tried like for 3-4 ti.es and got different answers and didn't get the right answer at all, someone help plzz

Can I also get some advices to not make mistake or a way I can follow to not fall in easy mistakes like forgetting a number or plus or minus

[granite idol]

what class is it for? or what level of math?

and your first equation should have a "-12" instead of plus

[jolly epoch]

Idk if same system here, but we call it math 2c, for first yr at high skl

[granite idol]

then you probably learned substitution?

[jolly epoch]

a -12, didn't got it

[jolly epoch]

Yee

I learned both method

[granite idol]

well elimination might be easier, if that's the other method

[jolly epoch]

Ohyhyh -12

[jolly epoch]

I tired this way

I tried both way😭

Idk what I'm doing for mistakes

If I devide the first one by 3

[granite idol]

well did you fix the first equation? to have a -12

[jolly epoch]

And then w -1

[jolly epoch]

Yes, imma try do it now

[granite idol]

and if you divide the first equation by 2, you can eliminate "x", then solve for "y"

[jolly epoch]

Done that

Or not that

Wait imma try ur way

[jolly epoch]

The first?

Cos it's 6x

And the 2nd have 3x

So the 2nd ?

[granite idol]

you could multiply the second equation by 2 if you wanted to

and then subtract equation 2 from equation 1

[jolly epoch]

Ohhhyhhh

Nowwwwww

Everything was ruined cos of the +12😂I even confused my teacher

Any advices to not make those mistake

[granite idol]

no you have to multiply everything in the equation by 2

including the "7y", and the "4"

[jolly epoch]

Imma kill myself 🤦‍♀️

Hkjk

Jk*

Wait

I got

-14y+9y=-16

[winged cloak]

in line 1

is that a + or a -

[granite idol]

not quite, re-check your arithmetic

[jolly epoch]

Which one?

[granite idol]

they already fixed it

[winged cloak]

so which one is it

[granite idol]

it should be 6x - 12, as I said above

[jolly epoch]

I got 5y=-16

That's drivning me crazy

[granite idol]

no, make sure you multiply everything in the second equation by 2

then subtract equation 2 from equation 1

do it carefully

[jolly epoch]

Imma do it for 100000 time now hahaha

Now right?

Bro how stupid i can be to fall in different mistakes more than one time🤦‍♀️😂

[granite idol]

yes

so now you can solve for x

[jolly epoch]

Yee done it

Thanks a lot frrr:))))

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[glacial pawn]

I'm learning Complex numbers and while watching the video i saw this
can anyone explain why the blue one going like this and not how i draw it ?

[marsh walrus]

just for the number -1+2i?

[glacial pawn]

yes

[viral loom]

i = up

[marsh walrus]

imaginary axis is vertical

real is horizontal

[glacial pawn]

and why isnt the same with the red one?

[viral loom]

it is

[marsh walrus]

its a different number but the same convention is used

[viral loom]

3 = real part (horizontal)

i (vertical)

it's the same

[glacial pawn]

can u tell me how can i see the x y ?

isnt -1 and 3 the x

and 1*i is y ?

[viral loom]

You might be looking your own draw, that's why u're getting confused

[glacial pawn]

ig but still i dont get it

i was told i has the function to make the vector 45 degree

[marsh walrus]

just think of them like coordinates

[glacial pawn]

but i dont see it

[marsh walrus]

(x, y)

x+iy

[glacial pawn]

i was doing it on the red on

[glacial pawn]

but with blue it was confusing

[marsh walrus]

it is exactly the same convention

[glacial pawn]

wait am i stupid orblind

[marsh walrus]

you might review plotting points in 2d coordinates tbh

[glacial pawn]

i guess i was blind

[marsh walrus]

https://www.youtube.com/watch?v=yaOf7ioCgFQ

ah

it happens

[glacial pawn]

but onther question

i

what does it do

[glacial pawn]

i cant see an impact from it in this graph

[marsh walrus]

do? impact?

what do you mean

what does what do? to what?

[glacial pawn]

the number i

was it not for 45degree

[marsh walrus]

it gives a number an imaginary component

was it not for 45 degree

im not sure what you mean

[glacial pawn]

hahaha i saw a video talking about the number being used to turn vectors for 45 degree

i have to watch it again before i talk probley i got it wrong

[marsh walrus]

well if you compare 1 and 1+i

they will be separated by 45 degrees

i dont know if thats what you mean

[glacial pawn]

yes

[glacial pawn]

that it

i will end it for now but thank u for helping me and sry for taking ur time by a dumb questions

.close

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[marsh walrus]

nah ur good

no questions are dumb questions

[glacial pawn]

should i type reopen or something ?

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[mortal sandal]

Try to think about some kind of symmetry that simplifies things

[glacial lodge]

I am thinking of 1/4 probability of each operation

then products and multiplication cancel out except one 3 so there is a 3 down there but there can be a lot of posiblity there

[mortal sandal]

think maybe of some kind of +- correspondence

[glacial lodge]

all i can gei it 3K or 1/3K 1 , 3K are not co-prime

i would be happy you provide me with the solution

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[gritty lotus]

im working on this summation problem and need to right my answer in terms of n

but im having trouble dealing with k/n

I found a mistake and updated the last line

@icy lance sorry for the ping but would you happen to know whts wrong here?

i cant seem to figure it out

[icy lance]

why did it become 24 * k/2?

[gritty lotus]

tht was a error

its supposed to be 48

oh shoot i didnt update it in the ss i sent

one momment

my confusion is with the 16(k^2/n^2)

cause k = n right? or rather we replace it with n

so shouldnt it just b 16*1=16

[icy lance]

why is the summation formula having n/2 also, you would have 48/n *(the general formula for n)

youre not replacing k with n

that would apply if it was a limit but this is a sum

you will need to use the general formula for k^2

[gritty lotus]

so then how do we get rid of k?

cause the question asks for answer in terms of n

[icy lance]

its the same as the last question, you have 36n+(48/n)(general sum formula for k) + (16/n^2)(general formula for k^2)

the general formulae are in terms of n

[gritty lotus]

what is the general sum formula for k used to get 48/n?

im not sure if i fully understand that part

[icy lance]

the 48/n isnt from the formula, its factored out, the sum of (48k/n) =48/n * the sum of k

its like sum(2k)=2* sum(k)

same logic

[gritty lotus]

im so confused

ok what would be the answer?

maybe i can look at that and figure it out

[gritty lotus]

still a bit confused

[icy lance]

you just apply the general formulae to the two sums as usual