help-19

[red perch]

Hold on let me draw it for you

Is that clear?

[feral mirage]

but what about a and b

[red perch]

They are complementary angles I think that's what you call ot

Means that

A and b will both be equal to 180

[feral mirage]

but that would only be possible if the lines were parallel and the line was perpendicular right?

[red perch]

Yea but the given figure can assume it is parallel

[feral mirage]

it never mentioned that

so idk if this was like a bonus or an error

[gritty spire]

no

it doesnt matter whether they are parralel

plus just eyeballing conditions not in the text is 99% wrong

@feral mirage are you still here

[feral mirage]

yes

[gritty spire]

so

uh

do u know the

uh

外角公式

[feral mirage]

just speak eng

cuz my chinese aint that good

[gritty spire]

bro idk the word for it

hang on

[feral mirage]

describe it

[gritty spire]

using ts

[red perch]

Exterior angle theorem

[gritty spire]

u can

[feral mirage]

oh yea

ik that

[red perch]

Sorry for assuming the lines are Parallel and perpetual

[gritty spire]

move the d+f and c+e into two angles

[feral mirage]

ok then what does that have to do

so b = d + f and a = c + e?

[gritty spire]

which form the interior of the bottom quadrangle

[gritty spire]

no, its the other 2 unnamed angles

in the bottom quadrangle

[feral mirage]

oh wait

mb

ohhhh

i understand it now

thanks

how u close this

[gritty spire]

type

.close

[feral mirage]

.close

[odd edge]

Channel closed

Closed by @feral mirage

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid leaf]

hi! im evaluating improper integrals for the first time, and i got smacked in the face with the laplace transform. im super confused, im doing my best to integrate by parts but in the final step i realized i messed up somewhere and am getting a different answer than the key shows. can someone try to explain to me where the mistake is? for clarity, i took capital i to be the initial integral just so i didnt have to write it out again haha

[rancid leaf]

shit i think i see it nvm

i shoulda rubber ducked it

.close

[odd edge]

Channel closed

Closed by @rancid leaf

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hot oar]

need help with this one

[hot oar]

heres what i did but it looks wrong

specifically the orthogonal part

[haughty scaffold]

seems right to me

why do you think its wrong

oh

one thing

in the orthogonal

you have -2k - 27/14k

and that somehow turns into +2-27/14

once you fix that youre golden though

[odd edge]

@hot oar Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[loud rune]

I'm trying to take derivative of a cube-root radical and I've attempted to use a conjugate by utilizing the difference of cubes identity

[loud rune]

I got to the point of direct substitution and I thought everything was going well, but apparently my answer is incorrect

[nimble blaze]

show attempt

[loud rune]

my algebra isn't great, so i feel like i'm missing something with the radicals at the end, because h comes out quite nicely

[nimble blaze]

seems ok, who's saying it's incorrect

[loud rune]

webassign :\

[nimble blaze]

what exactly are you entering in the system

[loud rune]

oh

it's g(a)

lol

hahaha

[nimble blaze]

always read the question

carefully

[loud rune]

yes, moving too quickly

thanks for the reminder and thanks for double-checking my work

[nimble blaze]

also, have you not been introduced to stuff like power rule?

[loud rune]

long day of class and tutoring had my brain a little fried 😭

[nimble blaze]

or are you not allowed to use it

[loud rune]

that's next in our lesson plan

yeah

not allowed yet

[nimble blaze]

ah k

good algebra practice

[loud rune]

yesss, my weakness

thanks again!

.close

[odd edge]

Channel closed

Closed by @loud rune

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elder vault]

Why A,P, and D are on the same line

[mystic saffron]

do you know ceva?

[minor bronze]

ceva theorem

[elder vault]

NO. can you explain it in simple words

[mystic saffron]

it says that if D,E,F are points on BC, CA, AB then AD, BE, CF concur if and only if BD/DC * CE/EA * AF/FB = 1

but if you're supposed to use something else then idk if you can use this

[minor bronze]

do you know燕尾模型

[odd edge]

@elder vault Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow crypt]

,rccw

[odd edge]

@still blade Has your question been resolved?

[odd adder]

well with "it was not partly sunny on friday" and "i worked last monday or I worked last friday"

you can deductively infer that friday must've been a sunny day

yeah but can't you just formalize that

W(x): I work on day x
S(x): It is sunny on day x
P(x): It is partly sunny on day x

P1: W(x) -> (S(x) ∨P(x))
P2: W(M) ∨ W(F)
P3: ¬S(T)
P4: ¬P(F)

Then you have two cases to consider

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vernal yacht]

mhm, but this is not a question as far as I’m concerned

[short terrace]

I think they were answering the question that was here previously

Or continuing off it

[minor bronze]

we can close this now, can we?

[short terrace]

That's up to them really

Cuz technically they are continuing their own question

[odd adder]

yes

[golden sonnet]

report it as a troll

[odd adder]

also you can say something about monday

[golden sonnet]

end it

[odd adder]

😭 what

[void yew]

It doesn't look like a troll

[short terrace]

What troll

[odd adder]

^ their actual question is here

[short terrace]

They're literally continuing from their own question

[golden sonnet]

oh

i didnt see it

[odd adder]

Lol

[golden sonnet]

and hence i landed on the wrong conclusion

[odd adder]

wait "if i work on friday"?

it's already the case that you work on a friday

[short terrace]

No it isn't

It's a disjunction

Monday or Friday

[odd adder]

okay well i thought he was considering it case by case

since he's talking about friday

exclusively here

[short terrace]

Ah

@still blade get back here and have a conversation

[odd adder]

😭

[void yew]

[short terrace]

Otherwise it's just us fighting each other

[void yew]

OP gonna timeout again at this rate

[short terrace]

And gonna reopen the channel again

And be accused of trolling again

[odd adder]

😭

[short terrace]

Ad infinitum

[minor bronze]

ill just close it

.close

[short terrace]

You can't lmao

[void yew]

Oh yay you're here

[short terrace]

Where were/are we

It's one part of it

You have two cases to consider from P2

This is the W(F) case

What about W(M)

[minor bronze]

i thought we can

lol

i could close others one sometimes

[odd adder]

that's the other half of the conclusion

yeah

[odd edge]

Channel closed

Closed by @still blade

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager sable]

how do i prove that (a+b) ² - (a-b)² = 4ab?

[atomic hornet]

just expand

[hollow quarry]

Expand the LHS

[eager sable]

yes but if i expand how do i come to the conclusion that's it 4ab?

because i would have
a² + 2ab + b²
a² - 2ab + b²

[hollow quarry]

Simplify the expression

remember the minus too

[eager sable]

what do you mean by this

[nimble blaze]

general simplification practices,
combine like terms, cancel where possible, etc

same meaning as in something like simplify
4x + y + x + 2y
(random example not related to your question)

[odd edge]

@eager sable Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hot oar]

unclear where to start on this one

[late dust]

Make a plane with two vectors, for example PQ and PR; all points on that plane are then of the form P + aPQ + bPR; check if S is of that form

[hot oar]

why only 2 vectors

theres 4 points

[mortal trench]

3 points define a plane

Then check if the 4th point is on that plane

[viscid crescent]

it should be 3 vectors

PQ,PRand PS

[mortal trench]

Nope you only need 2 vectors (plus an initial point)

[viscid crescent]

AND FOR COLLINEARITY you need them to be parallel

OR WAIT!!

Why not use parametric equation of line

r=A+λ(B−A)

And if bot set of points follow it they are collinear

or maybe check for ABxAC=0
if its true A,B,C are linear then

do the same for ABxAD

if it checks out

then all four points are collinear

[late dust]

You should read the question again

[odd edge]

@hot oar Has your question been resolved?

[warped glacier]

https://math.stackexchange.com/questions/1330357/show-that-four-points-are-coplanar

you're fairly close to the right idea

with the 3 vectors PQ, PR, PS, you could also check their determinant

if the determinant is 0, then yes, they lie on the same plane (at least, so they could also all be collinear)

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[honest turtle]

Tan x = sin x/cos x

[vagrant pilot]

Hey check this outt!

.close

[odd edge]

Channel closed

Closed by @vagrant pilot

Use .reopen if this was a mistake.

[vagrant pilot]

i did it

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz pier]

can someone pls tell me what i did wrong here (finding the simplified boolean expression from a k map)

[quartz pier]

im acc stuck

https://tenor.com/view/squidward-spare-change-spare-some-change-begging-poor-gif-18999842

[cerulean vortex]

seems right

[quartz pier]

but its messing up my circuit

and its this hex for sure

let me send my truth table that iderived this from

S_2 output from here

lemme send the tets acse i failed one sec

it should be outputting 1 for the first and 0 for second but mine does the other way

I reviewed my circuit aswell its the same as my simplified expression

oh btw D3 = X3

when i only turn on the d0/x0 pin

acc looking at the expression it doesnt seme possible for it to be 1 when only x0/d0 is on....

[cerulean vortex]

this table says 0001 is 1

[cerulean vortex]

but this one says 0001 is 0

[quartz pier]

so my simplified expression is wrong right

so that means i grouped wrong

but i dont know how

bcz my truth table is for sure correct

[cerulean vortex]

your expression matches the table but the tables don't match

[quartz pier]

oh what

i dont get it

[cerulean vortex]

why is your table correct?

[quartz pier]

because hex 2 should be on for the digit 1

like

right now its doing this

its not turning on the second hex

my truth table says it should

but my expression says it shouldnt

so im confused

[cerulean vortex]

you think the tables match?

[quartz pier]

like the kmap and the table?

oh wait

[cerulean vortex]

the two things that i linked to

[quartz pier]

OMGGG

bro im so sorry

smh

tysm

.close

[odd edge]

Channel closed

Closed by @quartz pier

Use .reopen if this was a mistake.

[cerulean vortex]

no problem

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quartz pier]

how about now

Its still not working

I dont get it

[cerulean vortex]

shouldn't the first line in the k-map be 1110?

[quartz pier]

bro there is something acc wrong with me rn

mb

let me fix and try agaib brb

[quartz pier]

\bar{X_1}X_0

oops wrong paste

I dont know how I keep making it worse

hasss to be the way im grouping

do i group the 4 1s on the left twice? (2 overlapping 1s)

[cerulean vortex]

you made an error when you factored out x_3 bar

[odd edge]

@quartz pier Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silver sapphire]

I never know if my proof is solid enough or not

[silver sapphire]

Proof. Given A and B are countable. Then there exist two total surjective functions $g$ and $f$ defined as:
[ g: \N \to A]
[f: \N \to B ]

Define a total subjective function $h$
[
h(n) =
\begin{cases}
g(n/2), & \text{if } n \text{ is even} \[6pt]
f((n-1)/2), & \text{if } n \text{ is odd}.
\end{cases}
]
for all $\ n \in \N$

Since $h$ interleaves both sets, $h$ subjectively maps the union of A and B to $\N$.
Therefore, $A \cup B$ is countable. $\square$

[clever fjord]

Scriptkitty
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[silver sapphire]

I don't know if my conclusion is correct

[odd edge]

@silver sapphire Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent schooner]

Hi, is this correct?
My doubt comes from 1. to 2. , if we can quit the log from the square root

[atomic hornet]

Not sure about your work

[latent schooner]

Ok, ty anyway

[short terrace]

What is the base of the log

[latent schooner]

10

[short terrace]

Wait is this an equation and you're solving it for x

[latent schooner]

Yes

[short terrace]

Cuz the way you've written makes it look like 7 different questions lmao

[latent schooner]

I have one doubt but to clarify I put numbers to order it

[short terrace]

The first step doesn't seem correct

Could you explain to me what you wanted to do to go from 1 to 2

[latent schooner]

Quit the log so it's easier for the equation than developing the log elevated 2 inside the square root and then have a large number on the square root

[clever fjord]

Xavier 🌺

Well $\sqrt{a+b} \neq \sqrt{a} + \sqrt{b}$

[short terrace]

What you're supposed to do here is square both sides

[latent schooner]

Ok, I'll try it ty

But if there is one term elevated 2 on a square root, we cannot quit it from the root? Quitting also the exponential 2?

[short terrace]

If it's the only term then yes

Unfortunately it isn't in our case

[latent schooner]

√3^2 + 7, this is not 3√7?

[short terrace]

No

[latent schooner]

Ok, I'll study it ty!

.close

[odd edge]

Channel closed

Closed by @latent schooner

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[edgy holly]

How do I prove this?

[edgy holly]

I mean I understand its obvious by drawing cones. But how I do I show this mathematically.

Brothers and Sisters. Why so silent?

<@&286206848099549185>

Anyone?

🙏

How to begin this?

[golden sonnet]

brilliant.

will do it somehow.

absolutely brilliant.

[edgy holly]

I don't get it.....

was that sarcasm?

<@&286206848099549185> Help Helpers. Why does everyone get a answer except me 😭 . This is my third time posting consequitively with no answer.

[abstract epoch]

!15m

[odd edge]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[abstract epoch]

i havent read this yet so i cant help

[edgy holly]

Its been 15 min

[abstract epoch]

been like 10 since the 1st ping

[edgy holly]

it says if your question has not been answered. So itsn't it like after posting 15 min?

I am not sure

But I didn't get any response but the first ping, so I had to second ping anyway. Is my system glitched?

[stoic cloud]

doesn’t matter

[abstract epoch]

ok sorry mb

i thought it was supposed to be atleast 15 mins after posting the questions and between pings

[atomic hornet]

Honestly, there is a strong relation between the assistance you may receive and the difficulty of the question. If you cannot get help here, might consider moving it to topic channels. At there, you have higher chances to recevie helps.

[edgy holly]

That's honestly sad

This is not even tough. Its pre-calculus

I am just stuck

Ok Imma go to the Topics channel

.close

[odd edge]

Channel closed

Closed by @edgy holly

Use .reopen if this was a mistake.

[blazing wolf]

That’s not precalc lmfao

[edgy holly]

isn't conics pre-calc

or Algebra-b

[amber veldt]

these have partial derivatives my friend

[blazing wolf]

PDEs my bro

Do y still need help

[edgy holly]

Yeah

[edgy holly]

please help

[blazing wolf]

Tell me what class it’s for and I’ll do it

[edgy holly]

11th

[crystal zinc]

don't do it for them

[blazing wolf]

What the

[crystal zinc]

just guide them

[edgy holly]

guide me

thats better

[blazing wolf]

Alr

[golden sonnet]

nah never

[blazing wolf]

First read the question

[golden sonnet]

why would i do that

[edgy holly]

also why?

[edgy holly]

done

[crystal zinc]

this was a corollary in the second year of my degree

if I find it I'll send it

[edgy holly]

thanks

[golden sonnet]

how can they expect it from us then

it is weird tbh

[edgy holly]

bro its not that hard. I mean understanding it.

Proving it is a whole different world

[blazing wolf]

Okay first

[golden sonnet]

uk partial differential?

[blazing wolf]

Differentiate f

[edgy holly]

physics bro. WPE. That much only

[golden sonnet]

yea

[edgy holly]

I get two equations

two lines that are given to be exact

[blazing wolf]

$$\frac{\partial{F}}{\partial{x}}= \frac{\partial{L_1}}{\partial{x}}L_2 +L_1 \frac{\partial{L_2}}{\partial{x}}=p_1 L_2 + p_2 L_1 $$

[clever fjord]

Benjamin

[blazing wolf]

And the other is

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal zinc]

oh it indeed looked something like this

[crystal zinc]

oops i just claimed the channel

[edgy holly]

no problem

[blazing wolf]

$$\frac{\partial{F}}{\partial{y}}= \frac{\partial{L_1}}{\partial{y}}L_2 +L_1 \frac{\partial{L_2}}{\partial{y}}=q_1 L_2 +q_2 L_1$$

[clever fjord]

Benjamin

[blazing wolf]

Now evaluate these at a common point

Im not doing the rest you should know how to do it lol

This isn’t 11th grade math bro is rage baiting

[edgy holly]

I am not bro

THis is truly 11th grade 💀

[golden sonnet]

it is

fr

[blazing wolf]

That’s crazy

[golden sonnet]

one of the hardext exams of the world needs such grit and determination tbh

it aint the hardext exams of the world if such clarity isnt maintained

[edgy holly]

bro I think SAT is harder than JEE

because English is there

💀

[blazing wolf]

If the two lines are parallel or coincide then the determinant is 0 and the system of partials does not give a unique intersection point, this is what you want for this degenerate case bro

[golden sonnet]

nah nah

no chance

[blazing wolf]

So that’s all

The SAT is easy asf

[edgy holly]

ok got it

Thank you very much @blazing wolf . I cant show how grateful I am

[blazing wolf]

No problem bro

Good luck in your studies

[golden sonnet]

@edgy holly sorrry mate that i didnt even start solving this problem of yours

[edgy holly]

@crystal zinc Close this if possible

[golden sonnet]

i thought i would but didnt

[crystal zinc]

!close

.close

[odd edge]

Channel closed

Closed by @crystal zinc

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic schooner]

im just confused how when you do the problem you get x is greater than or equal to 13 and less than or equal to 4 to get you know the values to plot on the line but somehow the sign ends up changing to just greater than for the value 4 and idk why the sign changes lol

[arctic schooner]

the video is an example of a different problem but theyre both done the same exact way

[lament forge]

you can't divide by 0 and if it were equal then the denominator would be 0

not sure if that's what you're asking

[arctic schooner]

ohhh

ok that makes a lot of sense i was asking about that yes

tank u

.close

[odd edge]

Channel closed

Closed by @arctic schooner

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm linden]

is there an easier way of finding the value of this that doesnt involve splitting into 2 different summations

[tacit elm]

Hmmm what’s 2 infinities ?

Oh oh oh it’s 200 ! Sorry

[low locust]

splitting it into two summations is already pretty easy

doesnt get much easier

[storm linden]

is there a better way of just doing it in one or should you just split it

[tacit elm]

Split it, it’s really no big deal

[nimble blaze]

you could apply AP directly

[storm linden]

can you

does r always have to equal 1 to do it or is that just geometric

[atomic hornet]

it's basically 5(5+6+.....) -2*(200-5+1)

[nimble blaze]

there is no r here, this is arithmetic not geometric

[storm linden]

i mean the bit on the bottom of the summation

can you work it out just with r=5 or does it always have to be something=1

[tacit wasp]

So the 2?

[nimble blaze]

why r

[tacit wasp]

r is for geometric sequences, not arithmetic

[storm linden]

idk why r it says r in the question

im just wondering if theres a shorter way of going about it

[tacit wasp]

Ohhh that r

[nimble blaze]

oh shoot, sry

starting index doesn't matter that much

[tacit wasp]

The shortest way is probably splitting the sum. But if the sum had started from 0 then the formula for the sum of an arithmetic sequence would be faster, but only a little

[nimble blaze]

choose the most appropriate formula for what you have

[cerulean vortex]

if you don't want to separate it and use the triangle sum formula, there's this formula

[nimble blaze]

the fastest way is the way you're most comfortable with

[storm linden]

idk im just prone to making stupid mistakes especially with series

[odd edge]

@storm linden Has your question been resolved?

Channel closed

Closed by @storm linden

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic swift]

I'm struggling with dimensional analysis, I need to find d here. I've tried multiplying the given values multiple different ways, but I just can't find side length

[pallid epoch]

Hi again

[arctic swift]

Oh hello

This is my current attempt, but my program says it’s wrong

[pallid epoch]

Okay so I would suggest starting by assuming you have 1 cm^3 of it

How many grams of it do you have?

[arctic swift]

We have a mole, so 238g

[arctic swift]

Wait why assuming this?

[pallid epoch]

Well... if we can work out how many atoms are in 1 cm^3, we can then divide our 1 cm^3 up into that many pieces and we're done

[arctic swift]

Okay... I guess I follow?

Hang on, let me try and figure out atoms/cm^3

Well I've calculated 1 mol taking up 12.741 cm^3....

Wait a minute

[pallid epoch]

That's not how I approached this but if you do it correctly it should come out the same

[arctic swift]

Is your way more efficient?

[pallid epoch]

Well... it makes intuitive sense

Do you have an intuition for your method?

[arctic swift]

I'm not sure. The thing that's throwing me off is that I'm given density in g/cm^3 when I want to know it in g/mol (I think)

[pallid epoch]

This suggests to me that you don't have a complete intuition for it

So let's approach it my way for now

Maybe you can figure it out your way afterwards

So let's assume we have 1 cm^3 of it

And we want to know how many atoms of it we have in there

[arctic swift]

Okay

[pallid epoch]

How many grams of it do we have?

[arctic swift]

18.68g

[pallid epoch]

Mmhmm

How many atoms is that?

[arctic swift]

Oh wait okay

Thats 0.078 (18.68g/238g) of a mole, so we have that same proportion of atoms. so we have about 4.725x10^22 atoms

[pallid epoch]

Okay

So that's how many are in the cube

How many are in 1 side of the cube?

[arctic swift]

Cube root, so ~36151983.94 atoms

[pallid epoch]

What's the length of the side?

[arctic swift]

1 cm

[pallid epoch]

So what's the diameter of 1 atom?

[arctic swift]

36151983.94 atoms / 1cm

Do we flip it? 1/36151983.94?

No, that's basically the same as my wrong answer...

[arctic swift]

I just don't know how to make this leap of logic from knowing atoms/cm

[pallid epoch]

Okay so we have 36151983.94 atoms = 1 cm

[arctic swift]

Yes

[pallid epoch]

So 1 atom = ? cm

[arctic swift]

1/36151983.94?

I just don't know what you're getting at

[pallid epoch]

Yep

[arctic swift]

My homework program is giving me incorrect, I'm not sure what's wrong

[pallid epoch]

Look at the units

[arctic swift]

oh f*** me

x100

[pallid epoch]

Also, I'd keep it in exact form so you don't get rounding errors as you go along

[arctic swift]

That's still wrong... its the same thing but 10^-6 right?

I might just email a TA or something

[pallid epoch]

Nope

How many m is 1cm?

[arctic swift]

0.01

Oh, I should be dividing by 100

That was right

[pallid epoch]

There we go

[arctic swift]

Should I just do the whole problem with the SI units converted at the start, or convert at the end?

Like 0.238kg instead of 238g

[pallid epoch]

Why would you do that?

You have g/cm^3 and g, so it makes sense to just leave them as they are

Just make sure to keep track of your units as you go along

[arctic swift]

I suppose, yeah

I guess it doesn't matter for most since they all cancel out anyways

[pallid epoch]

I got 2.76917 × 10^-10 btw

Does that help?

[arctic swift]

Yes, thank you

[odd edge]

@arctic swift Has your question been resolved?

Channel closed

Closed by @arctic swift

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silk crescent]

not that sure how to use a piecewise function

[lyric dust]

piecwise function just tells u how the function works in pieces as written in each line

so for example, if x is less than or equals to 1, f(x) = 1

if x is say, 0.5, it is between 0 and 1, so we use the 4th row which tells us that f(0.5) = -0.5

[silk crescent]

how do i apply that to limits tho

[lyric dust]

let say we want to look at the left hand side of the limit 0

or $0^-$ depending on whatever notation u prefer

[clever fjord]

Dootud

[lyric dust]

since that is slightly less than 0

which "section" do u think that belongs to?

[silk crescent]

-1<x<0

[lyric dust]

yep

ok so then lets evaluate the limit, so we know we want to use the 2nd row f(x) = -x for our limit calculation

so lim x->0^- f(x) = lim x->0^- (-x)

and etc. for the other ones

[silk crescent]

okay

thank u

.close

[odd edge]

Channel closed

Closed by @silk crescent

Use .reopen if this was a mistake.

[cyan cape]

watch a video for piecewise function limits

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chrome dome]

really simple concept it stuck on my head it goes like:

Why does ¾ + ⅖ results in 23/20 but if we simplify it the results become 17/10?

[warped glacier]

the result is not 17/10

[chrome dome]

right

but why when i simplify it dividing 4 by 2 on ¾

so it goes 3/2 and 1/5

[warped glacier]

$\frac{4}{2 + \frac{3}{4}}$? or what?

[clever fjord]

south

[chrome dome]

its easier for me to take a pic of what im doing holdon

A = ¾ B = ⅖

whats A + B and whats A . B (i dont need help with this i already got this done its quite easy)

[warped glacier]

okay that's clearer

[chrome dome]

but why if i simplify it goes 17/10 which is wrong?

[warped glacier]

how are you simplifying it to get 17/10?

[chrome dome]

chagpt isnt helping especially with my shitty explanations

[chrome dome]

uhh so like 4 (on the ¾) is divisible by 2 (on ⅖) so i just divide both

[warped glacier]

that's not how it works

[chrome dome]

how does simplification works in adding and subtracting fractions then?

[warped glacier]

okay, so you want a common denominator

so we can always multiply any number by 1, and it won't change

in this case, we can multiply $\frac{3}{4} \cdot \frac{5}{5}$

[clever fjord]

south

[warped glacier]

cause 5 divided by 5 = 1

and also, multiply $\frac{2}{5} \cdot \frac{4}{4}$

[clever fjord]

south

[chrome dome]

right

[warped glacier]

so what is the denominator of both now?

[chrome dome]

20

thats what i understood

makes a bit more sense now that i just cant simplificate like a caveman

and i need a common denominator

[warped glacier]

yep!

so for multiplication, you just multiply $\frac{2}{3} \cdot \frac{4}{5} = \frac{2 \cdot 4}{3 \cdot 5}$ and it works

[clever fjord]

south

[warped glacier]

division is the same, cause you would multiply by 5/4 instead

but with addition and subtraction, you need a common denominator

so that the 'pieces' are the same size

like if you have a bolo de nata and you cut it into 5 equal pieces

if I have 1 piece and you have 2 pieces, you have 3 pieces of the same size, so 3/5th of the bolo

[chrome dome]

bolo de nata

sounds fancy

[warped glacier]

lmao

but if the pieces are different sizes, you can't say how much of the cake you have

you could cut a tiny piece, or you could cut a huge piece

[chrome dome]

im that case a commom denominator would be 8

but its bigger than the numbers we already have so im reverse simplifying

so wouldnt make sense

im on onto something?

Ok, thanks this helps btw, i already took a screenshot of the chat incase i need it again you can go help someone else i think i get it already

[odd edge]

@chrome dome Has your question been resolved?

Channel closed

Closed by @chrome dome

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[outer wadi]

Does this look ok, just some scratch work for the proof but are all steps valid?

[outer wadi]

part d

im kinda following what they did for proving x_ny_n converges to xy in this link
https://vignonoussa.com/wp-content/uploads/2013/01/limit-theorems.pdf

[lofty spade]

can you justify the existence of M?

[outer wadi]

since y_n convergers then it must be bounded above and below so we can take a lower bounded M where M <= |y_n| and since y_n is not equal to 0 we can choose M to be greater than 0

this lower bound doesnt have to be the greatest lower bound right?

[outer wadi]

@lofty spade

[lofty spade]

elaborate on the statement that you can choose M to be greater than 0?

[outer wadi]

by the definition of absolute value we cant have |x| < 0 so 0 is the least lower bounde of |y_n|???? if so that means every other lower bound is greater or equal to so M >= 0 but M is a lower bound of |y_n| and |y_n| cant equal 0 so M > 0

I just made up least lower bound idk if thats a thing

ive only heard of greatest lower bound

[lofty spade]

there is no least lower bound

-10000 is a lower bound

[outer wadi]

thats true

let me think some more on it

wait

@lofty spade if we let M be the greatest lower bound of |y_n| then since 0 is a lower bound of |y_n| we must have M >= 0, since |y_n| cant equal 0, M > 0

[lofty spade]

elaborate on why M can’t equal zero? consider the sequence 1/1, 1/2, 1/3, … which is a sequence of positive numbers, yet has no positive lower bound

[outer wadi]

hmm thats true, M can equal 0 because the greatest lower bound doesnt have to be included

so 0 could be the greatest lower bound

let me think some more

[lofty spade]

haha I knew you need to work on justifying M > 0 at the start, because it is a bit subtle

[outer wadi]

I agree with you, but my professor seems to have just assumed M > 0 also

he used c instead of doing the entire thing out but in the statement he just says y cant be 0 and ist bounded so M > 0

but I think M >= 0 like you said

[outer wadi]

this proof in the link for 1/y^n seems to have approached it comlpetely different than how they approached part c

[lofty spade]

it’s similar

[lofty spade]

well, he skipped a step then

[outer wadi]

yeah seems so, I'll skip this proof since I have a lot to get through and it seems to be a bit more work than I thought

thanks for the help

[lofty spade]

no problem

[lofty spade]

you could ask your professor to justify this step

[lofty spade]

hint: y is not 0, which helps

[odd edge]

@outer wadi Has your question been resolved?

Channel closed

Closed by @outer wadi

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone elbow]

Calculate for every $n \in \mbb{N}$, the remainder of dividing by 18 $$5 \cdot 35^n + 73^{3021} + \sum_{k=1}^n 3^k \cdot k!$$

[cerulean vortex]

every term of the sum, except the first, is divisible by 18

[clever fjord]

Renato

[lone elbow]

I made a typo in the latex

now its fixed

[cerulean vortex]

all right

[lone elbow]

how did that happen?

[cerulean vortex]

9 | 3^k and 2 | k! when k > 1

[lone elbow]

2 is not divisible by 1?

[cerulean vortex]

it is

2 | k! means "2 divides k!" or "k! is divisible by 2"

[lone elbow]

my bad

[cerulean vortex]

no worries

[lone elbow]

so?

[cerulean vortex]

so 18 | 3^k * k! when k > 1

[lone elbow]

yes

so we can get rid of the other numbers in the sum? except for the first one?

[cerulean vortex]

yeah

[lone elbow]

mod 3 18

is 3

the remainder of dividing 3 by 18?

[cerulean vortex]

yes, 3 is the remainder of dividing 3 by 18

[lone elbow]

ok, got it

this is... kinda fun

we might need to use euler theorem for 73^{3021}?

[cerulean vortex]

i thought so too but it's easier than that

[lone elbow]

or like, fermat

[cerulean vortex]

hint: || 73 = 18*4 + 1 ||

easier than fermat

[lone elbow]

mod 73 18 = 1

[cerulean vortex]

yeah so $73^{3021}\equiv 1^{3021}\pmod{18}$

[clever fjord]

Axe

[lone elbow]

1^(3021)=1?

[cerulean vortex]

yeah

[lone elbow]

1 mod 18 = 1

[cerulean vortex]

yes

[lone elbow]

so far we got 3 + 1

5 × 35^n = 5 x (7x5)^n = 7^n × 5^(n+1)

[cerulean vortex]

what is 35 mod 18?

[lone elbow]

5 is prime and 35 is composite

35 = 18 + 17

[lone elbow]

I think 17

[cerulean vortex]

yeah

or -1

[lone elbow]

17 * 5 mod 18

[cerulean vortex]

there's not much more you can simplify here, but you can notice that there are only two powers of 35

[lone elbow]

interesting

so its 17 or -1?

[cerulean vortex]

-1 or 1

or you can say, 1 or 17

[lone elbow]

1?

[cerulean vortex]

sorry i didn't explain well

[lone elbow]

,, 35^n \equiv 17^n \pmod{18}

[cerulean vortex]

17^n

[clever fjord]

Renato

[cerulean vortex]

yeah

[lone elbow]

and 17^n = (-1)^n (mod 18)

[cerulean vortex]

yeah

[lone elbow]

but we don't know if n is even or odd

[cerulean vortex]

right

[lone elbow]

we need to consider both possibilities

[cerulean vortex]

yup, cases

[lone elbow]

okay, for now, lets assume n is even

5 = 5 (mod 18)

(5 * 1) + 1 + 3

= 9

that's the reminder when n is even

of the whole thing

if n is odd, we have (5 × -1) + 1 + 3

-5 + 4 = -1

,w -1 mod 18

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by renatoxbz

[lone elbow]

17 = -1 (mod 18)

(5 x 17) + 1 + 3

,calc 5*17 + 4

[clever fjord]

Result:

89

[lone elbow]

73 = 4*18 + 1
73 = 1 (mod 18)

5 = 5 (mod 18)

35 = 18x2 - 1

35 = -1 (mod 18)

35^n = (-1)^n mod 18

1 if even -1 if odd

[cerulean vortex]

it's just 9 or 17

[lone elbow]

how

[cerulean vortex]

you already solved it here

[lone elbow]

dude math really is confusing

we have for the odd case

5 = 5 mod 18
35^n = (-1)^n (mod 18)
so 5 x 35^n = 5 x (-1)^n (mod 18)

so when n is odd we have

13 = -5 (mod 18)

13 + 1 + 3 = 17

73 = 4 x 18 + 1
73 = 1 (mod 18)

73^(3021) = 1^(3021) (mod 18)

73^(3021) = 1 (mod 18)

and for the sum we only consider 3 = 3 (mod 18)

so in total we have 3 + 1 + 13 = 17

for the odd case

[lone elbow]

I appreciate it, though it is certainly confusing jajaj

like, this basic divisibility thingy is very fun but very gigabrain

you know what I mean?

[cerulean vortex]

yeah there's some rules to learn

[lone elbow]

I found it interesting though, I appreciate it

.solved

[odd edge]

Channel closed

Closed by @lone elbow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich monolith]

hi I wanted to ask if this server helped w pre-calc and calc ab

[shell haven]

Ye

[atomic hornet]

yes

[shell haven]

Just post the question

[odd edge]

@rich monolith Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud galleon]

for the squeeze theorem, i just got some help with what it is, but what are the a and l values referring to here? i know x cannot be zero, so a cannot be zero either?

[unkempt lichen]

"Referring to the statement of the squeeze theorem in the PCE reading..."
do you have a copy of that statement?

[short terrace]

Well show us how squeeze theorem was defined for you

[short terrace]

There's more below

Don't give us half the theorem lol

But either way, you have your a and l here

[cloud galleon]

it's just an example i think

[cloud galleon]

so l is what the limit equals to? what it is squeezing?

and a is what it is apparoaching?

[cloud galleon]

ahh okay got it

so in this case, a is what you can replace x with? and it cannot be zro

and if it gets to infinity or -infinity, then l starts to become zero?

both bounds must apparoach the same number?

[late dust]

limits

[cloud galleon]

why cant the first option be right?

it would seem to approach + or -1 for both bounds

[late dust]

-1/1 ≠ 1/1

[cloud galleon]

ohhhhhh

but with any infinity sign, it works cause it approaches just 0?

tysm

[odd edge]

@cloud galleon Has your question been resolved?

Channel closed

Closed by @cloud galleon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean tartan]

would this just be asking where the peak would be for this equation, or am I missing something?

[odd edge]

@lean tartan Has your question been resolved?

[lean tartan]

.close

[odd edge]

Channel closed

Closed by @lean tartan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide pollen]

hey i would like a hint on how to prove the red step more clearly as i dont think its enough. if it is then cool

[wooden python]

for h between 0 and pi/2, sin(h) is positive and so equal to its own absolute value

[wide pollen]

ik my question is if saying this enough for the red step to be ok

[wooden python]

you're looking at two functions which are equal when close to 0

[odd edge]

@wide pollen Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden python]

got a diagram?

[minor bronze]

lemme draw it out

[bitter folio]

BRO

Think man think

What did you get so far @minor bronze

[atomic hornet]

Carbonite is gonna roar at his peer for asking dumb question again sigh..

[minor bronze]

im not locked in

[bitter folio]

no but i helped him

[bitter folio]

its ok

same

[atomic hornet]

yeah, I'm just joking. You're still being helpful

[bitter folio]

THINK what type of quadrilateral has opposite 90 angles

[minor bronze]

Concyclic!

[bitter folio]

YES

Now finish

[minor bronze]

is it ptomley

[bitter folio]

The ratio cube thingy is ugly

[bitter folio]

😭

[bitter folio]

Make it nice

[minor bronze]

also i dun understand ur soln

[bitter folio]

wha

[minor bronze]

why end at AB/AF = AD/AB

[bitter folio]

wdym

[minor bronze]

did you do Q12

i got it thanks

[bitter folio]

GOOD

[minor bronze]

12 is nontrivial

[bitter folio]

There was a nontrivial question?

blyat what is q12

i do now wait ah

@minor bronze bro just coord bash it

it aint that deep

transform equal angles into similar triangles

[minor bronze]

oh

hm

how

[bitter folio]

Nevermind i just did it

Not hard

Lemme write everything down

[minor bronze]

kk

[bitter folio]

@minor bronze now that youre here

Pick a number from 1 to 4

And a letter from a, c, g, n

[minor bronze]

how to prove that BDC~AEM

[minor bronze]

C4 haha

[bitter folio]

ok

So g1

[minor bronze]

what

[bitter folio]

I ciphered to shift your answers up by 1

[minor bronze]

^

[bitter folio]

Bro what

I just wrote the whole thing

This config is common

[minor bronze]

oh yeah

[bitter folio]

bro

[minor bronze]

my diagram so badly drawn

that they dont look similar

[bitter folio]

十六减九

[minor bronze]

石榴煎酒

[bitter folio]

搞完了吗

! done

[odd edge]

If you are done with this channel, please mark your problem as solved by typing .close

[minor bronze]

not yet

15 looks easy

but i dun want to coord bash

(or trig bash_

[atomic hornet]

Looks like vector can be applied here

lemme pin this rq

[minor bronze]

ooh

[minor bronze]

vector?

[vernal yacht]

I’m not so sure, lemme try

[minor bronze]

do you need the diagram

[atomic hornet]

Would you like to sketch it yourself?

[minor bronze]

i do have a diagram with me

[atomic hornet]

Welp, then consider using mine lol

[minor bronze]

ah ok

[atomic hornet]

More like trig bash

[minor bronze]

yeah

[atomic hornet]

Do you have any idea?

[minor bronze]

i do not want bashing so

at least our teacher kills us when we bash

[atomic hornet]

What is consider bashing?

I mean the work of this question must be lengthy

[minor bronze]

is there a legit way to do this (synethetic)

[atomic hornet]

I don't find one. I would start by assigning variable t to the side length of the square myself

[minor bronze]

hm

[atomic hornet]

lemme patch it, probably 2 would be better

Setting t just makes our life more difficult

[atomic hornet]

超凶🔥

@minor bronze Let's find the fundamental way in the first place.

[minor bronze]

ok

[bitter folio]

Come on do it

Not hard

[atomic hornet]

$\tan(\frac{\pi}{4} - 2\theta) = \frac{2-t}{2}$

[clever fjord]

This is sad 😢

[bitter folio]

I came back after doomscrolling

[minor bronze]

its ahrd

[atomic hornet]

damn

[bitter folio]

Hai ya what is this

[minor bronze]

the questions at the back are hard

🙁

[bitter folio]

This question is easy

[minor bronze]

@bitter folio how u synethic this

@bitter folio ok buddy

[bitter folio]

Bro

[minor bronze]

?

[atomic hornet]

So sad that I don't have paper with me

[bitter folio]

COME ON

DO IT

[minor bronze]

石榴煎酒

how

[atomic hornet]

I want to engage as well

[bitter folio]

Extend AD to P

Such that AD = PD

Then its trivial

[bitter folio]

no need

[bitter folio]

no need complicated thingy

Come on man

[minor bronze]

WHAT DOES EXTENDING HELPP

[bitter folio]

BRO

LOOK AT THE LENGTH CONDITION

SO UGLY

[minor bronze]

ah yes

then

[bitter folio]

BF = AD + FD 😭

BF = FP

Now do it

[minor bronze]

where did F come from

[atomic hornet]

Are we talking about the same question?

[bitter folio]

My diagram a bit messed wait

F is your E

[bitter folio]

Yes

[minor bronze]

ptoog

proff

proof

[bitter folio]

What?

We want to show that ofc

[minor bronze]

show ur diag

[bitter folio]

Ok

One sec lemme draw it

[minor bronze]

@bitter folio too op

[bitter folio]

shaddup

我很菜

NOW can you do it

KO the thingy

Or i KO you in school

Hallo @minor bronze

[odd edge]

@minor bronze Has your question been resolved?

[minor bronze]

hm

oh, i get it thanks

anw the other probelms ill do in sch or sth idk

.close

[odd edge]

Channel closed

Closed by @minor bronze

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bitter folio]

.good np

[minor bronze]

wiat

[minor bronze]

sorrry chat

[bitter folio]

AIYO

THIS ONE ALSO

Algebra bash

[minor bronze]

shattap

how to do syntehtic

[bitter folio]

Then i dont help

[minor bronze]

i might

[vernal yacht]

Brutal

[minor bronze]

read the qn wrongly

[bitter folio]

No.