help-19

[odd edge]

Channel closed

Closed by @leaden light

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spiral crane]

4a

[spiral crane]

I got this answer but in the book the answer is 4x -5y = -17

I can't tell where I'm making the mistake

<@&286206848099549185>

[wraith ginkgo]

why did you assume the line perpendicular passing through P was at the midpoint between them

@spiral crane

[spiral crane]

Oh, there was a similar worked example that used midpoint to determine the line

Originally, my answer was y= -5/4 +15

But I cut that off

[wraith ginkgo]

well, that doesnt really work here, you gotta imagine the two lines

hold on

[spiral crane]

Sorry for the trouble-

[spiral crane]

But yeah that didn't work out-

[light raven]

The perpendicular actually went through the point P
Not the midpoint of PQ
@spiral crane

Fix that and ig u r good to go!

[wraith ginkgo]

you got the slope right

just use P as the point that lies on the line m because thats what the problem stated

[light raven]

@spiral crane

[spiral crane]

Hold on let me try and I'll let you know? It won't take long, and again I'm sorry for the trouble

[spiral crane]

Wait isn't that what I did initially or am I missing on something?

[wraith ginkgo]

no you used the midpoint

which is not on the line

[spiral crane]

Just a min

[wraith ginkgo]

its fine haha

[spiral crane]

Referring to this one

Didn't use midpoint

Just gradient and point p

[wraith ginkgo]

the picture is not very clear, but if you used the gradiant and the point P, you should get the correct answer

send me a better picture of what you did if it still doesnt work

[odd edge]

@spiral crane Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

How do I convert 3.25 radians to degrees

[mystic saffron]

I know that the formula is 180/pi

But this one doesn’t have pi

Like

If it was 3.25pi I would multiply it by pi/180

To convert successfully

[viral frost]

180/pi you mean

You're right but I guess you are allowed to write it out till a few decimal places?

[mystic saffron]

Yes

[leaden karma]

the angle does not have to have pi

that just makes it easier to do the calculation (since the pi cancels)

[viral frost]

Yeah

[leaden karma]

but 180/pi is still just a number

you can multiply that with any number

[mystic saffron]

Is it fine if pi doesn’t cancel out

[leaden karma]

yes

the number will just be irrational

,calc 3.25 * (180/pi)

[clever fjord]

Result:

186.21128341752

[odd edge]

@mystic saffron Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wild zinc]

What ideas do you have?

[gritty flower]

To be honest I have no idea where to start

[wild zinc]

How would we get a linear factor out of a quadratic polynomial?

[gritty flower]

Not sure

[rapid kestrel]

Try factorising

[gritty flower]

(m-3)(m-3) over (m-4)(m-3)?

[rapid kestrel]

Yes

[gritty flower]

Then what?

[rapid kestrel]

You can cancel an (m-3) at the top and at the bottom

[gritty flower]

So (m-3) over (m-4)

[gritty flower]

So a is 3 and b is 4 right

.close

[odd edge]

Channel closed

Closed by @gritty flower

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

can i change integral from pi/4 to 3/4pi f(1+sinx) dx to integral from -pi/4 to pi/4 f(1+cosx) dx

[fluid tundra]

yes

that is a valid transformation which results in an equivalent numerical answer

[mystic saffron]

ty

.close

[odd edge]

Channel closed

Closed by @viscid bison

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich hound]

Anyone can help?

[spiral crane]

.close to free

[rich hound]

But I need help why would I close

.close

[odd edge]

Channel closed

Closed by @rich hound

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[odd edge]

@shadow meteor Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal barn]

So

[tidal barn]

Let say I havea basis B and basis C of the same vector space. f: V->V

Then I have a matrix rrepresantating mapping [f]B_K , means it takes transforms vectors from base B to K(canonical base).

If I do [f]B_K . [ID]C_B , will that equal to [f]C_K?

<@&286206848099549185>

@brittle beacon is there any help for remembiring from which side and what identity to multiply matrix with if i want my final matrix to chosen basis?

[brittle beacon]

how do you mean? as in like in your example, if you wanted that to be in another basis instead of K?

[tidal barn]

so here i changed the upper inder "the input one"

what if i wanted to change the output one

for example from [f]B_C

[brittle beacon]

If you wanna change the output one, multiply from the left by the appropriate transition matrix

So say if we were given $[f]_{K \to K}$ as the matrix of $f$ under the basis $K$ for $V$ (both in input and output)

[clever fjord]

@brittle beacon

[tidal barn]

yeh so output is multiplying from left, input from right

I guess it has some algebraic proof, why it works but i guess u dont know it off-head

do you?

Also, this works if its f: V->V right? what if its different spaces

[brittle beacon]

It's mostly just writing stuff out component wise I think (which I'm pretty lazy to do), e.g. knowing that something like $x$ in the basis ${e_1, ..., e_n}$ (where $V$ is $n$-dimensional) can be written like $x = x_1 e_1 + \ldots + x_n e_n$ then working with that

[clever fjord]

@brittle beacon

[brittle beacon]

And it's kind of similar but taking into account that the spaces may be different dimensions

[tidal barn]

i will send an example

I know its in diff language

but mainly u understand, the thing they ask is to count f((3,2,1)T)

@brittle beacon can u tell me how u would transform it

[brittle beacon]

is that (3, 2, 1) in standard basis or?

[tidal barn]

yes

[brittle beacon]

In that case, convert that to the B basis, multiplying it by the conversion matrix $\pmqty{2 & 1 & 1 \ 1 & 1 & 1 \ 2 & 0 & 1 }^{-1}$

[clever fjord]

@brittle beacon

[tidal barn]

is this correct?

[brittle beacon]

Then what you get from that, left multiply by [f]_C^B, then if you want the result in standard basis, after that, multiply by the transition matrix from C basis to standard

[brittle beacon]

Yep

[tidal barn]

is it equivalent to what u said

[brittle beacon]

Yep, pretty much what I said!

[tidal barn]

yeah and we obviously start multiplying from left, right?

left->right

[brittle beacon]

how do you mean? As in evaluating that product?

(if so, then note that matrix multiplication is associative so you can evaluate the product however you wish)

[tidal barn]

hold on

@brittle beaconthats not defined

nvm it is

i just cant even insert the wrong matrix into matrixcalc.org

:)

[brittle beacon]

[tidal barn]

@brittle beacon Also

[f]K2_K3 doesnt exist right

cuz inverse of non square matrix doesnt exist

[brittle beacon]

It does, note that f doesn't need to be invertible itself, and is basically what you're finding

In fact, because the dimensions of the spaces differ, f is not invertible as is

[tidal barn]

so how would u get

[f]K2_K3

if you know [f]K3_K2

[brittle beacon]

Wait

[brittle beacon]

As in K2 being the "start" and K3 being the "final" space, you mean?

[tidal barn]

yes

[brittle beacon]

(sorry getting mixed up with the $[f]_C^B$ notation lol)

[tidal barn]

u say its possible?

[clever fjord]

@brittle beacon

[brittle beacon]

Well, having [f] from K3 to K2 is possible, and what we have (that's what I meant in my original post)

[tidal barn]

cuz there could be many of those

[tidal barn]

yea i know

but ([f]K3_K2)^-1 = [f]K2_K3

[brittle beacon]

But [f] from K2 to K3 isn't - most notably too, because that would imply that you have a 2 element basis of a three dimensional space, and a three-element basis of a two dimensional space

[tidal barn]

yea, so that doesnt exist

[brittle beacon]

Well more that it should be [f^{-1}] K2_K3, but then again f isn't invertible either

[tidal barn]

but we can get some mapping f K2_K3 given right?

for example f((x,y)) =
(x + 2y)
(x + y)
(2x)

[brittle beacon]

Yea it's possible to have a linear map like that given to you, for which you can find a matrix for (though similarly it isn't properly invertible)

[tidal barn]

ye ye

@brittle beacon last thing please

[brittle beacon]

[tidal barn]

f: Z2_5 -> Z2_5 from B to K is
(1 1)
(2 3)

We want [f^{-1}] C_K , which equals [f] C_K.

So to do this we would do [f]B_K [id]C_B = [f] C_K ?

@brittle beacon

[brittle beacon]

We want [f^{-1}] C_K , which equals [f] C_K.
does it?

But you can find [f^{-1}] from K to B by finding the inverse of that matrix in the appropriate space

Then of course, finding [id] from C to K, then [f^{-1}] from K to B, then [id] from B to C

[tidal barn]

[f^{-1}] C_K = ([f]K_C)^{-1}

and that equals to fK_C

right?

@brittle beacon[f]B_K [id]C_B = [f] C_K so this is correct?

[brittle beacon]

I mean without me computing it, not necessarily, unless the matrix is its own inverse

[brittle beacon]

This is correct yep

[tidal barn]

ok perfect, I understand it

thank you so much @brittle beacon

[brittle beacon]

No problem, a pleasure

[tidal barn]

Do you have open dms for more algebra questions?

@brittle beacon

[brittle beacon]

You can DM sure if you'd like, though I may be busy at times so reply slowly

Will try to reply when I can of course!

[tidal barn]

Yea, obviously :) thanks and have a nice day

.close

[odd edge]

Channel closed

Closed by @tidal barn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant umbra]

Let P = (1,-3,4) and Q = (5,1,-2)

[distant umbra]

find the coordinates of the point which lies one third of the distance between P and Q

earlier in the book

[long tinsel]

section formula

[distant umbra]

serge lang says we can use the formula

s(t) = P + t(Q-P)

[wind valve]

sorry, didn't see the points

[distant umbra]

but i dont necessarily understand from where does Q-P come?

how does Q-P have same direction as PQ?

and then finally in the answer, they substitute 1/3 as t and solves for it. but i dont understand why.

so can someone please help with these 2 questions

[tender carbon]

i think one of the way to solve tia problem is: find coordinates of PQ vector. find the vector 1/3PQ. transform P parallel to the vector 1/3PQ and you will end up the point which is located from 1/3 from P to the direction of Q

[odd edge]

@distant umbra Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

Sorry this might be a bad question, but basically whenever I want to show a set is uncountable, all i need to show is that there is no surjection right?

[tall veldt]

surjection from where to where?

[mystic saffron]

like if you have X and P(X) as sets, show a surjection from f:X -> P(X) doesnt exist

[late dust]

Whatever X is, there is no surjection from X to P(X)

If you want to show that X is uncountable, then you must show there is no surjection from N to X

P(X) doesn't matter

[mystic saffron]

isnt this cantors diagonalization, to show that no surjection implies uncountability

[late dust]

Not sure what you mean

Cantor's diagonal argument is just a proof that there exist uncountable sets

And that R is such a set

[odd edge]

@mystic saffron Has your question been resolved?

[mystic saffron]

when do you use it

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[karmic hollow]

Csn someone help

[karmic hollow]

With 7sinx+3cosx=0

?

Idk if u csn do this

But 7sinx+3-1sinx=0

Im being idiotic

[boreal crag]

What are you trying to do?

[karmic hollow]

Sorry

Well

[loud hornet]

Can someone help me please

[karmic hollow]

I am trying to solve for x

Eu

U need to use another chsnnel

Ok

👍

[boreal crag]

^

!occupied

[odd edge]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[karmic hollow]

Iam trying to solve 7sin x + 3cos x =0

For x

Idk what to do

Like do i put it into thr trig identity when tan =sin/cos

[boreal crag]

Hmm

[karmic hollow]

Im not sure

I judt started learning alevel trigonometry

[boreal crag]

It's hard to think of how to explain in a way that makes sense

[karmic hollow]

Oh no

[boreal crag]

But there's something clever you can do just by moving things around

[karmic hollow]

Fr fr

[boreal crag]

Yeah

[karmic hollow]

Hmm

[fluid tundra]

yeah you basically want to do this

do you know what arctan() is?

[karmic hollow]

Like what arc tan means

Or the value

Of theta

Cos i dont have the value

Ik arc tan is reverse tan

If u mesn that

[boreal crag]

Can you turn the equation with two trig functions just into an equation with just tangent

[karmic hollow]

?

How

[boreal crag]

move one of the functions over to the other side by subtracting it

[karmic hollow]

Right

So

E.g.

7sin x =-3cosx

Does that work

[boreal crag]

Yeah

then you move it back over by dividing

[karmic hollow]

Ah ok

Wait

Could i theoretically do

7sinx +3cos x

Then divide 7sin x

To get 3cos x =-7sin x

Theb divide by 3 cos x

To get tan x =7/3

Or do i not understand this properly

Thats incorrect

Idk then

[tepid acorn]

That’s correct

But you forgot negative

[karmic hollow]

Oh

Wtf

So

Wait

Can someone write out the steps to how i did it

Cos im co.fusing my self

Like i get tan =-3/7

[tepid acorn]

Ur doing it right with the manipulations just make sure you manipulate correctly

[karmic hollow]

Ok

Im still confused tho

So with trig functions

U divide to get them to thr other side

Then they become negative?

Is that correct

[odd edge]

@karmic hollow Has your question been resolved?

Channel closed

Closed by @karmic hollow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[novel hollow]

Can someone double check my work pls

[novel hollow]

This rewritten as 1 logarithm would be

?

t= sqrtC (A/A-N)

[sharp oak]

Your log is gone

[novel hollow]

104

Idk how to type it

[sharp oak]

Be careful, you mean A / (A - N)

I'd consider using two lines per question, for clarity here

[novel hollow]

O ok

[sharp oak]

But yeah that looks right

[novel hollow]

But other than parenthesis was it good

Ty!

[odd edge]

@novel hollow Has your question been resolved?

Channel closed

Closed by @novel hollow

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lavish jackal]

henlo

[lavish jackal]

does the part a) asking for midline and part b) for amplitude?

[spiral basalt]

they're two examples
For each, find the three things asked in the actual question

[lavish jackal]

what three things?

[lavish jackal]

oh okay

my bad didn't see that lmfao

thanks

.close

[odd edge]

Channel closed

Closed by @lavish jackal

Use .reopen if this was a mistake.

[spiral basalt]

don't worry, no matter how old we get, we still fail at reading comprehension every now and then

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sour pewter]

how do this

[faint verge]

$^3\sqrt$

[clever fjord]

George
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[faint verge]

cube root is equivalent to taking everything to the power of 1/3

so:

[sour pewter]

but how does it turn into x^3 sqrt x

[faint verge]

i think thats x cuberoot x

since x^4 becomes x^(4/3)

= x^1 time x^(1/3)

i.e. x times cuberoot x

[sour pewter]

sorry im not following

[faint verge]

this

is $x \times \sqrt[3]x$

[clever fjord]

George

[faint verge]

not $x^3 \times \sqrt{x}$

[clever fjord]

George

[faint verge]

so when we take cuberoot of x^4, we divide the exponent by 3 = x^(4/3) = x^(3/3) times x^(1/3)

= x times cuberoot x which is what is written

is that ok?

[odd edge]

@sour pewter Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

anyone got a clue on how i would go about disproving this

[fringe bough]

Intuitively you could choose some subset of B\A and show that that subset is infinite

[mystic saffron]

ohh

that's smart

i forgot u could do that

btw

i dont understand why i need to show a bijection for this

are ther not only 2 roots of z^2 ?

would A not just have 2 elements...

[fringe bough]

A contains both square roots of each negative integer

z^2 = -n, but n can be any natural number

[mystic saffron]

oh i thought when it said for some n it means a fixed n

[fringe bough]

No, but they could have made it more clear by just using a comma rather than "for some"

[mystic saffron]

yea cz normally when u say for some u normally mean a fixed n in the natural numbers dont u?

[fringe bough]

Well, it's that each z is a square root of a particular -n

for example i is a root of z^2 = -1
and 2i is a root of z^2 = -4

So those number, i and 2i, are each a root of z^2 = -n for some n

[mystic saffron]

icic

i thought it meant all the z such that the z is a solution to z^2 = -n for some particular n

[fringe bough]

I'd maybe interpret it that way if "for some n in N" was outside the set brackets

like, "This set A exists for some n in N"

but instead it's in the formulation of z

so it's like, "z has to satisfy this condition for some n in N"

[mystic saffron]

ok i found the bijection

[mystic saffron]

why cant they just say for n exists in N then 😭

the some completely threw me off 😭

[fringe bough]

yeah, I agree it would be a bit more clear with just a comma

[mystic saffron]

legit that's a 7 mark qu too

😠

[odd edge]

@mystic saffron Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange drum]

am i doing this right?

[noble palm]

4 isnt a prime

but if the set was {2,3,5} you'd be right (im assuming P means prime)

[strange drum]

P is positive integer i thought

[noble palm]

oh ok

i mean theres diferent definitions

[strange drum]

the fancy P

idk how to write it

[noble palm]

which one j curious

[strange drum]

none

[noble palm]

damnn

if P does mean positive integers, you're fine though

but you dont necessarily need to specify it's positive because you already implied that by saying x>1

just need that it's an integer after that point

[noble palm]

oh

[strange drum]

but isnt set builder notation structured like that?

universe | rule

[noble palm]

theres multiple ways to go about it

sometimes you can have the universe be a larger set

and the restriction will make the set stay the same

like {x in Z | x>1 and x<6} also works

[strange drum]

in?

[noble palm]

$\epsilon$

[clever fjord]

znsn

[noble palm]

same as element of

[strange drum]

i did that tho

[noble palm]

your thing certainly works

i just want to say that we could also set the universe as the integers as well

[strange drum]

Z wouldnt work

[noble palm]

why?

[strange drum]

it includes negatives

[noble palm]

yeah but your condition of x>1 excludes negatives

[strange drum]

so it works?

[noble palm]

yeah, theres often not just one way to build sets

[strange drum]

oh

im new so idk

[noble palm]

just a nice fact to know

[strange drum]

lemme try b

[noble palm]

alr

[strange drum]

how would i describe x10 until 10000

oh

[strange drum]

b) { x element of P | 10^x and x<5 or x>0}

right?

[noble palm]

almost but not quite

cuz 10^x doesnt really mean anything here

in ur condition

[strange drum]

oh

[noble palm]

im not sure if your teacher taught u this yet but you can also specify that x is an element of Set on the right side of the |

for example {2x|x in P}

would mean all the even positive integers

[strange drum]

so like

[noble palm]

so you could put 10^x at the left of the | instead of the right

[strange drum]

b) { 10^x | x element of P }
how do i set bounds

or like add rules

[noble palm]

i have to go now so (b) ||{10^x|x in P and 1<=x<=4}
and (c) {x in P | x only has two divisors}||

[odd edge]

@strange drum Has your question been resolved?

Channel closed

Closed by @strange drum

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

How the hell do I solve this number 7. And the answer is 176ft, how do I get there at all

[odd edge]

@mystic saffron Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[south dirge]

soo

[south dirge]

im in calc 3 and all the problems on this homework have been extremly easy up to this one

a bird flies from its nest 3km in the direction of 60 degrees north of east where it stops to rest on a tree it then flies 18km in the direction due southeast and lands atop a telephone pole place an xy coordinate system so that the origin is the birds nest the x axis points east and the y axis points north

a) at what point is the tree located . B) at what point is the telephone pole located

i got 0 idea how to do this 🥲

[leaden widget]

just use trig, you are given the angles and hypotenuse lengths of triangles basically

[south dirge]

my brain is off can ya gimme formula 🥲

[leaden widget]

you are in calc 3, you should be very familiar with soh cah toa, that's all it is

just draw yourself a picture

[south dirge]

this picture looks wrong

.close

[odd edge]

Channel closed

Closed by @south dirge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[potent vessel]

idk how to implement the 17^2 into the identity

[dim thicket]

yon want (a+b)^2 = 17^2

[silent grail]

its equal to 17^2

[potent vessel]

yeah i did that and got b = {-27, 7}

when i plugged a as 10

[silent grail]

$100+2ab+b^2=17^2$

[clever fjord]

Vѳrtєx-

[silent grail]

right?

$100+2(10)b+b^2=17^2$ even better

[clever fjord]

Vѳrtєx-

[potent vessel]

yeah

[silent grail]

$100+20b+b^2=17^2$

[clever fjord]

Vѳrtєx-

[potent vessel]

yep

[night heron]

I'm not sure you need to do something as long as this

[potent vessel]

so then i evaluate the 17^2 and subtract 100

and then divide by 20?

[silent grail]

oh yeah you said 7 and -27

[dim thicket]

this is good

[silent grail]

but you're finding the numerical value of 2ab

[potent vessel]

yeah i did from the other side but thats what i got

[silent grail]

you can also just notice $(a+b)^2=17^2$ so $a+b=17$ or $a+b=-17$

[dim thicket]

thats the better way

[clever fjord]

Vѳrtєx-

[potent vessel]

ohhhh

but how do we find the one numerical value

is there multiple

[silent grail]

do 2 times a times b

[dim thicket]

technically it could be both

[silent grail]

i think there should be two values

[potent vessel]

i looked at the answer key and it said 140 before coming here

and i was so confused

[dim thicket]

but if you want to use that identity to calculate 17^2 using -27 doesnt make sense

[silent grail]

that's $2\cdot7\cdot10$

[clever fjord]

Vѳrtєx-

[silent grail]

2ab

[potent vessel]

ohh so we would reject the -27

[dim thicket]

mathematically there is no reason to, but given the context, using -27 doesnt make sense

you want to simplify the calculation

but with b=-27 youd have to calculate 27^2 to calculate 17^2

making the problem harder

[potent vessel]

ok ok

[silent grail]

the problem is basically saying "instead of calculating 17^2 you can calculate 10^2+2(10)(7)+7^2"

which would lowkey take longer but whatever, it could be useful in some other contexts

[potent vessel]

ok thank you guys

[dim thicket]

surely its quicker than calculating 27^2 thp

[odd edge]

@potent vessel Has your question been resolved?

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic saffron]

help please

[restive delta]

!status

[odd edge]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[quasi sparrow]

use polynomial division

[mystic saffron]

so i pretty much long divison right

so 6x^3-5x^2-17x+6

x-2?

or do i have to substitute x = 2 into the equation to make it 0

?

[restive delta]

You can do that to first show that x-2 is a factor

And then use long division to find the other 2 factors

[mystic saffron]

so i get 6x^3-5x^2-17x+6 divided by x-2 yea

after that

[restive delta]

Wdym

[mystic saffron]

for long division

6x^3-5x^2-17x+6 divided by x-2

to find other factors

[restive delta]

Yes

Divide it to get a quadratic

And then you'd have to factorise the quadratic to find other two factors

[mystic saffron]

yk for a how would i work it out

do i just write substiituite x = 2 into f(x)?

or substitute g(x) = 2 into f(x)

i think last one yea

[restive delta]

You would just get 0 if you did that

[mystic saffron]

thats showing its a factor tho right

[restive delta]

Yes

But to find remaining two factors

Use long division

[mystic saffron]

so i write substitute g(x) = 2 into f(x) to find factor yea

[restive delta]

You mean to write it as
6(g(x))³-5(g(x))²-17(g(x))+6 = 0?

By substituting x=g(x)?

[mystic saffron]

for working out i just wrote substitute g(x)=2 into f(x) to find

yea

g(x) into f(x)

[restive delta]

What did you get after that

[mystic saffron]

i got 0

[restive delta]

Yes

By substituting x=2 you'll only prove the first part

Which is that x-2 is a factor

But now divide the given polynomial by (x-2)

Using long division

[mystic saffron]

i got 6x^2+7x-3

that right or nah

.close

[odd edge]

Channel closed

Closed by @pastel flicker

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lone mural]

determine convergence or divergence with direct test

idk what to conpare it to

[dreamy yacht]

1/(n(n-1))

For big enough n

[lone mural]

$\frac{1}{n!} < \frac{1}{n(n-1)}$

[clever fjord]

dabbingpotato

[lone mural]

$\frac{1}{n!} > \frac{1}{n(n-1)}$

[clever fjord]

dabbingpotato

[lone mural]

why wouldn't itbe this

oh wait

okay thx

and we know that 1/n(n-1) is convergent because limit test to 1/n^2

[dreamy yacht]

You're welcome

[lone mural]

.close

[odd edge]

Channel closed

Closed by @lone mural

Use .reopen if this was a mistake.

[dreamy yacht]

Moreover it is a telescope sum

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obsidian plover]

claim

[pulsar hedge]

LOL

[quasi sparrow]

don't occupy a help channel for this

if you have a math question, ask it

[pulsar hedge]

https://homeworkify.st/mirror-1

lets you bypass chegg

anyone prolly close chat

[restive delta]

.close

[odd edge]

Channel closed

Closed by @restive delta

Use .reopen if this was a mistake.

[restive delta]

Wait what

.reopen

[odd edge]

✅

[restive delta]

How was I able to close

[pulsar hedge]

yo lorentz

could you work your domain magic

and help me in 7

🥺

[wooden python]

!noadvert

[odd edge]

Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, so advertising can quickly turn into spam.

[pulsar hedge]

aight sorry Ann

mb

[fringe bough]

@obsidian plover please either post a specific math question here or close the channel

[obsidian plover]

.close

[odd edge]

Channel closed

Closed by @obsidian plover

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hardy barn]

Need help with this one

[hardy barn]

I guess I could rewrite 81 as 9•9, 72 as 9•8, 24 as 8•3 and 36 as 9•4?

[odd edge]

@hardy barn Has your question been resolved?

[hardy barn]

No

[odd edge]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[signal perch]

so I'm looking at some class notes and I dont understand why she added pi to theta

[forest sky]

$\tan(\theta)$ is periodic with a period of $\pi$, so $\tan(\theta+\pi) = \tan(\theta) = \tan(\theta + 2\pi) = \tan(\theta + k\pi)$ for any integer $k$

[clever fjord]

cloud

[signal perch]

i see

thanks

.close

[odd edge]

Channel closed

Closed by @signal perch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silver thicket]

how is this not transitive?

[silver thicket]

i checked ab, bc, and cd but i think i am doing it wrong

[wooden python]

(b,d) ∈ R, (d,c) ∈ R, but (b,c) ∉ R.

thats one counterexample i saw immediately

[silver thicket]

oh, im supposed to check basically every group of 3 ?

i thought they had to be consecutive like abc

[wooden python]

no

their names don't matter

[silver thicket]

is the easiest way to do this, then, to just look for the Y's and check?

[wooden python]

for transitivity, the property (x,y) ∈ R & (y,z) ∈ R => (x,z) ∈ R has to hold for every possible trio of x, y and z

and for explicitly given relations like this idt there is any easier way than brute force

[silver thicket]

ah okay

ty!

.close

[odd edge]

Channel closed

Closed by @silver thicket

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old agate]

When we are using Lagrange multipliers to calculate the maxima and minima can this constant “lambda” be 0 in grad f = lambda grad g

[quasi sparrow]

If lambda is zero then you're ignoring the constraint

So no

[old agate]

Ok

Ty

.close

[odd edge]

Channel closed

Closed by @old agate

Use .reopen if this was a mistake.

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert marlin]

I'm supposed to prove if a is a unit and b is a zero divisor then ab is a zero divisor (in Zn)

[desert marlin]

but I'm confused because I think I've proven it without using the fact that a is a unit at all

so I;m wondering if I have glossed over something and I was hoping someone would let me know

since b is a zero divisor, then there is a d such that b!=0 and d!=0 but bd=[0]

then a(bd)=a(0)=0=(ab)d

and thus, since d!=0 ab is a zero divisor

[low locust]

well, ab could be zero already

[desert marlin]

oh right I have to show ab!=0

okay I know that b!=0 already

a is a unit so there is some x where ax=[1]

if a is 0 then 0x=0 != [1]?

is that all

[low locust]

well then a isnt zero

but why is ab not zero

[desert marlin]

if ab=0 then a=0 or b=0

but b isn't 0

[low locust]

no

[desert marlin]

and a isn't 0

no?

[low locust]

mod n doesnt have the zero divisor property

b is literally a zero divisor. bd=0 even tho b and d arent zero

[desert marlin]

yeah

[low locust]

the problem is that a could be another such number d

[desert marlin]

why's that a problem

[low locust]

well then ab would be zero

even tho a and b arent

[desert marlin]

oh if a congruent d mod n

[low locust]

no, not only then

[desert marlin]

when

[low locust]

zero divisors dont come in pairs

for example if n=12 and b=6, then d could be 2 or 4 or 6 or 8 or 10

[desert marlin]

I see

Okay so here's what I know

there is some x such that ax=1 there is some d such that bd=0 (b not 0, d not 0)

I want to show there is a y, such that (ab)y=0

let's times axbd=0*1

ab(xd)=0

[low locust]

and you want to show that ab isnt zero already

[desert marlin]

but I need to show that ab not 0 and xd not 0

d is not 0, if x was 0 then ax couldn't be 1

so xd not 0

now I need to show ab isn't 0

a isn't 0

b isn't 0

but maybe still ab is..

[low locust]

intuitively speaking, if a is a unit, then we can divide by it

so from ab=0 we would get b=0

[desert marlin]

?

what

we can divide

[low locust]

just like in the real numbers

multiplying by a^-1 is the same as "dividing" by a

thats what division is

[desert marlin]

a^(-1) = x ?

ab=0

abx=0x

[low locust]

just like subtraction is adding with (-a)

[desert marlin]

(ax)b=0

1b=0

b=0

contradiction

so ab not 0

[low locust]

yes

[desert marlin]

one more thing though

just because

x not 0 and d not 0

how do we know that xd not 0

it could be the same thing

with ab

[low locust]

x is a unit again

but you dont actually need xd

your first attempt was fine

(ab)d=0

[desert marlin]

what

[low locust]

you just needed to argue that ab isnt zero

thats all you left out

[desert marlin]

but is xd fine

I like it better this way

[low locust]

it still works, yes. imo its not as nice but thats subjective

[desert marlin]

kinda thought u were laughing here

tbh

XD

xd

[low locust]

and like you said, you would again have to show that xd isnt zero

[desert marlin]

if xd=0

axd=a0

1d=0

d=0

contradiction

Okay ty again Denascite

🐺 🌲

.close

[odd edge]

Channel closed

Closed by @desert marlin

Use .reopen if this was a mistake.

[low locust]

.reopen

[odd edge]

✅

[desert marlin]

.reunlcose

[low locust]

exercise: try showing that if a isnt a zero divisor in Z_n, then it is a unit

hint, consider the function f(x)=ax

(this works in every finite ring, not just Z_n)

lcose

[desert marlin]

if a is not a zero divisor in Zn

then there is no b not 0 such that ab=0

then

n does not divide ab

for all b

then a=1

[low locust]

try working just with ring properties

[desert marlin]

okay that's not really an attempt

[desert marlin]

can I slip out of this one if I

,ti austinu

[clever fjord]

The current time for austinu is 02:36 AM (PST) on Thu, 18/01/2024.

[low locust]

oh wow austin wants to go to bed

[desert marlin]

XD

[low locust]

thats a new one

[desert marlin]

f(x)=ax

is never 0

so

[low locust]

well its zero for x=0

[desert marlin]

oh

right

[low locust]

what properties of functions could you check

[desert marlin]

derivatives and whatnot

vertical line test

[low locust]

well ok derivatives make no sense over general rings

how is that more formally known?

[desert marlin]

well

for any x in the domain

geez idk how to say it

only 1 output

per input

[low locust]

I mean the technical term for a function that passes the vertical line test

[desert marlin]

in the domain

a function

[low locust]

surely you know that term

[desert marlin]

I would just call this a function

perhaps it is

[low locust]

ah fuck

[desert marlin]

wait

[low locust]

sry I was thinking horizontal line test

[desert marlin]

give me 1 second

oh horizontal line test

that's not injective

if f(x1)=f(x2) then x1=x2

so if it passes then it is injective

i think

[low locust]

ok

[desert marlin]

I've never done the horizontal line test

[low locust]

is our function injective?

you have never checked whether a function is injective or surjective?

[desert marlin]

I have but not by graphing

Just by algebra and my marvelous mind

[low locust]

yeah I dont mean to graph here

[desert marlin]

okay so

if

ax=ay

then

[low locust]

graphing over Z_n would be weird anyway

[desert marlin]

x=y

if

a^-1 exists

and

if a is a unit

[low locust]

well you dont know that yet

[desert marlin]

it does

[low locust]

you know that a is not a zero divisor

[desert marlin]

okay well if a is a unit then we're injective

[low locust]

you want to show that a is a unit

[desert marlin]

so perhaps I need to show that our function is injective

some other way

[low locust]

yes

[desert marlin]

can I be cheeky and say it's linear so it has to be?

[low locust]

no

[desert marlin]

hm

[low locust]

that doesnt work for example with 2x in Z_12

[desert marlin]

oh I didn't know is our function over the integers?

how peculiar

[low locust]

from Z_n to Z_n

or generally, from our ring to itself

[desert marlin]

suppose f(x)=ax is not injective

then there exists y, z such that f(y)=f(z) but y!=z

then ay=az

but y!=z

[low locust]

yes

[desert marlin]

then

uh

[low locust]

how could you rearrange that

[desert marlin]

ay-az=0

a(y-z)=0

a is a zero divisor

NO GOOD

I win

thus our function is injective

[low locust]

yes

[desert marlin]

and thus a is a unit

from earlier

that was kinda fun

[low locust]

well no

not that fast

[desert marlin]

damint

[low locust]

we showed that if a is a unit, then the function is injective

[desert marlin]

no longer having fun

[low locust]

you cant just use the other direction

[desert marlin]

if the function is injective I must prove a is a unit

okay

[low locust]

what do you know about injective and surjective

over a finite set

[desert marlin]

That's pretty vague

[low locust]

yes

[desert marlin]

f(x1)=f(x2) => x1=x2

well

if it is a set

you can't have two elements that are the same

so f(x1) never equal f(x2) if it is injective

[low locust]

so if f:A->A and A has n elements, how many elements does the image need to have

[desert marlin]

ah

I did this before I think

n

[low locust]

I hope you did

thats what I based the exercise on

[desert marlin]

haha

so what's your point about the image

it has the same amount of elements as our domain

being n

[low locust]

yes

and the image is also a subset of A. which again has n elements

so therefore the image ... ?

[desert marlin]

is A?

[low locust]

yes

so our function is also surjective

[desert marlin]

bijective

[low locust]

yes. in general, for a function f:A->A with A finite, its equivalent that: f is injective, f is surjective, f is bijective

[desert marlin]

so since 1 is in Zn ther e has tobe an element that makes ap=1

[low locust]

another exercise, show that this isnt true for infinite A

yes

exactly

[desert marlin]

lol

my definition of bijective

was

if it is surjective

and injective

[low locust]

yes

[desert marlin]

so idk what ur other exercise is about

[low locust]

that is the definition

[desert marlin]

oh I see

[low locust]

mostly that injective and surjective arent equivalent

[desert marlin]

I thought you were asking me to prove that

[low locust]

if A is infinite

[desert marlin]

if f:A->A is injective and surjective but A is infinite then f isn't bijective

and I was like huh

[low locust]

good anyway

now you can go to bed 😛

[desert marlin]

The world needs more Denascites

I wish u were my algebra teacher

thanks

[low locust]

maybe I am

[desert marlin]

No

you'd introduce rings faster than week3

otherwise

I might take back everything nice I ever said about you

for boring me so much

[low locust]

well I would do quite a bit of other stuff before probably

with groups

[desert marlin]

alright then I can conclude that u r definitely not my teacher

[low locust]

or maybe I lied

[desert marlin]

we didn't even do euclidean algorithm

[low locust]

not yet I assume. but you definitely need it to find inverses in Z_n

[desert marlin]

why not yet

we did division algorithm

it should've been next :(

[low locust]

🤷‍♂️

[desert marlin]

But I was feeling pretty smart when we were doin euclids lemma and I was like yeah shes gonna do bezouts next

and then she did bezouts

and I was like yeah prime factorization is next

and then it was

but anyways I should go to bed

[low locust]

you should

[desert marlin]

Have you ever watched Goodwill Hunting?

[low locust]

ages ago, yes

[desert marlin]

I just watched it for the first time while doing this HW

not while u were helping me of course

🐺

it's really good

maybe watch it again idk

okay bye

.close

[odd edge]

Channel closed

Closed by @desert marlin

Use .reopen if this was a mistake.

[low locust]

bye

[tall veldt]

Bezouts identity?

[desert marlin]

d=ax+by or something

gcd

d

a,b

if

ueah

linear combination

[tall veldt]

Why would she do that and not euclid algorithm

[low locust]

.reopen

[odd edge]

✅

[low locust]

yeah thats weird

[desert marlin]

if d=gcd(a,b) then d=ax+by for some x,y integers

[low locust]

ea is how you calculate the solution to bezout

[desert marlin]

maybe I'm stupid

[low locust]

how else did you even prove it

[desert marlin]

Let me look

uh so we did it by constructing a set

S={am+bn}

and using division algorithm and WOP

[tall veldt]

But you have no method of finding the a and b?

[desert marlin]

I mean Ic an find anything

personally

[tall veldt]

Whack

[desert marlin]

except for any zeroes of the riemann zeta functin not having real part 1/2

can't find those

one ay

day

.reclose

.reunopen

.rereclosethechannel

@odd edge Please close this channel

useless...

[tall veldt]

.solved

[odd edge]

Channel closed

Closed by @tall veldt

Use .reopen if this was a mistake.

[desert marlin]

ohhh that's how

[tall veldt]

It's okay you're new

[exotic pelican]

Hello guys
I'm trying to find a function that looks like this
I just forgot everything I knew about functions...

Doesn't have to be exact, something alike then I'll just play with the parameters. Thanks ahead🙂

[potent nexus]

Arctan

[exotic pelican]

Thanks!

[odd edge]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shrewd anchor]

Hey, how can simplify this?

[wooden python]

do you know Chinese remainder thm

,w factorize 4147

[clever fjord]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ann_dec

[shrewd anchor]

never heard about this. need to look that up

[wooden python]

bruh

💀

hmm

bashing will be difficult

[odd edge]

@shrewd anchor Has your question been resolved?

Channel closed

Closed by @shrewd anchor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fickle laurel]

This four-digit number is equal to the product of the sum of its digits multiplied by the square of the sum of the squares of its digits.
What is this mysterious number?

I've tried running all combinations in Python and found two solutions (2023 and 2400). However, my maths teacher gave it to me this morning and said there was a way to solve it analytically