i mean
#help-19
sharp oak
Yes. You'd need to rearrange to get the angle
toxic monolith
i cant see any problem here
toxic monolith
take exercise book and find cosA, with your datas
vale sand
okay let me try
yeah still not even comeing up close
Okay heres the basic problem
i appartenly have no idea how to calculate angles when the triangle is not a right triangle
sharp oak
This comment down is how
- See the Cosine law
- Rearrange it algebraically for cos(theta)
- Plug in your known values
vale sand
oh yeah good question i wanted to ask
why cosine only for that law
i mean why is cosine only work besides the name
vale sand
What does sin law solve for?
toxic monolith
okay let me try
assume theoretically that cosA = 0.25, then how you find angle ?
do youhave calculator ?
vale sand
Uh yeah
toxic monolith
so use it
vale sand
useing cosine law
toxic monolith
set deg mode
sharp oak
sin law involves two sides and two angles, where each angle is across from the side
vale sand
7^2 equals 3^2 plus 5^2 minus
toxic monolith
and take inverse , arc cos
vale sand
30 and then cos
whatever that would be
so
48 equals 34 minus 30 cos smtn
therefore it would have to be negative to have 48 equals 48
sharp oak
What did you get after algrbaically rearranging?
vale sand
Uh was i supposed to i was just working the formula
49 equals 34 - 30 and then the unkown
so therefore it would be
cos 120
-.5
and then
okay yeah
figured it out
Thanks guys
@sharp oak thx for the help later
.close
odd edgeBOT
odd edgeBOT
Available help channel!
crystal wadi
A large pan contains a mixture of oil and water. After 2 litres of water are added to the original contents of the pan, the ratio of oil to water is 1:2. However, when 2 litres of oil are added to the new mixture, the ratio becomes 2:3.
Find the original ratio of oil to water in the pan (in its simplest form).
I asked ai and it answered 1:2, which is clearly wrong since it was 1:2 after 2L of water was added.
sinful dirge
Hello guys.. The question are to find C such that area of shaded region A1 and A2 are equal.
line y=c and curve y=8x-27xcube . However, i tried every way and it seems like the answer is numerical . Very weirdddš
odd edgeBOT
Hello guys.. The question are to find C such that area of shaded region A1 and A...
@sinful dirge Has your question been resolved?
sinful dirge
<@&286206848099549185>
jolly wraith
?
dense cloud
Yep
sinful dirge
helo gais
and if i found the value of x1 and x2, how would i know if c is equal to x1 or x2
<@&286206848099549185> anyone please š
jolly wraith
no
sinful dirge
nuuu y
shy sundial
hi
sinful dirge
hi
inner bloom
<@&286206848099549185> anyone please š
Hi
sinful dirge
hii
shy sundial
This is what you have for now
- and 2) are justified because you are supposing a and b are the x's that satisfy 8x-27x^3 = c
- from A1 = A2
you can use 2) into 3) to find a value for b. Look that b must be greater than 0
after finding the value of b, you can plug it back into 2) to get what c must be
@sinful dirge
sinful dirge
oh wow.. thanks.. let me try it
shy sundial
and if i found the value of x1 and x2, how would i know if c is equal to x1 or x...
c could be x1 or x2, but not necessary
look that x1 is a point in between, but c cannot be equal to x1 since c > 0 and x1 < 0 (in this immediate example below this comment)
Here's the problem summarized in a sketch,
clever fjordBOT
odd edgeBOT
@sinful dirge Has your question been resolved?
sinful dirge
ya but for checking maybe
ohya trueš
ok can
i solved it š thanx so much @shy sundial
shy sundial
np
sinful dirge
.close
fleet harbor
odd edgeBOT
fleet harbor
can someone please help me
i have no idea how to do this
idk if my working is right
brittle beacon
what type of differential equations do you know how to solve? 
odd edgeBOT
@fleet harbor Has your question been resolved?
fleet harbor
first order and second order
homogenous and non homogenous
<@&286206848099549185>
scenic sinew
@fleet harbor an you obtain the differential equation
ah yuo did find it
tbh their question just isn't clear
they say "denote velocity by v" but what they ask for doesn't seem like it should need it
brittle beacon
first order and second order
You'd have a second order one here, wouldn't you? as acceleration is second derivative of position/displacement
scenic sinew
$F = ma = (1) a = \dv[2]{x}{t} = 6 - 5x$
brittle beacon
The fact that $F = ma$, you have $m=1$ and that you're also given $F = 6 - 5x$ gets you $\ddot{x} = 6 - 5x$
scenic sinew
nice we're thinking the same things at the same time
fleet harbor
i get that
but itās not a function of t
force = acceleration but how do i get x(t)
brittle beacon
but itās not a function of t
Acceleration is a function of time, no? (being the second derivative of displacement)
brittle beacon
You said you know second order differential equations - have you happened to deal with second order linear differential equations?
brittle beacon
Yea there you go 
fleet harbor
thanks
odd edgeBOT
@fleet harbor Has your question been resolved?
haughty prairie
odd edgeBOT
haughty prairie
ignore the selected one
whole pulsar
Whatās the question?
haughty prairie
oh wait would D be the answer
shut garnet
seems u r right
haughty prairie
Whatās the question?
rationalize denominator and simplify
yea my brain froze for a sec, ty
.close
gleaming hedge
have to find all alpha for which these series are congruent
gleaming hedge
our lecturer expanded nsin(1/n) using Taylor
became 1/6n^2+O(1/n^4)
saw that we can use the theorem for lim n-> inf an/bn
if either is congruent, then both are congruent
he saw that he could use 1/n^2 from the expansion
and got 1/n^(2Ī±)
then he put both series in a limit
lim (1-nsin(1/n))^Ī±/1/n^(2Ī±)
is that enough?
he saw that for Ī±=1/2 1/n^(2Ī±) becomes congruent
because of the criterion 1/x^p
that's enough, right?
.close
simple pond
Imagine we've the next exercise: find if the matrix A is diagonalizable. I would follow the next steps Find the autovalues (d) with its charasteristic polinomial |A-d*I|=0, then, I would have to find the numbers of autovectors for each autovalue so i can know if the geometrical multiplicty is equal to the algebraical multiplicity of the autovalues. But I want to know if there's other way to know it, so I've noticed that if rg(A-d*I|0)=2 we would have an only autovector because in the undeterminated system we would have to put an only parameter to solve it, and if rg(A-d*I|0)=1 I would have to put 2 parameters to solve it, so it generates 2 autovectors, which means that in that cases (which are the most of the cases that I've seen) if rg(A-d*I)=2 which at the same time is rg(A-d*I|0) I would have an only base, but if that's equal to 1 I would have two bases. So I would be able to find out the geometrical multiplicity without knowing the autovectors (the ones that we need, I mean the bases of the autospaces), just calculating the dimension of our vectorial space minus the rank of the matrix, but if I want to use that method that suposition must always work, otherwise said. I want to know if: for a space R^n the geometrical multiplicity (G) matches to the next formula: G=n-k being k the rank of the rank of the matrix (A-d*I)
simple pond
I know that for a realistic utility I shouldn't do that, because I need to know the autovectors and all that things but in a lot of exams in my university they only ask if the matrix is diagonalizable or not so doing it in that way would help me a lot
odd edgeBOT
@simple pond Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
peak maple
why do they need to add 3
odd edgeBOT
why do they need to add 3
peak maple
from here
livid storm
What do you want to show
fossil moth
They intend to complete perfect square
So they added 3 to both sides for their convenience
olive ledge
,w x^2 -2x + 1 \geq -1
fossil moth
Yeah, the question arises, what are these steps for, and what is the main question here
Knowing the cause and understanding it let us know the effect
odd edgeBOT
@peak maple Has your question been resolved?
peak maple
What do you want to show
That the function is increasing
fossil moth
To prove a function is increasing, you have to show that derivative of f(x)>=0 for all x belongs to R
peak maple
Yh I was just wondering why do they need to add three to complete square
tacit bronze
can someone help me figure this out please thank you
wooden python
how did you get 0.63245
clever fjordBOT
Ann
tacit bronze
yes
tacit bronze
Oh ok do you know how i would get the answer.my teacher dosent speak loud enough so i didnt understand when he was going over it
wooden python
ok so then you're saying that the concept of "slope" is completely unknown to you.
is that correct?
@tacit bronze
tacit bronze
yes
wooden python
the slope of a line joining two points $(x_1, y_1)$ and $(x_2, y_2)$ can be found with the following formula (which \textit{defines} it, really): $$m = \frac{y_2 - y_1}{x_2 - x_1}$$
clever fjordBOT
Ann
wooden python
do you know this?
wooden python
show all of your calculations
all of them
if you used a calculator, show exactly what you entered into it
wooden python
yes
then you lied to me when you said the concept of slope was completly unknown to you
or maybe you misled me unintentionally, which is more likely.
tacit bronze
sorry what i meant is that even when i did do it i still got something wrong
wooden python
.-.
well again.
i don't see what you are doing.
so you will have to show me.
if you don't show me all of your calculations, then i cannot help you.
tacit bronze
this is what i got .But i know its wrong
sorry for the misunderstanding
this is the hint thatt i got
clever fjordBOT
Result:
6.3245553203368
oh let me try that
wooden python
you could also be a bit smarter and simplify $\frac{f(x)-0}{x-0}$ in the general case (it simplifies quite nicely) and then plug into that.
clever fjordBOT
Ann
wooden python
would save you some work.
wooden python
.close
tacit bronze
.close
cyan spoke
The little prime omega function can be defined as so:
cyan spoke
Is there a similar convenient expression for the big prime omega function?
odd edgeBOT
@cyan spoke Has your question been resolved?
odd edgeBOT
@cyan spoke Has your question been resolved?
mystic saffron
ig it ll be Ī©(n) = -Ī£ Ī¼(d) / d
cyan spoke
ig it ll be Ī©(n) = -Ī£ Ī¼(d) / d
why do you think that?
I mean even for a number like 2 you get -1/2
gilded vector
If CB and AM are of equal length, how large is Ī±?
Ive been stuck on this problem for a while now, because I just dont know where to start.
I already have a few equations:
Ī“1 = Ī“2 = 20Ā°
Ī± = 140Ā° - Ī²
Ī± + Ī“1 + Ī“2 + Ī² = 180Ā°
My thought was to somehow find Ī² and then calculate Ī± from that
Just to be clear though, I just need a little hint on where to start, not a solution to the problem
mystic saffron
a means alpha?
lavish pollen
If CB and AM are of equal length, how large is Ī±?
Ive been stuck on this problem...
is CB part of the circle
gilded vector
a means alpha?
yes
gilded vector
is CB part of the circle
what exactly do you mean by that
lavish pollen
i think you can say CM=BM because theyre radii of the circle and using that the angle M in the triangle MCB is 140 degrees and calculate d1 and d2
whcin in this case d1=d2 because MCB is an isosceles traingle
gilded vector
that is correct
mystic saffron
CM and BM are the radius, CB is the chord
gilded vector
both B and C are on the circle
lavish pollen
a+b=40 definitely i just dont know how to continue it form there i suck ass at geometry lamo
gilded vector
you mean a+b = 160Ā°, right? because d2 = 20Ā°
lavish pollen
isnt there a rule that says that one angle is equal to the sum of the 2 adjacent ones?
gilded vector
isnt there a rule that says that one angle is equal to the sum of the 2 adjacent...
i dont think so
full yarrow
try forming a simultaneous equation with the internal sum property of triangles
2 unknowns, 2 equations
gilded vector
isnt there a rule that says that one angle is equal to the sum of the 2 adjacent...
if you had a really pointy triangle for example, that wouldnāt apply
full yarrow
i.e
you know alpha + beta + 40 = 180deg
and you know that alpha + (beta + 20) + 20 = 180
you can solve these simultaneously to find both alpha and beta
oh wait
no
nevermind
gilded vector
yeah
full yarrow
huh
gilded vector
those are the same
gilded vector
<@&286206848099549185> does anyone else have an idea
full yarrow
alright got it
CB forms the arc of a circle right
try drawing a tangent from point C so it intersects with AM
similarly, draw a perpendicular line from the midpoint of CB, which should intersect M
i think that gives you enough information
say the midpoint of CB is point P
gilded vector
try drawing a tangent from point C so it intersects with AM
you mean a line with āslope 0ā
?
gilded vector
M is the midpoint though
and CM is a radius
so it would be perpendicular to CM, right?
lavish pollen
is CA tangent to the circle or nah
full yarrow
alright
so uhh
the last thing i've tried
if we denote AM and CB as length L
using sine rule, you can find an expression for CM
gilded vector
is CA tangent to the circle or nah
it doesnāt appear to be
full yarrow
then, using cosine rule, you can find an expression for AC
then using sine rule again you can find angle alpha
gilded vector
could you explain that rule
full yarrow
sin(A) / a = sin(B)/b = sin(C)/c
cosine rule is c = sqrt(a^2 + b^2 - 2abcos(C))
theres probably a smarter way of doing it, but i think it'll give you the right answer
gilded vector
so that would be
AC = AM*sin(40Ā°)/sin(Ī²)
im gonna assume that both AM and CB have the length 1
to make it easier
fluid tundra
If CB and AM are of equal length, how large is Ī±?
Ive been stuck on this problem...
you can solve this problem with a little bit of clever trigonometry
gilded vector
the thing is, I barely know anything about trig
gilded vector
im gonna assume that both AM and CB have the length 1
so then AC = sin(40Ā°) / sin(Ī²)
full yarrow
yeah
though uhhh
the brute force method leads to quite a messy answer so i'm not sure how correct it is
gilded vector
true
I did a bit of research and it seems that if we can get the length of AM, AC and CM, we can calculate Ī±
fluid tundra
the key here is that AM = CB
this solution is hard to come up with but in my opinion is very clean and nice
gilded vector
so?
full yarrow
I did a bit of research and it seems that if we can get the length of AM, AC and...
yeah, and you can find the length of AC using the cosine rule
since you know the length of AM and CM
gilded vector
so then AC = sin(40Ā°) / sin(Ī²)
.
gilded vector
how would that work
full yarrow
the cosine rule
agile swan
Hello , Can you help me with the differential Geometry question? My question is how can I find the frenet frames of the Darboux vector?
full yarrow
you can calculate the length opposing the angle using the angle and it's two subtending sides
fluid tundra
Hello , Can you help me with the differential Geometry question? My question is ...
ask question in #help-15
full yarrow
i.e, the 40 degree angle, AM and CM
CM you can find using the 140 degree angle CMB, as well as the length of CB and your delta angles
gilded vector
looks correct
fluid tundra
everything is relative here so you can comfortably denote any side length as anything and you will be fine
gilded vector
AM = CM = 1 makes it easier though (I think)
fluid tundra
sure thing
the condition we want to use up is AM = CB
as long as we can successfully use this condition, we have the answer
to use this, we want to relate CM to AM and CB
fluid tundra
the way i did this was using definitions of trig identities
CB = 2CMcos(20)
AM = CMsin(40) + CMsin(40)cot(a)
gilded vector
idk if that is correct but im gonna assume it is
fluid tundra
do you understand how i obtained the length for CB?
gilded vector
I think im gonna try to learn a bit more about trig and see if I can understand the equations
full yarrow
AM = CMsin(40) + CMsin(40)cot(a)
far cleverer
fluid tundra
the reason i don't like my solution is that it's very difficult to see the manipulation that's needed to determine cot(A)
... that task alone could be its own problem and be respectable in its own right
full yarrow
yeah, good spot
odd edgeBOT
@gilded vector Has your question been resolved?
odd edgeBOT
@gilded vector Has your question been resolved?
gleaming mason
odd edgeBOT
gleaming mason
I am not sure how to find the transformations for these, a lot is happening in the function
The 1st one is correct
odd edgeBOT
@gleaming mason Has your question been resolved?
odd edgeBOT
@gleaming mason Has your question been resolved?
gleaming mason
Does no one know how to do this ;-;
gleaming mason
<@&286206848099549185>
cinder elk
@gleaming mason You wouldn't really have to look at the transformations, mainly the powers.
the powers tell you in which directions the ends are going and how may roots the function can have at maximum
if squared, there can be a maximum of 2 roots, if cubed maximum of 3 roots, so on
if 2, 4, 6, 8... then the graph will start by approaching 0 from large positive numbers and go back up to large positive numbers (unless flipped like -x^2) like a big U, may not always have a rounded bottom though
since in these ones you it doesn't matter what you plug in, you get a positive number of it
however with a function whos leading power is 3, 5, 7, it would like kind of like a sideways s
since you can plug a negative into it and get a negative out
gleaming mason
@cinder elk coming in clutch again ā¤ļø ā¤ļøā¤ļøā¤ļø
cinder elk
@gleaming mason do you get what I am saying with this? also hell yeah
gleaming mason
gleaming mason
the powers tell you in which directions the ends are going and how may roots the...
.
Ok so
Whereās our y value? For number 2, if we started with it
cinder elk
y-value?
cinder elk
- cannot be D, btw
gleaming mason
I know A and B are x^3 graphs at least
cinder elk
I know A and B are x^3 graphs at least
yes
cinder elk
in 2, what happens if you factor out the x(3 - x)^2
gleaming mason
(3-x) (3-x) twice
cinder elk
distribute it
gleaming mason
X^2 -6x+9
cinder elk
now x(x^2 - 6x + 9)
gleaming mason
.
cinder elk
?
gleaming mason
Ignore it keeps me from having to scroll
cinder elk
ok
gleaming mason
X^3 + 9x-6x^2
cinder elk
now you have almost another function that has x^3 + 9x - 6x^2
the whole function will be (x^3 + 9x - 6x^2)/3
gleaming mason
Okay?
gleaming mason
Ok
cinder elk
$\frac{x^3 + 9x - 6x^2}{3}$
clever fjordBOT
dragonbreath
cinder elk
you have 2 functions that will look like the sideways S
cinder elk
they're any function that has a power of 3 as the highest power
gleaming mason
ā¦
cinder elk
typically, they can also be basic x^6 or x^9
yeah but now you have which two functions are those, you just have to figure out which is which
gleaming mason
How the heck would I graph a quadratic function;-;
cinder elk
?
gleaming mason
**dragonbreath**
.
gleaming mason
Yes
cinder elk
sorry, that is an either or, yes makes me more confused
gleaming mason
oh that one?
.
gleaming mason
**dragonbreath**
.
cinder elk
plug in 0, what do you get?
cinder elk
0 can be in the numerator, it just can't be in the denominator
gleaming mason
Ok
cinder elk
lets think of division like this, take nothing and try to split it into 3 groups, how many groups do you have?
or I guess this way might work as well
clever fjordBOT
dragonbreath
cinder elk
**dragonbreath**
too explain why 0/x can be possible but x/0 isn't think of it like this
what times three equals 0?
gleaming mason
0
clever fjordBOT
dragonbreath
cinder elk
what times 0 equals 3 or can you bring you to the closest multiple of 0 to 3
gleaming mason
Nothing?
cinder elk
yep
gleaming mason
Okā¦so in case of graphing the quadratic/ 3
cinder elk
0
so now that you get 0 by plugging in 0 which graph that looks like a sideways S has a point at the point (0, 0)
gleaming mason
B! It goes thru the origin
cinder elk
yep, therefore the other sideways S function belongs to which Function?
gleaming mason
3
cinder elk
yep, so the last graph belongs too?
gleaming mason
Ok, so for D if this was a different problem and I didnāt know, Iām substituting 0?
cinder elk
you can, that will tell you where the y-intercept is at
so if all the graphs have different y-intercepts that you can clearly tell apart, you can use that method
gleaming mason
Ok so for this, I know -f(x) will reflect amongst the y axis
So -x^3 makes sense
But what about the second half
cinder elk
what is the point on the y-axis?
gleaming mason
4,-32
cinder elk
that says -32?
no not that point
this one
I should be able to figure out that it says 0, -10?
cinder elk
ok, so the graph was only shifted up and down (after the flip about the x-axis)
so if you plug in 0 to your function that you have right now, what do you get?
gleaming mason
0
cinder elk
and basically how do you get that to -8?
cinder elk
no
0 +- ? = -8
-x^3 - 6x^2
-(-2)^3 - 6(-2)^2
--8 - 6(4)
8 - 24 = - 16
so you need to plug in 0 into your function and somehow get -8 out of it, what can you do to get this as a possibilty?
cinder elk
how can 0 + 0 = -8?
cinder elk
yes, but you are creating a function so you can add other numbers after it
so if it is -0^3 - 6(0)^2 +- ? = -8
gleaming mason
0+0 + ? =-8
cinder elk
yep
cinder elk
0 + 0 + 64 = -8
cinder elk
there is no trick question here what would you literally plug in there to get -8?
gleaming mason
-8
cinder elk
yes
gleaming mason
cinder elk
i CANNOT with that emoji, lmfao
gleaming mason
So just an additional minus 8
cinder elk
yes, it moves the function down 8
gleaming mason
So explained short
cinder elk
?
gleaming mason
In the first graph, itās already at 0
In the second itās reflected but also 0,-8
Because itās -8, it brings your graph down and you have to import it into your function
cinder elk
yes
cinder elk
try -x^3 + 6x^2 - 8
gleaming mason
Ah yes, because the - is distributed
cinder elk
yes, did it say it was correct?
gleaming mason
Yes
cinder elk
ok
gleaming mason
Dragonbreath, are you going to be online like last night?
cinder elk
maybe, maybe not. It just depends on how tired I get cause I woke up around noon today (est), so maybe. I mean I have nothing much tomorrow but some homework so maybe
gleaming mason
Okk, I have another set of problems involving trig
I have an entrance exam Tuesday and thatās why Iāve had so many questions trying to get everything
P4 (Set 2) is 50 questions, but I think I have a better clue of what Iām doing for those , I may have some questions here and there, but probably not as much
And I may try to get 10/15 out of the way tonight
Can I come to you as a consistent tutor to help me prepare? Not for every question, but you seem to be the most available and helpful
cinder elk
you can try, I mean I don't personally mind if you ping me when you open a help request, but I know mods might have a slight problem with it, I may also not see it right away
shell mesa
Hi I'm confused about this graph
odd edgeBOT
Hi I'm confused about this graph
odd edgeBOT
@shell mesa Has your question been resolved?
odd edgeBOT
@shell mesa Has your question been resolved?
odd edgeBOT
@shell mesa Has your question been resolved?
dark kraken
It's asking what changes a contonuities are represented in the data
!status
odd edgeBOT
It's asking what changes a contonuities are represented in the data
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
6
jolly zephyr
odd edgeBOT
jolly zephyr
stuck on a)
desert marlin
what comes after -8
jolly zephyr
16
desert marlin
and after that?
jolly zephyr
-32
desert marlin
next?
jolly zephyr
64
jolly zephyr
-128
jolly zephyr
yes
desert marlin
and after -512?
jolly zephyr
1024
jolly zephyr
my teacher told us not to do that
desert marlin
Okay
Well can you describe your sequence
at every step what happens
it multiplies by 2
jolly zephyr
x-2
desert marlin
and the sign alternates
right
so everytime you're essentially doing 2^(n) (-1)^(n)
check that this formula does what you want it to
what is the first term?
2^(1) (-1)^(1) = -2
the second?
jolly zephyr
-2
jolly zephyr
4
desert marlin
Great
so it works
the sequence is, 2^(n)*(-1)^(n)
Okay so now you want to know
what value of n, gives you 1024
right?
jolly zephyr
yes
desert marlin
Okay
the (-1)^(n) term really doesn't matter for figuring that out does it?
you can't get -1024
if you can get 1024
Agree?
so really all we have to know is when 2^(n)=1024
does that make sense?
jolly zephyr
yes
desert marlin
Great so can you solve 2^(n)=1024?
jolly zephyr
no
desert marlin
You just did earlier
jolly zephyr
oh
desert marlin
without realizing
jolly zephyr
is there a quicker way
desert marlin
you can take the log_2 of both sides
plain sun
can someone please help me with this?
odd edgeBOT
can someone please help me with this?
hoary marsh
!status
odd edgeBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
$\text{first at all, notice that }\text{ }x\neq2\\\text{also }\text{ the given inequality is true}\\\text{for all }\text{ }x-2<0\text{, since then left side will be negative}\\\text{but right side positive}$
clever fjordBOT
Joanna Angel
toxic monolith
can someone please help me with this?
$\text{so consider the case, where both sides are positive}$
clever fjordBOT
Joanna Angel
plain sun
$\text{so consider the case, where both sides are positive}$
the right side is bigger?
toxic monolith
$\text{it is going to look like }\\8<\left( x-2 \right)^{3}$
clever fjordBOT
Joanna Angel
toxic monolith
for x > 2
toxic monolith
for some values
solve the rest it is goign to be easy
uncut furnace
Could someone help me with how to prove this? I honestly just don't know where I should go from here
uncut furnace
oops ;; I'm really sorry, could you explain? it's just, i took some absences and now 9th grade math isn't 9th grade math-ing
hoary marsh
Are you aware of $\sin^{2}\left(x\right)+\cos^{2}\left(x\right)=1$?
clever fjordBOT
LE SSERAFIM
uncut furnace
um i need help again........ justt where do i begin with number 4/what identities should i use?
green elm
maybe use sin(2x) = 2sin(x)cos(x)?
unless A is a complex number, there's not gonna be a solution obviously
mystic saffron
unless A is a complex number, there's not gonna be a solution obviously
this is 9th grade apparently
so no complex
green elm
so the question makes no sense
sinA and cosA are both numbers between -1 and 1, their product can't be -2
mystic saffron
yeah its odd
uncut furnace
could anyone explain to me why that is? because I really don't understand but I wouldn't know how to explain if I asked my teacher about this
green elm
if you take a number, and multiply it by a number between -1 and 1, the result can't be larger (in absolute value) than the original number
if you multiply it by 1, nothing changes
if you multiply it by -1, only its sign changes
if you multiply it by something strictly between -1 and 1, its absolute value gets smaller
toxic monolith
could anyone explain to me why that is? because I really don't understand but I ...
look if sinAcosA = -2, then 2sinAcosA = -4, then sin(2A) =-4, and that is impossible, show it to your teacher, that he or she made a mistake
odd edgeBOT
@uncut furnace Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
thorn imp
odd edgeBOT
thorn imp
The sin is -1/2
And I have to put it into algabreic foÅ
Form
Cause I cant find these coordinates on the unit circle
.close
odd edgeBOT
odd edgeBOT
Available help channel!
rich yacht
odd edgeBOT
rich yacht
between the two steps where did everything about cot 70 and tan 70 and stuff go
Like the stuff in the brackets
this part
viral frost
||cot(x) = 1/tan(x)||
atomic niche
How could I solve this equation finding for x?
odd edgeBOT
How could I solve this equation finding for x?
silver light
start by using the basic algebra steps
multiply both sides by 2 to simplify one side of the equation and it'll be easier to go from there
atomic niche
4x/3 = 2x + 1 correct?
silver light
4x=3(x+1) would be a better way of solving it
oh i see what you've done...
you multipled the right hand side of the equation by 2, twice
atomic niche
Oh i thought if you multiply one side by 2 you do that the other side too
silver light
yeah i did mean that, but you did that twice on the right hand side i think...
... = x+1
----- (x2)
2
= x+1
not 2x+1, which is what you put down
simple mistake to make, keep your head up
atomic niche
Ah i thought you simply do it like this 2(x+1/2)
silver light
im sure if i was a smart person i could explain how to do it that way and get the right answer, but i think thats just confusing you for the moment... make things easier on your self and simplify your thinking and working out
atomic niche
I see, well then we have 4x=3(x+1) which becomes
4x = 3x + 3
x = 3
atomic niche
im just curious how did you get to 4x=3(x+1) if possible heh
atomic niche
.close
odd edgeBOT
silver light
ahhhhhhh i see its only possible by the OP
odd edgeBOT
Available help channel!
hexed edge
Hi everyone
odd edgeBOT
Hi everyone
hexed edge
can anyone explain to me the working in blue?
I have no idea how it works and how they calculate all the matrix
how did it become 0, -7, - 4 and -1...
low locust
the working in black also got those 0,-7,-4
you are subtracting twice the first row from the second
hexed edge
you are subtracting twice the first row from the second
ohh what about the third
hexed edge
ohh
hexed edge
exactly what they are writing next to it
how did it become 1/7
where did this 7 come from
low locust
to make the leading entry (which is a -7) to a 1
hexed edge
ohh I think I get it
We always need to make the matrix look like this right?
1 0 0
0 1 0
0 0 1
That's how we solve it?
gusty blaze
i am kinda confused here
odd edgeBOT
i am kinda confused here
gusty blaze
this is my first day in linear algebra
i thought we would add 4/5 times row 1 to row 2
oh but i guess that doesn't work because we lose the 0 in the first column
what is the goal here
how do we know when to stop applying these rules
.close
gusty blaze
how do you know when a matrix is solved
odd edgeBOT
how do you know when a matrix is solved
gusty blaze
like how do we know this is a solved matrix
why not keep going until the rest of the 1's are 0's
ashen flax
I believe its because if you look at it like a system of equations, each "1" represents one of the variables in your equation
So that matrix is saying x = -7 and y = 4
If the rest of the 1's were zeros that wouldn't make much sense because then that's saying ??? = -7 and ??? = 4
Does that make sense?
timber dome
like how do we know this is a solved matrix
I would like you to try making the rest of the ones into zeroes.
odd edgeBOT
@gusty blaze Has your question been resolved?
gusty blaze
Does that make sense?
so once we're done solving we should have one 1 per row in our matrix, for each variable we are trying to solve for?
gusty blaze
I would like you to try making the rest of the ones into zeroes.
i am not good at linear algebra so idk how
timber dome
It's not possible is what I mean.
timber dome
so once we're done solving we should have one 1 per row in our matrix, for each ...
Yes, exactly. Sometimes, this is not possible, which either means there are no solutions to the system of equations or there are an infinite number of solutions.
Take for example the system of equations x+y=1; 2x+2y=2. This has infinitely many solutions and you will never be able to transform it into the form x=a; y=b for some constants a and b.
nimble relic
how do I find these using unit circle?
odd edgeBOT
how do I find these using unit circle?
mystic saffron
are u more comfortable with radians or degrees?
if the latter, we can do our work in degrees first
nimble relic
degrees to be honest
nimble relic
90 degrees right
nimble relic
like drawing a triangle in the unit circle u mean
nimble relic
not really
mystic saffron
what does the angle 120 make with the negative x axis
nimble relic
is it 60? or maybe should I watch a video about this
mystic saffron
yeah its 60
nimble relic
ok so I understand what u mean
mystic saffron
so like
what u can do is evaluate tan(60)
and because cos is negative in quadrant 2
plug a negative sign
nimble relic
oh ok
mystic saffron
tan(120) = -tan(60)
nimble relic
so -3.2
mystic saffron
no
dont approximate
at all
if its irrational dont approximate it
unless they ask u to
odd edgeBOT
@nimble relic Has your question been resolved?
wooden python
well this is a tiny tiny bit cheaty, but the degree of the numerator is basically 1.5
(if one were to extend such a notion to roots and the like)
this might sound stupid
you are right it does sound stupid.
big * big^(1/2) = big^(3/2), maybe.
(x-3)/x approaches 1
and sqrt(9-x) approaches +ā
god
if you want to use l'hop then use l'hop idk
it IS applicable here so like
go nuts
it is overkill
amber schooner
odd edgeBOT
wooden python
trust me l'hop is not only overkill but also long here
odd edgeBOT
Available help channel!
gusty blaze
what is the trick here
odd edgeBOT
what is the trick here
gusty blaze
my ti 84 has been carrying me through other systems of equations
but this is the first one with a variable in it
idk how to solve this
nocturne belfry
what is the trick here
maybe a video would be helpful? https://www.youtube.com/watch?v=8Zj5riYu13s
oh cool i found one that has no sound
gimme a sec
odd edgeBOT
@gusty blaze Has your question been resolved?
gusty blaze
https://www.youtube.com/watch?v=RFtxCsisa30
hmm i am confused here
where did the h go in the third step
nocturne belfry
looks like a typo
gusty blaze
ohh okay
odd edgeBOT
@gusty blaze Has your question been resolved?
rancid compass
odd edgeBOT
rancid compass
someone explain to be how to do 125 b, c and 126 a, b
i completely forgot how to do this
spare hornet
take 2 as common
rancid compass
haveb't done this in over 3 months
rancid compass
wait
spare hornet
wha
rancid compass
126 b
rancid compass
bruh
spare hornet
mb
let me see
loked at worng part
ok
factor it
then multiply it together
if you get the function given a is 1
if not then try to find a thru trial and error
spare hornet
wat ima do it and show u
spare hornet
no for b you factor then to check if you ahve right answer u mutiply if you dont get back to og eqaution then u nee value of a
spare hornet
yeah
rancid compass
how do i simplify the function
spare hornet
okay 125 c?
rancid compass
yeah
spare hornet
okay
spare hornet
denominator take 2 as common so 2(x-3) on the top factro like before and if nayhting cancels cancel
spare hornet
x^2-2x-3/2x-6
yeah
rancid compass
denominator take 2 as common so 2(x-3) on the top factro like before and if nayh...
ok so i got x^2-2x-3/2(x-3)
what now?
spare hornet
factor on top
rancid compass
x(x-2)
spare hornet
on the numerator
spare hornet
yeah
spare hornet
wait a sec
let me do it
it should be
(x-3)(x+)
(x+1) on top
and x-3 cancels
so
(x-1)/2
so
(x-3)(x+1)/2(x-3) x-3 cancel
gone
woosh
spare hornet
yeah
rancid compass
hol up
spare hornet
wht grd r u in
rancid compass
10th
spare hornet
oh where?
im in 11
u should be more advanced in 10th
than what u are doing
imo
rancid compass
u should be more advanced in 10th
im in pre-dp
higher level math
we have to take higher level in 10th grade, but after that we can choose the difficulty
we're essentially repeating 9th grade math but a bit harder
mystic saffron
$$\lim_{{a \to \infty}} \int_{0}^{a} \frac{2x+1}{x^{4}+2x^{3}+3x^{2}+2x+2} ,dx
$$
mystic saffron
oh no
main creek
edit your original message
tall veldt
missing some _
clever fjordBOT
snow
main creek
!status
odd edgeBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
this is big bully problem
tried diving by x^4
dead end
that's all
i dont know how to approach this
i need hints
but small ones
i also have like choices
main creek
looks like a PFD problem