We get $3x - 2x -y -(-y) = 1 -(-1)$
#help-19
tight crescent
clever fjordBOT
USS-Enterprise
undone swift
Thank you 🙂
tight crescent
$x -y + y = 1 +1$
clever fjordBOT
USS-Enterprise
tight crescent
$x = 2$
clever fjordBOT
USS-Enterprise
tight crescent
And boom, we've already got x!
tight crescent
Thank you 🙂
no problem 🙂
And we do the same thing we did before
Go into one of the earlier equations, plug x in and get y
Say $2x - y = -1$
$2 \cdot 2 - y = -1$
undone swift
4-y=-1?
tight crescent
$4 - y = -1$
clever fjordBOT
USS-Enterprise
tight crescent
$-y = -5$
clever fjordBOT
USS-Enterprise
tight crescent
$y = 5$
clever fjordBOT
USS-Enterprise
tight crescent
Of course, even if you use different methods you get to the same solution
This is math
undone swift
Thank you for real 
tight crescent
We isolated one variable (y) and plugged it into another equation, got x, then got y
And now we got rid of one variable (y)
We could have also gotten rid of x
But that's more work
Okay, so now that we have x and y
We can get the length of the sides
Remember this from before
$3x + 2 = 2y - x = y + 3$
undone swift
Yeah it depends some people prefer easier methods and some hard methods
clever fjordBOT
USS-Enterprise
undone swift
I prefer easier lol
tight crescent
You've got sides (3x + 2), (2y - x), (y + 3)
tight crescent
Yeah it depends some people prefer easier methods and some hard methods
Yep 🙂
undone swift
The way you're doing these methods it's really helpful thank you 🙂
tight crescent
If we plug the variables x = 2 and y = 5
We get 3 * 2 + 2 = 8 for the first side
2 * 5 - 2 = 8 for the second
5 + 3 = 8 for the third
Notice how they are the same!
It's a equilateral triangle
undone swift
For real!
undone swift
So the side of your triangle is 8cm!
that's part from b) or?
tight crescent
And there's a cool formula for the area of a equilateral triangle
tight crescent
that's part from b) or?
a) says find x and y
We did
b) says find the area
and we need the length of a side for the area
undone swift
b) says find perimeter
undone swift
I'll send screenshot again don't worry!
I'm for real sorry tho if this is a lot hard working
tight crescent
How do we find the perimeter of a equilateral triangle?
tight crescent
I'm for real sorry tho if this is a lot hard working
Don't worry about it! That's why we are here!
undone swift
undone swift
Don't worry about it! That's why we are here!
Yeah it's just this teacher this year everyone in my class are rlly annoyed rn
tight crescent
Yeah it's just this teacher this year everyone in my class are rlly annoyed rn
I bet 🙂
undone swift
Yeah my friend and I work together but I will send her a message to tell her that one guy online helped me with this equation 🙂
she doesn't have discord
except social media lol
tight crescent
Hehe
Okay so
Just the easiest part follows
how do we get the perimeter of an equilateral triangle?
undone swift
how do we get the perimeter of an equilateral triangle?
Hmm
we focus on these again?
wait no
tight crescent
What's the perimeter of a shape?
tight crescent
Don't worry about that
undone swift
What's the perimeter of a shape?
perimeter of shape?
undone swift
Don't worry about that
Thank you 🙂
tight crescent
Yep
tight crescent
The perimeter measures the total length around the outside of a shape
It means
You add the lengths of all the sides
But an equilateral triangle has 3 sides a
So the perimeter is just 3a
And we know our side has a length of 8cm
So what's the perimeter?
undone swift
8x3 = 24?
undone swift
Dang! So we only needed 3a I thought we needed more haha
tight crescent
So the answers: a) x = 2, y = 5 and b) perimeter = 3a = 3 * 8cm = 24cm
tight crescent
Dang! So we only needed 3a I thought we needed more haha
Nope 🙂
undone swift
So the answers: a) x = 2, y = 5 and b) perimeter = 3a = 3 * 8cm = 24cm
Thank you 🙂
tight crescent
The perimeter is always adding all the sides
undone swift
The perimeter is always adding all the sides
Ohhh
undone swift
This math thing can be really complicated sometimes haha
tight crescent
yep ... hehe
undone swift
Anyway. I hope I've been of help at least a bit
You did great you're really a great tutor!
You really reminded me of my teacher's last year ngl!
tight crescent
Thank you! Means a lot
undone swift
Thank you! Means a lot
Thank you! You rlly are a great tutor! 🙂
tight crescent
So yeah, my DMs are always open
Just shoot me a DM if you have another question
And I'll get to you as soon as I can
undone swift
So yeah, my DMs are always open
Thank you!
tight crescent
No problem. Have a good day
undone swift
At the same time I feel bad because my friend was sad on yesterday we literally had a lot of hws to do and she said life is too short to do these things etc
undone swift
No problem. Have a good day
You too you deserve better!
tight crescent
At the same time I feel bad because my friend was sad on yesterday we literally ...
Damn, that sucks
undone swift
Damn, that sucks
Yeah I just finished 8 pages of hws today for each subjects
undone swift
Yeah we really had a lot
tight crescent
Ah
undone swift
Lol
undone swift
Yeah for real I got tired like even my mom asked if I'm ok and when I will take a break lol
tight crescent
😂
tight crescent
hehe
undone swift
and we also had to literally buy things online today too what were they thinking like were some kind of technition? 😂
tight crescent
Damn
tight crescent
Hah, not yet
undone swift
Hah, not yet
Keep up the great work!
tight crescent
Thanks. You too
undone swift
What subjects u have?
tight crescent
Well
undone swift
I have about coding I used to have science but not anymore lol
tight crescent
I've got Math, Slovene, English, Chemistry, Biology, History, Geography, Sociology, Art History, German, Physics
undone swift
I've got Math, Slovene, English, Chemistry, Biology, History, Geography, Sociolo...
Dang
How are you doing tho?
Are u doing great atleast?
undone swift
I'm doing as I want to
Yeah don't give up on yourself u deserve better!
undone swift
That's great I used to have science before and we used to do research it's all thanks to my friend that I passed we mostly had online assignments for those
tight crescent
That's great I used to have science before and we used to do research it's all t...
Haha. That's a good friend
undone swift
Haha. That's a good friend
Yeah!
tight crescent
Well look anyway, I gotta go now
So
It was nice meeting you
See you around some day 🙂
And good luck with the homework
🙃
undone swift
Well look anyway, I gotta go now
Ok goodluck I wish you the best!
Don't listen to the haters! Focus on yourself!
tight crescent
😄
undone swift
See you around some day 🙂
See you 🙂
tight crescent
Just please .close
undone swift
Just please `.close`
Yeah hold on cuz my brothers needs smth
tight crescent
👍
undone swift
👍
Heyy back sorry my brother needed help with his art hws
Thank you again for helping 🙂
.close
pine drift
Hi I need help with this question. I got y = 1 but it says that’s wrong…
I tried
3(1) - 4x + 10 = 9
pine drift
zenith jasper
you have x = 1 and you are given y = -4x + 10
pine drift
Should I put that x value in
mystic saffron
yes
but there is no point in what you did
you want to find y
y= -4x +10, put x = 1
pine drift
I did it bc it says in the 1st step to substitute y value into the first equation
Does that mean something else
mystic saffron
yes
pine drift
Hi again. I got the blue line slope but I couldn’t get the yellow line slope. Idk how to do it… I kind of see a point on (2,20) and (4,40) ?
pine drift
silent pine
so for the yellow line you have points (0,0) and (6, 63) and using that you should be ok
pine drift
Ohhh ok so they gave it to me already?
silent pine
right
pine drift
Yeah it’s correct! Tysm! I didn’t know what to do
silent pine
no problem glad I could help
pine drift
.close
odd edgeBOT
odd edgeBOT
Available help channel!
glass horizon
coukd anyone help on 4a and 4b?
odd edgeBOT
coukd anyone help on 4a and 4b?
glass horizon
for a, do i just double the masses in the equation i found in 3?
or start from my equation i found for acceleration and double that
odd edgeBOT
@glass horizon Has your question been resolved?
coarse shuttle
coukd anyone help on 4a and 4b?
if both masses are doubled just substite ma with 2ma and mb with 2mb
then factor
and the twos will cancel out
so it doesnt change
glass horizon
okay thanks! do you know how to do 4b? @coarse shuttle
i got t = undefined
but i dont know what that means?
coarse shuttle
since both masses are equal you're dividing by 0
Which first of all is unholy to write as is
lol
glass horizon
lol
glass horizon
eh i dont think my teacher cares
but what does t = undefined mean?
that the blocks fall down at the same time or wont even reach the ground at all?
coarse shuttle
it's a matter of calculating the limit
glass horizon
OH WAIT do they not reach the ground because since they are attached to the same cord they'll be in equilibrium of each other
?
i forgot to send the drawing oops
coarse shuttle
OH WAIT do they not reach the ground because since they are attached to the same...
well depends
It's not exactly undefined
There are one sided limits
Consider the following
$\underset{x\to m}{lim} \quad \sqrt{\frac{-a(m+x)}{m-x}}$
clever fjordBOT
Azenx
coarse shuttle
If x comes from the right, the limit will give +infinity
if x comes from the left, the limit will give i*infinity
Which doesnt exactly physically makes sense
So let's assume x comes from the right
t goes to infinity
And you indeed have equilibrium
coarse shuttle
If x comes from the right, the limit will give +infinity
Since m-x becomes very small -a(m+x) becomes very big
Or you could factor and show rigourosly but idk if you already did limits
odd edgeBOT
@glass horizon Has your question been resolved?
odd edgeBOT
Available help channel!
@austere rover Has your question been resolved?
Available help channel!
narrow shoal
pls help me. I dont understand why 5% higher is the correct answer.
narrow shoal
Its from a deca practice test, and I need to know how to do it asap.
frail thistle
Gross profit = sales - COGS
then you find gross margin
Do you know how to find it?
frail thistle
Ok gross margin or gross profit in the way they state it is gross profit/sales
narrow shoal
bc in the question is says the sales amount
frail thistle
it's just a percentage
More specifically if $1 of sales, how much of that $1 is gross profit
If you calculate gross profit and then the gross margin, you'll get to your answer of % and then compare with the industry standard
narrow shoal
ok ill try that ty
frail thistle
Lemme know if you're able to get to the right answer
frail thistle
Can you show me your steps?
narrow shoal
frail thistle
Why are you subtracting 20000?
narrow shoal
260,000 bc cost of goods sold is $260,000
frail thistle
I mean why are you subtracting 140000 by 260000
You already found gross profit with sales - COGS
Which is 140000
narrow shoal
yea but then how do i convert that into percentage
frail thistle
Remember gross margin is gross profit (140000)/sales
narrow shoal
oooh so would i do 140000/ 400,000?
frail thistle
Yup
narrow shoal
ooooooooooooooooh
frail thistle
Yeah and what does that get you?
narrow shoal
.close
lyric marlin
very last step
double check what you're scaling Z2 by
yes
as in the thing you're doing to get the last matrix
if you do Z3-1/8Z2, yes
pretty sure it's a 3 and not a 2 in the last column
-24/8 = -3
seems good
mellow basin
odd edgeBOT
mellow basin
please help with this
odd edgeBOT
@mellow basin Has your question been resolved?
mellow basin
^
forest sky
which problems are you stuck on?
odd edgeBOT
@mellow basin Has your question been resolved?
chilly ridge
Confused on how to construct the inequality
odd edgeBOT
Confused on how to construct the inequality
fervent hawk
are those Y_1, Y_2 in the form of mx+c?
chilly ridge
Ig?
fervent hawk
if not, we can't conclude anything
chilly ridge
Must be then
chilly ridge
Alr how ab this one
fervent hawk
Alr how ab this one
i see, this is clearer
fervent hawk
Alr how ab this one
let's tackle this first then
we need to find a range of values for x so that Y1 is greater than Y2
chilly ridge
X=6
fervent hawk
as you can see from the table top down,
Y1 is increasing, and
Y2 is decreasing
chilly ridge
Yeah
fervent hawk
so Y1 will increase and increase
and Y2 will decrease and decrease
to a certain point that they reaches the same.
dull fossil
Hello
fervent hawk
which is exactly at x=5
dull fossil
Confused on how to construct the inequality
Do u still need help w this
chilly ridge
which is exactly at x=5
Yeah sure gotta finish this one tho
chilly ridge
which is exactly at x=5
Ok
fervent hawk
Ok
now that we know
Y1 will keep on increasing, so
after x=5, Y1 will be always > Y2
recall, we need a "range of values" for x
chilly ridge
Makes sense
fervent hawk
so, we need x to be greater than 5 in order to have Y1>Y2
how do we write in math symbols
chilly ridge
X≥5
chilly ridge
So that solves it or is that just part of it
fervent hawk
it solves it already
chilly ridge
Yeah makes sene
fervent hawk
@dull fossil your turn
dull fossil
Ok so this will be funny
We've been simply asked for the x values where y1 is less than y2
chilly ridge
Ok
dull fossil
Which is clearly visible on graph, red line is always below blue line on the left side of intersection
Which is (-3,-2)
So for all values from -inf to -3
It's y1<y2
That's our answer
chilly ridge
The answer is -Inf to -3?
dull fossil
Yeah, you can enter it as x<-3 or simply (-inf,-3)
chilly ridge
Js -3 beyond
dull fossil
Yea
dull fossil
chilly ridge
.close
odd edgeBOT
stiff reef
f ◦ g where f (x) = 1/(25 − x2) and g(x) = √(x − 5)
odd edgeBOT
f ◦ g where f (x) = 1/(25 − x2) and g(x) = √(x − 5)
stiff reef
i thought it would be 1/-x+20 but symbolabs says its 1/-x+30
oh wait i get it
mb
cuz like -1(x-5)
so -x+5
-x + 25+5
.close
gray plover
Let a > 0 and b > 0, solve for x.
a+b/(a+b/(a+b/...b/(a+b/x)) (2017 fraction traits) = x
gray plover
I am kind of new to these equations so i don't really now how to start
I got that x also equals b/(-a+b/(-a+b/...b/x-a)
mystic saffron
start with simplifying
gray plover
how would you do it exactly ?
toxic rose
Let a > 0 and b > 0, solve for x.
a+b/(a+b/(a+b/...b/(a+b/x)) (2017 fraction t...
U got a photo of the question?
gray plover
Yes
wait a minute
Sorry couldn't rotate
@toxic rose
<@&286206848099549185>
.close
odd edgeBOT
odd edgeBOT
Available help channel!
delicate summit
odd edgeBOT
void yew
with those values I doubt there is one other than by graphing
delicate summit
oh
void yew
Mainly the 0.2048
delicate summit
ok so i will do the graph method thanks
void yew
,w 10p^3(1 - p)^2 = 0.2048 solve for p
clever fjordBOT
zenith tartan
lol
clever fjordBOT
void yew
They're all rational so I guess you can multiply out by 625 make it into a polynomial equation with integers, then rewrite as q(x) = 0 and use rational roots theorem to check for roots I guess 
,calc 16*7
clever fjordBOT
Result:
112
Only 112 potential roots to check for with that method 
But since $1$ is close to being a root
clever fjordBOT
992qqoloy
void yew
You could start by checking values near 1 I guess
And that's how you might get 4/5 within a reasonable amount of effort
Oh wait
,calc 225*8
clever fjordBOT
Result:
160
Result:
3125
,calc 257
clever fjordBOT
Result:
70
OK this time it's right
rotund cliff
,calc 9*10^1000+99^999
clever fjordBOT
Result:
Infinity
????????
odd edgeBOT
@delicate summit Has your question been resolved?
remote token
odd edgeBOT
remote token
(y-y1)/(x-x1)?
remote token
(6-1)/(-2-1)=5/-3)=-(5/3)
zenith tartan
yes
now you have the slope
now you can use point slope form of the line
to find its
equation
,, y-y_1=m(x-x_1)
clever fjordBOT
!Yajat!
zenith tartan
put y1 and x1 the same as you used to find the slo;pe
remote token
6-1=(-5/3)(-2-1)?
mellow knoll
let $\alpha, \beta, \gamma$ be the roots of $x^3 - 5x^2 + 5 = 0$
\ Find a polynomial equation with integer coefficients whose roots are $\alpha - 1, \beta - 1, \gamma - 1$
clever fjordBOT
魔法の🌙kitty!
mellow knoll
surely, theres an easier way than expanding (x-(a-1))(x-(b-1))(x-(y-1))
south plume
imagine a graph
mellow knoll
imagining a graph
upbeat drum
(or vietas formulas)
south plume
it's roots are where it intersects 0
mellow knoll
mhmm
south plume
now, your roots are 1 less theb they were before
wooden python
actually there is a clever way that is sort of like expansion and sort of not
south plume
now, your roots are 1 less theb they were before
so now all of them are 1 unit away to the left from where they were before
mellow knoll
mhm
wooden python
$(x - (\alpha-1))(x - (\beta-1))(x - (\gamma-1)) = (x+1 - \alpha)(x+1 - \beta)(x+1 - \gamma)$, so you can get the polynomial you want by replacing all $x$ with $(x+1)$ in your eq
clever fjordBOT
AnnGhost
south plume
mhm
therefore, the entire function shifted to the left
by 1 unit
let your initial polynomial be f(x)
what you have now is f(x+1)
meaning substitute x+1 everywhere x is
south plume
$(x - (\alpha-1))(x - (\beta-1))(x - (\gamma-1)) = (x+1 - \alpha)(x+1 - \beta)(x...
yeah that's what i was explaining just now lol
mellow knoll
yeah thought so-
damn alr yay theres an easy way then
i hav a follow-up question with the same eq and roots
Find a polynomial equation with integer coefficients whose roots are a^2, b^2, y^2
mellow knoll
Find a polynomial equation with integer coefficients whose roots are a^2, b^2, y...
is there a clever graphing/substitution idea for this? @south plume
clever fjordBOT
south plume
ah!
mellow knoll
oo
south plume
is there a clever graphing/substitution idea for this? <@474467399207223307>
the roots will be roots of $f(\sqrt{x})$ and $f(-\sqrt{x})$
clever fjordBOT
artemetra
mellow knoll
huh?
mellow knoll
o btw i hav alrdy got an answer of x^3 - 25x^2 - 50x + 25, i jus wanted an easy way
mellow knoll
f(sqrt(x)) will give 2 roots and f(-sqrt(x)) will give 1 root
oh? it doesnt rly make sense to me
south plume
okay fair i kinda found that out using desmos just know
but
the idea is that the inverse of $x^2$ is $\pm \sqrt{x}$
clever fjordBOT
artemetra
clever fjordBOT
artemetra
mellow knoll
ohhh
south plume
because these operations (subtracting one and adding one) are opposite
south plume
ig
mellow knoll
so if the roots were like, a^2 -1
then f(+-sqrt(a+1))?
mellow knoll
🤯
south plume
let me check
mellow knoll
woah
mellow knoll
i need to show my teacher this 💀
molten lotus
Hello
molten lotus
1.13 isn't the same as a directional derivative, right? This is just basically dl/dw right? Note that w is a parameter (the weights)
echo ginkgo
Yes it's just dl/dw @molten lotus
potent sphinx
Could someone explain what constrained cost of construction means?
clever fjordBOT
everg
pastel dew
however the other options have all three variables used ...so there are not constraint
potent sphinx
If one of the other options also had only 2 variables, how would I go about finding the correct one
pastel dew
**everg**
because of this
20 is the fixed volume
so you would find the correct answer by compute it
potent sphinx
How do you know constraint is 20/xy
Nvm
You just equate xyz=20 and solve for z
Sorry I’m really tired haha
pastel dew
are you italian ?
potent sphinx
Yeh
odd edgeBOT
@potent sphinx Has your question been resolved?
dense moat
How would you calculate the probability of landing on a area based on the size of the section?
wooden python
!xy
odd edgeBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
tardy lagoon
calculate the ratio of the areas
dense moat
if you dropped 3 markers onto a circular board with an outer ring making up 48% and 6 inner sections making up the other 52%, how do you calculate the probably of 1 marker landing on the outer section?
lean willow
^
dense moat
i thought so, my teacher wants me to use a tree diagram, but that wouldnt figure out the actual chance
tardy lagoon
tree diagram works though
dense moat
how
tardy lagoon
add the probabilities
dense moat
wdym
tardy lagoon
the tree diagram should have 8 outcomes
3 of them have 1 marker landing on the outer section
add the probabilities of the 3 outcomes
for each outcome, follow their path and multiply the probability
dense moat
wouldnt it look like this tho?
dense moat
wdym reverse?
dense moat
tardy lagoon
looks much cleaner
dense moat
but anyway, wouldnt it look like that?
tardy lagoon
yes
dense moat
and when i multiply them i get roughly .11 out of 1
tardy lagoon
label the number of marker on outer ring
dense moat
wouldnt it be?
dense moat
label the number of marker on outer ring
wdym?
tardy lagoon
and when i multiply them i get roughly .11 out of 1
show your work
for example in,in,in have 0 marker hitting outer ring
number of out basically
dense moat
i still dont understand
tardy lagoon
you have 8 outcomes on the right
dense moat
yeah
tardy lagoon
each representing how the markers could have been
dense moat
yeah
tardy lagoon
we want to calculate probability of 1 marker landing on outer section
dense moat
yeah
tardy lagoon
so first find all the outcomes with 1 marker landing on outer section
dense moat
3
tardy lagoon
circle them on your diagram
dense moat
then entire branch or just the out?
dense moat
like that?
tardy lagoon
why decimal lol
dense moat
0.389376
39%
damn i need 48%
do i just increase the size of the outer ring until it gets to 48%?
chance
tardy lagoon
wait
you need to adjust the size
bruh why didn't you said so earlier
set the size of outer ring = p
dense moat
because i didnt know it would come to 39%
dense moat
p = 942.48cm2
tardy lagoon
wait no
dense moat
no?
dense moat
so p = 48% then?
tardy lagoon
isn't 48% the result you want?
you want the probability of getting 1 marker on outer section = 48%
tardy lagoon
but I thought you said to adjust the area of outer ring
dense moat
ok
tardy lagoon
or x if you prefer
dense moat
idm
dense moat
0.389376
tardy lagoon
no
dense moat
?
tardy lagoon
that's when p=0.48
dense moat
yeah
tardy lagoon
to get 1 marker on outer section
we need to have 1 marker on outer and 2 marker on inner
dense moat
yeah
tardy lagoon
ok now that's a lot simpler
dense moat
and theres need to be a chance of getting at least 1, 48 percent of the time
dense moat
yeah
dense moat
ok
dense moat
so whats that mean then
tardy lagoon
probability of 3 markers hitting inner section
= (probability of hitting inner section)^3
and we want to find out the probability
so we set it to p and solve
dense moat
whats ^
clever fjordBOT
WhereWolf(ping if needed)
dense moat
so its the same as p x p x p?
tardy lagoon
yes
dense moat
oh, thats alot easier then
tardy lagoon
we want to let probability of at least 1 marker hitting outer section = 48%
dense moat
yeah
tardy lagoon
how to turn that statement into an equation?
dense moat
yeah but i meant like what u did earlier
(probability of hitting inner section)^3
or just like x = 48%?
tardy lagoon
we know the probability of all hitting inner section = p^3
dense moat
yeah
dense moat
wdym they are complementary
tardy lagoon
complementary means that they are like opposite
like in a coin toss
head and tails are complementary
getting head means not getting tail and not getting tail means getting head
in math their probability adds up to 1
dense moat
yeah
dense moat
yeah
tardy lagoon
=?
dense moat
?
tardy lagoon
no
dense moat
damn
tardy lagoon
we wanta to separate at least one outer
dense moat
at least one outer = 1 + all inner?
at least one outer = 1 - all inner?
still wrong?
tardy lagoon
at least one outer = 1 - all inner?
this
plugging in the values we want
48%=1-p^3
we just need solve for p
dense moat
is it 52%
tardy lagoon
p^3=52%
tardy lagoon
???
dense moat
idk
tardy lagoon
if you had 3^p yes
dense moat
to undo the ^3
tardy lagoon
use the cube root
dense moat
3√52
dense moat
would this work
clever fjordBOT
WhereWolf(ping if needed)
tardy lagoon
yes
remember I set p as area percentage inner section
wait no
ficed it
fix
what should be the area percentage of outer section?
(they are also complement)
dense moat
.2 ?
tardy lagoon
yeah
dense moat
so what does that mean then
tardy lagoon
area percentage = 20.5854848%
tardy lagoon
isn't that what you want
oh wait
yeah
the area percentage of outer section such that the probability of getting at least 1 marker on outer section = 48%
dense moat
yeah
tardy lagoon
area percentage = 20.5854848%
the answer is here
dense moat
how
tardy lagoon
review:
let p = area precentage of inner section
then p^3 = probability of 3 inner markers
1-p^3 = probability of at least 1 outer marker
=48%
solving 1-p^3=48%, we get p = 0.804
now 1-p = area percentage of outer section
thus we get 0.196
tardy lagoon
area percentage = 20.5854848%
oops I made a mistake here should be 19.5854848%
dense moat
yeah but what is the are percentage for
dense moat
shouldnt it be more tho
oh wait hang on
so 20% means that theres a 48% chance of at least one hitting
tardy lagoon
yes
dense moat
wait, how hard is it to calculate just 1 hitting
cus idk if i need just 1 or at least 1
tardy lagoon
a bit harder
dense moat
i think its at least 1
maybe
do u want the whole question
i was tryna shorten it a bit
it wont make much of a difference
tardy lagoon
sure
dense moat
i have to design a board game where you drop 3 markers onto it, the board needs to made up of at least 4 sections. to win you need to get 31 or more points and there needs to be between a 45 and 49% of winning
so i thought id make a board where the outer ring is 31 points and the rest were 0 or 1 or smth, and then the outer ring have a 48% of getting hit
tardy lagoon
nothing
tardy lagoon
yep
dense moat
if i close this channel, can i still see all these messages?
tardy lagoon
yes
dense moat
how
odd edgeBOT
tardy lagoon
no problem
odd edgeBOT
Available help channel!
river solar
odd edgeBOT
river solar
Anyone know how to do this
odd edgeBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@river solar Has your question been resolved?
river solar
- I did 7.4+.457(127)
fervent peak
You are asked an interval, not an exact score
odd edgeBOT
@river solar Has your question been resolved?
odd edgeBOT
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Available help channel!
spark cargo
$\lim_{z \to 2i} \frac{z^2+9}{2z^2+8}$
odd edgeBOT
$\lim_{z \to 2i} \frac{z^2+9}{2z^2+8}$
clever fjordBOT
Dubleyou
spark cargo
I'm unable see any factoring trick over here
my best guess is that limit is dne as we get different limits over different paths
can you help?
leaden karma
my best guess is that limit is dne as we get different limits over different pat...
yeah pretty much
LHL != RHL, hence DNE
spark cargo
i'm not much aware to show it here formally, can you help me relate to a multivariable limit case?
say I choose path along x- axis, y=0
what changes should I make here?
$\lim_{y\to 2} \frac{(x)^2+9}{2(x)^2+8}$
leaden karma
how did limit change to 0?
spark cargo
as in x to zero?
so i can't choose that path?
along y=0, there no variable y plug tho
clever fjordBOT
Dubleyou
spark cargo
@leaden karma
spark cargo
**Dubleyou**
how do I evaluate this along y=0?
leaden karma
what do you mean y=0?
spark cargo
not sure what you're trying to say here
i change z=x+iy
spark cargo
how do I evaluate this along y=0?
it's a path,
leaden karma
the point 0+2i does not lie on y=0
you need to choose a path on which the point actually lies
leaden karma
yep
spark cargo
y=x+2?
the second path
i can just write cartesian equation without worrying complex right?
odd edgeBOT
@spark cargo Has your question been resolved?
opaque spindle
ok so i have a cubic equation f(x) = 2x³ - dx² + (1-d²)x + 5, and obviously there is a parameter there. Additionally i have been told that it is divisible by x - d. Except I have run into an issue involving the number left over after horner's method: I have solved it to (x-d)(2x²+dx+1) but still have d+5 left over, what do i do with it that d+5?
ember oak
Well if it divdes your polynomial, the remainder should be 0, right?
opaque spindle
so i didn't use the method correctly?
tall veldt
are you being asked to find d?
odd edgeBOT
ok so i have a cubic equation f(x) = 2x³ - dx² + (1-d²)x + 5, and obviously ther...
Show your work, and if possible, explain where you are stuck.
ember oak
i am being asked to find d
Well, your remainder is d+5, and it needs be zero. Any ideas?
opaque spindle
-5
and i am pretty certain d+5 is correct since i plugged d into the original function and it came out as d+5
but im uncertain if -5 is enough?
ember oak
it is
opaque spindle
isnt a parameter ususally something like 5 < d < 14?
ember oak
Sure. $5\le d \le 5$
clever fjordBOT
SWR
ember oak
If you insist on it being an interval
ember oak
d=-5 is what you want
odd edgeBOT
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Available help channel!
calm lava
Would anyone be able to do more of a tutoring session over the Delta Method for statistics? I have a couple of problems that I am trying to work out with the notes from class, but I am having a hard time thinking of physical steps to solving the equations.
calm lava
the Last part in the IMPORTANT box are the questions, but I am more wanting an outline as to how to go about solving them. Even if I can get help solving the first one and then I can try the other two on my own... But I have to use the Delta Method to solve them.
thank you
mystic saffron
Would anyone be able to do more of a tutoring session over the Delta Method for ...
yeah i can
odd edgeBOT
@calm lava Has your question been resolved?
odd edgeBOT
odd edgeBOT
Available help channel!
warm gulch
Could someone help me with this dealing with complex numbers? I have the solutions but don't understand the steps.
what are the solutions of: z^3=27
Specficially could you help explain this " We know that the argument of z^3 is 3(theta). since z^3 = 27, we know that its argument is 0"
warm gulch
civic wedge
its the first one
warm gulch
?
zenith tartan
no solution please
odd edgeBOT
odd edgeBOT
Available help channel!
wary notch
hi
wooden python
!15m
odd edgeBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
wooden python
also insufficient info
rigid dragon
I don’t see how it’s insufficient, can’t you just use the lengths to form a right triangle then you can use Pythagorean theorem
rigid dragon
Like view it as a rectangle with a triangle on top
wary notch
Okay
winter cradle
Just assume them to be right angles
wary notch
Just assume them to be right angles
yes
winter cradle
Itll be fine
wary notch
ty
winter cradle
Now apply pythagoras
wary notch
oka