#help-17
1 messages · Page 226 of 1
then idk it depends on the scale
If you only have the character to measure I don’t think it’s possible to get his accurate height
Ill close the channel now
.close
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Hello
🌊
I need help with geometry rq u got me?
What's your doubt
We do not help, we lead
Huh..
🤦♂️
Anyway
Imma lil slow so yea idk understand da question
Idk if u can see dat
Use the properties of circle
Note that one of the circle is smaller
Therefore, AB=BC would be Bullshirt
I put bc=cd is that right
Because one of them is smaller
Sure thing
What is bc and cd in terms of the small circle
Idk if theres another answer tho
Idk
They are all r____s of the small circle
Radius
.close
How i close this 😭
Type .close
.close
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im watching this video and i cant understand why the a0s, a1s, etc. cancel out
chef you can consider it as subtracting
on both sides
like a_1 - a_0 = 4
thus the a_0 cancels out
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20th
hi do you need help on your test
Nah its just the last year paper so
<@&286206848099549185>
sum of odd terms = A1 +A3+A5......
Sum of even terms = A2+A4+A6.....
i didn't understand the question so idk maybe
you just need to substitute what it means to be an arithmetic progression for all the A_i terms
subsititute 2A+1?
yah !
odd?
no. look up what it means for it to be an arithmetic progression
every term should have same commen difference
write a formula for the general A_i term
a+(n-1)d
that's the general nth term. yea plug that in for all the A_n
<@&286206848099549185>

<@&286206848099549185>
<@&286206848099549185>
this is the right start. keep going
,rotate
right?
what do i do after this T_T
calculate things in the problem
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so it will not be differentiable at those values of x, where the function isn't continuous
this ^
i see
can i get some help along with this question so i can further understand?
can someone give me a brief definition of differentiability
the existence of the limit
lim h -> 0 (f(x+h)-f(x))/h
The normal person's explanation for that is: if the graph doesn't jump or randomly change direction in one moment (like |x|) then it's differentiable
i see
thank you the normal person definition helped
so -1 would be a non differentiable right
It's not the most rigorous definition but it's the most reasonable one for this problem imo
Should be yep
is x=4 one as well?
Yep
would there by anymore?
Shouldn't be if I'm not dumb 😭
i got it wrong
Fuck
i got one more attempt
-1 and -6 I would say
Well, at x=4 the function is not even defined
Because it's got a slope of "∞"
but x =-1 and x=4 look the same
The basic idea is we can't really say anything about the rate of change if we just say it's infinite
Indeed, both -1 and 4 are points of non differentiability
so it would be -1,-4,-6?
nice thank you can you help me awith another one
So
Yeah I'm saying they set the interval to exclusively less than 9
ok i got another question
i say x=-4
x=-1
x=7
any others im missing?
nice i got it correct
this might be a hard one
i dont know if vertical asymptoes is non differentiable
i say -3 and 3
agghh hi got it wrong
I forgot the exact rules for these ones
i think its jsut 3
But 1 should also not be differentiable
We technically don't consider holes to be differentiable points, but the limit exists if it's still smooth around it
Should be -3 and 4
@timid ruin Has your question been resolved?
nope
there isnt an answer
-3 and 4 arent continuous
oh i see
Oml wait
4 is a removable discontinuity, and -3 is a vertical asymptote
therefore, you should click the "Remove answer" so that there is no answer
-9 and 9 would still work?
so if it is continous does it mean there will be a differentiability?
Mb
ok it was no solution
you can see that in the interval that is listed, there is no "Greater than and equal to" symbol
good job
Differentiablity needs continuity and some extra conditions
0 -7
x=0 is 1 of the answers
i found 2
are there any more?
can you differentiate a point that is at a corner on a graph?
like
wait hang on
i might be seeing that wrong
only through that range -9 and 9
x=-2 might be non-differentiable, but i could be seeing wrong, you cant differentiate corner points
does horizontal tangent line matter for differentiablility?
This is the problem with these types of questions😔
so hard to tell
im all too familiar with delta math, i can understand
but we can notice this
ok it was those 2
does it have to be a v curve?
any curvature with a corner point is differentiable
like a sharp v curve
it the curve is like a v, or has a sharp, no curve, its not differentiable
if it has the slightest curve, its fine
honestly, only time when lookin at curves so intently is allowed XD
For differentiablility, only the first derivative has to exist
yes deltamath is a little crazy
So... as long as it's not a sudden curve it's fine
do you do your own delta math farside?
i get some assigned (a lot, too much for any human in my class to apparently do in 1 hr)
for some reason, back in calc, my class would have like 2 people, including me, who would do the delta math in like 1 minute, while everyone would still do it for like a week
idk why
regardless, i assume the issue is resolved?
you are chosen one
feels like that XD
alr drop em
Bro might be gojo
what are your study methods any way farside for calc
i dont study :|
i dont know how to study
and im yet to get anything lower than A '-'
this is a correct hypothesis
yup i think your just the chosen one
I've had that streak and I'm hoping my actual Calc class doesn't ruin that
I've been self study fr now
AP calc AB?
i self study then i see the test and im lik ewow
bc the teacher I had for AB was...interesting
College lvl
i learned more from milk cartons than him
i am taking bc
i dont know how i am gonna manage
you'll manage
the test kill me
oof
i think you have a photographic memory mabye
ok this is the last part of the section
i am thinking these are corrects
oooooh boi
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C(-2) = A(-2)*B(-2) = 1*9, etc
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Draw a pre-image polygon with vertices A(-2,5) B(-1,1) C(3,3) D(2,7). Translate the pre-image using the vector 〈-2,3〉 to create the polygon A'B'C'D'. Change the color of the image and show the coordinates of each vertex.
Is this correct?
Looks like it
@tacit hawk Has your question been resolved?
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How can I demonstrate that all natural powers of 2 are NOT divisible between 3?
for example 2/3 is not integer
4/3 is not integer
8/3
16/3...
I have tried for 2^35 and all of them are not divisible by 3
Prove
lol
Literally I was messing around with random thoughts and then I got stuck with this problem in my mind
idk, lemme do something in python. I will thy with very very bigi numbers
Maybe I can find a case when this is not true in a small number. (Small like 2^100 lol)
since 2/3 = 0.66... raising the 2 by any integer power x would result in 0.66... being multiplied by 2^x.
log3(2) is irrational so no matter what do you multiply it by, you won't get a integer
since 0.66... x 2 = 1.33.. and 0.66... x 2 x 2 = 2.66... and 0.66... x 2 x 2 x 2 = 5.33... and so on, you will see every number that is 0.66... x 2^x end with either a .33... or a 0.66... without ever changing therefore they will all not be divisible by 3.
thanks
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I need help
printing error or typo
Ok thx
ask ur teacher about it
np
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Hello! I am confused about how 5 is less than and equal to 9, I understand that 5 is less than to 9, but not the equal part. The second one, im not sure how 5 is greater than 5 itself.
≤ doesnt mean less than AND equal to
it means less than OR equal to
so if either is true, it satisfies
I see now, thank you very much!!!
yw
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Can someone let me know if I solved part A correctly pretty please
no, f(g(2)) is not equal to 0.5.
g(2) = 2
plug that back in to f(x) to get f(2)
so you just have to look at the graph to see what f(2) is
@desert spindle Has your question been resolved?
Oh, so f(g(2)) would be 4?
yes
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nvm…
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what have you tried
Apply a²-b² formula
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Show me all the steps
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
Can you tell me what method I use to to start?
Is it the quotient rule, product rule?
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Hey, I need help to transform intersection 3d point to 2d uv point
I made this code looking at other formulas ```lua
function lineIntersectsPlane(lineStart, lineEnd, planePosition, planeSize, planeNormal)
local lineDirection = lineEnd - lineStart
local planeToPoint = planePosition - lineStart
local denominator = planeNormal:dot(lineDirection)
-- Check if the line and plane are not parallel
if math.abs(denominator) > 0.0001 then
local t = planeToPoint:dot(planeNormal) / denominator
-- Check if the intersection point is within the bounds of the line segment
if t >= 0 and t <= 1 then
local intersectionPoint = lineStart + lineDirection * t
-- Check if the intersection point is within the bounds of the plane
local halfSize = planeSize / 2
local minBound = planePosition - halfSize
local maxBound = planePosition + halfSize
if intersectionPoint.x >= minBound.x and intersectionPoint.x <= maxBound.x and
intersectionPoint.y >= minBound.y and intersectionPoint.y <= maxBound.y and
intersectionPoint.z >= minBound.z and intersectionPoint.z <= maxBound.z then
-- return 0-1 x and y coordinates of the intersection point
return (intersectionPoint - minBound) / planeSize
end
end
end
return false
end```
it works great
but now I need to know where exactly did user hover on the plane
like top left should be 0,0, top right 1, 0 bottom right 1, 1
I tried looking for solution on google but I cant find anything, only some not related formulas
@shadow orchid Has your question been resolved?
@shadow orchid Has your question been resolved?
You are gonna want some vectors u, v in the plane to be used as basis
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How many four-digit numbers contain the digit 5 or 7 (or both)?
(also give me a solution, i am stuck on this question, srry for bad english)
What have you tried?
do you mean 5, 7 and both ?
what a coincidence
Lmao
lemme see if I can solve it tho
yeah it can't be just a case
I am guessing it's combination permutations sum
ya perm since order matters
I did this last semester and forgot it all lmao
Yea
I can guide you little bit
Try to find out the 4 digit number can exist
okay i got it
i.e.
9999-0999=>9000 (total number of only 4 digit numbers)
so first there 9000 different 4 digit numbers
9 x 10 x 10 x 10 (In each place it would be 10 different options - digits - but the first digit cannot be 0 as it wouldnt be a 4 digit number anymore so it becomes 9 options.)
then you find how many numbers do NOT contain 5, 7, or both bc it's quicker than doing it the other way around
10 digits - 5 and 7 is then 8 digits.
so your combinations looks like
7 (remember the first number cant be 0 so we get 7) x 8 x 8 x 8
you get 3584
now 9000 - 3584 is 5416
yea
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I’m not sure what the union of these two sets would look like exactly
Well
I understand it would be 6, 7 and all reals such that x > 7 however I’m not sure how to write this in set notation
Ari
Number line
or ${6} \cup {x \in \mathbb{R} | x \geq 7}$
Would it not be the set that contains the number 6 or is just writing 6 sufficient?
But regardless thank you for your help
Ari

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Need help on question 3
Please don't occupy multiple help channels.
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I need some help.
How can I find the area of this triangle?
1/2 * h * g
but I know about the angles and the sides, but not the height itself
do you know trigonometry?
there is also a formula called Heron's formula which just uses the side lengths
You can also use 1/2 . (Cos of the angle)(Other 2 sides)
Yess?
Yes, so from RS the length = 2.30 and the angle at the very bottom is 81.4 degrees
I don't know about that theory. It must be done with sine, cosine, tan...
SP is = 3
This is sin not cos mb
Oh
that is not enough to constrain the triangle, you need more info
yea
look up the cosine law
What are we missing?
I didn't see that you had SP as well
I have calculated the angles and sides.
all of them?
Yess but how
wich formula?
Maybe this can be used idk if you have been taught this tho
6?
It's b ;-;
Idk if you have been taught this but yea you can if you want
,tex .sohcahtoa
hayley 🥥 🌴
So I have to reverse the triangle?
because if I turn the triangle over, it's a right-angled triangle, isn't it?
figure out the length of the purple line
ahh
so I can use either tan, sin or cos
should I use Pythagoras' theorem?
.
So what will the formula be? Am a bit confused. @mild flower
So if the length for PS normal was 2.30, can just halve it?
<@&286206848099549185>
I have the angles from the triangle, but I can only find half of each number from the isosceles triangle.
@quick vigil
Huh
What can't you understand?
@long kraken Has your question been resolved?
which question do you have
.
HELP pls
I can't solve the formula because it gives me the wrong result.
@mild flower
help me
We need to use the tangent, since we need to find both legs, unless it is the other way around.
Come on, only this task is missing.
I found out, so the length of the purple line is 1,75 cm?
@long kraken Has your question been resolved?
@long kraken Has your question been resolved?
@long kraken Has your question been resolved?
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hi
There's a tan, and an inverse sec 
yes
tan(cos(5/3))
not sure how to proceed using 5/3 as an angle measure without a calc
(calc is short for calculator btw)
Not quite, I don't think
the notation sec^{-1} usually means inverse sec, which is not 1/sec
sec inverse x is cos inverse 1/x
No, it's not (or at least, it usually isn't!)
Anyways, can you think of a way to relate tan and sec, maybe?
ngl i'd just draw up a right-angled triangle, letting theta=sec^(-1)(5/3)
just use this it will convert to a easier form, or you can do what chartbit said
i can rewrite it the sec part as sec(theta)=5/3. draw the triangle and get that 4 is the missing leg. so then tan of that triangle would be 4/3 yea
i got tripped up bc i remember doing trig proofs and sec^-1 i would always just reciprical
close.
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I dont understand how it can go straight from positive and increasing to negative and increasing
so there is a break in the line from 1 to 3?
if you were to graph
yea where it drops
from positive to negative
what about 3<x<4
hm
so from 3<x<4 I guess it would be concve down and decreasing
thats one funky graph
yeaaaaa
😔
alrighty
thanks!!
how do it
oh
sorry
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xsquare + ysquare = 25
how can I get x and y
now I have 2 diferent equations with x and y isolated. What's next?
Do you have more info then that?
Find all the pairs of integers that solve: xsquare + ysquare = 25
is x2 + y2 "factorizable"
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hey i'm new here maybe u guys help me a lot
i need help too lool
i'm a jee aspirant and ?
!occupied
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this is easy question btw
what is jee aspirant 😭
can I say I am mit aspirant
ye its pretty easy, im js confused where 85 seconds would be
like on the line
its used for student who prepare for IIT
i know how to solve how can i tell u ??/
just in between 80 and 90, but whoever solved it just approximated
Does this mean I am a top college aspirant too then
Its an exam through which you can get admission in top engineering college in India
ah
so no 1/2 or wtv?
yup
maybe
Dawg its not that deep its a help channel just help him and then close smh😭
-4/2 ½ m/s?
u fr ain’t a jee aspirant
Frfr
ya i aint 😭
no like you notice that the slope of a displacement graph is equal to the velocity
let me solve the question but how will i send the answer
and the graph is a straight line from 60s to 100s
you dont
i put -4 for the rise since it's a negative slope
Whatever I think ur just overthink ing
is this calc?
physics class
yeah im def overthinking ig
From 60 to 85?
🤦
The rise is -4 1/2 from 60 to 85 right
.
😭🙏🙏🙏
simplified would be 1.8 m/s tho right
Which one, 60-85?
yeah
But yeah its -1.8
Np bro
.close
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all here are high school students like me ??
.reopen
✅
wait lowkey
FOR NUMBER 2
IS IT 4/10 OR 5/11
Im lowkey losing brain cells at 1 am
😦
Where section
did you see what the y units are
i
He means that the y is in cm
y units should be cm
oh
shjfbdhsjfbdjs
i almost screwed up units
doing this at night is a bad idea ngl
next time i ask for help ill do it at a reasonable time so you dont struggle with my stupidity 🙏
probably
Is section 2, 4/10 cm/s or 5/11 cm/s?
stupid question its 4/10 cm/s
🙏
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I would try the u sub u = x+2
I don't immediately see that working
And then power rules of integration will work it out
i get (u-2)^2 (u)^1/2
oh yes
I see the vision
Yep now expand
am i stupid isnt this wolfalph's font?
yes LMFAO
wtf
fair
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can someone pls explain how derivative of the top part is the lower part
apply product rule
Oh yeah
distribute as in
multiply the P^9 to P+1
youre welcone
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Is there any other way to solve this question other than a long method of
using this proof
???
who is you
yea it's aight
did you try finding an f(x) and g(x) to use this
I always be looking at the same problems as u 😦
feel free to take over
g(x) will remain x^2+x and I'll have to find how to rewrite the the terms inside bracket I remember getting it this way but don't remember the splitting
hence is there a better method?
I dont see a better way either
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how can I implicit differentiation to find dy/dx?
just differentiate like how you normally would, but you need chain and product rule for the left side
Is this correct?
I did
i didn't got u. What mistake did I made?
it was supposed to be 2y
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how do i solve this?
what does solution to the inequality mean
Split in two cases where 6u-18 is +ve and -ve
whats +ve and -ve
The values of u where the inequality is true
Positive and negative
what does inequality mean
The thing on top you are meant to solve
Hollow is strictly less than or strictly greater than (<,>)
Filled is for less than or equal to, greater than or equal to(≤,≥)
is this right? u<1. - u>5
and if so can you give me pointers on how to draw it?
the line confuses me too
Lemme check
thx
the line says interval
Can you be a bit clearer
so i have to use two dots
and then i can click on the line
to mark the interval between
so i need to use the hollow dots right?
Yes
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What did you try?
I tried distributing the n at the start and multiplying Everyhting
maybe induction works
Ok, this is not how you do it here
There is a shorter way
Have you learn modulos?
No
Ok, it doesn't really matter but ok
There are 3 possible cases
Either n = 3k, for some integer
Either n = 3k + 1, for some integer k
Either n = 3k + 2 for some integer k
In any cases, exactly one of these 3 terms in the product will be divisible by 3
I let you think about it
Where did you get ‘k’
Oh
i dont know if this is easier, but either n, n + 1 or n + 2 is a multiple of 3, you could see what happens in each case
0, 3, 6, 9, 12, 15, ..... are such that n = 3k
1, 4, 7, 10, 13, 16, ..... are such that n = 3k + 1
2, 5, 8, 11, 14, 17, ..... are such that n = 3k + 2
Well I was told that the problem is always divisible by 3
I just need to prove it
I just don’t know how to correctly write it out
if n is not 3k, then it must be 3k+1 or 3k+2
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I'm stuck on part B
So far the only reason ive been able to come up with is that its because there would be a negative area, if ad<bc and the formula used was ad-bc. But I'm getting confused by the hint the question gives and im unsure as to whether im on the right track or not
@fickle apex Has your question been resolved?
<@&286206848099549185>
@fickle apex Has your question been resolved?
<@&286206848099549185>
@fickle apex Has your question been resolved?
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Hey there! I think I understand/identified what was asked (this is statistics), but I wanted someone to check over my answers just to make sure they're right.
1.1 Definitions of Statistics, Probability, and Key Terms
For each of the following eight exercises, identify: a. the population, b. the sample, c. the parameter, d. the statistic,
e. the variable, and f. the data. Give examples where appropriate.
- A fitness center is interested in the mean amount of time a client exercises in the center each week
what i answered:
a. all the clients in the center
b. the amount of clients in the center
c. average amount of time a client exercises in the center each week
d. average amount of time the clients spends exercising
at the center
e. amount of time one client spent
on exercising in the center each week
f. time spent by clients exercising
<@&268886789983436800>
<@&268886789983436800>
Ty
Ty
@exotic trout Has your question been resolved?
I'm not sure my answer is correct, I jus want someone to go over it to see if anythings wrong and how I can fix it
<@&286206848099549185> 
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helo
what math are you in
algebra 2
and what are you trying to find
the domain
homegirl.
alright well what is something you can never divide by?
0?
yes
so if you set the bottom to 0 what does that give you
the heck are you doing lol
/calc
undefined?
,calc 0/0
Result:
NaN
yep, which means where the function is undefined
that means if you solve for y in: sqrt(y - 10) = 0
Idk I haven't done math in 3 years
but the function cannot be undefined.
you will get where the domain is undefined
were finding the difference.
huh
i dont get it
f(x) = (x+h) - f(x) / h
sqrt(y - 10) = 0 would become y = 100?
dont get me or dont get nate
i dont get you
well no because you need to get rid of the square root first
if you square everything you shouldve gotten y -10 = 0
im lost
which would be y = 10
this means that the function at 10 or under
im asking for help 2
were trying to solve the same problemo
oh
so
sorry i meant 10 or under*
which means the function is undefined between negative infinity and 10
this leaves what as the domain of the function?
10?
but the lim is h > 0
where are you getting h from lol
no
you just solved the equation
you found that 10 or under is where the function is UNDEFINED
okay
yep
so the domain of the function is where y is above 10
man im gonna be honest i have no idea what youre trying to ask me right now
go ahead
then solve the problem if youre so smartie
i just did
hold on
i think youre getting confused rn, tony is the one that i am helping
tony's problem was asking for domain
i helped tony solve for domain
then what are you guys trying to solve for
cant really just give me a function and not give me what to solve for
.-.
thats what i was talking abt
ic
alright well
just find f(2+h) by plugging in (2+h) into f(x) first
then find f(2)
then subtract
then divide by h
i dont get it
okay
okay
so
so after that?
after that
the opp is always true