#help-17

1 messages · Page 162 of 1

vocal sleetBOT
gentle umbra
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i can have a cheat sheet filled with this kind of stuff but once the variation changes (ie. asks for water in a cylinder or something) i will completely blank out

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so i want to know how to generalize all of these types of problems into one formula hopefully…

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like 3d work problems

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what should i look for that is the same for all variations?

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vocal sleetBOT
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@gentle umbra Has your question been resolved?

vocal sleetBOT
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@gentle umbra Has your question been resolved?

edgy sapphire
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yea the thing about pyramids/cones is that the area is scaling linearly from the point to the base

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here it goes from 0 (point) to a side of 100 over a height of 0-60, so the side length formula is (100/60)*y

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volume is area*height though so you need the area of that changing square, so (100y/60)^2, plus you multiply by the density for the weight

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for cones it's the same but you want the radius which is like that 50 you found, then pi*r^2

vocal sleetBOT
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@gentle umbra Has your question been resolved?

gentle umbra
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i got started a little bit on it but got stuck after setting the ratios up

edgy sapphire
vocal sleetBOT
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@gentle umbra Has your question been resolved?

vocal sleetBOT
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vital loom
vocal sleetBOT
vital loom
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How did 143.13 become negative

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is it not 180 plus or minus theta

vocal sleetBOT
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late reef
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Hello

vocal sleetBOT
late reef
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How am I supposed to know if the function is wide or narrow? , the function is:

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a +(x + p)² +k

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The a affects whether it will be narrow or wide, but how will I know?

fervent wasp
late reef
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Lets say its 2.

fervent wasp
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The greater |a| is, the narrower it is

late reef
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And if its -1 its upside down ?

fervent wasp
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yep

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If a<0 it faces down

late reef
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Ok thx let mr chek it

fervent wasp
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If a>0, it faces upward

vocal sleetBOT
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@late reef Has your question been resolved?

vocal sleetBOT
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finite hatch
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how come

vocal sleetBOT
finite hatch
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they get this

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173 MeV

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i though to get to MeV u need to multiply the eV by 10^8

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so its 1.73 x 10^18

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oh

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um.

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bye guys

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vocal sleetBOT
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vocal sleetBOT
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neon kernel
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Given are the common densety functions of the 'accidental' variables X and Y:
Consider following statements:

neon kernel
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how many are correct

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Does anyone know how to find the last one

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I think it would be Pi/4

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als = if and elders = elsewhere

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found it

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vocal sleetBOT
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vocal sleetBOT
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quartz beacon
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would this question: Denote in the complex plane all the numbers z = a + bi for which Im(conjugated of z)² = 1, be equal to y=-1/2x?

vocal sleetBOT
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@quartz beacon Has your question been resolved?

vocal sleetBOT
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@quartz beacon Has your question been resolved?

vocal sleetBOT
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@quartz beacon Has your question been resolved?

sharp perch
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xy = -1/2

quartz beacon
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what am i supposed to do w the a+bi

sharp perch
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Im((a - bi)²) = -2ab = 1

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But you considered x and y

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Doesn't matter really

quartz beacon
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vocal sleetBOT
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vocal sleetBOT
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thick vessel
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I understand how to find key features when graphing rational functions, however I do not understand certain problems when they are in this format

thick vessel
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Should I divide first?

mental falcon
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remember that division by a fraction you can treat as multiplication by the reciprocal

thick vessel
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Also I wondering if for all problems like this I should put both the numerator and denom in factored form

mental falcon
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so you can rewrite it as $\frac{(x^2-4x)(x+4)}{(4x-8)(x+2)}$

twin meteorBOT
thick vessel
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From there I would distribute straight across right?

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For both numerator and denom

mental falcon
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well i mean if you're trying to find key features

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why? it's easier to work with a factored form

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or what would be your purpose in distributing exactly?

thick vessel
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Nevermind you're right.

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Thank you

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vocal sleetBOT
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vocal sleetBOT
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fast imp
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really struggling with this, i honestly have no idea where to even begin

fast imp
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i guess i could try like doing something in base 99 but i dont think thats it

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or no it would be base 100

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and i still dont think that would work

hollow raptor
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Choose primes, you'll be given a linear combination so you can factorize it and get the unknowns

inner osprey
inner osprey
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there aren't any restrictions on the numbers Berris can name

fast imp
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i think base like 200 might actually do something

hollow raptor
inner osprey
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it doesn't matter integer or not

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the fact that Harris can only use secret 2-digit numbers is already extremely restrictive

fast imp
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its assumed to be across the integers, this is a number theory book

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id be very surprised it it wasnt across the integers

inner osprey
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that's fine but my point is this problem need not be confined to the integers as it does not heavily affect the solving process

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you can solve it using integers as a restriction if you wish

fast imp
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well i cant solve it, thats why im asking for help lol

crimson shell
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The base for expansion of abc would be 100 as a, b and c are 2 digit numbers

fast imp
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since any integer that large has tons of ways of making it from adding 3 smaller numbers

hard atlas
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make up three numbers x,y,z. and then tell me 10000x+100y+z

fast imp
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oh shit wait

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ive gotta sketch this out

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but like

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wait no it might work

hollow raptor
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The two digit restriction is what makes it work

hard atlas
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you are overthinking probably

hard atlas
crimson shell
fast imp
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so like the idea is to pick the numbers 10000, 100, and 1, and then berris converts the number harris gives to base 100?

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or something like that

hard atlas
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you dont specifically need to frame this in terms of base 100

fast imp
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oh true it does work in base 10

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woah

hard atlas
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you can already read off the numbers from the result

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base 100 is just base 10 but two digits at the same time

fast imp
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wow that was an amazing problem

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thank you guys

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vocal sleetBOT
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vocal sleetBOT
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lyric raptor
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Let $f$ be a function from a finite set $A$ to itself. Prove that $f$ is injective if and only if $f$ is surjective. Does this remain true if the finiteness assumption on $A$ is dropped?

I understand why this must be true. in the direction injectivity implies surjectivity:

Assume the function is not surjective. This means $|f(A)| < |A|$.

The codomain and domain are the same set, so $| \text{codom} f | = |A|$. Since injectivity implies that $|f(A)| \ge |A|$ and $f(A) \subseteq A$, we know $|f(A)| \le |A|$. Consequently, $|f(A)| = |A|$. This contradicts with $|f(A)| < |A|$, and thus $f$ must be surjective.

I qualitativly understand the reverse, but am even less sure how to write it out.

Is my reaosning ocrrect, and how can I turn it into a proof? Thanks!!

twin meteorBOT
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Nameless

vocal sleetBOT
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@lyric raptor Has your question been resolved?

vocal sleetBOT
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@lyric raptor Has your question been resolved?

lyric raptor
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<@&286206848099549185>

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quasi roost
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Discrete Math

Q: Prove A ∩ (B ⊕ C) = (A ∩ B) ⊕ (A ∩ C)

I showed my work so far, but I've hit a wall since adding X and Y back in doesn't lead to what I'm looking for

quasi roost
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This was my first answer but I'm not sure if this would be valid as it seems too simple for the assignment

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Ping me if you reply to the message

edgy gulch
quasi roost
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Alright I'll try that

quasi roost
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Since it proves the right side is false, however the left side may still be true or false, not sure how I could do that

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unless 1 side being false means the entire statement is false

edgy gulch
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lemme see

edgy gulch
quasi roost
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Oh wait I saw it wrong, in my head I saw that it would need A and A^c to be true which would always be false i read that really wrong woops

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even then I'm till kind of lost what to do after the last line and what law I could apply

edgy gulch
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its gonna be a lot of distributive laws

quasi roost
edgy gulch
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hmm i would have to think about that

quasi roost
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ok and you're sure distributive laws is the only way to go about this cause looking at it, it looks like its gonna get super messy idk

edgy gulch
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yes it will get super messy

quasi roost
edgy gulch
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but trust me it'll simplify nicely

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but for now yeah its gonna be hell

quasi roost
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@edgy gulch how do I know which way to distribute it? Or it doesn't matter

edgy gulch
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and distribute it that way

quasi roost
edgy gulch
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yeah

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gosh i hate using set operations to do boolean algebra

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using addition as OR and multiplication as AND is so much easier to keep track of stuff

vocal sleetBOT
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@quasi roost Has your question been resolved?

quasi roost
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@edgy gulch i've been staring at this for awhile im mad confused, i could do distribution again but at that point there is no way i'll even see how it'd simplify

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i did notice that these have to cancel out and be forced as false though, unless im reading that wrong

edgy gulch
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yes indeed

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so you can just get rid of them

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since they'll just be empty sets

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then what you have left is (A∩B∩C') ∪ (A∩C∩B')

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reverse the distribution law

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A∩((B∩C') ∪ (B'∩C))

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A∩(B⊕C)

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and boom we done

quasi roost
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o ok thank you im just gonna write it all out with the laws i used, have you been doing discrete math for awhile?

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at what point can u just look at something and know how to do it

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cause every new question i look at i just get so confused

edgy gulch
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i mean i completed one semester of it

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ill try to help if i know how

quasi roost
edgy gulch
quasi roost
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I have 1 more question, I got this answer for another set problem with my work already shown, does this look alright or did I miss something midway

edgy gulch
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yeah looks good

quasi roost
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.close

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vocal sleetBOT
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fathom hedge
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doing comp sci, trying to understand union find, not understanding dot points 3 and 4

fathom hedge
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why is it log_2(2k)

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i cant intuit it at all

vocal sleetBOT
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@fathom hedge Has your question been resolved?

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@fathom hedge Has your question been resolved?

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finite hatch
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i dont get question b

vocal sleetBOT
vocal sleetBOT
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@finite hatch Has your question been resolved?

scenic ravine
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If the two decks are shuffled together

scenic ravine
finite hatch
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idk

scenic ravine
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you have two decks

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how many cards is that

finite hatch
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104

scenic ravine
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ok, in how many ways can you arrange 104 cards

finite hatch
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uh

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104!

scenic ravine
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remember , so cards are repeated

finite hatch
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o

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wat?

scenic ravine
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some cards

finite hatch
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whatcards

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2 of each?

scenic ravine
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yes

finite hatch
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104!/2!?

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wait ok i skipped that one

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how does the n! turn into an n

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in the third line

ionic owl
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Try writing out n * (n-1)! and n!

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How are they related?

finite hatch
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n! = nx(n-1)x(n-2)...

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n!=n x (n-1)!

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oh

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ok

vocal sleetBOT
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@finite hatch Has your question been resolved?

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orchid pier
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Is this worked out correctly?

vocal sleetBOT
orchid pier
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.rotate

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,rotate

twin meteorBOT
orchid pier
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in the solutions they used comparison test but is my method correct aswel?

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or does 6^n / 3^n +4^n not equal (6/3+4)^n

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karmic oar
#

can someone give me a trick to remeber the radians of the unit circle(I have memorised the angles(convert them from radians) as well as the coordinates)

wraith python
karmic oar
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k lemme check

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this does not answer my querstion

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I am asking how to memorize the pi/6, pi/4, pi/3, pi/2 so and so forth

wraith python
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You're only interested in memorizing the radian measure?

karmic oar
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yes

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the rest ik

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lol

wraith python
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What are you trying to understand about radian measures? That will help me explain whatever it is you are trying to learn.

karmic oar
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how do I memorize it

wraith python
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Just the values themselves? Their relation to degrees? Their position on a unit circle?

karmic oar
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the vals themeself

wraith python
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,calc pi/2

twin meteorBOT
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Result:

1.5707963267949
karmic oar
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okay...

wraith python
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So the numerical values?

karmic oar
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no just the radians

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like pi/2 etc..

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and whatever comes after it

wraith python
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You named all of the important radians aside from pi and 2pi.

karmic oar
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pi is 180

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2pi is 360

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pi/2 is 90

wraith python
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After that, it's really just learning how to apply them to reference angles.

karmic oar
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I get those but what about everything else

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this

wraith python
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7pi/6 is just 7pi/6 - pi = pi/6. From there, you can see that the difference in values are just negative signs from pi/6.

karmic oar
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I am confused man

wraith python
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One moment, let me make a graph.

karmic oar
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okay

wraith python
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You should read about reference angles.
https://www.cuemath.com/geometry/reference-angle/

A reference angle is an acute angle enclosed between the terminal arm and the x-axis. It is always positive and less than or equal to 90 degrees. Let us learn more about the reference angle in this article.

karmic oar
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ik what ref angles are

wraith python
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So what's the problem?

karmic oar
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i dont know how to remmevber the unit circle radians

wraith python
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Like 7pi/6 or 3pi/2?

karmic oar
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YES

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like how to memeorize all of them

wraith python
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You don't need to remember every single radian in a unit circle. Just do the conversion as needed to pi/2, pi/3, pi/4, or pi/6 as needed.

karmic oar
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the pi/6, pi/4, pi/3, pi/2, 2pi/3, 3pi/4, 5pi/6, pi, 7pi/6, 5pi/4, 4pi/3, 3pi/2, 5pi/3, 7pi/4, 11pi/6, 0

wraith python
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After that, it's just a matter of remembering the signage.

karmic oar
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how to memorize what I said above

wraith python
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Well one group of them is just continuously adding pi/4.

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pi/4, pi/2, 3pi/4, ...

karmic oar
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My mind is not working rn

wraith python
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The other is just adding pi/6.

karmic oar
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ic the pattern for quad 1 and quad 2 its for the denomitoers: 6, 4, 3, 2, then for quad 2 its 2, 3, 4, 6

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but the numerator tho

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wait

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for quad 2 5pi/6 becomes 7pi/6

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its 2pi increment for numerator

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and that applies to all

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so all I have to do is memeorize quad 1 and not 2

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then I got the rest

wraith python
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In 2Q, just add pi/2.

karmic oar
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and the sign chamghe is self explantaroy

wraith python
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In 3Q just add pi

karmic oar
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oh wait

wraith python
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In 4Q, add 3pi/2.

karmic oar
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I AM ENLIGHTNED

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thanks man

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have a good one

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tawny shadow
#

if you can find the perpendicular line of a linear function by finding the negative reciprocal of the gradient then how do you find the perpendicular line of a quadratic function?

tawny shadow
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y = mx +c , m is the gradient and a perpendicular line would be y = -(1/m)+c

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wait what

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m = gradient

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i have no idea

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uhhh

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.close

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quasi roost
#

Discrete Math

Q If g : A → B is surjective and f : B → C is injective, then g ◦ f is surjective

Showed my work so far, but I'm confused on how to prove g ◦ f is surjective or if I missed a step in between, hit a wall

vocal sleetBOT
#

Please don't occupy multiple help channels.

quasi roost
#

ping me if you reply to this please

vocal sleetBOT
#

@quasi roost Has your question been resolved?

quasi roost
#

made it more clear

safe sable
# quasi roost made it more clear

Surjective does not mean that two different values in the domain map to the same value in the codomain, it means that each value in the codomain has an element in the domain that maps to it

quasi roost
safe sable
#

Oh, is the question asking you to just find an example of functions satisfying that property?

#

Or to prove it is true for all functions f,g satisfying the assumptions?

safe sable
#

Ah okay. So do you think it is true or false?

#

It's not clear if you're trying to prove or disprove it

quasi roost
safe sable
#

Got it. To prove something is true, you can't just use an example, you actually need to show that the conclusion follows from the assumptions. To disprove something, you can just use a counterexample

#

Also, I think it should be f ○ g, not g ○ f

quasi roost
safe sable
#

I mean, the codomain of f is C, but g takes A as it's domain, so g ○ f isn't well defined

#

Unless the notation they're using is supposed to be read left to right, not right to left, which is quite uncommon but not unheard of

#

In any case, g is first, then f, for it to make sense

quasi roost
quasi roost
quasi roost
#

for now i have it like this

vocal sleetBOT
#

@quasi roost Has your question been resolved?

vocal sleetBOT
#

@quasi roost Has your question been resolved?

quasi roost
#

.cllose

#

.close

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queen crest
vocal sleetBOT
queen crest
#

Could I get some help w/ #19?

#

This is what I’ve done so far

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@queen crest Has your question been resolved?

vocal sleetBOT
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@queen crest Has your question been resolved?

edgy gulch
queen crest
#

Yeah, I did

edgy gulch
#

then find the intersection points between them

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novel wedge
vocal sleetBOT
novel wedge
#

How do I do this

regal bane
#

Note that x is the upper limit of that integral. What happens to that integral as x approaches 0?

#

Keeping in mind the lower limit is 0, ofc.

novel wedge
#

Area is 0

#

Cause ur just taking integral of 0 to 0

regal bane
#

Right. The numerator approaches 0 here.

novel wedge
#

Yea

#

So 0/0?

regal bane
#

Yeah exactly

#

L'h applies here

novel wedge
#

How would I do that tho

regal bane
#

Know the first fundamental theorem of calculus?

#

It applies very directly here

novel wedge
#

I forgot it

#

Is it like g’(x) = the integral

#

If bound is x?

vocal sleetBOT
#

@novel wedge Has your question been resolved?

raven owl
novel wedge
twin meteorBOT
#

Sora Harewataru

raven owl
#

I mistyped

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raven owl
#

the good thing about ftc2 is u dont have to find the antiderivative

novel wedge
#

Wait but if I wanted to find the anti derivative

#

How would I do that?

novel wedge
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novel wedge
#

Hi

vocal sleetBOT
raven owl
#

that is when you will use ftc2

novel wedge
#

Oh alr

raven owl
#

because derivatives and integrals are like inverses they cancel nicely

novel wedge
#

And derivative of integral cancels out bc it’s just derivative of anti derivative rigjt

#

Yea

raven owl
#

yeah thats even better

novel wedge
#

Would the answer then be 0?

#

Wait no undefined

raven owl
#

Looks like it has an answer. You might need to do L'Hopital multiple times

#

and its not 0

novel wedge
#

but i got up to

#

cos(0)*6(0) -cos(0) / 24(0) which is 1/0

raven owl
#

did you remember to chain rule sin(3x^2)

#

first L'Hopital gets sin(3x^2)-sin(0)=sin(3x^2) in numerator

novel wedge
#

Yeah

#

oh sin(0) is a constant i forgot

#

wait but then it would be 0

raven owl
#

sin(3(0)^2)=sin(0)=0

novel wedge
#

i thought sin(0) was 0

raven owl
#

Yeah lol idk I said that

#

so we have 0/0

novel wedge
raven owl
#

yeah

novel wedge
#

ok and then after hospitaling it again

#

cos(3x^2) * 6x / 24?

raven owl
#

I think you should have 24x in the denominator at this point

#

let me double check

novel wedge
#

oh yeah i meant 24x sorry

raven owl
#

yeah

#

then 1 more time

novel wedge
#

Or can i jus

#

cancel out the x's?

raven owl
#

Oh yeah that might work

novel wedge
#

Cause if i hospital one more time id get 0

raven owl
novel wedge
#

so i get 1/4

raven owl
#

yeah

novel wedge
raven owl
#

yeah it still gives 1/4

novel wedge
#

Wait how

raven owl
#

you get like 6*sin(3x^2)-6xcos(3x^2)/24 = 6-0/24 = 1/4

novel wedge
#

Oh my days

raven owl
#

maybe sin and cos are switched

novel wedge
#

i forgot abt the product rule

raven owl
#

yeah

novel wedge
#

Okok that makes alot more sense

#

Thanks

raven owl
#

np

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#

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mental falcon
#

$\lim_{x\to0}(\csc^2-x^{-2})$

vocal sleetBOT
twin meteorBOT
mental falcon
#

to do this limit, i wrote it as 1/sin^2 - 1/x^2 then found a common denominator, then it became indeterminate form 0/0 then had to apply lhopitals like 4 times until it finally worked out, which was rather painful and long, is there an easier way to do this limit?

dawn kestrel
#

Unfortunately I don’t think so

#

Sometimes just have to grind out a bit of lhopitals

#

There might be something slightly easier by playing around with the common denominator and maybe some trig identities, but it’s negligible I assume

mental falcon
#

ok thank you

#

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cinder mulch
#

Find the value of the expression 20x^2y^4, if 4xy^2 = - 6

drifting terrace
#

try squaring both sides of 4xy^2=-6

cinder mulch
sullen notch
#

try change of variables xy^2 = a in both expressions

wide sundial
#

4xy^2 = -6 so xy^2 = -6/4

cinder mulch
#

ohhh... i understood

#

.close

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mild raven
vocal sleetBOT
mild raven
#

ok

#

this seems silly

#

this is a calc 2 problem

#

but for some reason im having trouble taking the derivative of that y =

#

its not nessecairly that i cannot do it

#

I have the derivative

#

but simplifying it to a point where when i use SA formula

#

im getting tripped up on the part where i Use the property sqrt a * sqrt b to simplify the integrand

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timid leaf
vocal sleetBOT
timid leaf
#

take 2!

#

hows it lookin

#

not sure about the bottom half tbh, ai kind of spoonfed

worthy citrus
#

yep looks good, your work before the first bold line is not needed as they just want you to verify they are inverse to each other which is what the rest of your work does

timid leaf
#

yeah, it was just part of my process lol

#

thanks!

#

.close

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native heath
#

Proof by induction

vocal sleetBOT
#

@native heath Has your question been resolved?

native heath
#

<@&286206848099549185>

obsidian vigil
#

For sum of squares and sum of a variable

native heath
#

Im trying to solve it but im having problems with both sides of the equation when im solving for n=k+1

obsidian vigil
#

Can I see your work?

native heath
#

idk what to add on which side and the sigma notation is just messing me up

native heath
#

I tried removing the sigma notation to make it easier

#

But i just dont get it, ive watched a thousands of videos and AI couldnt explain it properly

obsidian vigil
#

Do you know the standard formulas for the sigma notation

#

We learn this here with Sigma notation idk bout u

native heath
#

No ive never seen smth like this

#

I mean i know what sigma is

#

i understand what it is but when using it in induction its just making things complicated

ruby vapor
# native heath

When you have k^2(k+1)+(3k+2)(k+1), factor out the (k+1) to get (k+1)(k^3+3k+2) and it's easier to work with

native heath
#

I never factored anything before

#

so im pretty lost in factoring

#

Can you solve it and show me your work? Maybe that will help me somehow

ruby vapor
# native heath Can you solve it and show me your work? Maybe that will help me somehow

Not having factored anything before will make problems like this a lot harder. There's only one more step to go after I wrote, but here it is: $k^2(k+1)+(3k+2)(k+1)=(k+1)(k^2+3k+2)=(k+1)(k+1)(k+2)=(k+1)^2(k+2)$ You're allowed to factor out a (k+1) the exact same way you can factor out a 2 (for example) if all the terms have a 2. When you get $(k^2+3k+2)$, that's a quadratic you can figure out a few different ways, it depends on how you were taught/are comfortable with.

twin meteorBOT
#

DonDoesMath

ruby vapor
#

And the goal of this induction is to get to show that $\sum\limits_{k=1}^{n+1}(3k-1)(n+1)=(n+1)^2(n+2)$, so the last step I reached proved that

twin meteorBOT
#

DonDoesMath

native heath
#

Ok

#

i think i get it now

#

Ty for your help

ruby vapor
#

No problem!

native heath
#

.close

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#
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wheat drum
#

How will I move on? I think I messes up somewhere

wheat drum
#

this is practice problem for the main question and this is how the textbook does it

sharp perch
#

Why did you substitute $x$ as zero when the condition given is $y\left(\frac{\pi}{3}\right) = 7c$

twin meteorBOT
wheat drum
#

ummmm good question

#

💀

wheat drum
sharp perch
#

It's dropped because sin is positive

wheat drum
#

For this question how would I proceed or are there any errors?

sharp perch
#

Should be $-e^{-z}=-2e^{t}+C$

twin meteorBOT
wheat drum
sharp perch
#

$\int \frac{1}{e^z};dz = \int e^{-z};dz = -e^{-z} + C$

twin meteorBOT
sharp perch
#

Does that make sense?

wheat drum
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@wheat drum Has your question been resolved?

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worldly badger
#

Really bad at math, the fraction kind of screwed me up, keep getting a different answer compared to the answer key, any help?

subtle blaze
#

Could you show us what you did? Maybe we could see where you went wrong

worldly badger
#

but i did most of the steps right

#

used this formula

#

the 3/8 fraction keeps messing me up, i dont really know how to solve the questions with the fraction like that

#

<@&286206848099549185> sorry for the ping, need help asap, exams in 2 hours

outer dune
#

Can you show what you did

vast shale
#

coefficient of x^7 is 12C7 (3/8)^5(4)^7

outer dune
#

yes but

#

does op know why

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#

@worldly badger Has your question been resolved?

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worldly badger
worldly badger
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rugged nacelle
vocal sleetBOT
rugged nacelle
#

I need help with this limit

#

I'm stuck here (honestly idek if im on the right path but yea)

#

I'm assuming I have to create a bunch of limits I alrdy know (tan(x)/x when x approaches 0 is 1 and tan(ax)/x when x approaches 0 is a)

#

<@&286206848099549185>

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vast moth
vocal sleetBOT
vast moth
#

the answer is supposed to be
x + y3 - 11 = 0

#

not
x + y3 - 10 = 0

#

i went through it a couple times and i keep getting the same answer

#

can someone help ?

grim dawn
# vast moth

you have a slope of 1/3 instead of -1/3 for the normal

#

and also your 1/6 dissapears and isnt added

#

oh

vast moth
#

oh shit, alr lemme try

grim dawn
#

unless 3.5-1/6 is 10/3 and i made a mistake

#

let me check

#

ah yea no u did do that part correctly

#

just the sign then

vast moth
#

ok its right

#

thanks again 😁

#

.close

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viral steeple
#

A regular hexagon whose center is at the origin has one vertex on the positive y-axis at a distance of 3.5 feet from the center. Find the polar coordinates (using radians) of the vertices and find the distance between 2 consecutive vertices. (round the distance to 2 decimals places)


I've tried muliple things like finding (0, 3.5), I tried to get the vertices which I thought was: (3.5, pi/6), (3.5, pi/2), (3.5, 5pi/6), (3.5, 7pi/6), (3.5, 7pi/6), (3.5, 3pi/2), (3.5, 11pi/6). and the distance: 3.5ft.

I think this is wrong though, can some one please help thanks!!!

cunning rose
#

I need help

#

Choices are 44.625, -44.625, 133.875, -1991. 390625

viral steeple
#

<@&286206848099549185>

terse forum
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#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#

@viral steeple Has your question been resolved?

viral steeple
#

<@&286206848099549185>

proud zealot
#

you can calculate the area of the right triangle displayed

#

and then multiply that area by the number of triangles there would be in the shape

#

so in this case 10 triangles

proud zealot
#

so in this case $\frac{1}{2}(5.1/2)*3.5$ is one triangle

twin meteorBOT
#

sabllamas

proud zealot
#

@viral steeple does that make sense??

viral steeple
#

hmm that was like the other dude's question

#

sorry mine was before that

proud zealot
#

oh! my bad

viral steeple
#

your good

#

<@&286206848099549185>

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#

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stoic patrol
#

bro I joined this server yesterday and got freaking 245 pings

stoic patrol
#

<@&286206848099549185> I joined this server a day ago and why did I have 245 pings

#

explain yall

tight sonnet
#

because people ping

#

like you

tough hedge
#

Exactly

tight sonnet
#

💀

tough hedge
#

!15m

vocal sleetBOT
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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

tough hedge
#

HAHAHAH

tight sonnet
#

remove the "helpers" role youd get much less ping

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vapid lion
#

someone help w this math question pls

vocal sleetBOT
lime gorge
#

@limpid shadow

#

is this dude in ur class

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@vapid lion Has your question been resolved?

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pearl juniper
#

So im doing sinusoidal functions, and somehow I keep messing up the phase shift. The distance between pi, and pi/4 is 5pi/4 and I cannot understand as to how.

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#

@pearl juniper Has your question been resolved?

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@pearl juniper Has your question been resolved?

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rancid sky
#

“y varies inversely as the square root of x, y equals to √6/6, when x = 24”

here’s my solution so far I’m new to the topic and unsure if it’s correct or not

rancid sky
#

! Status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
rancid sky
#

2, 4

livid horizon
#

You don't need to add the ± while taking sqrt(24)

rancid sky
#

fr?

#

ok2

livid horizon
#

Like sqrt(4) is taken to be 2

#

It's never -2

rancid sky
#

okayyy

livid horizon
#

Also in step 2, won't sqrt(24)= 2sqrt(6)?

rancid sky
#

Yes the 2 isn’t as clear

livid horizon
#

Oh kk

timber wagon
#

you maade a silly mistake there

#

the 2 doesnt cancel out so k=2

vocal sleetBOT
#

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meager talon
#

Can anyone explain how the 2nd step or I say x³-1/x-1 come?

strong grove
#

$$(x^3 - 1^3) = (x-1)(x^2 + x + 1)$$
$$\frac{(x^3 - 1^3)}{x-1} = \frac{\cancel{(x-1)}(x^2 + x + 1)}{\cancel{x-1}} = x^2+x+1$$

twin meteorBOT
#

JustToPro

meager talon
#

.close

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ornate birch
#

can anyone guide me through the process of answering this?

karmic forge
#

You have to do it one by one

#

First u/v

ornate birch
#

yes okay wait

karmic forge
#

Assume numeroter u and denominator v

#

Calculate du/dx,and dv/dx

ornate birch
#

then chain hold on

karmic forge
#

g' is 4

ornate birch
#

oh right my bad

karmic forge
#

And for f(x) use uv

#

uv formula

ornate birch
#

im not familiar in using that on quotient rule

#

we only use that in chain rule

#

is it ok that i stick to what ik how to use but still do the process

karmic forge
#

We have to find f'

ornate birch
#

ahhh getss

#

so i will do chain rule

#

hold on

karmic forge
#

And we can use chain rule for that

ornate birch
#

yes ok ok

#

product rule

karmic forge
#

You know gof(x) rule

ornate birch
#

yes

karmic forge
ornate birch
#

im doing it rn

karmic forge
#

Put u back

#

And go backwards

#

You have all the dervitatives

ornate birch
#

is this correct

#

how do i go from here

karmic forge
#

Yeah good job

#

Keep going

ornate birch
#

how do i continue the last line?

#

should i get lcd and add them or that's the derivative of f(x)?

karmic forge
#

Ya that's the value of f'

karmic forge
ornate birch
#

i dont need to add through lcd?

karmic forge
#

Why lcd just use u/v formula

#

You have f' and g'

#

Use( f/g)'=(gf'-fg')/g^2

ornate birch
#

ok wait

#

is this correct

#

<@&286206848099549185> sorry for the ping

#

<@&286206848099549185>

lucid zinc
#

dw about the ping gimme a second to answer you

#

i am struggling to understand how u derived sqrt(x³-1)

#

the derivative of sqrt(u) is simply u'/2sqrt(u)

#

meaning 3x²/2sqrt(x³-1)

#

oh my bad

#

i didn't notice the x

#

shits so unnecessarily complicated it hurts my brain

#

i need paper

lucid zinc
ornate birch
#

how did u get that

vocal sleetBOT
#

@ornate birch Has your question been resolved?

lucid zinc
#

and like i said to derive the square root you can use the chain rule

#

just as (sqrt(x))' = 1/2sqrtx

#

(sqrt(u))'=u'/2sqrt(u)

ornate birch
#

i dont get it

lucid zinc
#

hmm

#

you don't know the chain rule?

ornate birch
#

no, i cant visualize what you said

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#

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primal mauve
vocal sleetBOT
primal mauve
#

at a given time, vector (1 | 2 | -4) is modeling the direction of the falling sunlight

Calculate the angle of which the sunlight hits the ground (x1 ,x2)

#

the solution is:

sin alpha = |(1|2|-4) * (0|0|1)| all divided by square 21 = 4 / square 21 = alpha = 60.8°

#

where do I get the normal vector ( 0|0|1) or square 21 from ??

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vast citrus
vocal sleetBOT
zinc quail
vast citrus
vast citrus
#

ive tried everything i know and still stuck

zinc quail
#

try to do it in reverse

#

can you fold A into a cube?

#

yes :)

#

likewise you do so for the others

vast citrus
#

wait how

zinc quail
#

you can imagine to fold it back into a cube

vast citrus
#

im confused

zinc quail
#

then obv you can cut a cube such that it unfolds that way

vast citrus
#

so im looking for the ones that fold into a cube

zinc quail
#

sure

vast citrus
#

bro im deadass so stuck

#

legitly the last 2 question are about shapes

#

bro

zinc quail
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primal mauve
primal mauve
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rare viper
#

How do you divide a whole number between a ratio? Like, you know 21 must be divided in two with a ratio of 4/3

dark kiln
#

divide in 7

rare viper
#

which equals three

dark kiln
#

so 12 and 9

rare viper
#

Oh, I see. So cool, thank you

#

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leaden sail
#

I have an img

vocal sleetBOT
leaden sail
cobalt ocean
leaden sail
#

i couldnt do anything

cobalt ocean
leaden sail
#

wait i dont get what BC will be

#

HE will be -a + b

#

HG will be a + c

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#

@leaden sail Has your question been resolved?

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#

@leaden sail Has your question been resolved?

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@leaden sail Has your question been resolved?

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@leaden sail Has your question been resolved?

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@leaden sail Has your question been resolved?

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unreal sage
#

Just need some clarification for this question, and my working so far, the only thing I don't understand is for the x,y values, I was told by my lecturer it's just t but I wanna know why

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#

@unreal sage Has your question been resolved?

unreal sage
#

<@&286206848099549185>

#

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pliant portal
#

On a n*m matrix there are non-intersecting(they do not attack each other) rooks that cover all the squares. How many squares are hit twice if n=7 and m=13

lyric fossil
#

what have you tried

vocal sleetBOT
#

@pliant portal Has your question been resolved?

pliant portal
#

I tried (6+12)*8

#

But its not correct

lyric fossil
#

where did that number come from

pliant portal
#

Every rook hits 6 squares in the same collumns and 12 in the same row

#

I meant *7

#

18*7

lyric fossil
#

right but you just counted all the squares each of the rooks see

#

each square is seen twice

#

so you counted every square twice

pliant portal
#

My options are a)42 b)21 c)56 d)37 e)91 f)28

#

So even if i divide by 2 i dont get the right answer

lyric fossil
#

oh because of the extra squares that aren't seen twice

pliant portal
#

Oh

#

Yeah

#

63-7

lyric fossil
#

well not quite

#

think of it as

#

you have 13 columns, but only 7 rooks

#

so although the rooks see 12 squares horizontally, only 6 of those are seen by another rook

#

so you actually want (6 + 6) * 7 / 2

#

rather than (6 + 12) * 7 / 2

#

you basically just want a 7x7 grid

pliant portal
#

Oh right

#

Thanks

#

.close

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#
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tidal knoll
#

I'd like to integrate what's in the box, I thought I'd do that by parts but I don't know the indefinite integral of exp(-ax²)...
Substitution doesn't seem good, because it's exp(-ax²) not exp(-ax³),
and Wolfram doesn't give any explanation. I wouldn't like anything with the error function either since I'm not that familiar with it. Does anyone know the integration trick ?

unborn coral
#

The integral of exp(x^2) is a result you may memorize! Or you use tricks to get it (e.g. converting it to a polar integral). What class is this for?

tidal knoll
unborn coral
tidal knoll
#

ok, but I need the indefinite integral of that for my particular problem, don't I ?

#

like

#

and even if it was ok to use directly the "integrated between -inf and inf" version, I'd get something that is not convergent:

#

Maybe I just have to memorize some integrals like the error function related ones

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#

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tidal knoll
#

.close

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timber scaffold
#

hello i want to develop a diffential equaition to prict price of asset based on no. of factors. as time passes the eqation evolves into chaos

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#

@timber scaffold Has your question been resolved?

timber scaffold
#

no

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@timber scaffold Has your question been resolved?

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onyx swallow
#

I can't solve this

vocal sleetBOT
onyx swallow
#

it's confusing to me

vast shale
#

mathematically

onyx swallow
#

I think it's sum of all numbers/total amount of numbers or something

vast shale
#

the mean score for class A and class B

onyx swallow
#

Class A:
Mean score= sum of all scores/ number of students
75= sum of all scores/28

vast shale
#

yuh

onyx swallow
#

Class B:
Mean score = sum of all scores/ 32

#

i'm not sure what the sum here is

#

it mentions the sum of the mean but idk if that counts

vast shale
vast shale
vast shale
#

no

onyx swallow
#

wait I mean sum

vast shale
#

it's not thr mean wcore

#

yeah

#

so sum of all scores of class A = 2100

#

now

#

what would be the average for BOTH class A and B together?

#

can u write that out mathematically

onyx swallow
#

what do I find the average of exactly?

vast shale
#

the average score of both class A and class B considered together

onyx swallow
#

Average score= 2100+ (Mean score * 32)

vast shale
#

well you have to be careful here

#

okay lets backtrack

#

first things first

#

we want to find

mean of class A and B = (sum of all scores from class A and B)/(amount of students in class A and B)

#

agreed?

#

@onyx swallow

onyx swallow
#

yes

vast shale
#

sum of grades from A & B = Sum of grades from A + sum of grades from B

#

agreed?

onyx swallow
#

yes

vast shale
#

what is "amount of students in class A and B"

#

you are given the numbers

onyx swallow
#

60

vast shale
#

ok

#

fantastic

#

now

#

solve for "sum of grades from class B"

#

you have

75 = (sum of A + sum of B)/60

vast shale
onyx swallow
#

sorry i'm very disorientated-

#

I can't think clearly

vast shale
#

you should take a break then. Don't pressure yourself too much

onyx swallow
#

the problem is that my homework is due tomorrow-

#

I have like 6 other questions I don't know how to solve

vast shale
#

to encourage you our problem is almost finished if you want to keep pushing a bit more

#

oh i see

#

hmm cant ask for a deadline extension?

calm ore
#

can someone help me with grade 12 calc

vast shale
vocal sleetBOT
calm ore
#

mb

onyx swallow
#

she's strict so she'll probably just take a graduation point away from me ;-;

vast shale
#

awww that's really unfortunate man

#

well the choice is up to you. I can continue helping you with this if you are still able to

onyx swallow
#

i'll try writing everything u mentioned here

#

maybe seeing all the info at once is easier

vast shale
#

aight

#

your goal is to find the mean score of class B, which written would be:

mean B = (sum of grades of B)/(num of students in B)

you know num of students in B, so u just need to find sum of grades of B. You also know that:

mean A & B = (sum of grades of A + sum of grades of B)/(num of students in A & B)

You can try solving for "sum of grades of B" in the aboce and then plug it in into your first equation above, ans thats the answef

#

@onyx swallow

#

i summarised what u need to do if that helps

onyx swallow
#

thanks

#

that helped me a lot, I think I got my answer now

vast shale
onyx swallow
#

here is my working

vast shale
vast shale
#

i may have miswrotr that

#

do the same stuff but replace 75 with 72.6

onyx swallow
#

new answer is 70.5

vast shale
#

yeah!!

#

u got it :D

onyx swallow
#

I thought I wouldn't be able to get it without coffee ;-;

vast shale
#

but y did so good job

onyx swallow
#

do u mind helping me with one last question?

#

or should I reopen-

vast shale
#

aight

#

go ahead

onyx swallow
#

(this is one of the topics I dislike)

vast shale
#

aight do u have any ideas

onyx swallow
#

I know that there are two sum formulas that I don't know the difference of (when to use each one)

vast shale
#

anyways lets start

onyx swallow
#

I think my basic understanding in this topic is also bad ;-;

vast shale
#

issoki

#

lets see how it goes