#help-17
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i can have a cheat sheet filled with this kind of stuff but once the variation changes (ie. asks for water in a cylinder or something) i will completely blank out
so i want to know how to generalize all of these types of problems into one formula hopefully…
like 3d work problems
what should i look for that is the same for all variations?
…
@gentle umbra Has your question been resolved?
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yea the thing about pyramids/cones is that the area is scaling linearly from the point to the base
here it goes from 0 (point) to a side of 100 over a height of 0-60, so the side length formula is (100/60)*y
volume is area*height though so you need the area of that changing square, so (100y/60)^2, plus you multiply by the density for the weight
for cones it's the same but you want the radius which is like that 50 you found, then pi*r^2
@gentle umbra Has your question been resolved?
so i just keep in mind about the similar triangle and applies to everything shaped like this?
i got started a little bit on it but got stuck after setting the ratios up
right, since those 3d shapes are a point transforming into a full base at a steady rate
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Hello
How am I supposed to know if the function is wide or narrow? , the function is:
a +(x + p)² +k
The a affects whether it will be narrow or wide, but how will I know?
It depends on the absolute value of a
Lets say its 2.
The greater |a| is, the narrower it is
And if its -1 its upside down ?
Ok thx let mr chek it
If a>0, it faces upward
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how come
they get this
173 MeV
i though to get to MeV u need to multiply the eV by 10^8
so its 1.73 x 10^18
oh
um.
bye guys
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Given are the common densety functions of the 'accidental' variables X and Y:
Consider following statements:
how many are correct
Does anyone know how to find the last one
I think it would be Pi/4
als = if and elders = elsewhere
found it
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would this question: Denote in the complex plane all the numbers z = a + bi for which Im(conjugated of z)² = 1, be equal to y=-1/2x?
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If z = x + iy then yes
xy = -1/2
what am i supposed to do w the a+bi
Nothing
Im((a - bi)²) = -2ab = 1
But you considered x and y
Doesn't matter really
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I understand how to find key features when graphing rational functions, however I do not understand certain problems when they are in this format
Should I divide first?
remember that division by a fraction you can treat as multiplication by the reciprocal
Also I wondering if for all problems like this I should put both the numerator and denom in factored form
so you can rewrite it as $\frac{(x^2-4x)(x+4)}{(4x-8)(x+2)}$
Soosh
well i mean if you're trying to find key features
why? it's easier to work with a factored form
or what would be your purpose in distributing exactly?
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really struggling with this, i honestly have no idea where to even begin
i guess i could try like doing something in base 99 but i dont think thats it
or no it would be base 100
and i still dont think that would work
Choose primes, you'll be given a linear combination so you can factorize it and get the unknowns
doesn't it?
but theyll all be added together
there aren't any restrictions on the numbers Berris can name
i think base like 200 might actually do something
Ah yes, I'm assuming integers
it doesn't matter integer or not
the fact that Harris can only use secret 2-digit numbers is already extremely restrictive
its assumed to be across the integers, this is a number theory book
id be very surprised it it wasnt across the integers
that's fine but my point is this problem need not be confined to the integers as it does not heavily affect the solving process
you can solve it using integers as a restriction if you wish
well i cant solve it, thats why im asking for help lol
The base for expansion of abc would be 100 as a, b and c are 2 digit numbers
im still not sure how that would help though
since any integer that large has tons of ways of making it from adding 3 smaller numbers
make up three numbers x,y,z. and then tell me 10000x+100y+z
The two digit restriction is what makes it work
you are overthinking probably
it might help if you just do it
Would give you (100^2)a + 100b +1c so that a, b and c still remain visible in the sum as abc, acb, bac, bca etc.
so like the idea is to pick the numbers 10000, 100, and 1, and then berris converts the number harris gives to base 100?
or something like that
you dont specifically need to frame this in terms of base 100
you can already read off the numbers from the result
base 100 is just base 10 but two digits at the same time
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Let $f$ be a function from a finite set $A$ to itself. Prove that $f$ is injective if and only if $f$ is surjective. Does this remain true if the finiteness assumption on $A$ is dropped?
I understand why this must be true. in the direction injectivity implies surjectivity:
Assume the function is not surjective. This means $|f(A)| < |A|$.
The codomain and domain are the same set, so $| \text{codom} f | = |A|$. Since injectivity implies that $|f(A)| \ge |A|$ and $f(A) \subseteq A$, we know $|f(A)| \le |A|$. Consequently, $|f(A)| = |A|$. This contradicts with $|f(A)| < |A|$, and thus $f$ must be surjective.
I qualitativly understand the reverse, but am even less sure how to write it out.
Is my reaosning ocrrect, and how can I turn it into a proof? Thanks!!
Nameless
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Discrete Math
Q: Prove A ∩ (B ⊕ C) = (A ∩ B) ⊕ (A ∩ C)
I showed my work so far, but I've hit a wall since adding X and Y back in doesn't lead to what I'm looking for
This was my first answer but I'm not sure if this would be valid as it seems too simple for the assignment
Ping me if you reply to the message
seems like its easier if you work with the right side
Alright I'll try that
I did the right side and I got a statement that would always be false, did I miss a step or is this on the right track still?
Since it proves the right side is false, however the left side may still be true or false, not sure how I could do that
unless 1 side being false means the entire statement is false
lemme see
how did you get that it will always be false?
Oh wait I saw it wrong, in my head I saw that it would need A and A^c to be true which would always be false i read that really wrong woops
even then I'm till kind of lost what to do after the last line and what law I could apply
its gonna be a lot of distributive laws
ok i'll try that, also is watson amelia your top 5
hmm i would have to think about that
ok and you're sure distributive laws is the only way to go about this cause looking at it, it looks like its gonna get super messy idk
yes it will get super messy
take A intersect B as your entire A
and distribute it that way
so something like this and then distribute it ok ill try that
yeah
gosh i hate using set operations to do boolean algebra
using addition as OR and multiplication as AND is so much easier to keep track of stuff
@quasi roost Has your question been resolved?
@edgy gulch i've been staring at this for awhile im mad confused, i could do distribution again but at that point there is no way i'll even see how it'd simplify
i did notice that these have to cancel out and be forced as false though, unless im reading that wrong
yes indeed
so you can just get rid of them
since they'll just be empty sets
then what you have left is (A∩B∩C') ∪ (A∩C∩B')
reverse the distribution law
A∩((B∩C') ∪ (B'∩C))
A∩(B⊕C)
and boom we done
o ok thank you im just gonna write it all out with the laws i used, have you been doing discrete math for awhile?
at what point can u just look at something and know how to do it
cause every new question i look at i just get so confused
if its still boolean algebra then yeah i suppose
Thank you for the help, makes sense to me now
I have 1 more question, I got this answer for another set problem with my work already shown, does this look alright or did I miss something midway
yeah looks good
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doing comp sci, trying to understand union find, not understanding dot points 3 and 4
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@finite hatch Has your question been resolved?
If the two decks are shuffled together
in how many ways can you arrange them>?
idk
104
ok, in how many ways can you arrange 104 cards
remember , so cards are repeated
some cards
yes
104!/2!?
wait ok i skipped that one
how does the n! turn into an n
in the third line
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Is this worked out correctly?
in the solutions they used comparison test but is my method correct aswel?
or does 6^n / 3^n +4^n not equal (6/3+4)^n
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can someone give me a trick to remeber the radians of the unit circle(I have memorised the angles(convert them from radians) as well as the coordinates)
Look up the Hand Trick on Youtube.
k lemme check
this does not answer my querstion
I am asking how to memorize the pi/6, pi/4, pi/3, pi/2 so and so forth
You're only interested in memorizing the radian measure?
What are you trying to understand about radian measures? That will help me explain whatever it is you are trying to learn.
how do I memorize it
Just the values themselves? Their relation to degrees? Their position on a unit circle?
the vals themeself
,calc pi/2
Result:
1.5707963267949
okay...
So the numerical values?
You named all of the important radians aside from pi and 2pi.
After that, it's really just learning how to apply them to reference angles.
7pi/6 is just 7pi/6 - pi = pi/6. From there, you can see that the difference in values are just negative signs from pi/6.
I am confused man
One moment, let me make a graph.
okay
You should read about reference angles.
https://www.cuemath.com/geometry/reference-angle/
A reference angle is an acute angle enclosed between the terminal arm and the x-axis. It is always positive and less than or equal to 90 degrees. Let us learn more about the reference angle in this article.
ik what ref angles are
So what's the problem?
i dont know how to remmevber the unit circle radians
Like 7pi/6 or 3pi/2?
You don't need to remember every single radian in a unit circle. Just do the conversion as needed to pi/2, pi/3, pi/4, or pi/6 as needed.
the pi/6, pi/4, pi/3, pi/2, 2pi/3, 3pi/4, 5pi/6, pi, 7pi/6, 5pi/4, 4pi/3, 3pi/2, 5pi/3, 7pi/4, 11pi/6, 0
After that, it's just a matter of remembering the signage.
^^^
how to memorize what I said above
My mind is not working rn
The other is just adding pi/6.
ic the pattern for quad 1 and quad 2 its for the denomitoers: 6, 4, 3, 2, then for quad 2 its 2, 3, 4, 6
but the numerator tho
wait
for quad 2 5pi/6 becomes 7pi/6
its 2pi increment for numerator
and that applies to all
so all I have to do is memeorize quad 1 and not 2
then I got the rest
In 2Q, just add pi/2.
and the sign chamghe is self explantaroy
In 3Q just add pi
In 4Q, add 3pi/2.
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if you can find the perpendicular line of a linear function by finding the negative reciprocal of the gradient then how do you find the perpendicular line of a quadratic function?
do i need to find the negative derivative of x^2 or smthing
y = mx +c , m is the gradient and a perpendicular line would be y = -(1/m)+c
wait what
m = gradient
i have no idea
uhhh
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Discrete Math
Q If g : A → B is surjective and f : B → C is injective, then g ◦ f is surjective
Showed my work so far, but I'm confused on how to prove g ◦ f is surjective or if I missed a step in between, hit a wall
Please don't occupy multiple help channels.
ping me if you reply to this please
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made it more clear
Surjective does not mean that two different values in the domain map to the same value in the codomain, it means that each value in the codomain has an element in the domain that maps to it
Yes but I wanted to put an example that I could use for the proof, so the example I used had two distinct values map to one
but I should reword it with "Let" thank you, unless I shouldn't be using this example at all
Oh, is the question asking you to just find an example of functions satisfying that property?
Or to prove it is true for all functions f,g satisfying the assumptions?
This is the question
Ah okay. So do you think it is true or false?
It's not clear if you're trying to prove or disprove it
I believe it's true so I'm trying to prove it
Got it. To prove something is true, you can't just use an example, you actually need to show that the conclusion follows from the assumptions. To disprove something, you can just use a counterexample
Also, I think it should be f ○ g, not g ○ f
I thought this too, but in the questions it is labelled as this
ill check emails my teacher sent just incase but this is mostly what confused me a lot
I mean, the codomain of f is C, but g takes A as it's domain, so g ○ f isn't well defined
Unless the notation they're using is supposed to be read left to right, not right to left, which is quite uncommon but not unheard of
In any case, g is first, then f, for it to make sense
Found no email, but I found this
This is from the lectures from the same teacher, the [X] is supposed to be ◦, and in this case it does not look reversed, but I think the teacher intended on the assingment for it to be reversed since it does say at the bottom that the reverse is not well defined
So I need to use f(g(x)) for it to make sense
How would I go about doing this then, since I'm not sure how else to do the problem
for now i have it like this
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draw the graphs of those straight lines
Yeah, I did
then find the intersection points between them
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How do I do this
Note that x is the upper limit of that integral. What happens to that integral as x approaches 0?
Keeping in mind the lower limit is 0, ofc.
Right. The numerator approaches 0 here.
How would I do that tho
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$\frac{d}{dx}\int_0^xf(x)=f(x)-f(0)$
So do I have to find the anti derivative?and then evaluate ?
Sora Harewataru
I mistyped
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the good thing about ftc2 is u dont have to find the antiderivative
How do I know when to apply ftc2 rather than just integrating
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Hi
when you take the derivative of an integral
that is when you will use ftc2
Oh alr
because derivatives and integrals are like inverses they cancel nicely
And derivative of integral cancels out bc it’s just derivative of anti derivative rigjt
Yea
yeah thats even better
Looks like it has an answer. You might need to do L'Hopital multiple times
and its not 0
did you remember to chain rule sin(3x^2)
first L'Hopital gets sin(3x^2)-sin(0)=sin(3x^2) in numerator
sin(3(0)^2)=sin(0)=0
i thought sin(0) was 0
Is this after doing hosptial once
yeah
oh yeah i meant 24x sorry
Oh yeah that might work
Cause if i hospital one more time id get 0
yeah you can
so i get 1/4
yeah
did u hospital it an additional time?
yeah it still gives 1/4
Wait how
you get like 6*sin(3x^2)-6xcos(3x^2)/24 = 6-0/24 = 1/4
Oh my days
maybe sin and cos are switched
i forgot abt the product rule
yeah
np
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$\lim_{x\to0}(\csc^2-x^{-2})$
Soosh
to do this limit, i wrote it as 1/sin^2 - 1/x^2 then found a common denominator, then it became indeterminate form 0/0 then had to apply lhopitals like 4 times until it finally worked out, which was rather painful and long, is there an easier way to do this limit?
Unfortunately I don’t think so
Sometimes just have to grind out a bit of lhopitals
There might be something slightly easier by playing around with the common denominator and maybe some trig identities, but it’s negligible I assume
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Find the value of the expression 20x^2y^4, if 4xy^2 = - 6
try squaring both sides of 4xy^2=-6
try change of variables xy^2 = a in both expressions
4xy^2 = -6 so xy^2 = -6/4
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ok
this seems silly
this is a calc 2 problem
but for some reason im having trouble taking the derivative of that y =
its not nessecairly that i cannot do it
I have the derivative
but simplifying it to a point where when i use SA formula
im getting tripped up on the part where i Use the property sqrt a * sqrt b to simplify the integrand
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yep looks good, your work before the first bold line is not needed as they just want you to verify they are inverse to each other which is what the rest of your work does
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Proof by induction
<@&286206848099549185>
Expand brackets and use the formulae
For sum of squares and sum of a variable
Im trying to solve it but im having problems with both sides of the equation when im solving for n=k+1
Can I see your work?
idk what to add on which side and the sigma notation is just messing me up
1 sec
I tried removing the sigma notation to make it easier
But i just dont get it, ive watched a thousands of videos and AI couldnt explain it properly
Do you know the standard formulas for the sigma notation
We learn this here with Sigma notation idk bout u
No ive never seen smth like this
I mean i know what sigma is
i understand what it is but when using it in induction its just making things complicated
When you have k^2(k+1)+(3k+2)(k+1), factor out the (k+1) to get (k+1)(k^3+3k+2) and it's easier to work with
I never factored anything before
so im pretty lost in factoring
Can you solve it and show me your work? Maybe that will help me somehow
Not having factored anything before will make problems like this a lot harder. There's only one more step to go after I wrote, but here it is: $k^2(k+1)+(3k+2)(k+1)=(k+1)(k^2+3k+2)=(k+1)(k+1)(k+2)=(k+1)^2(k+2)$ You're allowed to factor out a (k+1) the exact same way you can factor out a 2 (for example) if all the terms have a 2. When you get $(k^2+3k+2)$, that's a quadratic you can figure out a few different ways, it depends on how you were taught/are comfortable with.
DonDoesMath
And the goal of this induction is to get to show that $\sum\limits_{k=1}^{n+1}(3k-1)(n+1)=(n+1)^2(n+2)$, so the last step I reached proved that
DonDoesMath
No problem!
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How will I move on? I think I messes up somewhere
this is practice problem for the main question and this is how the textbook does it
Why did you substitute $x$ as zero when the condition given is $y\left(\frac{\pi}{3}\right) = 7c$
Kappa
so i drop the absolute value bc x is between 0 and pi/2; therefore making x positive?
x is positive, but the absolute value is on sin
It's dropped because sin is positive
For this question how would I proceed or are there any errors?
Should be $-e^{-z}=-2e^{t}+C$
Kappa
why?
$\int \frac{1}{e^z};dz = \int e^{-z};dz = -e^{-z} + C$
Kappa
Does that make sense?
no I thought you could not take the integral if n=-1
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Really bad at math, the fraction kind of screwed me up, keep getting a different answer compared to the answer key, any help?
Could you show us what you did? Maybe we could see where you went wrong
im on my computer right now, i wrote it in a notebook so i cant share it
but i did most of the steps right
used this formula
the 3/8 fraction keeps messing me up, i dont really know how to solve the questions with the fraction like that
<@&286206848099549185> sorry for the ping, need help asap, exams in 2 hours
Can you show what you did
coefficient of x^7 is 12C7 (3/8)^5(4)^7
@worldly badger Has your question been resolved?
I got it now
thanks, this kind of helped
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I need help with this limit
I'm stuck here (honestly idek if im on the right path but yea)
I'm assuming I have to create a bunch of limits I alrdy know (tan(x)/x when x approaches 0 is 1 and tan(ax)/x when x approaches 0 is a)
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the answer is supposed to be
x + y3 - 11 = 0
not
x + y3 - 10 = 0
i went through it a couple times and i keep getting the same answer
can someone help ?
you have a slope of 1/3 instead of -1/3 for the normal
and also your 1/6 dissapears and isnt added
oh
oh shit, alr lemme try
unless 3.5-1/6 is 10/3 and i made a mistake
let me check
ah yea no u did do that part correctly
just the sign then
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A regular hexagon whose center is at the origin has one vertex on the positive y-axis at a distance of 3.5 feet from the center. Find the polar coordinates (using radians) of the vertices and find the distance between 2 consecutive vertices. (round the distance to 2 decimals places)
I've tried muliple things like finding (0, 3.5), I tried to get the vertices which I thought was: (3.5, pi/6), (3.5, pi/2), (3.5, 5pi/6), (3.5, 7pi/6), (3.5, 7pi/6), (3.5, 3pi/2), (3.5, 11pi/6). and the distance: 3.5ft.
I think this is wrong though, can some one please help thanks!!!
<@&286206848099549185>
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@viral steeple Has your question been resolved?
<@&286206848099549185>
you can calculate the area of the right triangle displayed
and then multiply that area by the number of triangles there would be in the shape
so in this case 10 triangles
1/2 base * height
so in this case $\frac{1}{2}(5.1/2)*3.5$ is one triangle
sabllamas
@viral steeple does that make sense??
oh! my bad
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bro I joined this server yesterday and got freaking 245 pings
<@&286206848099549185> I joined this server a day ago and why did I have 245 pings
explain yall
Exactly
💀
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HAHAHAH
remove the "helpers" role youd get much less ping
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someone help w this math question pls
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So im doing sinusoidal functions, and somehow I keep messing up the phase shift. The distance between pi, and pi/4 is 5pi/4 and I cannot understand as to how.
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“y varies inversely as the square root of x, y equals to √6/6, when x = 24”
here’s my solution so far I’m new to the topic and unsure if it’s correct or not
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2, 4
You don't need to add the ± while taking sqrt(24)
okayyy
Also in step 2, won't sqrt(24)= 2sqrt(6)?
Yes the 2 isn’t as clear
Oh kk
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Can anyone explain how the 2nd step or I say x³-1/x-1 come?
$$(x^3 - 1^3) = (x-1)(x^2 + x + 1)$$
$$\frac{(x^3 - 1^3)}{x-1} = \frac{\cancel{(x-1)}(x^2 + x + 1)}{\cancel{x-1}} = x^2+x+1$$
JustToPro
Ah, Got it.
Thanks brother.
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can anyone guide me through the process of answering this?
yes okay wait
g' is 4
oh right my bad
im not familiar in using that on quotient rule
we only use that in chain rule
is it ok that i stick to what ik how to use but still do the process
We have to find f'
And we can use chain rule for that
You know gof(x) rule
yes
And use u(x) and v(x) or other then f(x) ,g(x) you willget confuse
how do i continue the last line?
should i get lcd and add them or that's the derivative of f(x)?
Ya that's the value of f'
Here f'
i dont need to add through lcd?
ok wait
is this correct
<@&286206848099549185> sorry for the ping
<@&286206848099549185>
dw about the ping gimme a second to answer you
i am struggling to understand how u derived sqrt(x³-1)
the derivative of sqrt(u) is simply u'/2sqrt(u)
meaning 3x²/2sqrt(x³-1)
oh my bad
i didn't notice the x
shits so unnecessarily complicated it hurts my brain
i need paper
f'(x)=sqrt(x³-1)+3x³/2sqrt(x³-1)
how did u get that
@ornate birch Has your question been resolved?
derivative of x times the square root + x times the derivative of the square root
and like i said to derive the square root you can use the chain rule
just as (sqrt(x))' = 1/2sqrtx
(sqrt(u))'=u'/2sqrt(u)
i dont get it
no, i cant visualize what you said
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at a given time, vector (1 | 2 | -4) is modeling the direction of the falling sunlight
Calculate the angle of which the sunlight hits the ground (x1 ,x2)
the solution is:
sin alpha = |(1|2|-4) * (0|0|1)| all divided by square 21 = 4 / square 21 = alpha = 60.8°
where do I get the normal vector ( 0|0|1) or square 21 from ??
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where are you stuck
its asking me choose all the shapes below that you could get by cutting some of the edges of a cube and unfolding it
am aware
ive tried everything i know and still stuck
try to do it in reverse
can you fold A into a cube?
yes :)
likewise you do so for the others
wait how
you can imagine to fold it back into a cube
so am i looking for the ones that fold into a cube or the ones that dont
im confused
if you can fold them back into a cube
then obv you can cut a cube such that it unfolds that way
so im looking for the ones that fold into a cube
sure
but you just need to fold them backwards
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can you by any chance help me out too? on my previous one
this
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How do you divide a whole number between a ratio? Like, you know 21 must be divided in two with a ratio of 4/3
divide in 7
which equals three
so 12 and 9
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I have an img
what have you tried
idk i tried joining the lines
i couldnt do anything
try and write EF and EH and FG and HG in terms of the vectors a, b, c
alr
wait i dont get what BC will be
HE will be -a + b
HG will be a + c
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Just need some clarification for this question, and my working so far, the only thing I don't understand is for the x,y values, I was told by my lecturer it's just t but I wanna know why
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On a n*m matrix there are non-intersecting(they do not attack each other) rooks that cover all the squares. How many squares are hit twice if n=7 and m=13
what have you tried
@pliant portal Has your question been resolved?
where did that number come from
Every rook hits 6 squares in the same collumns and 12 in the same row
I meant *7
18*7
right but you just counted all the squares each of the rooks see
each square is seen twice
so you counted every square twice
My options are a)42 b)21 c)56 d)37 e)91 f)28
So even if i divide by 2 i dont get the right answer
oh because of the extra squares that aren't seen twice
well not quite
think of it as
you have 13 columns, but only 7 rooks
so although the rooks see 12 squares horizontally, only 6 of those are seen by another rook
so you actually want (6 + 6) * 7 / 2
rather than (6 + 12) * 7 / 2
you basically just want a 7x7 grid
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I'd like to integrate what's in the box, I thought I'd do that by parts but I don't know the indefinite integral of exp(-ax²)...
Substitution doesn't seem good, because it's exp(-ax²) not exp(-ax³),
and Wolfram doesn't give any explanation. I wouldn't like anything with the error function either since I'm not that familiar with it. Does anyone know the integration trick ?
The integral of exp(x^2) is a result you may memorize! Or you use tricks to get it (e.g. converting it to a polar integral). What class is this for?
exp(-a^x^2) = e^x^2?
It's for a quantum physics class, I was calculating the expectation value of x² for a given wave function
I see, in that case yea you may need to use the classic result! See here https://en.m.wikipedia.org/wiki/Gaussian_integral
ok, but I need the indefinite integral of that for my particular problem, don't I ?
like
and even if it was ok to use directly the "integrated between -inf and inf" version, I'd get something that is not convergent:
Maybe I just have to memorize some integrals like the error function related ones
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hello i want to develop a diffential equaition to prict price of asset based on no. of factors. as time passes the eqation evolves into chaos
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no
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I can't solve this
it's confusing to me
I think it's sum of all numbers/total amount of numbers or something
right can u try writing an equation to represent that for both classes individually
the mean score for class A and class B
Class A:
Mean score= sum of all scores/ number of students
75= sum of all scores/28
yuh
Class B:
Mean score = sum of all scores/ 32
i'm not sure what the sum here is
it mentions the sum of the mean but idk if that counts
right this is fine. Now, try multiplying both sides of that equation by 28
u will find that out soon dw
mean score=2100
no
wait I mean sum
it's not thr mean wcore
yeah
so sum of all scores of class A = 2100
now
what would be the average for BOTH class A and B together?
can u write that out mathematically
what do I find the average of exactly?
the average score of both class A and class B considered together
Average score= 2100+ (Mean score * 32)
well you have to be careful here
okay lets backtrack
first things first
we want to find
mean of class A and B = (sum of all scores from class A and B)/(amount of students in class A and B)
agreed?
@onyx swallow
yes
ok
sum of grades from A & B = Sum of grades from A + sum of grades from B
agreed?
yes
ok
what is "amount of students in class A and B"
you are given the numbers
60
ok
fantastic
now
solve for "sum of grades from class B"
you have
75 = (sum of A + sum of B)/60
you know sum of A to be this
you should take a break then. Don't pressure yourself too much
the problem is that my homework is due tomorrow-
I have like 6 other questions I don't know how to solve
to encourage you our problem is almost finished if you want to keep pushing a bit more
oh i see
hmm cant ask for a deadline extension?
can someone help me with grade 12 calc
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mb
she gave us that hwk 4 days ago but I had to study for 2 exams so I didn't start it til now
she's strict so she'll probably just take a graduation point away from me ;-;
awww that's really unfortunate man
well the choice is up to you. I can continue helping you with this if you are still able to
i'll try writing everything u mentioned here
maybe seeing all the info at once is easier
aight
your goal is to find the mean score of class B, which written would be:
mean B = (sum of grades of B)/(num of students in B)
you know num of students in B, so u just need to find sum of grades of B. You also know that:
mean A & B = (sum of grades of A + sum of grades of B)/(num of students in A & B)
You can try solving for "sum of grades of B" in the aboce and then plug it in into your first equation above, ans thats the answef
@onyx swallow
i summarised what u need to do if that helps
ayee thats good
here is my working
ah
ur procedure is totally fine but like it says 72.6 for both actually
i may have miswrotr that
do the same stuff but replace 75 with 72.6
new answer is 70.5
I thought I wouldn't be able to get it without coffee ;-;
(this is one of the topics I dislike)
aight do u have any ideas
I know that there are two sum formulas that I don't know the difference of (when to use each one)
ok i think this one might take a bit longer to do so you need to bear with me for my explanation
anyways lets start
I think my basic understanding in this topic is also bad ;-;

