#help-17
1 messages · Page 90 of 1
alr, so the final answer is 15 [W 53 N]?
or N 53 W? 🤔
well im not familiar with this notation u r using..
basically imagine urself facing the west, and then u turn towards the north thru 53deg
i mean is it 53 degrees from the west or north?
ah
yes I get it now
thank you
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hello can you help me solve a ratio and proprtian question

hi
can i ask
Two numbers are in the ratio 9:4 . if 7 is added to each of the numbers.The ratio becomes 5:3 . Find the numbers ?
<@&286206848099549185> Hey im new no one is helping
ok
you play roblox
9a = 4a
5(a+7) = 3(a+7)
write it as formulaas.
solve for a
i dk algebra
18 and 8
im dumb
my guy you posted the message one minute ago have some patience
k
you gotta try
Yeah!
i gave you the simulaneous eq
teach me algebra
Let's call the two numbers in the ratio 9:4 as 9x and 4x, where x is a positive constant.
So, we have:
First number = 9x
Second number = 4x
According to the given information, when 7 is added to each of these numbers, the new ratio becomes 5:3. So, we have:
(9x + 7) / (4x + 7) = 5/3
To solve for x, we can cross-multiply:
3(9x + 7) = 5(4x + 7)
Now, distribute the numbers on both sides of the equation:
27x + 21 = 20x + 35
Next, subtract 20x from both sides:
27x - 20x + 21 = 35
Combine like terms:
7x + 21 = 35
Now, subtract 21 from both sides to isolate 7x:
7x = 35 - 21
7x = 14
Now, divide by 7 to find the value of x:
x = 14 / 7
x = 2
So, we've found that x = 2. Now, we can find the two numbers:
First number = 9x = 9 * 2 = 18
Second number = 4x = 4 * 2 = 8
Therefore, the two numbers are 18 and 8.
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
!nosols\
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
relax
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
chill out bro
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When I complete this problem, Im only subsituting the 2 functions that I circled and Im not exactly sure where Im going wrong
@main totem Has your question been resolved?
@main totem Has your question been resolved?
hello, could you show your work? 🤔
the resulting integrand should be
14/(2t^2 + 2t) I think
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i didnt get that
wait I actually did
it simplifies to 7/t^2+t
right?
the issue is that it still doesnt work
I should subsitute the bounds into the function 7/t^2+t right
No, that's not the rule of substitution 🤔
You're given t= tan(x/2)
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why arent you allowed to simplify
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Can anybody find the pattern?
without more information i would do a linear interpolation.
300000 sawfly cococons -> 7,5 shrews. 600000 -> 19 you need 500000 which is 2/3 on the way from 300000 to 600000 -> 2/3 from 7,5 to 19 -> ...
is it 7.67?
plus 7.5 (you start from 7.5)
with a linear interpolation: yes
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How do I get coefficients out of the inside of trigonometric functions?
I'm in IB Math Y2. We learnt how to change sin(2x) etc, but homework has sin 3x and sin x/2 and like sin sqrt(3)x/3
Im pretty sure it's just formulas
And you have to change what's inside the function to get to a known formula
@obtuse needle Has your question been resolved?
oka7y one of us just found more identities int he formula booklet that work 👍
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I’m stuck on a basic tangent line question for calculus.
The question is:
“Sketch the circle of radius 2 centered at 3,-3 and the Line L with equation y=2x+2. Find the coordinates of all the points on the circle where the tangent line is perpendicular to L.”
I know the slope of the tangent lines that would be perpendicular but I’m stuck trying to find how I could use that to find the specific points on the circle where it is perpendicular to L.
if the slope of the tangent at a point is perpendicular to L, then the radius at that point is parallel to L
so intersect the line which passes through the centre of the circle with gradient the same as L, with the circle, to obtain the points
The red line has the same slope since it’s parallel and I figured out the b from the circle’s centre point
Y = 2x-9
But do I then do something like:
-1/2x + b = 2x-9
Wasn’t sure how to progress when I found it was parallel
once you have the equation for the red line
you can either equate it to the equation of the circle to get the intersection points
or you can find the points on that line a distance of 2 (the radius) away from the centre of the circle
@stoic trout Has your question been resolved?
So something like (x-3)^2 + (2x-9+3)^2 = 4?
yes
Ok I found one of the answers but how do I find the other one
its a quadratic; you should get 2 solutions
Oh I think I messed up at one of the steps but I think I know how to do it now tysm
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np
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I need help in geometry, I got a test tomorrow and trying to study, but I’m stuck trying to prove statements. How would I prove angle B is congruent to angle C?
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Does anyone have any idea how to do this question
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how to solve lim (sin5x)/(3x) as x approaches 0; knowing that sinx/x = 1
perhaps let u=5x and do some subbing and factoring
L'hospital brother
lhopital is so unnecessary here lmao
how to solve?
basically this
kk
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not sure how they got this answer, but then again, i'm not sure how I got my answer either haha!
my logic was that we have the initial amount, and its exponentially decaying by 0.6%, but either way, now I'm trying to understand the solution, but it doesn't make much sense to me
<@&286206848099549185>
no
sorry im in class
oh, I got it
the 207/50000 = 3*69/500
they are accounting for the amount already in the body at the moment t = 0.69s
this way, when t = 0.69, the exponent is 0 and the amount in the body is exactly 0.47 ml
@undone shell
also you shouldn't be exponentiating the rate in your version
oh okay, so its the rate (found in first part) to the power of the 0.6% decrease, plus the amount thats already in the body?
you would want a form like
f(t) = 0.47(1-0.006)^(t - 0.69)
= 0.47(0.994)^(t-0.69)
and that would be the same
...pretty sure.
no
it's the initial amount, times
Ohhh, okay. are we subtracting it from 1 here because its a percent?
got it
this is an equivalent expression
umm, wait
I'm messing it up
when t=0.69 seconds, we need 47 mL, and we need to be losing 0.06% = 0.006 every second
0.006 = 3/500
the formula for decay is P = P_0 e^(-rt)
that's why you see
$Q(t) = \frac{47}{100}e^{-\frac{3}{500}t}$
Disorganized
but we also need to make sure that when t=0.69, the exponent is zero
we can do that by just doing 0.006*0.69
which is the same as (3/500)*0.69
and adding it to the existing exponent
which is what they did
oh okay, thats where it came from. i see
that's 207/50000
thank you so much for clearing that up, i really appreciate your time
$Q(t) = \frac{47}{100}e^{\left(-\frac{3}{500}t + \frac{207}{50,000}\right)}$
Disorganized
this should still also be true
equivalent
okay, thats the form i'm more comfortable with anyways, so thanks for that as well
np
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a bit confused on this
@vocal vale Has your question been resolved?
<@&286206848099549185>
(f o g)(x) is another way of writing f(g(x))
In this case x=2, so we want to know what f(g(2)) is.
You've correctly identified that g(2) = 8
but now what value do we plug into f(x)?
1, no?
Plugging x = 1 into f(x) will give us f(1) = 9
hm
For f(g(x)), we want to plug x into g(x) and then plug g(x) into f(x)
So for f(g(2)), we want to plug 2 into g(x) and then plug g(x = 2) into f(x)
We have already found g(x = 2) = 8
What value should we then plug into f(x)?
We don't want to do that. Keep in mind that $$ g(2) = 8 \neq 2$$ and so $$ f(g(2)) \neq f(2) $$
thedude365
Since $$ g(2) = 8$$, what is $f(g(2))$ equal to? $$ f(g(2)) = f(...) $$
thedude365
3?
Why 3?
I think you're reversing the placement of the numbers. The answer's f(g(2)) = f(8) = 3
i was pretty stuck on tryna figure this out but the second one got it for me
thank you so much
of course
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im not sure why this is wrong
how did you obtain that answer
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Help me I'm stupid. I want to add 91% isopropol alcohol to 70%, and then dilute that final mixture with water to a final concentration of 70%. I know about c1v1 = c2v2, but I am having issues actually implementing it
I want the final volume to be 940ml, and I have 320ml of 70%
I just don't know how to procede from here
wut
It is physically impossible to go down to 70% concentraction if you have 0.0000000000000000000000000000000000000000000000000000000000000000000000000001 ml of 91% in it
Sorry, I meant to say add water to dilute it down to 70%
I'll edit the first message
So, I have 320ml of 70% iso, I want to add some volume of 91% and then dilute to a final volume of 940ml
So you'll have two equations
One equation for when you add x ml of 91%
and another for when you dillute it with water to reach 940ml
Right, but I feel like I need to solve the two simultaneously...
And I never learned how to solve systems of equations in school 🤷♂️
Hm....
Im trying to think of how tha'd work
Okay maybe I got it
So If I use c1v1 = c2v2, (0.70.32) = (c20.94), that leaves me with a c2 of 0.23....
so that means I need to figure outhow to dilute the 91% to 23%, right?
Did my math do the math things there?
Nope, I screwed that up
Okay let me try this: c1v1 = c2v2. I need 640ml of liquid at 70%, so if I dilute the 91% and find out what v1 is needed, that give me (0.91v1) = (0.70.640), and solving for v1 gives me 0.490ish. Which means I would need to add 490ml and then top off to my final volume with water
I think that's right
athe 640ml of liquid comes from my wanted 940ml, and I already have 320
Which is...wrong...but I think my process and thinking is correct
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U(8) is the multiplicative group consisting of elements mod 8 such that their greatest common divisor with 8 is 1
can you list the elements of U(8)?
1, 3 , 5 , 7
can you list <3>?
thats kind of part of my confusion. is it just integer multiples of 3?
no
3^n
ohhh duh
the group is under multiplication
right
so 3, 3*3, 3*3*3, ...
okay
(and inverses)
okay so then im lost
which elements do you get if you start at 3 and repeatedly multiply by 3
just 3 and 1
okay, so then pick an element of U(8) that is not <3>?
yes, for example 5. what is 5*{1,3} ?
yes
so <5>={5,7}
so without calculating, what is 7*{1,3} ?
no
wait why not? do we need to check powers of 5?
if you want to find <5>, yes
and this is {7,5}
oh right okay my bad
ok, so the left cosets of <3> are {1,3} and {5,7}
right okay
do we have to calculate the right cosets now or do you know something about the group so that we can skip that?
U(n) is abelian right?
yes
we could predict theres only 2 cosets from lagranges theorem? cuz U(8) has 4 elements and <3> has 2?
am i understanding that correctly?
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this is a PRACTICE TEST
how do I figure out f^-1(T)
i just saw that 3 maps to 6 and 6 maps to 6 mod 9
but potentially other things could map to 3 and 6, how can i find them
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How am i supposed to do this?
How do i know where the shape begins and ends?
I've read this part of my book three times
and none of those times did the words in the book change to include the information required to solve this
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is there a way to further simplify this?

why is it funny?
what forbidden god have you angered to be given this problem
just trying to figure out how to simplify
lord have mercy

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how do i solve a differential equation with the laplace transform where one of terms is a product of a function of x and y
for example y' = 2x(25-y)
like if i take the Laplace of all terms one of them ends up being 2*L{xy}
how do i evaluate that
Have you checked the transform table
for xy?
yes
its not there
unless im missing a property of the transform i can use
i feel like ive checked everything
30
It looks like you're just gonna get an ODE again though
Your original ODE is separable so don't really need to do laplace
oh wow
yea its cause im doing an investigation comparing methods
so i need to show its possible with the laplace transform
would that be solvable
Don't know I don't know what the resulting ODE is
Inverse of something involving y?
ok i got something
Your question didn't make sense as y is a function of x
i got y = Ae^2x - 25x + (25e^2x)/2 - 25/2
yea sorry i dont know what i said
i meant product of a function of x AND just y
,w solve y' = 2x(25-y)
,w laplace transform of 2t(25-y(t))
what does this mean
yea but the notation
The derivative of the laplace transform of y
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I want to mention that I just learned the trigonometric functions, and I discovered this thing. I'm sorry if this thing should be explained in school later, but for the moment, I'm still curious.
What have u learned about trigonometric functions so far
U just learned that sin30 = 1/2 etc?
yes, I know the ratios, untill 60*
Okay so u know sin = opp/hyp, cos = adj/hyp rtc
In highschool, in my country, we will learn the trigonometric functions on a circle, and we will prove things, and etc, that's what our professor told us
yes
oh, actually, its just proportions, nothing makes sin special
Now I don't even know what I'm asking
Cosine is not the inverse of sine..
Yeah, I'm sorry, Idk what was in my head
Thank you very much for your time, have a great day!
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I need help
Just ask your question
I need to find slope on a table
@brittle canopy Has your question been resolved?
of course your question isn't answered, if you don't put the function/equation or anything related to it how is somebody going to help you. We can't read your mind.
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Your professor has just told you about The Victorian Way (a YouTube channel).1 You
decide to watch two different episodes at random. For this problem, you will need to know
that of the 77 available videos on this channel, 71 feature Mrs. Crocombe and 6 don’t.
What is the probability that only one of the videos you watch will feature Mrs. Crocombe?
almost but not quite
the probability you calculated is for the event that the first episode you watch features crocombe and the second does not, in that exact order
So how should I go about fixing it ?
multiply by 2
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Help pls
your handwriting is hard to read
can you write it neater or maybe type it up in LaTeX if you're able
lim as x->0
sin(3/x) / (3/x)
mb lol
do i have to manipulate this to the sinx/x =1
Is it as x approaches 0?
Yes
Yes
idk how to do it
@bleak remnant Recheck if question says infinity or 0 for the value which x approaches
its 0
This is different from the limit you typed
get rid of the double fraction
no like i remember an examble where we manipulated the function to sinx/x=1
thats why i thought of using that
wait why are we using u
We want to make it look like $$\lim_{x \rightarrow \infty} \frac{\sin x}{x}$$
Cyrenux
Well u= 3/x works too
@bleak remnant Yeah my bad let u=3/x but same result as before
What does u approach? @bleak remnant
0
No, thats what x approaches
Well nah, it can be positive infinity or negative infinity
Depending if you are approaching from left or right
I don't understand why we changed the it from 0 to infinity
I mean the x approaches
You are confusing this limit:
$$\lim_{x \rightarrow 0} \frac{1}{x}$$ this limit does NOT exist
Cyrenux
Because if you approach 0 from right, right limit is +infinity
If you approach 0 from left, left limit is -infinity
Since right limit and left limit are not equal, limit doesnt exist
You need to understand this limit first
For you to understand next step
Forget your question
Learn this limit correctly first
Oh ok2
You thought it was existed and that it was equal to infinity
Reread what i typed, do you understand
For infinite limits we check the left and right hand limits first right
I remember it from our discussion
Its dne cuz left is -int and right is +inf
Yes
Now, earlier we were doing a substituion, namely
u=3/x ( where x approaches 0)
But notice u wouldnt be able to approach any value...
Yeah
So we need to consider two cases
u= 3/x as x approaches 0 from right
And u = 3/x as x approaches 0 from left
For first case, u will approach positive infinity
While on second case, u will approach negative infinity
Yeah im following
Show that both limits have same value
Then our original limit ( which you asked) will exist and have a value
I gtg now
Cya
I don't think so.
1 / 0.0001 = 10000
1 / -0.0001 = -10000
1 / 0 = Infinity
1 / -0 = -Infinity
But 0 = -0
Hence 1 / 0 is Undefined
The third and fourth lines are a bit weird to write, but the idea is correct, except that the fourth line should be -infinity, I assume
Though the limit in the question actually exists
$\lim_{x \to 0} \frac{\sin(\frac 3 x)}{\frac 3 x}$ exists and is equal to $L$ iff [\lim_{x \to 0^-} \frac{\sin(\frac 3 x)}{\frac 3 x} = \lim_{x \to 0^+} \frac{\sin(\frac 3 x)}{\frac 3 x} = L.]
So consider these two cases.
oh is that
squeeze theorem?
cuz if it is then ill have to close this cuz i dont get that yet lol
or yeah
Hm, perhaps not necessarily. Wait a second
Squeeze theorem seems to be the easiest though
has it not occurred to anybody here to write $\frac{\sin(3/x)}{3/x}$ as $\frac{1}{3} x \sin(3/x)$
Ann
and yes squeeze thm kills this
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Man it's hard
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I have done intergrating fractions in the past but i semi rememered how to do it
for example, if i have $\int \frac{1}{x+1} dx$ \ i would do $y = x+1$ \ $\therefore \frac{dy}{dx} = 1 \cdot (x+1)$ \ $\therefore \frac{dy}{dx} = (x+1)$
yomiko
and then im suppose to compare somewhere
i forgot how to
not sure what you tried to do there
do you mean partial fractions?
the integral of 1/(x+1) is ln|x+1|
am i meant to do $y = ln(x+1)$?
yomiko
well yeah but how do you get to that
well you kinda have to know it
i can't just remeber every integral there is
i did 1/x+1 as an example
i know that its ln|x+1|
i just want to know how i would get to that
well either you take it as the definition of ln
or you differentiate ln and see that this is what you get
well not every, no. but this is one of those you have to know
1/linear integrates to ln
yh i think thats how i used to do it
$y = ln(x+1)$ \ $\frac{dy}{dx} = \frac{1}{x+1} \cdot 1$ \ compare with integral $\frac{1}{x+1} \rightarrow \frac{1}{x+1}$ \ $\therefore (1)ln(x+1)$
yomiko
right?
if its $\int\frac{2}{x+1}\frac{dy}{dx}$, $\frac{1}{x+1} \rightarrow \frac{2}{x+1}$ it would be $2$ ln(x+1)
yomiko
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Find the volume of the solid above the xy-plane, under the surface z = 1 − x^2-y^2
To find volume you use triple integrals
So to find area you have a double integral right?
Never seen double integral aswell, area is just normal integral no??
Under each graph is the area
To find area between two curves you need to use a double integral
Someone can probably explain it better than I can lol but one sec
Alr
So here we have a parabola bounded by y = 3
You can’t find the area with one integral, that would give you the area under the parabola which you don’t want
So we set up a double integral
Ohhhh i see
We use the blinds of the function in x and y as the parameters of the integral
So we can see that we want values from x=-1 to x=1
I see
And we want y values y = 3x^2 (bottom) to y = 3 (top)
You need to go from top to bottom or else your answer will have a wrong sign
Ahhh alright
In 3 space it’s the same thing except now we need an integral for z
I understand yea
It’s helpful to sketch out the curve
can you show that
set one of the variables equal to zero and sketch out the 2d graph. If we set y = 0, we can graph it in the xz plane as z = 1-x^2
which is a parabola
actually it’s better to draw it in the xy plane so set z = 0 and you just get a circle with radius 1
does that make sense
so the surface is like an upside down bowl
Ngl no, since this is all new to me, the triple and double integral i mean
maybe can u explain the solution there?
And it might be clear then for me
for example
whats r
Okay uh word of advice you should get familiar with shapes in 3 space before jumping into the calculus but yeah
why is r=1, where did theta come from
So they put it into cylindrical coordinates to make it easier to solve
Since we know it’s an upside down bowl shape
Alright
We know it’s a circle with radius that goes from 0 to 1
So the radius changes as we go down the graph. It starts at 0 at the top and goes to 1 when it hits z = 0
So we integrate radius as a function
ohhh
Next is theta. If we look at the graph from the top down we see a circle and a wedge
We can find the bounds of the circle that the wedge is in terms of theta
And we can integrate in terms of theta
And then finally is z, which is still z
alright and how do i know what theta to pick
► My Multiple Integrals course: https://www.kristakingmath.com/multiple-integrals-course
Learn how calculate the volume of a solid using a triple integral in cylindrical coordinates. In this problem, the solid lies within a cylinder, above a plane, and below a cone and must be converted from cartesian coordinates to cylindrical coordinates.
● ...
graph the wedge over the circle and use the intercepts
I have to go but you should really go over planes and surfaces in 3 space, it’ll make these problems a lot easier
just one thing, if it was 25-x^2-y^2 what would the theta interval then be?
is it still pi/4 to pi/3?
<@&286206848099549185>
@vast shale how many degrees are in a circle
Does that change when you make the circle bigger?
No
So its still pi/4 to pi/3 if r was 5 instead of 1 right? Because the circle is the same
@latent jasper
can anyone confirm this? <@&286206848099549185>
someone?
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Why is a number divided by itself equal to 1? What is the concept of this?
If want to evenly share 5 apples to 5 friends, how many do you give each friend?
But can we only find a concept for division like this? Or can we see it another way?
hmm
Yea, what I needed was a more complicated way of looking at this
may I ask what this is for?
I just thought about it
I wanted to see mathematics in a way beyond rules
Something I could see
Sure. An axiom of a field is that every number a other than zero has an inverse. That is $a*a^{-1}=1$. In real numbers we call that division and write $a/a=1$. It is by definition like this.
Gigrise
I think I got something out of this, thanks for the reply
I wanted to be able to delve deeper into this way of thinking about mathematics, I don't know exactly where to start
lol
(If there are any errors in my grammar, it's because I'm using a translator)
Actually you can even weaken that definition. and say every number $a$ other than $0$ must have SOME inverse b. that means
$a*b=1$. THEN you can proove that this number $b$ is actually unique for every $a$. And we can write $b=a^{-1}$ because it is unique.
So it is a proof in a way to ur questions why the number $b$ must be number $a$ itself.
Gigrise
I don't think I understood very well how a number having an inverse interferes with division resulting in 1.

I am trying to not further confuse you.
In a field, there is no such operation as division. But we say DIVISION is a multiplication by an inverse. it is a consequence of having an inverse and multiplication operation.
that means by symbol $1/n$ we really mean the inverse of $n$. and the symbol $n/n:=n*n^{-1}$ means $n$ multiplied by the inverse $n^{-1}$
Gigrise
and multiplication by the inverse means by definition that its product is =1 .
I understand. I still need to see other examples and think more about this but you helped me
🫶
I suggest you take a look at group theory. atleast the very basics.
you will understand
Group theory?
https://pages.mtu.edu/~kreher/ABOUTME/syllabus/GTN.pdf
this for example
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I've not got a clue how to do it, because everything I thought was the correct method isn't giving me a working answer
Multiplying the matrix by (x,y) gives
3x-2y = x
4x-6y = y
Which I guess gives me the equations y=x and y= 4/7 x
part b by the way
but neither of those are right
really dont know what im supposed to do
tried substituting y for mx but neither of these are right either
lol im just throwing shots in the dark
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How do I do the chain rule versions?
@blazing yacht Has your question been resolved?
apply chain rule, where u is a function of x
Could you give me the first 3 answers as an example
Is it just like this on all of them?
yeah lol
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hello, i'd like to ask a question about prime numbers
alright!
so
i was doing a formula for a card game i'm working on, and this formula kept generating prime numbers
then i wondered about other formulas that generate prime numbers like that
could someone send me some links about it?
or tell me more
In number theory, a formula for primes is a formula generating the prime numbers, exactly and without exception. No such formula which is efficiently computable is known. A number of constraints are known, showing what such a "formula" can and cannot be.
Formulas for the nth prime number actually exist! One was cleverly engineered in 1964 by C. P. Willans. But is it useful?
References:
Herbert Wilf, What is an answer?, The American Mathematical Monthly 89 (1982) 289–292.
https://doi.org/10.1080/00029890.1982.11995435
C. P. Willans, On formulae for the nth prime number, The M...
note that this doesn't mean every 6n+-1 is a prime, it doesn't go both ways
that's very interesting, that's basically what i was doing with some extra steps haha! the formula was xy + x + 1 and it kept generating prime numbers every so often when i inputed y as 1/3 and and x as N
thanks for the help
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Hi, can someone explain why we set this equation equal to pi and not 0, as sin of both would give us 0?
they're both possible solutions
because periodic trig functions have infinite solutions
But the 0 does not give us the same ans no?
oh it gives negative solutions does it
,ask -(1.326/(8sqrt(2))
which is negative time
so its just invalid
ah
makes sense
so we just have to use trial and error in this case
or is there a way to know?
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I'm a little new to probability/combinatorics and I was really curious to find out the number of ways to get > k heads out of n total flips. I found a solution (attached) but it only works for n = 2m + r and k = m + r (where m, r > 0). I sort of understand why it doesn't work for values less than this but I'm not entirely sure how I would go about finding a completely closed form.
@tacit hill Has your question been resolved?
<@&286206848099549185> halp please
no
no? never in a million years could I have predicted that one
wait I thought you were joking please come back
hello i bet it's better to post some screenshots than just the file (and I'm weak at probability/combinatorics)
@tacit hill Has your question been resolved?
hello?
hello!
i just read once and got no clue about how you get the conclusion (as I've said, I'm weak at this).
however one thing I'm really curious is that you didn't say the k heads in the at least k has to be consecutive
well I meant in a row = consecutive
ohhhh
that's kind of what I did in the first part
you can position that whole n - k + 1 different ways in a series of n flips
arrgggh, hahaha, I'm brain stuck
uhhhh, okay so you can call that one whole W and the rest of the flips (we don't know what they are yet) X. We can have all the consecutive heads first and then all the other random flips: WXXX..., we could have the heads occur after the first flip XWXX... all the way until W is at the very end XXX...W
there are n - k + 1 different places for W to be in
im still processing XD
okay okay take your time
and basic calculation:
https://byjus.com/question-answer/what-will-be-the-next-number-in-the-given-number-sequence-1-3-8-19/
but for "why", I don't know 😔,sorry
@tacit hill Has your question been resolved?
@tacit hill how's it going?
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I found t = (s^2 + 1)^(-1)
Just making sure, would I plug that into the unit tangent and curvature equations?
@trim cedar Has your question been resolved?
😢
dont worry guys i got this
🫡
Hold on I gotta refresh cus I only remember Calc 1 and 2 stuff not Calc 3 
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How do I find the particular solution of this differential Equation and how do I proceed after that to solve the initial value problem?
u can actually treat this as a differential equation of y'
let u = y', then u have u' = 1 - u, which is linear
What's 11-67+98-8÷5000
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for this equation f, why can we simply substitute e^x as h, and then work with the derivative of only g after?
this question asks us to find the extreme value of the range, to finally determine the entire range of f
can we assume that if x can be substituted with a function, that means, in the context of ranges, some g(x) = x?
if you want the extreme values of f(x) = h(g(x)), you are allowed to compute for the extremes of g(x) when h(x) is increasing
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do my drawings look correct?
@cursive fern Has your question been resolved?
Sorry I fell asleep am I allowed to reopen (somewhere else of course)
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.close
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how does $\int x^2 , 2x , dx=\frac{x^4}{2}+c$
SimonWin
Because I thought I had to do integration by parts haha
but apparently, you can say $\int2x^3dx$
SimonWin
but i don't see how that work
x^2 * 2x is just 2x^3, apply power rule for integration
You don't see how x^2 * x is x^3?
.close
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i solved it but i am not sure about my solve. is it correct?
The question is to prove algebraically that each function is inverse function to the another function
is $g(x) = \sqrt[3]{\frac{x+6}{2}}$ or $\frac{\sqrt[3]{x+6}}{2}$?
Ann
it’s the second one
are you sure? because then f and g won't be inverses.
so it's $\sqrt[3]{\frac{x+6}{2}}$
Ann
ah my bad
the left side that x’s it’s mean my wrong solve
then i tried one more time in the right. under the row i made
amm
no
what?
it's an advertiser, ignore them
What is 1-567+68-7-8÷5000×8
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i wrote all my corrections in red
the paper i send its literally a litter
i am sorry for that
i will write it again in another paper
@paper depot
it’s clear now
i solved it in another paper. is it correct?
@paper depot ms. is it correct?🤔
these arrows are overkill, also you don't need to be this formal with me
but i guess it is correct
i was worried about the number i I delet it with each other
but if you said it’s correct then i can be sure about
thank you for helping. final question. in (2x^3 -6)+6. is it ok to delete it with each other i mean the 6’s because its Polynomial my teachers said if it’s Polynomial and number alse you can’t delete it with each other like this
@rapid birch Has your question been resolved?
🌹😁
i asked many questions i am sorry but that’s important question for me
are the 2 vertical lines parallel?
yeah
aight
lemmme help
note that x, 45, 98 degrees are all ina triangle, and it's sum is always 180.
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hi i need help
Linda thought of a natural number and then added a 5 to the left and an 8 to the right in the number representation. This increased the number Lina thought of by 518215.
Find the number Lina thought of and explain why it is uniquely determined.
Show your work, and if possible, explain where you are stuck.
@subtle trail Has your question been resolved?
<@&286206848099549185>
Show your work, and if possible, explain where you are stuck.
pleas.!:!:!:
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
step 1
please somoeone im beggigngyou
let the number be ABCD, then
new number is 5ABCD8,
and 5ABCD8-ABCD=518215
use column form to tackle it.
i still dont understand
there @subtle trail
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Can someone explain the steps done here?
they add and subtract all even numbers from 2 to 2n
so that your odd numbers in the original sum can be grouped into the sum of the first 2n natural numbers
I see, so something like 1+2-2+3+4-4+5 ?
yes
+6-6 at the end
the way they did it
but yes
and also they group all the subtracted terms on the right
I still don't quite get how it turns into 2n-2(1+...+n). Can you show in a little bit more detail? 😓 How exactly does he group the subtracted terms? It wouldn't be ...+2n-1-2n would it?
@robust spruce Has your question been resolved?
.close
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In a arbitrary group G, is the number of elements in the group generated by an element ‘a’ is same as it’s order?
yes
a^n=e means there is upmost n elements in the set right?
how do i see it exactly n elements?
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How do I do part b of this question I don’t know how to do it ?