#help-17

1 messages · Page 90 of 1

vale frigate
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yes, so its 53deg north of west

half summit
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or N 53 W? 🤔

vale frigate
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well im not familiar with this notation u r using..

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basically imagine urself facing the west, and then u turn towards the north thru 53deg

half summit
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ah

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yes I get it now

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thank you

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vocal sleetBOT
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vast shale
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hello can you help me solve a ratio and proprtian question

vale frigate
vast shale
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hi

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can i ask

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Two numbers are in the ratio 9:4 . if 7 is added to each of the numbers.The ratio becomes 5:3 . Find the numbers ?

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<@&286206848099549185> Hey im new no one is helping

subtle barn
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ok

vast shale
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you play roblox

cursive turret
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write it as formulaas.

blissful fable
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solve for a

vast shale
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i dk algebra

subtle barn
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18 and 8

vast shale
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im dumb

blissful fable
vast shale
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k

blissful fable
subtle barn
blissful fable
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i gave you the simulaneous eq

vast shale
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teach me algebra

subtle barn
# vast shale Two numbers are in the ratio 9:4 . if 7 is added to each of the numbers.The rati...

Let's call the two numbers in the ratio 9:4 as 9x and 4x, where x is a positive constant.

So, we have:
First number = 9x
Second number = 4x

According to the given information, when 7 is added to each of these numbers, the new ratio becomes 5:3. So, we have:

(9x + 7) / (4x + 7) = 5/3

To solve for x, we can cross-multiply:

3(9x + 7) = 5(4x + 7)

Now, distribute the numbers on both sides of the equation:

27x + 21 = 20x + 35

Next, subtract 20x from both sides:

27x - 20x + 21 = 35

Combine like terms:

7x + 21 = 35

Now, subtract 21 from both sides to isolate 7x:

7x = 35 - 21
7x = 14

Now, divide by 7 to find the value of x:

x = 14 / 7
x = 2

So, we've found that x = 2. Now, we can find the two numbers:

First number = 9x = 9 * 2 = 18
Second number = 4x = 4 * 2 = 8

Therefore, the two numbers are 18 and 8.

cursive turret
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!nosols

vocal sleetBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

subtle barn
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!nosols\

vocal sleetBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

subtle barn
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!nosols

vocal sleetBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

subtle barn
#

!nosols

vocal sleetBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

river kettle
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relax

blissful fable
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chill

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wtf

subtle barn
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dam that's cool

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!nosols

vocal sleetBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

river kettle
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chill out bro

vast shale
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!nosolos

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wot is sthat

subtle barn
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anyways

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dm me

vocal sleetBOT
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@vast shale Has your question been resolved?

vocal sleetBOT
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main totem
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When I complete this problem, Im only subsituting the 2 functions that I circled and Im not exactly sure where Im going wrong

vocal sleetBOT
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@main totem Has your question been resolved?

vocal sleetBOT
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@main totem Has your question been resolved?

silk kindle
silk kindle
vocal sleetBOT
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@main totem Has your question been resolved?

vocal sleetBOT
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main totem
vocal sleetBOT
main totem
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wait I actually did

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it simplifies to 7/t^2+t

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right?

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the issue is that it still doesnt work

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I should subsitute the bounds into the function 7/t^2+t right

silk kindle
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You're given t= tan(x/2)

vocal sleetBOT
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@main totem Has your question been resolved?

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main totem
vocal sleetBOT
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@main totem Has your question been resolved?

vocal sleetBOT
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@main totem Has your question been resolved?

vocal sleetBOT
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wide pilot
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Can anybody find the pattern?

vocal sleetBOT
wide pilot
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<@&286206848099549185>

cursive turret
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without more information i would do a linear interpolation.

wide pilot
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hmmm

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could you please guide me with that?

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Y=Y1(Y2-Y1)/(X2-X1) X (X-X1)

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Right?

cursive turret
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300000 sawfly cococons -> 7,5 shrews. 600000 -> 19 you need 500000 which is 2/3 on the way from 300000 to 600000 -> 2/3 from 7,5 to 19 -> ...

wide pilot
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oh

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just a second let me try

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7.67

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?

cursive turret
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plus 7.5 (you start from 7.5)

wide pilot
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ahhh

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so it is

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15.17

cursive turret
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with a linear interpolation: yes

wide pilot
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thank you

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got it

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@grim plover Has your question been resolved?

vocal sleetBOT
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obtuse needle
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How do I get coefficients out of the inside of trigonometric functions?

obtuse needle
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I'm in IB Math Y2. We learnt how to change sin(2x) etc, but homework has sin 3x and sin x/2 and like sin sqrt(3)x/3

crisp moat
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Im pretty sure it's just formulas

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And you have to change what's inside the function to get to a known formula

vocal sleetBOT
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@obtuse needle Has your question been resolved?

obtuse needle
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oka7y one of us just found more identities int he formula booklet that work 👍

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stoic trout
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I’m stuck on a basic tangent line question for calculus.

The question is:
“Sketch the circle of radius 2 centered at 3,-3 and the Line L with equation y=2x+2. Find the coordinates of all the points on the circle where the tangent line is perpendicular to L.”

I know the slope of the tangent lines that would be perpendicular but I’m stuck trying to find how I could use that to find the specific points on the circle where it is perpendicular to L.

north ruin
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if the slope of the tangent at a point is perpendicular to L, then the radius at that point is parallel to L

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so intersect the line which passes through the centre of the circle with gradient the same as L, with the circle, to obtain the points

stoic trout
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The red line has the same slope since it’s parallel and I figured out the b from the circle’s centre point

Y = 2x-9

But do I then do something like:

-1/2x + b = 2x-9

Wasn’t sure how to progress when I found it was parallel

north ruin
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once you have the equation for the red line

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you can either equate it to the equation of the circle to get the intersection points

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or you can find the points on that line a distance of 2 (the radius) away from the centre of the circle

vocal sleetBOT
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@stoic trout Has your question been resolved?

stoic trout
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So something like (x-3)^2 + (2x-9+3)^2 = 4?

north ruin
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yes

stoic trout
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Ok I found one of the answers but how do I find the other one

north ruin
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its a quadratic; you should get 2 solutions

stoic trout
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Oh I think I messed up at one of the steps but I think I know how to do it now tysm

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.closed

north ruin
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np

stoic trout
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.close

vocal sleetBOT
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merry cosmos
vocal sleetBOT
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@vast shale Has your question been resolved?

vocal sleetBOT
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vocal sleetBOT
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bitter herald
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I need help in geometry, I got a test tomorrow and trying to study, but I’m stuck trying to prove statements. How would I prove angle B is congruent to angle C?

bitter herald
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And here is an example

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Would this be right?

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forest haven
vocal sleetBOT
forest haven
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Does anyone have any idea how to do this question

vocal sleetBOT
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lofty spindle
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how to solve lim (sin5x)/(3x) as x approaches 0; knowing that sinx/x = 1

pale perch
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perhaps let u=5x and do some subbing and factoring

odd pawn
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L'hospital brother

lofty spindle
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without using l'hospital

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i know how to solve with that

grizzled halo
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lhopital is so unnecessary here lmao

lofty spindle
grizzled halo
lofty spindle
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kk

vocal sleetBOT
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undone shell
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not sure how they got this answer, but then again, i'm not sure how I got my answer either haha!

undone shell
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my logic was that we have the initial amount, and its exponentially decaying by 0.6%, but either way, now I'm trying to understand the solution, but it doesn't make much sense to me

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<@&286206848099549185>

idle aurora
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no

undone shell
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no?

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<@&286206848099549185>

idle aurora
floral pike
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oh, I got it

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the 207/50000 = 3*69/500

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they are accounting for the amount already in the body at the moment t = 0.69s

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this way, when t = 0.69, the exponent is 0 and the amount in the body is exactly 0.47 ml

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@undone shell

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also you shouldn't be exponentiating the rate in your version

undone shell
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oh okay, so its the rate (found in first part) to the power of the 0.6% decrease, plus the amount thats already in the body?

floral pike
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you would want a form like
f(t) = 0.47(1-0.006)^(t - 0.69)
= 0.47(0.994)^(t-0.69)

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and that would be the same

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...pretty sure.

floral pike
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it's the initial amount, times

undone shell
undone shell
floral pike
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this is an equivalent expression

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umm, wait

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I'm messing it up

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when t=0.69 seconds, we need 47 mL, and we need to be losing 0.06% = 0.006 every second

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0.006 = 3/500

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the formula for decay is P = P_0 e^(-rt)

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that's why you see

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$Q(t) = \frac{47}{100}e^{-\frac{3}{500}t}$

twin meteorBOT
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Disorganized

floral pike
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but we also need to make sure that when t=0.69, the exponent is zero

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we can do that by just doing 0.006*0.69

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which is the same as (3/500)*0.69

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and adding it to the existing exponent

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which is what they did

undone shell
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oh okay, thats where it came from. i see

floral pike
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that's 207/50000

undone shell
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thank you so much for clearing that up, i really appreciate your time

floral pike
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$Q(t) = \frac{47}{100}e^{\left(-\frac{3}{500}t + \frac{207}{50,000}\right)}$

twin meteorBOT
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Disorganized

floral pike
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equivalent

undone shell
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okay, thats the form i'm more comfortable with anyways, so thanks for that as well

floral pike
vocal sleetBOT
#

@undone shell Has your question been resolved?

vocal sleetBOT
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vocal vale
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a bit confused on this

vocal sleetBOT
vocal vale
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ik that f(2) = 1 and g(x)= 8

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but idk what to do with that

vocal sleetBOT
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@vocal vale Has your question been resolved?

vocal vale
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<@&286206848099549185>

late grove
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(f o g)(x) is another way of writing f(g(x))

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In this case x=2, so we want to know what f(g(2)) is.

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You've correctly identified that g(2) = 8

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but now what value do we plug into f(x)?

vocal vale
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1, no?

late grove
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Plugging x = 1 into f(x) will give us f(1) = 9

vocal vale
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hm

late grove
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For f(g(x)), we want to plug x into g(x) and then plug g(x) into f(x)

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So for f(g(2)), we want to plug 2 into g(x) and then plug g(x = 2) into f(x)

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We have already found g(x = 2) = 8

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What value should we then plug into f(x)?

vocal vale
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instead of 2

late grove
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We don't want to do that. Keep in mind that $$ g(2) = 8 \neq 2$$ and so $$ f(g(2)) \neq f(2) $$

twin meteorBOT
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thedude365

late grove
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Since $$ g(2) = 8$$, what is $f(g(2))$ equal to? $$ f(g(2)) = f(...) $$

twin meteorBOT
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thedude365

vocal vale
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3?

late grove
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Why 3?

vocal vale
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f(3) = 8

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man idk why that was so hard i learned this like 2 years ago

late grove
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I think you're reversing the placement of the numbers. The answer's f(g(2)) = f(8) = 3

vocal vale
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thank you so much

late grove
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of course

vocal vale
#

.close

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hushed jetty
vocal sleetBOT
hushed jetty
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im not sure why this is wrong

sly sierra
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how did you obtain that answer

hushed jetty
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wait its because im stupid

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my bad ik the answer thanks

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.close

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errant matrix
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Help me I'm stupid. I want to add 91% isopropol alcohol to 70%, and then dilute that final mixture with water to a final concentration of 70%. I know about c1v1 = c2v2, but I am having issues actually implementing it

errant matrix
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I want the final volume to be 940ml, and I have 320ml of 70%

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I just don't know how to procede from here

vast shale
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It is physically impossible to go down to 70% concentraction if you have 0.0000000000000000000000000000000000000000000000000000000000000000000000000001 ml of 91% in it

errant matrix
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Sorry, I meant to say add water to dilute it down to 70%

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I'll edit the first message

vast shale
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nvm

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yeah that works

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You should do it in two steps

errant matrix
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So, I have 320ml of 70% iso, I want to add some volume of 91% and then dilute to a final volume of 940ml

vast shale
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So you'll have two equations

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One equation for when you add x ml of 91%
and another for when you dillute it with water to reach 940ml

errant matrix
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Right, but I feel like I need to solve the two simultaneously...

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And I never learned how to solve systems of equations in school 🤷‍♂️

vast shale
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then you can subsitute one equation into the other

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then it'll just be one

errant matrix
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Hm....

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Im trying to think of how tha'd work

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Okay maybe I got it

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So If I use c1v1 = c2v2, (0.70.32) = (c20.94), that leaves me with a c2 of 0.23....

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so that means I need to figure outhow to dilute the 91% to 23%, right?

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Did my math do the math things there?

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Nope, I screwed that up

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Okay let me try this: c1v1 = c2v2. I need 640ml of liquid at 70%, so if I dilute the 91% and find out what v1 is needed, that give me (0.91v1) = (0.70.640), and solving for v1 gives me 0.490ish. Which means I would need to add 490ml and then top off to my final volume with water

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I think that's right

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athe 640ml of liquid comes from my wanted 940ml, and I already have 320

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Which is...wrong...but I think my process and thinking is correct

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.close

vocal sleetBOT
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honest heath
vocal sleetBOT
honest heath
#

U(8) is the multiplicative group consisting of elements mod 8 such that their greatest common divisor with 8 is 1

hard atlas
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can you list the elements of U(8)?

honest heath
#

1, 3 , 5 , 7

hard atlas
#

can you list <3>?

honest heath
#

thats kind of part of my confusion. is it just integer multiples of 3?

hard atlas
#

no

honest heath
#

like 3n for some integer n?

#

okay

hard atlas
#

3^n

honest heath
#

ohhh duh

hard atlas
#

the group is under multiplication

honest heath
#

right

hard atlas
#

so 3, 3*3, 3*3*3, ...

honest heath
#

okay

hard atlas
#

(and inverses)

honest heath
#

right

#

is it 3^n mod 8?

hard atlas
#

yes

#

I was just too lazy to write that

honest heath
#

okay so then im lost

hard atlas
#

which elements do you get if you start at 3 and repeatedly multiply by 3

honest heath
#

just 3 and 1

hard atlas
#

yes

#

so <3>={1,3}

honest heath
#

okay, so then pick an element of U(8) that is not <3>?

hard atlas
#

yes, for example 5. what is 5*{1,3} ?

honest heath
#

oh

#

its {5,7}

hard atlas
#

yes

honest heath
#

so <5>={5,7}

hard atlas
#

so without calculating, what is 7*{1,3} ?

hard atlas
honest heath
hard atlas
#

if you want to find <5>, yes

honest heath
hard atlas
#

but you are asked for the cosets of <3>

#

not for <5>

honest heath
#

oh right okay my bad

hard atlas
#

ok, so the left cosets of <3> are {1,3} and {5,7}

honest heath
#

right okay

hard atlas
#

do we have to calculate the right cosets now or do you know something about the group so that we can skip that?

honest heath
#

U(n) is abelian right?

hard atlas
#

yes

honest heath
#

okay

#

one more thing

honest heath
#

am i understanding that correctly?

hard atlas
#

yws

#

yes

honest heath
#

okay fosho! thank you!

#

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#
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fathom hedge
vocal sleetBOT
fathom hedge
#

this is a PRACTICE TEST

#

how do I figure out f^-1(T)

#

i just saw that 3 maps to 6 and 6 maps to 6 mod 9

#

but potentially other things could map to 3 and 6, how can i find them

#

.close

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vast shale
#

How am i supposed to do this?

vocal sleetBOT
vast shale
#

How do i know where the shape begins and ends?

#

I've read this part of my book three times

#

and none of those times did the words in the book change to include the information required to solve this

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#

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tacit knot
#

is there a way to further simplify this?

vocal sleetBOT
grizzled halo
#

kek

#

you could factorise the quadratics if you want

languid berry
tacit knot
#

why is it funny?

languid berry
#

what forbidden god have you angered to be given this problem

tacit knot
#

just trying to figure out how to simplify

languid berry
#

lord have mercy

late grove
vocal sleetBOT
#

@tacit knot Has your question been resolved?

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cyan sky
#

how do i solve a differential equation with the laplace transform where one of terms is a product of a function of x and y

cyan sky
#

for example y' = 2x(25-y)

#

like if i take the Laplace of all terms one of them ends up being 2*L{xy}

#

how do i evaluate that

worthy citrus
#

Have you checked the transform table

cyan sky
#

yes

#

its not there

#

unless im missing a property of the transform i can use

#

i feel like ive checked everything

worthy citrus
#

30

#

It looks like you're just gonna get an ODE again though

#

Your original ODE is separable so don't really need to do laplace

cyan sky
cyan sky
#

so i need to show its possible with the laplace transform

cyan sky
worthy citrus
#

Don't know I don't know what the resulting ODE is

cyan sky
#

ok im gonna try

#

what would be the inverse laplace transform of C/(y-2)

worthy citrus
#

Inverse of something involving y?

cyan sky
#

ok i got something

worthy citrus
#

Your question didn't make sense as y is a function of x

cyan sky
#

i got y = Ae^2x - 25x + (25e^2x)/2 - 25/2

cyan sky
#

i meant product of a function of x AND just y

worthy citrus
#

,w solve y' = 2x(25-y)

cyan sky
#

so still wrong

#

but

#

i probably did something wrong

worthy citrus
#

,w laplace transform of 2t(25-y(t))

cyan sky
worthy citrus
#

?

#

That's the laplace transform of the RHS of your ODE

cyan sky
worthy citrus
#

The derivative of the laplace transform of y

vocal sleetBOT
#

@cyan sky Has your question been resolved?

#
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vocal sleetBOT
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tough kraken
#

I want to mention that I just learned the trigonometric functions, and I discovered this thing. I'm sorry if this thing should be explained in school later, but for the moment, I'm still curious.

vale frigate
#

What have u learned about trigonometric functions so far

tough kraken
#

um, sin, cos, tg, ctg 'till (60*)

#

ratios

vale frigate
#

U just learned that sin30 = 1/2 etc?

tough kraken
#

yes, I know the ratios, untill 60*

vale frigate
#

Okay so u know sin = opp/hyp, cos = adj/hyp rtc

tough kraken
#

In highschool, in my country, we will learn the trigonometric functions on a circle, and we will prove things, and etc, that's what our professor told us

vale frigate
#

Then I don't think I understand what your question is

#

Can u maybe rephrase it

tough kraken
#

oh, actually, its just proportions, nothing makes sin special

#

Now I don't even know what I'm asking

vale frigate
#

Cosine is not the inverse of sine..

tough kraken
#

I mean, it has the ratios

#

inverted

vale frigate
#

Not really

#

Sin = opp/hyp

tough kraken
#

Yeah, I'm sorry, Idk what was in my head

#

Thank you very much for your time, have a great day!

#

.close

vocal sleetBOT
#
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brittle canopy
#

I need help

vocal sleetBOT
vast shale
#

Just ask your question

brittle canopy
#

I need to find slope on a table

vast shale
#

Send your question so we can tell what exactly you want

vocal sleetBOT
#

@brittle canopy Has your question been resolved?

solemn cape
vocal sleetBOT
#

@brittle canopy Has your question been resolved?

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vocal sleetBOT
tawdry wedge
#

.close

vocal sleetBOT
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bleak bloom
#

Your professor has just told you about The Victorian Way (a YouTube channel).1 You
decide to watch two different episodes at random. For this problem, you will need to know
that of the 77 available videos on this channel, 71 feature Mrs. Crocombe and 6 don’t.
What is the probability that only one of the videos you watch will feature Mrs. Crocombe?

bleak bloom
#

Im pretty sure its (71/77) x (6/76)

#

Since its exactly one video

paper depot
#

almost but not quite

#

the probability you calculated is for the event that the first episode you watch features crocombe and the second does not, in that exact order

bleak bloom
#

So how should I go about fixing it ?

paper depot
#

multiply by 2

bleak bloom
#

oh I see what ur saying

#

cause it can be 6/77 x 71/76 ?

vocal sleetBOT
#

@bleak bloom Has your question been resolved?

bleak bloom
#

@paper depot .close

#

.close

vocal sleetBOT
#
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bleak remnant
vocal sleetBOT
bleak remnant
#

Help pls

paper depot
#

your handwriting is hard to read

#

can you write it neater or maybe type it up in LaTeX if you're able

bleak remnant
#

lim as x->0

sin(3/x) / (3/x)

#

mb lol

#

do i have to manipulate this to the sinx/x =1

regal bane
#

Is it as x approaches 0?

lament linden
bleak remnant
lament linden
#

@bleak remnant Recheck if question says infinity or 0 for the value which x approaches

bleak remnant
#

its 0

lament linden
hard atlas
#

get rid of the double fraction

bleak remnant
#

thats why i thought of using that

lament linden
#

Oh right i see now my bad

#

Let u= 1/x now

#

What does u approach

bleak remnant
#

wait why are we using u

lament linden
#

We want to make it look like $$\lim_{x \rightarrow \infty} \frac{\sin x}{x}$$

bleak remnant
twin meteorBOT
#

Cyrenux

lament linden
#

Well u= 3/x works too

#

@bleak remnant Yeah my bad let u=3/x but same result as before

bleak remnant
#

I mean why are we using u for a limit

#

We can do that?

lament linden
#

Changing variables

#

Yeah we can

#

But u will approach a different value than x

bleak remnant
#

So lim of sinu/u

#

Its still indeterminate?

#

Or no nvm

#

Its 1

lament linden
#

What does u approach? @bleak remnant

bleak remnant
#

0

lament linden
#

No, thats what x approaches

bleak remnant
#

u approaches infinity

#

sinu / u as x approaches infinity is zero

#

Right

lament linden
#

Depending if you are approaching from left or right

bleak remnant
#

I don't understand why we changed the it from 0 to infinity

#

I mean the x approaches

lament linden
#

You are confusing this limit:
$$\lim_{x \rightarrow 0} \frac{1}{x}$$ this limit does NOT exist

twin meteorBOT
#

Cyrenux

lament linden
#

Because if you approach 0 from right, right limit is +infinity

If you approach 0 from left, left limit is -infinity

Since right limit and left limit are not equal, limit doesnt exist

bleak remnant
#

Wait im sorry can we like go back to the start

#

Im lost

lament linden
#

You need to understand this limit first

#

For you to understand next step

#

Forget your question

#

Learn this limit correctly first

bleak remnant
#

Oh ok2

lament linden
#

You thought it was existed and that it was equal to infinity

#

Reread what i typed, do you understand

bleak remnant
#

For infinite limits we check the left and right hand limits first right

#

I remember it from our discussion

#

Its dne cuz left is -int and right is +inf

lament linden
#

Yes

#

Yes

#

You get this now right

bleak remnant
#

Yes

lament linden
#

Now, earlier we were doing a substituion, namely

u=3/x ( where x approaches 0)

#

But notice u wouldnt be able to approach any value...

bleak remnant
#

Yeah

lament linden
#

So we need to consider two cases

#

u= 3/x as x approaches 0 from right

#

And u = 3/x as x approaches 0 from left

#

For first case, u will approach positive infinity

While on second case, u will approach negative infinity

bleak remnant
#

Yeah im following

lament linden
#

Show that both limits have same value

#

Then our original limit ( which you asked) will exist and have a value

#

I gtg now

#

Cya

bleak remnant
#

ohh ok

#

thanks!

wary mantle
#

I don't think so.

alpine saddle
#

1 / 0.0001 = 10000
1 / -0.0001 = -10000
1 / 0 = Infinity
1 / -0 = -Infinity

But 0 = -0
Hence 1 / 0 is Undefined

wary mantle
alpine saddle
#

Yeah

#

Made a mistke lol

#

Thanks for noticing

wary mantle
#

Though the limit in the question actually exists

bleak remnant
#

still lsot

#

lost

wary mantle
# bleak remnant

$\lim_{x \to 0} \frac{\sin(\frac 3 x)}{\frac 3 x}$ exists and is equal to $L$ iff [\lim_{x \to 0^-} \frac{\sin(\frac 3 x)}{\frac 3 x} = \lim_{x \to 0^+} \frac{\sin(\frac 3 x)}{\frac 3 x} = L.]

#

So consider these two cases.

bleak remnant
#

oh is that

#

squeeze theorem?

#

cuz if it is then ill have to close this cuz i dont get that yet lol

#

or yeah

wary mantle
#

Hm, perhaps not necessarily. Wait a second

#

Squeeze theorem seems to be the easiest though

paper depot
#

has it not occurred to anybody here to write $\frac{\sin(3/x)}{3/x}$ as $\frac{1}{3} x \sin(3/x)$

twin meteorBOT
paper depot
#

and yes squeeze thm kills this

bleak remnant
#

i go sleep thanks for the help ill dream about this hopefully

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
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sonic flame
#

Man it's hard

vocal sleetBOT
rugged vortex
#

I agree

#

You have an actual question or

vocal sleetBOT
#

@sonic flame Has your question been resolved?

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crimson sedge
#

I have done intergrating fractions in the past but i semi rememered how to do it
for example, if i have $\int \frac{1}{x+1} dx$ \ i would do $y = x+1$ \ $\therefore \frac{dy}{dx} = 1 \cdot (x+1)$ \ $\therefore \frac{dy}{dx} = (x+1)$

twin meteorBOT
#

yomiko

crimson sedge
#

and then im suppose to compare somewhere
i forgot how to

hard atlas
#

not sure what you tried to do there

#

do you mean partial fractions?

#

the integral of 1/(x+1) is ln|x+1|

crimson sedge
#

am i meant to do $y = ln(x+1)$?

twin meteorBOT
#

yomiko

crimson sedge
hard atlas
#

well you kinda have to know it

crimson sedge
#

i can't just remeber every integral there is

#

i did 1/x+1 as an example

#

i know that its ln|x+1|

#

i just want to know how i would get to that

hard atlas
#

well either you take it as the definition of ln

#

or you differentiate ln and see that this is what you get

hard atlas
#

1/linear integrates to ln

crimson sedge
#

$y = ln(x+1)$ \ $\frac{dy}{dx} = \frac{1}{x+1} \cdot 1$ \ compare with integral $\frac{1}{x+1} \rightarrow \frac{1}{x+1}$ \ $\therefore (1)ln(x+1)$

twin meteorBOT
#

yomiko

crimson sedge
#

right?

#

if its $\int\frac{2}{x+1}\frac{dy}{dx}$, $\frac{1}{x+1} \rightarrow \frac{2}{x+1}$ it would be $2$ ln(x+1)

twin meteorBOT
#

yomiko

crimson sedge
#

.close

vocal sleetBOT
#
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vast shale
#

Find the volume of the solid above the xy-plane, under the surface z = 1 − x^2-y^2

vast shale
#

How do i solve that?

#

I dont understand one thing here

#

Never seen 3 integrals

latent jasper
#

To find volume you use triple integrals

vast shale
#

I see

#

Can you explain the steps? I dont understand it

#

@latent jasper

latent jasper
#

So to find area you have a double integral right?

vast shale
#

Never seen double integral aswell, area is just normal integral no??

#

Under each graph is the area

latent jasper
#

To find area between two curves you need to use a double integral

#

Someone can probably explain it better than I can lol but one sec

vast shale
#

Alr

latent jasper
#

So here we have a parabola bounded by y = 3

#

You can’t find the area with one integral, that would give you the area under the parabola which you don’t want

#

So we set up a double integral

vast shale
#

Ohhhh i see

latent jasper
#

We use the blinds of the function in x and y as the parameters of the integral

#

So we can see that we want values from x=-1 to x=1

vast shale
#

I see

latent jasper
#

And we want y values y = 3x^2 (bottom) to y = 3 (top)

vast shale
#

Why cant it be vice versa

#

That y=3 is on bottom

latent jasper
#

You need to go from top to bottom or else your answer will have a wrong sign

vast shale
#

Ahhh alright

latent jasper
#

In 3 space it’s the same thing except now we need an integral for z

vast shale
#

I understand yea

latent jasper
#

It’s helpful to sketch out the curve

vast shale
#

can you show that

latent jasper
#

set one of the variables equal to zero and sketch out the 2d graph. If we set y = 0, we can graph it in the xz plane as z = 1-x^2

#

which is a parabola

#

actually it’s better to draw it in the xy plane so set z = 0 and you just get a circle with radius 1

#

does that make sense

#

so the surface is like an upside down bowl

vast shale
#

Ngl no, since this is all new to me, the triple and double integral i mean

vast shale
#

And it might be clear then for me

#

for example

#

whats r

latent jasper
#

Okay uh word of advice you should get familiar with shapes in 3 space before jumping into the calculus but yeah

vast shale
#

why is r=1, where did theta come from

latent jasper
#

So they put it into cylindrical coordinates to make it easier to solve

#

Since we know it’s an upside down bowl shape

vast shale
#

Alright

latent jasper
#

We know it’s a circle with radius that goes from 0 to 1

vast shale
#

Why is the radius 1

#

oh nvm

#

if i had 25-.... r=5 right

latent jasper
#

So the radius changes as we go down the graph. It starts at 0 at the top and goes to 1 when it hits z = 0

#

So we integrate radius as a function

vast shale
#

ohhh

latent jasper
#

Next is theta. If we look at the graph from the top down we see a circle and a wedge

#

We can find the bounds of the circle that the wedge is in terms of theta

#

And we can integrate in terms of theta

#

And then finally is z, which is still z

vast shale
#

alright and how do i know what theta to pick

latent jasper
latent jasper
#

I have to go but you should really go over planes and surfaces in 3 space, it’ll make these problems a lot easier

vast shale
#

is it still pi/4 to pi/3?

#

<@&286206848099549185>

latent jasper
#

@vast shale how many degrees are in a circle

#

Does that change when you make the circle bigger?

vast shale
#

So its still pi/4 to pi/3 if r was 5 instead of 1 right? Because the circle is the same

#

@latent jasper

#

can anyone confirm this? <@&286206848099549185>

#

someone?

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#
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sick loom
#

Why is a number divided by itself equal to 1? What is the concept of this?

dense stump
#

If want to evenly share 5 apples to 5 friends, how many do you give each friend?

sick loom
#

But can we only find a concept for division like this? Or can we see it another way?

dense stump
#

uh

#

I mean I don’t see an easier way lol

vague pewter
#

n*1/n

#

=1

sick loom
#

catthonk hmm

sick loom
dense stump
#

may I ask what this is for?

sick loom
#

I wanted to see mathematics in a way beyond rules

#

Something I could see

exotic quarry
twin meteorBOT
#

Gigrise

sick loom
sick loom
#

lol

#

(If there are any errors in my grammar, it's because I'm using a translator)

exotic quarry
twin meteorBOT
#

Gigrise

sick loom
exotic quarry
#

I am trying to not further confuse you.
In a field, there is no such operation as division. But we say DIVISION is a multiplication by an inverse. it is a consequence of having an inverse and multiplication operation.

#

that means by symbol $1/n$ we really mean the inverse of $n$. and the symbol $n/n:=n*n^{-1}$ means $n$ multiplied by the inverse $n^{-1}$

twin meteorBOT
#

Gigrise

exotic quarry
#

and multiplication by the inverse means by definition that its product is =1 .

sick loom
#

I understand. I still need to see other examples and think more about this but you helped me

#

🫶

exotic quarry
#

I suggest you take a look at group theory. atleast the very basics.

#

you will understand

sick loom
#

Group theory?

exotic quarry
sick loom
#

Okay, thanks bro

#

🤝

#

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vestal lagoon
vocal sleetBOT
vestal lagoon
#

I've not got a clue how to do it, because everything I thought was the correct method isn't giving me a working answer

#

Multiplying the matrix by (x,y) gives
3x-2y = x
4x-6y = y

#

Which I guess gives me the equations y=x and y= 4/7 x

#

part b by the way

#

but neither of those are right

#

really dont know what im supposed to do

#

tried substituting y for mx but neither of these are right either

#

lol im just throwing shots in the dark

vocal sleetBOT
#

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blazing yacht
#

How do I do the chain rule versions?

vocal sleetBOT
#

@blazing yacht Has your question been resolved?

grizzled halo
#

apply chain rule, where u is a function of x

blazing yacht
#

Is it just like this on all of them?

grizzled halo
#

yeah lol

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sleek wadi
#

hello, i'd like to ask a question about prime numbers

grizzled halo
#

fr

sleek wadi
#

alright!

#

so

#

i was doing a formula for a card game i'm working on, and this formula kept generating prime numbers

#

then i wondered about other formulas that generate prime numbers like that

#

could someone send me some links about it?

#

or tell me more

grizzled halo
grizzled halo
# grizzled halo

note that this doesn't mean every 6n+-1 is a prime, it doesn't go both ways

sleek wadi
# grizzled halo

that's very interesting, that's basically what i was doing with some extra steps haha! the formula was xy + x + 1 and it kept generating prime numbers every so often when i inputed y as 1/3 and and x as N

#

thanks for the help

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#

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hearty delta
#

Hi, can someone explain why we set this equation equal to pi and not 0, as sin of both would give us 0?

grizzled halo
#

they're both possible solutions

#

because periodic trig functions have infinite solutions

hearty delta
#

But the 0 does not give us the same ans no?

grizzled halo
#

oh it gives negative solutions does it

hearty delta
#

,ask -(1.326/(8sqrt(2))

grizzled halo
#

which is negative time

hearty delta
#

so its just invalid

grizzled halo
#

yes

#

so first valid solution is with pi

hearty delta
#

ah

#

makes sense

#

so we just have to use trial and error in this case

#

or is there a way to know?

grizzled halo
#

uh notice that you need more than 0 to get a positive solution

#

that would be it

hearty delta
#

yeah that makes sense

#

thank you so much

#

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tacit hill
#

I'm a little new to probability/combinatorics and I was really curious to find out the number of ways to get > k heads out of n total flips. I found a solution (attached) but it only works for n = 2m + r and k = m + r (where m, r > 0). I sort of understand why it doesn't work for values less than this but I'm not entirely sure how I would go about finding a completely closed form.

vocal sleetBOT
#

@tacit hill Has your question been resolved?

tacit hill
#

<@&286206848099549185> halp please

lyric verge
tacit hill
#

no? never in a million years could I have predicted that one

tacit hill
split wind
#

hello i bet it's better to post some screenshots than just the file (and I'm weak at probability/combinatorics)

tacit hill
#

okay okay

vocal sleetBOT
#

@tacit hill Has your question been resolved?

tacit hill
#

hello?

split wind
#

hello!

split wind
# tacit hill hello?

i just read once and got no clue about how you get the conclusion (as I've said, I'm weak at this).
however one thing I'm really curious is that you didn't say the k heads in the at least k has to be consecutive

tacit hill
#

well I meant in a row = consecutive

split wind
#

ohhhh

tacit hill
#

so at least k consecutive heads

#

sorry about that lol

split wind
#

then you can do this:

#

treat HH...H (k times) as a whole

tacit hill
#

that's kind of what I did in the first part

#

you can position that whole n - k + 1 different ways in a series of n flips

split wind
#

arrgggh, hahaha, I'm brain stuck

tacit hill
#

uhhhh, okay so you can call that one whole W and the rest of the flips (we don't know what they are yet) X. We can have all the consecutive heads first and then all the other random flips: WXXX..., we could have the heads occur after the first flip XWXX... all the way until W is at the very end XXX...W

#

there are n - k + 1 different places for W to be in

split wind
#

im still processing XD

tacit hill
#

okay okay take your time

split wind
split wind
vocal sleetBOT
#

@tacit hill Has your question been resolved?

split wind
#

@tacit hill how's it going?

vocal sleetBOT
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trim cedar
vocal sleetBOT
trim cedar
#

I found t = (s^2 + 1)^(-1)

#

Just making sure, would I plug that into the unit tangent and curvature equations?

vocal sleetBOT
#

@trim cedar Has your question been resolved?

trim cedar
#

😢

agile oasis
#

dont worry guys i got this

trim cedar
#

🫡

livid tapir
#

Hold on I gotta refresh cus I only remember Calc 1 and 2 stuff not Calc 3 devastation

trim cedar
#

lol its ok

#

ill review with some other ppl tomorrow on the assignment

#

.close

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vast shale
#

How do I find the particular solution of this differential Equation and how do I proceed after that to solve the initial value problem?

vast shale
#

I got the homogenous solution

vale frigate
#

u can actually treat this as a differential equation of y'

#

let u = y', then u have u' = 1 - u, which is linear

vast shale
#

I see

#

and the initial value problem is solved how?

#

sorry I am quite lost

sonic flame
#

What's 11-67+98-8÷5000

paper depot
vocal sleetBOT
#

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long flame
vocal sleetBOT
long flame
#

for this equation f, why can we simply substitute e^x as h, and then work with the derivative of only g after?

#

this question asks us to find the extreme value of the range, to finally determine the entire range of f

#

can we assume that if x can be substituted with a function, that means, in the context of ranges, some g(x) = x?

hybrid flicker
#

if you want the extreme values of f(x) = h(g(x)), you are allowed to compute for the extremes of g(x) when h(x) is increasing

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#

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cursive fern
#

do my drawings look correct?

vocal sleetBOT
#

@cursive fern Has your question been resolved?

tacit hill
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@cursive fern Has your question been resolved?

cursive fern
#

.close

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rose shard
#

how does $\int x^2 , 2x , dx=\frac{x^4}{2}+c$

twin meteorBOT
#

SimonWin

rose shard
#

Because I thought I had to do integration by parts haha

#

but apparently, you can say $\int2x^3dx$

twin meteorBOT
#

SimonWin

rose shard
#

but i don't see how that work

river minnow
#

x^2 * 2x is just 2x^3, apply power rule for integration

#

You don't see how x^2 * x is x^3?

rose shard
#

Yes

#

Oh.. I wrote + which confused me

#

x^2+2x

vale patio
#

how to solve X

rose shard
#

.close

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rapid birch
#

i solved it but i am not sure about my solve. is it correct?

rapid birch
#

The question is to prove algebraically that each function is inverse function to the another function

paper depot
#

is $g(x) = \sqrt[3]{\frac{x+6}{2}}$ or $\frac{\sqrt[3]{x+6}}{2}$?

twin meteorBOT
rapid birch
#

it’s the second one

paper depot
#

are you sure? because then f and g won't be inverses.

paper depot
#

so it's $\sqrt[3]{\frac{x+6}{2}}$

twin meteorBOT
paper depot
#

what was the point in telling me the wrong info

#

anyway here

rapid birch
#

ah my bad

#

the left side that x’s it’s mean my wrong solve

#

then i tried one more time in the right. under the row i made

#

amm

paper depot
#

no

rapid birch
#

what?

paper depot
#

it's an advertiser, ignore them

sonic flame
#

What is 1-567+68-7-8÷5000×8

paper depot
vocal sleetBOT
sonic flame
vocal sleetBOT
rapid birch
#

you math’s enemy

#

go out 😭

paper depot
#

i wrote all my corrections in red

rapid birch
#

the paper i send its literally a litter

#

i am sorry for that

#

i will write it again in another paper

#

@paper depot

#

it’s clear now

#

i solved it in another paper. is it correct?

#

@paper depot ms. is it correct?🤔

paper depot
#

these arrows are overkill, also you don't need to be this formal with me

#

but i guess it is correct

rapid birch
#

i was worried about the number i I delet it with each other

#

but if you said it’s correct then i can be sure about

rapid birch
# rapid birch

thank you for helping. final question. in (2x^3 -6)+6. is it ok to delete it with each other i mean the 6’s because its Polynomial my teachers said if it’s Polynomial and number alse you can’t delete it with each other like this

vocal sleetBOT
#

@rapid birch Has your question been resolved?

rapid birch
#

i asked many questions i am sorry but that’s important question for me

indigo vault
vale patio
#

yeah

indigo vault
#

aight

#

lemmme help

#

note that x, 45, 98 degrees are all ina triangle, and it's sum is always 180.

vale patio
#

ok

#

ty

vocal sleetBOT
#

@rapid birch Has your question been resolved?

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subtle trail
#

hi i need help

Linda thought of a natural number and then added a 5 to the left and an 8 to the right in the number representation. This increased the number Lina thought of by 518215.

Find the number Lina thought of and explain why it is uniquely determined.

vocal sleetBOT
#

@subtle trail Has your question been resolved?

subtle trail
#

<@&286206848099549185>

vocal sleetBOT
subtle trail
#

pleas.!:!:!:

vocal sleetBOT
# subtle trail pleas.!:!:!:
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
subtle trail
#

step 1

#

please somoeone im beggigngyou

split wind
#

let the number be ABCD, then
new number is 5ABCD8,
and 5ABCD8-ABCD=518215
use column form to tackle it.

split wind
#

emm

#
Column Form
     5 A B C D 8
-        A B C D
________________
     5 1 8 2 1 5
split wind
subtle trail
#

OHH THANK YOI

#

.close

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robust spruce
#

Can someone explain the steps done here?

vocal sleetBOT
paper depot
#

they add and subtract all even numbers from 2 to 2n

#

so that your odd numbers in the original sum can be grouped into the sum of the first 2n natural numbers

robust spruce
#

I see, so something like 1+2-2+3+4-4+5 ?

hard atlas
#

yes

paper depot
#

+6-6 at the end

#

the way they did it

#

but yes

#

and also they group all the subtracted terms on the right

robust spruce
#

I still don't quite get how it turns into 2n-2(1+...+n). Can you show in a little bit more detail? 😓 How exactly does he group the subtracted terms? It wouldn't be ...+2n-1-2n would it?

vocal sleetBOT
#

@robust spruce Has your question been resolved?

robust spruce
#

.close

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opal obsidian
#

In a arbitrary group G, is the number of elements in the group generated by an element ‘a’ is same as it’s order?

hard atlas
#

yes

opal obsidian
#

a^n=e means there is upmost n elements in the set right?

#

how do i see it exactly n elements?

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#

@opal obsidian Has your question been resolved?

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wintry walrus
#

How do I do part b of this question I don’t know how to do it ?