So you have 3713.15 = 3500(1 + i)^2
#help-17
hexed estuary
You need to solve for i
Start by dividing 3500 out and then square root it and subtract 1
sharp dust
Start by dividing 3500 out and then square root it and subtract 1
I got i as .03
sharp dust
Alright
hexed estuary
honestly lowkey surprised it's such a clean answer,
vocal sleetBOT
@sharp dust Has your question been resolved?
formal vapor
vocal sleetBOT
formal vapor
How to find B
outer warren
sine rule
outer warren
so you know the sine rule?
vocal sleetBOT
@formal vapor Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
vast shale
“Use the well ordering principle to prove that the GCD of a set of n integers is an integer linear combination of these integers”
I need help determining the set of counter examples to use for the well ordering proof, it has me stumped.
vocal sleetBOT
“Use the well ordering principle to prove that the GCD of a set of n integers is...
vast shale
.close
scenic sandal
Given $f (x, y , z) = x^2y^3 − z$. Find the tangent plane for level surface $f (x, y , z) = 1$ at
(2, 1, 1).
vocal sleetBOT
Given $f (x, y , z) = x^2y^3 − z$. Find the tangent plane for level surface $f (...
twin meteorBOT
afeAlway
scenic sandal
The method I am supposed to use is that the gradient is orthogonal to the level surface. I got the gradient at that point to (4, 12, -1). Then I did: (4, 12, -1) (x-2, y-1, z-1) = 0 and got z = 4(x-2) + 12(y-1)+1 but the correct answer is z = 3 + 4(x − 2) + 6(y − 1). What did I do wrong?
paper depot
this is some kind of cruel joke
the point (2, 1, 1) does not lie on the surface f(x,y,z)=1, does it?
f(2, 1, 1) = 3, by the looks of it.
scenic sandal
f(2, 1, 1) = 3, by the looks of it.
You are actually correct.
But it is on prof powerpoint
paper depot
does the prof give any working out
scenic sandal
nope just answers
scenic sandal
Consider the function f defined by
$(x, y , z) = x^2y^ 3 − z.$
a) Determine the tangent plane of the level surface $f (x, y , z) = 1$ at the point
(2, 1, 1)
twin meteorBOT
afeAlway
scenic sandal
Not that it helps but I just thought you should see the original question as it is
scenic sandal
guessing they are uncooperative about checking their own answers?
happens often tbh I usually get stuck and realize their answer is wrong lol
paper depot
it is wrong in this case
queen flicker
queen flicker
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
steep musk
gray yarrow
!status
vocal sleetBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
.close (resolved in another channel)
vocal sleetBOT
vocal sleetBOT
Available help channel!
wispy finch
Can someone help me integrate this I forgot how the tabular method works
wispy finch
.close
proud igloo
Let us consider the following problem:
The costs to be incurred to produce equipment for a machine tool is 1000 euros. We have been ordered 3 pieces of equipment at the price of 2000 euros each. In the production process there is an operation which can fail with probability Pr = 0.1. When this happens the raw materials have to be thrown away and the process has to start all over again.
• What is the probability of having a profit?
vocal sleetBOT
Let us consider the following problem:
The costs to be incurred to produce equip...
proud igloo
i have the solution but cannot undersatnd a formula, for having a profit we must make 3 machine in between of 3 or max 5 tentatives
• PrI(3)=(1−p)3 =0.729;
• PrI(4) = 3C1(1 − p)3 p = 0.2187;
• PrI (5) = 4C2(1 − p)3 p2 = 0.04374;
(1-p)^3 in every formula sorry
civic pendant
Right
The probability of having a profit is the probability of at most 2 failures
otherwise you pay 6000 euros already
and you get paid 6000 euros
so you breakeven and don't have profit
proud igloo
why do we need to (1-p)^3 that what i dont understand..
civic pendant
So Pr[0 failures] + Pr[1 failuer] + Pr[2 failueres]
0 failures = (1-p)^3
1 failure = (3 choose 1) (1-p)^3 * p
soory
(1-p)^3 because you want eventually to suceed in all 3 productions
so 1 failure w.p. p and 3 successs w.p. (1-p)^3
proud igloo
oh okey thanks!
civic pendant
you are welcome
vocal sleetBOT
@proud igloo Has your question been resolved?
lone ember
erm
vast shale
No
lone ember
oh
vast shale
I think you dont know chain rule correctly
lone ember
i do know the chainrule but idk how to use it in trigo and squareroot correctly
lone ember
haha
oblique stone
(x - 12cos(4x))((x^2-3sin(4x))^-1/2)
twin meteorBOT
Zouni
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
vocal sleetBOT
@lone ember Has your question been resolved?
brazen perch
[\frac{-z^6+z^2}{z^4 - 1}]
vocal sleetBOT
\[\frac{-z^6+z^2}{z^4 - 1}\]
twin meteorBOT
dopediscorduser
twin meteorBOT
dopediscorduser
brazen perch
I don't think this is right
brazen perch
Take it from the numerator?
floral seal
$\frac{(-z^2)(z^4-1)}{z^4-1}$
twin meteorBOT
MochaOhwelp
twin meteorBOT
dopediscorduser
brazen perch
Okay
floral seal
**dopediscorduser**
start from this
brazen perch
[\frac{-z^6+z^2}{z^4 - 1}]
twin meteorBOT
dopediscorduser
floral seal
its wrong
brazen perch
Starting with the original equation
floral seal
ok
brazen perch
You're saying to multiply out of the denominator right?
brazen perch
Ohhh
brazen perch
**MochaOhwelp**
Okay this makes sense now
floral seal
yes
vocal sleetBOT
floral seal
no problem
tulip nebula
Let total students be x
40/100x is the number of graduate students. 15/100 * 40/100 * x =3/50x is the number of students who are pursuing a engineering and are graduate at same time
It's asking the percent of students who are graduate but pursue engineering degree at same time
0.24/0.4 percent?
Then by multiplying it to 100 should give percent
And that's correct answer
They are asking what percent of students that pursue an engineering degree must be graduate students
..so it's compulsary for that particular student to be both, a graduate and pursuer of enginnering degree at same time..
Ohh
Wait, are you confusing it with percent of enginnering students who are graduate
Sorry I'm wrong
I got the correct answer btw
I have to understand what is x and E in your copy
Including G
6/100/ 24/100
Because 6/100 is the percent of graduate students who pursued engineering and 24/100 is the percent of students who pursed engineering
No
You're telling me numbers in multiplier form so it's hard to understand
If total students is x then graduate students is 0.4x, and graduate students who pursued engineering is even less
And that's 0.06
What percentage of (students pursuing an engineering degree) are graduate.
So we first find number of students pursuing an engineering degree
And divide that by number of graduate students who pursed engineering
x is the total students there right?
If that's the case then 0.24x is the students pursuing the engineering course, both graduate and not graduate
I think it's simple after you understand the phrasing
It's asking what percent of y is x
You do x/y * 100
first we need to differentiate between graduate students and graduate students who pursue engineering course
There is no way graduate students are X
That's the hidden meaning
The question stated already
What percentage of fruits are apples
There are two apples on your tables
And three on bed
Total fruits is 10
What percentage of fruits sitting on table are apples
That's clearly 2/10 and not 5/10
Why not 5
because that's apple as last word
And number of apples is 5
Same wording in question
We don't consider X as graduate
But graduate who pursued engineering
It would 2/7 by the way
My bad
Because total fruits is 10 and 3 apples already sit on bed
lol
Glad it helps
Phrasing is indeed the toughest part of the question
You should look out for what's being asked in the question
Because you only need answer, be by crook or hook
As long as you find the crux of what's being asked, figure out your way to find that
Welcome
vocal sleetBOT
@vast shale Has your question been resolved?
compact haven
amber hound
vocal sleetBOT
amber hound
I am 15
viral copper
Dont say above 15
Be nice
amber hound
Parallel lines are lines that do not intersect right?
viral copper
Precisely
amber hound
Yep
viral copper
And congruent angles?
viral copper
Do you know what the markings on the angles indicate?
amber hound
The letters?
viral copper
The ticks on the angle
amber hound
Ah the line thing?
viral copper
Notice how in the 5th one, one angle has one tick but the other has 2
viral copper
Ah the line thing?
Yes
viral copper
2 has parallel lines yes
amber hound
3 is congruent lines?
viral copper
Why do you think so
amber hound
Because of the letters
No right
Im a person who forgets very easily our professor already taught us this and I forgot already
viral copper
The letters don't tell you anything about this stuff
viral copper
You need to look for the markings on the lines and angles
amber hound
3 doesn't have markings
viral copper
Arrows indicate parallel lines, and angles with the same number of ticks are equal
So they're not parallel
amber hound
And they're not congruent aswell?
viral copper
They won't be
amber hound
Alright thanks man!
viral copper
Atleast I don't think they should be
amber hound
You helped me alot
viral copper
You really can't say if you don't know the measure
viral copper
You helped me alot
No problem
vocal sleetBOT
@amber hound Has your question been resolved?
hasty badger
Why are you able to treat the ds/dt derivative as a fraction and what is it called when you do that? Is it a rule or something? (I would like to point out that even this is from physics, I could do it without these letters)
vocal sleetBOT
Why are you able to treat the ds/dt derivative as a fraction and what is it call...
vast shale
Why are you able to treat the ds/dt derivative as a fraction and what is it call...
in physics, ds is small displacement and dt is time. it is equal to dv
you just treat them as a fraction
because it also represents "very small displacement divided by very small time"
hasty badger
So when you integrate and you have a derivative with multiply you can use it as a fraction?
vast shale
yeah, if you have dv/dt you can just multiply both sides with dt and integrate
unkempt onyx
vocal sleetBOT
unkempt onyx
Trying to calculate the probability for getting C one time, looking at the solution and I can't understand why they are accounting for B at the last part C; B
timber orchid
Trying to calculate the probability for getting C one time, looking at the solut...
If you get C then A, that is C once.
If you get C then B, that is also C once
The last two terms are the odds that you get C; A, and C; B respectively
unkempt onyx
In each other one the C probability is getting multiplied by C againn
Why is it that in the last one C is getting multiplied by B
timber orchid
You want C exactly once
Getting C the first time means you are able to (not get C) the 2nd time
unkempt onyx
So can we just ignore the multiplication by B?
timber orchid
No?
unkempt onyx
Why do we need to multiply by B?
unkempt onyx
Oh I just realized
Thanks a lot
But why doesn't C; C get accounted for in that we also get C one time
Oh I know why
.close
ashen lion
Hello. I am stuck on one question. I created a graph from a real-life data table so it can't be completely accurate. We have a table where the x represents the months (1 January to 12 December). The y represents the average temperature of the month and then the function I created. My question is how do I find the temperature on June 29th? I tried many ways such as looking at the answer on the x-axis. Changing the period so it would only represent June but I can't seem to find the right answer. Here is my graph
vocal sleetBOT
Hello. I am stuck on one question. I created a graph from a real-life data table...
ashen lion
misty belfry
since you want june 29, I recommend looking at july 1 and going a bit back if you want to approximate it
the axis isn't evenly spaced, so finding an exact value is not possible
ashen lion
yes, finding the exact value is not possible but isn't there a way to calculate it? or just by looking at the graph?. Because the data is real
vocal sleetBOT
@ashen lion Has your question been resolved?
vocal sleetBOT
@ashen lion Has your question been resolved?
ashen lion
<@&286206848099549185>
vocal sleetBOT
@ashen lion Has your question been resolved?
vocal sleetBOT
@ashen lion Has your question been resolved?
random wave
yes, finding the exact value is not possible but isn't there a way to calculate ...
From just looking at the graph? Look at what you've been told before, it's responding to your question
vocal sleetBOT
vocal sleetBOT
Available help channel!
past apex
vocal sleetBOT
past apex
Idrk how to do this question, I equated the bottom two and go 1=g(2), but idk if thats right or even the correct way to do it
can you explain how?
i tried the first row, and i somehow got when x=5. y=10
:o
i got 5, 10
sly sierra
ah scratch that, i read the coords in the wrong order
ok
so in the first row:
col 1 tells you that f(-1) = 10, and col 2 tells you that g(5) = -1
therefore, f(g(5)) = f(-1) = 10
so (5, 10) goes in the third col
as you said
past apex
okok im going to try the second and third column using the same logic
ok i got it ty
do you mind helping me with one other question?
i got (f-g)x to be ax^2 - bx^2 + ax -3x -6
sly sierra
yep so far so good
now combine the terms involving x^2
and combine the terms involving x
and combine the constant terms
and compare with the given formula for (f-g)(x)
sly sierra
no.. only do the combining within your own formula, ignore the given one for now
so there should be no -4 for example
sly sierra
so (a-b)x^2 + (a-3)x-6?
almost
-6 is wrong
it should be -1 minus -5, which equals..?
past apex
oh 4 lol
sly sierra
yep
so (a-b)x^2 + (a-3)x + 4
now compare that with the formula given in the question:
4x^2 - ax + c
if those two polynomials are the same
then their coefficients must all be the same
so what does that tell you?
past apex
ah ic
so c=4
a = a-3
wait what
oh -a=a-3
and a-b=4
got itttt
2a=3
a=3/2
and so b would be -4+1.5
ty!
.close
gilded cliff
can someone please help me with the problem attached?
vocal sleetBOT
can someone please help me with the problem attached?
gilded cliff
first the wording is kind of weird and also I just don't know how to start
also please ping me because I'll be doing other work
thanks
vocal sleetBOT
@gilded cliff Has your question been resolved?
vocal sleetBOT
@gilded cliff Has your question been resolved?
vocal sleetBOT
floral pike
Yeah, you're just not done yet
cot(A) = 0 everywhere that cos(A) = 0...
I think cot(A) =-1 the same places tan(A) is -1
No solution? 🤔
Check wolfram
Or desmos
Good
That's where cos(A) = 0
(Since it is numerator of cot(A))
That's where cot(A) = 0
I chose to check where cos(A) = 0 because
cot(A) = cos(A)/(sin(A) = 0 --> cos(A) = 0
All 4 should be included
They are all in the required domain.
The definition of cotanget is cosine/sine
If we want cotangent to be 0, then cosine must be 0
Another interpretatation: the horizontal leg of a triangle in the unit circle is 0.
vocal sleetBOT
paper depot
don't think about "making a quadratic equation"
make an equation
if you do it right, it will be quadratic in this case
in terms of s, what is the area of one of doug's pieces of wood?
it is ""considered"" an equation
but you're also not following / not reading my instruction.
in terms of s, what is the area of one of doug's pieces of wood?
why did you jump way ahead
like yes sure 8s^2 = 200 (the spacing around the ^ is stylistically a bit sus) but like
you could have said "s^2" in response to my question and not kept me in the dark about your own progress
you do that a lot -- does "that" mean jumping ahead and deliberately not answering the questions ppl ask you?
or to put that in words: the area of a single piece of wood is s^2.
no, you need special permission, signed and notarized in triplicate...
of course you can.
unless your teacher has specifically forbidden you from writing part or all of that
wdym
that would obviously not be the entire solution??
like thats just one step along the way
the area of a single piece of wood is s^2
therefore the area of all 8 pieces of wood combined is 8s^2
and the problem says the combined area of all 8 pieces of wood is 200
therefore 8s^2 = 200
well you should give steps
vast shale
How do i solve this
vocal sleetBOT
How do i solve this
lavish sluice
Factorise the numerators and denominators
vocal sleetBOT
river minnow
csc(x) cannot be equal to that
woeful stream
not on real x, sure
river minnow
It would mean sin(x) = -2
You forgot about the case csc(x) = 2 though
csc(x) = 2
sin(x) = 1/2
x = (-1)^k * pi/6 + pik for an integer k
opal flare
Any help with this? 🙂
vocal sleetBOT
@opal flare Has your question been resolved?
opal flare
I was trying to construct C myself, without any luck
vocal sleetBOT
@opal flare Has your question been resolved?
woeful stream
Any help with this? 🙂
f is an injection from NxN to N
though i don't see how the tip relates
one thing I would consider is rearrange the outputs from
{1,2,3,4,6,8,9,12,16,18,24,...} into
{1,2,3,4,5,6,7,8,9,10,11}...
vocal sleetBOT
vocal sleetBOT
Available help channel!
bitter ridge
please help with d
vocal sleetBOT
please help with d
bitter ridge
I got the cross product but according to the answers provided, x and y = 6
vocal sleetBOT
@bitter ridge Has your question been resolved?
bitter ridge
<@&286206848099549185>
vocal sleetBOT
@bitter ridge Has your question been resolved?
bitter ridge
<@&286206848099549185>
distant smelt
please help with d
have you tried getting BD and AC and then getting the scaler product which is gonna be equal to zero for both cases and solve the two equations?
you're stuck at part D right?
merry python
please help with d
their dot product is zero
bitter ridge
have you tried getting BD and AC and then getting the scaler product which is go...
We are learning 3d vectors so I assumed that was the intended method, I did this and got the correct answer but it was lengthy
bitter ridge
their dot product is zero
do u know how I could do e
I worked out e to be (cos^-1(root41/root30)
which through a math error at me
distant smelt
We are learning 3d vectors so I assumed that was the intended method, I did this...
pretty sure thats the only way you could do it
vector product doesn't work here
bitter ridge
pretty sure thats the only way you could do it
other class mates said they were trying and failing at using the cross product
and they are smarter than me
I just never got a reasonable answer
anyway
bitter ridge
pretty sure thats the only way you could do it
do u know how I could do e
find angle VMP
merry python
do u know how I could do e
what is the formula of dot product?
bitter ridge
what is the formula of dot product?
But i need the angle in between for dot product and thats the thing I am trying to work out for the question
merry python
cos(theta) is their dot product/their magnitude product
distant smelt
do u know how I could do e
get M by using the midpoint formula between two points which are A & B in this case and then find MV and MP and use their dot product to get the angle
merry python
But i need the angle in between for dot product and thats the thing I am trying ...
we can do that without angle since we are given their cartesian form
distant smelt
^
merry python
bitter ridge
get M by using the midpoint formula between two points which are A & B in this c...
thats what I tried and got a calculator math error
bitter ridge
I dont understand what I am meant to do with that sorry
distant smelt
thats what I tried and got a calculator math error
show what you did, maybe u mistyped a number or something
merry python
I dont understand what I am meant to do with that sorry
example
dot product of
all are cap
(4i+3j+2k).(4i+k)
Their dot product is simply 16+2=18
4*4
2*1
bitter ridge
1/2 (b-a)
b = 11,-1,1
a = 1,-1,1
1/2(b-a) = (5,0,0) = m
distant smelt
1/2 (b-a)
b = 11,-1,1
a = 1,-1,1
1/2(b-a) = (5,0,0) = m
thats where you went wrong
thats not how you get the midpoint between two points
what you did was get half of the magnitude of the vector connecting between them
here's what you should do:
distant smelt
A = 1,-1,1
B = (11,-1,1)
m = (6,-1,1)
great!
now get vector MP & MV
i'm assuming you have point P from the previous question
bitter ridge
But with that answer, VM = root 50
and MP = 5
bitter ridge
i'm assuming you have point P from the previous question
point p = 6,2,5
distant smelt
But with that answer, VM = root 50
and MP = 5
you don't have to work with the magnitude
you can get the dot product using points
so things don't get messy
bitter ridge
I can ??
bitter ridge
Dot product = -25
distant smelt
it's the first thing you're usually taught
bitter ridge
it's the first thing you're usually taught
nvm, I got confused with what u asked, I did the dot product and got -25
merry python
find magnitude of vectors
multiply them
and divide dot product by the product
to get cos(theta)
distant smelt
nvm, I got confused with what u asked, I did the dot product and got -25
ok now you're gonna need cosine thjeta, do you know how to do that using the scalar product?
bitter ridge
ok now you're gonna need cosine thjeta, do you know how to do that using the sca...
no ???
distant smelt
.
bitter ridge
but i got -25 dot product
distant smelt
bitter ridge
???
merry python
That's what I said like 15 minutes ago
bitter ridge
ok hold on let me see if that works
distant smelt
That's what I said like 15 minutes ago
he didn't know how to get the midpoint, thats why he got lost
distant smelt
Dot product = -25
are you sure the dot product is -25 tho lol?
cuz that would mean that the angle between them is obtuse
which is clearly not true if you draw the pyramid
bitter ridge
cuz that would mean that the angle between them is obtuse
thats what I dont get but I think that works
mathematically
distant smelt
m = (6,-1,1) p = 6, 2 , 5 and V im not sure
distant smelt
thats what I dont get but I think that works
so you got the answer?
distant smelt
the meanwhile can u explain what b iv is asking, I dont get it
it wants you to compute the minima of the distance formula between the origin and the point M
do you know what that is
bitter ridge
do you know what that is
no, also the answer for the previous is slightly right
the answer is meant to be 45, I got 135, so 180-45 = 135
distant smelt
the answer is meant to be 45, I got 135, so 180-45 = 135
yeah the scalar product was probably 25 not -25
bitter ridge
this might make sense based on the azimuths
distant smelt
all g
bitter ridge
yeah the scalar product was probably 25 not -25
no it was -25
distant smelt
no it was -25
thats impossible lol
if it was -25 then the angle between the vectors would never be acute
bitter ridge
given that m = (6,-1,1)
VM = 0,-7,-1
MP = (0,3,4)
distant smelt
given that m = (6,-1,1)
VM = 0,-7,-1
MP = (0,3,4)
either point P or point V are slightly off
idk tbh
bitter ridge
it wants you to compute the minima of the distance formula between the origin an...
half of M?
distant smelt
p is given and v solutions from prior parts were given and were correct
im not sure, scalar products are positive when the angle between the vectors is acute but i mean the answer is close
rare tusk
Can someone help me solve number c?
vocal sleetBOT
Can someone help me solve number c?
silent spire
explain where you are stuck please
rare tusk
Number c? I cant solve it
silent spire
do you got a spark or just didnt know where to start
merry python
<@&286206848099549185>
!status
vocal sleetBOT
<@&286206848099549185>
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Idk where to begin
silent spire
what can you get from Q=0?
rare tusk
ysinA - xcosA = Q = 0, so i tried squaring the two sides but it didnt get me anywhere
silent spire
let me see
what can you infer from (x-y)^2/x^2+y^2
i think its crucial
However, i gtg
rare tusk
😐
silent spire
use pure algebra method
stoic drift
Can someone help me solve number c?
I guess we can start by equating.
ysinA=xcosA
Then we can square both sides.
y^2sin^2A=x^2cos^2A
Now sin^2A is nothing but 1-cos^2A so
y^2(1-cos^2A)=x^2cos^2A
y^2-y^2cos^2A=x^2cos^2A
y^2=x^2cos^2A+y^2cos^2A
Factoring cos^2A out.
y^2=(x^2+y^2)cos^2A
Now you can take it off from here. Ping for extra help.
I should really start using latex.
rose shard
Determine a vector $(x \neq 0)$ that belongs to both ker T and ran T.
twin meteorBOT
SimonWin
rose shard
So, suppose I already have the basis for both ker T and ran T could I not just take the sum of two of these vectors and that would include that they're in both since it requires a basis to be closed under addition, so it we sum both them then it's within both, perhaps? Or no? 😂
worthy citrus
a basis is not closed under addition, its a finite list of vectors, and by definition none of them are linear combinations of others
rose shard
Oh, well
Whops
But then how else could I go about finding some vector x for my lineare transformation T(x)=Ax that belongs to both?
vocal sleetBOT
@rose shard Has your question been resolved?
rose shard
<@213349376435814401> Has your question been resolved?
no
rose shard
**SimonWin**
^^
vocal sleetBOT
@rose shard Has your question been resolved?
rose shard
Couldn't it just be the sum of both basis?
Sum basis of ker T + sum basis ran T = v (the vector spanned by both bases? and belongs to both?
Could you not do something like that?
rose shard
.close
hybrid girder
Hey Mates! I am struggling with my financial algebra 
can someone help me figure out how to use the table to get the answer?
vocal sleetBOT
Hey Mates! I am struggling with my financial algebra <:ICNAMNTSKFSDMNFJKFSDASASF...
@hybrid girder Has your question been resolved?
rapid swift
Hey Mates! I am struggling with my financial algebra <:ICNAMNTSKFSDMNFJKFSDASASF...
which question?
or do you not understand what the table actually means?
hybrid girder
Any of them,, I have absolutely no idea what I am doing lol
rapid swift
so you don't know how to read the table? or you know how to read the table but don't get the questions?
hybrid girder
I know how to read the table, but I do not know the formulas to answer the questions
I think
hybrid girder
Yes, 14-16
rapid swift
do you first understand that the table gives you how much tax you pay for a given amount of taxable income?
rapid swift
so if you know how to read the table, why can't you figure out #16 at least?
im trying to figure out where your gap in understanding is
hybrid girder
I can probably do 16, I'm struggling with 14, and 15
rapid swift
Try doing 16 first
14 is basically doing the reverse process
trying to figure out what taxable income gives a certain amount of tax
it's a little more complicated, and it's really hard to do if you're not comfortable at least going the forward direction
15 should be just as easy to do as 16 if you know how to compute percents
floral pike
Where did you get 32440?
hybrid girder
For #16
floral pike
You are solving for the gross income, g
hybrid girder
Her taxable income is 32440
floral pike
So you don't need help with the first two problems in your screenshot?
hybrid girder
I do, but saccharine told me to try 16 first
Ah dang, I gotta go mates, to this class actually, I will probably figure it put, thank you for the help!!
.close
karmic sail
karmic sail
can someone hlep me
timber cypress
vocal sleetBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
vast shale
dont waste multiple people's time
karmic sail
you mean the guy who told me to guess
where can i actually find someone who can help
wicked sonnet
.close
rapid swift
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sharp pagoda
I know the value of tanx/2
How can I use that to find tan^2x/2?
vocal sleetBOT
I know the value of tanx/2
How can I use that to find tan^2x/2?
sharp pagoda
Do I just multiply tanx/2 * tanx/2?
pallid zenith
does that help?L
sharp pagoda
Ye I wrote that poorly..I have tan(x/2) and want to find tan²(x/2)
tulip nebula
Tan^2x is tan2x or (tanx)^2?
pallid zenith
dont forget your parens
sharp pagoda
But isn't tan²(x/2) ≠ (tan(x/2))²?
pallid zenith
theyre the same
tulip nebula
Just multiply by 2 and then square
pallid zenith
its a notational trick since squaring trig functions comes up so often
tulip nebula
And then again divide by 2
pallid zenith
But isn't tan²(x/2) ≠ (tan(x/2))²?
and id still suggest picking some variable if its helpful
vocal sleetBOT
vocal sleetBOT
Available help channel!
stone raven
What should i do next?
vocal sleetBOT
What should i do next?
stone raven
Like, what should i do with sqrt^n(sqrt(n))?
vocal sleetBOT
@stone raven Has your question been resolved?
stone raven
Would i do: lim n-> inf sqrt(n)^(1/n) = 1 ?
fleet ember
take the log
the limit becomes log(n)/2n + log(k)
so log(k) at infinity, and then take the exp again
vocal sleetBOT
@stone raven Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
fiery rose
So, I am reviewing basic trig substitution questions
vocal sleetBOT
So, I am reviewing basic trig substitution questions
fiery rose
And so I plugged in the problem because I don't understand how it got the answer.
I am stuck on step 3 -> I am not exactly sure why the integral of cos^2(theta) = 1/2 cos2u + 1/2
hidden kelp
that's because of a trig identity
$cos(2x) = \frac{cos^{2}(x)-1}{2}$
I think? And then you can isolate cos^2(x)
fiery rose
Oh, right, I completely forgot about these - I hate how they wrote it though.
hidden kelp
Yeah as ugly as it looks, that's how you want to write it so that 1/2 is its own integral and you have cos(2x) alone
fiery rose
write, I see that they seperate them for the rest of the problem.
I get why they wrote it like that though.
twin meteorBOT
imTyp0
fiery rose
Thank you so much - it makes sense now.
fiery rose
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
mighty spoke
vocal sleetBOT
<:shocked:723676848093134886>
thin vale
Do you have a question?
outer warren
.close
queen crest
vocal sleetBOT
queen crest
How would I do #3 here?
orchid jewel
How would I do #3 here?
If you fold #3 what shape do you think it creates
orchid jewel
look at the picture
and visualize connecting all the edges
what shape would it create
You have two circles
and a rectangle in middle
how would you position the two circles and rectangle to form a 3d shape
queen crest
how would you position the two circles and rectangle to form a 3d shape
I rlly can’t think of anything
orchid jewel
I rlly can’t think of anything
orchid jewel
can you visualize why it would be a cylinder?
queen crest
Yeah, I see it now
But how would that help me solve the problem?
Do I use the formula?
orchid jewel
you can
orchid jewel
Just think about it
How does the width of the rectangle
what shape does the edge of the rectangle form
when its in a cylinder
orchid jewel
😭 I'm just gonna stop asking questions
orchid jewel
Or, like, circular?
yes it makes a circle, because the edge is wrapping around the circle
queen crest
yes it makes a circle, because the edge is wrapping around the circle
Yeah
orchid jewel
If it wraps around the circle it would have the same circumference as the circle
so if you know the circumference of the circle you know the length of the rectangle
queen crest
Ohh right
Thanks sm!
I also keep getting the wrong answer for #7
Could u plz help me? @orchid jewel
flat whale
I also keep getting the wrong answer for #7
!show
vocal sleetBOT
I also keep getting the wrong answer for #7
Show your work, and if possible, explain where you are stuck.
orchid jewel
I also keep getting the wrong answer for #7
where'd you get 1.5 from?
queen crest
where'd you get 1.5 from?
I divided 3 by 2
The triangle I drew was so that I could use the Pythagorean Theorem
orchid jewel
I divided 3 by 2
why?
orchid jewel
why would you need to divide one of the sides to use Pythagorean theorem?
orchid jewel
I'm assuming you've already noticed that the shape is just a triangle extruded out into a 3d shape
If you were to find the area of the 2D shape ( the triangle ) and multiply it by the amount it was extruded you would get the answer
or maybe i'm wrong idk
yeahh
I thought the question was volume 😭
Surface area is what they're asking for
queen crest
Surface area is what they're asking for
Yeah
orchid jewel
If you were to split the 3D object into the 2D shapes that create it what shapes would you have
split wind
sorry to interrupt, you might have to ×2 with your 72.8
orchid jewel
Try finding the surface area of those individual 2D shapes and adding them together to get the surface area of the full shape 😭
Or use the formula idk
vocal sleetBOT
@queen crest Has your question been resolved?
queen crest
Yeah, but I’m not getting the right answer
I keep getting, like, 220
This is what I’m doing
Nvm, I got the right answer
.close
rigid jacinth
How do you convert a z-score into percentage of a population?
vocal sleetBOT
How do you convert a z-score into percentage of a population?
rigid jacinth
Particularly in problem 17
Cause I figured the z-score is 1.5
But I don’t know how to find the percent
Is there a thing you can do with ti 84 calculators?
karmic imp
But I don’t know how to find the percent
Use the z table
Like this https://www.z-table.com/
rigid jacinth
I’m getting something like .9332 which doesn’t seem right…
strange crater
it is
rigid jacinth
But it asks the what percentage of the patrons check more than 7 books out which is above the mean, so shouldn’t it be a smaller amount? Like not the majority?
Cause if 93.32% people checked more than 7 books out (when the mean is 4) the distribution feels off
Or do you subtract 1-0.9332?
strange crater
yes it'd be 1 - that
rigid jacinth
Okay, that makes so much sense!
Thank you!!!
🙏🙏🙏
@strange crater and @karmic imp for being super helpful
.close
undone aurora
is this true?
vocal sleetBOT
is this true?
orchid jewel
is this true?
does 1 equal 1?
undone aurora
yes
orchid jewel
good job
orchid jewel
is x^3 equal to x^3
orchid jewel
because they didn't
undone aurora
mhm
vast shale
vocal sleetBOT
vast shale
Can someone explain how they went from what i underlined to that i dont understand
nova fulcrum
oh wait
vast shale
oh wait
Ok
WAIT ACTUALLY
I KNOW
Because what they are saying is that it includes the number 3
up to 3
thats why they removed 4
cuz it doesnt even go there
i get it guys!!!
.close
brave ruin
For problems like this, the way to approach it is to figure out where the piece wise function is continuous right?
vocal sleetBOT
For problems like this, the way to approach it is to figure out where the piece ...
brave ruin
For the open intervals for which it is continuous?
To me that just means like, find where the holes are 🙂
silk comet
polynomials are continuous everywhere, so you only need to check for jump discontinuities
brave ruin
yeah!
that's true
jump discont would be like where the function will have values that I guess skip over certain values right?
silk comet
yeah, basically
silk comet
you need to make sure that the point where the two polynomials are “glued together” meet at the same value on both sides (for both polynomials)
brave ruin
does that involve one of the criteria for a limit? It's like both the one sided limits must have the same limit?
brave ruin
you need to make sure that the point where the two polynomials are “glued togeth...
Hmmm
Could you give me a hint for that?
silk comet
yes, but you don’t need to use limits here because each individual polynomial is continuous
brave ruin
gotcha
silk comet
their limit at any point is equal to their value at their point, by continuity
so you can simply evaluate each polynomial at the connection point
brave ruin
their limit at any point is equal to their value at their point, by continuity
that's lim as x-> a = a right?
brave ruin
so you can simply evaluate each polynomial at the connection point
remind me what connection point means
I don't think I've heard that used here
silk comet
yes
the red and blue parts don't contain discontinuities, because they are just polynomial functions, so you just have the one jump discontinuity
silk comet
for future problems, good to know that trigonometric functions and exponential functions are continuous
brave ruin
yeah
silk comet
and rational functions are continuous everywhere that their numerator is continuous and denominator is continuous and nonzero
vocal sleetBOT
vocal sleetBOT
Available help channel!
golden lily
Im not what im doing wrong
vocal sleetBOT
Im not what im doing wrong
peak matrix
golden lily
ok let me try again
@peak matrix
still wrong 
16x->16x^2, i used expand calculator
still wrong!!!!!!!
8x^3->8x^4
dim quail
$\frac{8x^4}{4}$
twin meteorBOT
bettim
golden lily
$\frac{8x^4}{4}$
any other suggestions where it went wrong?
*desmos calculator (16(4)^2)/3 into (16(4)^3)/3
ITS FINALLLY RIGHT, 13TH TRY LETS GOO
barely any sleep for last couple day messes up mathing skills like crazy
vocal sleetBOT
@golden lily Has your question been resolved?
keen raven
vocal sleetBOT
keen raven
Can somebody explain me what they did here?
boreal remnant
You effectively have four categories
Year 7 Walkers, Year 7 Not Walkers, Year 8 Walkers, Year 8 Not Walkers
The sum of all of these equals 100%
royal obsidian
i don't like this question
difficult the read, but nonetheless possible
here it says that 52% of the students are in year 7. How many are in year 8 that were asked, then?
||48%||
tell me if you understand that, maria
keen raven
100-52=48
keen raven
Year 7 Walkers, Year 7 Not Walkers, Year 8 Walkers, Year 8 Not Walkers
You meant then 52+48+20+80=100..?
boreal remnant
No
royal obsidian
100-52=48
this bit of your answer is correct
52% of the ones asked are from year 7, while 48% are from year 8
now they say that 20% of the ones they asked are year 8 students who walk to school
remember that the 20% is a part of the 48 percent
boreal remnant
This is what the question gives you, see if you can read through the bullets and see how these are found:
Year 7 Walkers + Year 7 non walkers = 52
Year 8 Walkers + Year 8 non Walkers = 48
Year 8 walkers = 20
Year 7 non Walkers + year 8 non Walkers = 42
Year 7 Walkers + Year 8 Walkers = 58
vocal sleetBOT
@keen raven Has your question been resolved?
latent glen
How can I prove that this sequence in Cauchy in Q?
vocal sleetBOT
How can I prove that this sequence in Cauchy in Q?
latent glen
Also the limit is root of 2 so how can it be Cauchy in Q if the limit isn’t even in Q
hard atlas
well thats the whole point of constructing R. that Q isnt closed, so we construct R by adding all the limits of all the cauchy sequences to it and obtain R
the definition of cauchy sequence doesnt say anything about needing a limit
vocal sleetBOT
@latent glen Has your question been resolved?
north kestrel
hello i have a question id be very happy if you check it real quick how i did
vocal sleetBOT
@north kestrel Has your question been resolved?
vocal sleetBOT
@north kestrel Has your question been resolved?
vocal sleetBOT
@north kestrel Has your question been resolved?
north kestrel
<@&286206848099549185>
vocal sleetBOT
@north kestrel Has your question been resolved?
north kestrel
<@&286206848099549185>
vocal sleetBOT
@north kestrel Has your question been resolved?
vocal sleetBOT
@north kestrel Has your question been resolved?
mental arch
k
north kestrel
i need someone to confirm is it right
agile hollow
How can I prove that this sequence in Cauchy in Q?
unique burrow
um... hey dude or gal
so uh... how would i solve this... u know
make it into a single logarithm
unique burrow
oh
unique burrow
Go in a diff one
how do i dat
rotund tartan
how do i dat
timber orchid
Discrete math btw *
Maybe ask in the discrete math channel? I have no idea how to do this
calm merlin
how do i dat
you've gotta use the laws of logarithm
vocal sleetBOT
@north kestrel Has your question been resolved?
fresh coyote
um... hey dude or gal
go to a vacant channel
north kestrel
All the helpers dont know discrete math ??
fresh coyote
white acorn
All the helpers dont know discrete math ??
Most probably don't lmao
woeful stream
so, giving backus-naur forms for strings in L1 to L8? any sources for what automatic and non-automatic mean?