help-13

[tropic oxide]

is there any letter in particular that you want to pick

if not i'll pick one for you. it doesn't matter that much.

,rccw

[tropic oxide]

this is in fact exactly the right equation,yes

...

any reason why you're not asking him to help you

russia

why do you ask?

да

а что

так как продолжим, по-русски, по-английски или без разницы?

i'm not your comrade by a long shot.

anyway.

yeah, sure.

do you understand where the equation comes from?

[wraith dagger]

GMDennis

[tropic oxide]

yes

again, do you understand where this equation comes from?

bože moj, my što, translitom budem pisat'?

no

square rooting both sides is a bad move here

it's not illegal but it just doesn't help.

(you WON'T get x-3 + x-8 = x)

anyway

it's better to expand (x-3)^2 and (x-8)^2

collect like terms

FOLD?

eventually also subtract x^2 from both sides

you will get a quadratic equation

which you can then solve

using any method you know.

[wraith dagger]

GMDennis

[tropic oxide]

https://tenor.com/view/my-poor-eyes-cover-button-gif-13223627

me when i see all this translit

[wraith dagger]

GMDennis

[tropic oxide]

с матом можно и поумереннее

izvinjajus*

я, конечно, сама не стесняюсь слова fuck в своей речи, но, блять, материться, сука, через слово, нахуй, это бля пиздец моветон

короче пока все в порядке

[wraith dagger]

GMDennis

[tropic oxide]

24?

так-то -6x - 16x = -22x

ты не долбаеб, ты прозевал арифметическую ошибку

ну например

🤨

ы!

$x = \frac{-(-22) \pm \sqrt{(-22)^2 - 4 \cdot 1 \cdot 73}}{2}$

[wraith dagger]

Ann

[tropic oxide]

дальше просто надо аккуратненько вбить это дело в калькулятор и округлить до миллиметра (т.е. до одного знака после запятой)

are you actually thinking of committing suicide?

or was that an exaggeration?

ok then please never joke about suicide again

ever

anyway

,w x^2 - 22x + 73 = 0

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ann_dec

[tropic oxide]

,calc 11 + 4 * sqrt(3)

[wraith dagger]

Result:

17.928203230276

[tropic oxide]

the value is correct but you need to round it

this measurement is in cm and the problem said to round it to the nearest mm

so just one final step

no

в задаче сказано до миллиметра округлить

мы все вычисляли в сантиметрах

попробуй не тупить

я же сказала нет

а ОКРУГЛЯТЬ кто будет?

нахуя

в задаче так сказано

нахуя

мимо

179.28 мм

округлить до миллиметра

не 179.9 получается

ты сейчас жестко тупишь

гифки вообще не помогают

ну серьезно

округление классе так в пятом или шестом проходят же

ты не знаешь, как округлять числа?

ага

так и есть

17.9 см или 179 мм

просто надо вспомнить, как числа округлять и до какой точности в задаче округлить сказано

я могу еще раз повториться

sure ok let's move on

i've had enough of this one myself

ебать какая разница

сарказм

я как-то задолбалась, чесслово

это дз на завтра, что ли?

мда

кажется мне, что ты попытался привести все к общему знаменателю 12x, но серьезно напортачил, пытаясь это сделать

x ≠ x/(12x)

1/x ≠ 1/(12x)

по-человечески бы выглядело так: $\frac{12x^2}{12x} + \frac{12}{12x} - \frac{25x}{12x} = 0$

[wraith dagger]

Ann

[tropic oxide]

затем домножаешь на 12x и снова получаешь квадратное уравнение

бля

не флуди

э

<@&268886789983436800> we got a spammer here

don't call me bro, please.

bad habit. you'll do well to unlearn it.

some people don't like being called some words

anyway whatever

this is a quadratic equation again. you know how to apply the quadratic formula. from this point on it is easy and only a matter of arithmetic.

ah, banned then.

good riddance, ig

.close

[cedar kiln]

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[slim jasper]

And their own help channel too.

[tropic oxide]

weh?

oh you're talking about the spam?

[slim jasper]

Yes.

[tropic oxide]

ironic cause they did it right after i told them not to spam

[cedar kiln]

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[crimson sedge]

Given:|a ⃗ | =1, |b ⃗ |=3, |с ⃗ |=5 (a ⃗,b ⃗)=60 degrees, (b ⃗,c ⃗)=90 degrees, (a ⃗,с ⃗)=120 degrees . Find |a ⃗-b ⃗+c ⃗ |.
(the squares are vector signs)

[crimson sedge]

pls help ;-;

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

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[graceful mango]

hi, i dont know how to start this question: A cog A makes 7 revolutions in the same time as Cog B makes 18 revolutions. On a certain day Cog B makes 374 more revolutions than Cog A. How many revolutions did each cog make in total?

[rain drift]

seems like this problem we can set up ratios

so we know that the ratio of cog A to cog B is 7/18, right?

$\frac{\text{cog A}}{\text{cog B}} = \frac{7}{18}$

[wraith dagger]

MellowDramaLlama

[rain drift]

So we know that Cog B makes 374 rotations more than cog A. There we have a unknown number of rotations. What should we call that uknown value?

[graceful mango]

r should be good?

[rain drift]

yeah sure

so we know that cog A rotated r times

how many times did cog B rotate then if cog B rotated 374 more than r?

[graceful mango]

374+r

[rain drift]

bingo!

and we know our ratio

so what we have is this

$\frac{7}{18} = \frac{r}{374 + r}$

[wraith dagger]

MellowDramaLlama

[rain drift]

now just solve for r 🙂

[graceful mango]

r = 238?

[rain drift]

yep!

so we know that cog A rotated 238 times and cog B rotated 238 + 374 = 612 times

and just to verify that's correct, we can work out what each fraction is. If they're equal, then we know we got the correct answer

,calc 7/18

[wraith dagger]

Result:

0.38888888888889

[rain drift]

sorry ignore that one

,calc 7/18

[wraith dagger]

Result:

0.38888888888889

[rain drift]

,calc 238/612

[wraith dagger]

Result:

0.38888888888889

[rain drift]

aaaye look at that 🙂

[graceful mango]

woohoo

[rain drift]

nice work!

[graceful mango]

thank you so much for helping i couldnt find any solution or help online with that style of question

[rain drift]

yeah no worries

gears typically work with ratios 🙂

[graceful mango]

do i need to close this or is it done automatically

[rain drift]

you can do .close

[graceful mango]

.close

[cedar kiln]

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[remote estuary]

hello, does anyone know what this symbol means

[dire geode]

The textbook should define it

[remote estuary]

it is a research paper, does not define it

[dire geode]

Authors probably fucked up then in their latex

[remote estuary]

idk its used like 10 times

[dire geode]

Link the paper

[remote estuary]

i believe that e_i is a simple subraction between model output and expected output if that helpss

and so the double dagger is some way of joining the error fct over all dimensions of the output

[carmine whale]

https://en.m.wikipedia.org/wiki/Dagger_(mark)#:~:text=A double dagger or diesis,after the asterisk and dagger.

[remote estuary]

it is almost the hermetian

[dire geode]

yea this paper is full of bad latex

[carmine whale]

Wikipedia says it's just a footnote symbol

[dire geode]

you need to find the original journal and not just some web archived one

[remote estuary]

as in print journal you mean

or jus not hosted on arxiv

[topaz flame]

Hey guys

y’all should help me on my geometry hw

[dire geode]

arxiv is usually fine but this paper isn't even there

find that

[dire geode]

this could also be good

[remote estuary]

the original link i found it from is where i downloaded the pdf i sent, it is formatted the same

nothing in my unis librarys either

[dire geode]

it's just a sum

again, wherever you got the paper from fucked up the formatting

[remote estuary]

word

those fuckers lmao

thank you

.close

[cedar kiln]

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[mellow nimbus]

would this just be cos x = 0.75

<@&286206848099549185>

[loud patrol]

i dont think so

isnt it like this

[mellow nimbus]

yea it is

[mellow nimbus]

do yk how to do this one

[loud patrol]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[mellow nimbus]

3

like ik the answer is 7.78

but both my ansers are in the 20s

[loud patrol]

ok

so we know that the force at time t is 16.8*t

and force is just mass times acceleration

[mellow nimbus]

yeah

[loud patrol]

so 45*a=16.8t

a=0.373t

[mellow nimbus]

yeah i got that

yupp

[loud patrol]

now how can we get displacement using that equation

[mellow nimbus]

yeah like .5at^2

?

[loud patrol]

no

those equations dont work in this case because acceleration is non constant

[mellow nimbus]

ohhh

[loud patrol]

do you know calculus

[mellow nimbus]

take the derivative

yes

[loud patrol]

derivative would get you jerk

but that is farther away from displacement

[mellow nimbus]

Integral!!!!

[loud patrol]

yeah

[mellow nimbus]

woahh

[loud patrol]

so whats the integral of 0.373t

[mellow nimbus]

0.187t +c

[loud patrol]

t^2

[mellow nimbus]

yeagh

my bad

[loud patrol]

so what does c represent in this context

when we have v = 0.187t^2+c

[mellow nimbus]

initill speed

[loud patrol]

yeah

and whats the initial speed

[mellow nimbus]

0

[loud patrol]

exactly

so we just have v = 0.187t^2

now how do we get to displacement

[mellow nimbus]

do we take integral again

[loud patrol]

i mean

whats the integral of velocity with respect to time

[mellow nimbus]

distance

[loud patrol]

yeah

so youre gonna be able to solve for displacement using that

so yeah integrate

[mellow nimbus]

and then plug in t

[loud patrol]

yes

[mellow nimbus]

yeah that worked

thanks sm bro

[loud patrol]

np

[mellow nimbus]

.close

[cedar kiln]

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[grand pier]

What type of discontinuity is this?

is this infinite or a jump

[warped coyote]

On the green one?

[grand pier]

oh i meant at x=0

[warped coyote]

From the right to left what does it look like?

[grand pier]

infinite discontinuity

but there is a point at x=0

which is 0.5

[warped coyote]

Well if you’re in calculus I’d say limit from the right is \infty but the limit from the left is 0.5 so it’s an infinite discontinuity if it were 0.5 to a finite value I’d say jump, but for that, I’d say infinite discontinuity

[cedar kiln]

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[molten kernel]

what steps to take

[uneven matrix]

whats the question..

[cedar kiln]

@molten kernel Has your question been resolved?

[molten kernel]

wdym exactly?

[cedar kiln]

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[elder sedge]

I need help with the following problem

[elder sedge]

ping me if someone responds

[cedar kiln]

@elder sedge Has your question been resolved?

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@elder sedge Has your question been resolved?

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@elder sedge Has your question been resolved?

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@elder sedge Has your question been resolved?

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[static stirrup]

how do i know the unit circle real values? like all of them? any chart or smth

[exotic furnace]

What do you mean “real values”

[deft saddle]

u can search up unit circle for the chart

[cedar kiln]

@static stirrup Has your question been resolved?

[static stirrup]

sorry the excact values

[pallid meadow]

you can memorise them if you want

there are diagrams

alternatively you can use triangles

which i find a lot easier to remember, you just need to remember your quadrants to know when it will be negative or positive

you just take sin, cos, and tan of those angles and you can easily find out their exact values

[cedar kiln]

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[fair copper]

am i supposed to use product rule or cna i just chain this

[waxen igloo]

ah

chain rule

because it is a compopsite function

[fair copper]

how do i know whn to product or trian

chain*

[waxen igloo]

basically

the product of two functions

would be like

5x^2 * (10x + 5)

right?

chain rule would be

(x+6)^9 or something

because it is composite

[fair copper]

what does composite mean

[waxen igloo]

uhm

how to i explain this

f(g(x))
this would be a composite fucntion
here, you first apply the function g to the input x, and then take the result of that and apply the function f. basically ur "stacking" or chaining these fucntions together

for ur question

sin(cosx)

f(x) = sin(x)

g(x) = cos(x)

f(g(x)) = f(cos(x))

= sin(cos(x))

does that make sense?

[fair copper]

sort of yea

[waxen igloo]

mm

[fair copper]

was i supposed to use quotient on this one or did i just make a dumb mistake

[cedar kiln]

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[keen nova]

i have this question about finding D to make sure we have a rectangle.

I verified that, if we put D at [2,2], the distances remain equal for opposites and adjacents

but my textbook says only [0,4] is the right answer. Why?

the only reason i can think of is naming convention implying A should connect directly with B

or that we should reason about their slopes, but i cannot see how

.close

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[peak minnow]

im pretty sure there is no z bar in denominator

[cedar kiln]

@crimson sedge Has your question been resolved?

[peak minnow]

yeah i realized that there is nothing u can do

i was just pointing out the question

,w solve 2a/(1+a+bi)

[wraith dagger]

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[cedar kiln]

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[hidden hound]

can someone help me solve 2D

[peak minnow]

a = 1
b = -5t
c = 9t^2
use quadratic formula

[hidden hound]

so like

[hidden hound]

im at this bit

but having -11t^2 in the root

doesn't seem right

[peak minnow]

its alright

u can have prime numbers in sqrt using this formula

[hidden hound]

oh

alr so i have -11t^2 in the square root

what now

can i further simplify

or na

[peak minnow]

yeah kindof
sqrt -11t^2 = tsqrt-11 , doesnt affect much

and that would be ur answer

[hidden hound]

so this would be answer?

[peak minnow]

yeah

[hidden hound]

wait i needa have the minus sign too

right?

[peak minnow]

u can

[hidden hound]

do i need it?

would my answer be wrong

without it?

[peak minnow]

$${\frac{5t+\sqrt{11t^2}}{2} , \frac{5t-\sqrt{11t^2}}{2}}$$

[hidden hound]

gah damn

[peak minnow]

u can right it , it might be better

[hidden hound]

wait

why is 5 over t

[peak minnow]

because i messed up

[hidden hound]

ah alr

also

[wraith dagger]

JustToPro

[hidden hound]

cant i take the t out of the square root

cause like surds

so it'll be

[peak minnow]

yeah thats ok

[hidden hound]

alr thanks

it cant be simplified more right?

[peak minnow]

nop

[hidden hound]

thanks again bro

.close

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@halcyon patrol Has your question been resolved?

[halcyon patrol]

<@&286206848099549185>

[mental trail]

What's "Cauchy-Rieman" with a single n?

[halcyon patrol]

I think that's probably just a typo ^^;;

<@&286206848099549185>

... I'd still greatly appreciate some help.

<@&286206848099549185>

[untold wind]

ok

what grade are you on?

just so i know

[halcyon patrol]

I'm a second year engineering student at university

[untold wind]

ok i wont be able to help

uhh

[halcyon patrol]

Ahh thanks anyway ^^;;

[untold wind]

np

happy to be here

[cedar kiln]

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[cedar kiln]

@halcyon patrol Has your question been resolved?

[halcyon patrol]

.close

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[gray flame]

hello

[gray flame]

Fast help pls

[crimson delta]

why does it have to be fast

[gray flame]

How i can simplify X/Y/Z calculation

[gray flame]

because its simple but my brain isnt working now

$X/Y/Z$

[wraith dagger]

kasperky

[gray flame]

Can i just put X/Y*Z

[peak minnow]

no u can put it as X*Z/Y

[gray flame]

Or X*Y/Z

[vagrant elbow]

This is ambiguous

For all you know this is a date

[crimson delta]

is it (X/Y)/Z or X/(Y/Z) ?

[gray flame]

It was just example.

[fair mortar]

you can write $\frac{X}{(\frac{Y}{Z})}$ as $\frac{XZ}{Y}$

[wraith dagger]

Bettim

[fair mortar]

also you can write $\frac{(\frac{X}{Y})}{Z}$ as $\frac{X}{YZ}$

[wraith dagger]

Bettim

[gray flame]

This is the original problem. t=T/W. I Know that W=pi*(D^4-d^4)/16d.

t=T/pi*(D^4-d^4)/16d

So I can write t=T16d/pi(D^4-d^4)?

[fair mortar]

yes

[gray flame]

thanks!

[cedar kiln]

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[cedar kiln]

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[ember kindle]

Please help me , this is a completely new topic for me , for part a , is assume its 8.

[digital cliff]

why 9

[ember kindle]

typo

[digital cliff]

aha, completely vertical lines just have the form x=a where a is some constant

this line is x=8

[ember kindle]

i have a bunch of other questions like this ? could you possibly tell me hopw you got that ?

[digital cliff]

just look at the x coordinate

if its a vertical line its x=const if its horizontal then its y=const

[ember kindle]

okay.

tysm

what about this one?

wait nvm

[floral terrace]

What do you think the answer is here? :3

[ember kindle]

it was y=-2

What about this ? I'm not sure how to explain b .

the question has changed.

uh @floral terrace

how would i do this bc this isnt vertical or horizontal

its to work out the equation of the line

@digital cliff

[digital cliff]

Do you know what gradient or slope means

[ember kindle]

no

[digital cliff]

Have you ever seen $m=\frac{y_2-y_1}{x_2-x_1}$

[ember kindle]

i have never seen anything like that in my life

[digital cliff]

Oops

[ember kindle]

its kinda hard to say but , but ive alr worked out the anwser

like a few minutes ago ,

[wraith dagger]

AℤØ

[digital cliff]

Take any two points on the line, yet the m, then take any singlr point and use y-y1=m(x-x1)

[ember kindle]

ye no.

[digital cliff]

Sorry abiut the messaging im walking around somewhat hurriedly

[ember kindle]

oh ok.

[cedar kiln]

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[delicate bramble]

i need help

[delicate bramble]

<@&286206848099549185>

help me

[misty pier]

4*(x+1)*(x+11) =924

And simplify

[delicate bramble]

should i expand first

+ 12x +11

that is the answer i get when i expand the brackets do i have to times 4

before i minus 924 or do i leave it and minus 924

[misty pier]

Divide by 4 both sides before expanding

[delicate bramble]

(X+1)(x+11) = 231

+ 12x +11 = 231

what should i minus

[misty pier]

Subtract 231 both sides

[delicate bramble]

ok

+ 12x - 220 = 0

i a going to factorise

(x+22) (x-10)

[cedar kiln]

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[onyx dove]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

@bronze briar Has your question been resolved?

[bronze briar]

.close

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[quasi prism]

i used the pathagoream theorem to find the hypotonuse and got square root of 15 ... so i did a^2 = 7^2 + 8^2 and then i subtracted them and got 15? is that wrong

[onyx dove]

are you saying that $$\sqrt{7^2+8^2}=15$$

[wraith dagger]

chlamydia

[quasi prism]

nvm i get it now

.close

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[flat barn]

Need help with midpoint and distance on a graph highschool geometry

[flat barn]

Can you walk me through a midpoint and distance on a graph equation?

I was out sick for 3 days and only got 1 day of review for the test that is tomorrow I have no idea what to do

[desert cedar]

I might be able to help

[flat barn]

alright

brb rq

[desert cedar]

Could you share an example? Or do you just need an explanation of midpoint

[flat barn]

let me see.

I hjust need an explanation in general

[desert cedar]

The distance formula for a linear graph is just the py. Theorem formed in a way where it measures the points of a graph

Lets say your first point is 1,1 and your second point is 5,4

[flat barn]

Hm

[desert cedar]

Plug in the numbers for distance. (5-1)^2 + (4-1)^2 and take the square root of that

9+16 =25. The root of 25 is 5

[flat barn]

What about the midpoint

[desert cedar]

For midpoint, just take the x values added together and divide it by two. So (5+1)/2 and (4 +1) /2

[flat barn]

mhm

[desert cedar]

It’s not super complicated. On a graph you can just point it out unless you’re in between intervals. Just memorize the formulas and you’ll be fine

[flat barn]

Thank you so much

[cedar kiln]

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[deep shell]

how do i do this

[cedar kiln]

@deep shell Has your question been resolved?

[deep shell]

<@&286206848099549185>

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@deep shell Has your question been resolved?

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[plucky notch]

.help

[cedar kiln]

Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

[plucky notch]

.reopen

.open

.help

[cedar kiln]

Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

[plucky notch]

.help

[cedar kiln]

Commands:
clopen: .close, .reopen, .solved, .unsolved
consensus: .poll
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

[plucky notch]

.help reopen

[cedar kiln]

Usage: .reopen
For use in help channels and help forum posts. Reopen a recently closed channel and/or mark the post as
unsolved.

[plucky notch]

AH MA GAH

[plucky notch]

OH

Can anyone help me quick?

I don't know how to do this

I got

[eager sparrow]

there are 2 ways here

Either multiply the expoenent 2 first at the numerator and denominator

or simplify the middle first

or the thing inside the bracket

When you have a negative exponent, it's automatically a reciprocal

[plucky notch]

don't I need to do the exponenets first>

?

[eager sparrow]

You can also do that

[plucky notch]

after moving the negatives

[eager sparrow]

hence I said there are 2 ways to solve it

you can move the negatives ffirst

or you can distribute the 2 the answer is still the same

[plucky notch]

It says the answer is 4q^20 over 9p^18

can you give me the steps?

please?

[eager sparrow]

Ok let's do the easier part

if you have a negative exponent, either the base is going to the denominnator or its either going to the numerator

[plucky notch]

I understand how I got the exponenets, I don't understand how I got the denominator and numerator

[eager sparrow]

aHH THAT one

Like are you confused with the fundamentals?

[plucky notch]

yes

[eager sparrow]

Like the reason why that's the case

ok

[plucky notch]

I don't know how the teacher got 9P

^18

[eager sparrow]

So when you do 2^8, it's just 2x2x2x2x2x2x2 eight times

when you have 2^8 / 2^4, you have

2x2x2x2x2x2x2x2/2x2x2x2

Or 8 2's multiplied by itself divided by 4 2's multiplied by itself multiple times

[plucky notch]

okay

I get that

[eager sparrow]

But you can see that we can just cancel it

the number of the same number to the bottom minus the number of the same numbers at the top

[plucky notch]

I know

I don't think you understood what I meant

[eager sparrow]

Now, let's say that the bottom is bigger

Ok

[plucky notch]

so

you see how the base number

is 9P

in the answer?

I don't understand how the base number turned into 9P

[eager sparrow]

Cause -3 x -3 is 9?

[plucky notch]

Well, yeah

but there is only one negative three

it's -3p^4 x 2p^14

[eager sparrow]

Yeah but it's a (-3)^2 right?

[plucky notch]

it used to be

[eager sparrow]

yeah

so what is negative x negative?

[plucky notch]

Does the exponent not turn into -3p^4

[eager sparrow]

cause that is -3 x -3

[plucky notch]

positiive

[eager sparrow]

Bruh include the coefficient

you're also forgetting it

cause that is an exponent so it's like all of it multiplie by itself 2 times

so there will be a case there where whatever on the top/ -3 x top/ -3

[plucky notch]

I don't get it

hold on

I get that exponents are multiplied by themselvesa

andanta

all of that

[eager sparrow]

like this

[plucky notch]

the teacher wants me to simplify

without changing the exponent into a base nuber

wait

can you solve it step by step?

so I could just see what you mean?

[eager sparrow]

Like this

cause that's an exponent right

so it would bound to happen where -3 x -3

p^2 x P^2 = p^4

ano so on

[plucky notch]

https://tenor.com/view/osaka-azumanga-daioh-angry-oh-my-god-oh-my-gah-gif-26425247

Okay I get what I was doing wrong

[eager sparrow]

I mean do you really understand the law of exponents

[plucky notch]

Also

[eager sparrow]

cause you can do it without using the one I shown you

Like that is the breakdown version

You don't usually use that because there would becase where there are ^7 or big powers

[plucky notch]

shouldn't it be 9P^4 x p^14

what happens to the P?

[eager sparrow]

Wait wut

ok

so coefficients are not affected by the exponent of a variable

IF AND ONLY IF IT EXPLICITLY SAYS IT

[plucky notch]

never mind

it was P

[eager sparrow]

like 7^-3 = 1/7^3

[plucky notch]

not 2P

I get it

[eager sparrow]

ok

[plucky notch]

okay

thank youu veryy muah

[eager sparrow]

no need for that

I already have my bebe

hahahhashahaha

[plucky notch]

I thought that when it's (-3^3) ^2 was -3^9

you helped

[plucky notch]

🤭🤭

.close

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[plain badge]

still confused on the last one

so yesterday i took lim as x approaches 0 of (cotx/x^-1)

which can be rewritten as lim as x approc 0 (x/tan(x)) right

since it's just 0/0 we can use lhopitals

so it results in 1/sec^2(x)

which is 1/1 = 1

is that good enough?

[cedar kiln]

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[ornate crescent]

Am I correct in saying that these two are separable, and the other two are not?

[polar holly]

wdym by seperable?

[ornate crescent]

I believe a separable differential equation is a differential equation that can be written with the variables isolated, but that understanding could be flawed.

[cedar kiln]

@ornate crescent Has your question been resolved?

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[quartz solstice]

correct me on this

if the y-int form is y=30x, then the standard form is

30x+y= -0

[quartz solstice]

is there such thing as -0 or justt 0?

wait hold on

it should be 30x-y = -0

or is it?

[upper abyss]

-0 is 0

[quartz solstice]

alright so it

30x-y = 0?

[cedar kiln]

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[strange bear]

Can someone tell me why it wouldn’t be B?

[sonic saddle]

A function can cross an ha

[slate lintel]

it could cross over the line any number of times

[sonic saddle]

A ha is just a behaviour as x approaches pos or neg infinity

[strange bear]

I thought an asymptote meant that it couldn’t touch the line

[slate lintel]

,w graph sin(10x)/x + 2

[wraith dagger]

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Requested by kitten.in.a.teacup

[livid hound]

,w graph sin(x)/x from x=-100 to 10000

[wraith dagger]

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Requested by ramonov

[sonic saddle]

For a vertical asymptote yes the function cannot cross

But then with an ha its simply just a behaviour as x approaches +/- infinity

[strange bear]

Ok that makes sense now, thank you

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[obtuse sparrow]

can anyone explain how they got to the part in red?

i think it has something to do with levi crevitia

levi civita*

[violet flume]

theres also einstein notation

is omega a matrix

@obtuse sparrow

i will use the opportunity to go grab my notes on this topic

[obtuse sparrow]

i was not under the impression omega was a matrix, let me take another look at the notes

[violet flume]

what kind of object is it?

not the new omega

the old omega

[obtuse sparrow]

oh yes

i think it is a matrix

and omega subscript im pretty sure is an element in the matrix

[violet flume]

so

im trying to be careful here sorry

[obtuse sparrow]

no worries

[violet flume]

we could probably enlighten a little by introducing the sums

maybe

say omega is m x n

$\frac 12 \sum _b \sum _c \epsilon _{abc} \omega _{bc}$

[wraith dagger]

jan Niku

[obtuse sparrow]

mmkay

[violet flume]

maybe this doesnt help

@obtuse sparrow do you know the size of omega?

[obtuse sparrow]

i do not unfortunately

well

do you mean

dimensions?

[violet flume]

yea

3x3?

[obtuse sparrow]

i believe so yes

[violet flume]

okay

in that case we can think more concretely

i hate they used omega twice

$\omega _1 = \epsilon _{1bc} \omega _{bc}$

[wraith dagger]

jan Niku

[violet flume]

only 2 elements contribute to each of these new omega pieces

i believe here youll have what

$\omega _1 = \omega {23} - \omega{32}$?

[wraith dagger]

jan Niku

[violet flume]

and more to your question

$\omega 3 = \omega{12}-\omega_{21}$

[wraith dagger]

jan Niku

[violet flume]

[obtuse sparrow]

hmmm

[violet flume]

oh

but its antisymmetric

and im dropping the one half

so $\omega_{21} = - \omega_{12}$

[wraith dagger]

jan Niku

[violet flume]

which is very convenient, because $\epsilon_{312} = -\epsilon _{321}$

[wraith dagger]

jan Niku

[violet flume]

youll get $\omega_{12} - \qty(- \omega_{12})$

[wraith dagger]

jan Niku

[violet flume]

the 1/2 here will eat the 2 you create

does that make sense?

alternatively just use the definition from antisymmetric $\omega_{ij} = -\omega _{ji}$ @obtuse sparrow

[wraith dagger]

jan Niku

[obtuse sparrow]

im a little hung up where youre getting this from w_3 = w_12 - w_21

[violet flume]

sure

so breaking down the levi civita

all of those variables of iteration run through 1, 2 ,3

but the symbol only has value where each 1 2 and 3 are present

no 2 variables are allowed to be the same

so $\epsilon_{321}$ has a nonzero value, $\epsilon_{323}$ is zero

[wraith dagger]

jan Niku

[violet flume]

to tell what the value is, you check and see if you can get the ordering of the indeces by just rotating 123

if you cant, and you have to switch two of the numbers leaving the third alone, then its negative

otherwise, its positive

sorry, negative and positive 1

wiki has this little table thing

does that much make sense? @obtuse sparrow sorry i keep pinging you

[obtuse sparrow]

the pings and help are very much appreciaed, thank you. just taking a sec to read through this

[violet flume]

no problem

[obtuse sparrow]

final question where exactly is w_23 cominng from here again?

everything else i get

[violet flume]

okay

you can run through and see w_a only gets its components from a couple places

$\omega _1 = \frac 12 \qty(\epsilon _{123} \omega _{23} + \epsilon _{132} \omega _{32})$

[wraith dagger]

jan Niku

[obtuse sparrow]

ok thats interesting

[violet flume]

we dont pick up any others because of levi citiva

theyre all index 121, 133, etc

zeros

since we've fixed a=1 by selecting omega _(1), these are the only ones that come out

[obtuse sparrow]

ok i think i get it

[violet flume]

levi civita is always weird fwiw

i feel like you need to derive the important stuff one time then just convince yourself its true every other time you see it

[obtuse sparrow]

basically the first formula, you have to run through all the permutations of a,b, c in the levi civita and the omega, but we specify w_1, then youre left only with 123 and 132 contributinos

[violet flume]

yea

[obtuse sparrow]

ok

i get this now

thanks so much

you da bomb dot com

[violet flume]

[obtuse sparrow]

thanks again!

.close

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[upper abyss]

What's the smallest value of the integrand in that range?

[ivory finch]

No idea

Idk how to integrate it

How does the integral change the value?

Also the smallest value is 1/6 without integral

The largest value is 1 without integral

[upper abyss]

Actually my method doesn't use the mean value inequality so that must not be what they want

But if you note that:
∫∫ 1/6 dxdy ≤ your integral ≤ ∫∫ 1 dxdy

That solves it

[ivory finch]

how do u know that?

what does 1/6 and 1 dxdy become?

[upper abyss]

1 and 6 lol

[ivory finch]

or is it just a property of integrals?

So if there's integrals in an equality I can compare integrals the same as normal numbers?

As long as there are the same number of them?

And the bounds are the same?

Like quadruple integral of 1 < quadruple integral of 2?

[upper abyss]

Take functions a and b.
If,
a < b

Then
∫ a dx < ∫ b dx

And that goes for multiple integrals too

[ivory finch]

Dope

[upper abyss]

Your integrand is greater than 1/6, so your integral is greater than ∫∫ 1/6 dxdy

[ivory finch]

Wait but

My numbers aren't 1/6 and 1

And they aren't being integrated

[upper abyss]

∫∫ 1/6 dxdy = 1

∫∫ 1 dxdy = 6

∫∫ 1/6 dxdy ≤ your integral ≤ ∫∫ 1 dxdy

1 ≤ your integral ≤ 6

Now this isn't an argument from mean value theorem, so I am missing something they want

Actually maybe it is
http://mathonline.wikidot.com/the-mean-value-theorem-for-double-integrals

[cedar kiln]

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[hybrid wren]

im trying to convert Latm to J do i use 101.325 * 10^3

[hybrid wren]

or just 101.325

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[mild hornet]

Are the reasons right (geometry)

[mild hornet]

Hey

Uh I’m sorry for the rush

It’s late

Due in a bit

I just wanna know what to fix here

Due in a few mins I’m stressing hard lol

[cedar kiln]

@mild hornet Has your question been resolved?

[mild hornet]

@fallen moat

Help

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[mild hornet]

It’s been 15m @fallen moat

50 mins I meant

Check

[fallen moat]

"Please do not ping or DM individual users about your question."

[mild hornet]

Wait an hour in like 3mins

[mild hornet]

Mb but

Can u help

Man

[mild hornet]

:/

[fallen moat]

?

[mild hornet]

Can u

Look at th

The second one

Reason

Is it right

[fallen moat]

3 reasons that i wouldn't be possible to help:

1. I didn't see your channel
2. I am busy
3. I don't know how to help

since 1 is K.O.ed that means it's 2,3

2 or 3, but this time it's 2 and 3

[mild hornet]

What

[mild hornet]

What

What’s the answer for reason

[cedar kiln]

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[crimson sedge]

When do I put plus c in bx+c?

How do I know when to add it and when not to

[idle tusk]

you add it because the numerator of the second term is a linear (degree 1) expression, but the denominator is a quadratic (degree 2)

[crimson sedge]

Doesn’t that mean you write the Bx part

[idle tusk]

no, because the general linear equation is of the form Bx+C

general quadratic would be $Bx^2 + Cx + D$

[wraith dagger]

artemetra

[idle tusk]

general n-degree would be $A_n x^n + A_{n-1} x^{n-1} + \cdots + A_{2} x^2 + A_{1} x + A_{0}$, not $A_n x^n$

[wraith dagger]

artemetra

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[frail dune]

can someone help me with this one? I started by finding the unit vector in the direction of the l axis [2/3 2/3 1/3] but don't know how to proceed

[frail dune]

also - is this quaternion result correct?

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[young anchor]

why is square root always positive?

[south tundra]

We define it to be nonnegative, that's it

[young anchor]

theres no hidden explanations behind it?

[prime notch]

nonnegative

[south tundra]

We could have as well defined it to be nonpositive and possibly readjust some definitions involving it

But it's simply convenience

[young anchor]

and when i solve inequalities it can be both?

[prime notch]

square root comes from this: $x^2 = a$

[wraith dagger]

A Note

[prime notch]

x could be

sqrt(a) and -sqrt(a)

[south tundra]

Yes, unless you have a certain restriction on your variables

[prime notch]

||square root isn't positive once it's imaginary number by the way. Don't have to know if you didn't learn this||

[young anchor]

and in a case like this sqrt is always positive right?

therefore fx has a maximum at 4?

[south tundra]

Always positive or zero

Why 4?

[young anchor]

1/2 will give highest y no?

[prime notch]

yes

[south tundra]

Ah I misread your message

I thought you meant the maximum is 4

Yes, the maximum is at x = 4

[young anchor]

so x^2 and sqrt(x) are two completley different things

in a way

[south tundra]

Of course

They are different in any way you look at them

[prime notch]

any way

[young anchor]

i guess i just got used to seeing a^2 = x too much then

either way thanks

appreciate the help

.close

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[cedar kiln]

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[warm vector]

for part b) how did they go from -12pi/5 to -2pi/5?

[sly abyss]

Simplified

It means the same thing

They are terminal angles

[warm vector]

ohhh

I see

so is it fine if I don’t use terminal angles to simplify further?

[sly abyss]

Quite frankly, I don’t know. But It’s also better to

Because it’s easier to visualize and work with

It’s kinda like simplifying fractions I guess

[warm vector]

mm i see

ok that makes sense, thanks

.close

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